Answer:
1. 2:5
2. 5:2
3. 2,5
Step-by-step explanation:
Hope you have a great day
Pls help me the question is in the photo !!
Answer:
14
Step-by-step explanation:
separate the figure into two shapes. On the little one is 2x1 which the answer is 2 then on the larger shape is 6x2 which is 12 then you add 12+2 and then you get your answer
pls help asap
Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the correct position in the answer box. Release your mouse button when the item is place. If you change your mind, drag the item to the trashcan. Click the trashcan to clear all your answers.
Indicate in standard form the equation of the line passing through the given points.
E(-2, 2), F(5, 1)
Answer:
The equation of the line that passes through the given points is ;
7y = -x + 12
Step-by-step explanation:
Here, we want to get the equation of the line that passes through the given points
The general equation form
is;
y = mx + b
where m is the slope and b is the y-intercept
Now, let us substitute the x and y coordinate values of each of the points;
for (-2,2); we have
2 = -2m + b
b = 2m + 2 •••••(i)
for F;
1 = 5m + b
b = 1-5m ••••••(ii)
Equate both b
1-5m = 2m + 2
1-2 = 2m + 5m
7m = -1
m = -1/7
Recall;
b = 2m + 2
b = 2(-1/7) + 2
b = -2/7 + 2
b = (-2 + 14)/7 = 12/7
The equation of the line is thus;
y = -1/7x + 12/7
Multiply through by 7
7y = -x + 12
Let v = - [3 1] and u=[2 1]. Write v as the sum of a vector in Span{u} and a vector orthogonal to u. (2) Find the distance from v to the line through u and origin.
The vector v can be written as the sum of a vector in Span{u} and a vector orthogonal to u as follows: v = (1/5)u + (-4/5)[1 -3].
The main answer can be obtained by decomposing the vector v into two components: one component lies in the span of vector u, and the other component is orthogonal to u. To find the vector in the span of u, we scale the vector u by the scalar (1/5) since v = - [3 1] can be written as (-1/5)[2 1]. This scaled vector lies in the span of u and can be denoted as (1/5)u.
To find the vector orthogonal to u, we subtract the vector in the span of u from v. This can be calculated by multiplying the vector u by the scalar (-4/5) and subtracting the result from v. The orthogonal component is obtained as (-4/5)[1 -3].
Thus, we have successfully decomposed vector v as v = (1/5)u + (-4/5)[1 -3], where (1/5)u lies in the span of u and (-4/5)[1 -3] is orthogonal to u.
In linear algebra, vector decomposition is a fundamental concept that allows us to express a given vector as a sum of vectors that have specific properties. The decomposition involves finding a vector in the span of a given vector and another vector that is orthogonal to it. This process enables us to analyze the behavior and properties of vectors more effectively.
In the context of this problem, the vector v is decomposed into two components. The first component, (1/5)u, lies in the span of the vector u. The span of a vector u is the set of all vectors that can be obtained by scaling u by any scalar value. Therefore, (1/5)u represents the part of v that can be expressed as a linear combination of u.
The second component, (-4/5)[1 -3], is orthogonal to u. Two vectors are orthogonal if their dot product is zero. In this case, we subtract the vector in the span of u from v to obtain the orthogonal component. By choosing the scalar (-4/5), we ensure that the resulting vector is orthogonal to u.
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PLS HELP! NEED TO RAISE GRADE! WILL GIVE BRAINLIEST AND A LOT OF POINTS!
2. A sequence can be generated by using , where and n is a whole number greater than 1.
(a) What are the first five terms in the sequence?
(b) Write an iterative rule for the sequence. Show your work.
{{{ THE BOLDED CHARACTERS SHOULD BE SMALL. }}}
A sequence can be generated by using an = a(n-1) - 5, where a1 = 100 and n is a whole number greater than 1.
a1 = 100 (given)
a2 = a1 - 5 = 100 - 5 = 95
a3 = a2 - 5 = 95 - 5 = 90
a4 = a3 - 5 = 90 - 5 = 85
a5 = a4 - 5 = 85 - 5 = 80
ANSWER for PART (a): 100, 95, 90, 85, 80
-----------------------------------------------------------------------------
an = a1 + d(n - 1)
a1 = 100d is -5 (common difference, and we know it is -5)an = 100 + -5(n - 1)
an = 100 + -5n + 5
an = 105 - 5n
ANSWER for PART (b): an = 105 - 5n
Answer:
I agree with the person above me and here give him brainliest
Step-by-step explanation:
6.01 x 0.2 =
Can anyone do this plz
Answer:
1.202
Step-by-step explanation:
please help me solve these equations for geometry :-((
The length M is 12
The measure of the angle BEC is 102
The measure of the arc AB is 128
The length PQ is 18.3
How to calculate the length MThe length M can be calculated using
M² = 8 * (8 + 10)
So, we have
M² = 144
Take the square roots
M = 12
How to calculate the BECThe measure of the angle BEC can be calculated using
BEC = 1/2 * (BC + AD)
So, we have
BEC = 1/2 * (156 + 48)
Evaluate
BEC = 102
How to calculate the ABThe measure of the arc ABcan be calculated using
AB = 180 - 2 * BC
So, we have
AB = 180 - 2 * 26
Evaluate
AB = 128
How to calculate the PQThe length PQ can be calculated using
x² = (12 + 8)² - 8²
So, we have
x² = 336
Take the square roots
x = 18.3
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what is the sum complete the equation-5 + (20)
Please help this is for a friend with co vid- 19
Answer:
am not sure but
Step-by-step explanation:
since they are similar they must have similar ratio
so 12/4 =3/1
so 3:1
4*3=12
for other sides I think
9*3 =27
and
6*3=18
y=27
x=18
Please Answer This, the question is on the picture. it needs to be a fraction
will mark brainllest if its right, no links!
(for hamster dude)
Answer:
x = 27.2 or 27 1/5
Step-by-step explanation:
cos 54° = 16/x
x = 27.2 or 27 1/5
ok soooo
when you rrly think abt it we all have kicked a pregnant lady
Answer:
Step-by-step explanation:
lol true
Determine the standard error of the estimated slope coefficient for the price of roses (point F) and whether that estimated slope coefficient is statistically significant at the 5 percent level. A. 9.42 and statistically significant since the t-statistic is greater than 2 in absolute value. B. 9.42 and statistically insignificant since the t-statistic is less than 2 in absolute value. C. 4.74 and statistically insignificant since the P-value is greater than 5 percent. D. 4.74 and statistically significant since the P-value is greater than 5 percent.
To determine the standard error of the estimated slope coefficient and its statistical significance, more information is needed, such as the t-statistic or the p-value associated with the estimated slope coefficient. The options provided do not include the necessary details to make a conclusion.
The standard error of the estimated slope coefficient measures the precision or variability of the estimated coefficient. It provides information about how much the estimated slope coefficient could vary across different samples.
The t-statistic and the p-value, on the other hand, are used to assess the statistical significance of the estimated slope coefficient. The t-statistic measures the number of standard errors the estimated coefficient is away from zero, while the p-value indicates the probability of observing a coefficient as extreme as the estimated one under the null hypothesis that the true coefficient is zero.
Without the t-statistic or p-value, it is not possible to determine the statistical significance of the estimated slope coefficient at the 5% level.
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First try was incorrect
A circle's diameter is 14 centimeters.
What is the circle's circumference (use 3.14 for pi and round to
nearest tenth)?
Answer:
Circumference = 2(pi)r
C = 2*3.14*4.0= 25.12 round 25.10 m
Step-by-step explanation:
Solve the problem. The function D(h) = 5e^-0.4h can be used to determine the milligrams D of a certain drug in a patient's bloodstream h hours after the drug has been given. How many milligrams (to two decimals) will be present after 9 hours? a. 182.99 mg b. 0.14 mg c. 1.22 mg d. 3.35 mg
B. 0.14 mg will be present after 9 hours.
The given function is D(h) = 5e^(-0.4h), which can be used to determine the milligrams D of a certain drug in a patient's bloodstream h hours after the drug has been given.
To find the milligrams after 9 hours, we need to plug in h = 9 in the function D(h) = 5e^(-0.4h).
D(h) = 5e^(-0.4h)
D(9) = 5e^(-0.4(9))
D(9) = 5e^(-3.6)
D(9) = 5 × 0.024419
D(9) = 0.1220 ≈ 0.12 mg
Hence, the answer is option (c) 1.22 mg.
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the heights of mature pecan trees are approximately normally distributes with a mean of 42 feet and a standard deviation of 7.5 feet. what proportion are between 43 and 46 feet tall.
The proportion of mature pecan trees between 43 and 46 feet tall can be calculated using the normal distribution with a mean of 42 feet and a standard deviation of 7.5 feet.
To find the proportion, we need to calculate the z-scores corresponding to the given heights and then find the area under the normal curve between those z-scores.
First, we calculate the z-score for 43 feet:
z1 = (43 - 42) / 7.5 = 0.1333
Next, we calculate the z-score for 46 feet:
z2 = (46 - 42) / 7.5 = 0.5333
Using a standard normal distribution table or a calculator, we can find the area between these two z-scores. The area corresponds to the proportion of trees between 43 and 46 feet tall.
The explanation would involve using a standard normal distribution table or a calculator to find the area under the normal curve between the z-scores of 0.1333 and 0.5333. This area represents the proportion of mature pecan trees between 43 and 46 feet tall.
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The record low temperature for a town is -13°F. Yesterday, it was 6°F. What is the
difference between the absolute values of these two temperatures?
Answer:
The difference between the absolute values of these two temperatures is 19°F.
Step-by-step explanation:
|-13| = 13
|6| = 6
13 + 6 = 19°F
Answer:
19
Explanation:
an absolute value is the value of a number without considering its sign.
thus, we can calculate the difference as such:
6 - (- 13) = 6 + 13 = 19
the difference between the absolute values of these two temperatures is 19.
i hope this helps! :D
Find the area of the triangle below.
Answer:
20.25
Step-by-step explanation:
Just multiply the base and height then divide the results in half.
Hope this helps!
find the value of a and b.
Answer:
2a°+2a°=180°[opposite angle of cyclic quadrilateralis 180°]
4a°=180
a=180°/4
a=45°
4b+2b=180°[similarly]
6b=180°
b=180°/6
b=30
Need help with this problem
C A- WHERE A) SUPPOSE A € M2x2 (R) A = [a A = AND det (A) = 0 ( STATE A FORMULA FOR VERIFY THAT iT WORKS. (i) USE YOUR FORMULA TO FIND 3 A= WHEN 5 . 27 Ut a AY SHOW ® SUPPOSE B a det (A). - [] Show: det B =
To verify that a matrix A satisfies the conditions A € M2x2(R), A = [a b; c d], and det(A) = 0, we can use the formula for the determinant of a 2x2 matrix:
det(A) = ad - bc
In this case, since det(A) = 0, we have:
ad - bc = 0
This formula allows us to check whether a given matrix satisfies the given conditions.
To find three matrices A when a = 5 and det(A) = 27, we can use the formula:
ad - bc = 27
Let's assume b = 1, c = 0, and d = 27/a.
Substituting these values into the formula, we get:
5 * (27/a) - 1 * 0 = 27
135/a = 27
a = 135/27
a = 5
Therefore, one possible matrix A that satisfies the conditions is:
A = [5 1; 0 27/5]
Similarly, we can find two more matrices by choosing different values for b, c, and d, as long as the determinant condition is satisfied.
Now, let's suppose B is a matrix such that det(B) = det(A):
B = [p q; r s]
To show that det(B) = det(A), we can equate their determinants:
det(B) = det(A)
ps - qr = ad - bc
Since we already know that ad - bc = 0, we can conclude that:
ps - qr = 0
This equation shows that the determinant of B is also zero, satisfying the condition det(B) = 0.
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Please help I need this quickly
Answer:
31 degrees
Step-by-step explanation:
1. since angle x and angle y are congruent, and segment xw and segment yw are congruent, you can assume that angle xzw and angle wzy are also congruent.
2. set angle xzw and angle wzy equal to each other
8x-1 = 5x+11
3. combine like terms
3x = 12
4. simplify to find the value of x
x = 4
5. plug x into the equation to find the degree of angle wzy
5(4)+11
20+11
=31 degrees
In a recent year, a research organization found that 517 of 766 surveyed male Internet users use social networking. By contrast 692 of 941 female Internet users use social networking. Let any difference refer to subtracting male values from female values. Complete parts a through d below. Assume that any necessary assumptions and conditions are satisfied. c) What is the standard error of the difference? (Round to four decimal places as needed.) d) Find a 95% confidence interval for the difference between these proportions. 00 (Round to three decimal places as needed.) In a recent year, a research organization found that 517 of 766 surveyed male Internet users use social networking. By contrast 692 of 941 female Internet users use social networking. Let any difference refer to subtracting male values from female values. Complete parts a through d below. Assume that any necessary assumptions and conditions are satisfied. c) What is the standard error of the difference? (Round to four decimal places as needed.) d) Find a 95% confidence interval for the difference between these proportions. 00
a) The proportion of male Internet users who use social networking is approximately 0.6747, and the proportion of female Internet users who use social networking is approximately 0.7358.
b) The difference in proportions is approximately -0.0611.
c) The standard error of the difference is approximately 0.0181.
d) The 95% confidence interval for the difference between these proportions is (-0.096, -0.026).
To calculate the standard error of the difference and find a 95% confidence interval for the difference between the proportions, we can use the formulas for proportions and their differences.
Let [tex]p_1[/tex] be the proportion of male Internet users who use social networking, and [tex]p_2[/tex] be the proportion of female Internet users who use social networking.
a) Proportion for male Internet users: [tex]p_1[/tex] = 517/766 = 0.6747
Proportion for female Internet users: [tex]p_2[/tex] = 692/941 = 0.7358
b) Difference in proportions: [tex]p_1 - p_2[/tex] = 0.6747 - 0.7358 = -0.0611
c) The standard error of the difference (SE) can be calculated using the formula:
[tex]SE = \sqrt{(p_1(1-p_1)/n_1) + (p_2(1-p_2)/n_2)}[/tex]
Where [tex]n_1[/tex] and [tex]n_2[/tex] are the sample sizes for male and female Internet users, respectively.
For male Internet users: [tex]n_1[/tex] = 766
For female Internet users: [tex]n_2[/tex] = 941
Plugging in the values, we have:
[tex]SE = \sqrt{(0.6747(1-0.6747)/766) + (0.7358(1-0.7358)/941)}[/tex]
d) To find the 95% confidence interval for the difference between these proportions, we can use the formula:
[tex]CI = (p_1 - p_2) \± (Z * SE)[/tex]
Where Z is the critical value corresponding to a 95% confidence level. For a large sample size, Z is approximately 1.96.
CI = (-0.0611) ± (1.96 * SE)
CI = -0.0611 ± 0.0355
CI = (-0.096, -0.026)
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I need help pls and no files ok pls no files
Answer:
$2,725
Step-by-step explanation:
The maximum number of days is 7.
The cost per days is $375.
The cost for 7 days is 7 * $375 = $2,625.
The owner applies a $100 fee for cleaning which must be added to the cost of the days.
$2,625 + $100 = $2,725
The greatest value for the range is the greatest cost there can be which is $2,725.
What is the distance to the nearest tenth A unit, between point M (-8,-1) and point N (3,5)?
Answer: 12.5
Step-by-step explanation:
Please help me with this I am stuck
Answer:
450 cm ^3
Step-by-step explanation:
Find the volume of a prism of altitude "h" with an equilateral triangular base of side "S" BY integration.
The volume of the prism with an equilateral triangular base of side S and altitude h is (S * h^2 * sqrt(3))/4.
To find the volume of a prism with an equilateral triangular base using integration, we can divide the prism into infinitesimally small slices parallel to the base and integrate their volumes.
Consider an infinitesimally thin slice located at a distance "y" from the base. The length of this slice is equal to the length of the base, S. The width of the slice at distance "y" can be determined by considering the height of the equilateral triangle at that distance, which is given by h - (h/S) * y.
The volume of this slice is then given by the product of its length, width, and infinitesimal thickness dy, which is S * [h - (h/S) * y] * dy.
To find the total volume, we integrate this expression from y = 0 to y = h:
V = ∫[0,h] S * [h - (h/S) * y] dy.
Evaluating this integral gives us the volume of the prism:
V = S * [h * y - (h/S) * (y^2/2)] evaluated from y = 0 to y = h.
Simplifying this expression yields:
V = (S * h^2 * sqrt(3))/4.
Therefore, the volume of the prism with an equilateral triangular base of side S and altitude h is (S * h^2 * sqrt(3))/4.
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If the n objects in a permutation problem are not all distinguishable, that is, if there are n1 objects of type 1, n2 objects of type 2, and so on, for r different types, then the number of distinguishable permutations is shown below.
n!n1!n2!…nr!
Find the number of distinguishable permutations of the letters in each word below.
(a) initial
n!/3!1!1!1!1!=
(b) Hawaii
n!/1!2!1!2!=
(c) decreed
n!/2!3!1!1!=
(a) There are 840 distinguishable permutations of the letters in the word "initial." (b) There are 180 distinguishable permutations of the letters in the word "Hawaii." (c) There are 420 distinguishable permutations of the letters in the word "decreed."
(a) For the word "initial," we have a total of 7 letters, with 2 "I"s, and 1 occurrence of each of the remaining letters. Applying the formula, we get:
n! / (3!1!1!1!1!) = 7! / (3!1!1!1!1!) = (7 × 6 × 5 × 4 × 3 × 2 × 1) / (3 × 2 × 1 ×1 × 1 × 1 × 1) = 840
(b) For the word "Hawaii," we have a total of 6 letters, with 1 "H," 2 "A"s, and 2 "I"s. Applying the formula, we get:
n! / (1!2!1!2!) = 6! / (1!2!1!2!) = (6 × 5 × 4 × 3 × 2 × 1) / (1 × 2 × 1 × 2 × 1 × 1) = 180
(c) For the word "decreed," we have a total of 7 letters, with 2 "E"s, 3 "D"s, and 1 occurrence of each of the remaining letters. Applying the formula, we get:
n! / (2!3!1!1!) = 7! / (2!3!1!1!) = (7 × 6 × 5 × 4 × 3 × 2 × 1) / (2 × 1 × 3 × 2 × 1 × 1 × 1) = 420
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Find the distance between the points (3, -8) and (8,4).
Answer:
13
Step-by-step explanation:
Answer:
13
Step-by-step explanation:
Hello There!
We can calculate the distance between two points using the distance formula
[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
where the x and y values are derived from the coordinates in which you are trying to find the distance between
The points we need to find the distance between is (3,-8) and (8,4)
So we plug the x values and y values into the formula
[tex]d=\sqrt{(8-3)^2+(4-(-8)^2} \\8-3=5\\4-(-8)=12\\d=\sqrt{5^2+12^2} \\5^2=25\\12^2=144\\144+25=169\\\sqrt{169} =13[/tex]
so we can conclude that the distance between the two points is 13 units
We formally define the length function f(w) of a string w = ww2...W), (where ne N, and Vi= 1,..., n W; € 2) as 1. if w = €, then f(w) = 0. 2. if w = au for some a € and some string u over 2, then f(x) = 1 + f(u). 1, ..., Prove using proof by induction: For any strings w = wW2...Wy. (where n € N, and Vi W: € 9), f(w) = n.
The length function f(w) of a string w = w₁w₂...W), where n ∈ N and Vi ∈ W: € 9, is equal to n.
The length function f(w) is defined recursively based on the structure of the string w. In the base case, if w is an empty string (ε), the length is defined as 0. In the recursive case, if w can be written as au, where a is a character from the alphabet and u is a string over the alphabet Σ, then the length is defined as 1 plus the length of u.
To prove that for any string w =w₁w₂...wy, where n ∈ N and Vi ∈ W: € 9, the length function f(w) is equal to n, we will use a proof by induction.
Base case:For w = ε (an empty string), we have f(ε) = 0, which satisfies the condition when n = 0.
Inductive step:Assume that for any string w = w₁w₂...wn, where n ∈ N and Vi ∈ W: € 9, the length function f(w) = n.
Now, consider a string w' = w₁w₂...wn+1. By the recursive definition, we can write w' as au, where a is the last character wn+1 and u is the string w₁w₂...wn. From our assumption, we know that f(u) = n.
Therefore, f(w') = 1 + f(u) = 1 + n = n + 1.
Since we have established that for any string w = w₁w₂...wy, where n ∈ N and Vi ∈ W: € 9, the length function f(w) = n, we can conclude that f(w) = n.
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Calculate (4 + 10i)^2
By applying the the FOIL method, which stands for First, Outer, Inner, Last we obtained the result -84 + 80i for (4 + 10i)^2.
To calculate (4 + 10i)^2, we can:
First, we multiply the first terms of each binomial:
(4 + 10i) * (4 + 10i) = 16 + 40i
Next, we multiply the outer terms of each binomial:
(4 + 10i) * (4 + 10i) = 16 + 40i
Then, we multiply the inner terms of each binomial:
(4 + 10i) * (4 + 10i) = 16 + 40i
Finally, we multiply the last terms of each binomial:
(4 + 10i) * (4 + 10i) = 100i^2
We know that i^2 is equal to -1, so we can substitute that in:
100(-1) = -100
Putting it all together, we get:
(4 + 10i)^2 = 16 + 40i + 40i + (-100)
= -84+80i
Therefore, by applying this method for squaring a complex number, we obtained the result -84 + 80i for (4 + 10i)^2.
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A quality control company was hired to study the length of meter sticks produced by a certain company. The team carefully measured the length of many meter sticks, and the distribution seems to be severely skewed to the right with a mean of 99.84 cm and a standard deviation of 0.2 cm.
a) What is the probability of finding a meter stick with a length of more than 100.04 cm? ____
b) What is the probability of finding a group of 42 meter sticks with a mean length of less than 99.82 cm?_____
c) What is the probability of finding a group of 50 meter sticks with a mean length of more than 99.87 cm? _____
d) What is the probability of finding a group of 28 meter sticks with a mean length of between 99.82 and 99.86 cm? ______
e) For a random sample of 32 meter sticks, what mean length would be at the 92nd percentile? ______
a) The probability of finding a meter stick with a length of more than 100.04cm is 0.44013.
b) The probability of finding a group of 42 meter sticks with a mean length of less than 99.82 cm is 0.65866.
c) The probability of finding a group of 50 meter sticks with a mean length of more than 99.87 cm is 0.44013.
d) The probability of finding a group of 28 meter sticks with a mean length of between 99.82and 99.86 cm is 0.11974.
e) The mean length that would be at the 92nd percentile for a random sample of 32 meter sticks is 99.89714 cm.
How is this so ?a) The probability of finding a meter stick with a length of more than 100.04cm is
P(X > 100.04 ) =1 - P(X <= 100.04)
= 1- Φ((100.04 - 99.84) / 0.2)
= 1 - Φ(0.12)
= 1 - 0.55987
= 0.44013
b) The probability of finding a group of 42 meter sticks with a mean length of less than 99.82 cm is
P(¯X < 99.82) = 1 - P(X >= 99.82)
= 1 - Φ((99.82 - 99.84) / 0.2 / √42)
= 1 - Φ(-0.1)
= 1 - 0.34134
= 0.65866
c) The probability of finding a group of 50 meter sticks with a mean length of more than 99.87 cm is
P(X > 99.87) = 1 - P(X <= 99.87)
= 1 - Φ((99.87 - 99.84) / 0.2 / √50)
= 1 - Φ(0.15)
= 0.44013
d) The probability of finding a group of 28 meter sticks with a mean length of between 99.82 and 99.86 cm is
P(99.82 < X < 99.86) = Φ ((99.86 - 99.84)/ 0.2 / √28) - Φ((99.82 - 99.84) / 0.2/ √28)
= Φ(0.15) - Φ(0.12)
= 0.55987 - 0.44013
= 0.11974
e) The mean length that would be at the 92nd percentile for a random sample of 32-meter sticks is
X₉₂ = μ + z₉₂ σ / √n
= 99.84 + z₉₂ (0.2) / √32
= 99.84 + 1.85 (0.2) / √32
= 99.84 + 0.05714
= 99.89714
Therefore, the mean length that would be at the 92nd percentile for a random sample of 32 meter sticks is 99.89714 cm.
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