A random sample of n = 145 items are selected for measurement. Nothing is known about the distribution of measurements. Are the requirements for constricting a confidence interval for the population mean satisfied? None of these No It depends Not enough information No answer text provided. Yes

The given null and alternative hypotheses, Hoi 3.1 and Ha 3.1, indicate that the hypothesis test is a two-tailed test.

In hypothesis testing, the null hypothesis (Hoi) represents the claim or assumption that is being tested, while the alternative hypothesis (Ha) represents the opposing claim or the hypothesis that the researcher is trying to support. The directionality of the test is determined by the alternative hypothesis.

In this case, the null hypothesis is stated as Hoi 3.1, and the alternative hypothesis is stated as Ha 3.1. Without knowing the specific details of the hypotheses, it can be determined that the test is two-tailed based on the notation used. The presence of two distinct hypotheses (Hoi and Ha) indicates that the test considers both directions of the distribution.

A two-tailed test is used when the alternative hypothesis does not specify a particular direction of the effect or relationship being tested. It is designed to determine whether the observed results are significantly different from the null hypothesis in either the positive or negative direction.

Therefore, the correct answer is A. Two-tailed test.

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The opposite sides are parallel.

Their angle measures add to 360°

Answer:

$360

Step-by-step explanation:

Find 3% of 500 = 15

Multiply 15 by 24 = 360

Step-by-step explanation:

In math the area of the parallelogram equal the base times the high

Where.....

A stand for (Area)

b stand for (Base)

h stand for (High)

Like shown in the photo above

I hope that is useful for you :)

Answer:

She will make a total commission of $1130+$325=$1445

Then 5% of $1445= $1445×5%=$72,75

Answer:

-84

Step-by-step explanation:

Since m=-4, we can plug -4 into the expression and use PEMDAS

7(m - 8)

7((-4)-8)

7(-12)

-84

Answer:

2×2×5×7=20×7=140

2×3×6×7=36×7=252

252+140=392

Answer:

y = -2x + 3

Step-by-step explanation:

If you do rise/run, you recognize that the slope of the line is -6/3, which = -2. You can also see that the y-intercept of the line is at 3.

The equation of a line is represented by y=mx+b, with m being the slope and b being the y-intercept value.

Just plug in -2 as m and 3 as b in y=mx + b, and you will get your answer.

Answer:

The correct answer would be D, it is a logarithmic function.

Step-by-step explanation:

Answer:

multiply 75.4 by 60 =4,524

Answer:

It's exponential

Step-by-step explanation:

a)  the inequality holds true for all values of n within the given range, we can conclude that for every integer n such that 0 ≤ n < 3, (n+1)² > n³

b) the inequality holds true for all values of n within the given range, we can conclude that for every integer n such that 0 ≤ n < 4, 2⁽ⁿ⁺²⁾ > 3ⁿ.

(a) To prove the statement for every integer n such that 0 ≤ n < 3, (n+1)² > n³ using proof by exhaustion, we will evaluate the inequality for each value of n within the given range.

For n = 0:

(0+1)² > 0³

(1)² > 0

1 > 0 - This is true.

For n = 1:

(1+1)² > 1³

(2)² > 1

4 > 1 - This is true.

For n = 2:

(2+1)² > 2³

(3)² > 8

9 > 8 - This is true.

Since the inequality holds true for all values of n within the given range, we can conclude that for every integer n such that 0 ≤ n < 3, (n+1)² > n³

(b) To prove the statement for every integer n such that 0 ≤ n < 4, 2⁽ⁿ⁺²⁾ > 3ⁿ using proof by exhaustion, we will evaluate the inequality for each value of n within the given range.

For n = 0:

2⁽⁰⁺²⁾ > 3⁰

2² > 1

4 > 1 - This is true.

For n = 1:

2⁽¹⁺²⁾ > 3¹

2³ > 3

8 > 3 - This is true.

For n = 2:

2⁽²⁺²⁾ > 3²

2⁴ > 9

16 > 9 - This is true.

For n = 3:

2⁽³⁺²⁾ > 3³

2⁵ > 27

32 > 27 - This is true.

Since the inequality holds true for all values of n within the given range, we can conclude that for every integer n such that 0 ≤ n < 4, 2⁽ⁿ⁺²⁾ > 3ⁿ.

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Answer:

x = -1 /2= -0.5 y = 15 /10= 1.5

The value of the line integral ∫c f · dr is -cos(1) i - sin(1) j + 1/6 k.

Evaluate the integral?

To evaluate the line integral ∫c f · dr, we need to substitute the given values of f(x, y, z) and r(t) into the integral expression.

[tex]f(x, y, z) = sin(x) i cos(y) j\ x(z) k[/tex]

[tex]r(t) = t^4 i - t^3 j + t k[/tex] ,  0 ≤ t ≤ 1

The line integral becomes:

[tex]\int c f * dr = \int c (sin(x) i cos(y) j x(z) k) * (dx i + dy j + dz k)[/tex]

Substituting [tex]x = t^4,\ y = -t^3, and\ z = t:[/tex]

[tex]\int c f * dr = \int c (sin(t^4) i cos(-t^3) j (t^4)(t) k) * (4t^3 dt i - 3t^2 dt j + dt k)[/tex]

Simplifying the expression:

[tex]\int c f * dr = \int c (4t^3 sin(t^4) dt i - 3t^2 cos(t^3) dt j + t^5 dt k)[/tex]

Integrating each component separately:

[tex]\int c f * dr = (\int 0^1 4t^3 sin(t^4) dt) i - (\int 0^1 3t^2 cos(t^3) dt) j + (\int 0^1 t^5 dt) k[/tex]

Evaluating each integral:

[tex]\int c f * dr = [-(cos(t^4))][/tex] evaluated from 0 to [tex]1 i - [sin(t^3)][/tex] evaluated from 0 to [tex]1 j + [t^6/6][/tex] evaluated from 0 to 1 k

Simplifying the expression:

[tex]\int c f * dr = -cos(1) i - sin(1) j + 1/6 k[/tex]

Therefore, the value of the line integral  [tex]\int c f * dr\[/tex]  is  [tex]-cos(1) i - sin(1) j + 1/6 k.[/tex]

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The derivative of the function y = x(6x + 1)⁵ is: dy/dx = (6x + 1)⁵ + 30x(6x + 1)⁴

To find the derivative of the given function, we can apply the rules of differentiation. Using the product rule, we differentiate each term separately and then add them together.

For the first term x, the derivative is simply 1.

For the second term (6x + 1)⁵, we apply the chain rule. The derivative of (6x + 1)⁵ with respect to x is 5(6x + 1)⁴ multiplied by the derivative of the inner function 6x + 1, which is 6.

Multiplying these derivatives together, we get (6x + 1)⁵ * 6 = 6(6x + 1)⁵.

For the third term x(6x + 1)⁴, we again apply the product rule. The derivative of x is 1, and the derivative of (6x + 1)⁴ is 4(6x + 1)³ multiplied by the derivative of the inner function 6x + 1, which is 6.

Multiplying these derivatives together, we get x * 4(6x + 1)³ * 6 = 24x(6x + 1)³.

Finally, we add the derivatives of each term to get the derivative of the entire function: dy/dx = (6x + 1)⁵ + 30x(6x + 1)⁴.

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Complete question:

Use the rules of differentiation to find the derivative of the function y= x(6x + 1)⁵

(6x + 1)⁵ + 30x(6x + 1)⁴

(6x + 1)⁴ (36x + 1)

x-1/6

No correct answer provided.

Step-by-step explanation:

Nsjssjsjsjshsnmsksjnsnsns

hola'

your answer is going to be 2.22 or 0.002 i think .

Answer:

0.75

Step-by-step explanation:

There are 3 favorable outcomes (pink, green, or blue).

There are 4 possible outcomes since there are 4 equal sectors.  

​

P(not purple)=3/4 =0.75

Answer:

Did this help?

Step-by-step explanation:

Answer:

2/5x7

Step-by-step explanation:

Answer:

C. and D.

Step-by-step explanation:

The root of √x is either equal or bigger than 9

Answer:

See Explanation

Step-by-step explanation:

The question is not clear. However, I will treat the question as:

[tex](26)x = 1[/tex]

[tex](50)x = 1[/tex]

and:

[tex](2^6)^x = 1[/tex]

[tex](5^0)^x = 1[/tex]

Solving: [tex](26)x = 1[/tex]  and  [tex](50)x = 1[/tex]

[tex](26)x = 1[/tex]

Divide both sides by 26

[tex]x = \frac{1}{26}[/tex]

[tex](50)x = 1[/tex]

Divide both sides by 50

[tex]x = \frac{1}{50}[/tex]

Solving [tex](2^6)^x = 1[/tex] and [tex](5^0)^x = 1[/tex]

[tex](2^6)^x = 1[/tex]

Express 1 as 2^0

[tex](2^6)^x = 2^0[/tex]

Remove bracket

[tex]2^{6x} = 2^0[/tex]

Cancel out 2

[tex]6x = 0[/tex]

Divide both sides by 6

[tex]x = \frac{0}{6}[/tex]

[tex]x = 0[/tex]

[tex](5^0)^x = 1[/tex]

Express 1 as 5^0

[tex](5^0)^x = 5^0[/tex]

Cancel out 5^0

[tex]x = 1[/tex]

Answer:

B

Step-by-step explanation:

Answer:

19

Step-by-step explanation:

ngl its kinda easy 5(2)+3(3) = 10+9 = 19

Answer:19

Step-by-step explanation:5x2=10+3x3=9 so 10+9=19

Answer:

You did not take the picture correctly, try taking it again

Step-by-step explanation:

I can’t seeeee

The function f(x) is discontinuous at x = 0 and x = 1.To determine the points of discontinuity, we need to look at the different intervals defined by the function.

At x = 0, the function has different definitions for the left and right sides of the point. For x < 0, f(x) = x + 3, and for x ≥ 0 and x ≤ 1, f(x) = 3x^2. Therefore, at x = 0, f(x) is discontinuous. It is continuous from the left (approaching from x < 0) and from the right (approaching from x > 0).

At x = 1, the function has different definitions for the left and right sides of the point. For x ≤ 1, f(x) = 3x^2, and for x > 1, f(x) = 3 - x. Therefore, at x = 1, f(x) is discontinuous. It is continuous from the left (approaching from x ≤ 1) and from the right (approaching from x > 1).

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a. the Laplace transform of a(t) is (28/s^2) + (3/s) + (4/s). b. the Laplace transform of b(t) is 5/s - 10/(s + 2) - 10/(s^3 + 2s^2).

a. To find the Laplace transform of a(t) = 28t + 3 + 4u(t), where u(t) is the unit step function, we can apply the linearity property and the transform of elementary functions.

Applying the linearity property, we can split the transform into three parts:

L{28t} + L{3} + L{4u(t)}

Using the transform of t (L{t} = 1/s^2), we get:

28/s^2 + 3/s + 4/s

Simplifying, we can combine the terms:

(28/s^2) + (3/s) + (4/s)

Therefore, the Laplace transform of a(t) is:

(28/s^2) + (3/s) + (4/s).

b. To find the Laplace transform of b(t) = 5 - 5e^(-2t)(1 + 2t), we can again apply the linearity property and the transform of elementary functions.

Applying the linearity property, we can split the transform into two parts:

L{5} - L{5e^(-2t)(1 + 2t)}

The transform of 5 is simply 5/s.

For the second part, we need to use the transform of e^(-at) and t.

The transform of e^(-at) is 1/(s + a), and the transform of t is 1/s^2.

Using these formulas, we get:

-5/(s + 2)(1 + 2/s^2)

Simplifying and combining terms, we have:

5/s - 10/(s + 2) - 10/(s^3 + 2s^2)

Therefore, the Laplace transform of b(t) is:

5/s - 10/(s + 2) - 10/(s^3 + 2s^2).

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