Five friends each conducted different studies comparing two variables. Each friend calculated the correlation coefficient, r, for their variables. Which r values suggest strong linear relationships? Select all that apply.

Step-by-step explanation:

Angles 4, 5, 8, 9 12, 13 and 16 are 48°, The rest of the angles will have 132°

A = ( 4 , 3 ) ..**&**.. B = ( - 1 , 1 )

_____________________________

Slope = [ y(B) - y(A) ] ÷ [ x(B) - x(A) ]

Slope = [ 1 - 3 ] ÷ [ - 1 - 4 ]

Slope = [ - 2 ] ÷ [ - 5 ]

Slope = 2/5

______________________________

y - y(0) = Slope × ( x - x(0) )

y - y(A) = Slope × ( x - x(A) )

y - 3 = 2/5 × ( x - 4 )

y - 3 = 2/5 x - 8/5

y = 2/5 x - 8/5 + 3

y = 2/5 x - 8/5 + 15/5

y = 2/5 x + 7/5

Answer:

Step-by-step explanation:

2w+5w-6+4w

=10w+4w-6

=14w-6

=2(7w-3)

Answer:

[tex]11w - 6[/tex]

Step-by-step explanation:

[tex]2w + 5w + 4w = 11w[/tex]

[tex]11w - 6[/tex]

Answer:

a) 2.5^2+19\times2.5-16.75

Step-by-step explanation:

(2.5)² +(19× 2.5) - 16.75

= 6.25 + 47.5 - 16.75 = 37

Answer:

Numbner of plant in field = 2,020

Cost of planting trees = R.s 151,500

Step-by-step explanation:

GIven:

Side of square field = 45 m

Area of well = 5 square meter

1 plant = 1 squre meter

Cost per tree = R.s 75

Find:

Numbner of plant in field

Cost of planting trees

Computtaion:

Area of planting trees = Area of filed - Area of well

Area of planting trees = [45 x 45] - 5

Area of planting trees = 2,025 - 5

Area of planting trees = 2,020 squre field

Numbner of plant in field = Area of planting trees /  1 squre meter

Numbner of plant in field = 2,020

Cost of planting trees = 75 x Numbner of plant in field

Cost of planting trees = 75 x 2,020

Cost of planting trees = R.s 151,500

Answer:

No, Alex had the better free throw percentage

Step-by-step explanation:

If you turn these data sets into completion percentage, (which is when you make a shot), Alex has a free throw % of 40, while Elizabeth's free throw % is only 36

Answer:

- 3.21

Step-by-step explanation:

Answer:

10 is the range  12 game were played in the season

Step-by-step explanation:

sorry if its wrong

Answer:
29 games were played in the season.
[6,8)

1,3,3,3,4,4,4,4,5,5,6,6,6,6,6,6,7,7,7,7,8,8,8,9,9,10,11,11,12

Step-by-step explanation:

Answer: 2×9=18

Step-by-step explanation:

Answer:

the fractio will be

[tex] \frac{2}{9} for \: each[/tex]

Answer:

Tip = $9

Step-by-step explanation:

Bill amount to nearest ten dollars = $60

[tex]tip = 15\% of 60 = \frac{15}{100} \times 60 = 9[/tex]

I = 6750

P= 25000

r = 9% = 0.09

t=?

I= prt

6750 = 25000×0.09× t

t = 6750/25000"0.09 = 3

Answer - 3 years.

Answer:

0.42857142857

Step-by-step explanation:

Answer:

20% off

Step-by-step explanation:

96/120 = 80% price still, so 20% off.

Answer:

It is C.

First of all, we can see that angle 1 is 132 degrees because they are the same angles/measurements. Therefore, angle 1 and angle 3 are also supplementary as they create a straight line, or 180 degree angle. As they are supplementary, angle 1 + angle 3 = 180. We know that angle 1 is 132, so we have 132 + angle 3 = 180, and angle 3 is 42 degrees.

Answer:

56t

Step-by-step explanation:

Step-by-step explanation:

what you typed in here must be wrong or incomplete.

what you typed is (with explicit multiplication symbols to make it clear)

10×x×2×y - 2

for x=-1 and y=-2

that shows then

10×-1 × 2×-2 - 2 = -10 × -4 - 2 = 40 - 2 = 38

but 38 is not in the answer options.

so, there must be something wrong with your problem description.

Answer:

radius = 19 ft

Step-by-step explanation:

volume of a cylinder: r²πh

12468.94 = r²π × 11

=> r² = 12468.94 ÷ 11π

=> r² = 361

=> r = 19

Answer:

r=19

Step-by-step explanation:

[tex]12468.94 = (3.14) {r}^{2} (11) \\ \frac{12468.94}{34.54} = \frac{34.54 {r}^{2} }{34.54} \\ \sqrt{361} = \sqrt{ {r}^{2} } \\ 19 = r[/tex]

Replace the x with n:

f(n) = 2n+1

Feel free to mark it as brainliest :D

Answer:

Step-by-step explanation:

given f(x) = 2x + 1

f(n) = 2n + 1

by substitution: n replaces x in the eqn

Answer:

[tex]5^{th} term = 126a^5b^4[/tex]

Step-by-step explanation:

[tex]\left(a+b\right)^n=\sum _{i=0}^n\binom{n}{i}a^{\left(n-i\right)}b^i\\\\(a + b)^9 =\sum _{i=0}^9\binom{9}{i}a^{\left(9-i\right)}b^i\\\\[/tex]

       [tex]=a^9 + 9a^8b + 36a^7b^2 + 84a^6 b^3 + 126a^5b^4+ 126a^4b^5+84a^3b^6+ 36a^2b^7+ 9ab^8+b^9[/tex]

[tex]5^{th} term = 126a^5b^4[/tex]

Answer:

Tangent

Step-by-step explanation:

Given

[tex]\angle C = 50[/tex]

See attachment for complete question

Required

Function to calculate BC

If AB is known, BC is calculated as:

[tex]\tan(C) = \frac{AB}{BC}[/tex]

Substitute d for AB and 50 for C

[tex]\tan(50) = \frac{d}{BC}[/tex]

Make BC the subject

[tex]BC = d * \tan(50)[/tex]

Hence, BC can be found using tangent

Answer

$1.25

Step-by-step explanation:

well a quarter is 25 and 4 of them is $1.00 plus 25 = $1.25 cents

Answer:

Step-by-step explanation:

The standard form of a circle is

[tex](x-h)^2+(y-k)^2=r^2[/tex] where h and k are the coordinates of the center of the circle, and r is the radius squared. Our center is located at (-6, -4)  and from the center to the outer edge is 2 units, so the radius is 2-squaraed, which is 4. That makes the equation for this circle

[tex](x-(-6))^2+(y-(-4))^2=4[/tex] which simplifies to

[tex](x+6)^2+(y+4)^2=4[/tex]

Answer:

yes

Step-by-step explanation:

Answer:

0.611 rad

Step-by-step explanation:

For the radian measure:

180° = π radians

180° : 110° = 11 / 18 ≈ 0.611

110° =  11π/18 rad ≈ 0.611 rad

hope this helps you

8 1/4

PLZ MARK BRAINLY

Step-by-step explanation:

2¾+5½

4x2+3=11

2x5+1=11

therefore we have

11/4 + 11/2

(11+22)/4

33/4= 8¼

Answer:

[tex]\cos(\theta_1) = \frac{\sqrt{111}}{20}[/tex]

Step-by-step explanation:

Given

[tex]\sin(\theta_1) = \frac{17}{20}[/tex]

[tex]Quadrant = 1[/tex]

Required

[tex]\cos(\theta_1)[/tex]

We know that:

[tex]\sin^2(\theta_1) + \cos^2(\theta_1) = 1[/tex]

This implies that:

[tex](\frac{17}{20})^2 + \cos^2(\theta_1) = 1[/tex]

Collect like terms

[tex]\cos^2(\theta_1) = 1 -(\frac{17}{20})^2[/tex]

[tex]\cos^2(\theta_1) = 1 -\frac{289}{400}[/tex]

Take LCM and solve

[tex]\cos^2(\theta_1) = \frac{400 -289}{400}[/tex]

[tex]\cos^2(\theta_1) = \frac{111}{400}[/tex]

Take square roots

[tex]\cos(\theta_1) = \frac{\sqrt{111}}{\sqrt{400}}[/tex]

[tex]\cos(\theta_1) = \frac{\sqrt{111}}{20}[/tex]

Answer:

m=-1and c=3

m=-2c=-3

m=5c=-2

m=3andc=-2