Help! Look at the image below!

Answer:

35

Step-by-step explanation:

Answer:

28.1 units

Step-by-step explanation:

Area of circle= πr², where r is the radius.

Given that the area is 20π,

20π= πr²

Divide both sides by π:

20= r²

Square root both sides:

[tex]r = \sqrt{20} [/tex]

[tex]r = \sqrt{4(5)} [/tex]

[tex]r = ( \sqrt{4} )( \sqrt{5} )[/tex]

[tex]r = 2 \sqrt{5} [/tex]

Circumference of circle= 2πr

Substitute the value of r:

Circumference of the circle

[tex] = 2(\pi)( 2\sqrt{5} )[/tex]

[tex] = 4\pi \sqrt{5} [/tex]

= 28.1 units (3 s.f.)

Answer:

25x + 75 ≥ 30

Hope this helps!

Answer:

Step-by-step explanation:

17. ≈ 1.41 + 5 = 6.41

18. ≈ 1.73 × 2.24 = 3.8752

19. ≈ 3.14 × 25 = 78.5

20. ≈ 2.24 × 2.24 = 5.0176

21. ≈ 10 - 2 × 3.14 = 10 - 6.28 = 3.72

22. I’m sorry. I don’t know.

please give me a brainliest answer

Answer:

A

Step-by-step explanation:

1ft times 1ft is only 1 ft

Answer:

1ft

Step-by-step explanation:

Answer:

42 = 2*3*7

Step-by-step explanation:

42 can be rewritten as 2*21, for example.  

2 is prime.  21 = 3*7.

Then 42 = 2 * 21 is also equal to:

         42 = 2*3*7. where these factors are ordered from least to greatest.  The prime factors of 42 are {2, 3, 7}.

Answer:

[tex]p(t) = - 3t + 75 \\ p(t) = 0 \\ - 3t + 75 = 0 \\ 3t = 75 \\ t = \frac{75}{3} \rightarrow \boxed{t = 25 \: mins} \\ 3 \: papers \: per \: mins \\ domain \: \boxed{t \geqslant 0} \: \\ because \: time \: cant \: be \: negative \: on \\ \: this \: perticular \: occasion \\ \therefore \: range \: \boxed {p(t) \geqslant 0 }[/tex]

Answer:

330 day passes, 367 tournament passes

Step-by-step explanation:

The number of day passes sold is 330, while the number of tournament passes sold is 367.

A set of simultaneous equations, often known as a system of equations or an equation system, is a finite collection of equations for which common solutions are sought.

Let the number of day passes sold be represented by x, while the number of tournament passes sold is y.

Given that on the first day of a water polo tournament, the total value of tickets sold was $17,610.

y = x + 37

Also, The number of tournament passes sold was 37 more than the number of days passes sold.

20x + 30y = 17610

20x + 30(x + 37) = 17610

20x + 30(x+ 37) = 17610

20x + 30x + 1110 = 17610

50x = 16,500

x = 16,500 / 50

x = 330

y = x + 37

y = 330 + 37

y = 367

Hence, the number of day passes sold is 330, while the number of tournament passes sold is 367.

Learn more about the System of equations here:

https://brainly.com/question/12895249

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Answer:  220

Step-by-step explanation:

A- 22.50 x 12 = 270

B- 12.50 x 12 = 150

C- 270 + 150 - 200 = 220

ANSWER- 220

Answer:

74/5

Step-by-step explanation:

15x5 =75 5ths. 1/5 + 74/5 = 75/5

Answer:

one

Step-by-step explanation:

y = (x + 3)^2

Start with the parent function y = x^2.

y = x^2 touches the x-axis at only 1 point, (0, 0).

The difference between y = (x + 3)^2 and its parent function y = x^2, is that in y = (x + 3)^2, x was replaced by x + 3. That is a translation of 3 units left. The function y = (x + 3)^2 still only touches the x-axis once, but at x = -3.

Answer: one

Answer:

Step-by-step explanation:

To answer this, set the function y = (x + 3)^2 touch the x-axis (where y = 0) and find the actual value(s) of x:

y = (x + 3)^2 = 0

Taking the square root of both sides, we get x + 3 = ±0, or x = -3.  As this equation is a quadratic, there MUST be two roots; the roots are {-3, -3}.  Thus in theory, the graph touches the x-axis in two places, but these two places are identical:   (-3, 0)

Answer:

x=8. Explanation: Factor of 6561 are. 6561=3×3×3×3×3×3×3×3=38. As such, 3x=6561 can be written as 3x=38. Hence, x=8.  Step-by-step explanation:

Answer:

The value of b is 3

then B - (n4 – 3)(n4 + 3)

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

not sure if it is correct

Answer:

9

Step-by-step explanation:

Answer:

P = 5/8 or 15/24

Step-by-step explanation:

p = 18/12 - 7/8

p = 36/24 - 21/24

p = 15/24   ( Simplify )

p = 5/8

Answer:

Step-by-step explanation:

[tex]p+\dfrac{7}{8}=\dfrac{18}{12}\\\\p=\dfrac{18}{12}-\dfrac{7}{8}\\\\\\LCM \ of 8 \ and \ 12 \ is \ 24\\\\p=\dfrac{18*2}{12*2}-\dfrac{7*3}{8*3}\\\\p=\dfrac{36}{24}-\dfrac{21}{24}\\\\p=\dfrac{15}{24}[/tex]

[tex]p=\dfrac{5}{8}[/tex]

Answer:

numerator - 4

denominator - 3

Step-by-step explanation:

6 × 2/9

12/9

4/3

Answer:

6

Step-by-step explanation: You subtract 12-6

Answer:

he  spent $75.80

Step-by-step explanation:

hope this helps:D

Answer:

Sequence 1: Translate 5 units to the right, and 5 units down

Sequence 2: Reflect across the origin, translate 1 unit down, 1 unit to the right

Step-by-step explanation:

Chose 1 point to focus in, such as (-1, 1)

Move that point 5 units to the right, and 5 units down. See how it matches up with the same corner of the red square?

Now, use that same point, and change the signs of both the x and y, this is to reflect across the origin. (In reality, you are just reflecting across the x and y axis)

So you originally have: (-1,1) -> (1, -1)

Now move this point one unit to the right, and 1 unit to the left.

It may seem that you made it touch the wring corner, but do the same thing with another corner's points. They all flipped!

Answer:

the answer is c :)

Step-by-step explanation:

Answer:

35

Step-by-step explanation:

Numbers that add up to 8 and number combinations

0 and 8: 80, 08

1 and 7: 17, 71

2 and 6: 26, 62

3 and 5: 35, 53

4 and 4: 44

Since the number must be between 25 and 40, the only possible numbers are 26 and 35

Since 26 is not the answer, the number is 35

Answer:

you need 8 bins because 150/20 is 7.5 but you can't have half a bin and you need somewhere to put the other books

Answer:

= a²-b²/a²b+ab²-a²b-ab²/a²b² =√√727+=% = infinite

Step-by-step explanation:

I'm not sure if this correct but hope it helps

Answer:

1

Step-by-step explanation:

This  is the solution to your question . Hope it helps you !!

Answer: 14 cm

Step-by-step explanation:

Answer:

R=14 cm

total area= πr²

=22/7*196=616 cm²

r2= 3.5 cm

area of the small circles= 2*πr²=2*12.25*22/7=77 cm²

length of rectangle=3

breadth=1

area =lb=3 cm²

area of the small circles+area of rectangle=77+3=80 cm²

remaining area=616-80=536 cm²

Answer:

A) Akash (1.5m), Meera (1.52), Rahul (1.54m), Lakshmi (1.56m)

B) Lakshmi is the tallest, 1.56m tall

Step-by-step explanation:

Rahul- 1.54m

Akash- 1500mm

Meera- 152cm

Lakshmi- 1560mm

Let's start by converting all the measurements to meters.

Rahul is already in meters, so he can just stay the same.

1500mm = 1.5m

152cm = 1.52m

1560mm = 1.56m

So our new measurements are:

Rahul- 1.54m

Akash- 1.5m

Meera= 1.52m

Lakshmi= 1.56m

We can now make our conclusions.

A) Akash (1.5m), Meera (1.52), Rahul (1.54m), Lakshmi (1.56m)

B) Lakshmi is the tallest, 1.56m tall

Answer:

Step-by-step explanation:

Let's convert all the heights to meters:

Rahul 1.54m

Akash 1.50 m

Meera 1.52 m

Lakshmi 1.56m

Now, let's arrange their heights in ascending order (shortest to tallest):

Akash 1.50 m

Meera 1.52 m

Rahul 1.54m

Lakshmi 1.56m

a) 1500 mm, 152 cm, 1.54 m, 1560 mm

b) therefore Lakshmi is the tallest.

Answer:

sorry I don't know about it

Transformation involves changing the position of a shape.

The complete statement is:

There are _3_ more ways with the order of the triangles reversed. There is a total of _9_ ways to write a congruence statement.

From the question, we understand that:

[tex]\mathbf{\triangle DVW \cong \triangle LCY}[/tex]

This mean that, the following 6 statements can be used as the congruent statements

[tex]\mathbf{\triangle DVW \cong \triangle LCY}[/tex]

[tex]\mathbf{\triangle DWV \cong \triangle LYC}[/tex]

[tex]\mathbf{\triangle VDW \cong \triangle CLY}[/tex]

[tex]\mathbf{\triangle VWD \cong \triangle CYL}[/tex]

[tex]\mathbf{\triangle WDV \cong \triangle YLC}[/tex]

[tex]\mathbf{\triangle WVD \cong \triangle YCL}[/tex]

A triangle has 3 sides, and there are 2 triangles in the question.

The number (n) of congruence statements is:

[tex]\mathbf{n = 3^2 = 9}[/tex]

The remaining (r) number of congruent statement is:

[tex]\mathbf{r = 9 - 6 = 3}[/tex]

So, the blanks should be completed with 3 and 9

Read more about congruent triangles at:

https://brainly.com/question/12413243