Center: (-10, -4), Point on Circle: (4, -2)
Use the information given to write an equation of the vircle.

Answers

Answer 1

Answer:

Step-by-step explanation:

Left hand side.

The left hand side is the general equation that includes the center of the circle.

The center is at -10,-4

(x + 10)^2 + (y + 4)^2 = r^2

Finding the radius.

the radius is found from the given point on the circle

Givens

x1 = -10

x2 = 4

y1 = - 4

y2 = - 2

Equation

r^2 = (y2 - y1)^2 + (x2 - x1)

r^2 = (-2 - - 4)^2 + (4 - - 10)^2

r^2 = 2^2 + 14^2

r^2 = 200

Note:

The graph below shows two things: the first is that the center is at -10,-4The second is that the radius is a little more than 14. The equation of a circle always expresses the radius as r^2
Center: (-10, -4), Point On Circle: (4, -2)Use The Information Given To Write An Equation Of The Vircle.

Related Questions

Simplify. Use only one symbol between terms. Use standard form. 6x + 3 - 8 + x

Answers

Answer:

7 is the answer

Step-by-step explanation:

Because 6x + 3 -8 + x = x is 6


[tex] \frac{ - 48 + 6}{ - 7} + ( - 3)( - 4)( - 2)[/tex]

Answers

Step-by-step explanation:

[tex] \frac{ - 48 + 6}{ - 7} + ( - 3)( - 4)( - 2) \\ = \frac{ - 42}{ - 7} + 12( - 2) \\ = 6 + ( - 24) \\ = 6 - 24 \\ = - 18[/tex]

Correct Given the sample data, find the mean (round to 2 decimals): 23, 27, 35, 44 1.00 points out of 1.00 Flag question Answer: 32.25 Check Correct Marks for this submission: 1.00/1.00 Question 6 Incorrect 0.00 points out of 1.00 Given the data from problem 5 (sample data: 23, 27, 35, 44), find the sum of the squared deviations (the numerator of the fraction under the square root in the formula). In finding the number, round all calculations to 2 decimals (if you carry more or fewer your answer may be off enough to be marked incorrect on this system).

Answers

The sum of the squared deviation for the given sample data (23, 27, 35, 44) is 212.00.

In statistics, the squared deviation is calculated by subtracting each data point from the mean and then squaring the result. The sum of these squared differences gives us a measure of how much the individual data points vary from the mean.  

Find the sum of squared deviations, we first calculate the mean of the data set. In this case, the mean is found by adding up all the values (23 + 27 + 35 + 44) and dividing the sum by the number of data points (4).

The mean turns out to be 32.25.Next, we subtract the mean from each data point:

(23 - 32.25) = -9.25

(27 - 32.25) = -5.25

(35 - 32.25) = 2.75

(44 - 32.25) = 11.75

Then, we square each of these differences:

(-9.25)² = 85.56

(-5.25)² = 27.56

(2.75)² = 7.56

(11.75)² = 138.06

Finally, we sum up these squared deviations:

85.56 + 27.56 + 7.56 + 138.06

= 212.00

Therefore, the sum of the squared deviations is 212.00 (rounded to two decimal places).

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find the lateral surface area help needed asap will give brainliest

Answers

Step-by-step explanation:

3 Area of lateral = 3 ( bh ) = 12.2 XIO +7.04X12.2 +7.04x 12.2 = 122+85.888+85.888 = 293.776

293.776 approximate to 288

It's been found that there is a 15% chance (3 out of 20) that you can
win a particular game. How many "wins” would you have if you
played 80 times?

Answers

Heyy ummm im tired I’ll answer this later

PLEASE ASAP HELP!!! ​

Answers

The correct answer is D

a uniform solid disk of mass m = 2.91 kg and radius r = 0.200 m rotates about a fixed axis perpendicular to its face with angular frequency 5.94 rad/s.

Answers

A uniform solid disk with a mass of 2.91 kg and a radius of 0.200 m is rotating about a fixed axis perpendicular to its face with an angular frequency of 5.94 rad/s.

The angular frequency of an object rotating about a fixed axis represents the rate at which it completes one full revolution in radians per second. In this case, the disk has an angular frequency of 5.94 rad/s.

The moment of inertia of a uniform solid disk rotating about its axis can be calculated using the formula:

I = (1/2) * m * [tex]r^2[/tex]

where I is the moment of inertia, m is the mass of the disk, and r is the radius of the disk. Substituting the given values, we have:

I = (1/2) * 2.91 kg * [tex](0.200 m)^2[/tex]= 0.0582 kg·[tex]m^2[/tex]

The moment of inertia is a measure of an object's resistance to changes in rotational motion. In this case, the disk's moment of inertia is 0.0582 kg·[tex]m^2[/tex].

The angular frequency, moment of inertia, and mass of the disk are related by the equation:

I * ω = L

where ω is the angular frequency and L is the angular momentum. Rearranging the equation, we can solve for the angular momentum:

L = I * ω = 0.0582 kg·[tex]m^2[/tex] * 5.94 rad/s = 0.3456 kg·[tex]m^2[/tex]/s

Therefore, the angular momentum of the rotating disk is 0.3456 kg·[tex]m^2[/tex]/s.

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If an apple pie recipe calls for 3 pounds of candy apples then how many cups of canned apples required

Answers

Answer:

Seven cups of canned apples are required to make apple pie recipe

Step-by-step explanation:

The weight of one canned apple is 0.45 pounds

Weight of total canned apple required to make the apple pie recipe is 3 pounds.

Total number of cups of canned apples required

[tex]= \frac{3}{0.45} \\= \frac{300}{45} \\= \frac{20}{3} \\[/tex]

So approximately seven cups of canned apples are required to make apple pie recipe

which would result in an integer

Answers

Answer:

c I think but I am not sure but I hope you have a good day

The augmented matrix of a system of linear equations AX = B was reduced to upper-triangular form so that 2 1 02 [AB] 3 0 where m and n are real numbers. State all values of m and/or n such that the following statements are true. (a) Matrix A is invertible. (b) The system AX- B has no solutions. (c) The system AX = B has an infinite number of solutions. (a) Columns of the augmented matrix (AB) are linearly independent. (e) The system AX = 0 has a unique solution. (f) At least one eigenvalue of the matrix A is zero. (g) Columns of the matrix A form a basis in R3.

Answers

a. Matrix A is invertible when |A| = -m ≠ 0 then statement true.

b. The system AX = B has no solution when m = 0 and n ≠ 0 has a real number then statement true.

c. The system AX = B has an infinite number of solutions when m = n = 0 then statement true.

d. Columns of the augmented matrix (AB) are linearly independent when m ≠ 0 and n= 0 then statement true.

e. The system AX = 0 has a unique solution when m ≠ 0 then statement true.

f. At least one eigenvalue of the matrix A is zero when m = 0 then statement true.

g. Columns of the matrix A form a basis in R³ when m ≠ 0 then statement true.

Given that,

The augmented matrix of a system of linear equations AX = B was reduced to upper-triangular form so that

[A|B] = [tex]\left[\begin{array}{ccc}2&1&0 \ | \ 2\\0&-1&3 \ | \ 1 \\0&0&m \ | \ n\end{array}\right][/tex]

Where m and n are real numbers.

We know that,

a. We have to prove matrix A is invertible.

For A to be invertible.

|A| ≠ 0

|A| is the determinant of the matrix A.

|A| = 2(-m) -1(0) + 0(0) = -m

Here, m is the real number.

So, |A| = -m ≠ 0

Therefore, Matrix A is invertible when |A| = -m ≠ 0 then statement true.

b. We have to prove the system AX = B has no solution.

When Rank[A|B] > Rank[A]

m = 0 and n ≠ 0 has a real number

Therefore, The system AX = B has no solution when m = 0 and n ≠ 0 has a real number then statement true.

c. We have to prove the system AX = B has an infinite number of solutions.

When m = n = 0, and Rank[A] < 3

Therefore, The system AX = B has an infinite number of solutions when m = n = 0 then statement true.

d. We have to prove columns of the augmented matrix (AB) are linearly independent.

When m ≠ 0 and m∈R and n= 0

Therefore, Columns of the augmented matrix (AB) are linearly independent when m ≠ 0 and n= 0 then statement true.

e. We have to prove the system AX = 0 has a unique solution.

When [tex]\left[\begin{array}{ccc}2&1&0 \\0&-1&3 \\0&0&m \end{array}\right]\left[\begin{array}{ccc}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}0\\0\\0\end{array}\right][/tex]

The equation are 2x + y = 0, -y + 3z = 0 and mz = 0

m ≠ 0 should be any real number except zero.

Therefore, The system AX = 0 has a unique solution when m ≠ 0 then statement true.

f. We have to prove at least one eigenvalue of the matrix A is zero.

When λ = 2, 1, m

m = 0 then eigen value is zero

Therefore, At least one eigenvalue of the matrix A is zero when m = 0 then statement true.

g. We have to prove columns of the matrix A form a basis in R³.

When m ≠ 0

Therefore, Columns of the matrix A form a basis in R³ when m ≠ 0 then statement true.

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A child toy is made by removing a triangular prism from the center of a wooden rectangular prism The triangular base of the triangular prism has a base length of 1 inch and a height of 1 inch. Write and solve an equation to find the volume of the toy.

Answers

*see attachment for the diagram given

Answer:

Volume of the toy = 68 in.³

Step-by-step explanation:

The equation to find the volume of the toy = volume of the wooden rectangular prism - volume of the triangular prism removed form the center

Volume of the toy = (L*W*H) - (½*bhl)

Where,

L = 8 inches

W = 3 inches

H = 3 inches

b = 1 inch

h = 1 inch

l = 8 inches

Plug in the values into the equation

Volume of the toy = (8*3*3) - (½*1*1*8)

Volume = 72 - 4

Volume of the toy = 68 in.³

If f is any function, then the associated Green's Function G[f] is given by G[f](x) = integral ^x_0 f(s) sin(x - s)ds. Use variation of parameters to show that G[f] is a solution of y" + y = f(x).

Answers

We have: u''(x) = ƒ(x)cot(x) - 2u'(x)cot(x).Thus, we can find a particular solution of this differential equation by using variation of parameters.

Let G(x) = ƒ(s)sin(x - s) ds.

Then, by the product rule, we have: G' = ƒ(s)cos(x - s) ds - ƒ(s)sin(x - s) ds, and G'' = -ƒ(s)sin(x - s) ds - ƒ(s)cos(x - s) ds. Hence, we have:G'' + G = ƒ(s)sin(x - s) ds - ƒ(s)cos(x - s) ds + ƒ(s)sin(x - s) ds = ƒ(s)sin(x - s) ds = G.

So, G is indeed a solution of y'' + y = ƒ(x).Next, we will use variation of parameters to find a second solution of the same differential equation.

Let us suppose that we have another solution of the form y = u(x) sin(x).

Then, y' = u(x)cos(x) + u'(x)sin(x), and y'' = - u(x)sin(x) + 2u'(x)cos(x) + u''(x)sin(x).

Substituting these into the differential equation, we get:- u(x)sin(x) + 2u'(x)cos(x) + u''(x)sin(x) + u(x)sin(x) = ƒ(x)2u'(x)cos(x) + u''(x)sin(x) = ƒ(x)

Dividing by sin(x), we get:2u'(x)cot(x) + u''(x) = ƒ(x)cot(x).

Now, let us assume that the second solution is of the form y = u(x)sin(x), where u is a function to be determined.

Then, we have: y' = u(x)cos(x) + u'(x)sin(x) and y'' = - u(x)sin(x) + 2u'(x)cos(x) + u''(x)sin(x).

Substituting these into the differential equation, we get: - u(x)sin(x) + 2u'(x)cos(x) + u''(x)sin(x) + u(x)sin(x) = ƒ(x)2u'(x)cos(x) + u''(x)sin(x) = ƒ(x)

Dividing by sin(x), we get:2u'(x)cot(x) + u''(x) = ƒ(x)cot(x).

Hence, we have: u''(x) = ƒ(x)cot(x) - 2u'(x)cot(x).Thus, we can find a particular solution of this differential equation by using variation of parameters.

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O There were 9 bags of
candy donated for the
neighborhood party.
Each bag contained
245 pieces. How much
candy did they have
for the party?

Answers

9*245 =2205
hope this helps

PLEASE HELP
WILL GIVE BRAINLIEST

Identify the situation that each graph could represent.

A ray is graphed in the first quadrant. The horizontal axis is labeled Time. The ray starts at the bottom left and continues to the upper right.



A. the length of a necklace that you make at a rate of 10 cm per hour without taking a break
B. the height of a balloon as it rises, gets caught in a tree for a few minutes, and then continues to rise
C. the total distance you are from home if you ride your bicycle three miles per hour for one hour, and then stop and take a rest
D. The volume of water in a bath tub as it is draining.

Answers

Answer:

The answer your looking for is, C.

The answer that you are looking for is c

PLEASE HELP:

The distance d, in kilometers, that a car travels at a speed of 80 km per hour, for t hours, is given by the equation d= 80t. What is the inverse to represent time, t as a function of distance, d?

Choices:
1. t= d/80
2.t= 80/d
3.t= 80d

Answers

Answer:

The car was traveling for 1.5 hours.

Step-by-step explanation:

Given that distance d, in kilometers, that a car travels at a speed of 80 km per hour , for t hours, is given by the equation d=80t.

Here wee need to find the time if the car has gone 120 kilometers.

That is

            d = 120 km

we need to find t.

            d=80t

           120 = 80 x t

The car was traveling for 1.5 hours.

find the hcf of px4 + px ,qx3 _ qx ​

Answers

Step-by-step explanation:

1st expression

= px^4 + px

= px ( x³ + 1 )

= px ( x + 1) (x² - x + 1)

2nd expression

= qx³ - qx

= qx ( x² - 1 )

= qx ( x + 1) ( x - 1)

HCF = x ( x + 1)

Hope it will help :)❤

Convert the point from Cartesian to polar coordinates. Write your answer in radians. Round to the nearest hundredth.
(−10,1)

Answers

The point (-10, 1) in Cartesian-Coordinates can be represented in polar coordinates as approximately (10.05, 3.0416 radians).

To convert the point (-10, 1) from Cartesian-Coordinates to polar coordinates, we can use the formulas:

r = √(x² + y²)

θ = arctan(y / x)

We know that, the point is (-10, 1), we substitute the values into the formulas:

We get,

r = √((-10)² + 1²) = √(100 + 1) = √101 ≈ 10.05, and

The point lies in second-quadrant, so, the angle is measured counterclockwise from the positive x-axis, which means it is between π/2 and π radians.

Therefore, The adjusted θ is : θ = π + arctan(1/-10) ≈ 3.0416 radians.

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If m(x) = x+5/x-1 and n(x)=x-3, which function has the same domain as (m o n)(x)?

Answers

it's simple it's really easy so the answer is 2.0 1682

The American Hospital Association stated in its annual report that the mean cost to community hospitals per patient per day in U.S. hospitals was $1231 in 2007. In that same year, a random sample of 25 daily costs in the state of Utah hospitals yielded a mean of $1103. Assuming a population standard deviation of $252 for all Utah hospitals, do the data provide sufficient evidence to conclude that in 2007 the mean cost in Utah hospitals is below the national mean of $1231? Perform the required hypothesis test at the 5% significance level.

Answers

We can conclude that the null hypothesis is rejected. There is sufficient evidence to support the claim that the mean cost in Utah hospitals is below the national mean of $1231.

How is this so?

H₀: μ ≥ 1231 (The mean cost in Utah hospitals is greater than or equal to the national mean)

Hₐ: μ < 1231 (The mean cost in Utah hospitals is below the national mean)

Given

Sample mean (x) = $1103Sample size (n) = 25Population standard deviation (σ) = $252Significance level (α) = 0.05

The test statistic for a one-sample t-test is given by

t = (x - μ) / (σ / √n)

Substituting we have

t = (1103 - 1231) / (252 / √25)

≈ -6.103

To determine the critical value, we need to find the critical t-value at the 5% significance level with degrees of freedom

(df) equal to (n - 1)

= (25 - 1)

= 24.

Using a t-distribution table or calculator, the critical value is approximately -1.711.

Since the calculated test statistic (-6.103) is smaller than the critical value (-1.711) and falls into the critical region, we reject the null hypothesis.

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Help please show work how to get the answer.

Answers

Answer:

A or D

Step-by-step explanation:

Solve for x.
20
8
4x+3
38

Answers

Answer:

x = 18

Step-by-step explanation:

The "Angle Bisector" Theorem says that an angle bisector of a triangle will divide the opposite side into two segments that are proportional to the other two sides of the triangle.

So, 20/8 = (4x + 3)/30

8(4x + 3) = 20(30)

32x + 24 = 600

32x = 576

x = 18

Mark sorted a set of shapes into two different categories. Explain, what two attributes were used to sort the shapes. help please!!

Answers

Group A parallelogram, Group B Quadrilateral.

Answer: Parallelogram and Quadrilateral.

The  two ways of classifying shapes are: Parallelogram and Quadrilateral.

There are different ways to classify an item.

How do one identify the type of quadrilateral?

Quadrilaterals can be known by;

It is a polygon with four sides.

Since rectangle is known to be a parallelogram that has four right angles.

A trapezoid is regarded as a quadrilateral with only one pair of parallel sides.

And Parallelograms are known to be shapes that has four sides with only two pairs of sides that are known to be parallel.

So we conclude that Group A parallelogram, and Group B Quadrilateral.

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Combine the like terms to create an equivalent expression for −n+(−4)−(−4n)+6

Answers

Answer:

3n + 2

Step-by-step explanation:

−n+(−4)−(−4n)+6

-n - 4 + 4n + 6

3n + 2

The time it takes for someone to finish a bowl of ramen can be modeled by a random variable with the following moment generating function: 

M(t)= 1/ (1−0.05t​)1​,t<0.05 


Find the variance of the time it takes for someone to finish a bowl of ramen.

Answers

Therefore, the variance of the time it takes for someone to finish a bowl of ramen is 4.6875.

Given, The moment generating function of the time it takes for someone to finish a bowl of ramen is

M(t)= 1/ (1−0.05t​)1​,t<0.05 We have to find the variance of the time it takes for someone to finish a bowl of ramen.

The variance of the random variable can be calculated by the formula Variance = M''(0) - [M'(0)]^2 where M(t) is the moment generating function of the random variable M'(t) is the first derivative of M(t)M''(t) is the second derivative of M(t)

We need to find M''(t) and M'(t)M(t) = 1/(1 - 0.05t)M'(t) = [0.05/(1 - 0.05t)^2]M''(t) = [0.1/(1 - 0.05t)^3] Now, at t = 0, M(0) = 1, M'(0) = 1.25, M''(0) = 6.25 Variance = M''(0) - [M'(0)]^2 Variance = 6.25 - (1.25)^2 Variance = 6.25 - 1.5625 Variance = 4.6875

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Given: The time it takes for someone to finish a bowl of ramen can be modeled by a random variable with the following moment generating function: M(t)= 1/ (1−0.05t​)1​,t<0.05. The variance of the time it takes for someone to finish a bowl of ramen is 400.

The moment generating function of a random variable is defined as [tex]$M(t) = \mathbb{E}(e^{tX})$[/tex] for all t in an open interval around 0 which X is a random variable.

We are given that the moment generating function of the random variable T is given by:

[tex]$$M(t)= \frac{1}{1-0.05t} ,\ t < 0.05$$[/tex]

The [tex]$n^{th}$[/tex] derivative of M(t) at 0 is given by:

[tex]$$\frac{d^n}{dt^n} M(t) \biggr|_{t=0} = \mathbb{E}(X^n)$$[/tex]

We differentiate $[tex]M(t)$[/tex] with respect to $t$ to get [tex]$$M'(t) = \frac{0.05}{(1 - 0.05t)^2}$$[/tex].

Differentiating [tex]$M'(t)$[/tex] with respect to [tex]$t$[/tex] we get [tex]$$M''(t) = \frac{2(0.05)^2}{(1-0.05t)^3}$$[/tex].

Differentiating [tex]$M''(t)$[/tex] with respect to [tex]$t$[/tex] we get [tex]$$M'''(t) = \frac{6(0.05)^3}{(1-0.05t)^4}$$[/tex].

Substituting t = 0, we get [tex]$$M'(0) = \frac{1}{0.05} = 20$$[/tex]

[tex]$$M''(0) = \frac{2}{(0.05)^3} = 800$$[/tex]

[tex]$$M'''(0) = \frac{6}{(0.05)^4} = 4800$$[/tex]

Using the following formula to calculate the variance of X: [tex]$$Var(X) = \mathbb{E}(X^2) - [\mathbb{E}(X)]^2$$[/tex], where [tex]$$\mathbb{E}(X^2) = M''(0) = 800$$[/tex].

[tex]$$[\mathbb{E}(X)]^2 = [M'(0)]^2 = 400$$[/tex]

Hence, we get:$$Var(X) = 800 - 400 = \boxed{400}$$.

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12 × (3 + 2²) ÷ 2 - 10

Answers

Answer:

32

Step-by-step explanation:

Answer:

32

Step-by-step explanation:

This should help

Least:
Greatest:.
Median
Lower Quartile Range:
Upper Quartile Range:
thx :)

Answers

Answer:

Below :)

Step-by-step explanation:

Least/Minimum: 0

Greatest/Maximum: 6

Median: 2

Lower Quartile Range: 1

Upper Quartile Range: 3

Find median:

0, 1, 1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 3, 3, 3, 3, 4, 4, 4, 6

Find Lower Quartile:

0, 1, 1, 1, 1, 1, 1, 2, 2, 2

Find Upper Quartile:

2, 2, 3, 3, 3, 3, 4, 4, 4, 6

What is the vertex of f(x) = -2|x + 1| + 2?

Answers

Answer:

(-1,2) i think

Step-by-step explanation:

What is 5x÷6=20
Pls help I can't figure it out

Answers

Answer:

x= 24

Step-by-step explanation:

5x=20*6

x=120/5

x=24

Hope this helps! Plz mark as brainliest! :)

In a normal distribution, approximately what percentage of scores fall between the z scores of -1.00 and + 1.00?

Answers

In a normal distribution, approximately 68% of scores fall between the z-scores of -1.00 and +1.00.

In a standard normal distribution, which has a mean of 0 and a standard deviation of 1, the Empirical Rule (also known as the 68-95-99.7 Rule) applies. According to this rule, approximately 68% of the data falls within one standard deviation from the mean.

Since the z-scores represent the number of standard deviations a particular value is away from the mean, a z-score of -1.00 represents one standard deviation below the mean, and a z-score of +1.00 represents one standard deviation above the mean. Therefore, using the Empirical Rule, we can conclude that approximately 68% of scores fall between these two z-scores (-1.00 and +1.00).

This percentage represents the central portion of the distribution that is within one standard deviation from the mean, providing a useful measure of the spread and concentration of data in a normal distribution.

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Which of the following sets of ordered pairs does not define a function?

{(1,2),(5,6),(6,7),(10,11),(13,14)}
{(−1,4),(0,4),(1,4),(2,4),(3,4)}
{(1,1),(2,2),(3,3),(4,4),(5,5)}
{(1,3),(5,2),(6,9),(1,12),(10,2)}

Answers

Answer: D

Step-by-step explanation: As we can see, D is the only one that has matching inputs, but those inputs have separate outputs. If they don't have the same output, it is not a function

Hope this helps :)

Other Questions
modeling is particularly effective when paired with ___________ when training novice performers who have learning disabilities. The following are primary purchasers of preferred stock except:a. Corporate investors,b. Insurance companies,c. Pension funds,d. Individual investors. The number of elements of Z3[x] / is 6 9 8 O 3 Question * The number of reducible monic polynomials of degree 2 over Zz is: 2 6 O 4 8 Konkuk Foundation (KF) began operations on January 1st 2021, the first day of its fiscal year with the assets, liability and net asset balances shown in the following table. Record the eight transactions (1-8) below on the worksheet provided with the exam.Account Beginning BalanceCash $25,000Grants Receivable 2,000Inventory 2,000Unrestricted Net Assets 50,000Pledges Receivable 1,000Property, plant, and equipment 25,000Wages Payable $5,000Be sure to identify the accounts impacted by each transaction and show that the transactions are balanced. You must enter each transaction in the worksheet provided.1) Took out a $50,000 bank loan. SF also signed a contract with a local car dealer to buy a van for their summer program and gave the dealer a $1,000 deposit. 2) Received $50,000 in contribution pledges and cash contributions from members of the Konkuk community. $25,000 of the contributions were received in cash. KF expects that 20% of the remaining pledges will not be collected. 3) Received a check for $10,000 from the Korea Society. This amount includes the final payment of $2,000 from a grant made by the Korea Society in 2019 as well as new grant for the remainder. 4) Purchased a van for $50,000. The van is expected to have a useful life of 10 years and no residual value. KF uses straight-line depreciation. The van was purchased at the beginning of the year. 5) Purchased $5,000 worth in supplies for the Summer Camp. KF paid 80% of the cost of the supplies in cash. 6) KF paid its employees $30,000 in wages during the fiscal year. Wage expense for the year was $25,000. The payment included the wages payable balance outstanding from fiscal year 2020. 7) By the end of the year, LU used $4,000 worth of supplies to operate their summer camp. 8) Complied with terms of the bank loan, which require KF to pay the bank $1,400. That includes interest for the year at an annual rate of 2% plus a portion of the principal.40. Prepare a Balance Sheet for KF as of December 31, 2021, the last day of fiscal year, along with a comparative balance sheet for the prior fiscal year, 2020.41. Prepare an Activity Statement for KF for the fiscal year ending December 31, 2021.42. Prepare a Cash Flow Statement for KF for the fiscal year ending December 31, 2021. Express the confidence interval 77.1% 3.8 % in interval form. ______Express the answer in decimal format (do not enter as percents). In the past, patrons of a cinema complex have spent an average of $2.50 for popcorn and other snacks. The amounts of these expenditures have been normally distributed. Following an intensive publicity campaign by a local medical society, the mean expenditure for a sample of 18 patrons is found to be $2.10. The standard deviation is found to be $0.90. Which of the following represents an 80% confidence interval for the population average amount spent by patrons of a cinema complex on popcorn and other snacks following an intensive publicity campaign by a local medical society? ($1.65, $2.55) ($1.73, $2.47) ($1.49, $2.71) ($1.82, $2.38) ($1.56, $2.64) Which statement is true about the definition of done (DoD)? The DOD should evolve as system capabilities evolve The teams share one common DOD At the higher levels there is only one DOD for everything that passes through Agile Release Train to a Solution increment or a release DOD is not used by teams because it is used as a method to manage technical debt across the ART Prove that there is a way to arrange all the dominoes in a cycle respecting the usual rules of the game using graph theory. When calculating the probability P(z -1.65) under the StandardNormal Curve we obtain: P1321 AGENCY COSTS AND CAPITAL STRUCTURE Galaxy Enterprises has earnings before interest and taxes of $9 million and $90 million of debt outstanding with a required rate of return of 7.3%. The required rate of return on assets in the industry is 12%. The corporate tax rate is 21%, but there are no personal taxes. The present value of Galaxys bankruptcy costs is $18 million. Compute Galaxys firm value. The weights of four randomly and independently selected bags of potatoes labeled 20.0 pounds were found to be 20.9, 21.4, 20.7, and 21.2 pounds. Assume Normality. Answer parts (a) and (b) below. a. Find a 95% confidence interval for the mean weight of all bags of potatoes. (Type integers or decimals rounded to the nearest hundredth as needed. Use ascending order). A mining companys reclamation plan is not permitted because there is no evidence that funding has been secured to repurpose the land in the manner proposed. What issue related to land reclamation is this an example of?A. Cost issueB. Conflict of interest issue C. Standards an measurements issue D. Quality assurance issue Minstrel Manufacturing uses a job order costing system. During one month, Minstrel purchased $203,000 of raw materials on credit; issued materials to production of $200,000 of which $25,000 were indirect. Minstrel incurred a factory payroll of $155,000, of which $35,000 was indirect labor. Minstrel uses a predetermined overhead rate of 150% of direct labor cost. The total manufacturing costs added during the period are: Multiple Choice $475,000. $527,500 $500,000. $562,500 $587,500 what discussions between byron and shelley influenced the development of her idea? evaluate the indefinite integral as a power series. x3 ln(1 x) dx A flexible budget is prepared before the master budget. True / False which type of web-based attack uses the get and post functions of an html form? Compare and evaluate how the companies described in this case study dealt with the challenges of BYOD. which of the following was derived from an ancestral cyanobacterium?a. falgellab. chloroplastc. mitosomed. mitochondrion How did countries around the world respond to the Holocaust after World War11?A. They demonstrated that crimes against humanity would not bepunished harshly.B. They established a new category of crimes for actions similar tothose of the Holocaust.C. They ordered that Germany pay huge reparations to Jews living inGermany.D. They established that no officer could ever be put on trial forfollowing orders.