To find the selling price after applying a discount of 12% to goods bought for $1200, we can follow these steps:
Step 1: Calculate the discount amount.
Discount Amount = 12% of $1200
Discount Amount = 0.12 * $1200
Discount Amount = $144
Step 2: Subtract the discount amount from the original price to get the selling price.
Selling Price = Original Price - Discount Amount
Selling Price = $1200 - $144
Selling Price = $1056
So, the selling price after applying a discount of 12% to goods bought for $1200 is $1056.
: A quadratic function is given. f(x) = x2 + 2x - 6 (a) Express the quadratic function in standard form f(x) = (b) Sketch its graph. (c) Find its maximum or minimum value. f(x) = maximum value minimum value
For the quadratic function,
(a) Standard form: f(x) = (x + 1)^2 - 7
(b) Its graph will be a parabola opening upward
(c) Minimum value: f(x) = -7
(a) To express the quadratic function f(x) = x^2 + 2x - 6 in standard form, we complete the square.
f(x) = (x^2 + 2x) - 6
To complete the square, take half of the linear coefficient (2) and square it: (2/2)^2 = 1.
Now, add and subtract this value inside the parentheses:
f(x) = (x^2 + 2x + 1 - 1) - 6
f(x) = (x + 1)^2 - 7
So, the standard form is f(x) = (x + 1)^2 - 7.
(b) Since the leading coefficient (1) is positive, the graph of this quadratic function opens upward. The vertex is at the point (-1, -7), which is the minimum point. To sketch the graph, plot the vertex and draw a parabola opening upward.
(c) The minimum value of the function is the y-coordinate of the vertex: f(x) = -7.
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Calculate the following probabilities. We do NOT know the degrees of freedom. 1) Find
P(T>t 0.2
(df))
. 2) Find
P(T
(df))
. 3) Find
P(−t 0.1
(df)
(df))
. 4) Find
P(T<−t 0.21
(df))
.
The probabilities to be calculated are as follows:
a. P(T > t 0.2(df))
b. P(T(df))
c. P(-t 0.1(df)(df))
d. P(T < -t 0.21(df))
a. To calculate P(T > t 0.2(df)), we need to find the probability that a Student's t-distribution with an unknown degrees of freedom (df) exceeds the value of t 0.2. Since the degrees of freedom are unknown, we cannot determine the exact value of this probability without knowing the specific distribution being referred to.
b. To calculate P(T(df)), we need to find the probability that a Student's t-distribution with an unknown degrees of freedom (df) falls within the range of values from negative infinity to positive infinity. Since this range covers the entire distribution, the probability is equal to 1.
c. To calculate P(-t 0.1(df)(df)), we need to find the probability that a Student's t-distribution with an unknown degrees of freedom (df) is less than or equal to the negative value of t 0.1. Again, since the degrees of freedom are unknown, we cannot determine the exact value of this probability without knowing the specific distribution being referred to.
d. To calculate P(T < -t 0.21(df)), we need to find the probability that a Student's t-distribution with an unknown degrees of freedom (df) is less than the value of -t 0.21. As mentioned before, without knowing the degrees of freedom, we cannot determine the exact value of this probability.
Therefore, the probabilities cannot be calculated without knowing the specific degrees of freedom and the distribution being referred to..
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etermine if the following matrix is invertible. explain why. [1 2 0]
[3 4 0]
[5 6 0]
In this case, the third column of matrix A is a linear combination of the first two columns, which makes the matrix singular and not invertible.
What is matrix?A matrix is a rectangular array of numbers or other mathematical objects, such as polynomials or functions, arranged in rows and columns.
Matrices are used to represent linear transformations, systems of linear equations, and other mathematical structures and operations.
To determine if a matrix is invertible or not, we need to calculate its determinant.
The given matrix is:
A = [1 2 0; 3 4 0; 5 6 0]
The determinant of 3x3 matrix is given by -
determinant(A) = a11(a22a33 - a23a32) - a12(a21a33 - a23a31) + a13(a21a32 - a22a31)
where aij is the element in i th row and j th column of the matrix.
By substituting the values from matrix A-
det(A) = 1(40 - 06) - 2(30 - 05) + 0(36 - 45)
det(A) = 0
Since the determinant of A is equal to zero, we can conclude that the matrix A is not invertible.
The matrix can be invertible if and only if its determinant is nonzero. When the determinant is zero, the matrix is said to be singular, which means that its rows or columns are linearly dependent, and it cannot be inverted.
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which of the following expressions is equivalent to 3^x+2
Answer: Option D 9(3)^x
Step-by-step explanation:
3^x+2 = 9(3)^x
9= 3^2
whenever there are same 2 numbers in multiplication, there powers are added.
Therefore, 3^2(3^x) = 3^(x+2)
Mr. Chan pays $8 to fill a 2-gallon can with gas for his lawn mower. At this rate, how
much will Mr. Chan pay to put 13 gallons of gas in his car?
A. $104.00
B. $52.00
C. $26.00
D. $3.25
Answer: b. $52.00
Step-by-step explanation:
find an equation of a parabola that has curvature 4 at the origin. (assume the parabola has its vertex at the origin, and opens upward.) y(x) =
The equation of the parabola that has curvature 4 at the origin and opens upward is:
y(x) = 2x^2
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Find the theoretical probability of the event occurring on a single roll of a number cube. P(multiple of 3) = A) 0
B) 1/3
C) 1/2
D) 2/3
Answer:
B) 1/3.
Step-by-step explanation:
There are six possible outcomes when rolling a number cube, and two of them are multiples of 3 (3 and 6). Therefore, the theoretical probability of rolling a multiple of 3 on a single roll of a number cube is 2/6, which simplifies to 1/3.
Therefore, the answer is B) 1/3.
The spacing between lines in the pure rotational spectrum of 7Li^35 Cl is 4.236 x 1040 s-1. The atomic masses for Li and 35Cl are 7.0160 amu and 34.9688 amu, respectively.
Part A Calculate the bond length of this molecule. Express your answer to four significant figures and include the appropriate units. ? ro =
Significant figures and include the appropriate units is [tex]r = 1.166 \times 10^{(-10)}[/tex]
Calculate the bond length of this molecule?Count up all of the bonds. Determine how many bond groups there are between individual atoms. By the total number of bonding groups in the molecule, divide the number of bonds between atoms. X-Ray crystallography is the only reliable method of determining molecule size. This gives you the crystal structure, including the positions of every atom, and you consequently know the size of the molecule. Any substance that can be crystallised can be used in this procedure, even huge molecules like protein and DNA.
spacing between lines [tex]=4.236*10^{10} s^{(-1)}[/tex]
atomic mass of Li = 7.0160 amu
atomic mass of cl = 34.9688
Bond length of molecule
B = h*c*B
[tex]6.626*10^{(-34)} J*S*3*10^{(10)} cm/s*2.118*10^{(10)} 1/cm[/tex]
[tex]B=42.06 \times 10^{(-24)}J[/tex]
Now according to relation
[tex]B=\frac{h^2}{8\pi^2 I}[/tex]
where I is moment of inertia
[tex]I=\frac{h^2}{8\pi^2 B}[/tex]
[tex]=(6.62*10^{(-34)})^2(JS)^2/8*(3.14)^2*(42.06*10^{(-24)})\\\\= 13.20*10^{(-47)}[/tex]
Calculate,
[tex]K=\frac{7.0160*34.968}{7.0160+34.9688} /\frac{10^{(-3)}kg/mol}{6.022*10^{(23)} mol^{(-1)}}[/tex]
[tex]= 0.970*10^{(-26)}kg[/tex]
[tex]I = \mu r^2 \\\\I=\sqrt{\frac{I}{\mu} }[/tex]
[tex]I=\sqrt{\frac{13.20\times 10^{-47 kg\ mx^2}}{0.970\times 10^{-26}kg} }[/tex]
[tex]r=1.166\times 10^{(-10)}[/tex]
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how many different eight-card hands are there with no more than three red cards?
There are 56,750,808 different eight-card hands with no more than three red cards. This can be answered by the concept of combination formula.
To solve this problem, we first need to determine the total number of eight-card hands, which is given by the combination formula:
C(52,8) = 52! / (8! × 44!) = 74, 957, 440
This represents the total number of ways to choose eight cards from a deck of 52 cards.
Next, we need to calculate the number of eight-card hands with more than three red cards. We can do this by breaking it down into cases:
Case 1: Four red cards
We need to choose four red cards from the 26 available, and four non-red cards from the remaining 26:
C(26,4) × C(26,4) = 14,950,976
Case 2: Five red cards
We need to choose five red cards from the 26 available, and three non-red cards from the remaining 26:
C(26,5) × C(26,3) = 2,786,040
Case 3: Six red cards
We need to choose six red cards from the 26 available, and two non-red cards from the remaining 26:
C(26,6) × C(26,2) = 230,230
Case 4: Seven red cards
We need to choose seven red cards from the 26 available, and one non-red card from the remaining 26:
C(26,7) × C(26,1) = 9,156
Case 5: Eight red cards
We need to choose eight red cards from the 26 available:
C(26,8) = 230,230
To get the total number of eight-card hands with more than three red cards, we simply add up the results of these five cases:
14,950,976 + 2,786,040 + 230,230 + 9,156 + 230,230 = 18,206,632
Finally, to get the number of eight-card hands with no more than three red cards, we subtract the result of the above calculation from the total number of eight-card hands:
74, 957, 440 - 18,206,632 = 56,750,808
Therefore, there are 56,750,808 different eight-card hands with no more than three red cards.
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If 5 wholes are divided into pieces that are each 1 4 4 1 start fraction, 1, divided by, 4, end fraction of a whole, how many pieces are there?
If 5 wholes are divided into pieces that are each [tex]$\frac{1}{4}$[/tex] start fraction, 1, divided by, 4, end fraction of a whole, there are 20 pieces.
What is fraction?In mathematics, a fraction represents a part of a whole or a collection of equal parts. It is a way of representing a number as a ratio of two integers, where the top number is called the numerator and the bottom number is called the denominator.
According to given information:If 5 wholes are divided into pieces that are each [tex]$\frac{1}{4}$[/tex] of a whole, we can find the total number of pieces by multiplying the number of pieces in one whole by the number of wholes:
Number of pieces in one whole=
[tex]$\frac{1}{\frac{1}{4}} = 4$[/tex]
Number of pieces in 5 wholes = 5 x 4 = 20
Therefore, there are 20 pieces.
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How can we reduce bias in an estimator: OA. use nonrandom sampling. B. use random sampling. C. increase the number of items included in the sample. D. decrease the number of items included in the sample.
To reduce bias in an estimator, (B) use random sampling and (C) increase the number of items included in the sample. Random sampling ensures that each member of the population has an equal chance of being selected, while increasing the sample size reduces sampling error and increases the representativeness of the sample.
To reduce bias in an estimator, it is important to use random sampling rather than nonrandom sampling. Random sampling ensures that every item in the population has an equal chance of being included in the sample, which helps to eliminate any potential bias. Additionally, increasing the number of items included in the sample can also help to reduce bias by providing a more representative sample. However, decreasing the number of items included in the sample can actually increase bias as it may not accurately represent the population. Therefore, it is important to use random sampling and include a sufficient number of items in the sample to reduce bias in an estimator.
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Report the correlation between gestation and longevity and comment on the strength and direction of the relationship. Interpret your findings in context. Now return to the scatterplot that you created earlier. Notice that there is an outlier in both longevity (40 years) and gestation (645 days). Note: This outlier corresponds to the longevity and gestation period of the elephant.
What do you think will happen to the correlation if we remove this outlier?
The correlation between gestation and longevity is positive and strong.
This means that as gestation increases, longevity also tends to increase. The outlier (elephant) with 645 days of gestation and 40 years of longevity may affect the correlation.
If we remove the outlier, the correlation between gestation and longevity is likely to weaken.
The outlier (elephant) has extreme values for both gestation and longevity, and removing it would lead to a more balanced distribution of data points.
This might result in a weaker but still positive correlation, suggesting that the relationship between gestation and longevity is not as strong as initially observed. In conclusion, the outlier plays a significant role in the observed correlation, and removing it would affect the strength of the relationship.
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Of the marbles in a bag, 2 are blue, 5 are yellow, and 2 are white. Sandra will randomly choose one marble from the bag.
Answer: The probability of Sandra choosing a blue marble is 2/9, the probability of choosing a yellow marble is 5/9, and the probability of choosing a white marble is 2/9.
Step-by-step explanation:
There are a total of 2 + 5 + 2 = 9 marbles in the bag.
The probability of Sandra choosing a blue marble is 2/9 because there are 2 blue marbles out of 9 total marbles.
The probability of Sandra choosing a yellow marble is 5/9 because there are 5 yellow marbles out of 9 total marbles.
The probability of Sandra choosing a white marble is 2/9 because there are 2 white marbles out of 9 total marbles.
The sum of these probabilities is equal to 1, as Sandra must choose one marble and it must be one of the available options:
2/9 + 5/9 + 2/9 = 9/9 = 1
Find the volume of the rectangular prism.
Answer: .75 or 3/4
Step-by-step explanation:
Answer:30/40
Step-by-step explanation:
to answer this question, we need to calculate 5/8x3/5x2
5/8 x 3/5 is just both top and bottom of each multiplied, 5 x 3 which is 15 and 8 x 5 which is 40, so 15/40 x 2/1 = 30/40
also try figure it out on your own.
he solution of a vibrating spring problem is x = 5 cos t-12 sin t. The amplitude is Select the correct answer. a) 17 b) -7 c) 7 d) 13 e) 60.
If The solution of the vibrating spring problem is given by x = 5 cos t - 12 sin t, then the amplitude is 13. The correct answer is (d) 13.
Explanation:
To find the amplitude, follow these steps:
Step 1: The solution of the vibrating spring problem is given by x = 5 cos t - 12 sin t.
Step 2: The amplitude of the vibrating spring can be found by taking the square root of the sum of the squares of the coefficients of the sine and cosine terms. The solution of the vibrating spring problem is given by x = 5 cos t - 12 sin t.
Step 3: To find the amplitude, you can use the formula A = √(a^2 + b^2), where a and b are the coefficients of the cosine and sine terms respectively.
Step 4: The coefficient of the cosine term is 5 and the coefficient of the sine term is -12. In this case, a = 5 and b = -12.
So the amplitude is:
A = √((5)^2 + (-12)^2) = √(25 + 144) = √169 = 13
The amplitude is 13. The correct answer is (d) 13.
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Hw 17.1 (NEED HELPPP PLS)
Triangle proportionality, theorem
Answer:
KL = 5 1/3
Step-by-step explanation:
Let x = KL.
[tex] \frac{10}{8 + x} = \frac{4}{x} [/tex]
[tex]10x = 4(8 + x)[/tex]
[tex]10x = 32 + 4x[/tex]
[tex]6x = 32[/tex]
[tex]x = \frac{16}{3} = 5 \frac{1}{3} [/tex]
Answer:
KL = 5 1/3
Step-by-step explanation:
Let x = KL.
[tex] \frac{10}{8 + x} = \frac{4}{x} [/tex]
[tex]10x = 4(8 + x)[/tex]
[tex]10x = 32 + 4x[/tex]
[tex]6x = 32[/tex]
[tex]x = \frac{16}{3} = 5 \frac{1}{3} [/tex]
for y=ln(x7 3x−9), to find y′ would require the chain rule. if y=f(g(x)), find an f(x) and g(x) that would allow you to use the chain rule
y' = (2x - 5)/(x^2 - 5x + 2)
Using the chain rule in this way allows us to differentiate more complicated functions by breaking them down into simpler functions and applying the chain rule appropriately.
In order to use the chain rule, we need to have a function of the form y=f(g(x)), where g(x) is the inner function and f(x) is the outer function.
One possible choice of f(x) and g(x) that would allow us to use the chain rule is:
g(x) = x^2 - 5x + 2
f(u) = ln(u)
Then, we can write:
y = f(g(x)) = ln(x^2 - 5x + 2)
To find y', we need to apply the chain rule:
y' = f'(g(x)) * g'(x) = 1/(x^2 - 5x + 2) * (2x - 5)
Therefore,
y' = (2x - 5)/(x^2 - 5x + 2)
Using the chain rule in this way allows us to differentiate more complicated functions by breaking them down into simpler functions and applying the chain rule appropriately.
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Explain the steps to measuring an angle using a protractor. How do you determine an angle’s measurement in degrees?
An angle is formed between two rays that are joined together at a single point ( vertex). Protractor helps to determine the measure of angle in degrees but with following the some steps of measurement.
An angle is a geometric shape formed when two rays meet at a point. A protractor is a measuring device, usually made of plastic or glass, used to measure angles. Some protractors are simple half disks or full circles. This is a protractor that helps you measure angles in degrees. Method of measuring an angle with the protractor:
Place the center of the protractor at the vertex of the angle.Fix the protractor with one arm of the angle at the base of the protractor (don't move the vertex).Look at the balance where the base arm is pointing at 0 degrees.Symbols in degrees from 0 to 180 degrees. It can be used directly to measure any angle from 0 to 360 degrees. Read the scale at the angle where the other arm passes the scale.So, using the above steps we can determine an angle’s measurement in degrees. For example if you wants to measure angle ∠ABC. Then follow the above steps and place the protactor like in figure 2. After right placement, we can easily measure the angle. Hence, the measure of angle
∠ABC is 40°.
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For what values of a and c is the piecewise function f(x) = {ax^2 + sin x, x lessthanorequalto pi 2x - c, x > pi differentiable? A = 3 pi/2 and c = pi/2 a = 3/2 pi and c = 7 pi/2 a = 3/2 pi and c = - pi/2 a = 3/2 pi and c = pi/2 a = 3 pi/2 and c = 2/pi
The values of a and c for which f(x) = {ax^2 + sin x, x ≤ π; 2x - c, x > π} is differentiable at x = π are a = 3π/2 and c = 2/π.
For the piecewise function f(x) to be differentiable at the point x = pi, the left-hand limit and right-hand limit of the derivative of f(x) must be equal. Therefore, we need to find the derivative of f(x) separately for x ≤ π and x > π and then evaluate the limits of these derivatives at x = π.
For x ≤ π:
f'(x) = 2ax + cos(x)
For x > π:
f'(x) = 2
To ensure that f(x) is differentiable at x = π, we need the left-hand and right-hand limits of f'(x) to be equal:
lim f'(x) = lim (2ax + cos(x)) = 2a - 1
x → π- x → π+
lim f'(x) = lim 2 = 2
x → π+ x → π+
Therefore, we need to have 2a - 1 = 2, which gives a = 3/2.
Now we need to check which of the given values of c satisfies the condition that f(x) is differentiable at x = π.
a) a = 3π/2 and c = π/2:
For x ≤ π:
f'(x) = 3πx + cos(x)
For x > π:
f'(x) = 2
Therefore, f(x) is not differentiable at x = π because the left-hand and right-hand limits of f'(x) are not equal.
b) a = 3/2π and c = 7π/2:
For x ≤ π:
f'(x) = (3/2π)x + cos(x)
For x > π:
f'(x) = 2 - 3c/2π = -7/2
Therefore, f(x) is not differentiable at x = π because the left-hand and right-hand limits of f'(x) are not equal.
c) a = 3/2π and c = -π/2:
For x ≤ π:
f'(x) = (3/2π)x + cos(x)
For x > π:
f'(x) = 2 - 3c/2π = 5/2
Therefore, f(x) is not differentiable at x = π because the left-hand and right-hand limits of f'(x) are not equal.
d) a = 3/2π and c = π/2:
For x ≤ π:
f'(x) = (3/2π)x + cos(x)
For x > π:
f'(x) = 2 - 3c/2π = -1/2
Therefore, f(x) is not differentiable at x = π because the left-hand and right-hand limits of f'(x) are not equal.
e) a = 3π/2 and c = 2/π:
For x ≤ π:
f'(x) = 3πx + cos(x)
For x > π:
f'(x) = 2 - 3c/2π = -1/π
Therefore, f(x) is differentiable at x = π because the left-hand and right-hand limits of f'(x) are equal.
Therefore, the values of a and c for which f(x) = {ax^2 + sin x, x ≤ π; 2x - c, x > π} is differentiable at x = π are a = 3π/2 and c = 2/π.
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by using the definition of conditional probability, show that p(abc) = p(a)p(b|a)p(c|ab).
The definition of conditional probability states that for events A and B, the conditional probability of B given A is:
p(B|A) = p(A and B) / p(A)
Using this definition, we can write:
p(a) = p(a)
p(b|a) = p(a and b) / p(a)
p(c|ab) = p(a, b, and c) / p(a and b)
Multiplying these three equations together, we get:
p(a) * p(a and b) / p(a) * p(a, b, and c) / p(a and b) = p(abc)
Simplifying this expression by canceling out the p(a) and p(a and b) terms, we get:
p(abc) = p(a) * p(b|a) * p(c|ab)
Therefore, we have shown that p(abc) = p(a) * p(b|a) * p(c|ab) using the definition of conditional probability.
Conditional probability is the probability of an event occurring given that another event has already occurred. It is written as P(A|B) and is read as "the probability of A given B". The formula for conditional probability is:
P(A|B) = P(A and B) / P(B)
This formula represents the probability of event A occurring, given that event B has already occurred. It is calculated by dividing the probability of both A and B occurring by the probability of event B occurring.
Conditional probability is an important concept in probability theory and has many applications in various fields, such as statistics, machine learning, and data science. It allows us to make predictions and make informed decisions based on the information we have.
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How much will a customer pay for an article marked at $360, if sales tax of 20% is charged?
Step-by-step explanation:
They will pay $ 360 PLUS 20% of 360 (20% is .20 in decimal)
$ 360 ( 1 + .20)
$ 360 ( 1.20) = $ 432
a. Convert the following number to binary without using hexadecimal on the way. i. 312
b. Convert the following number to binary using hexadecimal on the way. i. 773
c. Convert the following two complements value to decimal: i. 1111 0011
d. Convert the following decimal number to two complements binary numbers using 16 bits: i. -985
e. Convert the following packed decimal into their decimal equivalents: i. 0011 0111 1001 0110
f. Convert the following decimal number into their packed decimal binary equivalents: i. 1024
a) 312b in binary is 0011 0000 0001 0010 1011.
b) 773 in binary is 0011 0000 0000 0101.
c) The two's complement value 1111 0011 is equivalent to -13 in decimal.
d) -985 in 16-bit two's complement binary format is 1111 1111 1100 0011.
e) The packed decimal 0011 0111 1001 0110 is equivalent to the decimal value 3936.
f) The decimal number 1024 in packed decimal binary format is 0001 0000 0010 0100.
How to convert 312b to binary without using hexadecimal on the waya.To convert 312b to binary without using hexadecimal on the way, we can convert each digit to its binary representation and concatenate them together.
3 in binary is 0011
1 in binary is 0001
2 in binary is 0010
b in binary is 1011
Concatenating them together, we get:
0011 0000 0001 0010 1011
Therefore, 312b in binary is 0011 0000 0001 0010 1011.
b.To convert 773 to binary using hexadecimal on the way, we first need to convert 773 to its hexadecimal representation:
773 in hexadecimal is 0x305.
Then we can convert each hexadecimal digit to its binary representation:
0 in binary is 0000
x in binary is (not applicable)
3 in binary is 0011
0 in binary is 0000
5 in binary is 0101
Concatenating them together, we get:
0011 0000 0000 0101
Therefore, 773 in binary is 0011 0000 0000 0101.
c.To convert the two's complement value 1111 0011 to decimal, we first need to determine whether the value represents a negative number. We can do this by looking at the leftmost bit, which is 1 in this case. This means that the value is negative.
To convert from two's complement to decimal for a negative number, we need to perform the following steps:
Invert all the bits (i.e., change 1s to 0s and 0s to 1s).
Add 1 to the result of step 1.
Add a negative sign to the final result.
Inverting all the bits of 1111 0011, we get:
0000 1100
Adding 1 to this result, we get:
0000 1101
Finally, adding a negative sign to the decimal value of 0000 1101, we get:
-13
Therefore, the two's complement value 1111 0011 is equivalent to -13 in decimal.
d.To convert the decimal value -985 to a 16-bit two's complement binary number, we can follow these steps:
Convert the absolute value of the decimal number to binary.
If the decimal number is negative, invert all the bits of the binary number from step 1.
Add 1 to the result of step 2 if the decimal number is negative.
Pad the binary number with leading 0s to make it 16 bits long.
Converting the absolute value of -985 to binary, we get:
0000 0011 1100 1001
Since the decimal number is negative, we need to invert all the bits:
1111 1100 0011 0110
Then we add 1 to the result:
1111 1100 0011 0111
Finally, we pad the binary number with leading 0s to make it 16 bits long:
1111 1111 1100 0011
Therefore, -985 in 16-bit two's complement binary format is 1111 1111 1100 0011.
e.To convert the packed decimal 0011 0111 1001 0110 into its decimal equivalent, we can separate each nibble (4 bits) and convert them to their corresponding decimal values:
0 in decimal is 0
0 in decimal is 0
1 in decimal is 1
1 in decimal is 1
0 in decimal is
3 in decimal is 3
7 in decimal is 7
9 in decimal is 9
6 in decimal is 6
Then we concatenate the decimal values together, in the same order:
0011 0111 1001 0110 in decimal is 0111 3936
Therefore, the packed decimal 0011 0111 1001 0110 is equivalent to the decimal value 3936.
f.To convert the decimal number 1024 into its packed decimal binary equivalent, we can separate each decimal digit and convert it to its corresponding binary value. Since each decimal digit is represented by one nibble (4 bits), we will need four bits for each digit:
1 in binary is 0001
0 in binary is 0000
2 in binary is 0010
4 in binary is 0100
Concatenating them together, we get:
0001 0000 0010 0100
Therefore, the decimal number 1024 in packed decimal binary format is 0001 0000 0010 0100.
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What mixed number would be plotted where the arrow is pointing on the number line?
Number line with plotted numbers 0, 1, 2, 3, 4, and 5. Between each whole number, it is partitioned into fourths. There is a red arrow pointing to the tick mark one hop to the right of the number 2
The number line with plotted numbers 0, 1, 2, 3, 4, and 5 is present in above figure. The mixed number would be plotted where the arrow is pointing on the number line is equals to the [tex]2\frac{ 1}{4} [/tex].
A fraction, often called a fraction, is a combination of a number (integer) and a fraction (part of a whole number). So it has two parts. [tex]4 \frac{1}{7} [/tex] is an example of a mixed number. A number line is a horizontal line in which numbers are evenly distributed. It is used to pictorial representation of numbers. We have numbers for plotting on number line and conditions for plotting are
0, 1, 2, 3, 4, and 5 on number line Between each whole number, it is partitioned into fourths.There is a red arrow pointing to the tick mark on top to the right of the number 2.Now, the plotted number line is present in above figure. See the figure carefully. From the figure the mixed number that would plotted on red mark is [tex]2 \frac{1}{4} [/tex].
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Construct the exponential function that contains the points (0,-2) and (3,-128) Provide your answer below:
To construct the exponential function that contains the points (0,-2) and (3,-128), we can use the general form of an exponential function:
y = a * b^x
where y is the function value, x is the input value, b is the base of the exponential function, and a is a constant representing the y-intercept. To find the specific exponential function that contains the two given points, we need to solve for a and b using the given coordinates.
First, we can use the point (0,-2) to find the value of a:
-2 = a * b^0
-2 = a * 1
a = -2
Next, we can use the point (3,-128) to find the value of b:
-128 = -2 * b^3
64 = b^3
b = 4
Now that we know the values of a and b, we can write the exponential function:
y = -2 * 4^x
Therefore, the exponential function that contains the points (0,-2) and (3,-128) is y = -2 * 4^x.
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Which relation is a function?
Only table 2 is a function since it is a one to one mapping
What is a function?A function is a one-to-one mapping of an equation.
Since we have four expressions to determine if they are functions, we notice that
Expressions 1, 3 and 4 have more than one y value for the same value of x. so, they are one to many mappings and thus not functions.Also, we notice that table 2 has only one value of y for one value of x and thus one to one mappins and thus a functionSo, only table 2 is a function
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state whether the sequence an=(2n 1)2(5n−1)2 converges and, if it does, find the limit. a) converges to 1b) converges to 3/5c) divergesd) converges to 9/25e) converges to 0
The given sequence an=(2n 1)2(5n−1)2 converges or diverges with the same behavior as the sequence (4/25)^n. The option that suits the answer is option c.diverges. With the limit (4/25)
To determine if the sequence converges or diverges, we can use the limit definition of convergence.
First, we can simplify the expression inside the parentheses:
(2n + 1)^2 / (5n - 1)^2 = (4n^2 + 4n + 1) / (25n^2 - 10n + 1)
Then, we can use the fact that for two sequences {a_n} and {b_n}, if a_n / b_n converges to a non-zero constant, then {a_n} and {b_n} have the same convergence behavior.
So, let's take the limit of this new expression:
lim (n → ∞) [(4n^2 + 4n + 1) / (25n^2 - 10n + 1)]
We can use the highest degree terms in the numerator and denominator to simplify:
lim (n → ∞) [(4n^2 / 25n^2)]
This simplifies to:
lim (n → ∞) (4/25)
Since this limit is a non-zero constant, we can conclude that the sequence {an} converges or diverges with the same behavior as the sequence (4/25)^n.
Thus, the answer is (c) diverges.
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8 - 2d = c 4 + 3d = 2
Answer:
d = 3
Step-by-step explanation:
Newton's First Law - Worksheet
Focus Question: Does the speed of a car affect its stopping distance
Background Information Speed mit signs are posted on nearly every road.
Speed limits vary by location and are based on different factors, such as curvature
of the road, school rones, and how heavily populated an area is. Generally,
speed limits are higher on highways and lower in areas where people live.
Speed limits keep people safe because they keep cars from going too fast. The
faster a car is traveling, the longer it will take the car to stop. In areas where a
child might chase a ball into the road or someone may cross the street, it is important that a driver can
Pop very quickly if they are traveling over the speed limit, the driver will be much less likely to be
able to dop the car in an emergency. So, speed limits help limit driver speeds, which in turn helps
limit the time it takes to stop a moving car.
Today, you will be discovering how the speed of a car affects its stopping distance. Stopping distance
is the distance that a car continues to travel after the driver has applied the brakes.
Speed
(mph)
15
Graphing: The speeds listed in the data table below represent how fast an average car is travelling on
a straight, dry road. The Total Stopping Distance is the distance that a car would take to
come to a complete stop after a driver sees something in the road and stops the car. On
the back of this page, graph the data shown.
20
25
30
35
40
45
50
55
Total Stopping
Distance (feet)
26
40
56
74
96
119
145
174
205
SPEED
LIMIT
Speed
(mph)
60
65
70
75
80
85
90
95
100
55
239
275
314
Total Stopping
Distance (feet)
355
398
445
493
544
598
CFlying Colors Science
It can be seen that the car's stopping distance depends upon the initial speed.
Yes the speed of the car affects its stopping distance when the brakes are applied. Assume the initial velocity to be 'u' and after deaccelerating at 'a' m/s², the car stops after distance 'S'. Now, we can write that -
S = ut + 1/2 at²
We can also write -
v = u + at
t = (v - u)/a
t = - u/a {final velocity is zero}
Then, we can write that -
S = u x (-u/a) + 1/2 a(- u/a)²
S = u x (-u/a) + 1/2 x a x u²/a²
S = - u²/a + u²/2a
S = u²/a(1/2 - u)
So, it can be seen that the car's stopping distance depends upon the initial speed.
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use the given information to determine the remaining five trigonometric values. rationalize any denominators that contain radicals. (enter your answers in exact form.) csc a = 3/2, 90° < a < 180°sin A =cos A=tan A =cot A= Sec A=
Not possible since the value of sin(a) must lie between -1 and 1. Therefore, there is no solution for this problem.
We know that:
csc(a) = 3/2
Since csc(a) = 1/sin(a), we can find sin(a) as:
1/sin(a) = 3/2
Cross-multiplying, we get:
2sin(a) = 3
Dividing by 2, we get:
sin(a) = 3/2
This is not possible since the value of sin(a) must lie between -1 and 1. Therefore, there is no solution for this problem.
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NEED ALL QUESTIONS ANSWERED!!! 100 POINTS
After a dreary day of rain, the sun peeks through the clouds and a rainbow forms. You notice the rainbow is the shape of a parabola.
The equation for this parabola is y = -x2 + 36.
Graph of a parabola opening down at the vertex 0 comma 36 crossing the x–axis at negative 6 comma 0 and 6 comma 0.
In the distance, an airplane is taking off. As it ascends during take-off, it makes a slanted line that cuts through the rainbow at two points. Create a table of at least four values for the function that includes two points of intersection between the airplane and the rainbow.
Analyze the two functions. Answer the following reflection questions in complete sentences.
What is the domain and range of the rainbow? Explain what the domain and range represent. Do all of the values make sense in this situation? Why or why not?
What are the x- and y-intercepts of the rainbow? Explain what each intercept represents.
Is the linear function you created with your table positive or negative? Explain.
What are the solutions or solution to the system of equations created? Explain what it or they represent.
Create your own piecewise function with at least two functions. Explain, using complete sentences, the steps for graphing the function. Graph the function by hand or using a graphing software of your choice (remember to submit the graph).
The solution of both intersections shows where the plane intersects the rainbow.
A precise definition of function finds its roots in mathematics, wherein it is a principle that connects an item from one group (also known as the domain) to a definite element within another group (the range or codomain).
Symbolically expressed by varied means like equations, graphs, and tables. The importance of models based on functions can hardly be overstated, since they reveal links between various factors across disciplines such as physics, engineering, economics, and computer science.
Various examples of crucial functions are linear, quadratic, exponential, trigonometric, and logarithmic - all well-known amongst mathematicians worldwide.
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