Answer:
[tex]K=58.8N/m[/tex]
Explanation:
From the question we are told that:
Mass [tex]M=0.442[/tex]
Drop distance [tex]d=0.150[/tex]
Generally the equation for Spring Constant is mathematically given by
[tex]K=\frac{2mg}{x}[/tex]
[tex]K=\frac{2*0.442*9.8}{1.150}[/tex]
[tex]K=58.8N/m[/tex]
What would happen to the distance between the bright fringes produced by a diffraction grating if the entire interference apparatus (light source, grating, and screen) were immersed in water
Answer:
Since the wavelength would be reduced by the factor of N where N is the index of refraction, fringes would be be closer to one another.
(Similar to the difference of fringes of red light and blue light.)
A radio station broadcasts at a frequency of 600 kHz. Knowing that radio waves have a speed of 300 000 000 m/s, what is the wavelength of
these waves?
Answer:
ccvtesgdujtdchgdrgggggggfrrrtyfaasdddfffghgdshh
Which type of electromagnetic radiation is responsible for the colors of
objects?
O A. Radio waves
O B. X-rays
O C. Visible light
O D. Ultraviolet radiation
Answer:
C. Visible light
Explanation:
Visible light is responsible for the colors of objects.
Hope it will help :)❤
Warm air is less dense than cold air. The same is true of water. You decide to take a bath and turn on both the hot and cold faucets. When the tub is one-third full, you dip your hand in and discover the water is too cold. You turn the cold water faucet off and keep the hot water turned on. You leave the hot water running for ten minutes. When you return and dip your hand in, you discover that the water in the tub is different temperatures in different places. It is too hot close to the faucet and in a top layer across the entire tub. When you sit down, however, the water in the bottom of the tub is cold. Explain how this happens and why: • how the hot water ended up in a layer on the top and near the faucet. • why this is or is not a transfer of heat. • how the temperature of the water in the tub will change over time. • why you will eventually want to get out of the tub, considering the air and your porcelain enameled steel tub.
Answer:
Given that the warm water is less dense than the cold water, we have;
The cold water which is more dense than the warm water will remain settled in the lower part of the tub while particles of the less dense warm water will move above the cold water not being able to penetrate lower due of difference in their gravitational potential energiesThis is a case of (lack of) heat transfer due to inability of heat to penetrate into the lower layers and transfer the heat by conduction, from particle to particle, and therefore, one layer, the top remains warm while the other layer, the lower layer, remains coldWith time (over an hour) more and more warm water units will be able to penetrate deeper and make the lower layer warmer while the warm water at the top loses heat by evaporation to the atmosphere, until the entire water reaches equilibriumHeat will continue to be lost by evaporation to the air and by conduction through the porcelain to the steel tub until the water in the tub becomes coldExplanation:
Can you guys please like my spotify playlist
Answer:
sure
Explanation:
Answer:
uhm ok
Explanation:
A train moving west with an initial velocity of 20 m/s accelerates at 4 m/s2 for 10 seconds. During this time, the train moves a distance of
meters.
Answer:
400 m
Explanation:
Use s=ut+1/2at^2
Answer:
400 mExplanation:
When will you say a body is in (i) uniform acceleration? (ii) non-uniform
acceleration?
Answer:
Explanation:
A body is said to be in uniform acceleration if change in velocity with respect to time is the same in equal time interval .
A body is said to be in non uniform acceleration if change in velocity with respect to time is not the same in equal time interval.
Is there any difference between antimatter, dark matter, dark energy, and degenerate matter?
pakisagutan po need ko na yan ngayon
*answer this please*
Explanation:
antimatter - counterpart of ordinary matter; identical in every way except for charge. Examples are positrons (counter to electrons) and antiprotons (counter to protons). Direct contact between matter and antimatter results in total annihilation accompanied by huge radiation output.
dark matter - hypothesized as the non-visible or not directly observable kind of matter that could explain some of the unusual behavior of stars and galaxies.
dark energy - hypothesized to be some kind of a repulsive force like anti-gravity that could explain the apparent accelerated rate of expansion of the universe.
degenerate matter - a very dense form of matter made up of fermions (like protons and neutrons) only. Some stars are believed to be made of degenerate matter.
Answer:
Yes. Although the names sound vague and almost fictional, the types of matter called antimatter, dark matter, dark energy, and degenerate matter are all different, specific entities that really exist in our universe. ... Antimatter is just regular matter with a few properties flipped, such as the electric charge.
#Captainpower
One pot has a water height of 8cm. Calculate the water pressure at the bottom of the pot. They give g = 10N / kg p = 1000kg / m3
Answer:
P = 800 Pa
Explanation:
The pressure of water at the bottom of the pot can be given by the following formula:
[tex]P = \rho g h[/tex]
where,
P = Pressure at the bottom of the pot = ?
ρ = density = 1000 kg/m³
h = height of water = 8 cm = 0.08 m
Therefore,
[tex]P = (1000\ kg/m^3)(10\ m/s^2)(0.08\ m)[/tex]
P = 800 Pa
La resistividad de cierto alambre es 1.72x10 -8 Ωm a 20 oC .Una batería de 6v se conecta a una bobina de 20 m de este alambre, con un diámetro de 0.8 mm. ¿Cuál es la corriente en el alambre?
Answer:
i = 1.09 10⁴ A
Explanation:
For this exercise we will look for the resistance of the wire
R = ρ L / a
the area of the wire is
a =ππ r² = π πd² / 4
we substitute
R = ρ L 4 / π d²
R = 1.72 10⁻⁸ 20 4/π 8 10⁻⁴
R = 5.47 10⁻⁴ Ω
to calculate the current we use ohm's law
V = R i
i = V / R
i = 6 / 5.47 10⁻⁴
i = 1.09 10⁴ A
During a Buckeye football game, the quarterback throws a ‘long bomb' to a wide receiver. During it's flight, the ball reached a maximum height of 15 m [U] before it started falling back down, and during this time flew 30m [E], where it was caught. The receiver then ran it another 15 m [E] for a touchdown. A) Determine the distance and displacement experienced in the up-down dimension by the ball b) Determine the distance and displacement experienced by the ball in the east-west dimension.
Answer:
A) The distance traveled by the ball in the Up-down dimension is 30 m
The displacement of the ball in the up-down direction is 0 m
B) The distance the ball travels in the east west direction is 45 m [East]
The displacement of the ball is the east-west direction is 45 m [East]
Explanation:
The long measures of the ball motion are;
The maximum height reached = 15 m Up
The horizontal distance traveled by the ball during flight = 30 m East
The distance the receiver ran with the ball after the ball was caught = 15 m East
A) The distance traveled by the ball in the Up-down dimension = 15 m up + 15 m backdown = 30 m in the up-down direction
The displacement of the ball in the up-down direction, d = 15 m + (-15 m) = 0 m
B) The distance the ball travels in the east west direction = 30 m [E] + 15 m [E] = 45 [E]
The displacement of the ball is the east-west direction, d = 30 m + 15 m = 45 m [E].
Which is a problem that results from global dependence on nonrenewable resources?
A. The supply of these resources will eventually run out.
B. The cost of obtaining these resources increases as supplies dwindle.
C. Unequal global distribution of these resources causes international conflicts.
D. All of the above are problems that result from global dependence on nonrenewable resources.
Between which two points did they travel fastest?
How can you tell this from the graph that they travelled fastest during that section?
plzzz helppp mee
Answer:
During the section CD , the speed is fastest.
Explanation:
The rate of change of distance is called speed.
Speed = distance / time
Its SI unit ism/s. It is a scalar quantity.
The slope of the distance time graph is given by the speed of the object.
Here, the speed of AB is 30/3= 10 m/s .
The speed of BC is = 0 m/s
The speed of CD is (50 - 30)/(6 - 5) = 20 m/s
So, the speed is maximum during the section CD.
are Car Travels certain distance with a speed of 50 kilometre per hour and returns with a speed of 40 kilometre per hour what is the average speed for the whole journey
Best answer branlist and NO LINKS
Answer:
The average speed for the whole journey is 44.[tex]\overline 4[/tex] kilometers per hour
Explanation:
The average speed with which the car travels the distance, v₁ = 50 kilometer per hour
The average speed with which the car returns, v₂ = 40 kilometer per hour
Average speed, v = (Total distance, d)/(Total time, t)
Let 'd' represent the distance travelled, we have;
The time it takes the car to travel to the distance = d/50 hours
The time it takes the car to return = d/40 hours
The total time = (d/50 hours + d/40 hours) = d·(40 + 50)/(40 × 50) hours= 9·d/200 hours
The total distance = d kilometers+ d kilometers = 2·d kilometers
The average speed for the whole journey, v = 2·d kilometers/(9·d/200 hours) = 400/9 kilometers per hours = 44.[tex]\overline 4[/tex] kilometer/hour.
According to the Hertzsprung-Russell diagram, a star with a very high luminosity and a temperature of around 9000 K is most likely which type of star?
A. Main Sequence Star
B. Giant
C. Supergiant
D. White Dwarf
Answer:
supergiant
Explanation:
Answer:
the picture
Explanation:
you can see i got it right :)
Usain bolt ran the 200m race within 19.19 seconds. Calculate the speed of Usain bolt during the race
Answer: [tex]10.42\ m/s[/tex]
Explanation:
Given
Usain Bolt ran the race with a length [tex]200\ m[/tex]
Time is taken to complete it [tex]t=19.19\ s[/tex]
We know, [tex]\text{Distance}=\text{speed}\times \text{time}[/tex]
Insert the values
[tex]\Rightarrow 200=v\times 19.19\\\\\Rightarrow v=\dfrac{200}{19.19}\\\\\Rightarrow v=10.42\ m/s[/tex]
So, the speed of Usain Bolt is [tex]10.42\ m/s[/tex]
a round asteroid has a surface gravity of 0.0288
If the mass of the asteroid is 1.10x10^18 kg, what is its radius??
Answer:
50473.45
Explanation:
(6.67×10^-11)(1.10×10^18)/(x)^2=0.0288.
answer: 5.047345 × 10^4 (50473.45)
Two astronauts push off each other in space. The 90 kg astronaut ends up with a speed of 5 ms. What is the mass of the other astronaut it he ended up with
a speed of 7 m/s?
Answer:
jsjshs
Explanation:
nsnajsajsnzbzbzbaba
ik its a lot but can u help
Answer:
your correct ans is D.
object float in liquid when its density is less than liquid and sinks when its density is more than liquid..
stay safe healthy and happy.An argon gas occupies 56.2 L at 760 torr. If the volume of gas dereases to 1/4 of the original volume ,calculate its final pressure
Answer:
3040 torr
Explanation:
Applying,
PV = P'V'..................... Equation 1
Where P = Initial Pressure, V = Initial volume, P' = Final pressure, V' = Final volume.
Make P' the subject of the equation
P' = PV/V'................. Equation 2
From the question,
Given: P = 760 torr, V = 56.2 L, V' = 56.2/4 = 14.05 L
Substitute these values into equation 2
P' = (56.2×760)/14.05
P' = 3040 torr
what is the power of a student that has done a work of 10 joules in 10 seconds
Answer:
1 Watt
Explanation:
P=W/t
P=10/10
P=1 Watt
When red light and green light are mixed, the color created is
Answer:
blue lighp
Explanation:
the magnetic field 0.100 m from a wire is 4.20x10^-5 T. what is the field 0.200 m from the wire
Answer:
Your answer is given below:
Explanation:
A 46.0 g golf ball is travelling with a velocity of 5.10 m/s. What is the kinetic energy of the golf ball
Answer:
[tex]0.598\:\mathrm{J}}[/tex]
Explanation:
The kinetic energy of a golf ball is given by [tex]KE=\frac{1}{2}mv^2[/tex].
Since the golf ball is given in grams, we must convert to kilograms, as the SI unit of mass is kilograms.
[tex]46.0\:\mathrm{g}=0.046\:\mathrm{kg}[/tex]
Substituting given values, we have:
[tex]KE=\frac{1}{2}\cdot 0.046\cdot 5.10^2=\boxed{0.598\:\mathrm{J}}[/tex]
Answer: not sure
Explanation:I'm not sure
Pop up spring Lab
Describe the energy conversion that took place. What energy was present just before the jump? What energy is present at its maximum height? What happens in between?
Draw bar charts of energy before the jump, while the spring toy is compressed and after the jump at the maximum height of its jump. Be sure to label each type of energy.
Answer:
I honestly don't know but that thing looks cool lol
In an electric circuit, 40 C of electric charge pass a point in 5.0 s.
What is the current in the circuit?
A 0.13A
B
8.0A
C 45A
D
200 A
Answer:
Explanation:
current=amount of charge/time taken
=40/5
=8 ampere(A)
The current flowing in the circuit is 8 A.
The correct answer to the question is Option B. 8 A.
Quantity of electricity, current and time are related by the following equation:
Q = ItWhereQ is the quality of electricity.
I is the current.
t is the time.
With the above formula, we can obtain the current in the circuit as illustrated below:Quantity of electricity (Q) = 40 C
Time (t) = 5 s
Current (I) =?Q = It
40 = I × 5
Divide both side by 5
I = 40 / 5
I = 8 AThus, the current in the circuit is 8 A.
The correct answer to the question is Option B. 8 A
Learn more: https://brainly.com/question/21690385
I WILL MARK YOU THE BRAINLIEST NO LINKS
What will happen if you heat a liquid to high temperatures?
It will become a solid.
It will become a plasma.
It will become a gas.
It will become a colloid.
Answer:
it becomes a gas
Explanation:
the matter expands, turning into steam, a gas.
Jorge tightens a bolt on his bicycle with a wrench that is 0.20 m long. If he pulls perpendicularly on the end of the wrench with a force of 140 N, how much torque does he apply ?
Answer:
28Nm
Explanation:
Torque is expressed as the prduct of force and radius
Given
Force = 140N
radius = 0.20m
Torque = 140 * 0.2
Torque = 140 * 1/5
Torque = 28Nm
Hence the amouunt of torque applied is 28Nm
The citizens of Paris were terrified during World War I when they were suddenly bombarded with shells fired from a long-range gun known as Big Bertha. The barrel of the gun was 36.6 m long, and it had a muzzle speed of 2.20 km/s. When the gun’s angle of elevation was set to 55.0°, what would be the range? For the purposes of solving this problem, ignore air resistance. (The actual range at this elevation was 121 km; air resistance cannot be ignored for the high muzzle speed of the shells.)
Answer:
464.1 km
Explanation:
Using R = u²sin2Ф/g where R = range of projectile, u = muzzle speed = 2.20 km/s = 2.20 × 10³ m/s, Ф = angle of elevation or projection angle = 55° and g = acceleration du° to gravity = 9.8 m/s²
Substituting the values of the variables into the equation, we have
R = u²sin2Ф/g
R = (2.20 × 10³ m/s)²sin2(55°)/9.8 m/s²
R = 4.84 × 10⁶ m²/s²sin110°/9.8 m/s²
R = 4.84 × 10⁶ m²/s² × 0.9397/9.8 m/s²
R = 4.548 × 10⁶ m²/s²/9.8 m/s²
R = 0.4641 × 10⁶ m
R = 464.1 × 10³ m
R = 464.1 km
Which of the following is an example of cultural diffusion?
A.
the spread of soccer as a sport across countries
B.
the use of acupuncture in the United States
C.
releasing old traditions after moving to a new country
D.
participating in the pop culture of one country while maintaining personal beliefs
Answer:
A. the spread of soccer as a sport across countries
Explanation: