If a 70 kg man is standing on the surface of the earth, then what is his weight on the moon

Answer:

B=8.40x10^-5 T

Explanation:

To find the magnetic field at the new current, first you need to find the distance. To do so, alter the original equation from finding the field to finding the distance.

r (distance) = 4 pi x 10^-7 / 2 pi multiplied by 10.0 / 4.20 x 10^-5

which equals 0.04762

Next, just plug the numbers back into the original equation, taking into account the requested changes.

which equals 8.40x10^-5

Also it was right on Acellus ;)

Hope this helps :)

Answer:

D. displacement

Explanation:

Vector quantities have both magnitude and direction.

Scalar quantities have only magnitude.

Answer:

buoyant force

Explanation:

just trust meeee

Answer:

C

Explanation:

Answer:

16 pigs

Explanation:

Let the horses be H.

Let the pigs be P

Let the total number of animals be x.

Given the following data;

Ratio of P to H = 2:3 = 2 + 3 = 5

Number of horses = 24

To find the number of pigs;

First of all, we would determine the total number of animals x.

From the ratio of horse, H:

3/5 * x = 24

Cross-multiplying, we have;

3x = 120

x = 120/3 = 40

Next, we find the number of pigs;

Pigs = 2/5 * 40

Pigs = 80/5 = 16 pigs

Answer:

R=V/I

R= 2

Explanation:

R = 10V/5A

R = 2ohms

Answer:

a)   w = 873 rev,  b)  θ = 97.75 rev

Explanation:

This is a rotation kinematics exercise

         w = w₀ + α t

         θ = θ₀ + w₀ t + ½ α t²

let's start by reducing the magnitudes to the SI system

         w₀ = 300 rpm (2pi rad / 1 rev) (1 min / 60s) = 31.42 rad / s

          α = 6 rad / s²

a) let's look for the angular velocity

            w = 31.42 + 6 10

             w = 91.42 rad / s

b) θ₀ = 0

             θ = 0 + 31.42 to + ½ 6 10²

             θ = 614.2 rad

As they ask for the result in rpm and revolutions, let's carry out the reduction

         w = 91.42 rad / s (1 rev / 2pi rad) (60 s / 1min)

         w = 873 rev

         θ = 614.2 rad (1 rev / 2pi rad)

         θ = 97.75 rev

Answer:

About 4,000 K and 10⁻¹⁷ atm

Explanation:

The Big Bang theory states that the Big Bang which is the origin of the universe was about 13.75 billion years ago, and the temperature a few seconds later was 10³²K

The first element began forming at about 3 minutes after the Big Bang with a temperature of 10⁹ K, the nuclei of simple elements

The nuclei of hydrogen and helium began combine with electrons at a temperature of 3,000 K to 4,000 K to form the first neutral atoms. The pressure of the universe at that stage was 10⁻¹⁷ atmospheres

hey I read it do you use there a pacific question you want me to answer or something?

Answer:

I also recently read Call of the Wild for school and it was a great book.

Explanation:

Answer:

10

Explanation:

Answer:

60J

Explanation:

Since the book's weight is 30N and weight = mass * gravity (around 10m/s²):

30 = X * 10 ===>   X = 3.

Using the potential energy formula we have Gravity * Height * Mass:

10 * 2 * 3 = 60J

Answer:

Explanation:

1 mole of gas contains 6.02x10^23 molecules. That is the Avogadro's number. To find the number of moles, you divide the number of molecules by the Avogadro's number.

The correct answer is C.

Answer:

Explanation:

ans is C. divided by Avogadro no.

Answer:

43740 N and attractive force

Explanation:

Given that,

Charge 1, q₁ = -54.0 μC

Charge 2, q₂ = +36.0 μC

The distance between charges, r = 2 cm = 0.02 m

We need to find the force between charges. The formula for the force between charges is given by :

[tex]F=k\dfrac{q_1q_2}{r^2}[/tex]

Put all the values,

[tex]F=9\times 10^9\times \dfrac{54\times 10^{-6}\times 36\times 10^{-6}}{(0.02)^2}\\\\F=43740\ N[/tex]

As the charges are opposite, the force between them is attractive. Hence, the required force is 43740 N.

Answer:

It's option 1: they have the same density.

Explanation:

(≚ᄌ≚)ℒℴѵℯ❤

Answer:

The fall in temperature of the liquid is 8.6 +/- 0.1 ⁰C

Explanation:

Given;

initial temperature of the liquid, t₁ = 76.3  +/-  0.4⁰C

final temperature of the liquid, t₂ = 67.7  +/-  0.3⁰C

The change in temperature of the liquid is calculated as;

Δt = t₂  -  t₁

Δt = (67.7 - 76.3)  +/-  (0.3 - 0.4)

Δt = (-8.6)  +/-  (-0.1)

Δt = 8.6 +/- 0.1 ⁰C

Therefore, the fall in temperature of the liquid is 8.6 +/- 0.1 ⁰C

Answer:

a) The closest object Anne can see, while wearing Bill's glasses is at approximately 22.39 cm relative to her eyes

b) The closest object Bill can see while wearing Anne's glasses is at approximately 26.38 cm relative to his eyes

Explanation:

The point where Bill has a near point = 125 cm

The point where Anne has a near point = 75.0 cm

Their vision are both corrected to the normal near point = 25.0 cm

The distance of their glasses from the eye, d = 2.0 cm

The lens formula is presented as follows;

[tex]\dfrac{1}{f} =\dfrac{1}{d_0} +\dfrac{1}{d_i}[/tex]

The required distance of the of the object from Bill's glass, [tex]d_{oB}[/tex] = 25 cm - 2.0 cm = 23.0 cm

The distance of the of the image from Bill's glass, [tex]d_{iB}[/tex] = -(125 cm - 2.0 cm) = -123 cm

Therefore, for Bill, we have;

[tex]\dfrac{1}{f_B} =\dfrac{1}{d_{0B}} +\dfrac{1}{d_{iB}}[/tex]

Plugging in the values gives;

[tex]\dfrac{1}{f_B} =\dfrac{1}{23} -\dfrac{1}{123} = \dfrac{100}{2,829}[/tex]

Therefore;

[tex]f_B[/tex] = 2,829/100 cm = 28.29 cm

The required distance of the of the object from Anne's glass, [tex]d_{oA}[/tex] = 25 cm - 2.0 cm = 23.0 cm

The distance of the of the image from Anne's glass, [tex]d_{iA}[/tex] = -(75 cm - 2 cm) = -73 cm

The focal length for Anne is therefore;

[tex]\dfrac{1}{f_A} =\dfrac{1}{d_{0A}} +\dfrac{1}{d_{iA}}[/tex]

Plugging in the values gives;

[tex]\dfrac{1}{f_A} =\dfrac{1}{23} -\dfrac{1}{73} = \dfrac{50}{1,679}[/tex]

Therefore, we have;

[tex]f_A[/tex] = 1,679/50 cm = 33.58 cm

a) When Anne wears Bill's lasses, we have;

[tex]\dfrac{1}{f_B} =\dfrac{1}{d_{0A}} +\dfrac{1}{d_{iA}}[/tex]

Therefore, we get;

[tex]\dfrac{1}{28.29} =\dfrac{1}{d_{0A}} -\dfrac{1}{73}[/tex]

[tex]\dfrac{1}{d_{0A}} = \dfrac{1}{28.29} + \dfrac{1}{73} = \dfrac{10,129}{206,517}[/tex]

[tex]d_{0A}[/tex] ≈ 20.39 cm

The distance of the closest object Anne can see, from her eye, [tex]d_{oe}[/tex] =  [tex]d_{0A}[/tex] + d

∴ [tex]d_{oe}[/tex] ≈ 20.39 cm + 2.0 cm = 22.39 cm

The distance of the closest object Anne can see, from her eye, [tex]d_{oe}[/tex] ≈ 22.39 cm

b) The closest object that can be seen when Bill wears Anne's glasses, we have;

[tex]\dfrac{1}{f_A} =\dfrac{1}{d_{0B}} +\dfrac{1}{d_{iB}}[/tex]

Therefore;

[tex]\dfrac{1}{33.58} =\dfrac{1}{d_{0B}} -\dfrac{1}{123}[/tex]

[tex]\dfrac{1}{d_{0B}} = \dfrac{1}{33.58} +\dfrac{1}{123} = \dfrac{7,829}{206,517}[/tex]

∴ [tex]d_{oB}[/tex] ≈ 26.38 cm

The closest object Bill can see while wearing Anne's glasses,  [tex]d_{oB}[/tex] ≈ 26.38 cm.

Answer:

If the tunnel is straight, it will have 2 hours to pass through it

Explanation:

Train speed distance time

1km/hr. 1km. 1hr. 1km/hr. 2km. 2hr

Answer:

b) resistance

Explanation:

since resistance is responsible for heating, if it increases the circuit breaker opens breaking the flow of current to the circuit and thus preventing short circuits.

Answer:

An orbit is a regular, repeating path that one object in space takes around another one. An object in an orbit is called a satellite. A satellite can be natural, like Earth or the moon. ...Planets, comets, asteroids and other objects in the solar system orbit the sun

Explanation:

Answer:

The emf amplitude in the secondary coil is 26.53 V

Explanation:

Given that,

The number of turns of the primary coil of a transformer = 441

The number of turns of the secondary coil of a transformer = 1000

The emf in the primary is of amplitude 11.7 V

We need to find the emf amplitude in the secondary. We know that,

[tex]\dfrac{E_1}{N_1}=\dfrac{E_2}{N_2}\\\\E_2=\dfrac{E_1N_2}{N_1}[/tex]

Put all the values,

[tex]E_2=\dfrac{11.7\times 1000}{441}\\\\E_2=26.53\ V[/tex]

So, the emf amplitude in the secondary coil is 26.53 V.

Question: 18 kilogram Mass Block rest on level surface if the coefficient of static friction between the Block and the surface is 0.6 what  horizontal force is required to just move the blcok ( take gravity as 10m/s2 )

Answer:

108 N

Explanation:

From the question,

Applying

F' = mgμ................ Equation 1

Where F' = Frictional force = horizontal  force required to just move the block,  m = mass of the block, g = acceleration due to gravity, μ = coefficient of static friction.

From the question,

Given: m = 18 kg, μ = 0.6, g = 10 m/s²

Substitute these values into equation 1

F' = 18×0.6×10

F' = 108 N

Answer:

30 miles

Explanation:

Answer:

their final velocity is 0.091 m/s

Explanation:

Given;

mass of the first train, m₁ = 138,000 kg

mass of the second train, m₂ = 123,000 kg

initial velocity of the first train, u₁ = 0.288 m/s

initial velocity of the seocnd train, u₂ = -0.131 m/s (opposite direction to the first)

Let their common final velocity after been coupled = v

Apply the principle of conservation of linear momentum;

m₁u₁  +  m₂u₂ = v(m₁  +  m₂)

(138,000 x 0.288)    +    (-0.131 x 123,000)   =   v(138,000 + 123,000)

39,744   -   16,113   =  v(261,000)

23,631 = v(261,000)

v = 23,631 / 261,000

v = 0.091 m/s

Therefore, their final velocity is 0.091 m/s

Answer:

A simple pulley is a wheel with a rope that allows you to pull one end and have it lift whatever is on the other end. A modern, common example of this is a crane, often used in construction.

Explanation:

Answer:

1.45×10⁻¹⁶ C

Explanation:

Applying,

F = kqq'/r²................ Equation 1

Where F = force acting on the alpha particle, k = coulomb's constant, q = charge on the alpha particle, q' = charge on the atomic nucleus, r = distance of seperation between the alpha particle and the atomic nucleus.

make q' the subject of the equation

q' = Fr²/(kq)................. Equation 2

From the question,

Given: F = 79.8 N, r = 2.29×10⁻¹⁴ m, q = 2e = (2×1.6×10⁻¹⁹) = 3.2×10⁻¹⁹ C, k = 9×10⁹ Nm²/C²

Substitute these values into equation 2

q' = [79.8×(2.29×10⁻¹⁴)²]/(3.2×10⁻¹⁹×9×10⁹)

q' = (4.18×10⁻²⁶)/(2.88×10⁻¹⁰)

q' = 1.45×10⁻¹⁶ C

Answer:

what is the question? there isn't one

Answer:

When r1 – r2 equal the wavelength of the monochromatic light

Explanation:

This is because to observe a bright fringe a constructive interference pattern of path difference, r1 – r2 = mλ is observed, where m is an integer and λ = wavelength of monochromatic light.

For bright fringes and thus constructive interference, r1 – r2 must be integral multiples of the wavelength, λ. When r1 – r2 , we have the central bright fringe and thus m = 0.

The first order bright fringe which is adjacent to the central bright fringe is obtained when m = 1,

So r1 – r2 = 1 × λ

r1 – r2 = λ

Thus, the path difference required to produce the first order bright fringe that is adjacent to the central bright fringe is when r1 – r2 = λ, the wavelength of the monochromatic light.

The complete question is as follows: A student is subjected to a reaction force of 10 N northward from a 5 kg block while pushing the block over a smooth, level surface. Ignoring friction, what is the acceleration of the block?

Answer: The acceleration of the block is [tex]2 m/s^{2}[/tex].

Explanation:

Given: Force = 10 N

Mass = 5 kg

It is known that force applied on an object is the product of mass and acceleration.

Mathematically, [tex]F = m \times a[/tex]

where,

F = force

m = mass

a = acceleration

Substitute the values into above formula as follows.

[tex]F = m \times a\\10 N = 5 kg \times a\\a = \frac{10}{5}\\= 2 m/s^{2}[/tex]

Thus, we can conclude that the acceleration of block is [tex]2 m/s^{2}[/tex].