A coach needs to select 7 starters from a team of 16 players. How many ways can he arrange the team?

DO NOT PUT COMMAS IN YOUR ANSWER!

Answers

Answer 1

Answer:

The number of ways to select 7 players out of 16 is given by the combination formula:

C(16,7) = 16! / (7! * (16-7)!) = 11440

Once the coach has selected the 7 players, the order in which they are arranged does not matter. Therefore, the number of ways to arrange the team is simply the number of ways to select 7 players:

11440 ways.


Related Questions

Dustin skis on a circular ski trail that has a radius of 2.42 km. Imagine an angle with a vertex at the center of the circular trail that subtends the path Dustin skis.
a. If Dustin travels 0.96 km counter-clockwise along the ski trail, what is the angle's measure in radians? __ radians b. If the angle measures 3 radians, how far did Dustinski? __ km

Answers

a) The angle's measure in radians is 0.397 radians.

b)Dustin skis 7.26 km if the angle measures 3 radians.

a. To find the angle's measure in radians:

We need to use the formula:

θ = s/r

where θ is the angle in radians, s is the length of the arc, and r is the radius of the circle.

In this case, Dustin travels 0.96 km along the ski trail, which is the length of the arc. The radius of the circle is 2.42 km. So we have:

θ = 0.96/2.42 = 0.397 radians (rounded to three decimal places)

Therefore, the angle's measure in radians is 0.397 radians.

b. To find how far Dustin skis if the angle measures 3 radians:

We can use the same formula and rearrange it to solve for s:

s = θr

In this case, θ is 3 radians and r is still 2.42 km. So we have:

s = 3 x 2.42 = 7.26 km

Therefore, Dustin skis 7.26 km if the angle measures 3 radians.

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(a) Prove that the symbol < defines a relation on Z that is transitive but not reflexive and not symmetric. (b) Is < an antisymmetric relation? Prove your answer.

Answers

The relation R is transitive even if it is neither reflexive nor symmetric.

(a) If A=[5,6,7], then define a relation R on A as R=(5,6),(6,5).

The reflexivity of Relation R differs from that of (5,5),(6,6),(7,7)/R).

As a result of (5, 6)R and (6, 5)R, R is now symmetric.

On the other hand, (5,5)/R/R is not transitive.

R is hence symmetric but neither reflexive nor transitive: "(5,6), "(6,5)".

(b) Consider the relation R in the statement R, which is written as R=(a,b):ab.

We have (a,a) / R for any a because a cannot be strictly less than an itself. In reality, a=a.

R has no reflex.

Right now, (1,2)R(as12)

But two is not one less than one.

There is no symmetry in the ratio (2,1)/R.

Now, let (a,b),(b,c)R.

"A,B, and C" is a transitive verb.

As a result, relation R is transitive even if it is neither reflexive nor symmetric.

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HELP
A sequence of transformations will be performed on a triangle to create its image. A combination of rotations, reflections, and/or translations will be chosen for the sequence.
Which statement about the triangles is true?

1. Answer choice : The triangles will be congruent, no matter which types of transformations are chosen for the sequence.

Answers

The statement "The triangles will be congruent, no matter which types of transformations are chosen for the sequence" is false.

What is Sequence?

In mathematics, a sequence is a collection of numbers or other mathematical objects that are listed in a specific order. The individual numbers in a sequence are called terms, and the position of each term in the sequence is called its index or subscript.

The choice of transformations can affect whether the triangles are congruent or not. For example, if only translations are used, the resulting triangle will be congruent to the original triangle. Similarly, if a combination of rotation(s) and reflection(s) are used, the resulting triangle may also be congruent to the original triangle.

Therefore, the type and order of transformations used can affect whether the resulting triangles are congruent or not.

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Suppose you are in Watson Lake, Yukon. For a Notebook computer: Regular price $1598,
now 20% off

a) Calculate the discount.

b) Calculate the sale price, before taxes.

c) Calculate the sale price, including taxes. (GST 5% only)​

Answers

b because i took the test

Answer:

Step-by-step explanation:

a) The discount is 20% of the regular price, which is:

Discount = 20% x $1598 = $319.60

b) The sale price before taxes can be calculated by subtracting the discount from the regular price:

Sale price before taxes = Regular price - Discount

Sale price before taxes = $1598 - $319.60

Sale price before taxes = $1278.40

c) To calculate the sale price including taxes, we need to add the GST of 5% to the sale price before taxes:

Sale price including taxes = Sale price before taxes + (GST x Sale price before taxes)

Sale price including taxes = $1278.40 + (0.05 x $1278.40)

Sale price including taxes = $1278.40 + $63.92

Sale price including taxes = $1342.32

Therefore, the sale price including taxes is $1342.32.

A baseball team received a discount on each hat purchase. the team buys 14 hats total for a total of 14(d-3) dollars. how much does the team pay for each hat

Answers

The team pays d - 3 dollars for each hat after the discount.

What is Cost?

Cost is the amount of money required to purchase or produce a particular item or service. It is often represented by the symbol "C" in mathematical equations.

According to the given information:

Let's start by breaking down the given information:

The team buys 14 hats in total.

The total cost for the 14 hats is 14(d-3) dollars.

The team received a discount on each hat purchase.

To find the cost of each hat, we need to divide the total cost by the number of hats:

cost per hat = total cost / number of hats

Plugging in the given values, we get:

cost per hat = 14(d-3) / 14

Simplifying the expression by canceling out the common factor of 14, we get:

cost per hat = d - 3

Therefore, the team pays d - 3 dollars for each hat after the discount.

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a water bottling facility has a mean bottling rate of 35.2 thousand bottles per hour with a standard deviation of 2.04 thousand bottles. a nearby cola bottling facility has a mean bottling rate of 26.9 thousand bottles per hour with a standard deviation of 1.51 thousand bottles. one wednesday from noon to 1:00 p.m., the water bottling facility bottled 37.4 thousand bottles of water, and the cola bottling facility bottled 28.8 thousand bottles of cola. which facility increased their efficiency more during that hour?

Answers

During that hour, the cola bottling facility increased their efficiency more compared to the water bottling facility.To determine which facility increased their efficiency more during that hour, we need to calculate the deviation from the mean for each facility.

For the water bottling facility, the deviation is calculated as:
(37.4 - 35.2) / 2.04 = 1.08
For the cola bottling facility, the deviation is calculated as:
(28.8 - 26.9) / 1.51 = 1.26
Since the deviation for the cola bottling facility is higher, this means that they had a larger increase in efficiency during that hour compared to the water bottling facility.
To determine which facility increased their efficiency more during that hour, we will calculate the number of standard deviations away from the mean for each facility's performance.
1. Calculate the deviations for each facility:
Water bottling facility:
Deviation = (Actual bottles - Mean bottles) / Standard deviation
Deviation = (37.4 - 35.2) / 2.04
Deviation ≈ 1.08
Cola bottling facility:
Deviation = (Actual bottles - Mean bottles) / Standard deviation
Deviation = (28.8 - 26.9) / 1.51
Deviation ≈ 1.26
2. Compare the deviations:
The cola bottling facility has a higher deviation (1.26) than the water bottling facility (1.08).
Conclusion:
During that hour, the cola bottling facility increased their efficiency more compared to the water bottling facility.

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I need answer ASAP
Thanks if you help!!

Find the circumference of the circle

Answers

Circumference of a circle =2pie*radius
C=2*3.142*14
C=87.976m

Six points have these coordinates 1 2 4 6 5.6 5.6 4.7 4.5 3.8 3.1 2.8 Portions of the MINITAB printout are shown here The regression equation is y = 6.03-0.557 x Predictor Coef 6.0333 -0.55714 SE Coef 0.1587 0.04074 38.03 -13.68 0.001 0.003 Constant Predicted Values for New Observations New Obs 1 MINITAB Output 5.1762) 2.1206) Fit 95.0% PI SE Fit 4.9190 0.0926 1.5762 0.1961 95.0% c (4.6619, (1.0317, (4.3805, (0.8548 5.4576) 2.2975) X denotes a point that is an outlier in the predictors. Values of Predictors for New Observations New Obs 1 2.00 8.00(a) Find a 95% confidence interval for the average value of y when x = 2. (Enter your answers to four decimal places.)
(b) Find a 95% prediction interval for some value of y to be observed in the future when x = 2. (Enter your answers to four decimal places.)

Answers

A. the 95% confidence interval for the average value of y when x = 2 is (4.9241, 5.4283).
B. The 95% prediction interval for some value of y to be observed in the future when x = 2 is (4.6619, 5.4576).

(a) To find a 95% confidence interval for the average value of y when x = 2, use the provided information:

Predicted Value for New Obs 1 (x = 2): 5.1762
SE Fit: 0.0926

Now, apply the formula for confidence intervals:

CI = Predicted Value ± (t-value * SE Fit)

For a 95% confidence interval and degrees of freedom = 4 (6 points - 2 parameters), the t-value is approximately 2.776 (using a t-table).

CI = 5.1762 ± (2.776 * 0.0926)

CI = (5.1762 - (2.776 * 0.0926), 5.1762 + (2.776 * 0.0926))
CI = (4.9241, 5.4283)

So, the 95% confidence interval for the average value of y when x = 2 is (4.9241, 5.4283).

(b) To find a 95% prediction interval for some value of y to be observed in the future when x = 2, use the information provided:

95.0% PI: (4.6619, 5.4576)

The 95% prediction interval for some value of y to be observed in the future when x = 2 is (4.6619, 5.4576).

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find the value of x please !!!

Answers

Answer:

the value of x is 11.333 aproximate to 11.3

Step-by-step explanation:

71° = (9X + 40) /2

71° ×2 = 9X + 40 ........ crisscros it

142° = 9X + 40

142-40 = 9X

9X = 102

X = 102/ 9

X = 11.333 ~ 11.3

let y=f(x) be the particular solution to the differential equation dy/dx=x^2 + 1/ e^y with the initial condition f(1)=0. what is the value of f(2) ? 1.253 1.253 1.466 1.466 2.197 2.197 2.303

Answers

The closest value among the given options to ln(17/3) is 1.466. The value of f(2) is approximately 1.466.

To find the value of f(2), we need to first solve for the particular solution y=f(x) using the given differential equation and initial condition.

We can rewrite the differential equation as dy/dx = x^2 + e^(-y). Separating variables and integrating both sides, we get:

∫e^y dy = ∫x^2 dx + C
e^y = (1/3)x^3 + C
y = ln[(1/3)x^3 + C]

Using the initial condition f(1) = 0, we can solve for the constant C:

0 = ln[(1/3)(1)^3 + C]
C = -1/3

Thus, the particular solution is:

y = ln[(1/3)x^3 - 1/3]

To find f(2), we plug in x=2 into the equation above:

f(2) = ln[(1/3)(2)^3 - 1/3] = ln[8/3 - 1/3] = ln(7/3) ≈ 1.253

Therefore, the value of f(2) is approximately 1.253.
To find the value of f(2) for the given differential equation dy/dx = x^2 + 1/e^y with the initial condition f(1) = 0, first, we need to solve the equation. Since it is a first-order, nonlinear, separable differential equation, we can rewrite it as:

e^y dy = (x^2 + 1) dx

Now, integrate both sides:

∫e^y dy = ∫(x^2 + 1) dx

e^y = (1/3)x^3 + x + C

Apply the initial condition f(1) = 0:

e^0 = (1/3)(1)^3 + 1 + C
1 = 4/3 + C
C = -1/3

So, the particular solution is:

e^y = (1/3)x^3 + x - 1/3

To find f(2), solve for y when x = 2:

e^y = (1/3)(2)^3 + 2 - 1/3
e^y = 8/3 + 2 - 1/3
e^y = 17/3

Now, find the natural logarithm of both sides:

y = ln(17/3)

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how many ways are there to choose 10 coins from a piggy bank containing 100 identical pennies and 80 identical nickels? hint: use combinations with repetition group of answer choices c(180,10) c(10010) c(80,10) c(100,10) * c(80,10) c(11,1)

Answers

There are 11 ways to choose 10 coins from a piggy bank containing 100 identical pennies and 80 identical nickels.

To determine how many ways there are to choose 10 coins from a piggy bank containing 100 identical pennies and 80 identical nickels, you need to use combinations with repetition.

Since there are two types of coins (pennies and nickels), we can use the formula:

C(n + r - 1, r)

where n represents the number of types of coins (2 in this case), and r represents the number of coins we want to choose (10 in this case).

So, the formula becomes:

C(2 + 10 - 1, 10) = C(11, 10)

Calculating the combination, we get:

C(11, 10) = 11! / (10! * (11 - 10)!) = 11

Therefore, there are 11 ways to choose 10 coins from a piggy bank containing 100 identical pennies and 80 identical nickels.

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Let F be a field. Recall the definition of the gcd in F[x]: a gcd of a(x), b(x) is a common divisor of a(x) and b(x) in F[x] that is divisible by every common divisor in F[x].Show that if d(x) ∈ F[x] is a gcd of a(x), b(x), then so is c · d(x) for every nonzero c ∈ F.Conversely, show that every gcd of a(x), b(x) has the form c · d(x) for some nonzero c ∈ F.

Answers

g(x) and d(x) are associates in F[x], which means there exists a nonzero c ∈ F such that g(x) = c · d(x). Thus, every gcd of a(x) and b(x) has the form c · d(x) for some nonzero c ∈ F.

First, let's prove that if d(x) is a gcd of a(x) and b(x), then c · d(x) is also a gcd of a(x) and b(x) for every nonzero c ∈ F.

Let e(x) be a common divisor of a(x) and b(x) in F[x]. Then we have:

a(x) = e(x) q(x)

b(x) = e(x) r(x)

for some q(x), r(x) ∈ F[x]. Since d(x) is a gcd of a(x) and b(x), we have d(x) | e(x), which means there exists a polynomial s(x) ∈ F[x] such that e(x) = d(x) s(x). Therefore,

a(x) = d(x) s(x) q(x) = c · d(x) (s(x) q(x))

b(x) = d(x) s(x) r(x) = c · d(x) (s(x) r(x))

which shows that c · d(x) is also a common divisor of a(x) and b(x). Since this holds for every nonzero c ∈ F, we can conclude that c · d(x) is a gcd of a(x) and b(x).

Next, we need to show that every gcd of a(x) and b(x) has the form c · d(x) for some nonzero c ∈ F. Let g(x) be a gcd of a(x) and b(x), and let d(x) be another gcd of a(x) and b(x). Then we have:

g(x) | d(x) (since d(x) is also a gcd of a(x) and b(x))

d(x) | g(x) (since g(x) is a gcd of a(x) and b(x))

Therefore, g(x) and d(x) are associates in F[x], which means there exists a nonzero c ∈ F such that g(x) = c · d(x). Thus, every gcd of a(x) and b(x) has the form c · d(x) for some nonzero c ∈ F.

Combining these two results, we can conclude that if d(x) is a gcd of a(x) and b(x), then so is c · d(x) for every nonzero c ∈ F, and conversely, every gcd of a(x) and b(x) has the form c · d(x) for some nonzero c ∈ F.

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what is x in this equation? 5^2x -3 = 622

Answers

i found that x is 25.

hope that helps. went ahead and did the solution so you could see the steps

The quotient of a number and negative five increased by negative seven is three

Answers

The unknown number is -50.

How to find the unknown number?

Let's start by translating the given statement into an equation.

"The quotient of a number and negative five" can be written as x/(-5), where x is the unknown number. "Increased by negative seven" means we add -7 to this expression. Finally, we are told that this expression is equal to three. Putting it all together, we get:

x/(-5) - 7 = 3

We can simplify this equation by adding 7 to both sides:

x/(-5) = 10

Multiplying both sides by -5, we get:

x = -50

So the unknown number is -50.

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Evaluate using direct substitution.

Answers

Answer:

Step-by-step explanation:

f(-1) = 14


Find the volume of the cube.

Answers

Answer:

0.064 mi³

Step-by-step explanation:

Volume of cube = s³

S = 2/5 mi

Let's solve

(2/5)³ = 0.064 mi³

So, the volume of the cube is 0.064 mi³

You are driving on a highway and are about 195 miles from a state border. You set your cruise control at 60 miles per hour and plan to turn it off within 35 miles of the border on either side. Find the minimum and maximum numbers of hours you plan to have cruise control on.

Answers

The minimum duration with cruise control activated is approximately 2.67 hours. The maximum time with cruise control activated is around 2.08 hours.

How to find the minimum and maximum numbers of hours you plan to have cruise control on.

Divide the maximum distance by the pace at which you are traveling to find the maximum time with cruise control on:

2.08 hours = 125 miles at 60 miles per hour

Hence, the maximum time with cruise control activated is around 2.08 hours.

To calculate the minimum time with cruise control turned on, multiply 195 miles by 60 miles per hour, which is 3.25 hours.

Subtract the time it would take you to drive 35 miles on either side of the border:

3.25 hours minus 0.58 hours (35 miles per hour x 60 miles per hour) equals 2.67 hours

Hence, the minimum duration with cruise control activated is approximately 2.67 hours.

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How many fewer minutes did Lizzie practice on Tuesday than on Monday?

Answers

The steps to use to solve the problem are:

Step 1: Understand the problemStep 2: Plan a solutionStep 3: Solve the problemStep 4: Look  at the answerStep 5: share the answer

Lizzie had practiced 15 fewer minutes on Tuesday than on Monday.

What is the time about?

Note that from the question:

T = Tuesday

M = Monday

So T = M - 15,  

70  = M - 15

Hence  M = 85 minutes.

B. If Lizzie were to worked out for 85 minutes on Monday as well as 70 minutes on Tuesday, so she practiced:

85 - 70

= 15

So  Lizzie had practiced 15 fewer minutes on Tuesday than that of Monday.

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See full question below

Assessment items Lizzie works out 15 fewer minutes on Tuesday than on Monday. She worked out 70 minutes on Tuesday. Use the five-step problem-solving plan. How many minutes did she work out on Monday?How many fewer minutes did Lizzie practice on Tuesday than on Monday?

There are 54 green chairs and 36 red chairs in an auditorium.
There are 9 rows of chairs. Each row has the same number of
green chairs and red chairs.
Explain how the number of green chairs and red chairs in
each row can be used to write an expression that shows
the total number of chairs in the auditorium.
Use the drop-down menus to complete the explanation.
To determine the number of green chairs and red chairs in each
row, Choose... 54 and 36 by 9.
The total number of chairs can be expressed as the product of
9 and the Choose... of the green chairs and red chairs in
each row. This is represented by the expression
Choose...

Answers

To determine the number of green chairs and red chairs in each row, divide 54 and 36 by 9.

The total number of chairs can be expressed as the product of

9 and the 6 of the green chairs and 4 red chairs in each row.

This is represented by the expression 9(6 + 4)

How to write equivalent expression?

Number of green chairs = 54

Number of red chairs = 36

Number of rows of chairs = 9

Number of green chairs in each row = 54/9

= 6

Number of red chairs in each row = 36/9

= 4

Ultimately, the expression can be written as 9(6 + 4)

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a hotelier thinks to welcome 565 guests but has overstated by 20 percent. how many guests does he actually welcome​

Answers

well, he didn't welcome 565, he's off by 20%, that means he really welcomed 80% of 565, because 100% - 20% = 80%, so

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{\textit{\LARGE a}\% of \textit{\LARGE b}}\\ \cline{1-1} \\ \left( \cfrac{\textit{\LARGE a}}{100} \right)\cdot \textit{\LARGE b} \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{80\% of 565}}{\left( \cfrac{80}{100} \right)565}\implies \text{\LARGE 452}[/tex]

The table below shows that the number of miles driven by Jamal is directly proportional to the number of gallons he used.
Gallons Used
Gallons Used
Miles Driven
Miles Driven
14
14
525
525
43
43
1612.5
1612.5
47
47
1762.5
1762.5
How many gallons of gas would he need to travel
296.25
296.25 miles

Answers

Jamal would need approximately 7.9 gallons of gas to travel 296.25 miles.

We can use the concept of direct variation to solve this problem. Direct variation means that two quantities are related by a constant ratio. In this case, the number of miles driven is directly proportional to the number of gallons used.

To find the constant of proportionality, we can use the given data. From the table, we can see that when Jamal used 14 gallons, he drove 525 miles. So we can write:

14/525 = k

where k is the constant of proportionality.

Solving for k, we get:

k = 14/525

Now we can use this value of k to find how many gallons Jamal would need to travel 296.25 miles. Let x be the number of gallons he would need. Then we can write:

x/296.25 = k

Substituting the value of k, we get:

x/296.25 = 14/525

Solving for x, we get:

x = (296.25 × 14) / 525

x ≈ 7.9

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Consider the following concentration-time data for the decomposition reaction AB→A+B.Time (min) 0 20 40 120 220[AB] 0.206 0.186 0.181 0.117 0.036Determine the value of the rate constant, k.Express your answer using three significant figures. (units= M/s)

Answers

To determine the value of the rate constant, we can use the integrated rate law for a first-order reaction, which is: ln([AB]₀/[AB]) = kt.



Where [AB]₀ is the initial concentration of AB, [AB] is the concentration at time t, k is the rate constant, and t is the time.
We can rearrange this equation to solve for k: k = (1/t) * ln([AB]₀/[AB]), We can use any set of data points to calculate k, but it's best to choose a set that gives a straight line when ln([AB]₀/[AB]) is plotted against time.

Let's use the first and second data points:
ln([AB]₀/[AB]) = ln(0.206/0.186) = 0.099
t = 20 min

k = (1/20 min) * 0.099 = 0.00495 min⁻¹
We can also use the other sets of data points to calculate k and check if the values are similar:

ln([AB]₀/[AB]) = ln(0.206/0.181) = 0.135
t = 40 min

k = (1/40 min) * 0.135 = 0.00338 min⁻¹
ln([AB]₀/[AB]) = ln(0.206/0.117) = 0.613
t = 120 min
k = (1/120 min) * 0.613 = 0.00511 min⁻¹

ln([AB]₀/[AB]) = ln(0.206/0.036) = 1.763
t = 220 min
k = (1/220 min) * 1.763 = 0.00801 min⁻¹

The values of k calculated using different sets of data points are similar, which indicates that the reaction is first-order. The average value of k is: k = (0.00495 + 0.00338 + 0.00511 + 0.00801) / 4 = 0.00536 min⁻¹

Therefore, the value of the rate constant is 0.00536 min⁻¹ or 5.36 × 10⁻³ min⁻¹ (rounded to three significant figures). The units of k are min⁻¹ because the time is in minutes and the concentration is in M. We can also express k in units of s⁻¹ by multiplying it by 60, which gives 0.322 s⁻¹ (rounded to three significant figures).

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I had $370. 0. My Mom gave $150. 0. My Dad gave $150. 0. My Aunt and Uncle gave me $100. 0. I had another $30. 0. How much did I have?

Answers

You had a total of 800.0 after receiving all the contributions.

To determine how much you have, simply add the amounts given by your mom, dad, aunt and uncle, and the additional 30.0.

Start with your initial amount:

370.0

Add the amount given by your mom:

150.0

Add the amount given by your dad:

150.0

Add the amount given by your aunt and uncle:

100.0

Add the additional 30.0

Now, let's calculate:

370.0 + 150.0 + 150.0 + 100.0 + 30.0 = 800.0

You had a total of 800.0 after receiving all the contributions.

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Hello anyone that can help me with these please

Answers

Answer:

13 (x= -2, y= 1)

14 (x=3, y= -4)

Step-by-step explanation:

1 x+5y=3

3x-2y=-8

u gonna add 3 into x and make it negative

2 -3x-15y=-9

3x-2y=-8

x will be gone since 3x-3x

3 -17y=-17

y= 1

going to add y into x+5y=3

x+5=3

x=-2

question 14

y=2x-10

y=-4x+8

add - to everything in the bottom

y=2x-10

-y=4x-8

0=6x-18

18=6x

3=x

add 3 into x in y=2x-10

y=6-10

y=-4

two roots of a cubic auxiliary equation are r1 = 2i and r2 = 5. what is a corresponding homogeneous differential equation with constant coefficients?

Answers

The corresponding homogeneous differential equation with constant coefficients is y''' - (4i + 5)y'' + 20iy' - 20y = 0, where y is the dependent variable and i is the imaginary unit.

Given that the roots of the cubic auxiliary equation are r₁ = 2i and r₂ = 5, we can write the equation as

(x - 2i)(x - 2i)(x - 5) = 0

Expanding this equation, we get

(x² - 4ix + 4)(x - 5) = 0

Simplifying further, we get

x³ - (4i + 5)x² + 20ix - 20 = 0

Therefore, the corresponding homogeneous differential equation with constant coefficients is

y''' - (4i + 5)y'' + 20iy' - 20y = 0

where y is the dependent variable and i is the imaginary unit.

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the temperature of points on an elliptical plate x2+y2+xy≤4 is given by the equation t(x,y)=16x2+y2. find the hottest and coldest temperatures on the edge of the elliptical plate.

Answers

The hottest temperature on the edge of the elliptical plate is 32 and the coldest temperature is 8.

How to find the hottest and coldest temperatures on the edge of the elliptical plate?

The edge of the elliptical plate is given by the equation [tex]x^2 + xy + y^2 = 4.[/tex]

To find the hottest and coldest temperatures on this edge, we need to find the maximum and minimum values of the function t(x,y) subject to this constraint.

One way to solve this problem is to use Lagrange multipliers. Let's define a new function F(x,y,λ) as follows:

[tex]F(x,y,\lambda) = 16x^2 + y^2 + \lambda(x^2 + xy + y^2 - 4)[/tex]

The critical points of F(x,y,λ) occur when the partial derivatives with respect to x, y, and λ are all equal to zero:

∂F/∂x = 32x + 2λx + λy = 0

∂F/∂y = 2y + 2λy + λx = 0

∂F/∂λ =[tex]x^2 + xy + y^2 - 4[/tex]= 0

Solving these equations simultaneously, we get:

[tex]x = \pm \sqrt(2), y = \pm \sqrt(2)[/tex], λ = 8/3

The function t(x,y) takes on its maximum value of 32 at the points [tex](\sqrt(2), \sqrt(2))[/tex] and [tex](-\sqrt(2), -\sqrt(2))[/tex] and its minimum value of 8 at the points [tex](\sqrt(2), -\sqrt(2))[/tex] and [tex](-\sqrt(2), \sqrt(2)).[/tex]

Therefore, the hottest temperature on the edge of the elliptical plate is 32 and the coldest temperature is 8.

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Help me with this question Please

Answers

Step-by-step explanation:

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Question 6 of 9
Jennifer spent $10.25 on supplies to make lemonade. At least how many glasses of lemonade must she sell
at $0.45 per glass to make a profit?
At most 4.61 glasses
At least 5 glasses
At least 23 glasses
O At most 22.78 glasses

Answers

To make a profit, Jennifer needs to earn more money from selling glasses of lemonade than she spent on supplies. Let's first calculate how much it costs to make one glass of lemonade:

Cost per glass = Total cost / Number of glasses
Cost per glass = $10.25 / x (where x is the number of glasses)

To make a profit, Jennifer needs to sell each glass for more than the cost per glass. If she sells each glass for $0.45, then her revenue for x glasses would be:

Revenue = Price per glass x Number of glasses
Revenue = $0.45 x

For Jennifer to make a profit, her revenue must be greater than her cost:

Revenue > Cost
$0.45 x > $10.25 / x

Multiplying both sides by x, we get:

$0.45 x^2 > $10.25

Dividing both sides by $0.45, we get:

x^2 > 22.78

Taking the square root of both sides, we get:

x > 4.77

Since Jennifer cannot sell a fraction of a glass, the smallest number of glasses she needs to sell to make a profit is 5. Therefore, the answer is At least 5 glasses.

calculus grades (1.6) the dotplot shows final exam scores for mr. miller’s 25 calculus students. a. find the median exam score.b. Without doing any calculations, would you estimate that the mean is about the same as the median, higher than the median, or lower than the median?

Answers

a. To find the median exam score, we need to arrange the scores in order from least to greatest. Then we find the middle score. In this case, the dotplot is not available, so I cannot provide the exact median score. However, once the scores are arranged in order, we can identify the middle score as the median.

b. Without doing any calculations, it is difficult to estimate whether the mean is about the same as the median, higher than the median, or lower than the median. However, if the distribution is roughly symmetric, we can expect the mean to be about the same as the median. If the distribution is skewed, then the mean will be pulled towards the tail of the distribution, and may be higher or lower than the median depending on the direction of the skew. Without additional information about the shape of the distribution, it is difficult to make an accurate estimate.

a. To find the median exam score, follow these steps:

1. Arrange the final exam scores from the dot plot in ascending order.
2. Since there are 25 students (an odd number), the median is the middle value. It is the 13th value in the ordered list.

b. Without doing any calculations, we can estimate if the mean is about the same as the median, higher, or lower based on the distribution of the scores. If the dot plot shows a symmetric distribution, the mean and median would be approximately equal. If the distribution is skewed to the right (with a few high scores pulling the average up), the mean would be higher than the median. If the distribution is skewed to the left (with a few low scores pulling the average down), the mean would be lower than the median. if the distribution is roughly symmetric, we can expect the mean to be about the same as the median.

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The equation of the line tangent to the differentiable and invertible function f(x) at the point (-1,3) is given by y = –2x + 1. Find the equation of the tangent line to f-1(x) at the point (3, -1).

Answers

The equation of the tangent line to f-1(x) at the point (3, -1) is y = 1/(-2) x - 1/2.

This is because the slope of the tangent line to f(x) at (-1,3) is -2, and since f(x) and f-1(x) are inverse functions, the slopes of their tangent lines are reciprocals.

Therefore, the slope of the tangent line to f-1(x) at (3,-1) is -1/2. To find the y-intercept, we can use the fact that the point (3,-1) is on the tangent line. Plugging in x=3 and y=-1 into the equation y = -1/2 x + b, we get b = 1/2. Therefore, the equation of the tangent line to f-1(x) at (3,-1) is y = 1/(-2) x - 1/2.

In summary, to find the equation of the tangent line to f-1(x) at a point (a,b), we first find the point (c,d) on the graph of f(x) that corresponds to (a,b) under the inverse function.

Then, we find the slope of the tangent line to f(x) at (c,d), take the reciprocal, and plug it into the point-slope formula to find the equation of the tangent line to f-1(x) at (a,b).

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