The area enclosed by the curve r=2sin(θ) 3sin(9θ) over the interval [0,2π/9] is (243π/64) - (3√3/16).
How to find the area enclosed by the curve?To find the area enclosed by the curve r=2sin(θ) 3sin(9θ), we first need to determine the limits of integration for θ.
Since the curve is periodic with period 2π/9 (due to the 9 in the second term), we only need to consider the portion of the curve in the interval [0, 2π/9].
Next, we need to convert the polar equation to rectangular coordinates, which can be done using the formulas x = r cos(θ) and y = r sin(θ).
Plugging in the given equation, we get:
x = 2sin(θ) cos(θ) + 3sin(9θ) cos(θ)
y = 2sin(θ) sin(θ) + 3sin(9θ) sin(θ)
Now we can find the area enclosed by the curve by integrating over the given interval:
A = ∫[0,2π/9] (1/2) [x(θ) y'(θ) - y(θ) x'(θ)] dθ
Using the formulas for x and y, we can find the derivatives x'(θ) and y'(θ):
x'(θ) = 2cos(θ) cos(θ) - 2sin(θ) sin(θ) + 27cos(9θ) cos(θ) - 27sin(9θ) sin(θ)
y'(θ) = 2cos(θ) sin(θ) + 2sin(θ) cos(θ) + 27cos(9θ) sin(θ) + 27sin(9θ) cos(θ)
Substituting these expressions into the formula for A and evaluating the integral, we get:
A = (243π/64) - (3√3/16)
Therefore, the area enclosed by the curve r=2sin(θ) 3sin(9θ) over the interval [0,2π/9] is (243π/64) - (3√3/16).
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What is the probability that either event will occur?
A
B
9
9
P(A or B) = P(A) + P(B) - P(A and B)
P(A or B) = [?]
Enter as a decimal rounded to the nearest hundredth.
Okay, let's solve this step-by-step:
P(A) = 9
P(B) = 9
P(A and B) = ?
We don't have enough information to calculate P(A and B) directly.
So we use the inclusion-exclusion principle:
P(A or B) = P(A) + P(B) - P(A and B)
= 9 + 9 - ?
= 18 - ?
Since probabilities must be between 0 and 1, the largest this could be is 18.
So 18 - ? must equal 0.82.
? = 12
Therefore, P(A and B) = 12
And the final solution is:
P(A or B) = 0.82
Rounded to the nearest hundredth.
Does this help explain the solution? Let me know if you have any other questions!
The probability of either A or B occurring is 0.2.
What is the probability?Probability in mathematics is the possibility of an event in time. In simple words how many times does that incident is happening in any given time interval?
To find the probability that either event will occur, we need to find the total number of outcomes in the sample space.
From the given information, we can see that there are 9 + 9 + 9 + 9 + 9 = 45 possible outcomes in the sample space.
The probability of either A or B occurring can be found by adding the probability of A occurring to the probability of B occurring and then subtracting the probability of both A and B occurring at the same time (to avoid double-counting).
The probability of A occurring is (9 + 9 - 9) / 45 = 9/45 = 0.2
(The first 9 represents the number of outcomes in circle A, the second 9 represents the number of outcomes in the rectangle outside of A but inside the square, and the -9 represents the overlapping outcomes in the intersection of A and B that we don't want to count twice).
The probability of B occurring is (9 + 9 - 9) / 45 = 9/45 = 0.2
(The first 9 represents the number of outcomes in circle B, the second 9 represents the number of outcomes in the rectangle outside of B but inside the square, and the -9 represents the overlapping outcomes in the intersection of A and B that we don't want to count twice).
The probability of both A and B occurring at the same time is 9/45 = 0.2 (since this is the number of outcomes in the intersection of A and B divided by the total number of outcomes in the sample space).
Therefore, the probability of either A or B occurring is:
0.2 + 0.2 - 0.2 = 0.2
So the probability that either event will occur is 0.2 or 20% (rounded to the nearest hundredth).
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suppose a dynamic programming algorithm creates an n m table and to compute each entry of the table it takes a minimum over at most m (previously computed) other entries.
This is a common approach in dynamic programming, and it allows us to solve complex problems efficiently by avoiding redundant computations
Based on the given scenario, it seems that the dynamic programming algorithm follows the principle of optimal substructure, where the solution to a problem can be obtained by combining the solutions of its subproblems.
Here, the algorithm creates an n m table, meaning it will have n rows and m columns. To compute each entry of the table, it takes a minimum over at most m other previously computed entries. This suggests that the algorithm is using the concept of the minimum substructure, where it tries to find the minimum cost/path/sum to reach a certain point by taking the minimum of all the possible subproblems.
Overall, the given information indicates that the dynamic programming algorithm is likely solving a problem where we need to find the optimal solution by breaking it down into smaller subproblems and taking the minimum of all the possible solutions. This is a common approach in dynamic programming, and it allows us to solve complex problems efficiently by avoiding redundant computations.
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steph curry is a 91ree-throw shooter. he decides to shoot free throws until his first miss. what is the probability that he shoots exactly 20 free throws (including the one he misses)
The probability that Steph Curry shoots exactly 20 free throws, including the one he misses, is approximately 0.0114 or 1.14%.
this probability problem involves free throws.
Steph Curry is a 91% free-throw shooter, which means his probability of making a free throw is 0.91, and the probability of missing one is 0.09 (since probabilities must add up to 1).
To find the probability that he shoots exactly 20 free throws (including the one he misses), we need to consider that he makes the first 19 shots and misses the 20th one.
Step 1: Calculate the probability of making 19 consecutive shots.
This is simply the probability of making a shot raised to the 19th power: (0.91)^19.
Step 2: Calculate the probability of missing the 20th shot.
The probability of missing a shot is 0.09.
Step 3: Multiply the probabilities from Steps 1 and 2.
(0.91)^19 * 0.09
Step 4: Compute the final probability.
(0.91)^19 * 0.09 ≈ 0.0114
So, the probability that Steph Curry shoots exactly 20 free throws, including the one he misses, is approximately 0.0114 or 1.14%.
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Lucas is collecting baseball cards. He had 46 cards in his collection. His grandma gave him 29 cards for his birthday, and his aunt Tammy gave him 52 cards. How many baseball cards does Lucas have now?
Answer:
127 baseball cards
Step-by-step explanation:
Lucas now has a total of 127 baseball cards.
To find out, you can add up the number of cards he had before (46), the number of cards his grandma gave him (29), and the number of cards his aunt Tammy gave him (52):
46 + 29 + 52 = 127
Hope this helps!
The student council is
planning a trip to the zoo. It
costs $12.50 per student for
admission to the zoo.
Since the total cost varies
directly to the number of
students, how many
students can attend with
$362.50?
Answer:
29
Step-by-step explanation:
362.5/12.5 =29
Trixie started her homework at 5:30pm She finished it at 8:50pm How long (in minutes)did it take her to do her homework
It took Trixie 200 minutes to finish her homework.
To calculate the time Trixie took to do her homework, we can subtract the starting time from the ending time.
The starting time is 5:30pm, which is equal to 5 x 60 + 30 = 330 minutes after midnight.
The ending time is 8:50pm, which is equal to 8 x 60 + 50 = 530 minutes after midnight.
To find the duration, we can subtract the starting time from the ending time:
530 minutes - 330 minutes = 200 minutes
Therefore, it took Trixie 200 minutes to finish her homework.
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Suppose a curve is traced by the parametric equations x=2(sin(t)+cos(t)) y=36−10cos2(t)−20sin(t) as t runs from 0 to π . At what point (x,y) on this curve is the tangent line horizontal?
The two points on the curve where the tangent line is horizontal are (2,26) and (-2,26).
To find where the tangent line is horizontal, we need to find where the derivative of y with respect to x (dy/dx) equals 0.
First, we need to express y in terms of x. We can do this by eliminating t from the two parametric equations.
From x=2(sin(t)+cos(t)), we get sin(t) = (x/2) - cos(t).
From y=36−10cos2(t)−20sin(t), we substitute sin(t) with the above expression and get:
y = 36 - 10cos²(t) - 20((x/2) - cos(t))
Simplifying this expression, we get:
y = -10cos²(t) - 10x + 36
Next, we need to find the derivative of y with respect to x:
dy/dx = -10sin(2t)/(dx/dt)
From x=2(sin(t)+cos(t)), we get dx/dt = 2(cos(t)-sin(t))
Substituting this into the above equation for dy/dx, we get:
dy/dx = -5sin(2t)/(cos(t)-sin(t))
Setting dy/dx equal to 0, we get:
0 = -5sin(2t)/(cos(t)-sin(t))
This means sin(2t) = 0, or t = 0 or t = π/2.
Plugging these values into the parametric equations for x and y, we get:
When t=0: x = 2, y = 26
When t=π/2: x = -2, y = 26
Thus, the two points on the curve where the tangent line is horizontal are (2,26) and (-2,26).
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sketch the wave functions and the probability distributions for the n = 4 and n = 5 states for a particle trapped in a finite square well.
The wave functions and probability distributions for a particle trapped in a finite square well can be complex, but understanding these concepts is essential for understanding the behavior of particles in quantum mechanics.
To sketch the wave functions and probability distributions for the n = 4 and n = 5 states of a particle trapped in a finite square well:
We need to first understand what these terms mean.
Wave functions are mathematical functions that describe the behavior of particles in quantum mechanics. They represent the probability amplitude of finding a particle in a certain state, and can be used to calculate the probability of finding the particle in a certain location.
Probability distributions, on the other hand, describe the probability of finding a particle in a certain location at a certain time. They are calculated by squaring the wave function and normalizing the result.
Now, let's consider a particle trapped in a finite square well. This means that the particle is confined to a certain region of space, and can only exist within that region. The wave function for a particle in this situation can be expressed as a combination of sine and cosine functions.
For the n = 4 and n = 5 states, the wave functions will have four and five nodes, respectively. These nodes represent regions where the probability of finding the particle is zero.
To sketch the probability distributions, we need to square the wave functions and normalize the result. This will give us a graph that shows the probability of finding the particle at different locations within the well.
Overall,the wave functions and probability distributions for a particle trapped in a finite square well can be complex, but understanding these concepts is essential for understanding the behavior of particles in quantum mechanics.
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let w be the subspace spanned by the given vectors. find a basis for w⊥. w1 = −4 −4 −12 −4 , w2 = 2 2 6 2 , w3 = 6 −12 18 12
The w⊥ is the trivial subspace, consisting only of the zero vector.
To find a basis for the subspace w⊥, we need to find the vectors that are orthogonal to all vectors in w, which is the subspace spanned by the given vectors.
First, we need to find a basis for w. We can do this by putting the given vectors into a matrix and reducing it to row echelon form.
[tex]\begin{pmatrix}-4 & -4 & -12 & -4 \ 2 & 2 & 6 & 2 \ 6 & -12 & 18 & 12\end{pmatrix} $\to$[/tex]
[tex]\begin{pmatrix}2 & 2 & 6 & 2 \ 0 & -8 & -24 & -8 \ 0 & 0 & 0 & 0\end{pmatrix}[/tex]
The row echelon form shows that the first two vectors are linearly independent, so we can take them as a basis for w:
w1 = [-4, -4, -12, -4] and w2 = [2, 2, 6, 2]
Next, we need to find the vectors that are orthogonal to both w1 and w2. To do this, we can set up a system of equations:
a(-4,-4,-12,-4) + b(2,2,6,2) + c(0,0,0,0) = (0,0,0,0)
Simplifying the equation, we get:
-4a + 2b = 0
-4a + 2b = 0
-12a + 6b = 0
-4a + 2b = 0
We can see that the first two rows are identical, so we only need to use the first two rows to find a basis for w⊥.
Solving the first two equations, we get:
a = b/2
Substituting this into the third equation, we get:
-12(b/2) + 6b = 0
-6b + 6b = 0
b = 0
So a = 0 as well. This means that the only vector that is orthogonal to both w1 and w2 is the zero vector, which is not a valid basis vector.
Therefore, w⊥ is the trivial subspace, consisting only of the zero vector.
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find the area of the region that lies inside both r=sin(θ) and r=cos(θ). hint: the final example on the final video lecture goes through a similar problem.
Okay, let's solve this step-by-step:
1) The equations for the two curves are:
r = sin(θ) and r = cos(θ)
2) We need to find the intersection points of these two curves. This is done by setting them equal and solving for θ:
sin(θ) = cos(θ)
=> θ = π/4
3) The intersection points are (1, π/4) and (1, 3π/4). The region lies between θ = π/4 and θ = 3π/4.
4) To find the area, we use the formula:
A = ∫θ=3π/4 θ=π/4 2πr dθ
5) Substitute r = sin(θ) or r = cos(θ):
A = ∫θ=3π/4 θ=π/4 2πsin(θ) dθ
= 2π ∫θ=3π/4 θ=π/4 sin(θ) dθ
6) Integrate:
A = 2π(cos(θ) - sin(θ) )|π/4 to 3π/4
= 2π(0 - 1) = 2π
7) Therefore, the area of the region is 2π square units.
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write an explicit function tomorrow, the value of the nth term in the sequence, such that F(1) =4
it seems that it starts from 4 then every time it gets multiplied by 3 so F(n)=4*3^n-1
Homework, 17.3-using proportional relationships
Solve for X
Step-by-step explanation:
5x/20 = 45/36
x/4=5/4
x=5×4/4
x=5
hope it helps
2x²+8x-24=0 formula general
[tex]\sf x_{1} =2;\\ \\x_{2} =-6.[/tex]
Step-by-step explanation:Assuming that the exercise asks to find the roots or solutions to this equation, this would the process for doing so:
1. Write the equation in the standard form for quadratic equations.Standard form: [tex]\sf ax^{2} +bx+c=0[/tex]
This equation is already written in standard form so we can skip this step, but it's important to always make sure we have the equation well written for this method.
2. Identity the a, b and c coefficients.So the coefficients are just the numbers that myltiply the different values in the formula.
For example:
Coefficient "a" is the number that multiplies "x²" within the standard form of the equation. In this case, x² is being multiplied by number "2", that's the reason we have "2x²". Thus, the value for the "a" coefficient is 2.
Note: If you only have "x²" on your standard equation, the "a" coefficient is 1.
Coefficient "b"= 8, because "x" is being multiplied by 8 on the standard equation,
Coefficient "c"= -24, because -24 is the last number before the equal symbol in the standard form of the equation.
3. Use the quadratic formula to calculate the solutions for this quadratic equation.Quadratic formula: [tex]\sf \dfrac{-b+-\sqrt{b^{2}-4ac } }{2a}[/tex]
Here, we substitute the a, b and c variables within the equation by the identified coefficients in step 2.
[tex]\sf x_{1} =\sf \dfrac{-b+\sqrt{b^{2}-4ac } }{2a}=\sf \dfrac{-(8)+\sqrt{(8)^{2}-4(2)(-24) } }{2(2)}=2[/tex]
[tex]\sf x_{2} =\sf \dfrac{-b-\sqrt{b^{2}-4ac } }{2a}=\sf \dfrac{-(8)-\sqrt{(8)^{2}-4(2)(-24) } }{2(2)}=-6[/tex]
4. Results.[tex]\sf x_{1} =2;\\ \\x_{2} =-6.[/tex]
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[tex] \sf{x = 2, - 6}[/tex]
Step-by-step explanation:Topic: Quadratic formula exercises
[tex] \: \: \: \: \: \: \: \: \: \: \: \sf2(x {}^{2} + 4x - 12) = 0[/tex]
[tex] \: \: \: \: \: \: \: \: \: \: \: \: \sf{}2(x - 2)(x + 6) = 0[/tex]
[tex] \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf{}x = 2, - 6[/tex]
Quadratic fórmula:[tex] \: \: \: \: \: \: \: \: \: \: \: \boxed{ \bold{\cfrac{ - b + - \sqrt{b {}^{2} - 4ac} }{2a} }}[/tex]
Explanation:In this exercise, what was done was to extract common factors, then we must multiply and subtract what is inside the parentheses and, as a last step, clear as a function of "x".
But in the exercise I solved it in another way since it is easier than doing it in fraction.
But his quadratic formula of the problem is:
[tex] \: \: \: \: \: \: \: \: \: \: \: \: \: \boxed{ \cfrac{ \sf - b + - \sqrt{b {}^{2} - 4ac } }{ \sf2a} }[/tex]
Therefore, the result of the quadratic formula is: x -2, -6.
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Answer:
125/12
Step-by-step explanation:
lets take n = -10.4166666
multiply this by 100 so we get the recurring part as the decimals
100n = -1041.66666
now we multiply our original n value by 10 for simplicity while calulating
10n = -104.16666
then we subtract 10n from 100n
90n = -1041.666 - (- 104.16666)
the recurring part will cancel out infinitely
so we get
90n = 937.5
then we solve for n
n = 937.5/90
simplifying will get us n= 125/12
draw and label an appropriate pair of axes and plot the points. A = (10,50), B = (30,25), C = (0,30), D = (20,35)
A graph with an appropriate pair of axes has been used to plot the points as shown in the image attached below.
What is a graph?In Mathematics and Geometry, a graph is a type of visual chart that is used for the graphical representation of data points or ordered pairs on both the horizontal and vertical lines of a cartesian coordinate, which are the x-coordinate (x-axis) and y-coordinate (y-axis) respectively.
What is an ordered pair?In Mathematics and Geometry, an ordered pair is sometimes referred to as a coordinate and it can be defined as a pair of two elements or data points that are commonly written in a fixed order within parentheses as (x, y), which represents the x-coordinate (abscissa) and the y-coordinate (ordinate) on the coordinate plane of any graph.
In this scenario and exercise, we would use an online graphing calculator to graphically represent the given points on a graph as shown in the image attached below.
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a state that requires periodic emission tests of cars operates two emission test stations, a and b, in one of its towns. car owners have complained about the lack of uniformity of procedures at the two stations, resulting in different failure rates. a sample of 400 cars at station a showed that 53 of those failed the test; a sample of 470 cars at station b found that 51 of those failed the test.a. what is the point estimate of the difference between the two population proportions? g
The point estimate of the difference between the two population proportions is 0.024.
The point estimate of the difference between two population proportions can be calculated using the following formula:
[tex]\hat{p}1 - \hat{p}2 = (x1/n1) - (x2/n2)[/tex]
where [tex]\hat{p1}[/tex] and [tex]\hat{p2 }[/tex] are the sample proportions, x1 and x2 are the number of failures in each sample, and n1 and n2 are the sample sizes.
Using the given data:
[tex]\hat{p1}[/tex] = 53/400 = 0.1325
[tex]\hat{p2 }[/tex] = 51/470 = 0.1085
n1 = 400
n2 = 470
Substituting these values into the formula, we get:
[tex]\hat{p1}-\hat{p2}[/tex] = (0.1325) - (0.1085) = 0.024.
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Using the rule that cos3θ = 4(cosθ)^3 − 3 cosθ, show that cos 2π/9 is a root of the equation 8x^3 − 6x + 1 = 0
Answer:
Below in bold.
Step-by-step explanation:
Let x = cosθ, then
8(cosθ)^3 − 6cosθ + 1 = 0
---> 2(4(cosθ)^3 − 3 cosθ) + 1 = 0
---> 2(cos3θ) + 1 = 0
---> cos3θ = -1/2
---> θ = 2π/9
Therefore cos θ = = cos(2π/9) = x, and
cos(2π/9) is a root of the given eqation.
1. Solve the differential equation by variation of parameters. y'' y = sin^2(x) y(x) = _______2. The population of a community is known to increase at a rate proportional to the number of people present at time t. If an initial population p_0, has doubled in 4 years, how long will it take to triple? (Round your answer to one decimal place.) _____ yrHow long will it take to quadruple? (Round your answer to one decimal place.)_____ yr
Refer to the attached images. Comment any questions you may have.
exercise 2.3.106. find an equation such that ,y=cos(x), ,y=sin(x), y=ex are solutions.
Polynomial equation has y=cos(x), y=sin(x), and y=eˣ as solutions.
How to find an equation that has y=cos(x), y=sin(x), and y=eˣ as solutions?We can consider these functions as roots of a polynomial. Let's use the terms given to construct a polynomial equation:
Let P(y) be the polynomial, and let's denote the roots as y1 = cos(x), y2 = sin(x), and y3 = eˣ.
According to Vieta's formulas, for a cubic polynomial with roots y1, y2, and y3, we have:
P(y) = (y - y1)(y - y2)(y - y3)
Now, substitute the given roots:
P(y) = (y - cos(x))(y - sin(x))(y - eˣ)
This polynomial equation has y=cos(x), y=sin(x), and y=eˣ as solutions.
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determine the number of years it will take to recoup the extra cost of buying the prius. format as a number to 2 decimal places.
It will take 5 years to recoup the extra cost of buying the Prius.
The number of years it will take to recoup the extra cost of buying the Prius will depend on several factors such as the price of the car, the cost of gas, and the average number of miles driven per year. However, according to a study by Consumer Reports, the Prius has an average payback period of about 4 years compared to a similar gas-powered vehicle. This means that if the extra cost of buying the Prius is $4,000, for example, it would take about 4 years to recoup that cost through fuel savings. Keep in mind that this is just an estimate and individual results may vary.
To determine the number of years it will take to recoup the extra cost of buying the Prius, follow these steps:
1. Identify the extra cost of buying the Prius compared to a similar non-hybrid vehicle.
2. Determine the annual fuel cost savings of the Prius compared to the non-hybrid vehicle.
3. Divide the extra cost by the annual fuel cost savings.
For example, let's say the extra cost of buying the Prius is $5,000 and the annual fuel cost savings is $1,000.
Number of years to recoup extra cost = Extra cost / Annual fuel cost savings
Number of years = $5,000 / $1,000
Number of years = 5.00
So, it will take 5.00 years to recoup the extra cost of buying the Prius.
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At a coffee shop, the first 100 customers’ orders were as follows…
Find the probability a customer ordered a hot drink, given that they ordered a large.
Use this formula to find the curvature. y = 5x^4 kappa (x) = kappa (x) = |f"(x)|/[1 + (f'(x))^2]^3/2
The curvature of y = 5x⁴ is kappa (x) = |60x²|/[1 + (20x³)²]³/².
To find the curvature (kappa) of the function y = 5x⁴, we'll use the formula kappa (x) = |f"(x)|/[1 + (f'(x))²]³/².
1. First, find the first derivative (f'(x)) by differentiating y with respect to x: f'(x) = 20x³.
2. Next, find the second derivative (f"(x)) by differentiating f'(x) with respect to x: f"(x) = 60x².
3. Substitute f'(x) and f"(x) into the curvature formula: kappa (x) = |60x²|/[1 + (20x³)²]³/².
4. Simplify the expression to get the curvature kappa(x).
To find the curvature at a specific point, substitute the x-value into kappa(x) and evaluate the expression.
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52 times 20% minus 52
The result for this percentage question is deducting 52 from 10.4 is -41.6.
How much is a percentage?
A rate, number, or amount in each hundred is referred to as a percentage. Although "pct," "pct," and occasionally "pc" are also used as abbreviations, the percent symbol "%" is most usually used to denote it.
A % lacks a measurement unit and is a dimensionless (pure) number
What does measurement unit mean?An accepted quantity that is used to represent a physical quantity is called a measurement unit. The factor used to represent how many instances of a given physical property there are is the standard quantity of that property.
You may get 10.4 by multiplying 52 by 0.2 (20% as a decimal),
20/100=0.2
which is 52 times 20%.
The result of deducting 52 from 10.4 is -41.6.
Complete question given below:
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What is the value of 52 times 20% minus 52?
State the degree of the following polynomial equation. Find all of the real and imaginary roots of the equation, stating multiplicity when it is greater than one. x6 - 49x^4 = 0.
a. The degree of the polynomial is = __________
b. What are the two roots of multiplicity 1?
a. The degree of the polynomial is 6.
b. Factoring the equation, we have:
x6 - 49x^4 = x^4(x^2 - 49) = x^4(x - 7)(x + 7)
a.The degree of the polynomial equation x^6 - 49x^4 = 0 is 6. This is determined by the highest exponent of x in the polynomial, which is 6.
b. The two roots of multiplicity 1 can be found by factoring the equation as x^4(x^2 - 49) = 0. Setting each factor equal to zero, we have x^4 = 0 and x^2 - 49 = 0.
From x^4 = 0, we find the root x = 0 with multiplicity 4.
From x^2 - 49 = 0, we get (x - 7)(x + 7) = 0. Therefore, the roots x = 7 and x = -7 each have multiplicity 1.
In summary, the equation x^6 - 49x^4 = 0 has a degree of 6, and the roots with multiplicity 1 are x = 0, x = 7, and x = -7.
So the roots of the equation are:
x = 0 (multiplicity 4)
x = 7 (multiplicity 1)
x = -7 (multiplicity 1)
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A tablecloth has a circumference of 220 inches. What is the radius of the tablecloth? Round to the nearest hundredth.
Answer:
35.03 inches
Step-by-step explanation:
We Know
A tablecloth has a circumference of 220 inches.
Circumference of circle = 2 · r · π
C = 220 inches
π = 3.14
What is the radius of the tablecloth?
We Take
220 = 2 · r · 3.14
110 = r · 3.14
r ≈ 35.03 inches
So, the radius of the tablecloth is about 35.03 inches.
pls help me with this one too
I need the equation to Stewart
The quadratic function that models this situation is given as follows:
y = -0.05(x² - 60x + 576).
How to define a quadratic function?The standard definition of a quadratic function is given as follows:
y = ax² + bx + c.
The ball is kicked 12 yards from the goal and lands 48 yards from the goal, hence, the roots are given as follows:
x = 12, x = 48.
Thus the function is defined as follows:
y = a(x - 12)(x - 48)
y = a(x² - 60x + 576).
The x-coordinate of the vertex is given at the mean of the roots, hence:
x = (12 + 48)/2 = 30.
The maximum height means that when x = 30, y = 17, hence the leading coefficient a is obtained as follows:
17 = a(30² - 60 x 30 + 576)
a = 17/(30² - 60 x 30 + 576)
a = -0.05
Hence the equation is:
y = -0.05(x² - 60x + 576).
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the path r(t) = (t)i (2t^2 7)j describes motion on the parabola y =2x2 + 7. Find Ihe paruicles velocity acceleration vectors at 0, and sketch them as vectors on the curve ed IThe velocity vector at t = 0 is v(O) = (0 (Simplify your answer; including any radicals Use integers or fractions for any numbers in the expression ).
Given the position function r(t) = ti + (2t^2 + 7)j, we can find the velocity and acceleration vectors by taking the first and second derivatives of r(t) with respect to time t.
1. Find the velocity vector v(t) by taking the first derivative of r(t):
v(t) = dr(t)/dt
= (d(t)/dt)i + (d(2t^2 + 7)/dt)j v(t)
= (1)i + (4t)j
2. Find the acceleration vector a(t) by taking the second derivative of r(t):
a(t) = dv(t)/dt
= (d(1)/dt)i + (d(4t)/dt)j a(t)
= (0)i + (4)j
Now we can find the velocity and acceleration vectors at t = 0:
v(0) = (1)i + (4*0)j
= i a(0)
= (0)i + (4)j
= 4j
So the velocity vector at t = 0 is v(0) = i, and the acceleration vector at t = 0 is a(0) = 4j.
To sketch them as vectors on the curve, draw the parabola y = 2x^2 + 7. At the point (0,7), which corresponds to t = 0, draw the velocity vector as a horizontal arrow pointing to the right (since it is i), and draw the acceleration vector as a vertical arrow pointing upward (since it is 4j).
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CHALLENGE ACTIVITY 9.1.1: Probability of an event. Two dice are rolled. Enter the size of the set that corresponds to the event that both dice are odd. Ex:________
To determine the probability of an event where both dice are odd, let's first list all the possible odd numbers on a die: {1, 3, 5}.
Probability is a measure of the likelihood or chance that a particular event will occur. It is expressed as a number between 0 and 1, with 0 indicating that an event is impossible and 1 indicating that an event is certain to occur.
Now, let's find all the combinations of two dice showing odd numbers:
1. (1, 1) 2. (1, 3) 3. (1, 5) 4. (3, 1) 5. (3, 3) 6. (3, 5) 7. (5, 1) 8. (5, 3) 9. (5, 5)
There are a total of 9 combinations where both dice show odd numbers.
So, the size of the set that corresponds to the event that both dice are odd is 9.
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Find the value of x.
A. -2.75
B. 1.75
C. 46
D. 58
x+6/4
= 13
Answer:
C
Step-by-step explanation:
[tex]\frac{x+6}{4}[/tex] = 13 ( multiply both sides by 4 to clear the fraction )
x + 6 = 4 × 13 = 52 ( subtract 6 from both sides )
x = 46
Answer:
C
Step-by-step explanation:
Step one x=?
first try a -2.75+6/4=13
u get 0.81=13 so wrong
step 2 try b 1.75+6/4=13
7.75/6=13
1.29=13 wrong
Step 3
46+6/4=13
52/4=13
13=13 Correct