calculate the electric flux that passes thruigh each of the dix faces of the cube

The solution to the differential equation is then:

x(t) = 0.25e⁽⁻⁶·⁰²⁵t⁾ cos(2.181t)

And the system is underdamped because the roots of the characteristic equation have a non-zero imaginary part.

The force required to stretch a spring is directly proportional to the amount the spring is stretched. This relationship is known as Hooke’s Law. It can be expressed mathematically as:

F = -kx

Where F is the force applied to the spring, x is the displacement of the spring from its equilibrium position, and k is the spring constant.

For a mass-spring system under the influence of a damping force, the differential equation governing the system is:

m(d2x/dt2) + c(dx/dt) + kx = 0

where m is the mass of the object attached to the spring, c is the damping coefficient, and k is the spring constant.

The given force of 2 lb stretches the spring by 1 ft, so the spring constant is given by k = F/x = 2/1 = 2 lb/ft.

The 8-lb weight is released 4 in. above the equilibrium position, which is 0.25 ft. The initial displacement is therefore x(0) = 0.25 ft, and the initial velocity is v(0) = 0. The damping force is given by f_d = -3/2v. Using the values given, the differential equation for the system is:

m(d2x/dt2) + c(dx/dt) + kx = 0 (1)

The values of m, k, and c are given by

m = 8/g = 8/32.2 = 0.248 kg

k = 2/lb/ft * 0.4536 kg/lb * 0.3048 m/ft = 0.294 kg/sm = 0.248 kgc = 3/2

The equation of motion is then:

d2x/dt2 + 12.05dx/dt + 1.186x = 0 (2)

where we have substituted the values of m, c, and k into equation (1).

The characteristic equation is:

r2 + 12.05r + 1.186 = 0 (3)

Solving for the roots of the characteristic equation, we find:

r = (-12.05 ± √(12.052 - 4(1.186)))/2= -6.025 ± 2.181i

The roots are complex conjugates, so the solution to the differential equation can be written as:

x(t) = e⁽⁻⁶·⁰²⁵t⁾(C₁ cos(2.181t) + C₂ sin(2.181t)) (4)

The initial displacement and velocity are given by x(0) = 0.25 and v(0) = 0.

Substituting these values into equation (4) and taking the derivative, we get:

x(0) = C₁ = 0.25dx/dt|t=0 = -6.025

C₂ = 0

Solving for C₁ and C₂, we get:

C₁ = 0.25C2 = 0

The solution to the differential equation is then:

x(t) = 0.25e⁽⁻⁶·⁰²⁵t⁾ cos(2.181t) (5)

The system is underdamped because the roots of the characteristic equation have a non-zero imaginary part.

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Answer:

The type of bond is ionic bond also called electrovalent bond.

Explanation:

This ionic bond is formed through an electrostatic attraction between two oppositely charged atoms.

Hope this helps! :)

And also this question was already answered on Brainly if you wanna check it out.

Answer:

Yes

Momentum is a vector quantity

Explanation:

A vector quantity is a quantity that has both magnitude and direction

So definitely direction matters

Answer:

no on edge 2021

Explanation:

Answer:

A force of 355 N is applied to an object that accelerates at a rate of 7.8 m/sec2 . What is the mass of the object ?

Explanation:

Answer:

The kinetic energy of the baseball is 306.25 joules.

Explanation:

SInce the baseball can be considered a particle, that is, that effects from geometry can be neglected, the kinetic energy ([tex]K[/tex]), in joules, is entirely translational, whose formula is:

[tex]K = \frac{1}{2}\cdot m\cdot v^{2}[/tex] (1)

Where:

[tex]m[/tex] - Mass, in kilograms.

[tex]v[/tex] - Speed, in meters per second.

If we know that [tex]m = 0.5\,kg[/tex] and [tex]v = 35\,\frac{m}{s}[/tex], then the kinetic energy of the baseball thrown by the player is:

[tex]K = \frac{1}{2}\cdot m \cdot v^{2}[/tex]

[tex]K = 306.25\,J[/tex]

The kinetic energy of the baseball is 306.25 joules.

Answer:

When atoms from different elements are joined together in groups, they form molecules. The atoms in molecules bind together chemically, which means that the atoms cannot be separated again by physical means, such as filtration. The molecule has different properties from the elements from which is was made.

Explanation:

The force experienced by the loop can be utilized to measure the field strength of the uniform magnetic field.

This force is known as the magnetic force or the Lorentz force.

The magnetic force (F) on a current-carrying loop of wire in a magnetic field is given by the equation:

[tex]F = I * B * A * sin(\theta)[/tex]

Where:

F is the magnetic force,

I is the current flowing through the loop,

B is the magnetic field strength,

A is the area of the loop, and

θ is the angle between the magnetic field and the normal to the loop.

In this case, the loop is placed perpendicular to the magnetic field, so θ = 90 degrees, and sin(θ) = 1. Therefore, the equation simplifies to:

F = I * B * A

By adjusting the current and measuring the resulting force, we can calculate the magnetic field strength (B) using the equation:

B = F / (I * A)

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--The complete question is, How the force on a loop of wire in a magnetic field can be used to measure the field strength? the field is uniform, and the plane of the loop is perpendicular to the field.--

B: the maximum speed of the emitted electrons decreases.

The photoelectric effect is the phenomenon where electrons are emitted from a metal surface when light of sufficient energy, or frequency, falls on it. The energy of a photon of light is directly proportional to its frequency (E = hf), where h is Planck's constant and f is the frequency of the light.

When the frequency of the incident light is decreased, the energy of each photon decreases. According to the photoelectric effect equation (E = hf = Φ + 1/2mv²), where Φ is the work function of the metal and v is the speed of the emitted electron, if the energy of the incident photon is lower than the work function, no electrons will be emitted.

Since the frequency of the light is directly related to its energy, decreasing the frequency decreases the energy of the photons. Consequently, fewer electrons will have sufficient energy to overcome the work function and be emitted from the metal. Therefore, the number of electrons emitted from the metal decreases.

Furthermore, the maximum speed of the emitted electrons is determined by the energy of the incident photons. With decreased frequency and lower energy photons, the maximum kinetic energy of the emitted electrons decreases. As kinetic energy is directly proportional to the square of the velocity (1/2mv²), the maximum speed of the emitted electrons decreases.

The correct answer is B: the maximum speed of the emitted electrons decreases. As the frequency of the incident light is decreased, the number of electrons emitted from the metal also decreases, and the maximum speed of the emitted electrons decreases due to the lower energy of the incident photons.

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The gauge pressure that someone would measure for the can of soda located at sea level is 2.0 atm.

Gauge pressure is the pressure measured relative to atmospheric pressure. At sea level, the atmospheric pressure is approximately 1.0 atm. To find the gauge pressure, we subtract the atmospheric pressure from the internal absolute pressure.

Gauge pressure = Internal absolute pressure - Atmospheric pressure

Given that the internal absolute pressure is 3.0 atm and the atmospheric pressure is 1.0 atm, we can substitute these values into the equation:

Gauge pressure = 3.0 atm - 1.0 atm = 2.0 atm

If the can of soda is located at sea level, someone would measure a gauge pressure of 2.0 atm. Gauge pressure represents the pressure above or below atmospheric pressure, and in this case, the can has an internal pressure that is 2.0 atm higher than the atmospheric pressure at sea level.

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A.  FALSE. In the equation, 'b' represents the y-intercept not slope.

B. TRUE. The graph of a linear function is always a straight line.

C. FALSE. The domain of the function y = √3 − x is the set of all real numbers greater than or equal to 3.
D. FALSE. The operation of function composition is not commutative

The operation of function composition is not generally commutative. For functions f and g, it's not necessarily true that f(g(x)) = g(f(x)). The order in which functions are composed can affect the result.

The domain of the function y = √(3 - x) is the set of all real numbers less than or equal to 3.

This is because for the expression under the square root to be non-negative (and thus yield a real number as output), x must be less than or equal to 3.

However, if the expression was y = √3 - x, it would have a different meaning, and the domain would be all real numbers, because √3 is a constant, and subtracting any real number x from a constant yields a real number

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Answer:

liquids and gases

Explanation:

Liquids and gases are considered to be fluids because they yield to shearing forces, whereas solids resist them.

Answer:

680.4

Explanation:

the formula is V1 over T1 is equals (=) to V2 over T2 .

and we have been given that

V1 represents 315

T1 represents 25°c

V2 is unknown and what we're finding

T2 represents 54°c

so 315×54 all over 25 ...gives you 680.4

The density of water is 1.0 g/cm³. It's required to determine the mass of water displaced by a submerged 120-cm³ block and the buoyant force on the block.To find the mass of water displaced by a 120 cm³ block, we first need to know the mass of 1 cm³ of water, which is equal to its density, which is 1.0 g/cm³.

The volume of the block is 120 cm³, so we can calculate its mass by multiplying its volume by the density of water. Therefore, the mass of the block submerged in water is:120 cm³ × 1.0 g/cm³ = 120 gTo find the number of kilograms, we divide the value obtained by 1000. Therefore, 120 g = 0.12 kg.The buoyant force is equal to the weight of the water displaced by the block. The buoyant force equals the weight of water displaced by the object.

The weight of 1 cm³ of water is 9.8 N (newtons), which is equal to the weight of 1 g of water. We can use this to calculate the weight of water displaced by the block as follows:120 cm³ × 1.0 g/cm³ × 9.8 N/g = 1176 NTherefore, the buoyant force acting on the block is 1176 N (Newtons).

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Answer:

I'm corona positive and isolated feeling depressed just logged in to talk someone but people ignoring me thanks for this behaviour got disappointed bye everyone logging out had a great time

To make the red light appear green, you would need to be traveling at a speed of approximately 2.727×10⁸ m/s.

The color of light is determined by its wavelength. Red light has a longer wavelength than green light, with the given values of 650 nm and 550 nm, respectively.

The frequency of light is inversely proportional to its wavelength, so we can use the formula:

frequency = speed of light / wavelength

Given that the speed of light is 3×10⁸ m/s, we can calculate the frequencies of red and green light:

Frequency of red light = (3×10⁸ m/s) / (650×10⁻⁹ m) = 4.615×10¹⁴ s⁻¹

Frequency of green light = (3×10⁸ m/s) / (550×10⁻⁹ m) = 5.455×10¹⁴ s⁻¹

To perceive the red light as green, we need to match the frequencies. Since the speed of light remains constant, we can equate the two frequencies:

(3×10⁸ m/s) / (λ_red) = (3×10⁸ m/s) / (λ_green)

Simplifying the equation, we find:

λ_red = λ_green

From this, we can determine the speed required to make the red light appear green:

v = (λ_red - λ_green) / λ_green = (650×10⁻⁹ m - 550×10⁻⁹ m) / 550×10⁻⁹ m = 100×10⁻⁹ m / 550×10⁻⁹ m

v ≈ 2.727×10⁸ m/s

Therefore, in order for the red light to appear green, you would need to be moving at a velocity of approximately 2.727×10⁸ m/s.

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The image of the shopper is 75.0 cm from the mirror's surface, and it is virtual.

The magnification (m) of an image formed by a convex mirror is given by the formula:

m = -d_i / d_o,

where d_i is the distance of the image from the mirror's surface and d_o is the distance of the object from the mirror's surface. In this case, the magnification is given as 0.250.

Given that the shopper is standing 3.00 m from the convex mirror (d_o = 3.00 m) and the magnification is 0.250, we can rearrange the formula to solve for d_i:

d_i = -m * d_o.

Substituting the values into the formula:

d_i = -0.250 * 3.00,

   = -0.75 m.

The negative sign indicates that the image is virtual, meaning it cannot be projected onto a screen. Taking the absolute value, the image is 0.75 m from the mirror's surface.

Converting 0.75 m to centimeters, we get 75.0 cm.

The image of the shopper is located 75.0 cm from the convex mirror's surface, and it is a virtual image. This calculation utilizes the magnification formula for a convex mirror to determine the distance of the image based on the given magnification and object distance.

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When heating a sample of liquid water, the point at which boiling begins is best described as the temperature at which the vapor pressure of the liquid equals the atmospheric pressure.

The point at which boiling begins is when the vapor pressure of the liquid equals the atmospheric pressure. At this point, the liquid can no longer hold any more vapor and bubbles of vapor form and rise to the surface. The temperature at which this occurs is called the boiling point.

For water at sea level, the boiling point is 100°C (212°F). However, the boiling point of water can vary depending on the atmospheric pressure. At higher altitudes, the atmospheric pressure is lower, so the boiling point of water is lower. For example, at the top of Mount Everest, the boiling point of water is about 70°C (160°F).

The boiling point of a liquid can also be affected by the presence of impurities. For example, salt water has a higher boiling point than pure water. This is because the salt molecules interfere with the formation of water vapor.

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(a) The charge moving through the battery each second is 0.80 Coulombs. (b) The electric potential energy of the charge increases by 9.12 Joules as it moves through the battery.

Part A:

The charge moving through the battery each second can be calculated using the formula:

Q = I * t

Where Q is the charge, I is the current, and t is the time.

Given that the laptop uses 0.80 A while running, the charge moving through the battery each second can be calculated as:

Q = (0.80 A) * (1 s)

Calculating this expression gives us:

Q = 0.80 C

Therefore, the charge moving through the battery each second is 0.80 Coulombs.

Part B:

The change in electric potential energy as the charge moves through the battery can be calculated using the formula:

ΔPE = Q * ΔV

Where ΔPE is the change in electric potential energy, Q is the charge, and ΔV is the change in voltage.

In this case, since the battery has an emf (electromotive force) of 11.4 V, the change in voltage is equal to the emf. Therefore, we have:

ΔPE = Q * emf

Substituting the known values, we have:

ΔPE = (0.80 C) * (11.4 V)

Calculating this expression gives us:

ΔPE = 9.12 J

Therefore, the electric potential energy of the charge increases by 9.12 Joules as it moves through the battery.

(a) The charge moving through the battery each second is 0.80 Coulombs.

(b) The electric potential energy of the charge increases by 9.12 Joules as it moves through the battery.

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The distance between the two 100 kg persons needs to be approximately 8.17 x 10^-4 meters (or 0.817 mm) in order for the force they exert on each other to be equal to 1 N.

To calculate the distance between two 100 kg persons so that the force they exert on each other is equal to 1 N, we can use Newton's law of universal gravitation.

The formula for gravitational force (F) between two objects is:

F = (G * m1 * m2) / r^2

where G is the gravitational constant (approximately 6.672 x 10^-11 N·m^2/kg^2), m1 and m2 are the masses of the objects, and r is the distance between the centers of the objects.

In this case, we want the force to be 1 N, and both persons have a mass of 100 kg. Substituting these values into the formula, we get:

1 N = (6.672 x 10^-11 N·m^2/kg^2 * 100 kg * 100 kg) / r^2

Simplifying the equation:

1 N = (6.672 x 10^-7 N·m^2) / r^2

Rearranging the equation to solve for the distance (r):

r^2 = (6.672 x 10^-7 N·m^2) / 1 N

r^2 = 6.672 x 10^-7 m^2

Taking the square root of both sides:

r ≈ 8.17 x 10^-4 m

Therefore, the distance between the two 100 kg persons needs to be approximately 8.17 x 10^-4 meters (or 0.817 mm) in order for the force they exert on each other to be equal to 1 N. Option B, 6.672 x 10^-7 m, appears to be a typographical error as it corresponds to the value of the gravitational constant rather than the distance.

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The acceleration of this car include the following: A. 2 m/s².

In Science, the acceleration of a car can be calculated by using this mathematical expression:

a = (V - U)/t

Where:  

By substituting the given parameters into the acceleration formula, we have;

Acceleration, a = (40 - 10)/15

Acceleration, a = 30/15

Acceleration, a = 2 m/s².

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The direction of the electric field at the corner is along the line between the corner and the center of the square, outward of the center.

The formula to calculate the electric field at a point due to a point charge is given by: Electric field = (k * |q|) / r^2
Given that the charge at each corner is 4.75×10−6 C and the side length of the square is 2.12 m, we can calculate the electric field due to each charge at the corner. Since the charges are at the corners, the distance (r) between each charge and the corner is equal to the side length of the square (2.12 m). Calculating the electric field due to each charge and summing them up, we have:Electric field = (k * |q|) / r^2 + (k * |q|) / r^2 + (k * |q|) / r^2
Electric field = (3 * k * |q|) / r^2
Substituting the values, we get:

Electric field = (3 * 9 x 10^9 N m^2/C^2 * 4.75×10−6 C) / (2.12 m)^2

Electric field ≈ 2.526 x 10^6 N/C

Therefore, the magnitude of the electric field at one corner of the square is approximately 2.526 x 10^6 N/C. Now, let's determine the direction of the electric field at the corner. Since the other charges are positive, the electric field vectors due to these charges will point away from them. Considering the symmetry of the square, the electric field vectors at the corner will be directed along the line between the corner and the center of the square, outward of the center.Therefore, the direction of the electric field at the corner is along the line between the corner and the center of the square, outward of the center.

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The minimum possible coefficient of static friction between bike tires and the ground is zero. This means that there is no requirement for static friction to exist in order for the bike to remain stationary or in motion.

Static friction is the force that prevents two surfaces from sliding against each other when there is no relative motion between them. It depends on the nature of the surfaces in contact and the force pressing them together. In the case of bike tires and the ground, the coefficient of static friction measures the ratio of the maximum static frictional force to the normal force between the tire and the ground.

If the coefficient of static friction were zero, it would imply that there is no need for static friction to keep the bike tires from slipping. This situation can occur when the surfaces are extremely smooth or when other forces, such as rolling resistance or air resistance, provide enough stability to maintain traction.

However, it's important to note that a zero coefficient of static friction can also indicate a lack of friction altogether, which could make it impossible for the bike tires to maintain contact with the ground and result in sliding or loss of control.

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Answer:

he word that musicians use for frequency is pitch. The shorter the wavelength, the higher the frequency, and the higher the pitch, of the sound. In other words, short waves sound high; long waves sound low. ... In other words, it sounds higher

Explanation:

If a buffer solution is 0.210 m in a weak acid and 0.470 m in its conjugate base. The pH of the buffer solution is approximately 4.53.

To determine the pH of a buffer solution, we can use the Henderson-Hasselbalch equation, which is given by

pH = pKa + log ([A-] / [HA])

Where:

pH is the logarithmic measure of the hydrogen ion concentration in the solution.

pKa is the negative logarithm of the acid dissociation constant (Ka) of the weak acid.

[A-] is the concentration of the conjugate base.

[HA] is the concentration of the weak acid.

In this case, the concentration of the weak acid ([HA]) is 0.210 M, and the concentration of the conjugate base ([A-]) is 0.470 M. The acid dissociation constant (Ka) is given as 6.7 × [tex]10^{-5}[/tex].

First, let's calculate the pKa

pKa = -log(Ka) = -log(6.7 × [tex]10^{-5}[/tex]) = 4.18

Next, substitute the given values into the Henderson-Hasselbalch equation:

pH = 4.18 + log(0.470 / 0.210) = 4.18 + log(2.238) = 4.18 + 0.35

pH = 4.53

Therefore, the pH of the buffer solution is 4.53.

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Answer:

It's often called the law of inertia. Acceleration is produced when a force acts on a mass. The greater the mass (of the object being accelerated) the greater the amount of force needed (to accelerate the object). ... A more massive object has a greater tendency to resist changes in its state of motion.

Explanation:

Answer: It's often called the law of inertia. Acceleration is produced when a force acts on a mass. The greater the mass (of the object being accelerated) the greater the amount of force needed (to accelerate the object). ... A more massive object has a greater tendency to resist changes in its state of motion.

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The answer that is not a statement of the second law of thermodynamics is d. Energy does not flow spontaneously by heat from a cold to a hot reservoir.

Options a, b, and c all reflect different aspects of the second law of thermodynamics, such as the preferential direction of real processes, the increase of entropy in natural processes, and the limitation on constructing a heat engine that only performs work without rejecting any heat to a colder reservoir.

However, option d contradicts the second law by suggesting the spontaneous flow of heat from a cold to a hot reservoir, making it the answer that is not a statement of the second law of thermodynamics.

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The electric and magnetic field amplitudes of an electromagnetic wave can be calculated using the power output of the source and the distance from the source. We can use the formula:

P = (1/2)ε₀cE₀²A,

where P is the power output, ε₀ is the permittivity of free space (8.854x10⁻¹² C²/(N·m²)), c is the speed of light (3x10⁸ m/s), E₀ is the electric field amplitude, and A is the surface area of a sphere with radius R.

First, let's calculate the surface area of the sphere at a distance of 15.0 m:

A = 4πR² = 4π(15.0 m)² ≈ 2827.43 m².

Now, rearranging the formula, we can solve for E₀:

E₀² = (2P) / (ε₀cA) = (2 * 960 W) / (8.854x10⁻¹² C²/(N·m²) * 3x10⁸ m/s * 2827.43 m²).

Calculating this expression gives us E₀² ≈ 8.76x10⁻⁶ N²/C².

Taking the square root, we find:

E₀ ≈ 9.36x10⁻⁴ N/C.

Finally, we can use the relationship between the electric and magnetic field amplitudes in an electromagnetic wave:

B₀ = E₀ / c,

where B₀ is the magnetic field amplitude.

Substituting the values, we get:

B₀ ≈ (9.36x10⁻⁴ N/C) / (3x10⁸ m/s) ≈ 3.12x10⁻¹² T.

Therefore, the electric field amplitude at a distance of 15.0 m from the source is approximately 9.36x10⁻⁴ N/C, and the magnetic field amplitude is approximately 3.12x10⁻¹² T.

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Answer:

It happens because the Earth is tilted on its axis around 23 degrees therefore the sun normally never sets at north Pole in summers. The sun doesn't set at Arctic Circle on North pole from about April 19 to August 23 each year due to this phenomenon.

At a frequency of 500 Hz, the impedance of the circuit is approximately 180.026Ω, and the phase angle of the source voltage with respect to the current is approximately 0.637°.

A) To compute the impedance of the circuit, we use the formula:

Z = √(R² + (XL - XC)²)

Where Z is the impedance, R is the resistance, XL is the inductive reactance, and XC is the capacitive reactance.

Given:

Resistance (R) = 180Ω

Inductance (L) = 0.150H

Capacitance (C) = 0.600μF

= 0.600 × 10⁻⁶ F

At frequency f1 = 500 Hz:

XL = 2πf1L

XC = 1/(2πf1C)

Calculating XL and XC:

XL = 2π(500 Hz)(0.150 H)

= 471 Ω

XC = 1/(2π(500 Hz)(0.600 × 10⁻⁶ F))

≈ 5307 Ω

Using the formula for impedance:

Z1 = √(R² + (XL - XC)²)

= √(180² + (471 - 5307)²)

≈ 180.026 Ω

At frequency f2 = 1000 Hz:

XL = 2πf2L

XC = 1/(2πf2C)

Calculating XL and XC:

XL = 2π(1000 Hz)(0.150 H)

= 942 Ω

XC = 1/(2π(1000 Hz)(0.600 × 10⁻⁶ F))

≈ 2653 Ω

Using the formula for impedance:

Z2 = √(R² + (XL - XC)²)

= √(180² + (942 - 2653)²)

≈ 180.134 Ω

B) The phase angle (θ) of the source voltage with respect to the current can be calculated using the formula:

θ = atan((XL - XC)/R)

At frequency f1:

θ1 = atan((XL - XC)/R)

= atan((471 - 5307)/180)

≈ 0.637°

At frequency f2:

θ2 = atan((XL - XC)/R)

= atan((942 - 2653)/180)

≈ 0.318°

At a frequency of 500 Hz, the impedance of the circuit is approximately 180.026Ω, and the phase angle of the source voltage with respect to the current is approximately 0.637°. At a frequency of 1000 Hz, the impedance of the circuit is approximately 180.134Ω, and the phase angle is approximately 0.318°.

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