To eliminate the parameter t from the given parametric equations x = 4sin(3t) and y = 4cos(3t), we can use the trigonometric identity sin^2(t) + cos^2(t) = 1.
Squaring both equations, we get: x^2 = 16sin^2(3t) y^2 = 16cos^2(3t) Adding these two equations and using the trigonometric identity, we get: x^2 + y^2 = 16(sin^2(3t) + cos^2(3t)) x^2 + y^2 = 16 Taking the square root of both sides, we get: sqrt(x^2 + y^2) = 4 .
Therefore, the equation that represents the given parametric equations as a single equation in x and y is: x^2 + y^2 = 16 This is the equation of a circle with center at the origin and radius 4. the equation becomes: (x/4)² + (y/4)² = 1 Finally, we can write the single equation in x and y as: x² + y² = 16.
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Jasim wants to solve the equation 3x = 12. How could he use graphs to solve this equation?
Drag statements into order to complete an explanation.
Answer:
3x=12
divide boths by the coefficient of x
and x= 4
Let X1, X2,..., Xn be an iid random sample where Xi ~ Normal (µ,σ2), u unknown, and σ^2 unknown. Find the MLE's for both u and 02.
The MLE for u is the sample mean and the MLE for 02 is the sample variance.
To find the maximum likelihood estimators (MLEs) for both u and 02, we need to first write down the likelihood function.
The likelihood function for a normal distribution with unknown mean u and unknown variance 02 is given by:
L(u,02|X1,X2,...,Xn) = (2π02)^(-n/2) exp[-1/(2*02) Σ(Xi-u)^2]
Taking the natural logarithm of the likelihood function, we get:
log L(u,02|X1,X2,...,Xn) = -n/2 log(2π02) - 1/(2*02) Σ(Xi-u)^2
To find the MLE for u, we differentiate the log likelihood function with respect to u and set it equal to zero:
d/d u log L(u,02|X1,X2,...,Xn) = 1/(2*02) Σ(Xi-u) = 0
Solving for u, we get:
u = ΣXi / n
Therefore, the MLE for u is simply the sample mean.
To find the MLE for 02, we differentiate the log likelihood function with respect to 02 and set it equal to zero:
d/d(02) log L(u,02|X1,X2,...,Xn) = -n/(2*02) + 1/(2*02^2) Σ(Xi-u)^2 = 0
Solving for 02, we get:
02 = Σ(Xi-u)^2 / n
Therefore, the MLE for 02 is simply the sample variance.
In summary, the MLE for u is the sample mean and the MLE for 02 is the sample variance.
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United Bank offers a 15-year mortgage at an APR of 6.2%. Capitol Bank offers a 25-year mortgage at an APR of 6.5%. Marcy wants to borrow $120,000.
a. What would the monthly payment be from United Bank?
b. What would the total interest be from United Bank? Round to the nearest ten dollars.
c. What would the monthly payment be from Capitol Bank?
d. What would the total interest be from Capitol Bank? Round to the nearest ten dollars.
e. Which bank has the lower total interest, and by how much?
f. What is the difference in the monthly payments?
g. How many years of payments do you avoid if you decide to take out the shorter mortgage?
There are also equations, known as integro-differential equations, in which both derivatives and integrals of the unknown function appear. In each of Problems 26 through 28: (a) Solve the given integro-differential equation by using the Laplace transform. (b) By differentiating the integro-differential equation a sufficient number of times, convert it into an initial value problem. (c) Solve the initial value problem in part (b), and verify that the solution is the same as the one in part (a). 26. '(1) + (1 - 55°(E) dě = 1, °(0) = 0
The coefficients on both sides of the equation do not match, hence the given integro-differential equation cannot have a solution.
a). ƒ(t) = inverse Laplace transform of ƒ(s) = 1/55
b). y(t) = ƒ(t).
c). There is no answer to the given equation.
What is equation?A mathematical statement that establishes the equality of two expressions is known as an equation. It can be used to find a desired unknown quantity and is commonly written using symbols and numbers. Equations are useful for solving a wide range of issues as well as for describing links between various physical and chemical processes. Along with numerous other scientific and mathematical disciplines, programming is another area where equations are used.
Utilising Laplace transforms, the given integro-differential equation can be solved,
Let ƒ(t) = Laplace transform of ƒ(t).
Then,
(1) + (1 - 55°(E)) dě = 1
⇒ (1) + (1 - 55ƒ(s)) ƒ(s) = 1
⇒ ƒ(s) = [1 + (1 - 55ƒ(s)]/55
⇒ ƒ(s) = 1/55
Therefore, ƒ(t) = inverse Laplace transform of ƒ(s) = 1/55
The integro-differential equation is transformed into an initial value issue.
Let y(t) = ƒ(t).
Then,
(1) + (1 - 55°(E)) dě = 1
(1) + (1 - 55y(t)) y′(t) = 1
Considering t differently for each side,
y′′(t) = (1 - 55y(t))/55
Differentiating again,
y′′′(t) = -55y′(t)/55
Differentiating once more,
y(4)(t) = -55y′′(t)/55
We require four beginning values to solve this fourth order differential equation because of its complexity. Therefore,
y(0) = 0, y′(0) = 0, y′′(0) = 0, y′′′(0) = 1
c).The starting value problem's resolution
By varying the settings, we can use this strategy to address the initial value problem.
Let y1(t) = e2t, y2(t) = te2t, y3(t) = t2e2t, y4(t) = t3e2t.
Then,
y′1(t) = 2e2t, y′2(t) = e2t + 2te2t, y′3(t) = 2te2t + t2e2t, y′4(t) = 3t2e2t + t3e2t
y′′1(t) = 4e2t, y′′2(t) = 2e2t + 4te2t, y′′3(t) = 4te2t + 2t2e2t, y′′4(t) = 6t2e2t + 3t3e2t
y′′′1(t) = 6e2t, y′′′2(t) = 2e2t + 6te2t, y′′′3(t) = 6te2t + 2t2e2t, y′′′4(t) = 12t2e2t + 3t3e2t
By including these in the calculation,
[6e2t + 2e2t + 6te2t] + [-55(e2t + 2te2t + t2e2t + t3e2t)] = 1
8e2t + (-55te2t - 110t2e2t - 55t3e2t) = 1
Putting like terms' coefficients on both sides in equal amounts,
8 + (-55) = 1
-47 = 1
This cannot be done. As a result, the following equation cannot be solved.
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URGENT!! Will give brainliest :)
Describe the shape of the distribution.
A. It is uniform.
B. It is skewed.
C. It is symmetric.
D. It is bimodal.
Based on the provided image, it appears that the distribution is skewed to the right. This is indicated by the fact that the tail of the distribution extends further to the right than to the left, and the majority of the data points are concentrated on the left side of the distribution. Therefore, the answer would be B, it is skewed.
probability trees
i understand the method of probability trees however i don’t understand the wording of this question or how to start it, can somebody explain please?
The probability that a randomly selected individual does not have the disease but gives a positive result in the screening test is 33.8%.
How to calculate the probabilityThe probability of having the disease is P(A) = 0.15, so the probability of not having the disease is P(~A) = 1 - P(A) = 0.85.
Using Bayes' theorem:
P(~A|B) = P(B|~A) * P(~A) / [P(B|A) * P(A) + P(B|~A) * P(~A)]
= 0.1 * 0.85 / [0.7 * 0.15 + 0.1 * 0.85]
= 0.338
Therefore, the probability that a randomly selected individual does not have the disease but gives a positive result in the screening test is 0.338, or about 33.8%.
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c×cxdxd×d divided by
cxcxcxdxd
Answer:
Please leave more information regarding the question thank you
Can someone pls help me out with this?
Answer:
Every day, 33% of locusts are added to the locust population
George is randomly selecting an outfit from his dresser. He has two pair of blue pants and four pair of black pants. In his closet there are two blue shirts, four green shirts, and one red shirt.
1. what is the probability he selects black pants and a green shirt?
2. what is the probability he selects a green or blue shirt?
3. what is the probability he does not choose a blue shirt?
Answer:
Probability of George picking black pants and a green shirt is 2/13
Probability of George picking a green shirt is 6/7
Probability of George not choosing a blue shirt 5/7
Attempt 2 Select the true statement(s). As the sample size n increases, the distribution of the sum of the observations approaches a normal distribution. The sample mean varies from sample to sample. As the sample size n increases, the variance of the sample mean X also increases. The distribution of the mean X is never exactly normal. If the underlying population is not normal, the CLT says the distribution of the mean X approaches a normal distribution as the sample size n increases. Incorrect
Based on the terms you provided, I can help you identify the true statement(s):
1. As the sample size n increases, the distribution of the sum of the observations approaches a normal distribution.
2. The sample mean varies from sample to sample.
3. If the underlying population is not normal, the Central Limit Theorem (CLT) states that the distribution of the sample mean X approaches a normal distribution as the sample size n increases.
These statements are true. Note that the statement "As the sample size n increases, the variance of the sample mean X also increases" is incorrect, as the variance of the sample mean actually decreases when the sample size increases. Additionally, the statement "The distribution of the mean X is never exactly normal" is not universally true, as the distribution of the mean can be exactly normal under specific circumstances.
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can anyone help me with this im confused
The net for a cylindrical candy container is shown.
net of a cylinder with diameter of both circles labeled 1.6 inches and a rectangle with a height labeled 0.7 inches
The container was covered in plastic wrap during manufacturing. How many square inches of plastic wrap were used to wrap the container? Write the answer in terms of π.
1.84π square inches
2.4π square inches
5.68π square inches
6.24π square inches
double integral of x^2 2y bound by y = x, y = x^3, and x> 0
The double integral of x² 2y over the given region (bounded by y = x, y = x³, and x > 0) is 2/35.
How to evaluate the double integral of the x² 2y?To solve this double integral, we need to integrate the function x² 2y over the given region in the xy-plane.
The region is bounded by the curves y = x and y = x³, and the line x = 0.
First, we need to determine the limits of integration. Since x > 0,
we can integrate from x = 0 to x = 1.
For each value of x in this range, the lower bound of y is given by y = x, and the upper bound is given by y = x³.
Therefore, we need to integrate with respect to y from y = x to y = x³ for each value of x in the range [0, 1].
So, the double integral can be written as:
∫(0 to 1) ∫(x to x³) x² 2y dy dx
Integrating with respect to y first, we get:
∫(0 to 1) [x² y²]x³_x dy dx= ∫(0 to 1) (x⁶ - x⁴) dx= [1/7 x⁷ - 1/5 x⁵]0_1= 1/7 - 1/5= 2/35Therefore, the double integral of x² 2y over the given region is 2/35.
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For a population with a proportion equal to 0.32, calculate the standard error of the proportion for the following sample sizes of 40,80,120. round to 4 decimal places
The standard errors of the proportion for sample sizes of 40, 80, and 120 are 0.0733, 0.0518, and 0.0422, respectively,
How to calculate the standard error of the proportion?
To calculate the standard error of the proportion for a population with a proportion equal to 0.32 and sample sizes of 40, 80, and 120, we can use the formula:
Standard Error (SE) = √[(p * (1 - p)) / n]
where p is the proportion (0.32), and n is the sample size.
For a sample size of 40:
SE = √[(0.32 * (1 - 0.32)) / 40]
SE ≈ 0.0733 (rounded to 4 decimal places)
For a sample size of 80:
SE = √[(0.32 * (1 - 0.32)) / 80]
SE ≈ 0.0518 (rounded to 4 decimal places)
For a sample size of 120:
SE = √[(0.32 * (1 - 0.32)) / 120]
SE ≈ 0.0422 (rounded to 4 decimal places)
So, for a population with a proportion equal to 0.32, the standard errors of the proportion for sample sizes of 40, 80, and 120 are approximately 0.0733, 0.0518, and 0.0422, respectively, when rounded to 4 decimal places.
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I NEED HELP ON THIS ASAP! PLEASE, IT'S DUE TONIGHT!!!!
The distance travelled by the jet in 25 minutes found using area covered under the graph is 3.7 miles.
What is area?
The size of a surface or the area that any two-dimensional object or figure covers is known as its area.
Area of triangle = [tex]\frac{bh}{2}[/tex]
Area of rectangle=l x w
The area covered under graph= area of triangle+ area of rectangle
= [tex]\frac{bh}{2}[/tex] + l x w
Dimension of triangle:
base(time on x-axis)=5 seconds
height(speed on y-axis)= 600 miles per hour
=600÷3600 miles per seconds
=0.167 miles per seconds
Dimensions of rectangle:
length(time on x-axis):25-5 =20 seconds
width(speed on y-axis)= 600 miles per hour
=600÷3600 miles per seconds
=0.167 miles per seconds
Distance = The area covered under graph
= area of triangle+ area of rectangle
= [tex]\frac{bh}{2}[/tex] + l x w
=[tex]\frac{5(0.167)}{2}[/tex] + 20(0.167)
=0.4175 + 3.34
=3.7575
Distance ≈3.7 miles
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how many terms of the convergent series ∑n=1[infinity] 2 n1.1 should be used to estimate its value with error at most 0.000001?
We need to use at least 21168 terms of the series to estimate its value with an error at most 0.000001.
Explanation: -
To estimate the value of the convergent series ∑n=1[infinity] 2 n^(-1.1) with an error at most 0.000001, we need to use a partial sum that is close enough to the actual value of the series.
One way to approach this is to use the error bound formula for a convergent series:
|S - Sn| ≤ a_n+1/(1 - r),
where S is the actual sum of the series, Sn is the sum of the first n terms of the series, an+1 is the (n+1)th term of the series, and r is the common ratio (in this case, r = 1/2^(1.1)).
We want to find the value of n such that the error |S - Sn| is at most 0.000001.
Plugging in the given values, we get:
0.000001 ≤ 2(n+1)^(-1.1)/(1 - 1/2^(1.1))
Solving for n using a calculator or computer algebra system, we get n ≈ 21168.
Therefore, we need to use at least 21168 terms of the series to estimate its value with an error at most 0.000001.
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8.Points W
and V
create WV¯¯¯¯¯¯¯¯¯.
Point W
is located at (−6,−6)
and point V
is located at (−6,−2).
Imagine WV¯¯¯¯¯¯¯¯¯
is rotated 180∘
clockwise about the origin. Answer the following questions about W′V′¯¯¯¯¯¯¯¯¯¯¯¯.
A: What are the coordinates of point W′?
B: What are the coordinates of point V′?
Answer:
A: What are the coordinates of point W'?
The coordinates of point W' are (6, 6).
B: What are the coordinates of point V'?
The coordinates of point V' are (6, 2).
maybe i think so
Write an equation to show how to find the product of 1,000,000 and 1,000,000 using scientific notation.
The equation to show how to find the product of 1,000,000 and 1,000,000 using scientific notation can be expressed as (10^6 * 10^6).
What is the scientific notation?A number can be written in scientific notation in a case whereby the number is greater than or equal to 1 however not up to 10 multiplied by a power of 10.
Given that 1,000,000 and 1,000,000 which can be written in scientific notation as 1.0 * 10^6 and 1*10^6, then th product can be written as (10^6 * 10^6) = 10^12.
Hence, the product is 10^12.
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A farmer builds a water though to fit in a corner. The water though is made of two rectangular prisms
A) Length A = 5 ft and width B= 4 ft
B) Volume of the water though = 88 [tex]ft^3[/tex]
What is volume?
The space taken up by any three-dimensional solid constitutes a volume, to put it simply. A cube, cuboid, cone, cylinder, or sphere can be one of these solids. Cubic units are used to measure the volume of solids. The volume will be given in cubic metres, for instance, if the dimensions are given in metres.
Here consider the prism plane figure the dotted lines are equal to the width,
Then width B= 8-4 = 4 ft
Length A = 8-3 = 5 ft
B) Now volume of rectangular prism = lwh cubic unit.
Volume of big prism = 8*2*3=48 [tex]ft^3[/tex]
Volume of small prism = 5*4*2 = 40 [tex]ft^3[/tex]
Then Total volume = 48+40 = 88 [tex]ft^3[/tex]
Hence in the rectangular prisms,
A) Length A = 5 ft and width B= 4 ft
B) Volume of the water though = 88 [tex]ft^3[/tex]
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2)for the laplacian matrix constructed in (1), find the second-smallest eigenvalue and its eigenvector. what partition of the nodes does it suggest? what partition of the nodes does it suggest?
It can be used to partition the nodes of the graph into two sets. This partition may suggest the existence of two distinct communities or groups within the graph.
How can we determine the second-smallest eigenvalue and its eigenvector for the Laplacian matrix constructed in (1), and what does the resulting node partition suggest?To find the second-smallest eigenvalue and its eigenvector for the Laplacian matrix constructed in (1), we need to compute the eigenvalues and eigenvectors of the matrix. Once we have obtained the eigenvalues and eigenvectors, we can sort them in ascending order and select the second-smallest eigenvalue and its corresponding eigenvector.
The Laplacian matrix constructed in (1) is a symmetric matrix, which means that all its eigenvalues are real. The eigenvectors of the Laplacian matrix are orthogonal, which means that they form an orthonormal basis for the space spanned by the rows of the matrix.
Once we have computed the eigenvectors and eigenvalues of the Laplacian matrix, we can use them to partition the nodes of the graph into two sets. The partition is obtained by splitting the nodes based on the sign of the components of the eigenvector corresponding to the second-smallest eigenvalue. If the components are positive, we assign the nodes to one set, and if the components are negative, we assign them to the other set.
The partition suggested by the second-smallest eigenvalue and its eigenvector can give us insight into the structure of the graph. For example, if the graph is a community graph, the partition may suggest the existence of two distinct communities within the graph. If the graph is a social network, the partition may suggest two groups of people with different interests or affiliations.
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how do i solve this and what’s the answer
The volume of the empty portion of container B is 6104.2 ft³(nearest tenth)
What is word problem?A word problem in maths is a maths question written as one sentence or more. This statements are interpreted into mathematical equation or expression.
volume of empty space in container B = volume of B - volume of A
volume of A = πr²h
= 3.14 × 12² × 18
= 8138.88ft³
volume of B = πr²h
= 3.14 × 18² × 14
= 14243.04ft³
Therefore volume of empty space in B = 14243.04 - 8138.88
= 6104.2 ft³(nearest tenth)
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A formula that uses one or more previous terms to find the next term is an
Answer:
A formula that uses one or more previous terms to find the next term is a recursive formula.
Step-by-step explanation:
A recursive formula is a formula that defines any term of a sequence in terms of its preceding term(s).
Factor each completely if possible
(1) x^2 - 11x + 28
(2) 2x^2 + 8x + 6
(3) k^2 - 25
(4) a^2 - 9a + 20
(5) 7x^2 - 11x - 6
(6) 14x^2 - 52x + 30
(7) 6n^3 - 8n^2 + 3n - 4
(8) 15y^3 - 3v^2 + 20v - 4
Factors (1) x² - 11x + 28 = (x-4)(x-7), (2) 2x² + 8x + 6 = 2(x+1)(x+3), (3) k² - 25 = (k+5)(k-5), (4) a² - 9a + 20 = (a-5)(a-4), (5) 7x² - 11x - 6 = (7x+2)(x-3) , (6) 14x² - 52x + 30 = 2(7x-3)(x-5), (7) 6n³ - 8n² + 3n - 4 = (2n-1)(3n²-2n+4), (8) 15y³ - 3v² + 20v - 4 = (5y-1)(3y²+1)(4-v)
Describe Factorization?Factorization is a process of finding the factors of a given mathematical expression, which can be a number, polynomial, or algebraic expression. In other words, factorization involves breaking down a mathematical expression into simpler terms that multiply together to give the original expression. For example, the factors of the expression x^2 - 4 are (x + 2)(x - 2).
In algebra, factorization is an important tool for solving equations and simplifying expressions. By factoring, we can often simplify complex expressions, making them easier to work with and understand. In addition, factorization plays an important role in number theory, where it is used to find prime factors and calculate the greatest common divisor and least common multiple of numbers.
(1) x² - 11x + 28 = (x-4)(x-7)
(2) 2x² + 8x + 6 = 2(x+1)(x+3)
(3) k² - 25 = (k+5)(k-5)
(4) a² - 9a + 20 = (a-5)(a-4)
(5) 7x² - 11x - 6 = (7x+2)(x-3)
(6) 14x² - 52x + 30 = 2(7x-3)(x-5)
(7) 6n³ - 8n² + 3n - 4 = (2n-1)(3n²-2n+4)
(8) 15y³ - 3v² + 20v - 4 = (5y-1)(3y²+1)(4-v)
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Given that cos2α-5 and α terminates in quadrant I, find the exact value of sino. sina- (Simplify your answer, including any radicals. Use integers or fractions for any numbers in the expression.)
The result cos²(α) = -2 is not possible, as the square of cosine must be between 0 and 1. It appears there might be an error in the given information. Please double-check the values and try again.
Given that cos(2α) = -5 and that it terminates in quadrant I, we need to find the exact value of sin(α).
First, let's recall the Pythagorean identity: sin²(α) + cos²(α) = 1.
Since cos(2α) = -5, we need to find the value of cos(α). In order to do this, we'll use the double-angle formula for cosine: cos(2α) = 2cos²(α) - 1.
Now, we can plug in the given value of cos(2α) and solve for cos(α):
-5 = 2cos²(α) - 1
-4 = 2cos²(α)
cos²(α) = -2
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URGENT ANSWER QUICKLY PLEASE A manufacturer wants to design a cone-shaped container that has a volume of 175 cubic centimeters. Their old container is shown.
Hence,0.72 rather than to increase the radius to meet their requirements.
What is the cone ?A cone is a three-dimensional geometric form with a plane base and a smooth tapering vertex. A cone is made up of a collection of line segments, half-lines, its lines that connect the apex of the common point at to every point on a base that is in a flat other than the apex.
What is the volume ?A measurement of three-dimensional space is volume. It is frequently expressed quantitatively using US-standard units ,SI-derived units, as well as several imperial Volume and the notion of length are connected.
Let the new radius x and the old radius as r. The formed volume was 175 cubic cm, and the new container height is 5 cm,
V = [tex]\frac{1}{3}\pi r^2h[/tex], where V is the volume, r is the radius, and h is the height, is the formula for a cone volume.
We can construct an equation using the previous volume:
175 = [tex]\frac{1}{3}\pi r^2h[/tex]
the height is same for new and old container , so,:
175 =[tex]\frac{1}{3}\pi r^2*5[/tex]
175 = [tex]\frac{5}{3}\pi r^2[/tex]
By multiplying both sides by (5/3)
[tex]r^2 = \frac{175*3}{5*\pi}[/tex] ≈ 22.3 use [tex]\pi[/tex]=3.14
When both sides are square root
r ≈ 4.72
Therefore, the old container radius is 4.72 cm.
now,We subtract the old radius from the new radius for determine how much the radius must increase to s the new container:
x - r ≈ 4 - 4.72 ≈ -0.72
Because the new radius is lower than the old radius, the outcome is negative.
We would need to reduce the radius by roughly 0.72 cm rather than expand it to satisfy the needs of the new container.
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The question is in the image
The leading coefficient of the term with the highest power (6y⁴) is 6.
The degree of the polynomial is 4 because the highest power of y is 4 in the term 6y⁴.
The constant term is 2, which is the term without any variable (y) raised to a power.
What is the degree of the polynomial?The degree of a polynomial is the highest power of its variable. For example, in the polynomial expression 2x³ + 4x² - x + 1, the degree is 3, because the highest power of x is 3.
According to the given informationThe given expression is:
4y + 3y³ + 6y⁴ - 3y³ - 7y + 2
To find the coefficient, degree, and constant of this polynomial, we can simplify it by combining like terms:
-4y + (3y³ - 3y³) + 6y⁴ - 7y + 2
= -4y - 7y + 6y⁴ + 2
= 6y⁴ - 11y + 2
Therefore, the coefficient of the term with the highest power (degree) is 6, the degree of the polynomial is 4, and the constant term is 2.
Coefficients:
The coefficient of the term with the highest power (6y⁴) is 6.
The coefficient of the y-term (-11y) is -11.
The coefficient of the constant term (2) is 2.
Degree:
The degree of the polynomial is 4 because the highest power of y is 4 in the term 6y⁴.
Constant:
The constant term is 2, which is the term without any variable (y) raised to a power.
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If h(2) = 9 and h'(2) = −2, find
d/dx(h(x)/x)) at x=2
The derivative of x = 2 of the given function its value is -13/4.
To query the result of a function at x = 2, we must first use the division rule. The quotient law is a formula that calculates the derivative of a function that can be expressed as the quotient of two functions. Let
f(x) = h(x) and g(x) = x. We can express the function h(x)/x as f(x)/g(x). Now we can use the quotient rule like this:
d/dx(h(x)/x)) = d/dx(f(x)/g(x))
= [( g(x) * f '(x) )) - (f(x) * g'(x))] / (g(x))^2
= [(x * h'(x)) - (h (x) * 1) ] / x ^2
Now we can put the values given as x = 2 and h(2) = 9 and h'(2) = -2 into the formula:
d /dx(h(x)/ x) ) x = 2 = [ (2 * (-2)) - (9 * 1)] / 2^2
= (-4 - 9) / 4
= -13/4
Therefore, the derivative of x = 2 of the given function its value is -13/4.
That is, the function h(x) / x has a change of -13/4 at x = 2, so if we make a small change in x around x = 2, the function h(x ) / x changes units at x for each of 13 There is a /4 unit reduction. The negative sign indicates that the function decreases at x = 2; this is based on the fact that the number h(x) decreases less than the number x as x approaches 2.
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Given m
|| n, find the value of x.
m
n
126°
(8x-10)
8 is the value of x in parallel lines.
With an example, what is a parallel line?
Two lines in the same plane that are equally spaced apart and never meet are known as parallel lines in geometry. They can be either vertical or horizontal.
Examples of parallel lines in our everyday lives include zebra crossings, notebook lines, and railway tracks all around us. No matter how far apart they are on either side, two lines on the same plane are considered parallel if they never cross.
given
m ║n
8x - 10 + 126 = 180°
8x + 116 = 180°
8x = 180° - 116
8x = 64
x = 64/8
x = 8
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Can anyone post fake answers on this website
Answer:
If you're asking if its possible, yes it is
F(1) = 15 f(n)= f(n-1) x n evaluate the sequences in recursive form
Answer:
f(1) = 15
f(n) = f(n-1) x n
Step-by-step explanation:
The sequence in recursive form is:
f(1) = 15
f(n) = f(n-1) x n
Using this recursive formula, we can find the value of any term in the sequence by calculating the value of the previous term and multiplying it by the index of the current term.
For example, to find the value of f(2), we would use the formula:
f(2) = f(1) x 2
f(2) = 15 x 2
f(2) = 30
Similarly, to find the value of f(3), we would use the formula:
f(3) = f(2) x 3
f(3) = 30 x 3
f(3) = 90
And to find the value of f(4), we would use the formula:
f(4) = f(3) x 4
f(4) = 90 x 4
f(4) = 360
We can continue using this formula to find the values of any term in the sequence.
A coat that costs $131 is $18 less than twice the cost of a jacket, j. Write
an equation that represents the relationship between the cost of the coat
and the cost of the jacket
Answer:
2j - c
Step-by-step explanation: