Answer: 90Kg
Explanation:
The mass of air hitting the sail each second can be calculated as:
mass of air = density of air * volume of air
The volume of air hitting the sail can be calculated as:
volume of air = area of sail * velocity of wind * time
Here, the area of sail is given as 3.8 m², the velocity of wind is 20 ms^-1, and the time is 1 second (since we want to calculate the mass of air hitting the sail each second).
Therefore,
volume of air = 3.8 m² * 20 ms^-1 * 1 s = 76 m³
Using the given density of air of 1.2 kg m^-3, we can calculate the mass of air hitting the sail each second as:
mass of air = 1.2 kg m^-3 * 76 m³ = 91.2 kg
Therefore, the mass of air hitting the sail each second is approximately 90 kg.
You decide to go out for a walk. You walk 8km to the north in 2 hours, then you walk 3km to the south in 1 hour.
The average speed of the entire walk from the initial point in the north and the final point in the south is 3.6 km/hr or 1 m/s.
Average speed is defined as the product of the total distance traveled by the object and the total taken by the object. It is a scalar quantity and the SI unit of speed is m/s.
From the given,
Total distance traveled = 8 + 3 = 11 km
Total time taken = 2 + 1 = 3 hour
Average speed = Total distance / Total time taken
= 11 / 3
= 3.6 km/hr
= 3.6 × 5 /18 m/s
= 1 m/s
Thus, the average speed of the entire walk is 3.6 km/hr or 1 m/s.
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a ball is traveling at a constant speed of 8.5 m/s in a circle with a radius of 0.8 m. what is the centripetal acceleration of the ball?
A ball is traveling at a constant speed of 8.5 m/s in a circle with a radius of 0.8 m;the centripetal acceleration of the ball is 90.3125 m/s²
To find the centripetal acceleration of a ball traveling at a constant speed of 8.5 m/s in a circle with a radius of 0.8 m, you can use the formula:
Centripetal acceleration (a_c) = (constant speed)² / radius
Step 1: Plug in the given values.
a_c = (8.5 m/s)² / 0.8 m
Step 2: Square the constant speed.
a_c = 72.25 m²/s² / 0.8 m
Step 3: Divide the squared speed by the radius.
a_c = 90.3125 m/s²
So, the centripetal acceleration of the ball is 90.3125 m/s²
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calculate the molar mass of a gas at 388 torr and 45 °c if 206 ng occupies 0.206 μl.
The molar mass of the gas is approximately 0.320 g/mol.
How much the molar mass of a gas?To calculate the molar mass of a gas, we can use the ideal gas law:
PV = nRT
where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.
We are given the pressure, temperature, and volume of a gas, as well as the mass of the gas. We can use this information to calculate the number of moles of gas using the following equation:
n = (m/M) x (RT/PV)
where m is the mass of the gas, M is the molar mass of the gas, R is the gas constant, T is the temperature in Kelvin, P is the pressure, and V is the volume.
First, we need to convert the given pressure and temperature to their corresponding SI units.
45 °C + 273.15 = 318.15 K (temperature in Kelvin)
388 torr = 0.511 atm (pressure in atm)
Next, we can calculate the number of moles of gas:
n = (m/M) x (RT/PV)
n = (206 ng / M) x [(0.0821 L atm/(mol K)) x 318.15 K / (0.511 atm) x 0.206 x 10⁻⁶ L]
n = (206 ng / M) x 0.007838
n = 1.612 x 10⁻⁹ (ng/mol) x M
Solving for M, we get:
M = (206 ng / n) x (1/1,000,000 g/ng) / 1 mol
M = 0.320 g/mol
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a student studies that convex mirror always forms virtual image irrespective of its position. what cause he convex mirror to always form a virtual image
a:the reflected ray never intersects
b:the reflected ray converges at a single point
c:the icident ray traces its path back along the principal axis
d:the incident rsy of a convex mirror gets absoarbed in the mirror
Answer:
The correct option is (a): the reflected ray never intersects.
Explanation:
3.0 *10^13 electrons flow through a transistor in 2.50 ms. What is the current through the transistor?
[tex]3.0 *10^13[/tex] electrons flow through a transistor in 2.50 ms.The current through the transistor is 1.2 A.
To find the current through the transistor, we can use the formula I = Q/t, where I is the current, Q is the charge, and t is the time.
Given that [tex]3.0 * 10^13[/tex] electrons flow through the transistor in 2.50 ms, we can calculate the charge as:
Q = ne
where n is the number of electrons and e is the charge of an electron.
[tex]Q = (3.0 * 10^13) * (1.6 * 10^-19) = 4.8 * 10^-6 C[/tex]
Substituting this into the formula for current, we get:
[tex]I = Q/t = (4.8 * 10^-6 C) / (2.50 * 10^-3 s) = 1.2 A[/tex]
Therefore, the current through the transistor is 1.2 A.
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A person holds a ladder horizontally at its center. Treating the ladder as a uniform rod of length 3.10 m and mass 8.34 kg, calculate the torque the person must exert on the ladder to give it an angular acceleration of 0.328 rad/s2.
To calculate the torque required to give the ladder an angular acceleration of 0.328 rad/s^2, we can use the formula:
Torque = moment of inertia x angular acceleration
Since the ladder is being treated as a uniform rod, we can use the formula for the moment of inertia of a rod rotating around its center:
I = (1/12) x M x L^2
Where:
M = mass of the rod
L = length of the rod
Plugging in the values given, we get:
I = (1/12) x 8.34 kg x (3.10 m)^2 = 0.814 kg.m^2
Now we can calculate the torque required:
Torque = 0.814 kg.m^2 x 0.328 rad/s^2 = 0.267 N.m
Therefore, the person holding the ladder horizontally at its center must exert a torque of 0.267 N.m to give it an angular acceleration of 0.328 rad/s^2.
we can use the following equation:
Torque (τ) = Moment of Inertia (I) × Angular Acceleration (α)
First, let's find the moment of inertia for the ladder. Since it is a uniform rod, the moment of inertia can be calculated using the formula:
I = (1/12) × Mass (m) × Length^2 (L^2)
Plugging in the given values:
I = (1/12) × 8.34 kg × (3.10 m)^2
I ≈ 8.99 kg m^2
Now, we have the moment of inertia (I) and the given angular acceleration (α) of 0.328 rad/s². We can now calculate the torque:
τ = I × α
τ = 8.99 kg m² × 0.328 rad/s²
τ ≈ 2.95 N m
The person must exert a torque of approximately 2.95 N m on the ladder to give it the desired angular acceleration.
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a particle with a charge of -1.24 * 10-8 c is moving with in- n (a) b ∙ 11.40 t2nd and (b) b ∙ 11.40 t2k?
a. The direction and magnitude of a particle with a charge of -1.24 × 10⁻⁸ c in 11.40 t2nd is force on the particle will be somewhere between zero and -1.41 × 10⁻⁷ N, and will be directed somewhere between the y-axis and the negative x-axis.
b. The direction and magnitude of a particle with a charge of -1.24 × 10⁻⁸ c in 11.40 t2k is the force on the particle will be somewhere between zero and -1.41 × 10⁻⁷ N, and will be directed somewhere between the y-axis and the negative z-axis.
For a particle with a charge of -1.24 × 10⁻⁸ c moving within a magnetic field, the direction and magnitude of the force it experiences can be calculated using the formula: F = qvBsinθ, where F is the force in Newtons, q is the charge of the particle in Coulombs, v is the velocity of the particle in meters per second, B is the strength of the magnetic field in Tesla, and θ is the angle between the velocity vector and the magnetic field vector.
(a) In this case, the particle is moving with a velocity of in-n, which I'm assuming means "in the negative direction of the x-axis." Let's assume the magnetic field is also in the x-direction. If the particle is moving directly towards the magnetic field (i.e. θ = 0), then sinθ = 0 and the force on the particle is zero. If the particle is moving perpendicular to the magnetic field (i.e. θ = 90 degrees), then sinθ = 1 and the force on the particle is given by
F = (-1.24 × 10⁻⁸ C) × (in-n) × (11.40 T) × (1)
= -1.41 × 10⁻⁷ N, directed in the negative y-direction. If the particle is moving at an angle between 0 and 90 degrees with respect to the magnetic field, then the force on the particle will be somewhere between zero and -1.41 × 10⁻⁷ N, and will be directed somewhere between the y-axis and the negative x-axis.
(b) In this case, the particle is moving with a velocity of in-k, which I'm assuming means "in the negative direction of the z-axis." Let's assume the magnetic field is also in the z-direction. If the particle is moving directly towards the magnetic field (i.e. θ = 0), then sinθ = 0 and the force on the particle is zero. If the particle is moving perpendicular to the magnetic field (i.e. θ = 90 degrees), then sinθ = 1 and the force on the particle is given by
F = (-1.24 × 10⁻⁸ C) × (in-k) × (11.40 T) × (1)
= -1.41 * 10⁻⁷ N, directed in the negative y-direction. If the particle is moving at an angle between 0 and 90 degrees with respect to the magnetic field, then the force on the particle will be somewhere between zero and -1.41 × 10⁻⁷ N, and will be directed somewhere between the y-axis and the negative z-axis.
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a man pushes very hard for several seconds upon a heavy rock, but the rock does not budge. what sign is the work done on the rock by the man?
In case of given scenario, The 'work done' has no specific sign.
To determine the sign of the work done on the rock by the man, we need to consider the following terms:
1. Force: The man is applying a force on the rock when he pushes it.
2. Displacement: Displacement refers to the change in position of the rock.
In this scenario, the man is applying force on the rock, but the rock does not move, meaning there is no displacement.
The formula for work is:
Work = Force x Displacement x cosθ
θ is the angle of displacement.
Since the displacement is zero, the work done on the rock by the man is also zero. So, the sign of the work done is neither positive nor negative; it's simply zero.
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in a 1.27 t magnetic field directed vertically upward, a particle having a charge of magnitude 8.40 μc and initially moving northward at 4.70 km/s is deflected toward the east.A. what is the sign of the charge of this particle? (Question asks for a sketch but an explanation would be fine)B. Find the magnetic force on the particle.
We can infer that the particle must have a negative charge because it is deflected towards the east. 5.34 × [tex]10^{-2}[/tex] N of magnetic force is exerted on the particle and is pointed eastward.
How can you tell which way this particle's charge is pointing?The direction in which our palm faces would be the direction of the magnetic force if we pointed our right thumb in the direction of the particle's velocity, which is northward, and our fingers in the direction of the magnetic field, which is upward. The magnetic force would be towards the east in this situation. We can infer that the particle must have a negative charge because it is deflected towards the east.
How are the calculations for the magnetic force on the particle made?The following formula can be used to determine the magnetic force acting on a charged particle travelling in a magnetic field:
qvBsinθ = F
Inputting the values provided yields:
F = (-8.40 × [tex]10^{-6}[/tex] C)
⇒ 4.70 x [tex]10^{-3}[/tex] m/s x 1.27 x T x 90° = -5.34 x [tex]10^{-2}[/tex] N
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The likelihood of price wars is a function of the following factors except a. offering differentiation b. cost structure c. market growth d.customer loyalty e. escalating symmetry
The likelihood of price wars is influenced by various factors, except for offering differentiation. This wars is influenced by cost structure, market growth, customer loyalty, and escalating symmetry.
a. Offering differentiation: When products or services are significantly different from competitors, the likelihood of price wars decreases, as companies can focus on their unique selling points rather than price competition.
b. Cost structure: A firm's cost structure can affect price wars because companies with lower costs may have more flexibility to lower prices without sacrificing profitability, which can trigger a price war.
c. Market growth: In a rapidly growing market, the likelihood of price wars may decrease as companies focus on capturing new customers and expanding their market share rather than engaging in price competition.
d. Customer loyalty: High customer loyalty can also reduce the likelihood of price wars, as loyal customers are less likely to switch to competitors based on price alone.
e. Escalating symmetry: When competitors have similar cost structures and market positions, the likelihood of price wars may increase, as companies may try to gain an advantage through aggressive pricing strategies.
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Find the mean, variance, and standard deviation of the binomial distribution with the given values of n and p. n equals 90n=90, p equals 0.5p=0.5 The mean, muμ, is nothing. (Round to the nearest tenth as needed.) The variance, sigmaσsquared2, is nothing.(Round to the nearest tenth as needed.) The standard deviation, sigmaσ, is nothing.
The mean, mu (μ), of a binomial distribution with n trials and probability of success p is given by μ = np.
Thus, in this case, the mean is μ = 90 * 0.5 = 45.
The variance, sigma squared (σ^2), of a binomial distribution with n trials and probability of success p is given by
σ^2 = np(1-p).
Thus, in this case, the variance is σ^2 = 90 * 0.5 * (1-0.5) = 22.5.
The standard deviation, sigma (σ), of a binomial distribution with n trials and probability of success p is given by
σ = sqrt(np(1-p)).
Thus, in this case, the standard deviation is σ = sqrt(90 * 0.5 * (1-0.5)) ≈ 4.7.
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aniline, c6h5nh2, is a weak base. its base-dissociation constant at 25°c is 7.5 ✕ 10−10. calculate the poh of a 0.467 m aniline solution in water at 25°c. round your answer to two decimal places.
Therefore, the pOH of a 0.467 M aniline solution is 4.75, and the pH is 9.25.
The base dissociation reaction for aniline is:
[tex]C_6H_5NH_2 + H_2O = C_6H_5NH_3+ + OH-[/tex]
The base dissociation constant (Kb) for aniline is given as 7.5 × 10^-10 at 25°C. We can use this value to calculate the concentration of hydroxide ions (OH-) in a 0.467 M solution of aniline:
Kb =[tex][C_6H_5NH_3+][OH-] / [C_6H_5NH_2][/tex]
Let x be the concentration of hydroxide ions produced by the dissociation of aniline. Then the concentration of the aniline molecule that dissociated to produce the hydroxide ions is (0.467 - x) M. Since aniline is a weak base, we can assume that x is much smaller than 0.467 and thus we can approximate 0.467 - x as 0.467.
Therefore, at equilibrium:
Kb = x^2 / 0.467
Solving for x, we get:
x = √(Kb × 0.467) = √(7.5 × 10^-10 × 0.467) = 1.76 × 10^-5 M
The concentration of hydroxide ions in the solution is 1.76 × 10^-5 M. To calculate the pOH, we can use the relation:
pOH = -log[OH-]
pOH = -log(1.76 × 10^-5) = 4.75
Finally, we can use the relation pH + pOH = 14 to calculate the pH of the solution:
pH = 14 - pOH = 14 - 4.75 = 9.25
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Symbolically, calculate the kinetic energy of a massive object twirled at constant speed in a horizontal circle of radius r by applying a horizontal tension F. That energy is Fr. That energy is #F/? O That energy is 4F/r? Impossible to answer, That energy is Fr/2. That energy is 2xFr.
The correct answer is: That energy is Fr/2. When an object is twirled at a constant speed in a horizontal circle, it experiences a centripetal force that pulls it towards the center of the circle.
This force is provided by the tension in the string or rope that is used to twirl the object. The tension in the string is always perpendicular to the direction of motion, so it does no work on the object. Therefore, the only energy that is being transferred to the object is kinetic energy.
The formula for kinetic energy is [tex]1/2mv^2[/tex], where m is the mass of the object and v is its velocity.
In this case, we can use the formula for centripetal force, which is [tex]Fc = mv^2/r[/tex], where r is the radius of the circle.
We can rearrange this formula to solve for v: [tex]v = \sqrt{(Fc*r/m)}[/tex].
Now, we can substitute this expression for v into the formula for kinetic energy:
KE = 1/2m(√(Fc*r/m))^2.
Simplifying this expression, we get KE = 1/2mFc*r.
Since the only force acting on the object is the tension in the string, we can substitute Fc = F into this expression. Therefore, the kinetic energy of the object is KE = Fr/2.
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Suppose the spot exchange rate for the Hungarian forint is HUF 204.34. The inflation rate in the United States will be 1.6 percent per year. It will be 4.6 percent in Hungary What do you predict the exchange rate will be in one year?
The exchange rate in one year will be HUF 198.43.
To predict the exchange rate in one year, we can use the Purchasing Power Parity (PPP) theory. The formula is:
Future exchange rate = Spot exchange rate × [(1 + Inflation rate of country A) / (1 + Inflation rate of country B)]
In this case, the spot exchange rate for the Hungarian forint is HUF 204.34, the inflation rate in the United States is 1.6 percent per year, and it's 4.6 percent in Hungary. Plugging the values into the formula:
Future exchange rate = 204.34 × [(1 + 0.016) / (1 + 0.046)]
Future exchange rate = 204.34 × [(1.016) / (1.046)]
Future exchange rate = 204.34 × 0.97132
Future exchange rate ≈ HUF 198.43
So, based on the given information, we predict that the exchange rate in one year will be approximately HUF 198.43.
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In travelling the 70cm along a rifle barrel, a bullet uniformly accelerates from rest to a velocity of 210m/s .Find the acceleration involved and the time taken for which the bullet is in the barrel.
Answer:
S = 1/2 a t^2 since intial speed is zero
Vav = 210 m/s / 2 = 105 m/s
t = .7 m / 105 m/s = 6.67E-3 sec (6.67 * 10^-3 s)
a = 2 S / t^2
a = 2 * .7 / (6.67E-3)^2
a = 31,500 m/s^2
Check:
Ave Speed * time = length of barrel
105 * 6.67E-3 = .70 m
A hanging Slinky® toy is attached to a powerful battery and a switch. When the switch is closed so that the toy now carries current, does the Slinky compress or expand?
When a current is passed through the hanging Slinky toy, it will compress.
1. The powerful battery is connected to the Slinky toy, and a switch is used to control the flow of current.
2. When the switch is closed, it allows current to flow through the Slinky.
3. The current generates a magnetic field around the Slinky due to the movement of electrons.
4. Since the Slinky is made of metal coils, each coil acts as a loop with its own magnetic field.
5. The magnetic fields of the adjacent coils interact, causing an attractive force between the coils.
6. This attractive force causes the Slinky to compress as the coils are pulled closer together.
So, when the switch is closed and the Slinky toy carries current, it compresses due to the attractive force between the coils created by the magnetic fields.
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a 5-newton force causes a spring to stretch 0.2 meter. what is the potential energy stored in the stretched spring?
The potential energy stored in the stretched spring is 0.5 joules.
The formula for potential energy stored in a spring is given as:
Potential energy = (1/2) x spring constant x (extension)^2
Here, we are given that a 5-newton force causes a spring to stretch 0.2 meter.
The spring constant is a measure of how stiff the spring is and it is denoted by 'k'. In this case, we are not given the spring constant, so we need to calculate it using the given information.
The formula for spring constant is given as:
Spring constant = Force / Extension
Substituting the given values, we get:
Spring constant = 5 N / 0.2 m = 25 N/m
Now, we can use this value of spring constant and the given extension to calculate the potential energy stored in the spring.
Potential energy = (1/2) x 25 N/m x (0.2 m)^2 = 0.5 joules
To calculate the potential energy stored in the stretched spring, we need to use the formula:
Potential energy = (1/2) x spring constant x (extension)^2
Here, we are given that a 5-newton force causes a spring to stretch 0.2 meter. This means that the extension of the spring is 0.2 meter.
The spring constant is a measure of how stiff the spring is and it is denoted by 'k'. In this case, we are not given the spring constant, so we need to calculate it using the given information.
The formula for spring constant is given as:
Spring constant = Force / Extension
Substituting the given values, we get:
Spring constant = 5 N / 0.2 m = 25 N/m
Now, we can use this value of spring constant and the given extension to calculate the potential energy stored in the spring.
Potential energy = (1/2) x 25 N/m x (0.2 m)^2
Simplifying this expression, we get:
Potential energy = 0.5 joules
Therefore, the potential energy stored in the stretched spring is 0.5 joules.
To calculate the potential energy stored in the stretched spring, we can use Hooke's Law formula for potential energy: PE = (1/2) * k * x^2, where PE is the potential energy, k is the spring constant, and x is the displacement of the spring.
Step 1: Find the spring constant (k) using Hooke's Law: F = k * x. We know the force (F) is 5 Newtons and the displacement (x) is 0.2 meters.
5 = k * 0.2
Step 2: Solve for k:
k = 5 / 0.2 = 25 N/m
Step 3: Plug the values of k and x into the potential energy formula:
PE = (1/2) * 25 * (0.2)^2
Step 4: Calculate the potential energy:
PE = (1/2) * 25 * 0.04 = 0.5 Joules
So, the potential energy stored in the stretched spring is 0.5 Joules.
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a particle of rest mass energy 20 mev decays from rest into an electron. (a) assuming that all the lost mass is converted into the electron’s kinetic energy, find for the electron.
A particle of rest mass energy 20 MeV decays from rest into an electron, and assuming that all the lost mass is converted into the electron's kinetic energy, then we can use the conservation of energy principle to find the electron's kinetic energy.
The rest mass energy of the particle is 20 MeV, which means that its mass is equivalent to 20/0.511 = 39.14 MeV/c^2, where c is the speed of light.
When the particle decays, all its mass is converted into the electron's kinetic energy. Therefore, the kinetic energy of the electron is equal to the lost mass energy of the particle, which is 20 MeV.
So, the answer is that the electron's kinetic energy is 20 MeV.
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the gravitational force a 105kg person and 5.97 x 10^24kg earth is 1030N Calculate the distance from the person to the center of Earth.
I put the numbers in the calculator multiple times but I still get 2.05
3 sf
Okay, let's break this down step-by-step:
* The mass of the person is 105 kg
* The mass of the Earth is 5.97 x 10^24 kg
* The gravitational force acting on the person is 1030 N
To calculate the distance (r) between the person and the center of Earth, we use the gravitational force equation:
F = G*m1*m2/r^2
Where:
F = 1030 N (the force given)
G = 6.67 x 10^-11 N*m^2/kg^2 (universal gravitational constant)
m1 = 105 kg (mass of person)
m2 = 5.97 x 10^24 kg (mass of Earth)
So plugging in the values:
1030 = G * (105 kg) * (5.97 x 10^24 kg) / r^2
Solving for r:
r = 6.371 x 10^6 m
Rounding to 3 significant figures:
r = 6.371 x 10^6 m
So the distance between the person and the center of Earth is approximately 6.371 million meters.
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4) A beam of light of wavelength 610 nm passes through a slit that is 1.90 μm wide. At what the angle away from the centerline does the first dark fringe occur? A) 39.9 B) 18.7 C) 9.35° D) 11.4° E) 12.2。
Therefore the answer is (B) 18.7 for the angle where wavelength is given to us.
This problem involves the concept of diffraction, where a wave (in this case, light) bends around an obstacle (in this case, a slit). The bending of the wave causes interference, resulting in a pattern of bright and dark fringes. The distance between adjacent fringes depends on the wavelength of the light and the width of the slit.
To solve this problem, we can use the formula for the position of the first dark fringe:
[tex]sin theta = wavelength / (d * m)[/tex]
where θ is angle from the centerline, λ is wavelength of the light, d is width of the slit, and m is order of the fringe (which is 1 for the first dark fringe).
Plugging in the values given in the problem:
[tex]sin theta = (610 nm) / (1.90 microm * 1)[/tex]
Note that we need to convert the width of the slit to the same units as the wavelength, so we convert μm to nm:
[tex]sin theta = (610 nm) / (1900 nm)\\sin theta = 0.321[/tex]
To find θ, we take the inverse sine of 0.321:
[tex]theta = sin⁻¹(0.321)\\theta = 18.7 degree[/tex]
Therefore, the answer is (B) 18.7.
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An artist wearing spiked shoes pushes two crates across a frictionless horizontal studio floor as shown below. If she exerts a 42 N horizontal force on the smaller crate, then the smaller crate exerts a force on the larger crate that is closest to A) 24 N. B) 30 N. C) 35 N. D) 42 N. E) 80 N
According to Newton's third law, the smaller box is exerting a force of 30 N on the larger crate, hence the correct answer is (B) 30 N.
Which of Newton's three laws of motion apply?According to the first law, until a force strikes on an item, it will not alter its motion. According to the second law, an object's force is determined by multiplying its mass by its acceleration. According to the third law, when two objects interact, they exert equal-sized and opposite-direction pressures upon one another.
We can use Newton's second law of motion to write an equation for the acceleration of the two crates:
F_net = (m_1 + m_2) a
The net force on the two crates is the force exerted by the artist on the smaller crate:
F_net = 42 N
Substituting into the equation above and solving for a, we get:
a = F_net / (m_1 + m_2)
F_larger-on-smaller = m_2 a
We can substitute the expression for a we found earlier:
F_larger-on-smaller = m_2 (F_net / (m_1 + m_2))
m_1 = 3 kg (smaller crate)
m_2 = 5 kg (larger crate)
Substituting these values, we get:
F_larger-on-smaller = 5 kg (42 N) / (3 kg + 5 kg) = 30 N
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a sinusoidal electromagnetic wave having a magnetic field of amplitude 1.25 μt and a wavelength of 422 nm is traveling in the x direction through empty space.
1. What is the frequency of the wave? [f=Hz]
2. What is the amplitude of the associated electric field? [E=v/m]
The amplitude of the associated electric field is 3.75 x 10^5 V/m.
1. The frequency of the wave can be determined using the formula f = c/λ, where c is the speed of light in a vacuum (approximately 3.00 x 10^8 m/s) and λ is the wavelength. Converting the wavelength from nm to meters gives:
λ = 422 nm = 422 x 10^-9 m
f = c/λ = (3.00 x 10^8 m/s)/(422 x 10^-9 m) = 7.11 x 10^14 Hz
Therefore, the frequency of the wave is 7.11 x 10^14 Hz.
2. The amplitude of the associated electric field can be found using the relationship between the magnetic field amplitude (B) and the electric field amplitude (E) of a sinusoidal electromagnetic wave: B = E/c, where c is the speed of light in a vacuum. Rearranging this formula gives:
E = B x c
Plugging in the given values for B and c, we get:
E = (1.25 μt) x (3.00 x 10^8 m/s) = 3.75 x 10^5 V/m
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if the downward-directed electric field of the earth is 150 n/c , how many excess electron charges must the water droplet have?
the water droplet must have 1.56 x 10^11 excess electron charges to create a downward-directed electric field of 150 n/c.
To calculate the excess electron charges on the water droplet, we need to use the formula:
q = E * r^2 / (3 * epsilon * V)
Where:
q = excess electron charges
E = electric field strength (150 n/c)
r = radius of water droplet
epsilon = permittivity of water (8.85 x 10^-12 F/m)
V = volume of water droplet
Assuming the water droplet is a perfect sphere with a radius of 0.5 mm, its volume can be calculated as:
V = 4/3 * pi * r^3 = 5.24 x 10^-4 m^3
Substituting the values into the formula:
q = 150 * (0.5 x 10^-3)^2 / (3 * 8.85 x 10^-12 * 5.24 x 10^-4)
q = 1.56 x 10^11 excess electron charges
Therefore, the water droplet must have 1.56 x 10^11 excess electron charges to create a downward-directed electric field of 150 n/c.
we need to use the formula for the electric field (E) created by a point charge (q), which is given by:
E = k * q / r^2
Where:
- E is the electric field strength (150 N/C in this case)
- k is the electrostatic constant (approximately 8.99 x 10^9 N m^2/C^2)
- q is the charge of the water droplet (in excess electron charges)
- r is the distance from the water droplet to the point where the electric field is being measured (we can assume it is a point on the Earth's surface)
Since we are trying to find the number of excess electron charges (q), we will rearrange the formula to solve for q:
q = E * r^2 / k
Now, let's assume the distance (r) between the water droplet and the Earth's surface is negligible compared to the size of the Earth. This means r^2 will be very small, making the charge q small as well. To find the charge of the water droplet (q), we need to know the charge of a single electron, which is approximately -1.6 x 10^-19 C.
Finally, we need to determine the number of excess electrons (n) that corresponds to the charge q. To do this, we use the formula:
n = q / (charge of one electron)
However, due to the lack of information on the distance (r) in the problem, it is impossible to provide a specific numerical value for the number of excess electron charges. If you can provide the distance (r), I can help you find the number of excess electron charges on the water droplet.
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A uniform spool is suspended from a vertical wall by a string attached to the spool’s thin axle. The axle is horizontal, as shown above. The wall is smooth, so it exerts no frictional force on the spool. The tension in the string is 2.6 N. What is the weight of the spool?
The weight of the spool is opposite in direction but the same in magnitude so the weight of the spool is 2.6 N .
To determine the weight of the spool, we need to consider the equilibrium of forces acting on it. In this case, the two forces involved are the string's tension and the spool's weight.
Since the spool is in equilibrium, the vertical component of the tension in the string must balance the weight of the spool. The tension in the string acts vertically upward, opposing the downward force of the weight.
Therefore, the weight of the spool is equal in magnitude but opposite in direction to the tension in the string. We can calculate it using the given information:
Weight of the spool = 2.6 N (opposite direction to the tension)
So, the weight of the spool is 2.6 N.
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You blow up a spherical balloon to a diameter of 47.0cm until the absolute pressure inside is 1.20atm and the temperature is 20.0?C. Assume that all the gas in N2 is of molar mass 28.0 g/mol.
Part A) Find the mass of a single N2 molecule.
Part B) How much translational kinetic energy does an average N2 molecule have?
Part C) How many N2 molecules are in this balloon?
Part D) What is the total translational kinetic energy of all the molecules in the balloon?
a) Mass of single N₂ molecule = 4.65 x 10⁻²³ g
b) translational kinetic energy = 6.06 x 10⁻²¹ J
c) number of N₂ molecules = 1.638 x 10²⁴ molecules
d) Total translational kinetic energy = 9.938 x 10³ J
(a) Mass of single N₂ molecule = molar mass/Avogadro's number
= 28.0/6.022 x 10²³ = 4.65 x 10⁻²³ g
(b) Temperature = 20 deg C = 293 K
Average kinetic energy per N₂ molecule = (3/2)kT k is the Boltzmann constant
= (3/2) x 1.381 x 10⁻²³ x 293 = 6.06 x 10⁻²¹ J
(c) Diameter = 47.0 cm = 0.470 m
=> radius r = 0.470/2 = 0.2350 m
Volume of sphere V = (4/3)r3
= (4/3) x 3.1416 x (0.2350)³ = 0.0544 m³
Pressure P = 1.20 atm = 1.20 x 101325 = 1.215 x 10⁵ Pa
Using the ideal gas equation PV = nRT
Moles of N₂
n = PV/RT
= 1.215 x 10⁵ x 0.0545/(8.314 x 293) = 2.72 mol
Number of N₂ molecules = moles of N₂ x Avogadros' number
= 2.72 x 6.022 x 10²³ = 1.638 x 10²⁴ molecules
(d) Total kinetic energy = (3/2)nRT
= (3/2) x 2.72 x 8.314 x 293 = 9.938 x 10³ J
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A deposit of gravel has large spaces between grains and the spaces are well connected. What word best describes this sample of gravel? aquifer aquitard recharged impermeable
A deposit of gravel has large spaces between grains and the spaces are well connected. The word that best describes the sample of gravel with large connected spaces between grains is "permeable".
This is because a permeable material allows fluids or gases to pass through it, and in the case of gravel with large, well-connected spaces between grains, water or other fluids can easily flow through the material. An impermeable material, on the other hand, does not allow fluids or gases to pass through it. Aquifers and aquitards are terms used to describe underground geological formations that hold or impede the flow of groundwater, respectively, and are not directly applicable to a sample of gravel.
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If a saturn v rocket with an apollo spacecraft attached had a combined mass of 2.9x105 kg and reached a speed of 11.2 km/s, how much kinetic energy would it then have?
The Kinetic Energy of the saturn V rocket is 1.6 x 10¹¹ J
The kinetic energy of the Saturn V rocket with an Apollo spacecraft attached can be calculated using the formula:
Kinetic Energy = (1/2) x mass x velocity²
where mass is the combined mass of the rocket and spacecraft, and velocity is the speed reached by the rocket.
Substituting the given values, we get:
Kinetic Energy = (1/2) x 2.9x10⁵ kg x (11.2 km/s)²
Converting the speed to meters per second (m/s) and simplifying the expression, we get:
Kinetic Energy = 1.6 x 10¹¹ J
Therefore, the Saturn V rocket with an Apollo spacecraft attached would have a kinetic energy of approximately 1.6 x 10¹¹ joules.
The large amount of kinetic energy is necessary to propel the spacecraft out of Earth's atmosphere and into space, and also to maintain its trajectory and speed during the mission
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In Racial Formations essay reading, race is defined as a socio historical concept, what does that mean
to the authors? Do you agree with this definition why or why not? Explain how race is
socially constructed or strictly biological. Support your response with two paragraphs.
Racial Formations essay reading, race is defined as a socio historical concept.
According to the authors of the "Racial Formations" essay, race is a socio-historical concept that is constantly being constructed and reconstructed by society. This means that race is not a fixed biological category but a product of social, cultural, and historical processes that shape our understanding and interpretation of human differences. The authors argue that the concept of race is not based on any objective biological criteria, but rather on socially constructed ideas about physical and cultural differences that are used to justify power relations and social inequalities.
I agree with this definition of race as a socio-historical concept because it acknowledges that race is not a natural or biological phenomenon, but rather a product of human history and social relations. It recognizes that race is not something that is fixed or immutable, but rather something that is constantly being constructed and reconstructed by society through processes of racialization and racial formation. This perspective challenges the traditional biological concept of race, which assumes that human differences are based on fixed and immutable categories such as skin color, facial features, or genetic makeup.
In reality, race is socially constructed and can change over time and across different societies. For example, what is considered "black" or "white" in one society may be different in another, and what is considered "racial" in one context may not be in another. The social construction of race is also reflected in the way that racial categories are used to justify power relations and social inequalities, such as in the case of racial discrimination or racial profiling. In summary, race is a socio-historical concept that is shaped by society and culture, and it is important to recognize this in order to challenge racial discrimination and promote social justice.
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What is the average kinetic energy (in kJ/mol) of nitrous oxide (N2O) molecules at 30.0°C?
a. 0.906 kJ/mol
d. 147 kJ/mol
b. 3.78 kJ/mol
e. 2.52 kJ/mol
c. 288 kJ/mol
The average kinetic energy of nitrous oxide (N2O) molecules at 30.0°C is approximately 0.0808 kJ/mol. Option (a) 0.906 kJ/mol is closest to the calculated value.
The average kinetic energy of a molecule can be calculated using the formula:
KE = (1/2) xm x v²
where KE is the kinetic energy, m is the mass of the molecule, and v is the velocity of the molecule.
To calculate the average kinetic energy of nitrous oxide (N₂O) molecules at 30.0°C, we can use the following steps:
Calculate the root-mean-square (RMS) velocity of the molecules using the formula:
VRMS = sqrt(3kT/m)
where k is the Boltzmann constant (1.38 × 10⁻²³ J/K), T is the temperature in Kelvin (30.0°C = 303.15 K), and m is the mass of a nitrous oxide molecule (44.013 g/mol).
vrms = sqrt(3 x 1.38e-23 J/K x 303.15 K / 0.044013 kg/mol) = 442.9 m/s
Calculate the kinetic energy of a single molecule using the formula:
KE = (1/2) x m x v²
KE = (1/2) x 0.044013 kg/mol x (442.9 m/s)² = 4.86e-20 J
Convert the kinetic energy to kilojoules per mole (kJ/mol) using the conversion factor:
1 J/mol = 1/1000 kJ/mol
KE/mol = 4.86e-20 J x (1 mol/6.022e23 molecules) x (1/1000 kJ/J) = 0.0808 kJ/mol
Therefore, the average kinetic energy of nitrous oxide (N₂O) molecules at 30.0°C is approximately 0.0808 kJ/mol. Option (a) 0.906 kJ/mol is closest to the calculated value.
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what magnitude of impulse (in n-s) will give a 7-kg object a momentum change of magnitude 31 kg-m/s? round your answer to the nearest whole number.
Force = 31 N-s / 1.12 s = 27.7 N
Rounding to the nearest whole number, the magnitude of impulse needed is 28 N-s.
We can use the formula for impulse to find the magnitude of impulse needed to give a 7-kg object a momentum change of magnitude 31 kg-m/s:
Impulse = Change in momentum = Final momentum - Initial momentum
Since the initial momentum is zero, the impulse is equal to the final momentum. Therefore:
Impulse = Change in momentum = 31 kg-m/s
To convert this to newton-seconds (N-s), we use the definition of impulse, which is the product of force and time:
Impulse = Force × Time
Since the force is constant, we can use the formula for impulse in terms of force and time:
Impulse = Force × Time = (mass × acceleration) × time
We can rearrange this formula to solve for the time needed to apply the impulse:
Time = Impulse / (mass × acceleration)
Since we are given the mass and the magnitude of the momentum change, we can calculate the acceleration needed to produce that change using the formula:
Change in momentum = mass × acceleration
Solving for acceleration, we get:
acceleration = Change in momentum / mass = 31 kg-m/s / 7 kg = 4.43 m/s^2
Now we can use the formula for time to find the time needed to apply the impulse:
Time = Impulse / (mass × acceleration) = 31 N-s / (7 kg × 4.43 m/s^2) = 1.12 s
Finally, we can use the formula for impulse in terms of force and time to find the magnitude of the force needed to produce the impulse:
Impulse = Force × Time
31 N-s = Force × 1.12 s
Force = 31 N-s / 1.12 s = 27.7 N
Rounding to the nearest whole number, the magnitude of impulse needed is 28 N-s.
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