Find the slope of the line
(15,18) (6,12)

$32 for each hockey stick

Step-by-step explanation:

71+25=96

Zack received $32 for each hockey stick he sold. He earned $96 in total from selling 3 sticks after deducting $25 for gloves, leaving him with $71.

Given that Zack sold 3 old hockey sticks and earned a total amount of money.

He spent $25 of his earnings on a pair of used hockey gloves.

After buying the gloves, he had $71 remaining.

Now, we need to find out how much Zack received for each hockey stick.

Let's assume the amount he received for each hockey stick is "x" dollars.

Total earnings from selling the hockey sticks = Number of sticks sold × Amount received per stick

Total earnings = 3x

Zack spent $25 on gloves and had $71 remaining, so we can write this equation:

Total earnings - Amount spent = Remaining money

3x - 25 = 71

Now we can solve for x (the amount received for each hockey stick):

3x - 25 = 71

Add $25 to both sides:

3x = 96

Divide both sides by 3:

x = $32

So, Zack received $32 for each hockey stick he sold.

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Answer: [tex]y=\frac{1}{4}x-3[/tex]

Step-by-step explanation:

Answer:

10/5 ten fifths are in two

Step-by-step explanation:

10/5 = 2

Step-by-step explanation:

[tex] \sf{ \longmapsto \: D.f(t)=20,000(1.08)t}[/tex]

Answer:

x=11

m<a=80º

m<b=80º

Step-by-step explanation:

They are congruent so

8x-8=5x+25

8x=5x+33

3x=33

x=11

Answer:

Step-by-step explanation:

8x-8=5x+25

8x+5x=25--8

13x=33

x=2.5

x=3cm

1/5 is the slope and we can use (-4,0) as a starting point.

Answer:

Step-by-step explanation:

(4^29)

Step-by-step explanation:

[tex]\sqrt{18} = 3\sqrt{2}[/tex]

[tex]\sqrt{50}=5\sqrt{2}[/tex]

[tex]2\sqrt{8} = 4\sqrt{2}[/tex]

So [tex]3\sqrt{2} +5\sqrt{2} -4\sqrt{2}[/tex]

= [tex]4\sqrt{2}[/tex]

Please give me a brainliest answer

Answer:

35

Step-by-step explanation:

If she was 25, 10 years ago she has aged 10 years since she was 25 making her 35.

Answer:

Answer:

1) How does "Abe" relate to the merry-go-round? (The problem doesn't seem to say.)

2) How many people did each person provide for? So how many dozens were brought? How many are in a dozen? So how many cookies were brought?

Step-by-step explanation:

nm the top

There are n seats on a merry- go-round. A boy takes n rides. Between each ride, he moves clockwise a certain number of places to a new horse. Each time he moves a different number of places. Find all n for which the boy ends up riding each horse.

2) So if there are n horses, first the boy could move by one place then he could move by n+1 places then by 2n+1 so on and so forth, until he moves (n−2)n+1 places, in which case he'd would have been ridden each horse only one time and taken unique number of steps, which implies that all n's satisfy given condition.

1) I don't know how to cancer this let me resheerch and ill get back to you

P>S let this be help only if you need to annotate or reword thx

Answer:

5300

Step-by-step explanation:

Round 4619 up to 5000.

Round 288 up to 300.

Add them together!

Answer:

1. x=105

2. 12 cans for $4

3. 14

Step-by-step explanation:

1. 15/18 = x/126

126/18=7

x=15*7=105

2. 12 cans for $4.  36 for $11.50.  

36/3=12.  11.50/3=3.8333.  

12 cans for $4 is the better deal because it would be an equal deal if it was 36 for 12:00.  

3. Circumference = pi*d.  Circumference = 43.96.  pi=3.14.  3.14*x=43.96.  x=diameter.  x=14.  diameter = 14

--Explanation to 3.14*x=43.96:

3.14*x=43.96, = 3.14x=43.96

3.14x*100 =43.96*100

314x=4396

314x/314 = 4396/314

x=14

Answer:

50 minutes

Step-by-step explanation:

Amount of time his journey took = 15km ÷ 18km/h

                                                      = 0.833h (to 3sf)

                                                      = 50 minutes

Answer:

x=0.0278 or 1/36

Step-by-step explanation:

y=4

So,y=1/9x

4=1/9x

36x=1

x=1/36

x=0.0278

Answer: 61 unit^2

Step-by-step explanation:

ABCD is a rectangle with dimensions 12 by 11, for a total area of 132 (square units). Although I could determine the lengths of the parallel lines of the interior trapezoid from the data supplied, I'm lazy and decided, instead, to subtract from the total rectangle area the areas of the four right triangles formed outside the shaded area. The area of each triangle is (1/2)b*h, and we are given those dimensions on the figure.

The four triangle areas:

TriD = 36

TriA = 6

TriB = 20

TriC = 9

Total area = 71 square units.

Subtract this from the rectangle's area: 132 - 71 = 61 units^2

This is the area of the shaded trapezoid.

Step-by-step explanation:

y= -2x

that is the answer

The equation for a line is y = mx + b. where m is the slope and b is the y intercept.

The slope is -1/3 (rise: 1, run: -3)

And the y-intercept is at -4.

So the equation for the line is:

y = -1/3x - 4

And we want all the y values BELOW the line of -1/3x - 4 as well as the values on the line because it’s not dotted. So instead of equals we write:

y <= -1/3x - 4

“Y is less than or equals to -1/3x - 4” where it includes the solutions on the line, as well as any solutions below it.

y <= -1/3x - 4 is the answer

Answer:

the answer is 36....

because...

12*3=36

and also 4*9 =36

Any multiple of 12 is also a multiple of 4 true because Multiples of 4 can be found by multiplying 4 by another number. For example, 4×3=12.

A multiple is a result of multiplying a number by a whole number (it should not be a fraction). Multiples of an integer are obtained by subtracting the product of the decreasing numbers and the product of the whole numbers. For example, to find multiples of 6, we multiply 6 by 1, 6 by 2, 6 by 3, etc. The coefficients are the result of this multiplication. A number can have an infinite number of repetitions because multiples of a number are obtained by multiplying it by natural numbers. So we can write an infinite number of times for a given number. The table below shows the first 10 multiples of some numbers.

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Hello Carousel!

[tex] \huge \boxed{\mathfrak{Question} \downarrow}[/tex]

[tex] \huge \tt\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }[/tex]

[tex] \large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}[/tex]

[tex]\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) } \\ [/tex]

To start solving this question, note that ⇨ for any 2 differentiable functions, the derivative of the quotient of the 2 functions will be the denominator multiplied by the derivative of the numerator minus the numerator again multiplied by the derivative of the denominator whole divided by the denominator². By doing all these steps, we'll get it as..

[tex]\frac{\left(x^{1}-5\right)\frac{\mathrm{d}}{\mathrm{d}x}(3x^{2}-2)-\left(3x^{2}-2\right)\frac{\mathrm{d}}{\mathrm{d}x}(x^{1}-5)}{\left(x^{1}-5\right)^{2}} \\ [/tex]

Remember that the derivative of the polynomial will be the sum of the derivatives of its terms. We know that, the derivative of a constant term is 0 & the derivative of [tex]ax^{n}[/tex] is [tex]nax^{n-1}[/tex]. So..

[tex]\frac{\left(x^{1}-5\right)\times 2\times 3x^{2-1}-\left(3x^{2}-2\right)x^{1-1}}{\left(x^{1}-5\right)^{2}} \\ [/tex]

Now, simplify it..

[tex]\frac{\left(x^{1}-5\right)\times 2\times 3x^{2-1}-\left(3x^{2}-2\right)x^{1-1}}{\left(x^{1}-5\right)^{2}} \\ = \frac{\left(x^{1}-5\right)\times 6x^{1}-\left(3x^{2}-2\right)x^{0}}{\left(x^{1}-5\right)^{2}} \\ = \frac{x^{1}\times 6x^{1}-5\times 6x^{1}-\left(3x^{2}x^{0}-2x^{0}\right)}{\left(x^{1}-5\right)^{2}} \\ = \frac{6x^{1+1}-5\times 6x^{1}-\left(3x^{2}-2x^{0}\right)}{\left(x^{1}-5\right)^{2}} \\ = \frac{6x^{2}-30x^{1}-\left(3x^{2}-2x^{0}\right)}{\left(x^{1}-5\right)^{2}} \\ = \frac{6x^{2}-30x^{1}-3x^{2}-\left(-2x^{0}\right)}{\left(x^{1}-5\right)^{2}} \\ = \frac{\left(6-3\right)x^{2}-30x^{1}-\left(-2x^{0}\right)}{\left(x^{1}-5\right)^{2}} \\ = \frac{3x^{2}-30x^{1}-\left(-2x^{0}\right)}{\left(x^{1}-5\right)^{2}} \\ = \frac{3x^{2}-30x-\left(-2\right)}{\left(x-5\right)^{2}} \\ = \large \boxed{\boxed{ \bf \frac{3x^{2}-30x + 2}{\left(x-5\right)^{2}} }}[/tex]

__________________

Hope it'll help you!

ℓu¢αzz ッ

Answer:

{4, 5, 6, 7, 8, 9}

[tex]\{ x \ | \ 3 < x \leq 9 \}[/tex]

[tex]\{ x \ | \ 4 \leq x \leq 9 \}[/tex]

Step-by-step explanation:

See above.

Answer:

{ 4,5,6,7,8,9 }

{ x: 3 < x ≤ 9 }

Step-by-step explanation:

I hope the notations speak for themselves.

Hello there!

y-y1=m(x-x1)

y-3=4(x-1)

And that's our equation in point-slope form. Hope it helps!

~Just a joyful teen

[tex]SilentNature\\(GraceRosalia)[/tex]

A rectangle has 4 coordinates.

The coordinate of the last vertex is (-2,-8)

The points are given as:

[tex]\mathbf{A = (-7,-4)}[/tex]

[tex]\mathbf{B = (1,6)}[/tex]

[tex]\mathbf{C = (6,2)}[/tex]

Calculate distance AB

[tex]\mathbf{AB = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}[/tex]

So, we have:

[tex]\mathbf{AB = \sqrt{(-7 - 1)^2 + (-4 - 6)^2}}[/tex]

Calculate distance CD

[tex]\mathbf{CD = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}[/tex]

So, we have:

[tex]\mathbf{CD = \sqrt{(x - 6)^2 + (y - 2 )^2}}[/tex]

Equate AB and CD

[tex]\mathbf{ \sqrt{(x - 6)^2 + (y - 2)^2} = \sqrt{(-7 - 1)^2 + (-4 - 6)^2}}\\[/tex]

Cancel out the squares

[tex]\mathbf{ (x - 6)^2 + (y - 2)^2 = (-7 - 1)^2 + (-4 - 6)^2}[/tex]

By comparison

[tex]\mathbf{x -6 = -7-1}[/tex]

[tex]\mathbf{y-2 = -4-6}[/tex]

So, we have:

[tex]\mathbf{ x = 6-7-1 }[/tex]

[tex]\mathbf{ x = -2}[/tex]

[tex]\mathbf{y = 2-4-6 }[/tex]

[tex]\mathbf{y = -8}[/tex]

Hence, the coordinate of the last vertex is (-2,-8)

Read more about coordinates at:

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Answer:

[tex]y = 2x + 2[/tex]

Step-by-step explanation:

The equation of any (non-vertical) line can take the form

y = ax + b where a is the slope and b is the y intercept. We know that in this case, the y intercept is 2. So we can substitute b = 2:

[tex]y = ax + 2.[/tex]

Now, to find the x intercept, simply put y = 0 (since every point on the x axis has y = 0) and x = -1, since that is the given x intercept:

0 = -a + 2, so we see that a = 2. The equation is then:

y = 2x + 2

Answer:

smallest integer value of m=4

Step-by-step explanation:

Answer:

148 cm2

Step-by-step explanation:

5 * 4 * 2 = 40

6 * 5 * 2 = 60

6 * 4 * 2 = 48

40 + 60 + 48 = 148

Answer:

Step-by-step explanation:

T.S.A (TOTAL SURFACE AREA) OF CUBOID :

→ 2(lb + bh + lh)

( l = length, b = breadth , h = height )

→ Given :

• Length (l) = 6cm

• Breadth (b) or width = 4cm

• Height (h) = 5cm

Total Surface area of cuboid :

• 2( 6×4+ 4×5+ 5×6) cm²

• 2 ( 24 + 20 + 30 ) cm²

• 2 ( 74 ) cm²

• 148 cm²

Since 11% of $115 is $12.65, it is convenient to pay the flat fee of $12.

If you sell a smart phone online for $115, to determine how much you will pay if you use the online market with the lesser fee, the following calculation must be performed:

Thus, since 11% of $115 is $12.65, it is convenient to pay the flat fee of $12.

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Answer:

My answer is A. and I hope this'll help