Can somebody plsssss help me I’m really bad at math

Answer:

Kindly check explanation

Step-by-step explanation:

From the relative frequency below:

For NORTH - SOUTH:

Monday - Thursday = 115 ; has a relative frequency of 75.16%,

Hence, we can obtain the row total since it amounts to 100% thus;

75.16% of row total = 115

0.7516× row total = 115

Row total = 115 / 0.7516 = 153.00

Hence, Friday - sunday:

Row total - (Monday-Thursday)

153 - 115 = 38

FOR EAST - WEST:

Monday - Thursday = 21 ; has a relative frequency of 25.30%,

Hence, we can obtain the row total since it amounts to 100% thus;

25.30% of row total = 21

0. 253 × row total = 21

Row total = 21 / 0.253 = 83.00

Hence, Friday - sunday:

Row total - (Monday-Thursday)

83 - 21 = 62

x = (38 / 100) × 100%

x = 0.38 × 100%

x = 38.00 %

Answer:

The basic explanation:

North - South/Friday - Sunday- 38 // Row total- 153

East - West/Friday - Sunday- 62 // Row total- 83

x- 38

Answer:

no cule bro

Step-by-step explanation:

Answer:

15p4q3

Step-by-step explanation:

Answer:

Step-by-step explanation:

Part A ;

[tex]\sqrt{7} +\sqrt{3} +\sqrt{98} -\sqrt{18} \\\\\sqrt{98}=7\sqrt{2}\\\sqrt{18}=3\sqrt{2}\\\\=\sqrt{7}+\sqrt{3}+7\sqrt{2}-3\sqrt{2}\\\\\mathrm{Add\:similar\:elements:}\:7\sqrt{2}-3\sqrt{2}=4\sqrt{2}\\\\=\sqrt{7}+\sqrt{3}+4\sqrt{2}[/tex]

Part B ;

[tex]3\sqrt{5} - 3\sqrt{11} + 2\sqrt{121} -3\sqrt{90} \\\\2\sqrt{121}=22\\3\sqrt{90}=9\sqrt{10}\\\\=3\sqrt{5}-3\sqrt{11}+22-9\sqrt{10}[/tex]

Answer:

7

Step-by-step explanation:

let the unknown number be x

so x times 2 minus 3=11

it will now be 2x-3=11

the -3will cross the equal sign and change to +3

2x=11+3 which will be 2x=14

divide both sides by 2 and the final answer will be x=7

Answer: D

Step-by-step explanation:

Answer:

x = -7

Step-by-step explanation:

x - 3 = -10

Add 3 to each side

x - 3+3 = -10+3

x = -7

Even though 0.84800 has two more zeroes at the end, this is still the same number as 0.848.

0.84800 -> 0.848

Therefore, 0.848 = 0.48400

Best of Luck!

Answer:

20 socks fit $14.99 is the best deal out of the 3

Step-by-step explanation:

Here, we want to know the bag that contain the best deals for socks .

The best way to go about this is to know the unit prices of socks in each of the bags.

Let’s proceed;

12 socks for $9.99

The unit price here is 9.99/12 = 0.8325 per socks

20 socks for 14.99

Unit price here is 14.99/20 = 0.7495

10 socks for 19.99

The unit price here is 19.99/10 = 1.999

Out of all these options , we can see that the second option is actually the cheapest and offers what we should be pick as we are looking for suppliers since it charges the lowest;

So the best deal for socks is in the bag of 20 socks for $19.99

Answer:

4 2/4 (NOT SIMPLIFIED)

Step-by-step explanation:

Comprising means made of (aka including). You just add 1 1/4+1 1/4+1 1/4.

=3 3/4

The 1/8 is for the front and back cover. The bookworm ate through 3 volumes so there is 6 covers. So times 1/8 by 6. I turned the 6 into a fraction by putting it over 1. So now you have 1/8×6/1=6/8. Now you are going to add the 3 3/4 to the 6/8. You are going to turn the whole fraction to an improper. You are going to multiply the whole number(3) to the denominator(4), add that to the numerator(3) , and put it over the original denominator (4)= 15/4. Now you are going to set up the problem were you add the 6/8 to the 15/4. To add fractions the denominator have to be the same. With this problem you have two options: you can either do an equation to change the 6/8 denominator equal to 4 or an equation to change the 15/4 denominator equal to 8. Either one would work fine. I'm going to show you how to set the 6/8 denominator to 4.

1. Set it up as an equation                       6/8=x/4

2. Find what gets the first denominator to the second in this case dividing by 2                                                          6/8=x/4

3. What you do to the bottom is what you have to do with the top. So to find x, you need to divide 6 by 2= 3

So now your new equation is now 3/4+15/4. Adding this should give you 18/4, but most likely you have to write it as a proper fraction. To do this you are going to divide the 18 by 4. Your remainder will become your new numerator and the 4 will still be you denominator. The number times 4 fully goes into 18 will be your new whole number.

18/4=4.5

Answer:

-4x^2, -3x, -5

Step-by-step explanation:

-4x^2 + 2x - 5 (1 + x)

-4x^2 + 2x - 5 + 5x

-4x^2 - 3x - 5

Answer: D

Step-by-step explanation:

This problem seems to ask for the slope of the line. If not by counting, we can use the slope formula to solve. The formula is [tex]m=\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]. Let's use (1,2) and (2,-1).

[tex]m=\frac{-1-2}{2-1} =\frac{-3}{1}=-3[/tex]

Now, we know that the slope is -3.

We also know that A and C are eliminated because the line is going down, which signifies negative. We would be left with B and D. We know that B is incorrect because the slope would be less steep if B were to be the answer. Therefore, D is the correct answer.

Answer:

30 divided by 6=5

Step-by-step explanation:

a=5

5 times 6 is the product of 30

Answer: 1 73/90 if the decimal is 1.81 and the one is repeating

If the .81 is repeating then 1 9/11

Step-by-step explanation:

Answer:

20/11

Step-by-step explanation:

let 0.(81) = x

--> 100x = 81.(81)

--> 100x - x = 81.(81) - 0.(81)

--> 99x = 81

--> x = 81/99 = 9/11

1.(81) = 1 + 0.(81) = 1 + x = 1 + 9/11 = 20/11

Answer:

Step-by-step explanation:

Let b

Bill's rate of travel = x

Let Julie's rate of travel = 3x

The time each travels is 2.5 hours

Together they travel a distance of 190 miles

d = r*t

Bill's distance covered is r * t = 2.5x

Julie's distance travel is 2.5 * 3x = 7.5x

The total distance = Bill + Julie

2.5x + 7.5x = 190

10x = 190

x = 190/10

x = 19

Bill's distance = 2.5 * 19 = 47.5

Julie's distance = 19 * 7.5 = 142.5

Rate = distance / time

Bill's rate = 47.5 / 2.5 = 19 miles per hour.

Julie's rate = 142.5/2.5 = 57 miles per hour

Is there an easier way?

You should notice that Bill's rate is just x which is 19 miles / hour

You can also notice that Julie is going 3 times as fast or 19*3 = 57

Answer:

Ionic bonds usually occur between metal and nonmetal ions. For example, sodium (Na), a metal, and chloride (Cl), a nonmetal, form an ionic bond to make NaCl. In a covalent bond, the atoms bond by sharing electrons. Covalent bonds usually occur between nonmetals.

An ionic bond is held together by the electrostatic attraction between ions that are near one another. Electrostatic attraction is the attraction between atoms that have opposite charge and holds the atoms together in ionic bonds.

Answer:

Step-by-step explanation:

Got it correct on Khan Academy

Answer:

[tex]g(x) = x - 11[/tex]

Step-by-step explanation:

Given

[tex]f(x) = x - 5[/tex]

Required

Translate to the right by 6 units

When a function is translated to the right, the resulting function becomes

[tex]g(x) = f(x - h)[/tex]

Where h is the number of units moved;

Since; h = 6

[tex]g(x) = f(x - h)[/tex]

becomes

[tex]g(x) = f(x - 6)[/tex]

Solving for f(x - 6);

[tex]f(x) = x - 5[/tex]

Substitute x - 6 for x

[tex]f(x - 6) = x - 6 - 5[/tex]

[tex]f(x - 6) = x - 11[/tex]

This implies that [tex]g(x) = x - 11[/tex] is the result of the translation

Step-by-step explanation:

13? i forgot all this math XD

Answer:

D. 15cm2

Step-by-step explanation:

To find the area of a triangle, you multiply the base (10cm) and height of the triangle (3cm) and divide that by 2. So 10×3=30. Then, you need to divide this by 2. Since 30 is an even number, you won't get a decimal. So 30/2=15. And dont forget your units!

Answer:

Step-by-step explanation:

The question is incomplete. Here is the complete question.

The online program at a certain university had an enrollment of 580 students at its inception and an enrollment of 1725 students 3 years later. Assume that the enrollment increases by the same percentage per year. a) Find the exponential function E that gives the enrollment t years after the online program's inception. b) Find E(11), and interpret the result. c) When will the program's enrollment reach 5500 students?

Let E0 be the number of students that enrolled at inception

E(t) be the number of students that enrolled at any time t

At inception i.e at t = 0, E0 = 580

The exponential function E that gives the enrollment at inception will be expressed as;

E(t) = E0e^kt (note that the exponential power is positive since number of students keep increasing yearly).

At inception:

E(0) = 580e^k(0)

E(0) = 580(1)

E(0) = 580

If after 3years, enrollment increases to 1725 students i.e at t = 3, E(t) = 1725. The equation becomes;

E(3) = P0e^kt

E(3) = 580e^3k

1725 = 580e^3k

Make k the subject of the formula:

e^3k = 1725/580

e^3k = 2.9741

Apply ln to both sides of the equation

ln(e^3k) = ln(2.9741)

3k = 1.08995

k = 1.08995/3

k = 0.3633

The exponential function E that gives the enrollment t years after the online program's inception will be expressed as;

E(t) = E0e^kt

Given E0 = 580 and k = 0.3633

E(t) = 580e^0.3633t

b) To get E(11), we will substitute t = 11 into the resulting expression in (a) above to have;

E(t) = 580e^0.3633t

E(11) = 580e^0.3633(11)

E(11) = 580e^3.9965

E(11) = 580×54.4074

E(11) = 31,556.287

E(11) ≈ 31,556 students

This means that about 31,556students enrolled 11years later.

c) To know when the program's enrollment reach 5500 students, we will set E(t) to 5500, E0 to 580 and k to 0.3633 and calculate the value of t

From the equation E(t) = 580e^0.3633t

5500 = 580e^0.3633t

e^0.3633t = 5500/580

e^0.3633t = 9.4828

Apply ln to both sides

ln(e^0.3633t) = ln(9.4828)

0.3633t = 2.2495

t = 2.2495/0.3633

t = 6.19

t ≈ 6years

This means that the program's enrollment will reach 5500 students 6 years later.

Answer:

It does not represent a function. The domain value of 2 corresponds to two values within the range.

Step-by-step explanation:

Given the function:

Domain : Range

1 => 5

2 => 10

3 => 15

2 => 20

For a relation to be considered a function, every domain value should have exactly 1 range value assigned to it or mapped to it.

In order words, a domain value should not have different range values.

In the relation given, domain value of 2, has more than 1 range value, 10 and 20, assigned to it. It does not have exactly 1 range value.

Therefore, the relation does not represent a function because the domain value of 2 corresponds to two values (10 and 20), within the range.

Answer:

It does not represent a function. The domain value of 2 corresponds to two values within the range.

Step-by-step explanation:

Answer:

see I need help for chemistry pls anyone here helps me I must submit before 10:30

Answer:

4x-3y+20

Step-by-step explanation:

x=6.875

y=2.5

2x+y=30

x=12.5

y=-5

Answer:

c) none of the above

Step-by-step explanation:

this is because we should put the equation like:

1/3 - (-4/3) because the distance is 5 units and

1/3 + 4/3 = 5/3

this is because (-) × (-) = (+)

Answer:

Z= 0.08

Or

Z= 2/25

Step-by-step explanation:

100(z-0.2)=-10(5z+0.8)​

Opening all the bracket

100z - 20= -50z - 8

Collecting like terms, and at Same time adding up this like terms

100z +50z = -8+20

150z= 12

Dividing bith sides of the equation by 150 to look for the value of z

(150/150)(z)=12/150

Z= 0.08

Or

Z= 2/25

Answer:

A 99.9% confidence interval for the population mean is [22.31, 59.91] .

Step-by-step explanation:

We are given the following sample values;

X = 45.3, 42.3, 53, 49, 15.2, 52.3, 45.6, 39.6, 39.4, 16.1, 54.4.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                       P.Q.  =  [tex]\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }[/tex]  ~  [tex]t_n_-_1[/tex]

where, [tex]\bar X[/tex] = sample mean = [tex]\frac{\sum X}{n}[/tex]  = 41.11

             s = sample standard deviation = [tex]\sqrt{\frac{\sum (X - \bar X)^{2} }{n-1} }[/tex]  =  13.59

             n = sample size = 11

Here for constructing a 99.9% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.

So, 99.9% confidence interval for the population mean, [tex]\mu[/tex] is;

P(-4.587 < [tex]t_1_0[/tex] < 4.587) = 0.999  {As the critical value of t at 10 degrees of

                                                freedom are -4.587 & 4.587 with P = 0.05%}    

P(-4.587 < [tex]\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }[/tex] < 4.587) = 0.999

P( [tex]-4.587 \times {\frac{s}{\sqrt{n} } }[/tex] < [tex]{\bar X-\mu}{[/tex] < [tex]4.587 \times {\frac{s}{\sqrt{n} } }[/tex] ) = 0.999  

P( [tex]\bar X-4.587 \times {\frac{s}{\sqrt{n} } }[/tex] < [tex]\mu[/tex] < [tex]\bar X+4.587 \times {\frac{s}{\sqrt{n} } }[/tex] ) = 0.999

99.9% confidence interval for [tex]\mu[/tex] = [ [tex]\bar X-4.587 \times {\frac{s}{\sqrt{n} } }[/tex] , [tex]\bar X+4.587 \times {\frac{s}{\sqrt{n} } }[/tex] ]

                                       = [ [tex]41.11-4.587 \times {\frac{13.59}{\sqrt{11} } }[/tex] , [tex]41.11+4.587 \times {\frac{13.59}{\sqrt{11} } }[/tex] ]

                                       = [22.31, 59.91]

Therefore, a 99.9% confidence interval for the population mean is [22.31, 59.91] .