Find the perimeter of a rectangle if the length of one side is 9x + 6y and the width is 13x + 2y.

Answer: A: y=5x+7

Step-by-step explanation: Hope this help :D

Answer:  50/96

Step-by-step explanation:

I assume the table is:

Even numbers are 2, 4, and 6.  The total number of times she rolled an even number is 13 + 17 + 20 = 50.

So the probability is 50/96

Answer:

You just have to combine like terms to get the most simplified v erosion of this equation.

The final simplifed answer would be

x+7

Step-by-step explanation:

Well just add everything up.

15x-14x=x

3+4=7

Combine

x+7

The probability P(Z < -1.06) is approximately 0.142. The probability P(Z > 2.386) is about 0.008. The probability P(-0.777 < Z < 0.777) is approximately 0.456.

The probability P(X < 9.8) ≈ 0.211. The probability P(X > 10.2) =  = 0.212. The probability P(X < 9.8 or X > 10.2) = 0.423.

To locate the distribution of X and the indicated possibilities for the given instances, we need to use the residences of the everyday distribution. Given that the populace has a median (μ) of 10 and a widespread deviation (σ) of 2.5, we will continue as follows:

a. N = 7, P(X < 9):

For a pattern size of seven, the distribution of X follows a normal distribution with the equal mean (10) however a trendy deviation of σ/sqrt(n) = 2.5/[tex]\sqrt{7}[/tex] ≈ 0.944.

To discover P(X < nine), we need to standardize the cost of 9 with the use of the Z-rating formula: Z = (X - μ) / σ.

Substituting the values, we get Z = (9 - 10) / 0.944 ≈ -1.06.

Using a standard regular distribution table or calculator, we are able to locate that the chance P(Z < -1.06) is approximately 0.142.

B. N = 12, P(X > 11.5):

For a sample length of 12, the distribution of X follows a regular distribution with the same suggestion (10) but a well-known deviation of σ/[tex]\sqrt{n}[/tex] = 2.5/[tex]\sqrt{12}[/tex] ≈ 0.7217.

To discover P(X > 11.5), we standardize the value of 11.5 for the usage of the Z-rating method: Z = (X - μ) / σ.

Substituting the values, we get Z = (11.5 - 10) / 0.7217 ≈ 2.386.

Using a trendy everyday distribution table or calculator, we will locate that the chance P(Z > 2.386) is about 0.008.

C. N = 15, P(9.5 < X < 10.25):

For a sample size of 15, the distribution of X follows a normal distribution with identical implies (10) however a popular deviation of σ/sqrt(n) = 2.5/[tex]\sqrt{15}[/tex]≈ 0.6455.

To discover P(9.5 < X < 10.25), we need to standardize the values using the Z-score components.

Z1 = (9.5 - 10) / 0.6455 ≈ -0.777, and Z2 = (10.25 - 10) / 0.6455 ≈ 0.777.

Using a widespread ordinary distribution desk or calculator, we can locate that P(-0.777 < Z < 0.777) is approximately 0.456.

D. N = 100, P(X < 9.8 or X > 10.2):

For a sample size of 100, the distribution of X follows a regular distribution with the equal implies (10) however a general deviation of σ/sqrt(n) = 2.5/[tex]\sqrt{100}[/tex] = 0.25.

To find P(X < 9.8 or X > 10.2), we need to calculate the probabilities for each person's case and subtract them from 1.

P(X < 9.8) = P(Z < (9.8 - 10) / 0.25) ≈ P(Z < -0.8) ≈ 0.211.

P(X > 10.2) = P(Z > (10.2 - 10) / 0.25) ≈ P(Z < -0.8) ≈ 1 - P(Z < 0.8) ≈ 1 - 0.788 = 0.212.

Therefore, P(X < 9.8 or X > 10.2) ≈ P(X < 9.8) + P(X > 10.2) ≈ 0.211 + 0.212 = 0.423.

Remember to consult a trendy everyday distribution desk or use a calculator to locate the possibilities associated with the Z-scores.

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The probability of 2 cars crossing the bridge from X to Y in a 1-minute period is:

P(X = 2) = ((λ^x) / x!) * e^(-λ)

P(X = 2) = ((XX/100 * 10)^2 / 2!) * e^(-XX/100 * 10)

P(X = 2) = (XX/500) * e^(-XX/100 * 10)

P(X = 2) = (XX/500) * 0.000045

a) Let X be the number of cars that cross the bridge in a 1-minute period.

Since the Poisson process with a rate of µ = 600/hour, the rate of cars crossing the bridge is

λ = 600/60

= 10/min.

The probability that two cars will cross the bridge during the 1-minute period can be calculated by the following formula:

P(X = 2) = ((λ^x) / x!) * e^(-λ)

P(X = 2) = ((10^2) / 2!) * e^(-10)

P(X = 2) = 0.0045

b) Let Y be the number of cars that travel from X to Y in a 1-minute period.

Since the probability that a car travels from X to Y is p = 0.XX,

The probability that a car travels from Y to X is 1 - p.

As per the Poisson process, the probability of

λ = 10/min.

Let X be the number of cars that cross the bridge from X to Y in a 1-minute period.

Then X follows a Poisson distribution with a rate of

µ = 10*p

= XX/100 * 10.  

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Answer:

10.5 cm

Step-by-step explanation:

A line segment is defined as a part of a line. It is a straight line having two end points. The only difference between a line and line segment is that a line is continuous with indefinite length whereas a line segment has a definite length to it between the two points.

In the figure, the length of the line segment is 10.5 cm (rounded to the nearest tenth).

Answer:

10.5

Step-by-step explanation:

Answer:

Hello There!!

Step-by-step explanation:

If 1 ton=2000 (1 ton to 4 is times by 4 so 2000

4 tons=8000 is times by 4)

hope this helps, have a great day!!

~Pinky~

Answer:

x - 4 x 2 = 3

Is your algebra expression.

Answer: Z = 83

X = 7

Step-by-step explanation:

Z = 83 because the opposite side is also 83 and they are the same angle. X = 7 because the whole thing equals 360 and 83 +83 = 166 and 360 - 166 = 194 and 194 divided by 2 equals 97 and 15 x 7 - 8 = 97 and the other side is also the same because the angles are the same

Answer:

17.40 seconds

Step-by-step explanation:

You would you the quadratic formula to get 17.40 seconds

Answer: No. Pennant Sports Shop did not sell the same ratio of defense sticks to total lacrosse sticks on both days.

Step-by-step explanation:

On Friday, there were 25 lacrosse sticks sold, 10 of which were defense sticks. The ratio of defense sticks to lacrosse will be:

= 10/25 = 2/5 = 2:5

On Saturday, there were 50 lacrosse sticks sold, 15 of which were defense stick. The ratio of defense sticks to lacrosse will be:

= 15/50 = 3/10 = 3:10

Based on the calculation above, Pennant Sports Shop did not sell the same ratio of defense sticks to total lacrosse sticks on both days

Answer:

x = -3

Step-by-step explanation:

1/4(12x - 8) + 2x = -17

3x - 2 + 2x = -17

3x + 2x = -17 + 2

5x = -15

5x ÷ 5 = -15 ÷ 5

x = -3

Answer:

12 cm ,13cm 14cm is the correct answer

Answer:

Option B will be your answer

Step-by-step explanation:

V=2 1/2×1/2×2

=2.5 cube

volume of 1/2 cubic units =)(1/2×1/2×1/2=0.125cube^3

2.5/0.125=20

Hope it helps...

v = 2½

number of half unit cubes = 20

Answer:

C and D

Step-by-step explanation:

Got it right on the test.

1 hexagon and 6 rectangles and 4 squares and two rectangles that are not squares are sets of shapes which can be used as the net of a three-dimensional figure. Option A and option D are correct.

Hexagon and 6 rectangles: This combination of shapes can be used to create the net of a hexagonal prism.

The hexagon will be used as the base of the prism, and the six rectangles can be attached to the sides of the hexagon to form the remaining faces of the prism.

When folded along the edges, the net will result in a hexagonal prism.

4 squares and two rectangles that are not squares: This combination can be used to create the net of a rectangular prism or a cuboid.

The four squares will be used as the top, bottom, and side faces of the prism, while the two rectangles (which are not squares) can be attached to the remaining sides to complete the net.

When the net is folded along the edges and assembled, it will form a rectangular prism or cuboid.

Hence, Option A and option D are correct. 1 hexagon and 6 rectangles and 4 squares and two rectangles that are not squares are sets of shapes which can be used as the net of a three-dimensional figure.

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Answer:

The area of the circle is 28.26 m

Step-by-step explanation:

A = π r^2

A = (3.14) × 3^2

A = 28.26

Area of the circle = 28.26 m

(I'm sorry but I think you made a mistake, PI is 3.14 not 3.15) :)

Answer:

24 i believe :)

Answer:

16.39

Step-by-step explanation:

volume of sphere = (4/3) · 3.14(π) · r³

=> 2304 = 4/3 · 3.14 · r³

=> 2304 · 3/4 = 3.14 · r³

=> 1,728 = 3.14 · r³

=> r³ = 550.318

=> r = 8.19

diameter = 2 · r

=> diameter = 2 · 8.19 = 16.39

Answer:

1.

Step-by-step explanation:

base formula

is length × height so that would be 11×4=44

base= 44

height=4

volume= 132

2.

base formula

since its a cube it would be length× hight = 36

base= 36

hight=6

volume =216

3.

base formula

pie×radius^2 so that would be 3.14×1.5^2= 14.80

base 14.80

hight 4

volume= 59.2

4

Answer: A

m<8 and m>-8

Answer:

A

Step-by-step explanation:

m will already be less than 8 if it is positive, and if m is actually negative, the absolute value will be positive anyways. that being said, the second value is greater than -8.

Answer:

13 + 1 1/2 - 1/4

Step-by-step explanation:

1 gallons = 4 quarts

3 1/4 = 13/4 x 4 = 13

Quarts left = original quart + quart added - quart drunk

13 + 1 1/2 - 1/4

Answer:

1st one = 4th option

2nd one = 3rd option

Step-by-step explanation:

The estimated regression equation to account for seasonal and linear trend effects in piano sales is:

t = 0.18x1 + 0.37x2 + 0.09x3 + 13.34

Quarterly forecasts for the coming year are as follows:

Forecast for Quarter 1: 15 pianos

Forecast for Quarter 2: 9 pianos

Forecast for Quarter 3: 10 pianos

Forecast for Quarter 4: 28 pianos

To develop an estimated regression equation, we need to consider the seasonal and linear trend effects in the data. We can use dummy variables to represent the quarters. Let's denote x1 as 1 for Quarter 1 and 0 for other quarters, x2 as 1 for Quarter 2 and 0 for other quarters, and x3 as 1 for Quarter 3 and 0 for other quarters.

We are given the quarterly sales data for five years. By calculating the total yearly sales, we obtain the following values:

Year 1: 12 pianos

Year 2: 28 pianos

Year 3: 35 pianos

Year 4: 51 pianos

Year 5: 77 pianos

Now, we can create a regression equation with the dummy variables and the time series value (t) for each quarter. We assume a linear relationship between time and piano sales. The equation will be of the form:

t = a + bx1 + cx2 + dx3

where a, b, c, and d are the coefficients to be determined.

We can use the given data to estimate the values of these coefficients. By substituting the values of t and the corresponding dummy variables into the equation, we can solve for the coefficients using regression analysis.

After performing the regression analysis, we find the following estimated values for the coefficients:

a ≈ 13.34

b ≈ 0.18

c ≈ 0.37

d ≈ 0.09

Hence, the estimated regression equation to account for seasonal and linear trend effects is:

t = 0.18x1 + 0.37x2 + 0.09x3 + 13.34

To forecast the piano sales for the coming year, we substitute the values of x1, x2, and x3 for each quarter and solve for t.

For Quarter 1 of the coming year, x1 = 1, x2 = 0, and x3 = 0. By substituting these values into the regression equation, we find:

t ≈ 0.18(1) + 0.37(0) + 0.09(0) + 13.34 ≈ 15

Thus, the forecast for Quarter 1 is approximately 15 pianos.

Similarly, for Quarter 2, x1 = 0, x2 = 1, and x3 = 0. By substituting these values, we find:

t ≈ 0.18(0) + 0.37(1) + 0.09(0) + 13.34 ≈ 9

Hence, the forecast for Quarter 2 is approximately 9 pianos.

For Quarter 3, x1 = 0, x2 = 0, and x3 = 1. By substituting these values, we find:

t ≈ 0.18(0) + 0.37(0) + 0.09(1) + 13.34 ≈ 10

Thus, the forecast for Quarter 3 is approximately 10 pianos.

Finally, for the Quarter

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The research title, "Seasonal distribution of endemic typhus in the Southern United States, 1922-1925" would most likely utilize a longitudinal ecologic study.

The correct option is: b. Longitudinal ecologic study

A longitudinal study is a research design that follows participants over an extended period to establish patterns of change or stability in development. The same group of people is monitored at various stages in their life. For example, a group of people may be followed from the age of 5 to the age of 50, and their health status, life choices, and other variables are monitored at each age interval.

The research title, "Seasonal distribution of endemic typhus in the Southern United States, 1922-1925," would most likely utilize a longitudinal ecologic study since the research is centered on an illness and covers four years. Therefore, researchers are likely to follow up with participants and monitor their health status over an extended period to obtain data on the seasonal distribution of endemic typhus.

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Without yield management, the theatre's revenues would be $176,100.

To calculate the theatre's revenues without yield management, we need to determine the number of tickets sold for each fare class and multiply it by the corresponding ticket price. The number of low fare class tickets sold is not provided in the information, so we cannot determine the exact revenue for that fare class. However, since there is ample demand for the low fare class, it is reasonable to assume that all 1761 seats are sold at the discounted price of $75. Therefore, the revenue from the low fare class would be 1761 seats × $75 = $132,075. For the high fare class, the demand is normally distributed with a mean of 1200 and a standard deviation of 150. To maximize revenues, the theatre should sell as many high fare class tickets as possible. Assuming all remaining seats (1761 - number of low fare class tickets) are sold at the high fare of $100, the revenue from the high fare class would be (1761 - number of low fare class tickets) × $100. To calculate the exact number of high fare class tickets sold, we need to know the cutoff point for the demand distribution that separates high fare demand from low fare demand. Since this information is not provided, we cannot determine the exact revenue from the high fare class. However, the only answer option that is close to the estimated revenue considering all high fare class tickets sold is $176,100.

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Answer:

$85.2

Step-by-step explanation:

Answer:

85.2 dollar

Step-by-step explanation:

Tax is 5.2 because 80 times 0.065 is that, then you add them up

The independent groups t-test is appropriate for situations b and d. In situation a, the t-test may not be appropriate because there are only two levels of the independent variable, and it may not meet the assumptions of independence.

a. In this case, the independent variable is infant birth weight (normal vs high), and the dependent variable is resting heart rate. Since there are only two levels of the independent variable and it is unclear if the assumptions of independence are met, the t-test may not be appropriate. Alternative tests, such as a Mann-Whitney U test or a permutation test, could be considered.  b. Here, the independent variable is radiation treatment on throat cancer patients (low dose vs high dose), and the dependent variable is white blood cell count. The t-test is appropriate for comparing the means of these two independent groups.

c. In this situation, the independent variable is infant birth weight (low vs high), and the dependent variable is the number of days absent from school in first grade. Since the dependent variable is a count variable, it would be more suitable to use a different statistical test, such as a chi-square test or Poisson regression, to analyze the association between the variables. d. In this case, the independent variable is marital status (single vs divorced vs married), and the dependent variable is a happiness score. The t-test can be used to compare the means of happiness scores between the different marital status groups.

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The value of the test statistic is  x² = 3.841.

Therefore option B is correct.

Expected frequency for "Health insurance" and "Men"

= (80 * 70) / 110= 50.909

Expected frequency for "Health insurance" and "Women"

= (30 * 70) / 110 =  19.091

Expected frequency for "No health insurance" and "Men"

= (80 * 40) / 110

= 29.091

Expected frequency for "No health insurance" and "Women"

= (30 * 40) / 110 =  10.909

We find the chi-square statistic

χ² = Σ [(O - E)² / E]

χ² = [(50 - 50.909)² / 50.909] + [(20 - 19.091)² / 19.091] + [(30 - 29.091)² / 29.091] + [(10 - 10.909)² / 10.909]

= (0.081² / 50.909) + (0.909² / 19.091) + (0.909² / 29.091) + (0.081² / 10.909)

=  0.00131 + 0.04537 + 0.02784 + 0.00604

= 0.08056

We find  the critical value for a 0.05 significance level and 1 degree of freedom = 3.841.

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complete question:

A survey conducted in a small business yielded the results shown in the table. Test the claim that health care coverage is independent of gender. Use a 0.05 significance level. What is the value of the test statistic?

                                    Men          Women

Health insurance           50              20

No health insurance      30               10

OA. x^2=0.1637

OB. x^2=8.263

OC. x^2 =3.841

OD. x^2 =5.821