Can someone please show a piece of paper or ex’s plum how you do h point?

Divide 47 by 14:

Answer 3.357

Rounded to nearest hundredth: 3.36

Answer:

Step-by-step explanation:

Use the ratio below:

Solve for x:

Step-by-step explanation:

[tex]\sf\longmapsto \: \$ 17 = 3 \: hours[/tex]

[tex]\sf\longmapsto \: \$ 1 = x[/tex]

Now, Solve x–

[tex]\sf\longmapsto17x = 3[/tex]

[tex]\sf\longmapsto \: x = \frac{3}{17} \: hours \: per \: dollar[/tex]

Therefore,for 3/17 hours of bike a customer get per dollar.

9514 1404 393

Answer:

Step-by-step explanation:

Solution of the system by the usual means yields the parametric equations ...

  (a², b², c²) = (41 +t, t -7, 2t)

Since we want t-7 to be a perfect square, we can let ...

  t -7 = n²

  t = n² +7

Then the solutions are ...

  (a, b, c) = (±√(n²+48), n, ±√(2(n² +7)))

The only integer solutions are for n=±1 and n=±11. Then the 16 possible triples are ...

  (±7, ±1, ±4) and (±13, ±11, ±16) . . . where the signs can have any combination

Answer:

10/48 - 2/24 - 1/12

Step-by-step explanation:

answer is 1/12

Answer:

if you want to know the x is.

Step-by-step explanation:

(180°－4x)+(180°－6x)+2x=180°

x=22.5°

Answer:

EGFB

Step-by-step explanation:

To find the lengths of PQ and RS, we can use the Pythagorean Theorem, becasue both triangles have right angles. Base x height equals the area of the rectangle, and base x height divided by 2 gets us the height of the triangle. Thus:

1. 233 meters

2. 21, 840 square meters

3. 241.87 meters

4. 12, 600 meters

Hope this helps.

Answer:

110º

Step-by-step explanation:

a triangle has 180º total

so 180-35-35

110

the missing angle in the traingle on top is congruent to angle b

Answer:

Undefined

Step-by-step explanation:

the equation for slope is y2-y1/x2-x1

(-2-6)/(-7-(7))= -8/0

This would leave you with an undefined slope.

Answer: 50

Step-by-step explanation:

[6+√-64] × 3-√-16

(6+8i)(3-4i)

6(3-4i)+8i(3-4i)

18-24i+24i+32

18+32=50

Answer:

fifty

Step-by-step explanation:

fifty

Answer:

ok so it will be 16-bit

Step-by-step explanation:

let x be the flour

now

or,(21/2)+x=42/3

or,(21+2x)/2=42/3

or, 3(21+2x)=42×2

or, 63+6x=84

or,6x=84-63

or, 6x =21

or, x=21/6

thus she need 21/6 cups of flour

Answer:

4

Step-by-step explanation:

The √11 is ≈ 3.3166....

So the first whole number GREATER than 3.3166 is 4

-Chetan K

Answer:

√11 = 3.3166

The first whole number greater than 3.3166 is 4

Hope This Helps!

vâng vì phụ nữ là những người tán gẫu

Answer:

it is a answer

Step-by-step explanation:

Answer:

ㅛ해 주는 것이 좋다 나쁘다 라고 말하는 것은 아니다 싶으면 이 때 가장 중요한 역할을 하는 것 같다 ㅛ요톸 매매 ㅑ져뎌 재료 본연의 맛과 향을 느낄 수도 있다 보니

Answer:

11

Step-by-step explanation:

f(16) = 7 + 16/4

= 7 + 4

= 11

Answer:

Missing reason/statements:

Step-by-step explanation:

we will add 3+37=40

40/8=5

mark me brainlist plz

Answer:

You have to add a certain amount of a number to 3 7/8 to make five. Or the easy way, 5 - 3 7/8 = 1 1/8

Step-by-step explanation:

If you want can you make me brainlyist?

Also, I hope this helped!

Step-by-step explanation:

please send your teacher some nice greetings from me, as this problem description is very incomplete.

we have to guess and assume a few things.

I assume that for both people there is a function describing how many objects (x and y) are sewn after a given amount of time (t).

and we are only looking at a single work day. and not a week or a year.

so,

x = Taylor(t)

y = Thomas(t)

remember that the domain is the interval or set of valid values for the input variable (the argument of the function). in our case here this is t.

and the range is the interval or set of valid values for the output variable (x and y).

so, the domain for Taylor is the interval of valid work time

[0, 8] in hours. we could also define it in minutes to not get confused, and that would be [0, 480] in minutes.

Taylor's range is then (as he can do 6 per hour = 1 every 10 minutes)

[0, 8×6] or [0, 480/10] = [0, 48].

the domain for Thomas is his valid work time [0, 10] in hours or [0,600] in minutes.

Thomas's range is then (2 per hour or 1 every 30 minutes)

[0, 10×2] or [0, 600/30] = [0, 20]

please pick for the domain the scale (hours or minutes) your teacher prefers. I suspect hours due to the phrasing, but just in case I showed you both.

Domain defines the input interval and range defines the output interval.

Here for both Taylor and Thomas Domain is how many hours they have worked and range for both of them is how many hats and mittens they have produced in their working hour.

Domain defines the input interval and range defines the output interval corresponding to the domain interval.

In the given question domain of Taylor is (0,8) and each hat takes 10 mins or 1/6 hours

in 1/6 hours Taylor makes 1 hat

so, in (1/6 x 6) = 1 hour taylor will make ( 1 x 6 ) = 6 hats

so in 8 hours Taylor will make (8 x 6) = 48 hats

Range of taylor = (0,48).                             .(as in 0 hour he will make 0                                                                                                                                                                                                                                        

                                                                            hats )                                          

Domain of Thomas is 10 hours = (0,10)

Every pair of mittens take 30 minutes or 1/2 hour

so , In 1/2 hour Thomas makes 1 pair of mittens

      In(1/2 x 2 ) = 1 hour he will make (1 x 2)= 2 pair of mittens.

      In 10 hours Thomas will make (2 x 10 ) = 20 pair of mittens.

The range of Thomas is (0,20).                 .(as in 0 hour he can make no                                                                                                                                                                                

                                                                                        pair of mittens)  

Learn more about Domain and Range here :

https://brainly.com/question/28135761

#SPJ2                                    

Answer:

28.5

Step-by-step explanation:

1/2 is 0.5 as a decimal.

That would mean that 28 1/2 is the same as 28.5.

Hope this helps! Brainliest would be really appreciated!

Divide total pay by hourly rate:

522 / 22.50 = 23.2 hours

Answer: 23.2 hours

Answer:

8.75 per hour

Step-by-step explanation:

Since it is a linear function we can use the slope formula

m = ( y2-y1)/(x2-x1)

  = ( 370-20)/(40-0)

  =350/40

 = 8.75

Answer:

a) s[n] = 1.05s[n-1] +1000; s[0] = 50,000

 b) $83,421.88

 c) s[n] = 70000·1.05^n -20000

Step-by-step explanation:

a) Let s[n] represents the employee's salary in dollars n years after 2017. The salary in 2017 is given as $50,000, so ...

 s[0] = 50000 . . . . the recursion relation initial condition

The next year, the salary is multiplied by 1.05 and 1000 is added:

 s[1] = 1.05·s[0] +1000

This pattern repeats, so the recursion relation is ...

 s[n] = 1.05·s[n-1] +1000

__

c) It is convenient to find a formula for the salary before trying to compute the salary 8 years on. So, we work part (c) before part (b).

The base salary gets multiplied by 1.05 each year, so can be described by the exponential function ...

 base salary after n years = 50,000·1.05^n

The add-on to the raise becomes a geometric sequence whose common ratio is 1.05. The sum can be described by the formula for the sum of such a sequence:

 sum = a1(r^n -1)/(r -1) . . . . . (see note below)

 sum of add-ons = 1000(1.05^n -1)/(1.05 -1) = 20000(1.05^n -1)

So, the total salary after n years is ...

 s[n] = 50000·1.05^n + 20000(1.05^n -1)

The exponential terms can be combined, so we have the explicit formula ...

 s[n] = 70000·1.05^n -20000

__

b) The year 2025 is 8 years after 2017, so we want to find s[8].

 s[8] = 70000·1.05^8 -20000 = 70000·1.4774554 -20000

    = 103,421.88 -20000 = 83,421.88

In 2025, the employee's salary will be $83,421.88.

_____

Note on the sum of the add-ons

A geometric sequence starts with term a1 and gets multiplied by a ratio r to make the next term: a2=r·a1; a3=r²·a1, ....

The sum of such a geometric sequence has the formula

 Sn = a1·(r^n -1)/(r -1)

Here, the sequence starts in year 1 with a1=1000 and has a common ratio r=1.05. The denominator of the sum is r-1 = 0.05 = 1/20, so the sum can be written as

 Sn = 20000·(1.05^n -1).

Answer:

She pays 11.40 for the roast

Find unit rate then multiply

The answer is B It basically just expressing the 2×(6+9)

The expression 2 × (6 + 9) = (2 × 6) + (2 × 9) represents the distributive property option (B) is correct.

The distributive property is the property that expresses the distributive law of algebraic multiplication. Similarly, in polynomial expression we can use the distributive property, for example we can write a(c+b)  in the form of (ac+bc).

We have an expression:

= 2 × (6 + 9)

After applying the distributive property:

= (2 × 6) + (2 × 9)

= (12) + (18)

= 30

Thus, the expression 2 × (6 + 9) = (2 × 6) + (2 × 9) represents the distributive property option (B) is correct.

Learn more about the distributive property here:

brainly.com/question/5637942

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Answer:

Use the trend line to predict the number of Umbrellas sold in a month, if there were 10 rainy days. Draw the vertical line from 10 on the horizontal axis to the trend line. Then, draw horizontal line to the vertical axis from the trend line as shown below. Number of Umbrellas sold in the month is about 9, if there were 10 rainy days.

164449 avatar

I searched your answer and this came up, I'd answer but it wont let me sadly, but hopefully this will help??

Step-by-step explanation:

[tex]\large\underline{\sf{Solution-}}[/tex]

First equation is

[tex]\rm \longmapsto\:(x - a)(y - b) = (x - 2a)\bigg(y -\dfrac{b}{2}\bigg) [/tex]

can be further simplified to

[tex]\rm \longmapsto\:xy - bx - ay + ab = xy - \dfrac{bx}{2} - 2ay + ab[/tex]

[tex]\rm \longmapsto\: - bx - ay = - \dfrac{bx}{2} - 2ay [/tex]

[tex]\rm \longmapsto\: - bx + \dfrac{bx}{2} = - 2ay + ay[/tex]

[tex]\rm \longmapsto\: - \dfrac{bx}{2} = - ay[/tex]

[tex]\rm \longmapsto\: \dfrac{bx}{2} = ay[/tex]

[tex]\rm \longmapsto\:bx = 2ay[/tex]

[tex]\rm:\longmapsto \:\boxed{\tt{ bx - 2ay = 0}} - - - - (1)[/tex]

Second equation is

[tex]\rm \longmapsto\:x\bigg(x + \dfrac{1}{2b} \bigg) + y \bigg(y + \dfrac{a}{2}\bigg) - 2xy = 5 + {(x - y)}^{2} [/tex]

[tex]\rm \longmapsto\: {x}^{2} + \dfrac{x}{2b} + {y}^{2} + \dfrac{ay}{2} - 2xy = 5 + {x}^{2} + {y}^{2} - 2xy[/tex]

[tex]\rm \longmapsto\: \dfrac{x}{2b} + \dfrac{ay}{2} = 5[/tex]

[tex]\rm \longmapsto\: \dfrac{x + aby}{2b} = 5[/tex]

[tex]\rm :\longmapsto\:\boxed{\tt{ x + aby = 10b}} - - - (2)[/tex]

So, we have two equations in simplest form as

[tex]\rm \longmapsto\:bx - 2ay = 0 [/tex]

and

[tex]\rm \longmapsto\:x + aby = 10b[/tex]

Now, Consider

[tex]\rm \longmapsto\:\dfrac{a_1}{a_2} = \dfrac{b}{1} = b[/tex]

[tex]\rm \longmapsto\:\dfrac{b_1}{b_2} = \dfrac{ - 2a}{ab} = - \dfrac{2}{b} [/tex]

[tex]\bf\implies \:\dfrac{a_1}{a_2} \: \ne \: \dfrac{b_1}{b_2} [/tex]

This implies, System of equations is consistent having unique solution.

So, The student is correct as lines are intersecting.

So, option (b) is correct.

Answer:

when -2 , y = 1

when 0, y = -5

when 2, y = -3

when 3, y = 1

when 4, y = 7

Answer:

1. 2/5

2. 3/20

3. 6 1/9

4. 1/5

5. 11

6. 1

7. 3/13

8. 1 5/11

9. 2

10. 6 1/2

11. 20/27

12. 2 3/16

13. 4 13/18

14. 1 45/98

Hope this helps!

Step-by-step explanation: