A bungee jumper jumps off a bridge and bounces up and down several times.
She finally comes to rest 16 m below the bridge from which she just jumped.
If her mass is 50 kg and the spring constant of the bungee cord is 35 N/m,
how much energy was lost due to air resistance while she was bouncing?
(Recall that g = 9.8 m/s²)
OA. 5420 N
OB. 3360 N
OC. 4280 N
O D. 6550 N

A new wave created by the destructive interference of two waves is produced. The new wave is accurately described in statement A. Its amplitude is greater than that of the waves that produced it.

Destructive interference happens when the maxima of two waves are 180° out of phase; a positive displacement of one wave is canceled exactly by a negative displacement of the other wave.

Two or more waves combining to produce a wave with a smaller displacement is called destructive interference.

Two waves overlap producing a new wave that exhibits destructive interference. It has a larger amplitude than the waves that overlapped to produce it.

Hence, statement A correctly describes the new wave.

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Answer:

[tex]46.482 cm[/tex]

Explanation:

[tex]Since 1 in = 2.54cm\\\\18.3 inches =(18.3 x 2.54) cm\\ =46.482cm[/tex]

Answer:

According to Oxford Dictionaries "Precision" means "the quality, condition, or fact of being exact and accurate."

Explanation:

Hope this helps! :)

The sum of the maximum voltages across each element in a series RLC circuit is usually greater than the maximum applied voltage because voltages are added by vector addition.

Kirchhoff's loop rule states that the algebraic sum of potential differences, as well as the voltage supplied by the voltage sources and resistances, in any loop must be equal to zero.

In a series RLCcircuit, the voltages are not added by scalar addition but by vector addition.

Kirchhoff's loop rule is not violated since the voltages across different elements in the circuit are not at their maximum values.

Therefore, the sum of the maximum voltages across each element in a series RLC circuit is usually greater than the maximum applied voltage because voltages are added by vector addition.

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Answer:

Sorry if I kwon the

answer I telling u

the answer sorry

Out of the given equations,

241Am 23Np + 4He

18F → 180+ °C

14C → 14N+_e

152 Dy → 15. Dy+y

The first equation shows the alpha decay which is ₉₅Am²²⁴ →  ₉₃Np²³⁷ + ₂He⁴

Alpha particles are emitted in the form of radiations when radioactive decay occurs.  The atom of heavy nucleus emit the alpha particles that consist of two proton and two neutrons, also called helium nuclei.

The properties of alpha radiations are:

The Americium with atomic weight  224 undergo alpha decay and produce ₉₃Np²³⁷ . The alpha particle is helium nuclei.

₉₅Am²²⁴   →    ₉₃Np²³⁷ + ₂He⁴

Thus, the first equation represents alpha radiation.

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Answer:

the easy way to describe this is to use a light as an example.

Explanation:

Voltage is pretty much the loop used to help use a lightbulb to emit light. Without voltage, we would be unable to use lightbulbs. This applies to much more than a lightbulb, but it's the easiest way to describe how voltage works.

From the four figure table, the value of sin(55°) to 4 dp is 0.8192.

The term trigonometric ratios are those ratios that are obtained using the sides of a right angled triangle and they are sine, cosine and tangent.

If we have the value sin(55°), upon evaluation, we realize that the value of sin(55°) to 4 dp is 0.8192.

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Potassium will have the greatest atomic size because of its number of shells, followed by sodium which 1 valence electron compared to magnesium the same number of shells but 2 valence electrons.

The relative size of the atoms is determined from the number of shells and valence electron contained in the atom.

Sodium, 11 ----> 2, 8, 1

Magnesium, 12 ----> 2, 8, 2

Potassium, 19, -----> 2, 8, 8, 1,

Potassium will have the greatest atomic size because of its number of shells, followed by sodium which 1 valence electron compared to magnesium the same number of shells but 2 valence electrons.

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The information being conveyed by an object about the important events, advancements, and people of a specific time period is known as: C. historical significance.

Historical significance can be defined as an information that is being conveyed by an artistic object about the important events, advancements, technology, phenomenon, and people that have existed and occurred over a specific time period

This ultimately implies that, historical significance refers to the information that an object conveys with respect to the important events, advancements, technology, and people of a specific time period.

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The stone on the celestial body will be 50 N in weight. When the mass of a celestial body equals half of the mass of the earth.

The mass of the body is defined as the amount of matter a body has. It is denoted by m and its unit is kg.

Weight is defined as the amount of force an object exerts on the surface. It is given as the product of mass and the gravitational pull.

Given data:

[tex]\rm m_h = \frac{1}{2} m_E[/tex]

[tex]\rm r_h=\frac{1}{2} r_E[/tex]

[tex]\rm W_E = 100 \ N[/tex]

The weight of the body on earth is found as;

[tex]\rm W_E = m_Eg[/tex]

Substitute all the values:

[tex]\rm W_E = m_Eg \\\\\ 100 \ N = 2 m_hg \\\\ m_hg =50 \ N \\\\ W_h = 50 \ N[/tex]

Hence, the weight of the stone on the heavenly body will be 50 N.

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Answer:

I don't really understood the question

#21

According to first equation of kinematics

#22

#a

The order is

#b

for speed find absolute velocity

So order is

S1<S3<S2

Answer:

See below ~

Explanation:

Question 21 :

⇒ v = u + at

⇒ v = 5 + 1.3 (2)

⇒ v = 5 + 2.6

⇒ v = 7.6 m/s

=============================================================

Question 22 : At t = 3

Subpart (a)

⇒ Object 1 : v = 2 + 3(3) = 11 m/s

⇒ Object 2 : v = -8 - 4(3) = -20 m/s

⇒ Object 3 : v = 1 - 5(3) = -14 m/s

⇒ Hence, their velocities are in the order : Object 2 < Object 3 < Object 1

Subpart (b)

⇒ Object 1 : v = | 2 + 3(3) | = 11 m/s

⇒ Object 2 : v = | -8 - 4(3) | = 20 m/s

⇒ Object 3 : v = | 1 - 5(3) | = 14 m/s

⇒ Hence, their speeds are in the order : Object 1 < Object 3 < Object 2

Answer:

wood

Explanation:

Answer:

Greater gravity compresses the gas, making it denser and hotter, so the outward pressure increases. In any given layer of a star, there is a balance between the thermal pressure (outward) and the weight of the material above pressing downward (inward). This balance is called hydrostatic equilibrium.

The times and distances are represented by the function are

The distance is the length of path travelled by a body when moving with some speed and taking time t.

Given function is

D (t) = 300t +125 for 0≤t<2.5

D (t) = 875  for 2.5 ≤t≤3.5

D(t)= 75t +612.5 for 3.5<t≤6

According to the given function, for 2 hours, the traveler will travel from home,

D (2) = 300x2 +125 = 725 miles.

For time between 2.5 to 3.5 hr, the distance is constant i.e. 875 miles.

For total time 6hr, the distance travelled will be

D(6) = 75 x 6 +612.5 = 1062.5 miles.

Thus, the correct options are picked up.

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Answer:

B, D, E

Explanation:

got it right on edge

The density of the metal sphere is 2 times the density of the liquid as proved.

The net upward force acting on the sphere as it is dropped into the liquid is calculated as follows;

F =  σVg - ρVg

ma =  σVg - ρVg  

where;

σV(a) =  σVg  - ρVg

σ(a) = σg  - ρg

σ(g/2) = σg -  ρg  

g(σ/2) = g(σ -  ρ)

σ/2 = σ -  ρ

σ/2 - σ = -  ρ

-σ/2 = -  ρ

σ = 2ρ --- proved

Thus, the density of the metal sphere is 2 times the density of the liquid as proved.

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From the calculation, the wavelength of the waves is about 264 nm and belongs to the ultraviolet spectrum.

The term photoelectric effect can be used to describe the loss of electron from the surface of a metal. Given that; KE = E - W, where;

KE = kinetic energy of the emitted photoelectron

E = energy of the photon

W = work function of the metal

[tex]2= E - 2.71\\E = 2 + 2.71\\E = 4.71ev or 7.5 * 10^-19 J[/tex]

λ= hc/E

λ= [tex]6.6 * 10^-34 * 3 * 10^8/7.5 * 10^-19[/tex]

λ= [tex]2.64 * 10^-7 m[/tex] or 264 nm

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The final velocity of the block A will be 2.5 m/sec. The principal of the momentum conversation is used in the given problem.

According to the law of conservation of momentum, the momentum of the body before the collision is always equal to the momentum of the body after the collision.

In a given concern, mass m₁ is M, mass m₂ is 3M. Initial speed for the mass m₁ and  m₂ will be u₁=5 and u₂=0 m/s respectively,

According to the law of conservation of momentum

Momentum before collision =Momentum after collision

m₁u₁+m₂u₂=(m₁+m₂)v

M×5+3M×0=[M+3M]v

The final velocity is found as;

V=51.25 m/s

The velocity of block A is found as;

[tex]\rm V_f=\frac{(m_1-m_2)u_1}{m_1+m_2} +\frac{2m_2u_2}{m_1+m_2} \\\\ V_f=\frac{(M-3M)5+2\times3M\times0}{m_1+m_2} \\\\ V_f=2.5 m/s[/tex]

Hence, the final velocity of the block A will be 2.5 m/sec.

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The net force performs a total amount of work equal to

(45 N) (0.80 m) = 36 J

on the bullet, and this is in turn is equal to the change in the bullet's kinetic energy by the work-energy theorem. So we have

W = ∆K = 1/2 mv²

since the bullet starts at rest, where m = its mass and v = its final velocity.

Solve for v :

36 J = 1/2 (0.0050 kg) v²   ⇒   v = 120 m/s

Based on the calculations, the kinetic energy of the model rocket at this point is equal to: A. 7,200 Joules.

Given the following data:

Mass = 1 kg.

Height = 500 m.

Velocity = 120 m/s.

Mathematically, kinetic energy can be calculated by using this formula:

K.E = 1/2 × mv²

Where:

Substituting the given parameters into the formula, we have;

K.E = 1/2 × 1 × (120)²

K.E = 1/2 × 1 × 14,400

K.E = 7,200 Joules.

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The work John does is 680 J (joules).

To calculate the work done by John, we need to use the formula:

Work = Force * Distance * cos(theta)

where Force is the applied force, Distance is the displacement, and theta is the angle between the force and the displacement.

Substitute the given values into the formula:

Force = 60 N

Distance = 12 m

theta = 37 degrees

Convert the angle from degrees to radians:

theta_radians = 37 degrees * (pi/180)

Calculate the cosine of the angle:

cos(theta_radians) = cos(37 degrees * (pi/180))

Calculate the work done by John:

Work = 60 N * 12 m * cos(37 degrees * (pi/180))

Simplify the equation and calculate the numerical value:

Work ≈ 680 J (joules)

Therefore, the work done by John is approximately 680 joules.

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Answer:

5.775 m/s

Explanation:

radial acceleration = velocity / radius

=> velocity = radial acceleration * radius

=> v = 3.5 * 1.65 = 5.775 (m/s)

The potential difference across the capacitor is 5 × 10∧4 volts and the energy stored in it is 1. 25 Joules

The energy stored in a capacitor is an electrostatic potential energy.

It is related to the charge(Q) and voltage (V) between the capacitor plates.

It is represented as 'U'.

Formula:

Potential difference, V is the ratio of the charge to the capacitance of a capacitor.

It is calculated using:

V = Q ÷ C

Where Q = charge 5 × 10∧-5C and C = capacitance 10∧-9

Substitute the values into the equation

Potential difference, V = 5 × 10∧-5 ÷  10∧-9 = 5 × 10∧4 volts

Formula:

Energy, U = 1 ÷ 2 (QV)

Where Q= charge and V = potential difference across the capacitor

Energy, U = 1 ÷ 2 ( 5 × 10∧-5 × 5 × 10∧4)

= 0.5 × 25 × 10∧-1

= 0.5 × 2.5

= 1. 25 Joules

Therefore, the potential difference across the capacitor is 5 × 10∧4 volts and the energy stored in it is 1. 25 Joules

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Answer:

A. 0.502

B. 0.753

Explanation:

A. The angular acceleration of the flywheel is equal to the change in angular velocity divided by the change in time, which is equal to (4.6-2.09)/5 which is 0.502.
B. Angular acceleration is equal to the net torque divided by the rotational inertia. If you rearrange the equation, torque is equal to angular acceleration times rotational inertia, which is 0.502 times 1.5 which is 0.753.

Answer:

Assumption: the angular acceleration of this flywheel is constant.

Angular acceleration: [tex]0.502\; {\rm rad\cdot s^{-2}}[/tex].

Net torque on this flywheel: [tex]0.753\; {\rm kg \cdot m^{2} \cdot s^{-2}[/tex] (or, equivalently, [tex]0.753\; {\rm N \cdot m}[/tex].)

Explanation:

Change in the angular velocity of this flywheel:

[tex]\begin{aligned}\Delta \omega &= \omega_{1} - \omega_{0} \\ &= 4.6\; {\rm rad \cdot s^{-1}} - 2.09 \; {\rm rad \cdot s^{-1}} \\ &= 2.51\; {\rm rad \cdot s^{-1}}\end{aligned}[/tex].

Divide this change in angular velocity [tex]\Delta \omega[/tex] with the duration [tex]t[/tex] of the acceleration to find the average angular acceleration of this flywheel:

[tex]\begin{aligned}\alpha &= \frac{\Delta \omega}{t} \\ &= \frac{2.51\; {\rm rad \cdot s^{-1}}}{5\; {\rm s}} \\ &= 0.502\; {\rm rad \cdot s^{-2}}\end{aligned}[/tex].

By Newton's Second Law for Rotation, the net torque on this flywheel would be the product of the angular acceleration and the moment of inertia of this flywheel, [tex]I[/tex]:

[tex]\begin{aligned}\tau_{\text{net}} &= I\, \alpha \\ &= 1.5\; {\rm kg \cdot m^{2}} \times 0.502\; {\rm s^{-2}} \\ &= 0.753\; {\rm kg \cdot m^{2} \cdot s^{-2}} \\ &= 0.753\; {\rm (kg \cdot m \cdot s^{-2}) \cdot m} \\ &= 0.753\; {\rm N \cdot m}\end{aligned}[/tex].

The final temperature of the seawater-deck system is 990°C.

The increment in temperature adds up the thermal energy into the object. This energy is Heat energy.

The deck of a small ship reaches a temperature Ti= 48.17°C seawater on the deck to cool it down. During the cooling, heat Q =3,710,000 J are transferred to the seawater from the deck. Specific heat of seawater= 3,930 J/kg°C.

Suppose for 1 kg of sea water, the heat transferred from the system is given by

3,710,000 = 1 x 3,930 x (T - 48.17)

T = 990°C  to the nearest tenth.

The final temperature of the seawater-deck system is 990°C.

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The option which most likely represent the forces acting on the object is  ← 63 N and → 73 N.

When two or more forces are acting on the system of objects, then the to attain equilibrium, net force must be zero.

When the  resulting net force of an object is →10 N

The forces must be in x and  -x direction to balance and give net force of 10 N in +x direction.

So, +73N -63 N = +10 N

Thus, the correct option is ← 63 N and → 73 N

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The first two steps for finding the magnitude of the resultant vector is find the sum of the two horizontal vectors and the sum of the two vertical vectors.

The resultant of two vectors is determined from Pythagoras theorem is as shown below.

R² = a² + b²

Thus, the first two steps for finding the magnitude of the resultant vector is find the sum of the two horizontal vectors and the sum of the two vertical vectors.

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Answer:

B. A measure of mass per unit volume

Explanation:

trust me

Answer:ITS C I PASSED THE TEST

Explanation:I DID THE PLATO

The acceleration of the snail will be 7/13 m/sec². The acceleration is found as the rate of change of the velocity.

The rate of change of velocity with respect to time is known as acceleration. According to Newton's second law, the eventual effect of all forces applied to a body is its acceleration.

The given data in the problem is;

v(t)=1.4ln(1’t²) inches per minute

0<t<15 minute

Acceleration is found as;

[tex]\rm v('t)=1.4 \times \frac{1}{1+t^2} (2t)[/tex]

Acceleration at t= 5 minute;

[tex]\rm v'(5)=\frac{1.4(2)(5)}{1+5^2} =\frac{14}{26} \\\\ v'=\frac{7}{13}[/tex]

Hence, the acceleration of the snail will be 7/13 inch per square minute.

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