3. Pepsi puts 355 ml of soda in a can. How many drops is this?

Answer:

Looooolllllllllllll

Explanation:

What is the question bro

Answer:

False

Explanation:

When weak bases dissociate, an equilibrium is established rather than dissociating 100%. So OH- and metal ions are partially ionized.

Answer:

Dominant

Explanation:

hope this help

Answer:

Cl₂ is the limiting reactant.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

N₂ + 3Cl₂ —> 2NCl₃

From the balanced equation above,

1 L of N₂ reacted with 3 L of Cl₂.

Finally, we shall determine the limiting reactant. This can be obtained as follow:

From the balanced equation above,

1 L of N₂ reacted with 3 L of Cl₂.

Therefore, 134 L of N₂ will react with = 134 × 3 = 402 L of Cl₂.

From the calculation made above, we can see that a higher volume (i.e 402 L) of Cl₂ than what was given (i.e 99 L) is needed to react completely with 134 L of N₂.

Therefore, Cl₂ is the limiting reactant and N₂ is the excess reactant.

Answer:

Assuming that the atmospheric pressure is standard, the temperature will rise steadily until it reaches 100°C

Answer:

[tex]\lambda =4.33x10^{-12}m=4.33pm[/tex]

Explanation:

Hello there!

In this case, since the speed, wavelength and mass of an electron are related via the the Broglie wavelength:

[tex]\lambda =\frac{h}{m*v}[/tex]

Thus, by plugging in the mass of the electron and the Planck's constant, we obtain the following wavelength:

[tex]\lambda =\frac{6.626x10^{-34}J*s}{9.11x10^{-31}kg*1.68x10^{8}m/s}\\\\\lambda =4.33x10^{-12}m=4.33pm[/tex]

Best regards!

Answer:

2.87 gram

N2 is the limiting agent

Explanation:

We will find out if there is sufficient N2 and h2 to produce NH3

a) For 2.36 grams of N2

Molar mass of N2 = 28.02

Number of moles of N2 in 2.36 grams = 2.36/28.02

Mass of NH3 = 17.034 g

Now NH3 produced form 2.36 grams of N2 =  

2.36/28.02 * 2 * 17.034 = 2.87 g NH3

b) For 1.52 g of H2  

NH3 produced = 1.52/2.016 * (2/3) * 17.034 = 8.56

N2 Is not enough to produce 2.87 g of NH3 and also H2 is not enough to make 8.56 g of NH3.  

N2 is the limiting agent as it has smaller product mass

Answer:

Metalloid ; semiconductor

Explanation:

Answer:

True

Explanation:

All metals do rust but at different rates. Gold, platinum, and silver can rust if but at different rates. It can take time for it to rust, if you clean your metals, it won't rust, it'll take awhile before it rusts if you keep cleaning them.

Hopefully this helps :3 sorry if wrong :( plz mark brainiest if correct :D your bootiful/handsome! Have a great day luv <3

-Bee~

We would need to measure out approximately 44.84 grams of C5Hg to have 0.172 mol.

To determine the grams of C5Hg needed to have 0.172 mol, we need to use the molar mass of C5Hg and the given amount in moles. The molar mass of a compound represents the mass of one mole of that compound.

The molar mass of C5Hg can be calculated by summing the atomic masses of all the atoms in the compound:

C5Hg: (5 * atomic mass of C) + (1 * atomic mass of Hg)

Using the atomic masses from the periodic table:

Atomic mass of C = 12.01 g/mol

Atomic mass of Hg = 200.59 g/mol

Molar mass of C5Hg = (5 * 12.01 g/mol) + (1 * 200.59 g/mol) = 60.05 g/mol + 200.59 g/mol = 260.64 g/mol

Now, we can calculate the grams of C5Hg needed for 0.172 mol using the mole-to-mass conversion:

Grams of C5Hg = Moles of C5Hg * Molar mass of C5Hg

Grams of C5Hg = 0.172 mol * 260.64 g/mol = 44.84 grams (rounded to two decimal places)

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Answer:There is a iin dipole attraction between two hydrogen atom

Explanation:

The same atoms have the ion dipole attraction between them the same atoms repel each other

Answer:

Because of the artificial lights influencing the dark night, turning it into a grey.

The amount of copper in moles in the 27.5 g pure copper sheet is approximately 0.433 moles.

To calculate the amount of copper in moles in a pure copper sheet, we need to use the molar mass of copper and the given mass of the sheet.

The molar mass of copper (Cu) is approximately 63.55 g/mol. This value represents the mass of one mole of copper atoms.

Given that the mass of the pure copper sheet is 27.5 g, we can calculate the number of moles using the following formula:

moles = mass / molar mass

Substituting the values:

moles = 27.5 g / 63.55 g/mol

moles ≈ 0.433 mol

Therefore, the amount of copper in moles in the 27.5 g pure copper sheet is approximately 0.433 moles.

To arrive at this result, we divided the given mass of the sheet (27.5 g) by the molar mass of copper (63.55 g/mol). This calculation allows us to convert the mass of the sheet into the corresponding number of moles of copper.

The result tells us that the 27.5 g pure copper sheet contains approximately 0.433 moles of copper atoms. This conversion to moles is useful in various chemical calculations and allows for easier comparison and analysis of quantities on a molecular scale.

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Answer:

Blood capillaries

Explanation:

The walls of capillaries are just one cell thick. Capillaries therefore allow the exchange of molecules between the blood and the body's cells - molecules can diffuse across their walls. This exchange of molecules is not possible across the walls of other types of blood vessel.

Answer:

The pigment that causes leaves to be green is chlorophyll. ... As chlorophyll goes away, other pigments start to show their colors. This is why leaves turn yellow or red in fall. In fall, plants break down and reabsorb chlorophyll, letting the colors of other pigments show through.

Answer:

heat

Explanation:

Answer:

Thermal Energy

Explanation:

Answer:0.56L

Explanation:Molar mass of O2=32

N=0.8/32

N=0.025
V=0.025 x 22.4=0.56L

Because the space is ultimate thermos.

there are 6 O atoms suvdjwndje

Answer:

420 miles

Explanation:

From the question given above, the following data were obtained:

Time = 3.5 hours

Speed = 120 mi/h

Distance =?

Speed is defined as the distance travelled per unit time. Mathematically, it is expressed as:

Speed = distance / time

With the above formula, we can obtain the distance travelled by the plane as follow:

Time = 3.5 hours

Speed = 120 mi/h

Distance =?

Speed = distance / time

120 = distance / 3.5

Cross multiply

Distance = 120 × 3.5

Distance = 420 miles

Thus, the distance travelled by the plane is 420 miles

The different types of energy include thermal energy, radiant energy, chemical energy, nuclear energy, electrical energy, motion energy, sound energy, elastic energy and gravitational energy.

you could use any of these.

Answer: Chemical energy is energy stored in the bonds of atoms and molecules. ...

Mechanical energy is energy stored in objects by tension. ...

Nuclear energy is energy stored in the nucleus of an atom—the energy that holds the nucleus together.

Explanation:

Answer:

Producer

Explanation:

I took the test :)

Answer:

6C2H2(g) + 16H2O(g) + 3CO2(g) ------> 6Ca(OH)2(s) +  5CH2CHCO2H(g)

Explanation:

The reaction has the first step as the reaction of calcium carbide with water to yield acetylene and calcium hydroxide as follows;

6CaC2(s) + 12H2O(g) -----> 6C2H2(g) + 6Ca(OH)2(s)

In the second step, acetylene, carbon dioxide and water react to form acrylic acid as follows;

6C2H2(g) + 4H2O(g) + 3CO2(g) ------>  5CH2CHCO2H(g)

The overall reaction equation is as follows;

6C2H2(g) + 16H2O(g) + 3CO2(g) ------> 6Ca(OH)2(s) +  5CH2CHCO2H(g)

Answer:

Is the question not supposed to be what is the partial pressure of Nitrogen not Sodium

Answer: The change in time for the first quarter is  1.39 seconds.

The change in time for the second quarter is 0.78 seconds.

The change in time for the third quarter is 0.64 seconds.

The change in time for the fourth quarter is 0.54 seconds.  

Explanation: took info from my data and completed lab

Step 5: Measure the Speed of the Toy Car on the Higher Track

Calculate the change in time for each quarter of the track. Record the change in time in Table E of your Student Guide.

Also added the other calculations -

Calculate the average time the car took to reach each checkpoint. Record the average time in Table D of your Student Guide.

The average time to the first quarter checkpoint is 1.39 seconds.  

The average time to the second quarter checkpoint is 2.18 seconds.

The average time to the third quarter checkpoint is 2.82 seconds.

The average time to the finish line is 3.36 seconds.

Calculate the speed of the car at each checkpoint by dividing the distance between each checkpoint, in meters, by the change in time. Record your answers in Table E of your Student Guide.

The speed at the first quarter checkpoint is 1.09 m/s.  

The speed at the second quarter checkpoint is 1.95 m/s.

The speed at the third quarter checkpoint is 2.37 m/s.

The speed at the finish line is 2.80 m/s.

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