A 49 kg person is being dragged in their sleeping bag to the lake by a 593 N
force at an angle of 30°. If the person accelerates at a rate of 0.57 m/s?, how
much resistive force (force of friction) is acting on them?

NEED HELP LIKE RIGHT NOW PLz

Answers

Answer 1

Answer:

f = 485.62 N

Explanation:

Since, the bag is moving with some acceleration. Hence, the unbalanced force will be given as:

Unbalanced Force = Horizontal Component Applied Force - Frictional Force

Unbalanced Force = Fx - f

But, from Newtons Second Law of Motion:

Unbalanced Force = ma

comparing the equations:

ma = Fx - f

f = F Cos θ - ma

where,

f = frictional force  = ?

F = Applied force  = 593 N

m = mass of person = 49 kg

a = acceleration = 0.57 m/s²

θ = Angle with horizontal = 30°

Therefore,

f = (593 N)(Cos 30°) - (49 kg)(0.57 m/s²)

f = 513.55 N - 27.93 N

f = 485.62 N


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Answers

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Answers

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Answers

Answer:

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Answer:

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A car enters the freeway with a speed of 6.4 m/s and accelerates uniformly for 3.2 km in 3.5 min. How FAST (m/s) is the car moving after this time?

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Answer:

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Answer:

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Answers

Answer:

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Answers

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Answers

Answer:

200

Explanation:

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Number of turns in secondary coil = ?

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1. A plane flying horizontally at an altitude of 490 meters and having a velocity of 250 meters per second east, drops a supply packet to a work crew on the ground. It falls freely without a parachute. [Assume no wind and negligible air resistance.] A. Calculate the time required for the packet to hit the ground. (25 pts)

Answers

Answer:

t = 10 s

Explanation:

Given :

Altitude, h = 490 m

Initial velocity of a plane, u = 250 m/s

To find :

The time required for the packet to hit the ground. When it hits the ground its velocity will be 0. Let t is the required time. It can be calculated as follows :

[tex]t=\sqrt{\dfrac{2h}{g}} \\\\t=\sqrt{\dfrac{2\times 490}{9.8}} \\\\t=10\ s[/tex]

So, it will take 10 s to reach the ground.

2. For every action there is an equal and opposite reaction. Which Newton's law is defined?​

Answers

Answer:

newtons 3rd law

Explanation:

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Answer:

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Answers

Answer:

2500kgm/s

Explanation:

Change in momentum is equal to impulse, numerically.

Ft=m( v-u)

But he begins from rest so u= 0

Then

Ft= mv

500(5)=mv

2500= mv

The correct answer would be 2500 Kgm

How can temperature influence the rate chemical reaction between an acid and a base that will make our rocket defy gravity and launch upward?

Answers

Answer:

Explanation:

Generally, an increase in temperature increases the rate of a chemical reaction. Consequently, when the temperature of a reaction is raised, the molecules present in the reaction interact faster by colliding with one another and surpassing the effective collision of such reaction to bring about a high reaction rate. Similarly, in the case of the rocket launch, the same process occurs as the temperature increase will cause an increase in the reaction rate leading the hydrogen from the acid to react explosively with the oxygen from the base to form water - this makes the rocket defy gravity and launch upward.

calculate the height from from which a body is released from rest if its velocity just before hitting the ground is30m\s

Answers

Answer:

height = 45 m

Explanation:

Initial velocity = 0 m/s

Final velocity = 30 m/s

Acceleration due to gravity = +10m/s^2 ( because ball is going down )

Using the eqn of motion

[tex] {v}^{2} - {u}^{2} = 2gh[/tex]

where v= final velocity ; u = initial velocity ; g = acceleration due to gravity ; h = height

So,

[tex] {30}^{2} - {0}^{2} = 2 \times 10 \times h[/tex]

[tex] = > 20h = 900[/tex]

[tex] = > h = \frac{900}{20} = 45[/tex]

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