Answer:
165 ml
Explanation:
We are given;
Initial volume; V_a = 55 ml
Initial molarity; M_a = 3 M
Molarity of desired solution; M_b = 0.75 M
Volume of desired solution; V_b = (55 + x) ml
Where x is the volume of water to be added.
To solve for V_b, we will use the equation ;
M_a•V_a = M_b•V_b
V_b = (M_a•V_a)/M_b
V_b = (3 × 55)/0.75
V_b = 220 mL
Thus;
(55 + x) = 220
x = 220 - 55
x = 165 mL
Answer:
gotta concert mL to L
3.0=mol/0.055( you multiply morality and liter)
0.165 mol
you divide the mole by the other given molarity
0.165/0.75= 0.22 L
0.22 *1000= 220 mL
Explanation:
How are white blood cells linked to the lymphatic system?
Answer:
The lymphatic system produces white blood cells, known as lymphocytes. There are two types of lymphocyte, T cells and B cells. They both travel through the lymphatic system. As they reach the lymph nodes, they are filtered and become activated by contact with viruses, bacteria, foreign particles, and so on in the lymph fluid.
Explanation:
A truck has a kinetic energy of 1200j and is traveling at 9 m/s what is the truck mass
Answer:
Mass of truck = 29.62 kg (Approx.)
Explanation:
Given:
Kinetic energy = 1200 J
Speed of truck = 9 m/s
Find:
Mass
Computation:
The kinetic energy of a thing is the force that has attributable to its movement in physics.
Kinetic energy = [1/2][m][v]²
1,200 = [1/2][m][9]²
1,200 = [1/2][m][81]
Mass of truck = 29.62 kg (Approx.)
Coke in a Coca Cola bottle has a volume of 500 ml and a mass of 756 grams. What is its density
Answer: 1.11 g/mL is the density
Do noble gases form bonds? Why or why not?
◕‿↼ Hey There!
Answer → Source Noble Gases have a full valence shell, which is why they rarely form bonds with other atoms.
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is the value of an investment at the end of a specific time period. A. Compound interest B. Present value O C. Simple interest OD. Future value Which of the following recognizes the time value of money? O A. NPV B. ARR OC. Net cash flows D. Payback period
The value of an investment at the end of a specific time period is the Future value.
Future value is defined as the value of an asset or investment at a specific date in the future. It is calculated based on the present value of the investment, the interest rate, and the number of time periods. It is an important concept in finance as it recognizes the time value of money.
The time value of money recognizes that money today is worth more than the same amount of money in the future because of its earning potential. In other words, a dollar today is worth more than a dollar tomorrow because you can invest it and earn interest.
Future value takes into account the effects of compounding interest, which means that interest earned on an investment is added to the principal, and interest is earned on the new total.
On the other hand, NPV, ARR, net cash flows, and payback period are other important concepts in finance, but they do not explicitly recognize the time value of money. Net Present Value (NPV) is the difference between the present value of cash inflows and the present value of cash outflows.
ARR stands for Accounting Rate of Return, which is the average annual income from an investment over its life. Net cash flows are the total amount of cash inflows minus cash outflows. The payback period is the amount of time it takes for an investment to recoup its initial cost.
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Which of the molecules are used as second messengers in signal transduction pathways? insulin adenyl cyclase CAMP calcium ions P3
The molecules used as second messengers in signal transduction pathways are cAMP (cyclic adenosine monophosphate) and calcium ions. Options C and D are correct.
Cyclic adenosine monophosphate (cAMP) and calcium ions are both important second messengers involved in signal transduction pathways. When a signaling molecule, such as a hormone or neurotransmitter, binds to a receptor on the cell surface, it initiates a cascade of intracellular events.
One of these events is the activation of enzymes, such as adenylate cyclase, which synthesizes cAMP from ATP. cAMP then acts as a second messenger by binding to and activating protein kinase A (PKA), leading to the phosphorylation of target proteins and the amplification of the signal. Calcium ions also play a crucial role as second messengers by mediating various cellular processes.
They can be released from intracellular stores or enter the cell through calcium channels, and their binding to specific proteins triggers downstream signaling events. Together, cAMP and calcium ions function as key mediators in signal transduction, transmitting and amplifying signals from the cell surface to the intracellular environment. Options C and D are correct.
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identify the type of change (physical or chemical) that occurs when an iron bar rusts and when a substance freezes. use complete sentences to justify the type of change that occurs.
For the rusting of an iron bar, a chemical change occurs; while for the freezing of a substance , a physical change occurs.
When an iron bar rusts, a chemical change occurs. Rusting is a chemical reaction that involves the oxidation of iron in the presence of oxygen and water. The iron undergoes a chemical transformation and forms a new compound, iron oxide, which gives the rusty appearance. This change is irreversible and involves a rearrangement of atoms at the molecular level.
On the other hand, when a substance freezes, a physical change takes place. Freezing is a phase transition from a liquid to a solid state. During freezing, the substance undergoes a change in its physical state without any alteration in its chemical composition. The arrangement of molecules or atoms becomes more ordered as they transition from a disordered liquid state to a more structured solid state. This change is reversible, and the substance can return to its liquid state by melting.
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What does it mean to say that scientific models are open to change? (2 points)
a
Scientific models are usually not very accurate.
b
Scientific models can be adjusted when new information is found.
c
People can adjust scientific models to fit their personal beliefs.
d
Experimental results can be changed to fit the accepted model
If 0=30° then verify that sin20=2sin0.cos0
Answer:
It is proved that sin20=2sin0.cos0
Explanation:
Given
[tex]0=30[/tex] °
[tex]sin20=2sin0.cos0[/tex]
Substituting the value of "0" on both the sides, we get -
[tex]sin2 (30) =2sin 30 * cos 30\\sin 60 = 2 * sin 30 * cos 30 \\0.866 = 2 * 0.5 * 0.866\\0.866 = 0.866[/tex]
Since LHS = RHS
we can say that [tex]sin20=2sin0.cos0[/tex]
answer 1-5 of lesson outline for brainiest
Answer:
see explanation
Explanation:
1. mid-ocean ridge
2.gravity
3.normal,reverse
4.cools
5.stripes
6.spreading
7.continents
Which is a function common to both the muscular and skeletal systems?
Answer:
please give me brainlist and follow
Explanation:
In the musculoskeletal system, the muscular and skeletal systems work together to support and move the body. The bones of the skeletal system serve to protect the body's organs, support the weight of the body, and give the body shape.
Answer:
B. bending of the arm
Explanation:
What is the pOH of a solution whose pH is 12.41?
Answer:
1.59
Explanation:
14=pOH+pH
pOH=14-12.41
pOH=1.59
what is an magnetic pole
Answer:
Earth's magnetic field, also known as the geomagnetic field, is the magnetic field that extends from the Earth's interior out into space, where it interacts with the solar wind, a stream of charged particles emanating from the Sun.
o facilitate ease of dose calculations for cefazolin injection, your department policy
states that the resulting concentration after reconstitution should be 100 mg/mL. The
packaging insert for cefazolin 1-g vial instructs you to add 3.4 mL of sterile water without
bacteriostat, resulting in a reconstituted solution of 250 mg/mL
i. What is the final volume of the reconstituted cefazolin solution?
A 3 mL
B. 4 mL
C. 5 mL
D. 2.5 mL
ii. What is the volume of the cefazolin powder?
A 0.4 mL
B. mL
C. 0.7 mL
D. 0.6 mL
iii. What is the final volume of the 100mg/mL cefazolin solution?
A. 6 mL
B. 8 mL
C. 7 mL
D. 10 mL
The final volume of the reconstituted cefazolin solution is 4 mL. The volume of the cefazolin powder is 0.6 mL. The final volume of the 100 mg/mL cefazolin solution is 10 mL.
The packaging insert instructs to add 3.4 mL of sterile water without bacteriostat to the 1-g vial of cefazolin. This results in a reconstituted solution with a concentration of 250 mg/mL.
To find the final volume, we can set up the equation:
Concentration of reconstituted solution = Amount of drug / Final volume
Using the given concentration (250 mg/mL) and the amount of drug (1 g = 1000 mg), we can rearrange the equation to find the final volume:
250 mg/mL = 1000 mg / Final volume
Solving for the final volume:
Final volume = 1000 mg / 250 mg/mL = 4 mL
Therefore, the final volume of the reconstituted cefazolin solution is 4 mL.
To find the volume of the cefazolin powder, we need to subtract the volume of sterile water added from the final volume of the reconstituted solution.
Given that 3.4 mL of sterile water is added to the vial, and the final volume of the reconstituted solution is 4 mL, we can calculate the volume of the cefazolin powder as follows:
Volume of cefazolin powder = Final volume - Volume of sterile water added
Volume of cefazolin powder = 4 mL - 3.4 mL = 0.6 mL
Therefore, the volume of the cefazolin powder is 0.6 mL.
To determine the final volume of the 100 mg/mL cefazolin solution, we can use the concentration and the amount of drug.
We are given that the resulting concentration after reconstitution should be 100 mg/mL. Considering the amount of drug is 1 g (1000 mg), we can set up the following equation:
Concentration of reconstituted solution = Amount of drug / Final volume
Using the given concentration (100 mg/mL) and the amount of drug (1000 mg), we can rearrange the equation to find the final volume:
100 mg/mL = 1000 mg / Final volume
Solving for the final volume:
Final volume = 1000 mg / 100 mg/mL
Final volume = 10 mL
Therefore, the final volume of the 100 mg/mL cefazolin solution is 10 mL.
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for a particular redox reaction, mno2 is oxidized to mno−4 and ag is reduced to ag . complete and balance the equation for this reaction in basic solution.
The given redox reaction can be represented in the following way: MnO₂ → MnO⁴⁻ + Ag → Ag+
To balance the redox reaction, the following steps are to be followed:
1: First, balance the net ionic equation with the help of half-reactions:
MnO2 → MnO⁴⁻+ e- [Oxidation Half-Reaction]
Ag+ + e- → Ag [Reduction Half-Reaction]
2: Determine the number of electrons that are required to balance the half-reactions. The oxidation half-reaction requires five electrons.
MnO₂ → MnO⁴⁻+ 5e-
The reduction half-reaction requires one electron.
Ag+ + e- → Ag
3: Find the least common multiple of the electrons required in the half-reactions, and use it to balance the equation. The least common multiple of 5 and 1 is 5. To balance the equation, multiply the oxidation half-reaction by 1 and the reduction half-reaction by 5. This will give us the following balanced equation:
5MnO₂ + 16H₂O + Ag → 5MnO⁴⁻ + 8OH- + 4Ag+
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I NEED HELP THIS IS DUE TMR!
A 124.6-g sample of copper has a volume of 14 cm. what is the density of copper?
Answer:
The density of copper is 8.9 grams per cubic centimeter.
Explanation:
There is a writing mistake in statement, correct form is written below:
A 124.6 grams sample of copper has a volume of 14 cubic centimeters. What is the density of copper?
Let suppose that mass of the copper sample is distributed uniformly in its volume, then we shall use the following definition of density ([tex]\rho[/tex]), in grams per cubic centimeter:
[tex]\rho = \frac{m}{V}[/tex] (1)
Where:
[tex]m[/tex] - Mass, in grams.
[tex]V[/tex] - Volume, in cubic centimeters.
If we know that [tex]m = 124.6\,g[/tex] and [tex]V = 14\,cm^{3}[/tex], then the density of the sample of copper is:
[tex]\rho = \frac{m}{V}[/tex]
[tex]\rho = 8.9\,\frac{g}{cm^{3}}[/tex]
The density of copper is 8.9 grams per cubic centimeter.
A rod, X has a positive charge of 8. An otherwise identical rod, Y has a negative charge of 4. The rods are touched together, and then separated.
1.When they touch, what particles move between them?
2.Did the particles move from "X" or "Y" or from "Y" to "X"?
Answer:
1. electrons
2. From "Y" to "X"
Explanation:
1. Electrons move between the rod since the electrons are the only charge carriers which are free to move.
2. The particles move from from "Y" to "X" since the electrons are the only charge carriers which are free to move. The positive charge on rod x is due to a deficit of electrons while the negative charge on rod Y is due to the excess of electrons. When the rods come together, the electrons move from "Y" to "X" since the electrons are the only charge carriers which are free to move.
Which of the following statements is not true? a. Water is polar. b. Water stabilizes temperature. c. Water is essential for life. d. Water is the most abundant atom in Earth’s atmosphere.
Answer: d. Water is the most abundant atom in Earth’s atmosphere.
Explanation:
Water percentage in the atmosphere is 0.001 percent only as it not the major reservoir or source of water. The water is available in the atmosphere in the form of water vapors. These water vapors when aggregate and their concentration becomes high they fall down as rain on earth so the rain is collected in water reservoirs like oceans, rivers, lakes, ponds, aquifers, and other sources of water, which are the components of hydrosphere on earth. So, hydrosphere is most abundant in water. Moreover, water is not an atom instead it is the molecule formed by the combination of two molecules of hydrogen and one molecule of oxygen.
Are water waves transverse or longitudinal? How do you know? Own words please. No files or links either.
Answer:
Transverse waves are known by motion being perpendicular to the waves movements. Longitudinal waves move in a direction parallel to the way the wave moves. Water waves are an example of both as they move in a clockwise motion.
Explanation:
( Sorry if it is not the best answer but I did my best by researching )
determine how many grams of kno3 would dissolve in 100g of water at 50 degrees celcuis to make a saturated solution
The amount of KNO₃ would dissolve in 100g of water at 50 degrees celcuis to make a saturated solution is 44 g.
To create a saturated solution of KNO₃ in 100g of water at 50 degrees Celsius, the following steps should be taken:
Step 1: Find out the mass of the solvent in the saturated solution.
The solvent is water in this instance. So, using the formula for the mass of a solution, we can calculate the mass of the solvent in the saturated solution as follows:
Mass of solvent = Mass of solution - Mass of solute
= 100 g - Mass of KNO₃
Step 2: Determine the amount of solute that would be dissolved in the solution to make it saturated.
The mass of KNO₃ that would dissolve in 100 g of water at 50°C to create a saturated solution is 56g/100g of water.
Step 3: Calculate the mass of KNO₃ that would dissolve in 100g of water to make a saturated solution.
Mass of KNO₃ = Solubility of KNO₃ × Mass of solvent
Mass of KNO₃ = 56 g/100 g × (100 g - Mass of KNO₃)
Now, let's solve for Mass of KNO₃;
56 = 56g(100-Mass of KNO₃)/100100 - Mass of KNO₃ = 100
Multiply both sides of the equation by 100 to obtain;
5600 - 100 Mass of KNO₃ = 100
Mass of KNO₃ = 5600/10100 - 56
= 44 g
Therefore, 44 g of KNO₃ would dissolve in 100g of water to make a saturated solution.
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What is the maximum pH an aqueous solution of 0.050 M Cu(NO3)2 can be adjusted to before a precipitate of Cu(OH)2 will form?
a. 4.2
b. 5.0
c. 7.0
d. 8.5
5.0 is the maximum pH an aqueοus sοlutiοn οf 0.050 M Cu(NO₍)₂ can be adjusted tο befοre a precipitate οf Cu(OH)₂ will fοrm
What is pH?pH, οften knοwn as acidity in chemistry, has histοrically stοοd fοr "pοtential οf hydrοgen" (οr "pοwer οf hydrοgen"). It is a scale used tο describe hοw basic οr hοw acidic an aqueοus sοlutiοn is. When cοmpared tο basic οr alkaline sοlutiοns, acidic sοlutiοns—thοse with higher hydrοgen (H+) iοn cοncentratiοns—are measured tο have lοwer pH values.
Using a cοncentratiοn cell with transference, the pοtential difference between a hydrοgen electrοde and a standard electrοde, such as the silver chlοride electrοde, is measured tο get the primary pH standard values. With the use οf a glass electrοde, a pH metre, οr a cοlοr-changing indicatοr, the pH οf aqueοus sοlutiοns can be determined.
Cu(OH)2⇔[tex]Cu^2 +2OH-[/tex]
s[tex]^2=1.0*10^{-19}[/tex]
[tex]s=3.16*10^{=9}[/tex]
[tex]{OH-}=2s=6.3*10^{10^{-19}[/tex]
[tex]{H+}=10^{-14}/OH[/tex]
[tex]{H+}=1.58*10^{-6}[/tex]
[tex]pH=-log(1.58*10^{-6}[/tex]
pH≈5
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A lake has been infected by some type of new algae that is unknown. Every single day the amount of surface area that the algae takes up doubles. Day 1 has a certain amount, day 2 it is 2x that amount. It takes 87 days for the entire lake to be overrun by this new algae. How many days does it take to cover half of the lake? Show your work and explain your thinking. In science we need to be able to justify our answers.
hint: It is not the "obvious" answer.
Answer:
It takes 86 days take to cover half of the lake
Explanation:
In the day #1, the amount of the algae is X,
In the day #2 is 2X
In the day #3 is 2*2*X = X*2²
...
In the day #n the amount of the algae is X*2^(n-1)
Assuming X = 1m³. In the day 87, the area infected was:
1m³*2^(87-1)
7.74x10²⁵m³ is the total area of the lake
the half of this amount is 3.87x10²⁵m³
The time transcurred is:
3.87x10²⁵m³ = 1m³*2^(n-1)
Multiplying for 5 in each side:
ln (3.87x10²⁵) = ln (2^(n-1))
58.9175 = n-1 * 0.6931
85 = n-1
86 = n
It takes 86 days take to cover half of the lakeWhat are some ways your local environment would be affected if there was suddenly less water available?
I'll mark brainliest!
plant life dies
Explanation:
if all water disappears then plants would dry up and die, wich would impact the food chain
Write the balanced net ionic equation for the following reaction between aqueous Pb(NO3)2 and aqueous NaI and correctly label the states. Use the solubility table to determine if a precipitate forms before writing the net ionic equation. Must show the (1) balanced chemical equation with the right states (2) the cancellation of appropriate spectator ions and the final net ionic equation.
Balanced net ionic equation will be: Pb2+(aq) + 2I-(aq) → PbI2(s)
The balanced chemical equation for the given reaction is;Pb(NO3)2(aq) + 2NaI(aq) → PbI2(s) + 2NaNO3(aq)
This equation is balanced because the number of atoms of the elements present on both sides of the equation is equal.
The states of the substances in the above equation are:
aqueous Pb(NO3)2(aq) , aqueous NaI (aq) → soluble, based on the solubility table PbI2 (s) → precipitate, based on the solubility tableaqueous NaNO3 (aq)
Cancel out the spectator ions from the above equation and the net ionic equation will be:
Pb2+(aq) + 2I-(aq) → PbI2(s)
Hence, the balanced net ionic equation for the given reaction between aqueous Pb(NO3)2 and aqueous NaI and correctly label the states are Pb2+(aq) + 2I-(aq) → PbI2(s) and the states are as follows;
Pb2+(aq) → AqueousI-(aq) → AqueousPbI2(s) → Solid
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The ionic equation for the reaction is given as follows:Pb2+ (aq) + 2NO3- (aq) + 2Na+ (aq) + 2I- (aq) → PbI2 (s) + 2Na+ (aq) + 2NO3- (aq)The net ionic equation is the same as the ionic equation, with spectator ions removed.Pb2+ (aq) + 2I- (aq) → PbI2 (s)The final balanced net ionic equation is given as follows:Pb2+ (aq) + 2I- (aq) → PbI2 (s).
The balanced net ionic equation for the following reaction between aqueous Pb(NO3)2 and aqueous NaI and correctly label the states are given below:Explanation:Aqueous lead(II) nitrate (Pb(NO3)2) and aqueous sodium iodide (NaI) are mixed to form solid lead(II) iodide (PbI2) and aqueous sodium nitrate (NaNO3).Before writing the net ionic equation, it is important to determine whether a precipitate will form. By referencing the solubility table, it is discovered that lead(II) iodide is insoluble in water, indicating that a precipitate will form when the two solutions are mixed.The balanced molecular equation for the reaction is given as follows:Pb(NO3)2 (aq) + 2NaI (aq) → PbI2 (s) + 2NaNO3 (aq)To write the ionic equation, the insoluble solid lead(II) iodide must be separated into its component ions. PbI2 is a precipitate; it will not dissociate, while NaNO3 will dissociate into its component ions. The ionic equation for the reaction is given as follows:Pb2+ (aq) + 2NO3- (aq) + 2Na+ (aq) + 2I- (aq) → PbI2 (s) + 2Na+ (aq) + 2NO3- (aq)The net ionic equation is the same as the ionic equation, with spectator ions removed.Pb2+ (aq) + 2I- (aq) → PbI2 (s)The final balanced net ionic equation is given as follows:Pb2+ (aq) + 2I- (aq) → PbI2 (s).
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what product(s) forms at the cathode in the electrolysis of an aqueous solution of k2so4?
1. Sulfur
2. H2 and OH-
3. K
4. O2 and H+
We can see here that the product(s) formed at the cathode in the electrolysis of an aqueous solution of [tex]K_{2}SO_{4}[/tex] are: 2. H2 and OH-
What is electrolysis?Electrolysis is a chemical process that involves the use of an electric current to drive a non-spontaneous chemical reaction. It is typically carried out in an electrolytic cell, which consists of two electrodes—an anode (positive electrode) and a cathode (negative electrode)—immersed in an electrolyte solution.
During electrolysis, when an electric current is passed through the electrolyte, chemical reactions occur at the electrodes.
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Can someone help with 10 a and b please
Answer:
for question a element A and B are isobars
for question b element C and D have the same atomic numbers.
Explanation:
element A and B are isobars because they have the same mass numbers but different atomic numbers. The different atomic numbers is as a result of the difference in proton number of each elements A and B. (A and B are two different elements). element C and D are isotopes of the same element because they have the same atomic numbers (same number of protons) but differ in number of neutrons resulting in the different number of mass numbers. (C and D are the same elements)explain+how+you+could+estimate+22%+of+78+to+check+if+your+answer+is+reasonable....
You can estimate the value of 22 % of 78 by finding 10 % of 78 and then adding another 10% to reach as close to 22 % as possible.
How to estimate the value ?Start by finding 10% of 78. Divide 78 by 10 to get 7.8. Since you want to estimate 22%, you can take the calculated value of 10% (7.8) and multiply it by 2 to get 15.6.
Next, compare the estimated value of 15.6 with the actual value of 22% of 78. Calculate the actual value by multiplying 78 by 0.22 (since 22% is equivalent to 0.22). The result is 17.16.
Compare the estimated value of 15.6 with the actual value of 17.16.
By comparing the estimated value of 15.6 with the actual value of 17.16, you can assess the reasonability of your estimate.
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One advantage to using nuclear power is —
it produces no air pollution
it is hard to store and dispose of the waste
the expense of constructing nuclear reactors
the threat of an accident
Answer:
it produces no air pollution
17. What is the molarity of ZnCl2 that forms when 15 grams of Zn reacts completely with CuCl, if a
final volume of 175 mL is produced?
Zn + CuCl2 → ZnCl2 + Cu
Answer:
1.31M
Explanation:
Based on the reaction, 1 mole of Zn produce 1 mole of ZnCl₂. As the reaction occurs completely, the moles of Zn added = Moles of ZnCl₂ produced. To find molarity we need the moles of ZnCl₂ and the volume of the solution in liters:
Moles Zn = Moles ZnCl₂ -Molar mass Zn: 65.38g/mol-:
15g * (1mol / 65.38g) = 0.23 moles of ZnCl₂
Volume in Liters:
175mL * (1L / 1000mL) = 0.175L
The molarity is:
0.23moles / 0.175L
1.31MHow much of a 0.250 M sucrose solution must be used to prepare 400.0 mL of a 0.0310 M solution? mL
Answer:
49.6 mL
Explanation:
is the answer, I just did it :)
49.6mL of a 0.250 M sucrose solution must be used to prepare 400.0 mL of a 0.0310 M solution.
What is Molarity?Molarity of a given solution is known as the total number of moles of solute per litre of the solution. A solution that is 1.00 molar (written 1.00 M) contains 1.00 mole of solute for every liter of solution.
Molarity = (No. of moles of solute ÷ Volume of solution in liters)
The unit of molarity is mol L⁻¹.
Molarity is temperature dependent because as temperature changes, volume of the solution also changes.
We can also use the formula-
M1V1 = M2V2
M1 = 0.25
V2 = 400mL
M2 = 0.0310
V1 = ?
V1 = M2V2/ M1
V1 = 49.6mL
Therefore, 49.6mL of a 0.250 M sucrose solution must be used to prepare 400.0 mL of a 0.0310 M solution.
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