An object has an initial velocity of 15 m/s and a constant acceleration of 4 m/s2. How long will it take before its final velocity is equal to three times its initial velocity?

Answer:

600mph

Explanation:

hope this helps!

The reason why the moon does not fall back to the earth is that  the Moon's rotation about its own axis creates centripetal force

that balances Earth's pull.

The gravitational force is the force that keeps the solar system together. All the members of the celestial bodies are held in place by gravity.

Thus, the reason that keeps the moon from falling back to the earth is because the Moon's rotation about its own axis creates centripetal force that balances Earth's pull.

Hence,  their tangential velocity is sufficient to ensure that the flight path misses the object being orbited. The centripetal force is enough to bend the otherwise straight path into an ellipse.

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Answer:

  D. The Moon has a large tangential velocity that causes it to "miss" Earth as it falls toward it.

Explanation:

You want to know what keeps the Moon from falling directly to Earth.

The Moon does not fall directly to Earth because the direction of motion is more or less perpendicular to the direction of Earth from the Moon. That is, the large tangential velocity causes it to "miss" Earth.

Additional comment

One object will orbit another if their mutual gravitational attraction provides enough acceleration (change in speed and/or direction) to bend the path into a circular or elliptical one. If the acceleration is too little, the path may be bent, but no orbit will be established. If the acceleration is too great, the path may be bent to a curve that ultimately causes the objects to collide.

In general, the multi-body dynamics present in the solar system mean that the orbits of various objects are chaotic. In the short term, they are fairly predictable, but short-term behavior may not be predictive of long-term behavior.

Dressing suitably for different situations, using appropriate language, and maintaining good personal hygiene are all ways to demonstrate self-representation.

A person taking the charge of the organization and leading a team under him is known as a leader.

"The complete question is"Dressing suitably for different situations, using appropriate language, and maintaining good personal hygiene are all ways to demonstrate _______________. An employee will display _______________ by adhering to professional standards of the workplace and encouraging co-workers to do the same."

Options:

First Blank: work ethic

First Blank: self-representation

First Blank: diversity awareness

Second Blank: leadership skills

Second Blank: nonverbal skills

Self-representation may be shown through dressing appropriately for diverse settings, speaking politely, and keeping up with personal cleanliness.

By upholding the workplace's ethical norms and encouraging others to do the same, an employee will demonstrate leadership qualities.

Dressing suitably for different situations, using appropriate language, and maintaining good personal hygiene are all ways to demonstrate self-representation.

An employee will display leadership skills by adhering to the professional standards of the workplace and encouraging co-workers to do the same.

Hence, self-representation and leadership skills are the correct answer.

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Answer: I think Its the Height is 11.76 Meters (38.582677 Feet) between the bridge and the ground

Explanation: Supposing that where not counting air resistance in the equation, the equation [tex]D = ut+\frac{1}{2} at^{2}[/tex] states that 1/2 multiplied by earths gravitational acceleration multiplied by the amount of time to reach the bottom: 2.4 seconds equals 11.76 meters of height between the bridge and the ground.

We can calculate the width/thickness of a coin using a screw gauge by placing it in between the teeth of the gauge.

We can determine the width/thickness of a coin by using a screw gauge because screw gauge is an instrument that measures thickness of an object that are very thin. First we can placed the coin in between the teeth of the gauge and then move the gauge until the coin can be held tightly. After that note the reading on the scale.

So we can conclude that we can calculate the width/thickness of a coin using a screw gauge by placing it in between the teeth of the gauge.

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The speed of the car passing you is 6 m/s while car is moving 6 m/s behind the car.

The speed of the car passing you is determined by applying relative velocity principle as shown below;

Vr = Va - Vb

Vr = 26 m/s - 32 m/s

Vr = -6 m/s

Thus, the speed of the car passing you is 6 m/s while car is moving 6 m/s behind the car.

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vertical motion

h=1/2 gt²

100 = 1/2 x 10 x t²

t² = 100/5 = 20

t = 2√5 s

horizontal motion

x = v.t

x = 15 x 2√5

x = 30√5 m

Explanation:

the two vectors are 5i+11j+11k

Answer:

When electric voltage is applied, an electric field within the metal triggers the movement of the electrons, making them shift from one end to another end of the conductor. Electrons will move toward the positive side.

The SI unit is agreed internationally through an agreement known as convention of the meter.

SI unit stands for International System Of Units (SI) - which is the metric system that is used universally as a standard for measurements.

The SI unit is agreed internationally through an agreement known as convention of the meter, which describes the measurement of fundamental quantities such as mass, time, and length.

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Answer:

ma+mgsinh0​+f=F∴(25)(0.75)+(25)(10)sinh0​+μk​N=F∴18.75+(250)(0.6h)+μk​(mgcosh0​=F⟹18.75+150+μk​((25)(10)(0.76))=500∴168.75+μk​(190)=500⟹μk​(190)=331.25⟹μk​=1.74

Explanation:

Answer:

8.16m/s south

Explanation:

North is the negative direction.

60kg*(-5m/s)+79.5kg*v=(79.5kg+60kg)*(2.5m/s)

-300kgm/s+79.5kg*v=348.75kgm/s

79.5kg*v=648.75kgm/s

v=8.16m/s

Answer:

Upward: Negative

Downward: Positve

Explanation:

Let upward be positive

We want to find the work done on the object upwards.

The equation of work done due to gravity is

[tex]f _{g}d \cos( \alpha ) [/tex]

It is read as force of gravity times displacement times cos of the angle between the force and displacement.

Since gravity is happening down of the center of mass and the displacement is upwards, the angle is 180° so

[tex]f_{g}d \cos(180) [/tex]

Cosine of 180 is -1

so

[tex] - f_{g}d [/tex]

If we go downwards, the sign will be positive because cos(0)=1

Hi there!

We can use the following relationship between the Potential Difference and the Electric field:

[tex]V = E d[/tex]

V = Potential Difference (500V)
E = Electric Field (V/m)
d = separation between plates (0.2 m)

We can rearrange the equation to solve for the electric field:
[tex]E = \frac{V}{d}\\\\[/tex]

Plug in the given values.

[tex]E = \frac{500}{0.2} = \boxed{2500 \frac{V}{m}}[/tex]

Answer:

0.24 A

Explanation:

Voltage is given by the equation :

V = I × R

Voltage = Current × Resistance

Rearrange to make Current/I the subject :

18 = I × 75

I = 18÷75

I = 0.24 A

Hope this helped and brainliest please

Answer:

20m

Explanation:

So the formula for PE(Potential Energy) = Mass x Acceleration x Height

So we are given the following

PE = 1960

Mass = 10Kg

Acceleration = 9.8m/s^2 (The reason we have an acceleration is due to gravity)

Height = ?

So to calculate height we will use the same formula

1960 = 10 x 9.8 x h

1960 = 98 x h

1960 = 98h

we divide 98 on both sides

H = 20m

Hope this helped.

The difference between the manufacturer's claims and your findings is, the manufacturer is concerned about amount of fat in the meat while you are concerned about calories.

Your findings concluded that only fat can provide calories needed in the body, perhaps other classes of food or nutrients in the meat can provide calories as well.

In the manufacturer's claim there are about 3% fat in the lunch meat and doesn't necessary mean that all the calories needed is the 3% fat.

Thus, there are lots of difference between your findings and the manufacturer's claim. The manufacturer is concerned about amount of fat in the lunch meat while you are concerned about calories in the meat.

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Answer:

A, AND B,

Explanation: just trust me bro

The amount of force required to accelerate the given mass of the wagon is 129 Newtons.

A force is simply referred to as either a push or pull of an object resulting from the object's interaction with another object.

From Newton's Second Law, force is expressed as;

F = m × a

Where is mass of object and a is the acceleration.

Given the data in the question;

F = 8.6kg × 15m/s²

F = 129kgm/s²

F = 129N

Therefore the amount of force required to accelerate the given mass of the wagon is 129 Newtons.

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Answer:

Option B - 360 J

Explanation:

One of the formulas used to find out how much work was done is :

E = 0.5×m×v² (where m is the mass and v is the velocity)

Now we substitute values from the question and simplify :

E = 0.5×500×1.2²

E = 250×1.2²

E = 250×1.44

E = 360 J

So our answer is Option B

Hope this helped and have a good day

Answer:

B. period of the sound wave

T he role of oxygen in air supply is to keep all the ling beings live and healthy.

Oxygen is the most important gas required for the living of human beings, animals, birds and the whole ecosystem.

Oxygen is fundamental for breath on the grounds that the body utilizes it to 'consume' food atoms. Creatures take in oxygen while breathing in and radiate carbon dioxide while breathing out. Oxygen makes up practically 21% of the all out gases in air, with the majority of the excess gas being physiologically latent nitrogen.

Oxygen assumes a basic part in breath, the energy-delivering science that drives the digestion systems of most living things. We people, alongside numerous different animals, need oxygen in the air we inhale to remain alive. Oxygen is created during photosynthesis by plants and many sorts of organisms.

Thus, the air supply needs oxygen on the majority.

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Answer:

[tex]\huge\boxed{\sf 1.6\ units = 14.4p}[/tex]

Explanation:

Since,

So,

1.6 kWh = 1.6 units

If,

1.6 units = 9p × 1.6

1.6 units = 14.4p

[tex]\rule[225]{225}{2}[/tex]

Answer:

Friction     100 j

Explanation:

Friction causes the inequality between PE and KE

100 J

Answer:

metal, non, metal, metal, non, non, metal, non

Explanation:

knowledge

Answer:

Hello there seems to be no Images in this question but Kinetic energy is a push or a pull force which has to do with motion if you just need to know what t is. Next time be sure to add the pictures for it.

Explanation:

Thank you!

Hello the other person (#Sonichj123), was indeed correct there appears to be no picture in your question. Although there is no picture in your question, If you have another question I will be gladly to help you!

Explanation:

Thank you so much! (≥ФωФ≤)

Answer:

resolution

Explanation:

  That is the definition of resolution

Hi there!

To solve, we need to find the distance traveled by the proton at which the proton's velocity reaches 0 m/s. This indicates the point at which the repulsive force caused by the line of charge and its consequential acceleration causes the proton to stop for an instant and be repelled back in the opposite direction.

For this, we can use the work-energy theorem to solve.

Recall the following equations:
[tex]W = \Delta KE[/tex]

[tex]W = \int F \cdot dx\\\\KE = \frac{1}{2}mv^2[/tex]

We will integrate along the path from the point 19.0 cm (0.19 m) from the line up to a point 'z' at which the proton has no kinetic energy (v = 0 m/s). This means that the wire will be doing NEGATIVE work on the proton as it is decreasing the proton's kinetic energy.

The equation for a force acting on a charged particle is given as:
[tex]F_E = qE[/tex]

For an infinite line of charge, the electric field is given as:
[tex]E = \frac{2k\lambda}{r}\\\\F_E = \frac{2k\lambda q}{r}[/tex]

**λ = Linear charge density (C/m)

To set up our integral:
[tex]W = \Delta KE = \int\limits^z_{0.19} {\frac{2k\lambda q}{r}} \, dr = -\frac{1}{2}mv^2[/tex]

Integrate using the following natural log rule:
[tex]\int {\frac{1}{r}} \, dr = ln(r) + C[/tex]

[tex]\int\limits^z_{0.19} {\frac{2k\lambda q}{r}} \, dr = -\frac{1}{2}mv^2\\\\2k\lambda q ln(r) \left \| {{z} \atop {0.19}} \right. = -\frac{1}{2}mv^2\\\\2k\lambda q (ln(z) - ln(0.19) = -\frac{1}{2}mv^2\\\\2k\lambda q ln(\frac{z}{0.19}) = -\frac{1}{2}mv^2[/tex]

Now, we can begin solving for 'a'.

Move coefficients to one side:
[tex]ln(\frac{z}{0.19}) = -\frac{mv^2}{4k\lambda q }[/tex]

Take the base 'e' of both sides:
[tex]e^{ln(\frac{z}{0.19})} = e^{-\frac{mv^2}{4k\lambda q }}\\\\\frac{z}{0.19} = e^{-\frac{mv^2}{4k\lambda q }}\\\\z = (0.19)e^{-\frac{mv^2}{4k\lambda q }}\\\\z = (0.19)e^{-\frac{(1.67*10^{-27})(1200^2)}{4(8.99*10^9)(8.00*10^{-12}) (1.6*10^{-19}) }}\\\\\boxed{z = 0.1803 m= 18.03 cm}[/tex]

It will reach a distance 18.03 cm from the wire before it temporarily loses all of its kinetic energy (at rest) and begins to speed up in the opposite direction.