No simple graph with six vertices and the above degrees exists.Graph with 6 vertices with degrees 0, 1, 2, 3, 4, 5.For a simple graph, the sum of the degrees of all vertices must be even.The resulting graph is also an Eulerian graph.
a) There exists a simple graph with 6 vertices, whose degrees are 2,2,2,3,4,4.
The given degrees 2, 2, 2, 3, 4, 4 sum up to 17, which is an odd number.
A simple graph with six vertices whose degrees are all even must have a sum of degrees of 6 × 2 = 12, which is even.
Therefore, no simple graph with six vertices and the above degrees exists.
b) There exists a simple graph with 6 vertices whose degrees are 0, 1, 2, 3, 4, 5.
The sum of degrees of vertices in a graph is twice the number of edges, so there are a total of 2 × (0 + 1 + 2 + 3 + 4 + 5) = 30 degrees in this graph.
For the graph to be simple, there can be a maximum of one vertex of degree 5 and one vertex of degree 0.
The graph may be formed by starting with a vertex of degree 5, and joining it to the vertices of degrees 4, 3, 2, 1, and 0 in turn.
The resulting graph is shown in the following figure:Graph with 6 vertices with degrees 0, 1, 2, 3, 4, 5
c) There exists a simple graph with degrees 1, 2, 2, 3.
The degree sequence has an odd sum, so no simple graph can have that degree sequence.
This is because, for a simple graph, the sum of the degrees of all vertices must be even.
d) A graph containing an Eulerian circuit is called an Eulerian graph.
If 61 and 62 Are Eulerian graph, and we add the following edges between them, then the resulting graph is Eulerian:6For 6 to be added as an edge to both 1 and 2, they must have even degree.
Since they were originally Eulerian graphs, each vertex already had even degree.
After 6 is added as an edge to both vertices, it becomes possible to start at one vertex and traverse the graph by using edges that have not been used before and eventually return to the starting vertex.
Hence, the resulting graph is also an Eulerian graph.
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(50 POINTS) Write out each sum.
Step-by-step explanation:
12. n^2+2n
if you insert 1 for k and then work up by inserting 2 for k and adding those together and stoping at n.
13. 8-2(2^n)
if you insert 3 for k and then work up by inserting 4 for k and adding those together and keep on going but stopping at n.
Hope that helps :)
MARK BRAINLIESTTTTTT
Answer:
i think its c hope it helps
Step-by-step explanation:
Calculate each value for ⊙P. Use 3.14 for π and round to the nearest tenth.
please help!! will mark brainliest!!
Answer:
226.19 inches
Step-by-step explanation:
What is the Median for the Box & Whisker Plot below?
HELP PLEASEE
Answer:
20
Step-by-step explanation:
13. What is the quadratic function that has a graph that contains the points
{(-1,8), (0,5),(1,0))?
A g(x) = -x2 - 4x + 5
B g(x) = -x2 +5
C g(x) = -x2 + 7x + 5
D g(x) = -x2 + 4x + 5
Answer: D, i am a hight school teacher names miss smell my butt, and i know that i am right
Find the volume of an oblique circular cylinder that has a radius of five feet and a height
of three feet
Answer:
235.5 cubic feet
Step-by-step explanation:
The volume v of a circular cylinder whose base radius is r and height h is given as
v = πr^2h
where π is 22/7 or 3.14
Given that the radius is five feet and the height is three feet
the volume v = 3.14 *5^2 * 3
= 235.5 cubic feet
The volume of the oblique circular cylinder is 235.5 cubic feet
let W be the subspace of spanned by the vectors [3 1 1] and [15 11 -1]
find the projection matrix that projects vectors in R3 onto W.
P=
The projection matrix P is [1/√11 -1/√337].
To find the projection matrix that projects vectors in ℝ³ onto the subspace W spanned by the vectors [3 1 1] and [15 11 -1], we can follow these steps:
Let's start by normalizing the basis vectors of W. Normalizing means dividing each vector by its magnitude to obtain unit vectors.
First basis vector:
u₁ = [3 1 1]
Normalize: v₁ = u₁ / ||u₁||
Compute the magnitude: ||u₁|| = √(3² + 1² + 1²) = √11
Normalize: v₁ = [3/√11, 1/√11, 1/√11]
Second basis vector:
u₂ = [15 11 -1]
Normalize: v₂ = u₂ / ||u₂||
Compute the magnitude: ||u₂|| = √(15² + 11² + (-1)²) = √337
Normalize: v₂ = [15/√337, 11/√337, -1/√337]
Next, we construct a matrix P using the normalized basis vectors as columns.
P = [v₁ v₂]
P = [3/√11 15/√337]
[1/√11 11/√337]
[1/√11 -1/√337]
Therefore, the projection matrix P that projects vectors in ℝ³ onto the subspace W spanned by the vectors [3 1 1] and [15 11 -1] is:
P = [3/√11 15/√337]
[1/√11 11/√337]
[1/√11 -1/√337]
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Write the equation of the line graphed at the right(please help I really need this)
the correct answer is X= -3
Determine the domain and range in the function, f(x)=abx
f(x)=ab^x , when a =1/4 and b=16.
Find the total surface area of this cone. Leave your answer in terms of pie.
Answer:
90[tex]\pi[/tex]
Step-by-step explanation:
if you want explanation say in comments
The measures of the angles of a triangle are shown in the figure below. Solve for x.
Answer: x = 10
Step-by-step explanation:
The sum of interior angles in a triangle is equal to 180°.
(2x + 3) + (5x + 17) + 90 = 180
2x + 3 + 5x + 17 + 90 = 180
7x + 110 = 180
7x = 70
x = 10
Assuming the sample was taken from a normal population, what type of test should be performed to test the following?
H_ọ: µ = 190
H_A: μ > 190
X = 186
s = 22
n = 14
To test the given hypothesis, where the null hypothesis (H_ọ) states that the population mean (µ) is equal to 190, and the alternative hypothesis (H_A) states that µ is greater than 190, a one-tailed test should be performed.
Given that the sample mean (X) is 186, the sample standard deviation (s) is 22, and the sample size (n) is 14, we can use the t-test for a single sample to test the hypothesis.
Calculate the test statistic:
t = (X - µ) / (s / √n)
t = (186 - 190) / (22 / √14)
t ≈ -0.8182
Determine the critical value for the given significance level and degrees of freedom.
Since the alternative hypothesis is one-tailed (µ > 190), we need to find the critical value corresponding to the desired significance level (α). Let's assume a significance level of α = 0.05 and degrees of freedom (df) = n - 1 = 14 - 1 = 13. Using a t-distribution table or calculator, the critical value for a one-tailed test at α = 0.05 and df = 13 is approximately 1.771.
Compare the test statistic to the critical value:
If the test statistic is greater than the critical value, we reject the null hypothesis. Otherwise, we fail to reject the null hypothesis.
Since -0.8182 is less than 1.771, we fail to reject the null hypothesis.
Therefore, based on the given sample, assuming a normal population, and performing a one-tailed test at α = 0.05, we fail to reject the null hypothesis (H_ọ: µ = 190) in favor of the alternative hypothesis (H_A: μ > 190).
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please help------------,
Answer:
600 cm²
Step-by-step explanation:
The shaded area (A) is calculated as
A = area of square - ( area of 3 unshaded triangles )
area of square = 40 × 40 = 1600 cm²
area of lower right triangle = [tex]\frac{1}{2}[/tex] × 20 × 40 = 10 × 40 = 400 cm²
area of upper left triangle = [tex]\frac{1}{2}[/tex] × 40 × 20 = 20 × 20 = 400 cm²
area of lower left triangle = [tex]\frac{1}{2}[/tex] × 20 × 20 = 10 × 20 = 200 cm²
Then
A = 1600 - (400 + 400 + 200 ) = 1600 - 1000 = 600 cm²
4th grade math helplolll
Answer:
175 dollars
Step-by-step explanation:
from that word problem the equation that i was able to get out of it was
1225/ 7
^ the travel allowance and how much days they are going to be there
i dont know if you are allowed to use a calculator in your class but puting 1225/ 7 does give you a answer of a positive number of 175 dollars
meaning that they can only use 175 dollars a day so they dont go over the allowance
i hope this helps you! please stay safe and have a good day :)
Answer:
Um, the answer for that is 175.
Step-by-step explanation:
all you need to do is divide $1,225 by 7 which is 175.
Gary is 4 years less than three times his brothers age, \displaystyle bb. The sum of Gary and his brothers' age is 52. Write an equation to represent this relaitonship.
(PLS HELP ME WITH THAT QUESTION! IF YOU HELP ME I GIVE YOU BRAINLIEST I SWEAR)
A custom fish tank shaped like a rectangular prism needs to have a length of 21 inches, a width of 16 inches and hold a volume of 6758 cubic inches. What height must the tank be made to meet these specifications?
Answer:
i dont know im not that smart ask someone else dude
Step-by-step explanation:
Find the distance between the two points.
(-4, 7), (4,0)
units.
The distance between the two points is
Answer: √113 or 10.63
Step-by-step explanation: the exact answer is √113, or 10.63 if you're looking for the decimal form
Step-by-step explanation:
Let the distance between two points A = (-4,7) and B = (4,0).
Here, x1 = -4 , y1 = 7
x2 = 4 , y2 = 0
Use the distance formula to find out the distance between two points are:
AB = √[(x2-x1)²+(y2-y1)²]
= √[{4-(-4)}²+(0-7)²]
= √[(4+4)²+(-7)²]
= √[(8)² + (-7)²]
= √[(8*8)+(-7*-7)]
= √[64+49]
= √[113] ⇛10.630 units approximately.
Tell whether the angles are adjacent or vertical. Then find the value of X
Answer:
The angles are adjacent, and x=100
Step-by-step explanation:
The angles are adjacent because they share the same starting point. x=100 because x and the other angle are on a line, which has a measure of 180 degrees. We subtract 80 from 180 to get 100.
Hope this was helpful.
~cloud
Event A: You roll a double. Event B: The sum of the two scores is even. Event C: The score on the blue die is greater than the score on the red die. Event D: You get a 6 on the red die. Complete the following as a group. Discuss each question together and enter your answers. When you are done, be sure to finish the last few steps of the meeting agenda ("reflect" and "share recording"). = 1. Circle the pairs of events for which PIX and Y) = P(X) x P(Y) A&B A&C A&D B&C B&D C&D
Among the pairs of events A&B, A&C, A&D, B&C, B&D, and C&D, the pairs A&C and B&D satisfy the condition P(A∩B) = P(A) × P(B), indicating that they are independent events.
To determine if two events are independent, we compare the product of their individual probabilities to the probability of their intersection. If the product of the individual probabilities is equal to the probability of the intersection, then the events are independent.
Let's examine each pair of events:
A&B: Rolling a double and getting a sum of even scores are not independent events. The occurrence of one event does not guarantee the occurrence of the other.
A&C: Rolling a double and having the score on the blue die greater than the score on the red die are independent events. The probability of rolling a double is solely dependent on the outcome of the dice roll, while the probability of the blue die having a greater score than the red die is independent of the outcome of rolling a double.
A&D: Rolling a double and getting a 6 on the red die are not independent events. The occurrence of rolling a double does not affect the probability of getting a 6 on the red die.
B&C: Getting a sum of even scores and having the score on the blue die greater than the score on the red die are not independent events. The occurrence of one event does not guarantee the occurrence of the other.
B&D: Getting a sum of even scores and getting a 6 on the red die are independent events. The probability of getting a sum of even scores is solely dependent on the outcome of the dice roll, while the probability of getting a 6 on the red die is independent of the sum of the scores.
C&D: Having the score on the blue die greater than the score on the red die and getting a 6 on the red die are not independent events. The occurrence of one event does not guarantee the occurrence of the other.
In summary, the pairs of events A&C and B&D are the only pairs that satisfy the condition P(A∩B) = P(A) × P(B), indicating that they are independent events.
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Problem 8-28 The exponential distribution applies to lifetimes of a certain component. Its failure rate is unknown. Find the probability that the component will survive past 5 years assuming:
(a) lambda=.5
Pr=
(b) lambda=0.9
Pr=
(c) lambda=1.1
Pr=
The exponential distribution applies to the lifetimes of a certain component. Its failure rate is unknown. The probability that the component will survive the past 5 years assumes:
(a) lambda=.5
Pr= 0.082
(b) lambda=0.9
Pr= 0.082
(c) lambda=1.1
Pr= 0.036
In the exponential distribution, the failure rate is a degree of the way fast the factor is expected to fail. It is regularly denoted through the parameter lambda (λ).
The opportunity that a thing will continue to exist beyond a positive time may be calculated using the exponential survival function, which is given by:
[tex]Pr(X > t) = e^(-λt)[/tex]
where X represents the random variable denoting the life of the thing, t is the specific time, and e is the bottom of the herbal logarithm.
Now let's calculate the possibilities for each case:
(a) lambda = 0.5, t = 5
Pr(X > 5) = [tex]e^(-0.5 * 5)[/tex] ≈ 0.082
In this example, with a lambda of 0.5, the element has a notably low failure price. The opportunity of the thing surviving beyond 5 years is about 0.082, or 8.2%.
(b) lambda = 0.9, t =5
Pr(X > 5) = [tex]e^(-0.9 * 5)[/tex] ≈ 0.082
With a lambda of 0.9, the issue has a slightly higher failure rate as compared to the previous case. The probability of the aspect surviving beyond 5 years stays at about 0.082, or 8.2%.
(c) lambda = 1.1, t = 5
Pr(X > five) = [tex]e^(-1.1 * 5)[/tex]≈ 0.036
In this situation, with a lambda of one.1, the factor has a better failure fee. The possibility of the element surviving beyond 5 years decreases to approximately 0.036, or 3.6%.
In precis, the possibility of a component surviving the past five years in an exponential distribution relies upon the failure price parameter lambda.
A lower failure price ends in a higher chance of survival, at the same time as a higher failure price decreases the opportunity of survival. It is essential to don't forget these chances when assessing the reliability and toughness of additives in diverse packages.
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Hello um I need help if anyone could help me with this that would be perfect:))!!
Answer:
1. If D= whole numbers then the answer is B.0 if it is integers the answer is A.-10
2. The answer is D. That number is an irrational number.
Step-by-step explanation:
Im pretty sure that #1 is B.0, but since there are no labels and i haven't done this in a while, I wasn't quite sure. Sorry.
The function f(x) = \frac{5}{(1 - 9 x)^2} is represented as a power series \displaystyle f(x) = \sum_{n=0}^\infty c_n x^n . Find the first few coefficients in the power series. c_0 = c_1 = c_2 = c_3 = c_4 = Find the radius of convergence R of the series.
[tex]c_0 = 9, c_1 = 2(9^2), c_2 = 3(9^3), c_3 = 4(9^4)[/tex]and [tex]c_4 = 5(9^5)[/tex]. The radius of convergence R is infinity.
To find the coefficients of the power series representation of the function f(x) = 5/(1 - 9x)², we can expand the function using the geometric series formula. The formula states that for |x| < 1, we have:
1/(1 - 9x) = 1 + 9x + (9x)² + (9x)³ + ...
Now, let's differentiate both sides of the equation with respect to x:
d/dx [1/(1 - 9x)] = d/dx [1 + 9x + (9x)² + (9x)³ + ...]
To differentiate the left side, we can use the power rule:
d/dx [1/(1 - 9x)] = (1 - 9x)⁻²
To differentiate the right side, we differentiate each term individually. Since the derivative of x^n with respect to x is nxⁿ⁻¹, the terms with powers of x become:
d/dx [1 + 9x + (9x)² + (9x)³ + ...] = 0 + 9 + 2(9²)x + 3(9³)x² + ...
Equating the derivatives, we have:
(1 - 9x)⁻² = 9 + 2(9²)x + 3(9³)x² + ...
To obtain the coefficients of the power series representation, we compare the terms on both sides of the equation. Since the expression on the right side is already in the desired form, we can read off the coefficients as follows:
[tex]c_0 = 9\\c_1 = 2(9^2)\\c_2 = 3(9^3)\\c_3 = 4(9^4)\\c_4 = 5(9^5)[/tex]
Now, let's find the radius of convergence R of the series. The radius of convergence can be determined using the ratio test. The ratio test states that if the limit of |[tex]c_{n+1} / c_n[/tex]| as n approaches infinity is L, then the series converges if L < 1 and diverges if L > 1.
Applying the ratio test to our series, we have:
|[tex]c_{n+1} / c_n[/tex]| = |[(n+1)(9ⁿ⁺¹)] / [n(9ⁿ)]| = 9((n+1)/n)
Taking the limit as n approaches infinity, we get:
lim(n->∞) |[tex]c_{n+1}/ c_n[/tex]| = lim(n->∞) 9((n+1)/n) = 9
Since the limit is 9, which is less than 1, the series converges for all values of x within a radius of convergence R. Therefore, the radius of convergence R is infinity (R = ∞).
Therefore,[tex]c_0 = 9, c_1 = 2(9^2), c_2 = 3(9^3), c_3 = 4(9^4)[/tex]and [tex]c_4 = 5(9^5)[/tex]. The radius of convergence R is infinity.
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PLEASE HELP HURRY WILL GIVE BRAINLIST IF CORRECT
Answer:
26 per week
Step-by-step explanation:
All real solutions of the equation.
If $120.99 is charged for 654 units of electricity used,find the cost of one unit of electricity
Answer:
$5.41
Step-by-step explanation:
654 divided by 120.99=5.405... therefore the answer is $5.41
What is the best description of a food chain?
the competition among several species for the same food item
the transfer of energy from one organism to another
Answer:
the transfer of energy from one organism to another
Step-by-step explanation:
Combine the like terms to create an equivalent expression for 4z−(−3z)
Answer:
7z
Step-by-step explanation:
Answer: 7z
Step-by-step explanation:
two negatives cancel into a positive, so -(-3z) is +3z. 4z + 3z = 7z
Suppose that the number of defects on a roll of magnetic recording tape has a Poisson distribution for which the mean A is either 1.0 or 1.5, and the prior probability mass function of A is as follows: (1.0) = 0.4 and (1.5) = 0.6. If a roll of tape selected at random is found to have four defects, what is the posterior probability mass function of X? The posterior p.m.f is____.
The posterior probability mass function of X is given below:0.4 * 0.0183 = 0.00732.0.6 * 0.0513 = 0.03078. Posterior Probability Mass Function of X: ____0.00732 if A = 1.0.____0.03078 if A = 1.5.
Explanation: The probability mass function for Poisson distribution is given by: P(X = x) = (e^-λ * λ^x) / x!Where,λ is the mean. The given prior probability mass function of A is P (A = 1.0) = 0.4P(A = 1.5) = 0.6.
Thus, the mean is either A = 1.0 or A = 1.5.
Now, let X be the number of defects on a roll of tape. Using the law of total probability, the probability mass function of X is P (X = x) = P (X = x, A = 1.0) + P (X = x, A = 1.5)
Using Bayes' theorem, the posterior probability mass function is given by: P (A = 1.0 | X = 4) = P (X = 4 | A = 1.0) * P (A = 1.0) / P (X = 4) P (A = 1.5 | X = 4) = P (X = 4 | A = 1.5) * P (A = 1.5) / P (X = 4)
Now, we need to calculate P (X = 4 | A = 1.0) and P (X = 4 | A = 1.5) using the Poisson distribution.
P (X = 4 | A = 1.0) = (e^-1 * 1^4) / 4! = 0.0183.P(X = 4 | A = 1.5) = (e^-1.5 * 1.5^4) / 4! = 0.0513.
Now, we need to calculate the value of the denominator,
P (X = 4). P (X = 4) = P (X = 4, A = 1.0) + P (X = 4, A = 1.5) = P (X = 4 | A = 1.0) * P (A = 1.0) + P (X = 4 | A = 1.5) * P (A = 1.5)
Put the values: P (X = 4) = (0.0183 * 0.4) + (0.0513 * 0.6) = 0.0342.
Put the values in the above posterior probability mass function equations,
we get: P (A = 1.0 | X = 4) = 0.00732 and P (A = 1.5 | X = 4) = 0.03078.
Therefore, the posterior probability mass function of X is:0.00732 if A = 1.0.0.03078 if A = 1.5.
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Find the perimeter of the window to the nearest hundredth.
perimeter: about
ft
Based on the data shown below X 2 3 4 5 6 7 8 19 10 data 45.22 44.74 40.96 37.68 33.7 30.62 30.94 24.26 21.88 21.4 11 Find the correlation coefficient. What proportion of the variation in y can be explained by the variation in the values of x? Report answer as a percentage accurate to one decimal place.
There is a strong negative linear relationship between x and y, and almost all of the variation in y can be explained by the variation in x.
The correlation coefficient is -0.961 and the proportion of the variation in y that can be explained by the variation in the values of x is 92.3%.
The correlation coefficient measures the strength and direction of the linear relationship between two variables. In this case, the correlation coefficient between x and y is -0.961, which indicates a strong negative linear relationship between the two variables.
The coefficient of determination (r²) measures the proportion of the variation in y that can be explained by the variation in the values of x. In this case, the value of r² is 0.923, or 92.3%. This means that 92.3% of the variability in y can be explained by the variability in x. Therefore, there is a strong negative linear relationship between x and y, and almost all of the variation in y can be explained by the variation in x.
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