a. It is impossible for LCLX in an Xbar chart to be > an Upper Specification Limit. T_ F b. Statistical Tolerancing offers lower FTY over Worst Case Tolerancing. T /F
c. In Worst Case analysis, the probability of interference is > 0%. T F d. For sample sizes >> 30, o may be considered -s in SPC. T/F
e. For Cpk> 2, C charts are preferred for Statistical Process Control. T_ F f. If Cpk < 0, the process mean is still within the specification limits. T /f
g. Reducing assembly parts counts through DFM reduces OFD's. T/F
h. Defects are additive in a multi-step manufacturing process. T /F
i. FTY=1-DPU is valid for DPU's >0.5. T /F
j. Reducing the o of a process always increases the Cpk. T/F

Answer:

x = 8

Step-by-step explanation:

alternate-interior angles equal 180°

17x + 14 + 4x - 2 = 180

21x + 12 = 180

21x = 168

x = 8

Answer:

3x+4y=3

Step-by-step explanation:

Plug this in desmos graphing calculator.

For a discrete random variable X that is uniformly distributed over the numbers 1, 2, 3, ..., n, the expected value (EX) can be calculated as the average of all possible values of X. The variance (Var(X)) measures the spread or variability of the distribution.

The expected value and variance, we need to use the formulas for the mean and variance of a uniform distribution.

The expected value (EX) for a uniform distribution can be calculated as the average of all possible values of X. In this case, since X is uniformly distributed over the numbers 1, 2, 3, ..., n, the expected value can be found using the formula:

EX = (1 + 2 + 3 + ... + n) / n

Simplifying this expression, we get:

EX = (n + 1) / 2

The variance (Var(X)) of a uniform distribution can be calculated using the formula:

Var(X) = (n^2 - 1) / 12

where n is the total number of possible values.

Therefore, for a discrete random variable X that is uniformly distributed over the numbers 1, 2, 3, ..., n, the expected value is (n + 1) / 2, and the variance is (n^2 - 1) / 12. These formulas allow us to calculate the average and measure the spread of the distribution.

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Answer:

i think the answer is c but im not sure sorry if im wrong

Step-by-step explanation:

Answer: C

Step-by-step explanation:

just took the quiz

The conclusion based on the statement would be option C. Conclusion: A student taking the test in the afternoon has a greater chance of passing it than a student taking it in the morning.

Probability refers to a possibility that deals with the occurrence of random events.

The probability of all the events occurring need to be 1.

We need to Compare the probability that a student will pass the test in the morning with the probability that a student will pass the test in the afternoon.

The conclusion based on the statement would be;

C. P(pass morning) = 0.48

P(pass | afternoon) = 0.82

Conclusion: A student taking the test in the afternoon has a greater chance of passing it than a student taking it in the morning.

Therefore, the correct option is C.

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Answer:

1. 15

2. 16

3. 46

4. 59

Step-by-step explanation:

1. 44+30=74, 89-74=15

2. 90-74=16

3. 180-134=46

4. angles like that are the same

Answer:

1. x=5

2. x=16

3.x=46

4.x=59

Step-by-step explanation:

1. It says that the angle in total is 89 degrees (faded). then it shows the degrees 44 and 30. add them together to get 74 degrees. next subtract 89 by 74 to get the answer 5.

2. it shows a box at the corner of the angle (box means its a perfect 90 degree angle) so you need to subtract 90 by 74 to get the answer 16.

3. the whole entire angle is 180. so you need to subtract 134 from 180 to get the answer 46.

4. look focus on the one line that shows 59 degrees and right above it there is a blank. that arrow line represents 180 degrees. subtract 180 by 59 to get 121. next focus on the second line (the one that faces downward to the right) you then subtract 180 by 121 to get 59.

1.  44+30=74      89-74=5                 x=5

2.  box=90      90-74=16                   x=16

3. 180-134=46                                   x=46

4. 180-59=121    180-121=59             x=59

Answer:

12/5

Step-by-step explanation:

tan A = opp/adj

For angle theta, 12 is the opposite leg.

13 is the hypotenuse.

We were not given the length of the adjacent leg, but we can use the Pythagorean theorem to find it.

a^2 + b^2 = c^2

a^2 + 12^2 = 13^2

a^2 + 144 = 169

a^2 = 25

a = 25

The adjacent leg has a length of 5.

tan theta = opp/adj

tan theta = 12/5

Answer: 12/5

Answer:

x = 90 and 20 x 4 = 6x9 = k2 over -2

Answer:

Inequaltiy: 27 ≤ 14+c

Final answer: 13 ≤ c

Step-by-step explanation:

Well tony spent at most 27 dollars.

He spent 14 already and he can‘t get past 27 dollars but he can spend exactly 27 or even less.

So 27 ≤ 14+c

Answer:

B

Step-by-step explanation:

2 pi r subtracted by 2 pi r, you get answer

2 x 3.14 ~ 6.28, x 9 ~ 56.54.

2 x 3.14 ~ 6.28, x 8 ~ 50.24

56.54 - 50.24 ~ 6.3

Answer:

D. 2992 cubic inches of water

Step-by-step explanation:

Given data

Base Area= 187in^2

Height of 16 inches

The expression for the volume of a rectangular shaped tank is

V= Area*Height

substiute

V= 187*16

V=2992 in^3

Hence the volume is 2992 cubic inches of water

The required answer is  -

a. leaves a remainder of n² - 3n or (n - 6)(n + 7) ,the possible remainders are 0, 1, 4, 9, 5, 3

b .every n € Z that 121 | n² + 16n +20.

Explanation:-

(a) Remainder when n² + 16n + 20 is divided by 11:Let us first find out the value of n² + 16n + 20,n² + 16n + 20 = (n + 10)(n + 6) + 4As n and 11 are co-prime, by Fermat's Little Theorem, n¹⁰  ≡  1(mod 11)So, (n + 10)(n + 6) ≡ (n + 1)(n + 7) (mod 11)Hence, n² + 16n + 20 ≡ (n + 1)(n + 7) + 4 ≡ n² + 8n + 11 ≡ n² - 3n (mod 11).Therefore, when n² + 16n + 20 is divided by 11, it leaves a remainder of n² - 3n or (n - 6)(n + 7).

Thus, the possible remainders are 0, 1, 4, 9, 5, 3

(b) Prove that 121 | n² + 16n + 20 for every n ∈ Z . n ∈ Z, thenn² + 16n + 20 = (n + 8)² - 44(n + 8) + 324 = (n + 8 - 22)(n + 8 + 14) + 324= (n - 14)(n + 22) + 324.We know that 121 = 11² | (n - 14)(n + 22),

Therefore, 11 | (n - 14) or 11 | (n + 22)So, there exist k and l ∈ Z such that n - 14 = 11k or n + 22 = 11lWe have, n + 22 = n - 14 + 36Hence, n - 14 ≡ n + 22 (mod 11)If 11 | (n - 14), then 11 | (n + 22), if 11 | (n + 22), then 11 | (n - 14).Therefore, 121 | n² + 16n + 20. Thus, proved.

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The given quadratic expression is: $n^2 + 16n + 20$.

(a)We have to determine the possible remainders when this expression is divided by 11.

Let's solve for the remainder:$(n^2 + 16n + 20) \div 11$ $= \frac{(n + 8)^2 - 44}{11}$

We can write the given expression as $n^2 + 16n + 20 = (n + 8)^2 - 44$

Therefore,$\begin{aligned} (n^2 + 16n + 20) \div 11 & = \frac{(n + 8)^2 - 44}{11} \\ & = \frac{(n + 8)^2}{11} - 4 \end{aligned}$

For all possible values of $n$,

let's calculate the remainder of $\frac{(n + 8)^2}{11}$.

Let $a$ be the remainder when $n$ is divided by 11; then, $(n + 8) \div 11$ has a quotient of $q$ and a remainder of $r$. Therefore, $n + 8 = 11q + r$ $ \Right arrow n = 11q + r - 8$$\begin{aligned} n^2 & = (11q + r - 8)^2 \\ & = 121q^2 + r^2 + 64 + 22qr - 16q - 16r \end{aligned}$Let's now replace $n^2$

in the given expression:$(n^2 + 16n + 20) \div 11 = \frac{121q^2 + r^2 + 22qr - 16q + 6r + 64}{11}$

We have to find the remainders when $121q^2 + r^2 + 22qr - 16q + 6r + 64$ is divided by 11.

We observe that $121q^2$ is always divisible by 11, so we can ignore it.

We must find the remainders of $r^2 + 22qr + 6r + 64 - 16q$. $\begin{aligned} r^2 + 22qr + 6r + 64 - 16q & = r^2 + 2 \cdot 11qr + 11qr + 6r + 64 - 16q \\ & = (r + 11q)^2 + 6r - 16q + 64 \\ & = (r + 11q)^2 - 11(2q - r - 3) \end{aligned}$

The remainder is $r_0 = 11(2q - r - 3)$.

This remainder can take any value between $-10$ and $10$.

(b)We have to show that $121 | n^2 + 16n + 20$ for all integers $n$.We proved earlier that $n^2 + 16n + 20 = (n + 8)^2 - 44$.

We can restate this as $121 | (n + 8)^2 - 44$, which implies that $(n + 8)^2 - 44 = 121k$, where $k \in \mathbb{Z}$.Now we need to show that $k = \frac{n^2 + 16n + 20 - 121k}{121}$ is an integer.

Let's substitute $(n + 8)^2 - 44 = 121k$ into the given expression:$\begin{aligned} k & = \frac{(n + 8)^2 - 44}{121} \\ & = \frac{n^2 + 16n + 20 - 121k}{121} \\ & = \frac{n^2 + 16n + 20}{121} - k \end{aligned}$Thus, $k = \frac{n^2 + 16n + 20 - 121k}{121}$ is an integer for all $n \in \math bb{Z}$,

implying that $121 | n^2 + 16n + 20$ for all $n \in \math bb{Z}$.

Hence, we have proved that $121 | n^2 + 16n + 20$ for all $n \in \math bb{Z}$ using the method of mathematical induction.

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Answer:

C

Step-by-step explanation:

y=mx+b

3 = -2(3) + b

3 = -6 + b

9 = b

y = -2x + 9

2x + y = 9

Answer:

.

Step-by-step explanation:

The 90% confidence interval estimate for the overall difference in the percentages of Democrats and Republicans who prioritize protecting the environment is between X% and Y%.

To estimate the overall difference in the percentages of Democrats and Republicans who consider protecting the environment a top priority, we can use the concept of confidence intervals.

Confidence intervals provide a range of values within which we can be reasonably confident that the true population parameter lies. In this case, we want to estimate the difference in the proportions of Democrats and Republicans who prioritize protecting the environment.

The provided information states that in a random sample of 950 Democrats, 817 consider protecting the environment a top priority, while in a random sample of 800 Republicans, 384 share the same view. To construct a 90% confidence interval, we need to calculate the margin of error, which is determined by the sample sizes and proportions.

Using the formulas for the margin of error, we find that the margin of error is 3. With this information, we can state that we are 90% confident that the difference between the percentage of Democrats and Republicans who prioritize protecting the environment lies between X% and Y%.

The confidence interval estimate gives us a range within which we can reasonably expect the true difference to fall. However, it does not provide an exact value for the difference. The range allows for some uncertainty due to the sampling variability inherent in survey data.

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Answer:

22.8906 sq in

Step-by-step explanation:

SA of a sphere = 4 π [tex]r^{2}[/tex]

r = 2.7 / 2 = 1.35

4 x 3.14 x [tex]1.35^{2}[/tex] = 22.8906

Answer:

It’s a square-based pyramid

base(1) is the square on the bottom- ABCD

Faces(4) are the triangles on the sides eg- AED, DEC, CEB, BCA

There are 8 edges, four being at the bottom around the base and the other four being alone the faces

Finally there are 5 vertices, four being at the corners of the base and the fifth being the tip of the pyramid

Step-by-step explanation:

Answer:

50

Step-by-step explanation:

100÷1/2=50 so your answer would be 50

Let the number of children who rode the bus be C and the number of adults who rode the bus be A. Here's how to solve this problem:

Step-by-step explanation: We are given the following information:

Total number of passengers = 1000 Children's fare = $0.50. Adult fare = $1.75. Total revenue from fares = $1500. Let C be the number of children who rode the bus during the morning shift. Therefore, the number of adults who rode the bus will be (1000 - C). The total revenue from fares is given as:$0.50 × C + $1.75 × (1000 - C) = $1500. Simplifying this equation gives us: 0.5C + 1750 - 1.75C = 1500-1.25C = -250C = 200. Therefore, the number of children who rode the bus is C = 200. Therefore, the number of adults who rode the bus is:1000 - C = 1000 - 200 = 800.

Therefore, the number of adults who rode the bus during the morning shift is 800.

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Answer:

#1 - y = 2x

#2 - x is days for sale and y is times viewed

#3 - 80

#4 - 35

Step-by-step explanation:

a) The equation for the tangent at x = 0 is y - 2 = -42x.

(b) The equation for the tangent at x = 1 is y + 38 = -38x + 38.

(c) The equation for the tangent at x = 2 is y + 62 = -34x + 68.

(d) When x  = 1,the value of f(x) is -38.  This is the y-  coordinate of the point on the tangent line at x = 1.

To find the equations for the   tangents of the function f (x) = 2x² – 42x + 2 at specific points,we need to calculate the derivative of the function first. Let's differentiate f(x) with respect to x .

f(x ) =   2x² – 42x+ 2

f'(x) = d/  dx (2x²) – d/dx (42x)+ d/dx (2)

f'(x) = 4x – 42

So

(a) Tangent at x = 0  -

To find the equation for the tangent at x  = 0 we need to evaluate f'(x) at x = 0.

f'(0) = 4(0) – 42

f'(0) = -42

Since the slope of the tangent is -42 at x = 0, the equation of the tangent can be written in point-slope form using the point (0, f(0)).

Using f(0) = 2(0)² – 42(0) + 2 = 2, the equation for the tangent at x = 0 is -

y - 2 = -42(x - 0)

y - 2 = -42x

(b) Tangent at x = 1:

To find the equation for   the tangent at x = 1,we need to evaluate f'(x) at x = 1.

f'(1  ) =4(1) – 42

f'(1) = -38

Using f(1) = 2(1)² – 42(1) + 2 = -38, the equation for the tangent at x = 1 is  -

y + 38 = -38(x - 1)

y + 38 = -38x + 38

(c) Tangent at x = 2

To   find the equation for the tangent at x = 2,we need to evaluate f'(x) at x = 2.

f'(2) = 4(2) – 42

f'(2) = -34

Using f(2) = 2(2)^2 – 42(2) + 2 = -62, the equation for the tangent at x = 2 is:

y + 62 = -34(x - 2)

y + 62 = -34x + 68

(d)  To determine what is special about f when x = 1, we can evaluate the function at x = 1

f(1) = 2(1)² – 42(1) + 2

f(1) = -38

When x = 1,the value of f(x) is -38. This is the y  -coordinate of the point on the tangent line at x = 1. Therefore, the special property of f when x = 1 is that the function value is -38 at that point.

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Answer. 2, 3, 5, 7 , 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 179, 181, 191, 193, 197, 199

Step-by-step explanation:

There are 21 prime number between 100 and 200.

A number system is defined as a system of writing to express numbers.

A prime number is a whole number greater than 1 whose only factors are 1 and itself.

The prime numbers between 100 and 200 are

101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 179, 181, 191, 193, 197, 199.

One hundred one, one hundred three, one hundred seven, one hundred nine, One hundred thirteen, one hundred twenty seven, One hundred thirty one, one hundred thirty seven, one hundred thirty nine, one hundred forty nine, one hundred fifty one, one hundred fifty seven, one hundred sixty three,  one hundred sixty seven, one hundred seventy three, one hundred seventy  nine, one hundred eighty one, one hundred ninty one, one hundred ninty three, one hundred ninty seven, one hundred ninty nine.

There are no numbers  between 100 and 200 have 11 as a prime factor.

Hence there are 21 prime number between 100 and 200.

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Answer:YOUR ANSWER IS C

Step-by-step explanation:

Answer:

y=11/2x-10

20 character minimum

Answer:

It'll take 25 more minutes

Step-by-step explanation:

Answer: z= -0.5

Step-by-step explanation: mean m=120 and deviation s=10.

Z = (x-m)/s= (115-120)/10

Answer: z=−1.1

Step-by-step explanation:

z=\frac{x-\mu}{\sigma}

z=

σ

x−μ

​

z-score formula

z=\frac{104-115}{10}

z=

10

104−115

​

Plug in values

z=\frac{-11}{10}

z=

10

−11

​

Subtract

z=-1.1

z=−1.1

Divide

Answer:

(2,0)(0,2

(-1,-3)(-3,-1)

(-1,3) (1,0)

Step-by-step explanation:

The statement is false. The appropriate differential equation for the quantity Q of toxin in the tank is not given by dQ/dt = r (c/Vo).

In a tank problem with equal inflow and outflow rates and a constant input concentration c of a toxic substance, the appropriate differential equation for the quantity Q of toxin in the tank is dQ/dt = r(c - Q/Vo), where r is the inflow/outflow rate and Vo is the total volume of the mixture in the tank.

The term (c - Q/Vo) represents the difference between the input concentration and the concentration in the tank, scaled by the volume Vo. This equation accounts for the fact that the concentration in the tank changes over time due to the inflow of fresh mixture with concentration c and the outflow of the mixture with concentration Q/Vo.

Therefore, the correct differential equation is dQ/dt = r(c - Q/Vo), which reflects the balance between the inflow and outflow of the toxic substance and its accumulation or depletion in the tank.

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