A 0.250 kg block attached to a light spring oscillates on a frictionless, horizontal table. The oscillation amplitude is A = 0.125 m and the block moves at 3.00 m/s as it passes through equilibrium at x = 0. (a) Find the spring constant, k.

Answers

Answer 1

The spring constant, k will be 18 N/m.The ratio of force to one unit of displaced length is known as the spring constant.

What is the spring constant?

Spring constant is defined as the ratio of force per unit displaced length.

Given data;

Mass of  block,m=0.250 k

Amplitude,A = 0.125 m

Velocity,V=3.00 m/

Spring constant,K=?

The formula for the spring constant when the spring is oscillate at the given amplitude A:

[tex]\rm K = \frac{V_{max}^2 m}{A} \\\\ K = \frac{3.0 \times 0.250}{0.125} \\\\ K=18 \ N/m[/tex]

Hence, the spring constant, k will be 18 N/m

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Related Questions

A type of anchor that is a good choice when jacking or leveling
the fastening component is a(n)_
Select one:
O a. wedge anchor
O b. stud bolt anchor
O c. one-piece anchor
O d. hammer-set anchors

Answers

A type of anchor that is a good choice when jacking or leveling the fastening component is a stud bolt anchor.

What is a Stud bolt anchor?

These are the type of anchor which bare embedded in concrete with the threaded portion on the outside.

This makes it easier to jack or level the fastening component which is why option B was chosen.

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An aircraft lands and brakes, slowing from 250 m/s to 5 m/s in 30 secs. What is it's acceleration?
O-10 m/s²
-8.2 m/s²
-1.3 m/s²
-5.2 m/s²

Answers

The acceleration of the aircraft is determined as -8.2 m/s².

Acceleration of the aircraft

The acceleration of the aircraft is calculated as follows;

a = Δv/t

where;

Δv is change in velocityt is time

a = (5 - 250)/(30)

a = -8.2 m/s²

Thus, the acceleration of the aircraft is determined as -8.2 m/s².

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An object of volume 2.0×10⁴cm³ is under water .calculate the buoyant force of water on the object (Density of water=1000kg/m³)

Answers

Answer:

An object of volume 2.0×10⁴cm³ is under water .calculate the buoyant force of water on the object (Density of water=1000kg/m³) 196.2N

What happens to sound waves from an object as it moves toward you?

The pitch gets higher because of an increase in wavelength.
The pitch gets lower because of an increase in frequency.
The pitch gets lower because of an increase in wavelength.
The pitch gets higher because of an increase in frequency.

Answers

The event that happens to sound waves from an object as it moves toward you is The pitch gets higher because of an increase in wavelength.

What is sound waves?

Sound waves refer to a form of transverse wave that compress and vibrate while travelling from one medium to another thereby transferring energy.

Therefore, The event that happens to sound waves from an object as it moves toward you is The pitch gets higher because of an increase in wavelength.

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A car travels 263.0 miles in 5.5 hours. How long will it take to travel 363.0 miles at
this average velocity? (Answer to 1 decimal place)

Answers

From the average velocity calculated, if the car should travel 363.0 miles, the time elapsed will be 7.6 hours.

How long will it take to travel 363.0 miles at the given average velocity?

Note that; Velocity is the speed at which an object moves in a particular direction. It is expressed as;

v = distance / time

Given that;

Distance covered by the car d = 263.0 milesTime elapsed t = 5.5 hours

First we determine the velocity of the car.

v = distance / time

v = 263.0 miles / 5.5 hours

v = 47.8181 miles per hour.

Now, if the car travels 363.0 miles, time elapsed will be;

velocity = distance / time

time = distance / velocity

time = 363.0 miles / 47.8181 miles per hour

time = 7.6 hours

Therefore, from the average velocity calculated, if the car should travel 363.0 miles, the time elapsed will be 7.6 hours.

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