GIVEN: A = 10 - 20 3 - 3 - 2 sa, and the spectum of A is, A= (-2,1}, 112 = -2 1 = a) Determine a basis, B(-2) for the eigenspace associated with 1 =-2 b) Determine a basis, B(1) for the eigenspace associated with 12 =1c c) Determine Śdim E(10) NOTE: E(A) is the eigenspace associated with the eigenvalue, .

Answers

Answer 1

The correct option is (A) $\dim E(10) = 0$

Given A = \[\left[\begin{matrix}10 & -20\\3 & -3\end{matrix}\right]\] The Eigen values of A can be obtained by solving the characteristic equation|A-λI| = 0\[|A-\lambda I|=\left|\begin{matrix}10-\lambda & -20\\3 & -3-\lambda\end{matrix}\right|\]\[\Rightarrow (10-\lambda)(-3-\lambda)-(-20)(3)=\lambda^2-7\lambda+12=0\]\[\Rightarrow \lambda_1=4,\lambda_2=3\]The spectrum of A is, A= {-2,1}.1. Basis of the eigenspace associated with 1 = -2Basis of eigenspace associated with -2 can be found by solving(A+2I)X=0 \[\Rightarrow\left[\begin{matrix}12 & -20\\3 & -1\end{matrix}\right]\left[\begin{matrix}x_{1}\\x_{2}\end{matrix}\right]=\left[\begin{matrix}0\\0\end{matrix}\right]\]By Echolon form\[\left[\begin{matrix}12 & -20\\3 & -1\end{matrix}\right]\Rightarrow \left[\begin{matrix}1 & \frac{-5}{3}\\0 & 0\end{matrix}\right]\]Taking X = t\[\Rightarrow B(-2)=\begin{Bmatrix}\begin{matrix}\frac{5}{3}\\1\end{matrix}\end{Bmatrix}\]2. Basis of the eigenspace associated with 1 = 1Basis of eigenspace associated with 1 can be found by solving(A-I)X=0\[\Rightarrow\left[\begin{matrix}9 & -20\\3 & -4\end{matrix}\right]\left[\begin{matrix}x_{1}\\x_{2}\end{matrix}\right]=\left[\begin{matrix}0\\0\end{matrix}\right]\]By Echolon form\[\left[\begin{matrix}9 & -20\\3 & -4\end{matrix}\right]\Rightarrow \left[\begin{matrix}1 & \frac{-20}{9}\\0 & 0\end{matrix}\right]\]Taking X = t\[\Rightarrow B(1)=\begin{Bmatrix}\begin{matrix}\frac{20}{9}\\1\end{matrix}\end{Bmatrix}\]3. dimension of eigenspace associated with 1 = 0 as the basis is an empty set.  Hence the dimensions of E(-2), E(1), and E(10) are, \[dim\,E(-2)=1\]\[dim\,E(1)=1\]\[dim\,E(10)=0\]

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Related Questions

Please answer correctly I will mark you Brainliest!

Answers

Answer:

1047.12in³

Step-by-step explanation:

The volume of the sphere is:

V= 4/3 πr³

Where r is radius

Therefore the volume of each pinata is:

V= 4/3 x π x 5³

V= 523.6in³

The total:

V = 523.6 + 523.6 = 1047.12in³

what is the longitudinal position latitudinal position of Nepal ​

Answers

Step-by-step explanation:

I think that is your answer because in the Himalayas it lies between latitudes 26.

this is 9th grade math.funfdjvnuvuv

Answers

y = -2/5 x + 22/5 is the required equation of the line passing the coordinates

Determining the equation of a line

The equation of a line in slope intercept form is expressed as y = mx +b

where;

m is the slope

b is the y-intercept

Given the coordinate points (-4, 6) and (6, 2), the slope of the line is expressed as:

Slope = 2-6/6+4

Slope = -4/10
Slope = -2/5

For the y-intercept

2 = -2/5(6) + b

2 + 12/5 = b
b = 22/5

Hence the equation of the line passing the coordinate is y = -2/5 x + 22/5

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OMG PLS HELP WITH THIS IM PANICKING OMG I GOT A F IN MATH MY MOM JUST YELLED AT ME IM CRYING PLS HELP WITH THS- PLSS TELL ME WHAT TO DRAW

Answers

Answer:

The answer to this question is $14,916

Step-by-step explanation:

18,469 - 3,553 = 14916

As he already has money for the car.

A bar model is shown in the linked picture.


Please help me with the

Answers

Answer: i think its 10

Step-by-step explanation:

can somebody help me please

Answers

Answer:

B

Step-by-step explanation:

Using Pythagoras' identity in the right triangle

x² = 4² + ([tex]\sqrt{5}[/tex] )² = 16 + 5 = 21 ( take the square root of both sides )

x = [tex]\sqrt{21}[/tex] → B

Find the particular solution determined by the given condition. ds/dt = 16t^2 + 9t - 6; s = 120 when t = 0 The particular solution that satisfies the given condition is s =

Answers

The particular solution that satisfies the given condition is s = (16/3)t³ + (9/2)t² - 6t + 120

To find the particular solution of the differential equation ds/dt = 16t² + 9t - 6 with the condition s = 120 when t = 0, we need to integrate the right-hand side of the equation with respect to t and then solve for the constant of integration using the given condition.

First, let's integrate the right-hand side of the equation:

∫(ds/dt) dt = ∫(16t² + 9t - 6) dt

Integrating term by term, we get:

s = (16/3)t³ + (9/2)t² - 6t + C

Now, we can use the given condition s = 120 when t = 0 to determine the value of the constant of integration C:

120 = (16/3)(0)³ + (9/2)(0)² - 6(0) + C

120 = C

Therefore, the particular solution that satisfies the given condition is:

s = (16/3)t³ + (9/2)t² - 6t + 120

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Prove or disprove the following statement: if A, B, and C are
sets with finite cardinalities that satisfy A ∩ B ∩ C = ∅, then |A
∪ B ∪ C| = |A| + |B| + |C|.

Answers

The statement |A ∪ B ∪ C| = |A| + |B| + |C| is true, which means the statement is proven.

Let A, B, and C be sets with finite cardinalities that satisfy A ∩ B ∩ C = ∅.

We have to prove that |A ∪ B ∪ C| = |A| + |B| + |C|.

The addition law of sets states that the cardinality of a union of two finite sets is equal to the sum of the cardinalities of the sets minus the cardinality of their intersection.

Thus, we get: |A ∪ B ∪ C| = |A ∪ B| + |C| − |(A ∩ B) ∪ C| = (|A| + |B| − |A ∩ B|) + |C| − |(A ∩ B) ∩ C| = |A| + |B| + |C| − |A ∩ B ∩ C|.Since A ∩ B ∩ C = ∅, we get |A ∪ B ∪ C| = |A| + |B| + |C|.

Thus, the statement is proven.

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10 points!! Please give me real help!!

Answers

Answer:

32

Step-by-step explanation:

Tamika is making a flag design in the shape of a parallelogram. Which x- and y-values must she use in order to guarantee that the flag is in the shape of a parallelogram?​

Answers

Answer:

x = 1/2

y = 3

Step-by-step explanation:

Remark

The diagonals of a parallelogram cut each other in half. That means that x lengths are equal and the y lengths are equal

Equations

3y = y + 6

10x = 6x + 2

Solution for x

10x = 6x + 2                     Subtract 6x from both sides

10x - 6x = 6x - 6x + 2

4x = 2                              Divide by 4

4x/4 = 2/4

x = 1/2

Solution for y

3y = y + 6

3y - y = y- y + 6

2y = 6

y = 3

Answer:

Step-by-step explanation:

Suppose Nate loses 38% of all thumb wars.

(a) What is the probability that Nate loses two thumb wars in a row?
(b) What is the probability that Nate loses three thumb wars in a row?
(c) When events are independent, their complements are independent as well. Use this result to determine the probability that Nate loses three thumb wars in a row, but does not lose four in a row.

1. The probability that Nate loses two thumb wars in a row is: _______________
2. The probability that Nate loses three thumb wars in a row is:_____________

Answers

a. Probability of losing the second thumb war is also 0.38.

b. Probability of losing the third thumb war is also 0.38.

Given that Nate loses 38% of all thumb wars.

We can use the probability of losing the thumb war as

p=0.38.

The probability of winning is

1-0.38=0.62.

a) Probability of losing two thumb wars in a row is:

P(loses two in a row) = P(loses first) × P(loses second)

The probability of losing the first thumb war is 0.38.

The probability of losing the second thumb war is also 0.38

So,

P(loses two in a row) = (0.38) × (0.38)

= 0.1444

b) Probability of losing three thumb wars in a row is:

P(loses three in a row) = P(loses first) × P(loses second) × P(loses third)

The probability of losing the first thumb war is 0.38.

The probability of losing the second thumb war is also 0.38

The probability of losing the third thumb war is also 0.38.

So,

P(loses three in a row) = (0.38) × (0.38) × (0.38)

= 0.054872

c) When events are independent, their complements are independent as well.

If the probability of winning the thumb war is p, then the probability of losing the thumb war is 1-p.

The complement of "losing three in a row" is "not losing three in a row".

P(not loses three in a row) = 1 - P(loses three in a row)P(not loses three in a row)

= 1 - 0.054872

= 0.945128

The probability that Nate loses three thumb wars in a row, but does not lose four in a row is the probability of losing three minus the probability of losing four in a row.

P(loses three but not four in a row) = P(loses three in a row) - P(loses four in a row)

P(loses four in a row) = P(loses three in a row) × P(does not lose the next)

P(loses four in a row) = (0.38) × (0.38) × (0.38) × (0.62)

= 0.02081416

P(loses three but not four in a row) = 0.054872 - 0.02081416

= 0.03405784

The probability that Nate loses two thumb wars in a row is 0.1444

The probability that Nate loses three thumb wars in a row is 0.054872.

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Serenity is going to invest $850 and leave it in an account
for 5 years. Assuming the interest is compounded
annually, what interest rate, to the nearest hundredth of a
percent, would be required in order for Serenity to end up
with $1,130?

Answers

Answer:

5.86

Step-by-step explanation: its right on delta math

Determine the surface area of a cereal box with these dimensions width: 3 inches length: 8 inches height: 12 inches

Answers

It’s 11 inches amd 12 ft but hola Sonora

PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!!PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!!

Answers

Answer:

pi, and square root of 2

I don't think you're ACTUALLY going to give me brainliest

How many more gift card raffle tickets will
be entered than shopping spree raffle tickets
if there are 500 total raffle tickets?

Answers

Answer:

25 tickets

Step-by-step explanation:

If the answer is wrong, I don't know what to say because the answer I got is 25

The would be 25 more gift card raffle ticket than shopping spree raffle tickets if there are 500 total raffle tickets

What is an equation?

An equation is an expression that shows the relationship between two or more numbers and variables.

The shopping spree raffle tickets is 35% while the gift card tickets is 40%. Hence for 500 tickets:

Difference = (40% - 35%) * 500 = 25 tickets

The would be 25 more gift card raffle ticket than shopping spree raffle tickets if there are 500 total raffle tickets

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HELP ASAPPPPPPPPPPPPPP

Answers

3.14 x 11 = 34.54

Pi = 3.14 so times by 11 = 34.54

Help me with this please

Answers

Answer:

x = 138

Step-by-step explanation:

Exterior angle thm:

68 + 70 = x

x = 138

A tank contains 2380 L of pure water. A solution that contains 0.07 kg of sugar per liter enters a tank at the rate 7 U/min The solution is mixed and drains from the tank at the same rate. (a) How much sugar is in the tank initially? 0 (kg) (b) Find the amount of sugar in the tank after t minutes. amount = 166.6(1-e^(-t/340)) your answer should be a function of t) (kg) (c) Find the concentration of sugar in the solution in the tank after 33 minutes. concentration = 166.6 (kg/L)

Answers

The concentration of sugar in the solution in the tank after 33 minutes is approximately 0.00734 kg/L or 7.34 g/L.

(a) Initially, the tank contains pure water, so there is no sugar in the tank. Therefore, the amount of sugar in the tank initially is 0 kg.

(b) The amount of sugar in the tank after t minutes can be calculated using the formula:

amount = 166.6(1 - [tex]e^{-t/340}[/tex])

Here, t is the time in minutes. This formula is derived from the exponential decay model, where the rate of sugar leaving the tank is proportional to the amount of sugar present. The constant 166.6 represents the equilibrium amount of sugar in the tank.

As time passes, the term [tex]e^{-t/340}[/tex] approaches 1, and the amount of sugar in the tank approaches the equilibrium amount of 166.6 kg.

(c) To find the concentration of sugar in the solution in the tank after 33 minutes, we need to divide the amount of sugar by the volume of the tank. The volume of the tank is given as 2380 L.

First, let's calculate the amount of sugar in the tank after 33 minutes using the formula from part (b):

amount = 166.6(1 - [tex]e^{-33/340}[/tex])

amount ≈ 166.6(1 - 0.895)

amount ≈ 166.6(0.105)

amount ≈ 17.493 kg

Now, we can calculate the concentration:

concentration = amount / volume

concentration = 17.493 kg / 2380 L

concentration ≈ 0.00734 kg/L

Therefore, the concentration of sugar in the solution in the tank after 33 minutes is approximately 0.00734 kg/L or 7.34 g/L.

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*HURRY* Kale purchased a new car. The car had a list price of $28,730. Kale made a down payment of $2,750 and financed the rest, paying 4.9% interest compounded monthly over a payment period of four years. If Kale also had to pay 8.4% sales tax, a $750 vehicle registration fee, and an $88 documentation fee, what is his monthly payment

Answers

Answer:

$5934

Step-by-step explanation:

Solve the inequality
*
2x^2+ 5x – 3 < 0.

Answers

Answer:

heres the answer I think

Step-by-step explanation:

-3 < x < 1/2

can someone help plz ... mark brainliest ❤️

Answers

Answer:

Top:(4r⁹+3r³-5)

Bottom: r⁵

Step-by-step explanation:

i need help please explain to me the answer !

Answers

Answer:

If the triangle is similar then their ratio is also same

x = 8

6 4.8

X =8×6

4.8

x = 10 cm

hope this helps

good day mate

Please help if you would want brianleist!! :D ^^

Answers

Answer:

384

Step-by-step explanation:

v= L x W x H

v= 4 x 2 x 1.2

v= 9.6

9.6 x 40 = 384

lmk if you have any questions  :)

Answer:

A

Step-By-Step Explanation:

Step One: The first step is to figure out the volume of one. The volume formula is length times width times height. We have all the dimensions so: 4 times 2 times 1.2= 9.6.

Step Two: Now, we just mutiply the number by 40 since there are 40 slabs: 384.

Test for equality of population means against the alternative that the means are different assuming normality, choosing ? 5% and using two samples of sizes 12 and 18, with mean 10 and 14, respectively, and equal standard deviation 3.

Answers

The p-value (0.0208) is less than the significance level (0.05), we reject the null hypothesis. This indicates that there is sufficient evidence to suggest the case.

Null hypothesis (H0): The population means are equal, μ1 = μ2.

Alternative hypothesis (Ha): The population means are different, μ1 ≠ μ2.

Select the significance level (α): In this case, α = 0.05.

Now, The test statistic for a two-sample t-test is given by:

  t = (sample mean 1 - sample mean 2) / √((s1² / n1) + (s2² / n2))

  where s1 and s2 are the sample standard deviations, and n1 and n2 are the sample sizes.

Here X₁ = 10, X₂ = 14, s= 3, n₁ =12, n₂ = 18

So, t= (10-14) / √(3²/12) + (3²/18) et:

t= (-4)/ √(3/4 + 1/2)

t= -4 / (5/4)

t= -2.7931

Now, degrees of freedom (df):

= (9/12 + 9/18)² / (((9/12)² / 11) + ((9/18)² / 17))

= 25.164

So, the p value will be 0.0208.

As, p-value is less than α (0.0208 < 0.05), we reject the null hypothesis.

Since the p-value (0.0208) is less than the significance level (0.05), we reject the null hypothesis. This indicates that there is sufficient evidence to suggest the case.

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For a given confidence interval and significance level, and assuming a relatively small sample size, say 25, the relationship between a T critical value and a Z critical value can be best expressed as: a T-Value > Z-Value a True O False

Answers

T-value is not always greater than Z-value. Therefore, the statement is false

False. The relationship between a T critical value and a Z critical value is not that a T value is always greater than a Z value. The choice between using a T critical value or a Z critical value depends on the specific context and assumptions of the statistical analysis.

In general, when the sample size is small (typically below 30) and the population standard deviation is unknown, a T critical value is used. The T distribution accounts for the additional uncertainty introduced by the smaller sample size, resulting in wider confidence intervals and more conservative hypothesis tests compared to the Z distribution.

On the other hand, when the sample size is large (typically above 30) or the population standard deviation is known, a Z critical value is used. The Z distribution assumes a large sample size, and it is based on the known population standard deviation or the approximation of the sample standard deviation to the population standard deviation.

Therefore, it is incorrect to state that a T-value is always greater than a Z-value. The choice between T and Z critical values depends on the specific conditions and assumptions of the statistical analysis being performed.

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The results of an empirical study reveal the following: n=27, sample mean = 3,000, sample standard deviation = 900. The 90% confidence interval of the true population mean is closet to: = = 2,400 and 3,400 1,200 and 4,800 2,700 and 3,300 0 2,000 and 4,000.

Answers

The 90% confidence interval is approximately 2,400 and 3,400.

The 90% confidence interval of the true population mean can be calculated using the formula: sample mean ± (critical value * standard error). Since the sample size is small (n=27), we need to use the t-distribution and its corresponding critical value. For a 90% confidence level with 26 degrees of freedom (n-1), the critical value is approximately 1.706.

Using the given values, the standard error is calculated as the sample standard deviation divided by the square root of the sample size: 900 / sqrt(27) ≈ 171.97.

Substituting the values into the formula, the 90% confidence interval is approximately 3,000 ± (1.706 * 171.97), which yields a range of approximately 2,424.5 to 3,575.5.

Therefore, the closest option to the 90% confidence interval is 2,400 and 3,400.

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How many pints is 80 cups

Answers

Answer:

40

Step-by-step explanation:

2 cups = 1 pt

therefore

1/2 is the equation

...

80/2 = 40

Can someone help out? No BS please. ​

Answers

Answer:

Angle EHG

Step-by-step explanation:

If you want explanation tell me in comments

Answer:

the correct answer is angle EHB

Determine whether the following equation is separable. If so, solve the given initial value problem. dy/dt = 2ty +1, y(0) = -3 Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. The equation is separable. The solution to the initial value problem is y(t) = ___ B. The equation is not separable. 9.3.28

Answers

The equation is separable. The solution to the initial value problem is y(t) = y(0) = -3.

A. The equation is separable. The solution to the initial value problem is y(t) = ___

To determine whether the given differential equation is separable, we need to check if it can be written in the form dy/dt = g(t) * h(y), where g(t) is a function of t only and h(y) is a function of y only.

In this case, the equation is dy/dt = 2ty + 1. We can rearrange it as:

dy = (2ty + 1) dt

Now, we can see that we have both y and t terms on the right-hand side, indicating that the equation is not yet separable.

Therefore, the correct choice is B. The equation is not separable.

Unfortunately, no solution can be provided for the initial value problem y(0) = -3 since the equation is not separable.

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Find the absolute maximum and absolute minimum of the function z = f(x, y) = 3x² – 12x + 3y2 – 12y on the domain D: x2 + y2 < 4. (Use symbolic notation and fractions where needed.)

Answers

The absolute maximum and minimum of the function z = f(x, y) = 3x² - 12x + 3y² - 12y on the domain x² + y² < 4 are not provided.

To find the absolute maximum and minimum of the function z = f(x, y) = 3x² - 12x + 3y² - 12y on the domain D: x² + y² < 4, we need to locate the critical points and examine the boundaries of the domain.

First, we find the critical points by taking the partial derivatives with respect to x and y, setting them equal to zero, and solving for x and y. However, in this case, the given function is a quadratic expression without any cross-terms, so it does not have critical points.Next, we consider the boundary of the domain D: x² + y² = 4, which represents a circle of radius 2 centered at the origin. To find the extreme values on this boundary, we can use methods like Lagrange multipliers or parametrize the boundary and evaluate the function.

Since the absolute maximum and minimum values are not provided, further calculations are needed to determine these values for the given function on the given domain.

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