Find an equation for the perpendicular bisector of the line segment whose endpoints
are (3, 1) and (-9, -5).


Help plz

Answer:

y= -2x -8

Step-by-step explanation:

I will be writing the equation of the perpendicular bisector in the slope-intercept form which is y=mx +c, where m is the gradient and c is the y-intercept.

A perpendicular bisector is a line that cuts through the other line perpendicularly (at 90°) and into 2 equal parts (and thus passes through the midpoint of the line).

Let's find the gradient of the given line.

[tex]\boxed{gradient = \frac{y1 -y 2}{x1 - x2} }[/tex]

Gradient of given line

[tex] = \frac{1 - ( - 5)}{3 - ( - 9)} [/tex]

[tex] = \frac{1 + 5}{3 + 9} [/tex]

[tex] = \frac{6}{12} [/tex]

[tex] = \frac{1}{2} [/tex]

The product of the gradients of 2 perpendicular lines is -1.

(½)(gradient of perpendicular bisector)= -1

Gradient of perpendicular bisector

= -1 ÷(½)

= -1(2)

= -2

Substitute m= -2 into the equation:

y= -2x +c

To find the value of c, we need to substitute a pair of coordinates that the line passes through into the equation. Since the perpendicular bisector passes through the midpoint of the given line, let's find the coordinates of the midpoint.

[tex]\boxed{midpoint = ( \frac{x1 + x2}{2} , \frac{y1 + y2}{2}) }[/tex]

Midpoint of given line

[tex] = ( \frac{3 - 9}{2} , \frac{1 - 5}{2} )[/tex]

[tex] = ( \frac{ - 6}{2} , \frac{ - 4}{2} )[/tex]

[tex] = ( - 3 , - 2)[/tex]

Substituting (-3, -2) into the equation:

-2= -2(-3) +c

-2= 6 +c

c= -2 -6 (-6 on both sides)

c= -8

Thus, the equation of the perpendicular bisector is y= -2x -8.

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