4. Solve the Cauchy-Euler equation: x"y" - 2x*y" - 2xy +8y = 0 (12pts)

Answers

Answer 1

the general solution to the Cauchy-Euler equation x³y'" - 2x²y" - 2xy' + 8y = 0 is given by y(x) = c₁x² + c₂x⁻¹ + c₃x⁻¹ln(x) where c₁, c₂, and c₃ are constants.

To solve the Cauchy-Euler equation x³y'" - 2x²y" - 2xy' + 8y = 0, we'll make the substitution y = [tex]x^r[/tex], where r is a constant.

Let's differentiate y with respect to x:

y' = [tex]rx^{r-1}[/tex]

y" = [tex]r(r-1)x^{r-2}[/tex]

y'" = [tex]r(r-1)(r-2)x^{r-3}[/tex]

Now, substitute these derivatives into the original equation:

[tex]x^3(r(r-1)(r-2)x^{r-3} - 2x^2(r(r-1)x^{r-2}) - 2x(rx^{r-1}) + 8x^r = 0[/tex]

Simplifying, we get:

[tex]r(r-1)(r-2)x^r - 2r(r-1)x^r - 2rx^r + 8x^r = 0[/tex]

Combining like terms, we have:

r(r-1)(r-2) - 2r(r-1) - 2r + 8 = 0

Simplifying further, we get:

r³ - 3r² + 2r - 2r² + 2r + 8 - 2r + 8 = 0

r³ - 3r² + 8 = 0

To solve this cubic equation, we can try to find a rational root using the Rational Root Theorem or use numerical methods to approximate the roots.

By inspection, we find that r = 2 is a root of the equation. This means (r - 2) is a factor of the equation.

Using long division or synthetic division, we can divide r^3 - 3r^2 + 8 by (r - 2):

  2  |   1    -3    0    8

      |       2   -2   -4

_______________________

       1    -1   -2    4

The quotient is r² - r - 2.

Factoring r² - r - 2, we get:

r² - r - 2 = (r - 2)(r + 1)

So the roots of the equation r³ - 3r² + 8 = 0 are: r = 2, r = -1 (repeated root).

Therefore, the general solution to the Cauchy-Euler equation x³y'" - 2x²y" - 2xy' + 8y = 0 is given by:

y(x) = c₁x² + c₂x⁻¹ + c₃x⁻¹ln(x)

where c₁, c₂, and c₃ are constants.

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Given question is incomplete, the complete question is below

Solve the Cauchy-Euler equation:

x³y'" - 2x²y" - 2xy' + 8y = 0


Related Questions

The greatest snowfall in a 24- hour period was 76 inches. Which of these is the same as 76 inches?
A. 6 1/3 feet
B. 2.5 yards
C. 7.6 feet
D. 2 1/3 yards

Answers

Answer:

the answer is A. 6 1/3 feet

Step-by-step explanation:

There are 12 inches in a foot. 12 x6=72 r of 4

there are 12 inches in a foot 12÷4=3. 1/3 of a foot

6 + 1/3= 6 1/3

please answer this for me?

Answers

Answer:

n/a

Step-by-step explanation:

how does it feel

Which equation represents the line that passes through the point (3, –1) and is perpendicular to the graph of x + 4y = 10?

Answers

Answer:

y=6x+7

Step-by-step explanation:

The height, h metres, of a soccer ball kicked directly upward can be modelled by the equation h(t) = -4.9t2 + 13.1t + 1, where t is the time, in seconds, after the ball was kicked. a) How high is the ball after 2 s? 15 b) After how many seconds does the ball reach a height of 0.5 m? /3 21. Determine the inverse function for f(x)=(x - 2), state the domain and range for the function and its inverse. Write each step. 14 22. A farmer has 600m of fencing to enclose a rectangular area and divide 14 into three sections as shown. a) write a equation to express the total area enclosed as a function of the length x. b) Determine the domain and the range of this area function.

Answers

a) The height of the ball after 2 seconds is 7.6 metres.

b) The given function is f(x) = (x - 2).

a) The inverse function of f(x) is g(x) = x + 2.

b) A farmer has 600 metres of fencing to enclose a rectangular area and divide it into 14 sections.

a) The total area enclosed can be expressed as a function of the length of the rectangle x as A(x) = 300x - x².

b) The domain of the area function is (0, 300) and its range is [0, ∞).

a) h(t) = -4.9t² + 13.1t + 1 When the time, t = 2 seconds;

the height of the ball, h(t) =h(2) = -4.9(2)² + 13.1(2) + 1= -4.9(4) + 26.2 + 1= -19.6 + 27.2= 7.6 metres

Therefore, the height of the ball after 2 seconds is 7.6 metres.

b) h(t) = -4.9t² + 13.1t + 1When the height of the ball, h(t) = 0.5 metres; we can write the equation as:

0.5 = -4.9t² + 13.1t + 1

Rearranging,4.9t² - 13.1t + 0.5 - 1 = 0i.e. 4.9t² - 13.1t - 0.5 = 0

Solving using the quadratic formula, t = [-(-13.1) ± √(13.1² - 4(4.9)(-0.5))]/(2(4.9))= [13.1 ± √(171.61)]/9.8≈ 0.138 and t ≈ 2.23

Thus, the ball reaches a height of 0.5 metres twice, at approximately 0.14 seconds and 2.23 seconds.

The given function is f(x) = (x - 2).

a) We can find the inverse of a function by interchanging x and y and then solving for y.

Here, f(x) = (x - 2) so we can write it as x = (y - 2)

Interchanging x and y: x = (y - 2)

Solving for y, we get: y = x + 2

Hence, the inverse function of f(x) is g(x) = x + 2.

b) Domain and range of the function and its inverse

The domain of f(x) is all real numbers. (i.e. -∞ < x < ∞)

The range of f(x) is all real numbers. (i.e. -∞ < f(x) < ∞)

The domain of g(x) is all real numbers. (i.e. -∞ < x < ∞)

The range of g(x) is all real numbers. (i.e. -∞ < g(x) < ∞)

The steps of the solution are given below:

Therefore, the inverse function of f(x) is g(x) = x + 2.

The domain of f(x) is all real numbers, and its range is all real numbers.

Similarly, the domain and range of g(x) is all real numbers.

A farmer has 600 metres of fencing to enclose a rectangular area and divide it into 14 sections.

Let x be the length and y be the width of the rectangle.

a) Write an equation to express the total area enclosed as a function of the length x.

Perimeter of the rectangle = Total fencing = 600 metres2(x + y) = 600i.e. x + y = 300

Solving for y, we get:

y = 300 - x

Thus, the area of the rectangle is A(x) = xy = x(300 - x) = 300x - x²

Therefore, the total area enclosed can be expressed as a function of the length of the rectangle x as A(x) = 300x - x².

b) Determine the domain and range of the area function.

The domain of the function is the set of all possible values of x, which in this case is the set of all positive real numbers. (i.e. 0 < x < 300)

The range of the function is the set of all possible values of A(x), which in this case is the set of all non-negative real numbers. (i.e. 0 ≤ A(x) < ∞)

Therefore, the domain of the area function is (0, 300) and its range is [0, ∞).

The steps of the solution are given below:

Therefore, the total area enclosed can be expressed as a function of the length of the rectangle x as A(x) = 300x - x². The domain of the area function is (0, 300) and its range is [0, ∞).

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help plsss. marking brainliest

Answers

Answer:

1. 3

2. 1

Step-by-step explanation:

Answer:

1.3. now mark brainlieet plsssssssssss like you said you would

1. Select all of the situations below that model this fraction. *
Captionless Image
A. 243 people were at the park. 20 people were playing volleyball. How many people were not playing volleyball?
B. Marcy's bookshelf had 20 shelves. She had 243 books. How many books would go on each shelf if she put the same number of books on each shelf?
C. Josh made $243 in 20 days. How much did he earn each day?
D. Sally and Len bicycled 243 miles in 20 days. How many miles did they bicycle each day?

Answers

Answer:

A. 223 were not playing volleyball

B. 12 books on each shelf with 3 books left over..

C. 12.15$ a day

D. 12.15 miles per day.

Step-by-step explanation:

A. Subtract 20 from 243.

B. Since books cant be divided into fractions, you take 243 divided by 20, which is 12.15. However, we have to say 12 with 3 leftover because books isn't money, a distance measure, etc. and cannot be cut into pieces.

C. 243 / 20 is 12.15

D. 243 / 20 is 12.15

Pls someone help me

Answers

Answer:

Step-by-step explanation:

455

What is 40x + 4y = 24

Answers

Answer:

sorry but your question can't be solved any further because it doesn't have any like termsand you can't add40x and4y together it's impossible unless you multiply

Which rectangular equation represents the parametric equations x =t Superscript one-half and y = 4t? y = 4x2, for x ≥ 0 y = one-fourth x squared, for x greater-than-or-equal-to 0 y = 16x2, for x ≥ 0 y = StartFraction 1 Over 16 EndFraction x squared, for x greater-than-or-equal-to 0

Answers

Answer:

Answer is Option A

Step-by-step explanation:

the things people do for points smh :/

The rectangular equation which represents the parametric equations; x = t^(¹/2) and y = 4t is; y = 4x2, for x ≥ 0.

Rectangular Equation from Parametric equations

From the task content, it follows that the parametric equations given are;

x = t^(¹/2) and y = 4t

Hence, it follows that; t = x² and y= 4t

Ultimately, upon substitution of for t; the resulting rectangular equation is; y = 4t².

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PLEASE HELP WILL MARK BRAINLIEST

Answers

Answer:

36

Step-by-step explanation:

There are 30 red marbles and the ratio of black to yellow is 4/5, so 4/5=orange/green=orange/30.

30 is 6 times 5, so black=6 times 4=24. There are 24 black marbles.

Total of black and yellow=24+30=54.

40% of the marbles are green so 60% are black/yellow. Also 60% is 54 marbles.

60% is 60/100=3/5 so 3/5 of the total is 54 marbles, therefore 1/5 is 54/3=18 and 2/5 is the number of red marbles=2 times 18=36 red marbles.

to be honest i can't think of anything original for the visual thing, but i think the pi chart from the person above me would work well

Answer: 36

Step-by-step explanation: 2/5 of marbles are red, and 4:5 ratio is multiplied by 6 because there are 30 yellow marbles and so 3/5 of the marbles are 54 and 2/5 are 36. For visual model draw a pi chart with 40% red, 33% yellow, and 27% black.

which relation is also a function

Answers

A, as the x doesn’t repeat itself

predictive modelling and lifetime value modelling are the same
True or False

Answers

The given statement, "predictive modelling and lifetime value modelling are the same" is false. What is Predictive Modeling?

Predictive modeling is a technique for forecasting the probability of a certain event taking place in the future. It entails using current and past data to forecast the future events. In predictive modeling, you use known outcomes of historical data to determine whether specific patterns are likely to recur in the future. What is Lifetime Value Modeling? Lifetime Value Modeling is a method of forecasting the long-term earnings and profit of a business. It's a strategy for calculating the cumulative amount of profit generated by a customer over the life of their relationship with a company. Lifetime Value Modeling is used to decide the most effective ways to engage with consumers, such as personalized deals or special promotions, to maximize their lifetime value to the company by encouraging them to purchase more often and spend more during each transaction.

Predictive modeling and lifetime value modeling are distinct concepts that serve different purposes. Predictive modeling is used to forecast the future occurrence of specific events, whereas lifetime value modeling is used to calculate the long-term value of a customer to a company. So, the given statement is false.

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What is the best definition for “sample” as used in statistics?
the entire population of the group
a part of the population that represents the entire population
the difference between the maximum and minimum values observed
a measure of how much the values within a population vary

Answers

Answer:

a part of the population that represents the entire population

Step-by-step explanation:

Answer:

I think it is the second option

I hope it helps you  

Let A = {a,b,c}, B = {1, 2, 3, 4), and C = {w, x, y, z), and let R= {(2, 1), (6, 3), (6, 4), (C, 3)} and S = {(1, y), (1, 2), (2, w), (3, z)}. What is the composition relation ( RS) of R with S?

Answers

The pair (6, 3) in R, (6, 4) in R, and (C, 3) in R couldn't be matched with any pair in S, so they are not included in the composition relation RS.

To find the composition relation RS of R with S, we need to combine the ordered pairs in R and S in a way that the second element of each pair in R matches the first element of the pair in S.

Let's perform the composition:

R = {(2, 1), (6, 3), (6, 4), (C, 3)}

S = {(1, y), (1, 2), (2, w), (3, z)}

To form RS, we match the second element of each pair in R with the first element of each pair in S:

(2, 1) in R matches with (1, y) in S, so we combine them to form (2, y).

(2, 1) in R matches with (1, 2) in S, so we combine them to form (2, 2).

(6, 3) in R doesn't match with any pair in S.

(6, 4) in R doesn't match with any pair in S.

(C, 3) in R doesn't match with any pair in S.

Therefore, the composition relation RS is: RS = {(2, y), (2, 2)}

The pair (6, 3) in R, (6, 4) in R, and (C, 3) in R couldn't be matched with any pair in S, so they are not included in the composition relation RS.

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TILAPIA FISH!!!!!!!!!

Answers

Answer:

yes.

................................

You need help with anything??

What is the equation in point-slope form of the line passing through (0,5) and (-2, 11)?
Oy-5=-3(x + 2)
Oy-5= 3(x + 2)
Oy - 11 = -3(x - 2)
Oy - 11 = -3(x + 2)

Answers

Answer: y-11 = -3(x+2)

Let be a fixed vector in and vector be a solution to where Q is a m*n matrix.
Prove every solution to the equation is in the form?

Answers

Given a fixed vector b and a vector x is a solution to Qx = b, it is required to prove that every solution to the equation is in the form x = xh + xp where xh is a particular solution to Qx = b and xp is a solution to the equation Qxp = 0.

Let xh be a particular solution to Qx = b, so that Qxh = b.

Now consider the homogeneous equation Qx = 0.

This is an m × n system of homogeneous linear equations in the n unknowns x1, x2, ..., xn, whose coefficient matrix is Q.

Since xh is a solution to the equation Qx = b, it follows that the equation Q(x - xh) = Qx - Qxh = b - b = 0.

This means that x - xh is a solution to the homogeneous equation Qx = 0.

Now any solution to Qx = b is of the form x = xh + xp, where xp is any solution to the homogeneous equation Qxp = 0.

Thus, every solution to the equation is in the form x = xh + xp, as required.

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Please help me
Find the surface area
If you can explain to that would be great if not that’s fine
4 m
12 m
18 m

Answers

Answer

672 meters²

Step-by-step explanation:

2×(18×12 + 18×4 + 12×4) = 672 meters²

hope this helps :))

i need help!!!! i have to identify the area and i forgot how to do it and it was due 2 days ago!

Answers

Answer: I think B is the answer.

Step-by-step explanation:

Answer:not sure but

Step-by-step explanation: you can multiply each box, so lets say we have 20 times 7cm you multiply that and you get your answer, so put that a side

and once you multiply in each box add the numbers up and that should get your answer and make sure to add the "cm" at the end

Here is an equation and all the steps Clare and Lin took to solve it. Are both of their solutions correct? Explain your reasoning.

Answers

Answer:

Both solutions are correct

Step-by-step explanation:

Given

Expression:

[tex]14x - 2x +3 = 3(5x + 9)[/tex]

See attachment for Clare and Lins' solution

Required

Determine if they are correct or not

[tex]14x - 2x +3 = 3(5x + 9)[/tex]

Open bracket

[tex]14x - 2x + 3 = 15x + 27[/tex]

Collect like terms

[tex]14x - 2x -15x = -3 + 27[/tex]

[tex]-3x = 24[/tex]

Divide by -3

[tex]x = \frac{24}{-3}[/tex]

[tex]x = -8[/tex]

Both solutions are correct

helpppppppp will b marked brainliest!!!!!!!!!! Which system of equations is represented in the graph?
a. y= -2 x-2y=6
b. y= -2 x+2y=6
c. y= -2 2x-y= 3
d. y= -2 2x+y= -3

Answers

Answer: d. y= -2 2x+y= -3

Step-by-step explanation: Hope this help :D


The graph of the function f(x) = ax^2 + bx + c has vertex at (0, 2) and passes through the point
(1, 8). Find a, b and c

Answers

Answer:

Step-by-step explanation:

You need to use vertex form of a quadratic to solve this.

Consider the vertex to be [tex](h,k)[/tex]

Another way of representing a quadratic is in "vertex form":

[tex]f(x) = a(x-h)^2+k[/tex]

Now all you have to do is solve for a.  You know that the vertex is [tex](0,2)[/tex] and you have know the point of [tex](1,8)[/tex].  Now, all you have to do is plug in these values and solve for a.

[tex]8 = a(1-0)^2+2\\8=a(1)^2+2\\8=a+2\\a=6[/tex]

Now you know the equation is [tex]f(x) = 6(x-0)^2+2[/tex] , but you need it in quadratic form.  All you have to do is solve is distribute the 6:

[tex]6x^2+2[/tex]

You get:

a = 6

b = 0

c = 2

Please mark this as brainliest if it satisfies your question

Help me plz! I need help!

Answers

Answer:

function 2

Step-by-step explanation:

i looked at the table, and since t (which is the x-coordinate in this case) was 0, that means that 5.25 is the y-coordinate and is greater than 5 in the first equation.

1) According to one study, brain weights of men are normally distributed with a mean of 1.10 kg and a standard deviation of 0.14 kg. Use the data to answer questions (a) through (e).

a. Determine the sampling distribution of the sample mean for samples of size 3.

b. Determine the sampling distribution of the sample mean for samples of size 12.

d. Determine the percentage of all samples of three men that have mean brain weights within 0.1 kg of the population mean brain weight of 1.10 kg.

e. Determine the percentage of all samples of twelve men that have mean brain weights within 0.1 kg of the population mean brain weight of 1.10 kg.

_________________________________________

2) According to a study, brain weights of men in country A are normally distributed with mean 1.60 kg and standard deviation 0.12 kg. Apply the 68.26-95.44-99.74 rule to fill in the blanks.

68.26% of men in country A have brain weights between ___ kg and __kg

_____________________________________________

Answers

a) Sample distribution follows normal distribution with mean( μ) = 1.10 kg,

and standard deviation σ = 0.081

b) Sample distribution follows normal distribution with mean( μ)  = 1.10 kg,

and standard deviation σ = 0.04

d) The percentage of all samples of three men that have mean brain weights within 0.1 kg of the population mean brain weight of 1.10 kg is 79.77%.

e) The percentage of all samples of twelve men that have mean brain weights within 0.1 kg of the population mean brain weight of 1.10 kg is 99.3%.

2) 68.26% of men in country A have brain weights between 1.48 kg and 1.72 kg.

Solution:

Population standard deviation is the measure of how spread out the population data is. It measures the difference of the individual items from the mean. A standard deviation is a statistic that measures the dispersion of a dataset relative to its mean. It is calculated as the square root of variance by determining the variation between each data point relative to the mean.

1)

Given mean = 1.10 kg, standard deviation = 0.14 kg

a) To find the sampling distribution of the sample mean for samples of size 3.

Standard error of mean = σ/√n

= 0.14/√3

=0.081

Sample distribution follows normal distribution with mean( μ) = 1.10 kg,

and standard deviation σ = 0.081

b) To find the sampling distribution of the sample mean for samples of size 12.

Standard error of mean = σ/√n

= 0.14/√12

= 0.04

Sample distribution follows normal distribution with mean( μ)  = 1.10 kg,

and

standard deviation σ = 0.04

d) Determine the percentage of all samples of three men that have mean brain weights within 0.1 kg of the population mean brain weight of 1.10 kg.

Sample distribution follows normal distribution with mean( μ)  = 1.10 kg,

and

standard deviation σ = 0.081

Z = (x - μ) / σZ

= (1.1 + 0.1 - 1.1) / 0.081

= 1.23

Z = (1.1 - 0.1 - 1.1) / 0.081

= -1.23

P ( -1.23 < Z < 1.23) = 0.7977

The percentage of all samples of three men that have mean brain weights within 0.1 kg of the population mean brain weight of 1.10 kg is 79.77%.

e) Determine the percentage of all samples of twelve men that have mean brain weights within 0.1 kg of the population mean brain weight of 1.10 kg.

Sample distribution follows normal distribution with mean( μ )= 1.10 kg,

and

standard deviation σ = 0.04

Z = (x - μ) / σ

Z = (1.1 + 0.1 - 1.1) / 0.04

= 2.5

Z = (1.1 - 0.1 - 1.1) / 0.04 = -2.5

P ( -2.5 < Z < 2.5) = 0.993

The percentage of all samples of twelve men that have mean brain weights within 0.1 kg of the population mean brain weight of 1.10 kg is 99.3%.

2)

Given mean = 1.60 kg,

standard deviation = 0.12 kg

68.26% of men in country A have brain weights between μ - σ and μ + σ

68.26% of men in country A have brain weights between 1.48 kg and 1.72 kg.

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Find the distance between the points (–7,–9) and (–2,4).

Answers

Answer:

13.93

Step-by-step explanation:

see attached for explanation

Guided Practice
Find the square.


(c + 1)2


A.
c2 + 1


B.
c2 + c + 1


C.
c2 + 2c + 1

Answers

Answer:

C

Step-by-step explanation:

(c + 1)(c+1) = c² + c + c + 1 = c² + 2c + 1

which equation has no real solutions?

2x²+2x+15=0

2x²+5x-3=0

x²+7x+2=0

x²-4x+2=0​

Answers

Answer:

A

Step-by-step explanation:

x=

−b±√b2−4ac

2a

x=

−(2)±√(2)2−4(2)(15)

2(2)

x=

−2±√−116

4

and there is really no solution

On average, a banana will last 6.2 days from the time it is purchased in the store to the time it is too rotten to eat. Is the mean time to spoil less if the banana is hung from the ceiling? The data show results of an experiment with 16 bananas that are hung from the ceiling. Assume that that distribution of the population is normal.

3.9, 4.9,5.1, 3.9, 4, 5.8, 7, 5, 3.6, 4.3, 4.4, 6, 6.8, 6.7, 7.1, 5.2

What can be concluded at the the α = 0.05 level of significance level of significance?

Answers

Using a one-sample t-test, we cannot conclude that the mean time to spoil is significantly different when bananas are hung from the ceiling.

One sample t-test

3.9, 4.9, 5.1, 3.9, 4, 5.8, 7, 5, 3.6, 4.3, 4.4, 6, 6.8, 6.7, 7.1, 5.2

We can calculate the sample mean and sample standard deviation:

Sample mean (x) = (3.9 + 4.9 + 5.1 + 3.9 + 4 + 5.8 + 7 + 5 + 3.6 + 4.3 + 4.4 + 6 + 6.8 + 6.7 + 7.1 + 5.2) / 16 = 5.3

Sample standard deviation (s) = √[(Σ(xi - x)²) / (n - 1)] = √[(Σ( - 5.3)²) / 15] ≈ 1.273

We will perform a one-sample t-test using the null hypothesis (H0) that the mean time to spoil is equal to 6.2 days, and the alternative hypothesis (H1) that the mean time to spoil is less than 6.2 days.

The test statistic is calculated as:

t = (x - μ) / (s / √n)

Where μ is the hypothesized mean (6.2), s is the sample standard deviation (1.273), and n is the sample size (16).

Plugging in the values:

t = (5.3 - 6.2) / (1.273 / √16) ≈ -0.887

To determine the critical t-value for a one-tailed test at α = 0.05 level of significance with 15 degrees of freedom (n - 1), we refer to the t-distribution table or use statistical software. The critical t-value is approximately -1.753.

Since the test statistic (-0.887) does not exceed the critical t-value (-1.753), we fail to reject the null hypothesis. This means that there is not enough evidence to conclude that the mean time to spoil is less when bananas are hung from the ceiling compared to the average time of 6.2 days, at the α = 0.05 level of significance.

Therefore, we cannot conclude that the mean time to spoil is significantly different when bananas are hung from the ceiling.

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The second quartile for the numbers:
231,423,521,139,347,400,345 is
A 231
B 347
C 330,
D 423

Which of the following measures of variability is dependent on every value in a Set of data?
A Range
B. Standard deviation
C A and B
D. Neither A nor B

Which one of these statistics is unaffected by Outliers?
A Mean
B. Interquartile range
C Standard deviation
D. Range

Answers

The second quartile for the numbers 231, 423, 521, 139, 347, 400, 345 is 347. The median value is the second quartile

. So, when the numbers are arranged in ascending order, 347 is in the middle.

The following measures of variability is dependent on every value in a Set of data:

Standard deviation is the measure of variability that is dependent on every value in a Set of data.

Standard deviation is a measure that is used to quantify the amount of variation or dispersion of a set of data values.

Among these statistics, the Interquartile range is unaffected by outliers. The IQR is the distance between the first quartile (Q1) and the third quartile (Q3), which represents the middle 50% of the data.

The interquartile range (IQR) is unaffected by outliers because it only uses the values of the data points located at the 25th and 75th percentile of the data set to measure variability.

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The assembly time for a product is uniformly distributed between 6 to 10 minutes. The probability of assembling the product in 8 minutes or less is a. 0.25 b. 0.75 c. 0.5 d. 1.5

Answers

The assembly time for a product is uniformly distributed between 6 to 10 minutes.

The probability of assembling the product in 8 minutes or less is 0.5 (option c).

Solution: Given, the assembly time for a product is uniformly distributed between 6 to 10 minutes. The range is a = 6 to b = 10.The probability of assembling the product in 8 minutes or less is to be determined.

Let's calculate the probability using the formula:  P(x < or = 8) = (x - a) / (b - a)Here, a = 6, b = 10, and x = 8.P(x < or = 8) = (8 - 6) / (10 - 6) = 2 / 4 = 0.5Therefore, the probability of assembling the product in 8 minutes or less is 0.5. So, the correct option is (c) 0.5.

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