1-
the
Nalt and Gil-
Cu2+
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what are the spectator ions in this reaction

Answer:

Less

Explanation:

The hydronium from the HCl is used to neutralize the bicarbonate in the baking soda. The hydronium is the acid and the bicarbonate ion is the base while the sodium and chloride ions are pH-neutral. Since theres a 1:1 mole ratio of hydronium to HCl and bicarbonate to sodium bicarbonate, it would require less HCl to neutralize a less concentration baking soda solution.

The number of moles of gas in the container would be 4.62 moles

According to the ideal gas law:

  PV = nRT, where P = pressure, V, volume, n = mole number, and R = constant = 8.31

In this case, V = 58.953 L, P 467.81 kPa, and T = 719.11 K

Making n the subject:

   n = PV/RT = 58.953 x 467.81/8.31 x 719.11 = 4.62 moles

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Answer:

D

Explanation:

There are 2 oxygens on the reactants side (OH)2 but 4 on the products side (2H2O). You cannot get 2 oxygens out of nowhere, so it is not balanced.

Answer:

The Police Officer

Explanation:

The Police Officer said : her key the best key on world

Answer:

During the completion of mitosis (telophase), two new nuclei form around the separated sets of daughter chromosomes (see Figure 8.29).

Explanation:

The power delivered by the student's biceps will be 51.45W.

This is defined as the amount of energy converted per unit and the SI unit is Watts.

Power = Energy/time

Force = ma = 42 kg × 9.8m/s² = 411.6N.

Energy = Force × distance

           = 411.6N × 0.25m = 102.9J

Power = 102.9J/2s = 51.45W

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The age of the cat and presumably the village is approximately 13657 years. .

Half-Life is the time taken for half the amount of a substance to disappear.

To determine the age of the cat fossil, the following should be noted:

Mass of carbon in the sample = 0.194 × 10 lb = 1.94 lb

Ratio of carbon-12 to carbon-14 = 1 : 1.35 × 10^-12

Mass of carbon-14 initially present = 1.94 × 1/1.35 × 10^-12 = 2.619 × 10^-12

Ratio of present and original mass of carbon-14 = (5 × 10-13)/2.619 × 10^-12 =

The half-life of carbon-14 = 5700 years

The ratio of the mass of carbon-14 at present and initially = 0.191

Using the half-life formula, to calculate time elapsed:

[tex]t = \frac{t_{\frac{1}{2}}ln\frac{N_t}{N_o}}{-0.693}[/tex]

Substituting the values to solve for time, t, in years

[tex]t = \frac{5700 \times \: ln(0.191) }{-0.693} = 13656.8[/tex]

Time elapsed, t = 13656.8 years.

Therefore, the age of the cat and presumably the village is approximately 13657 years.

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Different isotopes of the same element emit light at slightly different wavelengths, the minimum number of slits  is mathematically given as

N=1820slits

Generally, the equation for the wave is mathematically given as

[tex]d\ sin\ (\theta\ m) \ = \ m\ \lambda[/tex]

Where the chromatic resolving power (R) is defined by

[tex]R\ =\ \lambda\ / \ d \ \lambda[/tex]

R = nN,

Therefore

[tex]\lambda_1 \ = \ (656.45)(1 \ * \ 10^{-9})/1mm[/tex]

[tex]\lambda_1= 656.45*10^{-9}[/tex]

and

[tex]\lambda_2= (656.27)(1*10^{-9})/1mm[/tex]

[tex]\\\\\lambda_2= 656.27*10^{-9}m[/tex]

In conclusion, the minimum number of slits is required to resolve these two wavelengths in second-order

[tex]N\ =\ \dfrac{\lambda}{m\ d\ T\ }\\\\[/tex]

Therefore

[tex]N\ =\ \dfrac{656.45 \ * \ 10^{-9}}{2\ * \ (0.18*10^{-9})}[/tex]

N=1820slits

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Answer: [tex]2168 ^{\circ} \text{C}[/tex]

Explanation:

For this question, we can use the formula [tex]Q=mc \triangle T[/tex], where [tex]Q[/tex] is the amount of heat absorbed, [tex]m[/tex] is the mass of the sample, [tex]c[/tex] is the specific heat constant, and [tex]\triangle T[/tex] is the change in temperature (final temperature minus initial temperature as stated in the question).

From the question, we know that [tex]m=175, Q=1.57 \times 10^{6}[/tex]. Furthermore, we know that [tex]c=4.18[/tex] (this is just a fact).

So, we get that [tex]1.57 \times 10^{6}=175(4.18)(\triangle T)[/tex], meaning [tex]\triangle T=2146[/tex].

Thus, [tex]t_{f}-22.0=2146 \longrightarrow t_{f}=\boxed{2168 ^{\circ} \text{C}}[/tex]

The criteria for designation as a biodiversity hotspot include species richness, endemism, and risk of extinction.

A biodiversity hotspot is a region having high levels of biodiversity in its communities and ecosystems.

A biodiversity hotspot must have a high number of endemic vascular plants (at least 1500 species).

In conclusion, the criteria for designation as a biodiversity hotspot include species richness, endemism, and risk of extinction.

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The energy carried by the waves depends on the amplitude of the wave. If the amplitude is doubled then the energy gets increased by four times.

The amplitude of a wave is the distance from the center line to the trough or the crest of the wave. The energy of the wave is directly proportional to the square of the amplitude.

E  ∝ A²

So if the amplitude is doubled then E = 4. Hence, the energy gets increased quadruples times. The energy is related to the frequency and the wavelength of the wave that travels.

Therefore, the energy gets increased by four times if the amplitude is doubled.

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The concentration of a solution of 192 grams dissolved to make 2150 mL of solution is 0.93M. Details about concentration can be found below.

The concentration of a solution can be calculated by dividing the number of moles of the substance by its volume.

no of moles of NH42CO3 = 192g ÷ 96g/mol = 2 mol

Concentration of solution = 2 moles ÷ 2.15L

Concentration of solution = 0.93M

Therefore, the concentration of a solution of 192 grams dissolved to make 2150 mL of solution is 0.93M.

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[tex]2 Fe (s) + 3 H _2SO _4 (aq)[/tex] → [tex]Fe _2(SO _4) _3 (s) + 3 H _2 (g)[/tex] equation has the same coefficients in the same order as [tex]3 O_2 + C_2H_6O[/tex] → [tex]2 CO_2 + 3 H_2O[/tex]

The numbers placed in front of formulas to balance equations are called coefficients.

For the given equation [tex]3 O_2 + C_2H_6O[/tex] → [tex]2 CO_2 + 3 H_2O[/tex] sum of the coefficient of the reactant side is 5 and sum of the coefficient is 4.

So, according to the question [tex]2 Fe (s) + 3 H _2SO _4 (aq)[/tex] → [tex]Fe _2(SO _4) _3 (s) + 3 H _2 (g)[/tex] equation has the same coefficients in the same order as [tex]3 O_2 + C_2H_6O[/tex] → [tex]2 CO_2 + 3 H_2O[/tex]

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Answer:

It’s c

Explanation:

edge 2022

The valence electron of the light metals are all in the range of 1 to 3.

Valence Electron is the number of electrons in the outer shell of an atom which participate in bond formation.

Number of Valence Electron in Boron is 3 and other light metals lighter than Boron have 1 , 2 of Lithium and Beryllium respectively,

The valence electron of the light metals are all in the range of 1 to 3.

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Answer:

i don't know send on my insta I'd its_arsh_pb27

Explanation:

1.0 m [tex]HNO_3[/tex] is added to 100 ml of water, the result is a solution with a concentration of 0.001 m [tex]HNO_3[/tex] and the ph of 0.001 M [tex]HNO_3[/tex] is 3

pH historically denoting "potential of hydrogen" (or "power of hydrogen") is a scale used to specify the acidity or basicity of an aqueous solution

GIven ,

[tex]H^{+}[/tex] = [tex]10^{-3}[/tex] M

we have the formula for

[tex]_PH[/tex] = - log [[tex]H^{+}[/tex]]

[tex]_PH[/tex] = - log [ [tex]10^{-3}[/tex] ]

       = 3 log 10

  [tex]_PH[/tex] = 3

Hence, [tex]_PH[/tex] of water is 7 but after adding 1 drop (0.001 m [tex]HNO_3[/tex] ), It changes to 3.

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Moles of Mercury Nitrate

Mass

Answer:

1,840g

Explanation:

I just took the test and got it right :)

Answer: 10.865

Explanation:

The molarity of the solution is [tex]\frac{0.0003}{0.410}=0.0007317073 \text{ M}[/tex].

So, the pOH is [tex]-\log(0.0007317073)=3.135[/tex]

Since pH + pOH = 14, the pH is 14-3.135, which is about 10.865

Answer:

The molar volume of a gas expresses the volume occupied by 1 mole of that respective gas under certain temperature and pressure conditions.

scientists use molar volume to measure gas because it it tells us about volume occupied by gas.

Molar volume

Given the remaining quantity after the given time and the half-life, the initial quantity or original mass of the sample is 32g.

Option A) is the correct answer.

Half-life is simply the amount of time it takes a given quantity to decrease to half of its initial value.

Using the expression:

[tex]N_{(t)} = N_{0}\frac{1}{2}^{\frac{t}{t_{\frac{1}{2} }} }[/tex]

Given the data in the question;

[tex]N_{(t)} = N_{0}\frac{1}{2}^{\frac{t}{t_{\frac{1}{2} }} }[/tex]

[tex]1.0g = N_{0} * (0.5)^{40days/8.07days}\\\\1.0g = N_{0} * (0.5)^{4.95662949}\\\\1.0g = N_{0} * 0.0322037055\\\\N_{0} = \frac{1.0g}{0.0322037055} \\\\N_{0} = 31.05g = 32g[/tex]

Therefore, given the remaining quantity after the given time and the half-life, the initial quantity or original mass of the sample is 32g.

Option A) is the correct answer.

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Familiar substances that sublime readily include iodine , dry ice , menthol, and camphor. Sublimation is occasionally used in the laboratory as a method for purification of solids, for example, with caffeine.

Answer:

l think gasoline and electric

The structures of the aldol addition and condensation products of pentanal are attached as an Image with this answer.

What is Aldol Addition ?

An aldol addition is a reaction that occurs between the enolate of an aldehyde or ketone and the alpha-carbon of another aldehyde or ketone to form a beta-hydroxy aldehyde or ketone.

The term aldol condensation has to do with a reaction in which a nucleophile attacks the carbonyl group of an aldehyde or a ketone to convert it to the enolate from which attacks another aldehyde or ketone at the carbonyl carbon to form the required product.

The product obtained in the process is shown in the image attached with the answer.

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Answer:

Coating a material with metal

(SInce the glasses will be coated with gold.)

Answer:

Chlorowanie wody jest procesem względnie tanim – koszt zbudowania samej instalacji do dezynfekcji, jak również koszt operacyjny wytworzenia 1 metra sześciennego uzdatnionej chlorem wody jest niższy od dezynfekcji wody za pomocą ozonu. Źródłem chloru w procesie dezynfekcji jest zazwyczaj podchloryn sodu, rzadziej dwutlenek chloru.

Explanation:

Hydroelectricity is the technology whose growth has surpassed the city's ability to provide sufficient water to its people.

Technology is the process of fusing science and the application of skills in scientific industries.

The population can use the waves even the tides of the ocean's water to create electricity which is reliable.

Of course in the beginning it will be expensive but the result will be effective and useful.

The area having a dry climate could be because of the winds that blow precipitating clouds away but they can have a stable climate by planting more trees where rain can be processed within the geographical location.

Finally, the problem of water supply can be fixed by installing water pipes to transport water to the community but in the process, water can be filtered or cleaned to prevent some diseases and social issues/calamities.

Hence, hydroelectricity is the technology whose growth has surpassed the city's ability to provide sufficient water to its people.

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Practical work refers to the art of conducting experiments in order to answer certain research questions.

In science, practical work refers to the art of conducting experiments in order to answer certain research questions. This could occur in a laboratory under controlled conditions or in the field.

In the physical sciences, most of the practical work is conducted in the laboratory under controlled conditions. However, some experiments in the biological sciences and most experiments in the social sciences are conducted outside the laboratory.

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