An experiment consists of tossing 3 fair (not weighted) coins, except one of the 3 coins has a head on both sides. Compute the probability of obtaining exactly 3 heads The probability of obtaining exactly 3 heads is
The probability of obtaining exactly 3 heads is 5/16.
We can find the probability of obtaining exactly 3 heads by considering the different ways in which this can happen.
First, suppose we toss the two normal coins and the biased coin with the two heads.
There is a probability of getting heads on each toss of the biased coin: 1/2
A probability of getting heads on each toss of the normal coins: 1/2
Therefore, the probability of getting exactly 3 heads in this case is:
(1/2) * (1/2) * (1/2) = 1/8
Now suppose we toss the two normal coins and the biased coin with the two heads, but we choose to use the biased coin twice. In this case, we need to get two heads in a row with the biased coin, and then a head with one of the normal coins.
The probability of getting two heads in a row with the biased coin is: 1/2, and the probability of getting a head with one of the normal coins is: 1/2. Therefore, the probability of getting exactly 3 heads in this case is:
(1/2) * (1/2) * (1/2) = 1/8
Finally, suppose we use the biased coin and one of the normal coins twice each. In this case, we need to get two heads in a row with the biased coin, and then two tails in a row with the normal coin. The probability of getting two heads in a row with the biased coin is: 1/2,
and the probability of getting two tails in a row with the normal coin is :
(1/2) * (1/2) = 1/4.
Therefore, the probability of getting exactly 3 heads in this case is:
(1/2) * (1/2) * (1/4) = 1/16
Adding up the probabilities from each case, we get:
1/8 + 1/8 + 1/16 = 5/16
Therefore, the probability of obtaining exactly 3 heads is 5/16.
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Compute the first 4 non-zero terms (if any) of the two solutions
linearly independent power series form centered on
zero for the Hermite equation of degree 2, that is y''-2xy'+4y=0
The power series solutions for the Hermite equation of 2 are zero for the first four terms of the given equation.
Equation = y''-2xy'+4y=0
The solutions can be expressed as power series using the Hermite equation of degree 2 can be calculated as:
y = ∑(n=0 to ∞) [tex]a_n x^{n}[/tex]
where [tex]a_n[/tex] is the coefficient of the nth term and x is the variable.
Differentiating y with regard to x,
y = ∑(n=0 to ∞) [tex]a_n x^{n-1}[/tex]
Double integrating the y with respect to x:
y'' = ∑(n=0 to ∞) [tex]a_nn(n-1)x^{n-2}[/tex]
Substituting the above equation in the Hermite equation
∑(n=0 to ∞) [tex]a_nn(n-1)x^{n-2}[/tex] - 2x∑(n=0 to ∞) [tex]a_n x^{n-1}[/tex] + 4∑(n=0 to ∞) [tex]a_n x^{n}[/tex] = 0
∑(n=0 to ∞)[tex][a_n(n(n-1) - 2n + 4)] x^{n}[/tex] = 0
Taking the coefficients of each term as zero:
[tex]a_n[/tex](n(n-1) - 2n + 4) = 0
The first four non-zero terms:
If n = 0,
[tex]a_o[/tex](0(0-1) - 2(0) + 4) = 0
[tex]a_o[/tex](4) = 0
[tex]a_o[/tex] = 0
If n = 1,
[tex]a_1[/tex](1(1-1) - 2(1) + 4) = 0
[tex]a_1[/tex](2) = 0
[tex]a_1[/tex] = 0
If n= 2,
[tex]a_2[/tex](2(2-1) - 2(2) + 4) = 0
[tex]a_2[/tex](2) = 0
[tex]a_2[/tex]= 0
If n = 3,
[tex]a_3[/tex] (3(3-1) - 2(3) + 4) = 0
[tex]a_3[/tex] (2) = 0
[tex]a_3[/tex] = 0
Therefore we can conclude that the power series solutions for the Hermite equation of 2 are zero.
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7.
A customer went to a garden shop and bought some potting soil for $17.50 and 4 shrubs. The total bill was $53.50. Write and solve an equation to find the price of each shrub.
A. 4p + $17.50 = $53.50; p = $9.00
B. 4p + 17.5p = $53.50; p = $2.49
C. 4p + $17.50 = $53.50; p = $11.25
D. 4(p + $17.50) = $53.50; p = $4.00
Answer: A. 4p + $17.50 = $53.50; p = $9.00
1: 17.50+4p= Nothing further can be done with this topic. Please check the expression entered or try another topic.
17.5 + 4 p
2: 4p=53.50-17.50= 4p=53.50-17.50
Step-by-step explanation: 9
The total bill: $53.50
17.50 + 4 x = 53.50
4 x = 53.50 - 17.50
4 x = 36
x = 36 : 4
x = $9
Answer: The price of each shrub is $9.
...............................................................................................................................................
Answer:
$9
Step-by-step explanation:
Let be the price of each shrub.
4 shrubs at each costs dollars
Potting soil is $17.50
Hence, total cost is the expression
We know that total bill is $53.50, so we can equate it to the expression:
This equation can be solved for to find cost of each shrub.
Solving for gives us:
So price of each shrub is $9
What is the approximate surface area of this right prism with triangular bases?
Answer:
394.2 ft
Step-by-step explanation:
7.8(9)=70.2
This is the measurement for the two triangular sides
9(12)(3)=324 This is the measurement for the three triangular sides
70.2 +324 = 394.2 APPROX
help pls plssssss now
Answer:
i would say B but i dont know
Step-by-step explanation:
The expression shown below was generated using a graphing calculator. Solve the expression and answer in correct scientific notation.
(4.5E6)(2.3E7)
A) 1.035×1014
B) 1.035×1013
C) 6.8×1013
D) 2.2×1013
what angle is opposite the longest side?
I will mark as brainliest
Answer:
75
Step-by-step explanation:
Answer:
the angle that is 75 degrees
Step-by-step explanation:
Because the longest side is always opposite of the largest angle and the smallest side is always opposite of the smallest angle.
PLEASE HELP! What does x equal?
Step-by-step explanation:
(FE+BC)/2=<FDE
<FDE=<BDC
it is basically the average of x and 70.
(x+70)/2=104
x=138
Hope that helps :)
Answer:
The answer is probly 70 degrees
i might be wrong
i just hope this works
good luck
bob is pulling a 30 kgkg filing cabinet with a force of 200 nn , but the filing cabinet refuses to move. the coefficient of static friction between the filing cabinet and the floor is 0.80.
Bob is exerting a force of 200 N on a 30 kg filing cabinet, but it remains stationary due to the static friction between the cabinet and the floor. The coefficient of static friction is given as 0.80.
The static frictional force acts between two surfaces in contact when there is no relative motion between them. The magnitude of static friction can be determined using the equation F_static = μ_static * N, where μ_static is the coefficient of static friction and N is the normal force.
In this scenario, Bob is applying a force of 200 N to the filing cabinet. In order to overcome the static friction and set the cabinet in motion, the applied force must be greater than or equal to the maximum static frictional force. The maximum static frictional force can be calculated by multiplying the coefficient of static friction with the normal force.
Since the cabinet is stationary, the applied force of 200 N is not sufficient to overcome the maximum static frictional force. The maximum static frictional force can be determined as F_static = μ_static * N = 0.80 * (30 kg * 9.8 m/s^2) = 235.2 N.
As the applied force of 200 N is less than the maximum static frictional force of 235.2 N, the filing cabinet remains stationary. Bob would need to apply a force greater than 235.2 N to overcome the static friction and set the cabinet in motion.
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Find the general solution to the differential equation dy xoay + 3y = x2 dx b) Find the particular solution to the differential equation dy dx = (y + 1)(3x2 – 1) E subject to the condition that y = 0 at x = 0 c) Find the particular solution to the differential equation dy dx = y X- subject to the condition that y = 2 at x = 1
a) The differential equation is y = [tex]e^{(4x)/x}[/tex] + 3 b) The particular solution is y = [tex]e^{x^3 - x}[/tex] - 1 c) The particular solution to the differential equation is given by the equations is y = 2x or y = -2x.
a) To find the general solution to the differential equation:
x(dy/dx) + 3y = [tex](e^{4x})/{x^2}[/tex]
We can start by rearranging the equation:
dy/dx = [[tex](e^{4x})/{x^2}[/tex] - 3y]/x
This equation is linear, so we can use an integrating factor to solve it. The integrating factor is given by:
μ(x) = e^(∫(1/x) dx) = [tex]e^{ln|x|}[/tex] = |x|
Multiplying both sides of the equation by the integrating factor:
|x| * dy/dx - 3|xy| = [tex]e^{(4x)/x}[/tex]
Now, let's integrate both sides with respect to x:
∫(|x| * dy/dx - 3|xy|) dx = ∫([tex]e^{(4x)/x}[/tex]) dx
Using the properties of absolute values and integrating term by term:
∫(|x| * dy) - 3∫(|xy|) dx = ∫([tex]e^{(4x)/x}[/tex]) dx
Integrating each term separately:
∫(|x| * dy) = ∫([tex]e^{(4x)/x}[/tex]) dx + 3∫(|xy|) dx
To integrate ∫(|x| * dy), we need to know the form of y. Let's assume y = y(x). Integrating ∫[tex](e^{4x)/x}[/tex] dx gives us a natural logarithm term.
Integrating 3∫(|xy|) dx can be done using different cases for the absolute value of x.
By solving these integrals and rearranging the equation, you can find the general solution for y(x).
b) To find the particular solution to the differential equation:
dy/dx = (y + 1)(3x² - 1)
subject to the condition that y = 0 at x = 0.
We can solve this equation using separation of variables. Rearranging the equation:
dy/(y + 1) = (3x² - 1) dx
Now, let's integrate both sides:
∫(dy/(y + 1)) = ∫((3x² - 1) dx)
The left-hand side can be integrated using the natural logarithm function:
ln|y + 1| = x³ - x + C1
Solving for y, we have:
[tex]y + 1 = e^{x^3 - x + C1}\\y = e^{x^3 - x + C1} - 1[/tex]
Using the initial condition y = 0 at x = 0, we can find the particular solution. Substituting these values into the equation:
0 = [tex]e^{0 - 0 + C1}[/tex] - 1
1 = [tex]e^{C1}[/tex]
C1 = ln(1) = 0
Therefore, the particular solution is:
y = [tex]e^{x^3 - x}[/tex] - 1
c) To find the particular solution to the differential equation:
x(dy/dx) - y = y
subject to the condition that y = 2 at x = 1.
We can simplify the equation:
x(dy/dx) = 2y
Now, let's separate variables and integrate:
(1/y) dy = (1/x) dx
Integrating both sides:
ln|y| = ln|x| + C2
Simplifying further:
ln|y| = ln|x| + C2
ln|y| - ln|x| = C2
ln(|y/x|) = C2
|y/x| = [tex]e^{C2}[/tex]
Since we are given the initial condition y = 2 at x = 1, we can substitute these values into the equation:
|2/1| = [tex]e^{C2}[/tex]
2 = [tex]e^{C2}[/tex]
C2 = ln(2)
Therefore, the particular solution is:
|y/x| = [tex]e^{ln(2)}[/tex]
|y/x| = 2
Solving for y, we have two cases:
y/x = 2
y = 2x
y/x = -2
y = -2x
So, the particular solution to the differential equation is given by the equations:
y = 2x or y = -2x.
The complete question is:
a) Find the general solution to the differential equation
x dy/dx + 3y = (e⁴ˣ)/(x²)
b) Find the particular solution to the differential equation dy/dx = (y + 1)(3x² - 1)
subject to the condition that v = 0 at x = 0
c) Find the particular solution to the differential equation
x dy/dx (y) = y
subject to the condition that y = 2 at x = 1
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determine the inteerval on which the following function is convave upor concave down. identify any inflection points. f(x)= x^4-4x^3 3
To determine the intervals on which the function [tex]f(x) = x^4 - 4x^3 + 3[/tex] is concave up or concave down, we need to find the second derivative of the function and analyze its sign.
First, let's find the first derivative of f(x):
[tex]f'(x) = 4x^3 - 12x^2[/tex]
Next, let's find the second derivative of f(x) by taking the derivative of f'(x):
[tex]f''(x) = 12x^2 - 24x[/tex]
To determine the intervals of concavity, we need to find where f''(x) is positive (concave up) or negative (concave down). We can do this by analyzing the sign of f''(x).
Now, let's find the values of x for which f''(x) = 0, as these will give us potential inflection points:
[tex]12x^2 - 24x = 0[/tex]
12x(x - 2) = 0
x = 0 or x = 2
The potential inflection points are x = 0 and x = 2.
To analyze the concavity of the function, we'll use test points within the intervals between the potential inflection points and beyond.
For x < 0, let's choose x = -1 as a test point:
[tex]f''(-1) = 12(-1)^2 - 24(-1) = 12 + 24 = 36[/tex]
Since f''(-1) = 36 > 0, the function is concave up for x < 0.
For 0 < x < 2, let's choose x = 1 as a test point:
[tex]f''(1) = 12(1)^2 - 24(1) = 12 - 24 = -12[/tex]
Since f''(1) = -12 < 0, the function is concave down for 0 < x < 2.
For x > 2, let's choose x = 3 as a test point:
[tex]f''(3) = 12(3)^2 - 24(3) = 108 - 72 = 36[/tex]
Since f''(3) = 36 > 0, the function is concave up for x > 2.
In summary:
The function is concave up for x < 0 and x > 2.
The function is concave down for 0 < x < 2.
The inflection points are x = 0 and x = 2.
I hope this clarifies the concavity and inflection points of the given function. Let me know if you have any further questions!
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A coastline recedes at a rate of 3cm per year. How much of the coastline dissappears after 4 years?
Answer:
12 cm of coastline
Step-by-step explanation:
Multiply the years (factor) by the receding amount, 3cm, (constant) BAM answer.
What does the best fit line estimate for the y value when x is 100
The best fit line estimate for the y value when x is 100 in this case is 205.
What is Equation?Two or more expressions with an Equal sign is called as Equation.
To determine what the best fit line estimate for the y value is when x is 100.
Assuming that you have a linear regression model with the equation y = mx + b, where "m" is the slope and "b" is the y-intercept, you would need to know the values of "m" and "b" to estimate the y value for a given x value.
If you have these values, you can substitute x = 100 into the equation and solve for y.
The resulting value will be the estimated y value for the given x value.
If the equation of the best fit line is y = 2x + 5, then the estimated y value when x is 100 would be:
y = 2(100) + 5
y = 200 + 5
y = 205
Hence, the best fit line estimate for the y value when x is 100 in this case is 205.
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Which dot plot represents the data in this frequency table?
Number 3 4 5 7 8
Frequency 3 2 4 2 3
Answer:
Im so sorry im late! The answer is A i just took the quiz!
Step-by-step explanation:
The correct dot plot is given in option 1.
What is a dot plot?Any data that may be shown as dots or tiny circles is called a dot plot. Given that the height of the bar created by the dots indicates the numerical value of each variable, it is comparable to a bar graph or a simple histogram. Little amounts of data are shown using dot plots.
As per the given data:
There are 4 options, with each option represented by a diagram also the number and frequency table is given
Number: 3 4 5 7 8
Frequency: 3 2 4 2 3
We can find the correct diagram of the dot plot by observing the number of cross against each value of the number on the line and then matching the obtained value with the given number and frequency table.
Hence, the correct dot plot is given in option 1.
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Determine which set of side measurements could be used to form a right triangle.
12, 16, 20
6, 14, 19
6, 8, 15
4, 5, 6
Only the side lengths 12, 16, and 20 can be used to create a right triangle.(Option-A)
The Pythagorean theorem, which states that the square of the length of the hypotenuse (the longest side) is equal to the sum of the squares of the lengths of the other two sides, must be satisfied for a set of side measurements to create a right triangle.
This theorem allows us to determine which sets of side measurements can create a right triangle. 202 = 400 for the set of measures 12, 16, and 20.
[tex]12^2 + 16^2[/tex] = 144 + 256 = 400
The measurements could result in a right triangle because they meet the Pythagorean theorem.
Measurements 6, 14, and 19 are as follows: 192 = 361 62 + 142 = 36 + 196 = 232 . (Option-A)
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Answer:
12, 16, 20
Step-by-step explanation:
A right triangle is a triangle that has one right angle, which is an angle that measures 90 degrees. The side opposite the right angle is called the hypotenuse. The other two sides are called the legs.
We can use the Pythagorean theorem to determine which set of side measurements. The Pythagorean theorem states that in a right triangle, the square of the hypotenuse is equal to the sum of the squares of the legs.
So, for each set of side measurements, we can calculate the square of each side and add them together. If the sum is equal to the square of the hypotenuse, then the set of side measurements could be used to form a right triangle.
Set 1: 12, 16, 20
Square of 12: 144Square of 16: 256Square of 20: 400The sum of the squares of the legs is 144 + 256 = 400.
The square of the hypotenuse is also 400.
Therefore, set 1 could be used to form a right triangle.
Set 2: 6, 14, 19
Square of 6: 36Square of 14: 196Square of 19: 361The sum of the squares of the legs is 36 + 196 = 232.
The square of the hypotenuse is 361.
Since the sum of the squares of the legs is not equal to the square of the hypotenuse, set 2 could not be used to form a right triangle.
Set 3: 6, 8, 15
Square of 6: 36Square of 8: 64Square of 15: 225The sum of the squares of the legs is 36 + 64 = 100.
The square of the hypotenuse is 225.
Since the sum of the squares of the legs is not equal to the square of the hypotenuse, set 3 could not be used to form a right triangle.
Set 4: 4, 5, 6
Square of 4: 16 Square of 5: 25 Square of 6: 36The sum of the squares of the legs is 16 + 25 = 41.
The square of the hypotenuse is 36.
Since the sum of the squares of the legs is not equal to the square of the hypotenuse, set 4 could not be used to form a right triangle.
Therefore, the only set of side measurements that could be used to form a right triangle is set 1.
Find the inverse of the following matrix. Write entries as integers or fractions in lowest terms. If the matrix is not invertible, type "N" for all entries. -5-1021 A = -2-5 9 1 2 -4
The inverse of matrix A is given by;
A^-1 = |5/139 -189/139 29/139 |
|-10/139 129/139 -27/139 |
|-5/139 19/139 -3/139 |
The given matrix is A =
| -5 -10 21 |
| -2 -5 9 |
| 1 2 -4 |
To find the inverse of a matrix, first find the determinant of that matrix. The determinant of matrix A is given as;
|A| = -5(-5(-4) - 2(9)) - (-10)(-2(-4) - 1(21)) + (21)(-2(2) - 1(-5))
|A| = -5(10) + 100 - 21(9)
|A| = -50 + 100 - 189
|A| = -139
Thus, the determinant of matrix A is -139. Now, we can use the formula of inverse of a 3x3 matrix;
A^-1 = 1/|A| * |(b22b33 - b23b32) (b13b32 - b12b33) (b12b23 - b13b22)|
| (b23b31 - b21b33) (b11b33 - b13b31) (b13b21 - b11b23)|
| (b21b32 - b22b31) (b12b31 - b11b32) (b11b22 - b12b21)|
where b is the cofactor of each element of matrix A.
The cofactor of element aij is denoted as Aij and given as Aij = (-1)i+j|Mij|.
Thus, the cofactors of matrix A are;
|-5 -10 21|
| -2 -5 9 |
| 1 2 -4 |
M11 = | -5 9 |
| 2 -4 |
M12 = | -2 9 |
| 2 -5 |
M13 = | -2 -5 |
M21 = | -10 21 |
| 2 -9 |
M22 = | -5 -21 |
| -2 5 |
M23 = | -2 -2 |
M31 = | -10 -5 |
| 2 9 |
M32 = | -5 -9 |
| 2 2 |
M33 = | -2 -2 |
Now we can find the inverse of matrix A as follows;
A^-1 = 1/-139 * |(5 189 -29)|
|(-10 -129 27)|
|(-5 19 -3) |
Hence, the inverse of matrix A is given by;
A^-1 = |5/139 -189/139 29/139 |
|-10/139 129/139 -27/139 |
|-5/139 19/139 -3/139 |
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2. Translate the sentence to function notation:
The cost of shipping depends on the distance shipped.
Answer:
see the explanation below
Step-by-step explanation:
The expression for the cost can be given as
y=mx+c
where x= the distance
m= the cost to move x distance
c= the fixed cost
Therefore the total cost to ship the cost will be y
Pennies made prior to 1982 were made of 95% copper Because of their copper content, these pennies are worth about $0.023 each. Pennies made after 1982 are only 2.5% copper Jenna reads online that 13.2% of pennies in circulation are pre-1982 copper pennies. Jenna has a large container of pennies at home. She selects a random sample of 50 pennies from the container and finds that 11 are pre-1982 copper pennies Does this provide convincing evidence that the proportion of pennies in her container that are pre-1982 copper pennies is greater than 0.132?
a. Identify the population, parameter, sample and statistic.
Population:________ parameter_________
Sample_________Statistic:__________
b. Does Jenna have some evidence that more than 13.2% of her pennies are pre-1982 copper pennies?
c. Provide two explanations for the evidence described in #2.
a)
Population: All pennies in the containerParameter: p = Proportion of pre-1982 copper pennies in the containerSample: 50 randomly selected pennies from the containerStatistic: Number of pre-1982 copper pennies in the sample = 11b) If the test statistic is greater than the critical value, we can reject the null hypothesis and conclude that there is evidence that the proportion is greater than 0.132.
c. Two possible explanations for the evidence that Jenna found are given below.
Solution:
a.
Identify the population, Parameter, sample, and statistic.
Population: All pennies in the container
Parameter: p = Proportion of pre-1982 copper pennies in the container
Sample: 50 randomly selected pennies from the container
Statistic: Number of pre-1982 copper pennies in the sample = 11
b.
To determine if Jenna has convincing evidence that more than 13.2% of her pennies are pre-1982 copper pennies, we can perform a hypothesis test.
Let's assume that the null hypothesis is that the proportion of pre-1982 copper pennies in the container is equal to 0.132, while the alternative hypothesis is that the proportion is greater than 0.132.
Then, we can calculate the test statistic and compare it to the critical value.
If the test statistic is greater than the critical value, we can reject the null hypothesis and conclude that there is evidence that the proportion is greater than 0.132.
c. Two possible explanations for the evidence that Jenna found could be:
1. The container has a higher proportion of pre-1982 copper pennies than the national average.
2. Jenna's sample is not representative of the container, and the sample proportion is higher than the population proportion by chance.
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I dont know the answer please help me yall
Answer:
180 customers made additional purchases
Step-by-step explanation:
In order to find the percent of something like 72% of 250 you need to convert the percentage to a decimal and multiply it to the number.
0.72 * 250 = 180
Answer:
180 customers
Step-by-step explanation:
Since 72% of the customers made additional purchases and there were 250 customers, we need to look for 72% of 250. To do this we convert 72 into a fraction, which makes it 0.72 and we turn the word "of" into a multiplication symbol (as of most commonly means multiplication in math). So, 0.72*250=180. Therefore, 180 customers made additional purchaces.
The rectangular prism has a volume of 936 cubic inches. Write and solve an equation to find the missing dimension of the prism.
Answer: Solution in photo
Write the word sentence as an equation. 12 less than a number m equals 20.
Answer:
12 - m = 20
Explanation: Less than can also be a subtraction symbol so 12 less than a number, which the number is unknown in this case would be replaced with m then equals to 20. 12 - m =20
pls HeLp meee and tyy
Answer:
Step-by-step explanation:
A whale is at the surface of the ocean to breathe. What is the whale's elevation?
Question: Find the M
Answer:
<ABC = 17
Step-by-step explanation:
I'm going to make a guess. My guess is that you want the measure of angle B. I didn't see that the diagram asks that very question.
If you join <ADC, that angle is also 34 degrees. By the property of angles touching the circumference of a circle, the angle touching the circumference is 1/2 the central angle
1/2 34 = 17
4) Of all the registered automobiles in Colorado, 10% fail the state emissions test. Ten automobiles are selected at random to undergo an emissions test. a. Find the probability: (Provide your answer with three decimal places) 1) That exactly three of them fail the test. [2 pts] 11) That fewer than three of them fail the test. [3 pts] 1) That at least eight of them fail the test. [3 pts] b. Find the mean, variance, and standard deviation of the number of automobiles fail the test. (Round your answers to three decimal places if needed) (5 pts]
The mean is 1, variance is 0.9, and standard deviation is 0.948, rounded to three decimal places. Given data: Of all the registered automobiles in Colorado, 10% fail the state emissions test.
Ten automobiles are selected at random to undergo an emissions test.a. Find the probability:
1) That exactly three of them fail the test.
For the number of success (x) and number of trials (n),
the probability mass function (PMF) for binomial distribution is given by: [tex]P(X = x) = C(n, x) * p^{(x)} * q^{(n-x)},[/tex]
where [tex]C(n, x) = (n!)/((n-x)! * x!) ,[/tex]
p and q are the probabilities of success and failure, respectively. Here, the probability of success is the probability of an automobile to fail the test, p = 0.10 and the probability of failure is q = 1 - p = 0.90.
Now, X is the number of automobiles that fail the test.
Thus, n = 10, x = 3, p = 0.10, and q = 0.90.
Using the above formula:
[tex]P(X = 3) = C(10, 3) * (0.10)^{(3)} * (0.90)^{(10-3)}\\= 0.057[/tex]
The required probability is 0.057, rounded to three decimal places.
1) That fewer than three of them fail the test.
The required probability is P(X < 3).P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) Using the above formula:
[tex]P(X = 0) = C(10, 0) * (0.10)^{(0)} * (0.90)^{(10)}[/tex]
= 0.3487P(X = 1)
= [tex]C(10, 1) * (0.10)^{(1) }* (0.90)^{(9)}[/tex]
= 0.3874P(X = 2) = [tex]C(10, 2) * (0.10)^{(2)} * (0.90)^{(8)}[/tex]
= 0.1937
Now, P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)
= 0.3487 + 0.3874 + 0.1937
= 0.9298
The required probability is 0.9298, rounded to three decimal places.
1) That at least eight of them fail the test.
The required probability is
P(X ≥ 8).P(X ≥ 8) = P(X = 8) + P(X = 9) + P(X = 10) Using the above formula:
[tex]P (X = 8) = C(10, 8) * (0.10)^{(8)} * (0.90)^{(2) }[/tex]
= 0.0000049
[tex]P(X = 9) = C(10, 9) * (0.10)^{(9)} * (0.90)^{(1) }[/tex]
= 0.0000001
[tex]P(X = 10) = C(10, 10) * (0.10)^{(10)} * (0.90)^{(0)}[/tex]
= 0.0000000001
Now,
P(X ≥ 8) = P(X = 8) + P(X = 9) + P(X = 10)
= 0.0000049 + 0.0000001 + 0.0000000001 = 0.000005
The required probability is 0.000005,
rounded to three decimal places.
b. Find the mean, variance, and standard deviation of the number of automobiles fail the test.
The mean (μ) for binomial distribution is given by: μ = n * p,
where n is the number of trials and p is the probability of success.
The variance ([tex]= 1 \sigma ^ 2 = n * p * q = 10 * 0.10 * 0.90 ^2[/tex]) for binomial distribution is given by: [tex]\sigma ^2 = n * p * q[/tex]
The standard deviation (σ) for binomial distribution is given by:
σ = √(n * p * q)
Here, n = 10 and p = 0.10.
Thus, q = 0.90.
Using the above formulas:
μ = n * p = 10 * 0.10
[tex]= 1\sigma ^2 = n * p * q = 10 * 0.10 * 0.90[/tex]
= 0.9σ = √(n * p * q)
= √(10 * 0.10 * 0.90)
= 0.948
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Graph y=\dfrac{2}{7}\,xy= 7 2 xy, equals, start fraction, 2, divided by, 7, end fraction, x.
Answer:
The answer is A, C, and D
The graph should be 7 units for x and 2 units for y.
Step-by-step explanation:
Full Question: Graph y = 2/7x
Look at attachment:
Hope this helps! :)
The graph of the linear function y = (2/7)x will be given below.
What is the graph of the function?The collection of all coordinates in the planar of the format [x, f(x)] that make up a variable function's graph.
A linear system is one in which the parameter in the equation has a degree of one. It might have one, two, or even more variables.
The equation of line is given as
y = mx + c
Where m is the slope and c is the y-intercept.
The function is given below.
y = (2/7)x
Compare the function with standard equation of the line,
Then the slope of the function is 2/7 and the y-intercept is zero, that means the line is passing through origin.
Then the graph of the linear function y = (2/7)x will be given below.
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find the LCM lowest common multiple and the HCF highest common factor of 40 and 56
Answer:
280 and 8
Step-by-step explanation:
the LCM is the lowest common multiple
the lowest multiple that can Divide 40 and 56 without a remainder = 280
the Hcf Is the highest common factor of 40 and 56
the highest number that can Divide both =8
In a two-way between subjects ANOVA, a significant main effect for B means that
A - the mean for B1 is not equal to the mean for B2.
B - the difference between A1 and A2 is not the same at B1 as for B2.
C - the mean for A1 is equal to the mean for A2.
D - the mean for B1 is equal to the mean for B2.
In a two-way between subjects ANOVA, a significant main effect for B means that option A - the mean for B1 is not equal to the mean for B2.
In a two-way ANOVA, we are examining the effects of two independent variables (factors) on a dependent variable. One of the factors is referred to as factor A, and the other as factor B. A main effect for B indicates that there is a significant difference between the means of the levels of factor B. Therefore, if we observe a significant main effect for B, it implies that the mean for B1 (one level of factor B) is not equal to the mean for B2 (another level of factor B). This suggests that the variable represented by factor B has a significant influence on the dependent variable, and there is a difference in the outcome between the two levels of factor B.
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CAN SOMEONE PLEASE HELP ME PLEASE
Answer:
If Then proof has been explained below!
Step-by-step explanation:
1.) If segment XY ║ ZW, then the 154° angle ≅ ∠2 (vertical angles)
2.) If segment XY ║ ZW, then ∠2 is complementary to ∠4
3.) If ∠2 is complementary to ∠4, then ∠4 = 28°
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Your grandmother always has a jar of cookies on her counter. One day while you are visiting, you eat 5 cookies from the jar. In the equation below, c is the number of cookies remaining in the jar and b is the number of cookies in the jar before your visit.
Answer:
b - 5 = c
Step-by-step explanation:
if you take the number of cookies before the visit (B) and then you eat 5, that would be (B - 5). after you eat the cookies, C is the amount left. so it’s a subtraction problem without 2 numbers. so the equation would be
b - 5 = c
or
before - 5 = after