A class of 33 students elected a class treasurer. There were 11 votes for Candidate A and 15 votes for Candidate B. The remaining students did not vote. Which expression gives the percent of voters who voted for Candidate A?

Answer:

800,000

Step-by-step explanation:

The numbers are above 5 making it round up not down

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Answer:

y=400h

Where y is distance and h is time.

Step-by-step explanation:

then put x valule into KL equation

Answer:

5

Step-by-step explanation:

Since, A, B, C, D are collinear.

[tex] \implies A - B - C - D \\

\therefore \: AD = (AB + BC) + CD \\ \therefore \: 18 = AC + CD.. (\because AB + BC =AC) \\ \therefore \: 18 = 8 + CD \\ \therefore \: 18 - 8 = CD \\ \therefore \: 10 = CD \\ \\ \because \: BC + CD = BD \\ BC = BD - CD \\ BC = 15 - 10 \\ BC = 5 \\ [/tex]

Answer:

complementary

Step-by-step explanation:

yes

The word that describes their measures of ∠1 and ∠2 is: complementary.

Recall:

From the information given, we know that:

m∠1 and m∠2 forms a right angle.

Since a right angle = 90 degrees, therefore:

m∠1 + m∠2 = 90° (complementary)

Therefore, the word that describes their measures of ∠1 and ∠2 is: complementary.

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Answer:

11

Step-by-step explanation:

Answer:

x=(-9)

PQ=2

PR=3

Step-by-step explanation:

Answer:

The answer is "[tex]\bold{\frac{343 \ \pi}{24} \ \text{cubic units}}[/tex]"

Step-by-step explanation:

The volume of the mass whose cross-sectional area has been perpendicular is usually sliced by the method The cross-section, which is based to parallel to y-axis;  

[tex]V = \int_{a}^{b} A (x)dx[/tex]

The semi-circular segment of the strong and seems to be perpendicular to foundation and  

Y-axis parallel.  

Its cross-section does have a diameter of: [tex](7-x)[/tex].  

It also transverse radius is: [tex]\frac{1}{2}(7-x)[/tex].  

The semi-circular segment area is,

[tex]Formula: \\\\ A(x)=\frac{1}{2} \times \pi \times r^2[/tex]

        [tex]=\frac{1}{2} \times \pi \times (\frac{(7-x)}{2})^2\\\\=\frac{1}{2} \times \pi \times (\frac{(7-x)^2}{4})\\\\=\frac{1}{8}\pi(7-x)^2\\[/tex]

when

[tex]0 \leq \ x \ \leq 7[/tex]

Calculating the volume from the solid accordingly:

[tex]V= \int_{0}^{7}\frac{1}{8} \times\pi \times (7-x)^2 dx[/tex]

   [tex]= \frac{1}{8} \pi \int_{0}^{7}(7-x)^2 dx \\\\= \frac{1}{8} \pi [\frac{(7-3)^3}{-3}]_{0}^{7}\\\\= \frac{\pi}{24} \times [7^3-0]\\\\= \frac{\pi}{24} \times 343\\\\= \frac{343 \pi}{24} \\[/tex]

Answer:

c

Step-by-step explanation:

They are not commutative because the domains of f(x) and g(x) are different.

The functions  [tex]f(x) = x^{3}[/tex] and [tex]g(x) = \frac{1}{x^{3} }[/tex] are not commutative because domains of f(x) and g (x) are different.

Here,

The functions are [tex]f(x) = x^{3}[/tex] and [tex]g(x) = \frac{1}{x^{3} }[/tex] and graph of the function are shown in figure.

We have to check the function are composite or not.

What is Domain of function?

The domain of a function is the set of all possible inputs for the function.

Now,

Domain of function  [tex]f(x) = x^{3}[/tex] is ( -∞, ∞).

And, Domain of function [tex]g(x) = \frac{1}{x^{3} }[/tex] is ( -∞,0 ) U ( 0, ∞).

Hence, the domain of the functions are different so they are not commutative.

So, The functions  [tex]f(x) = x^{3}[/tex] and [tex]g(x) = \frac{1}{x^{3} }[/tex] are not commutative because domains of f(x) and g (x) are different.

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Answer:

3.5

Step-by-step explanation:

total pretzel=10 1/2 or10.5

no. of brother = 3

now,

10.5 pretzel for each borther= 10.5/3

=3.5 ans

Answer:

Step-by-step explanation:

Change all numbers to their decimal form.

37.5 % = 37.5 / 100 = 0.375

1/3 = 0.3333

0.3 = 0.3

40% = 40/100 = 0.4

3/5 = 0.6

Order

0.3

0.33333

0.375

0.4

0.6

Answer:  t > 6/5

In decimal form, this would be t > 1.2

==============================================

Work Shown:

6t > t+6

6t-t > t+6-t ...... subtracting t from both sides

5t > 6

5t/5 > 6/5 .... dividing both sides by 5

t > 6/5

t > 1.2

Answer:

$220 is the amount of simple interest you will earn

Step-by-step explanation:

I = p * r * t

Principle = $2000

Rate = 5.5% (you need to change this to a decimal by dividing by 100) or

         0.055

Time = 2 years

I = 2000 * 0.055 * 2

I = $220

Answer:

39. r = 13.4

40. m = 12

Step-by-step explanation:

39. Given the equation, [tex] -0.8 + r = 12.6 [/tex], to solve for r, the following are the correct steps to take to arrive at the solution:

[tex] -0.8 + r = 12.6 [/tex] (given)

Add 0.8 to both sides of the equation (addition property of equality)

[tex] -0.8 + r + 0.8 = 12.6 + 0.8 [/tex] (this is where the error occurred.)

[tex] r = 13.4 [/tex]

40. The correct steps to take in solving the equation, [tex] -\frac{m}{3} = -4 [/tex] is as follows:

[tex] -\frac{m}{3} = -4 [/tex] (given)

Multiply both sides by 3 (multiplication property of equality)

[tex] 3*-\frac{m}{3} = 3*(-4) [/tex]

[tex] -m = -12 [/tex] (this is where the error occurred. This is what we should have at this line/step)

[tex] m = 12 [/tex] (dividing both sides by -1)

Answer:

Step-by-step explanation:

there are (1/6)/(1/3) one-third in one sixth

Step-by-step explanation:

that means

no. of one-third is 1/2

Answer:

there are 2 one third in one sixth

Answer:45

Step-by-step explanation:

[9(7-3)+13]-[11-(6+9)]

[9(4)+13]-[11-(15)]

[36+13]-[4]

49-4

45

Answer: The answer is 53

Answer:

A

Step-by-step explanation:

Answer:

x=3/8

Step-by-step explanation:

Answer:

Rs.15

Step-by-step explanation:

3% = 3/100 × 500 = 15

Answer:

  34.5%

Step-by-step explanation:

If we assume the relationship is approximately linear with time, we can use technology to draw a line of best fit through the given data. Extrapolating to the year 2030 predicts the value to be 34.5%.

In 2030, we might expect about 34.5% of male first-year college students to claim no religious affiliation.

_____

Additional comment

When it comes to religion, many factors are in play. The assumption we have made has no justification whatever, except that it provides a method for answering the question. (It also predicts the percentage to be 0 in 1963, which we believe to be unrealistic.) An exponential fit is better (r^2 = 0.97), and it predicts about 46.0%.

Answer:

There are 35 adult dogs and 20 puppies

Step-by-step explanation:

Represent the puppies with P and the Adult dogs with A

Given

[tex]A : P = 7 : 4[/tex]

Dogs = 55

Required

Determine A and P

First, we need to sum the ratios;

[tex]Total = A + P[/tex]

[tex]Total = 7 + 4[/tex]

[tex]Total = 11[/tex]

Adult Dogs is then calculated as follows;

[tex]A = \frac{A\ Ratio}{Total} * Dogs[/tex]

[tex]A = \frac{7}{11} * 55[/tex]

[tex]A = \frac{385}{11}[/tex]

[tex]A = 35[/tex]

Puppies is calculated by subtracting the number of adult dogs from the total

[tex]P = Dogs - Adult\ Dogs[/tex]

[tex]P = 55 - 35[/tex]

[tex]P = 20[/tex]

Hence;

There are 35 adult dogs and 20 puppies

Answer: 6/11

Work Shown:

22 people total, 10 men, so 22-10 = 12 women are in the class.

12/22 = (2*6)/(2*11) = 6/11 is the fraction of women in the class

Answer:

I'm pretty sure the answer they want is 12/22 or 6/11 students are women although some people are not men or women which technically makes the question impossible to solve.

Answer:

x=1

Step-by-step explanation:

Anytime there is a vertical line, the y value becomes infinite as the line goes on forever. The only restriction on the line is on the x value of your coordinate. The same goes for a horizontal line, only the x value would become infinite and the y value would be constant.

Vertical Line: (x,∞)

Horizontal Line: (∞,y)

Steps to solve:

x^2 + 2x + 3 when x = 4

~Substitute

4^2 + 2(4) + 3

~Simplify

16 + 8 + 3

~Add

24 + 3

~Add

27

Best of Luck!