Describe how you could show by adding aqueous sodium hydroxide and aqueous ammonia that a solution contained zinc ions.

Result with sodium hydroxide
Excess sodium hydroxide
Result with aqueous ammonia
Excess aqueous ammonia

Answers

Answer 1

Answer:

*result with sodium hydroxide: white ppt of Zn(OH)2

*excess sodium hydroxide: Precipitate dissolves to form a COLOURLESS solution

*Result with Aqueous ammonia: White ppt of Zn(OH)2

*excess aqueous ammonia: Precipitate dissolves to form a COLOURLESS solution


Related Questions

What elements are in H2F5BLi and how many atoms are in each element​.

20 point plus brainliest

Answers

Answer:

2 hydrogen

5 fluorine

1 boron

1 lithium

It is important to understand that while the absorbance value is related to the amount of light absorbed by a sample, it is not equal to or directly proportional to the amount of light absorbed. Consider a situation where 100 photons of light pass through a sample. After the light passes through the sample, 64 photons are detected. a) How many photons were transmitted through the sample

Answers

When 100 photons of light pass through a sample and 64 photons are detected after the passage of light, the number of photons transmitted through the sample is 64.

This is based on the methods of calculating the absorbance of light, which is depicted as the higher the amount of light transmission, the lower the amount of light absorbed.

Thus, when 64 photons of light in 100 photons are detected, 64 photons are transmitted, and therefore, the number of photons absorbed is 36.

Hence, hypothetically, if 100 photons of light are transmitted, 0 photons of light will be absorbed.

Therefore, in this case, it is concluded that the correct answer is 64 photos.

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What is the mass % of acetone in a 1.85 M solution of acetone (MM = 58.08 g/mol) in water? The density of the solution is 0.971 g/mL.

Answers

A 1.85 M acetone solution (MM = 58.08 g/mol) with a density of 0.971 g/mL has a mass percent of acetone of 11.0%.

What is the mass percent?

It refers to the mass of solute in 100 grams of solution.

Let's suppose we have 1 L of the solution.

Step 1: Calculate the mass of solute (acetone).

We have a 1.85 M solution of acetone (MM = 58.08 g/mol). We will calculate the mass of acetone using the following expression for molarity.

M = mass acetone / MM acetone × liters solution

mass acetone = M × MM acetone × liters solution

mass acetone = 1.85 mol/L × 58.08 g/mol × 1 L = 107 g

Step 2: Calculate the mass of the solution.

We have 1 L (1000 mL) of the solution with a density of 0.971 g/mL.

1000 mL × 0.971 g/mL = 971 g

Step 3: Calculate the mass percent of acetone.

%acetone = (107 g/971 g) × 100% = 11.0 %

A 1.85 M acetone solution (MM = 58.08 g/mol) with a density of 0.971 g/mL has a mass percent of acetone of 11.0%.

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The flask contains 25 mL of an unknown diprotic acid aqueous solution that reacts in a 1:2 stochiometric ratio with NaOH. Titrate the solution with NaOH to determine the concentration of the acid. Perform a titration by setting the concentration of the NaOH solution and adding it to the acid solution using the different Add Base buttons. The equilvalence point of the titration is passed when the indicator color changes. The unknown sample can be titrated multiple times by pressing the Retitrate button and starting over. Enter the concentration of the unknown acid solution.
To obtain accurate results, follow the following procedure:
switch the indicator to phenolphthalein titrate 1 mL at a time until solution turns pink, make note of volume added retitrate add 1 mL at a time until 1 mL less than the first titration add 0.05 mL at a time until the solution just turns pink

Answers

Answer:

The flask contains 25 mL of an unknown diprotic acid aqueous solution that reacts in a 1:2 stochiometric ratio with NaOH. Titrate the solution with NaOH to determine the concentration of the acid. Perform a titration by setting the concentration of the NaOH solution and adding it to the acid solution using the different Add Base buttons. The equilvalence point of the titration is passed when the indicator color changes. The unknown sample can be titrated multiple times by pressing the Retitrate button and starting over. Enter the concentration of the unknown acid solution.

Explanation:

does xef4 have resonance structure?​

Answers

Answer:

Yes

Explanation:The structure of XeF4 is square planar.

similarities between viruses and fungi

Answers

Answer:

I can't think of any similarities at all.

Viruses are just an aggregation of genomic material and protein. Occasionally lipid folds around it to make a covering called an envelope.

Fungi are living, eukaryotic cells that metabolize, grow, perform energy conversions and mate with each other.

Increasing the frequency _________________ the wavelength. Group of answer choices decreases increases does not change

Answers

Answer:

heightens

Explanation:

Is water wet? Why or why not

Answers

Answer: umm, yes? DUH

Explanation: touch some falling out of a tap

Answer:

Water is wet,

Explanation:

in the sense of being a liquid which flows easily, because its viscosity is low, which is because its molecules are rather loosely joined together. So it is wet.

What is the Ideal level for chlorine in a spa?

Answers

Answer:

at least 3 ppm in hot tubs/spas

Explanation:

Covert 645g of CuCl2 to mole

Answers

Answer:

kombinasi kuda-kuda belakang

Explanation:

maaf kalau salahnya

need help :( number 5 and 6​

Answers

So for number 5.

The genesis of a poem for me is usually a cluster of words. The only good metaphor I can think of is a scientific one: dipping a thread into a supersaturated solution to induce crystal formation. I don't think I solve problems in my poetry; I think I uncover the problems.

Number 6.
Unsaturated solutions: found in the vast majority of solutions. eg. blood, soda, alcoholic drinks, cell sap, battery acid.

Supersaturated solutions: invert sugar (a mixture of glucose and fructose), gasses dissolved in crude oil when it is still untapped, some clouds (those that cause cloudbursts).

saturated solution: the carbon dioxide dissolved in sodas (unopened), nitrogen in the air in the earth.

Determine the total mass of 5 moles of CuSO4.5H2O

Answers

Answer:

Answer: 1247.5 grams

Explanation:

explanation on image .

A 5.60 g sample of a weak acid with
Ка 1.3 x 10-4 was combined with 5.00 mL of
5.80 mol L-1 NaOH and the resulting solution
was diluted to 750 mL. The measured pH of the
solution was 4.35.
What is the molar mass of the weak acid

Answers

Answer:

pKa = - log Ka = - log (1.3 * 10^-4) = 3.886 5.20 mL of 6.20 M NaOH = 0.00520 L * 6.20 mole…

Explanation:

what mass of water (in grams) is produced by the reaction of 23.0 g of SiO2?

Answers

The mass of water produced by the reaction of the 23 g of [tex]SiO_2[/tex]  is 13.8 g.

The given chemical reaction;

[tex]4Hf (g) \ + \ SiO_2 (s) \ --> \ SiF_4(g) \ + \ 2H_2O(l)[/tex]

In the given compound above, we can deduce the following;

molecular mass of [tex]SiO_2[/tex] = 28 + (2 x 16) = 60 gmolecular mass of [tex]2H_2O[/tex] = 2(18) = 36 g

60 g of [tex]SiO_2[/tex]  --------- 36 g of water

23 g of [tex]SiO_2[/tex]  ------------- ? of water

[tex]mass \ of \ water = \frac{23 \times 36}{60} = 13.8 \ g \ of \ water[/tex]

Thus, the mass of water produced by the reaction of the 23 g of [tex]SiO_2[/tex]  is 13.8 g.

"Your question is not complete, it seems to be missing the following information";

In the reaction of the given compound, [tex]4Hf (g) \ + \ SiO_2 (s) \ --> \ SiF_4(g) \ + \ 2H_2O(l)[/tex], what mass of water (in grams) is produced by the reaction of 23.0 g of SiO2?

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detailed description of how group 1 atoms bond with group 7 atoms​

Answers

Answer:

group 7 atoms react

Explanation:

When a group 7 element takes part in a reaction, its atoms each gain one electron. These atoms form negatively charged ions . The ions have a stable arrangement of electrons, with a complete outer shell.

When 3.93 grams of lactic acid, CHoOs(s), are burned in a bomb
calorimeter that has a total heat capacity of 10.80 kJ-K-1, the
temperature of the calorimeter increases by 5.43 K. Assume AHrxn
=
AErxn. Given that AH°f of H¿O(I) = -285.8 kJ-mol-1 and AH°f of CO:(g)
= -393.5 kJ• mol-1, calculate the AH°f of lactic acid.

Answers

The heat released in the combustion of lactic acid is absorbed by the

calorimeter and in the decomposition of the lactic acid.

ΔH°f of lactic acid is approximately -716.2 kJ

Reasons:

Known parameters are;

Mass of the lactic acid = 3.93 grams

Heat  capacity of the bomb calorimeter = 10.80 kJ·K⁻¹

Change in temperature of the calorimeter, ΔT = 5.34 K

ΔHrxn = ΔErxn

ΔH°f of H₂O(l) = -285.8 kJ·mol⁻¹

ΔH°f of CO₂(g) = -393.5 kJ·mol⁻¹

The chemical equation for the reaction is presented as follows;

C₃H₆O₃ + 2O₂ → 3CO₂ + 3H₂O

The heat of the reaction = 10.80 kJ·K⁻¹ × 5.34 K = 57.672 kJ

Molar mass of C₃H₆O₃ = 90.07 g/mol

Number of moles of C₃H₆O₃ = [tex]\dfrac{3.93 \, g}{90.07 \, g/mol}[/tex] = 0.043633 moles

Number of moles of CO₂ produced = 3 × 0.043633 moles = 0.130899 moles

Heat produced = 0.130899 mole × -285.8 kJ·mol⁻¹ = -37.4109342 kJ

Moles of H₂O produced = 0.130899 moles

Heat produced = 0.130899 mole × -393.5 ≈ -51.51 kJ

Therefore, we have;

Heat absorbed by the lactic acid = ΔH°f of H₂O + ΔH°f of CO₂ + Heat absorbed by the calorimeter

Which gives;

Heat absorbed by lactic acid  = -37.4109342 kJ - 51.51 kJ + 57.672 kJ ≈ -31.249 kJ

The heat absorbed by the lactic acid ≈ -31.249 kJ

[tex]\Delta H^{\circ}f \ of \ C_3H_6O_3 = \dfrac{-31.249}{0.043633} \approx -716.2[/tex]

ΔH°f of C₃H₆O₃ ≈ -716.2 kJ

Heat of formation of lactic acid ≈ -716.2 kJ.

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A chemical reaction takes place in a closed system. The mass of the reactants before the reaction was grams. What must the mass of the products of the reaction be, according to the law of conservation of mass?

A. 35 grams B. 30 grams C. 70 grams D. 25 grams

Answers

Answer:

D. 25 grams

Explanation:

I think that's what the answer is

Is this equation balanced and in the lowest form?

4NH3 → 2N2 + 6H2

Answers

Answer:

It's balanced but not in the lowest form

Explanation:

The actual equation is given by

[tex]\\ \sf\longmapsto 2NH_3\longrightarrow N_2+3H_2[/tex]

Vitamin D is produced in the skin when 7-dehydrocholesterol reacts with UVB rays (ultraviolet B) having wavelengths between
270 nm and 300 nm. What is the energy range Emin < E< Emax of the UVB photons?

Answers

The energy range expected is 6.6 × 10^-19 J < E < 7.33 × 10^-19 J

The energy of the photon is given by;

E = hc/λ

E = energy of the photon

h = Plank's constant

c = speed of light

λ = wavelength of light

For the upper boundary range;

E = ?

h = 6.6 × 10^-34 Js

c = 3  × 10^8 m/s

λ = 270 × 10^-9

E =  6.6 × 10^-34 Js × 3  × 10^8 m/s / 270 × 10^-9

E = 7.33 × 10^-19 J

For the lower range;

E = ?

h = 6.6 × 10^-34 Js

c = 3  × 10^8 m/s

λ =300 × 10^-9

E =  6.6 × 10^-34 Js × 3  × 10^8 m/s / 300 × 10^-9

E = 6.6 × 10^-19 J

Hence, the energy range 6.6 × 10^-19 J < E <  7.33 × 10^-19 J

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What is the main component of natural gas

Answers

Answer:

I believe that would be methane! I hope this helps you!

Answer:

methane

Explanation:

The largest component of natural gas is methane, a compound with one carbon atom and four hydrogen atoms (CH4). Natural gas also contains smaller amounts of natural gas liquids (NGL, which are also hydrocarbon gas liquids), and nonhydrocarbon gases, such as carbon dioxide and water vapor.The main component in natural gas is methane. It also has ethane, propane, butane, hydrocarbons.

Please help me with all ASAP I’ll mark brainly

Answers

Answer:

Explanation:

1.c

2.j

3.h

4.b

5.f

6.d

7.a

8.i

9.e

10.g

The temperature at which a solid melts is the same as the temperature at which its liquid form solidifies (true or false)​

Answers

its false not true................

Answer:

True

Explanation:

This is true because, upon cooling the particles in a liquid loses energy, stops moving and remains constant and the forms a solid.

Therefore we can say the freezing point and melting point occurs at the same temperature

4. Some biologists declare "structure determines functions." The 3-D molecular geometry in small molecules (or units of molecules) are critical in the final shape of larger structures. Give an example, not found in your notes or textbook that illustrate how a change a final shape can affect how the structure functions (or how other substances interact with it) and explain your choice.​

Answers

The Three-Dimensional Structure of Biological Macromolecules Determines How They Function. ... Structural molecular biology uses x-ray diffraction, nuclear magnetic resonance, and other techniques to determine the three-dimensional arrangement of the atoms in biological molecules.

0
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70
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9
Can this balance be read to the nearest milligram?
O no
O yes

Answers

Answer:

30

Explanation:

yes of courseeee i cant balance with the nearest milligram

The two boron atoms listed in the table are isotopes of the boron. The two carbon atoms and the two oxygen atoms are also called isotopes. Based on the patterns in the particle compositions of these atoms, write a definition for “isotopes”

Answers

Answer:

A type of an atom which has a different number of neutrons but the same atomic number, therefore making it the same element. This atom would still have the same properties as well. (Ex: Vanadium-51 is an isotope of Vanadium that has 51 neutrons but still has 23 protons, as its atomic number is 23.)

Isotopes are variants of an element that have the same number of protons in their atomic nucleus, identifying them as the same chemical element, but differ in the number of neutrons.

The variations in neutron numbers among isotopes lead to differences in their atomic masses, resulting in isotopes having slightly different physical properties while retaining similar chemical behavior.

For example, in the case of boron, the two isotopes listed may have the same number of protons (5), but one has 6 neutrons, and the other has 7 neutrons, leading to slightly different atomic masses.

Similarly, for carbon and oxygen, the isotopes exhibit variations in neutron numbers while maintaining the same number of protons, defining them as isotopes of the respective elements. Isotopes play a crucial role in various scientific fields, including radiometric dating, nuclear energy, and medical imaging.

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What is the source of the magma that erupts from a volcano?

outer core

inner core

mantle

Earth's oceans

Answers

Answer:

the magma comes from the mantle

Is halogen radioactive

Answers

Answer: yes

Explanation:

What caused the channel on Mars? water or lava? give reasoning and evidence

Answers

Answer:

A channel in an ancient Martian "riverbed" wasn't carved by liquid water but was built by molten lava, according to a new study of surface features on Mars. ... On Earth, lava tubes form during sustained volcanic eruptions, when lava flowing through previously solidified masses leaves behind empty channels in the rock

Explanation:

The lava, itself (when liquid) is very much above the boiling point of water, so it is not wet with liquid water, so it's a no in that sense,' he writes. ... Lava does contain a lot of water, especially prior to eruption (when it's called magma), but also as it flows across the ground,' he explained.

Answer:

it was both both if you ask me it's water

Explanation:

il explain answer if you brainly me

What is volume?

A. The amount of space an object takes up
B. The amount of matter in an object or substance
C. The length of an object
D. The number of particles in an object or substance

Answers

B is correct answer

Answer:

Volume is the amount of space an object takes up. I hope this helps you! :D

28.5 g of iron shot is added to a graduated cylinder containing 45.50 mL of water. The water level rises to the 49.10 mL mark. From this information, calculate the density of iron.
HELLPPP CAN SOMEONE SOLVE THIS???

Answers

Answer:

Density if iron shot = 7.92 g/ml (2 sig. figs.)

Explanation:

By definition, density is mass per unit volume. That is,

Density (D) = mass(m)/Volume(V)

mass(m) = 28.5g (given)

Volume(V, of iron shot) = 49.10ml - 45.5ml = 3.6ml

Substitutuing into D = m/V = 28.5g/3.6ml = 7.9166667 g/ml (calc.ans)

≅ 7.92 g/ml (2 sig. figs.)

Hope this helps. :-)

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