If the demand function for city bus rides is P = 100 - 10Q and the present price of a ride is 60, then A. Raising prices will increase city revenue (note: remember that revenue = P*Q)
B. Raising prices will decrease city revenue
C. Raising prices will not change city revenue
D. From the information given it is not clear what would happen to city revenue if price is increased.

a. The probability of P(Z > 1.02) = 0.1539
b. P(Z ≤ -2.36) = 0.0091
c. P(0 ≤ Z ≤ 1.07) = 0.3577


1. To find the probabilities, you need to reference a standard normal (z) table.

2. For a. P(Z > 1.02), look up 1.02 on the z table. The corresponding value is 0.8461. Since the question asks for P(Z > 1.02), subtract the value from 1: 1 - 0.8461 = 0.1539.

3. For b. P(Z ≤ -2.36), look up -2.36 on the z table. The corresponding value is 0.0091. Since the question asks for P(Z ≤ -2.36), the value is already correct: 0.0091.

4. For c. P(0 ≤ Z ≤ 1.07), look up 1.07 on the z table. The corresponding value is 0.8577. Since the question asks for P(0 ≤ Z ≤ 1.07), subtract 0.5 (value for Z = 0): 0.8577 - 0.5 = 0.3577.

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It would take Deshaun 5 hours to drive 335 miles at the same rate.

The SI unit of speed is m/s, and speed is defined as the ratio of distance to time. It is the shift in an object's location with regard to time.

We can use the formula:

rate = distance / time

to solve the problem. The rate is constant, so we can use it to find the time for a different distance.

First, we find Deshaun's rate:

rate = distance / time = 469 miles / 7 hours = 67 miles per hour

Now we can use this rate to find the time it would take to drive 335 miles:

time = distance / rate = 335 miles / 67 miles per hour

time = 5 hours

Therefore, it would take Deshaun 5 hours to drive 335 miles at the same rate.

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The complete question is:

Deshaun drove 469 miles in 7 hours. At the same rate, how long would it take him to drive 335 miles?

The general solution of differential equation is, y = k * (x²-9).

We can begin by separating the variables of the differential equation:

y′ = (2y) / (x²-9)

y′ / y = 2 / (x²-9)

Now we can integrate both sides with respect to their respective variables:

[tex]\int \dfrac{y'}{y} dy = \int \dfrac{2}{x^2-9} dx[/tex]

ln|y| = ln|x²-9| + C

where C is the constant of integration.

Simplifying:

|y| = e^(ln|x²-9|+C) = e^C * |x²-9|

Since e^C is a positive constant, we can write:

y = k * (x²-9)

where k is a non-zero constant. Therefore, the general solution of the given differential equation is y = k(x²-9), where k is any non-zero constant.

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--The complete question is, Find the general solution of the given differential equation. y′ = (2y) / (x²-9).--

The value of c is -10/3. This can be answered by the concept of Differentiation.

To find the values of c for which the parabolas y = 9x² and x = c + 3y² intersect at right angles, we need to consider the slopes of the tangent lines at the intersection points.

First, let's find the derivatives of both functions to get the slopes:

For y = 9x², let's find dy/dx:
dy/dx = 18x

For x = c + 3y², let's find dx/dy:
dx/dy = 1 / (6y)

At the intersection points, we have:
9x² = y
c + 3y² = x

Since the tangent lines are perpendicular, their slopes multiply to -1:
(18x)(1 / (6y)) = -1

Now, substitute y = 9x² into the equation:
(18x)(1 / (6 × 9x²)) = -1
(18x)(1 / (54x²)) = -1
(1 / (3x)) = -1

Solving for x, we get x = -1/3.

Now substitute this value of x into the equation for y:
y = 9(-1/3)²
y = 9(1/9)
y = 1

So the intersection point is (-1/3, 1). Now substitute the value of y back into the equation for x to find c:
-1/3 = c + 3(1²)
-1/3 = c + 3
c = -1/3 - 3
c = -10/3

Therefore, the value of c is -10/3.

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a)  If the first person chosen is a boy, what is the probability that

the second person chosen is also a boy is: 12/27

b) The probability that both students chosen are girls is: 5/18

The parameters given are:

There are 28 students in a class

13 of the students are boys

According to the question we have

When first chosen a boy , then the rest is

28 - 1 = 27

Then the rest boys are 12

From 27, has 12 boys

The probability that the second person also is a boy = 12/27

b) There are:

28 - 13 = 15 girls

Probability that first is a girl = 15/28

Probability that second is a girl = 14/27

Thus:

P(both are girls) = (15/28) * (14/27) = 5/18

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The global maximum value of f(x, y) on the closed triangular region occurs at either (4, 0) or (0, 4), both of which have a value of 16.

The global minimum value of f(x, y) occurs at the critical point (0, 0), with a value of 0

To find the Optimization of multivariable functions i.e, global extreme values of [tex]f(x, y) = x^2 - xy + y^2[/tex] on the closed triangular region in the first quadrant bounded by the lines x = 4, y = 0, and y = x,

We need to first find the critical points of the function in the interior of the region and evaluate the function at these points, and then evaluate the function at the boundary points of the region.

To find the critical points of the function in the interior of the region, we need to solve the system of partial derivatives:

[tex]df/dx = 2x - y = 0\\f/dy = -x + 2y = 0[/tex]

Solving this system of equations, we get the critical point (x, y) = (0, 0).

To check whether this point is a maximum or a minimum, we need to evaluate the second partial derivatives of f:

[tex]d^2f/dx^2 = 2\\d^2f/dy^2 = 2\\d^2f/dxdy = -1[/tex]

The determinant of the Hessian matrix is:

[tex]d^2f/dx^2 \times d^2f/dy^2 - (d^2f/dxdy)^2 = 4 - 1 = 3[/tex]

Since this determinant is positive and [tex]d^2f/dx^2 = d^2f/dy^2 = 2[/tex] are both positive, the critical point (0, 0) is a local minimum.

Next, we need to evaluate the function at the boundary points of the region. These are:

(4, 0): f(4, 0) = 16

(0, 0): f(0, 0) = 0

(0, 4): f(0, 4) = 16

(y, y) for 0 ≤ y ≤ 4: [tex]f(y, y) = 2y^2 - y^2 = y^2[/tex]

Therefore, the global maximum value of f(x, y) on the closed triangular region occurs at either (4, 0) or (0, 4), both of which have a value of 16.

The global minimum value of f(x, y) occurs at the critical point (0, 0), with a value of 0.

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The surface area of the composite figure is 1,665.04 in².

The volume of composite figure is 1,079.66 in³.

The volume  and surface area of the composite figure is calculated by applying the following formula as shown below;

The surface area = area of cone + area of hemisphere

S.A = πr(r + l) + 3πr²

S.A = π x 10 (10 + 13)  +  3π(10²)

S.A = 1,665.04 in²

The volume of composite figure is calculated as follows;

V = ¹/₃πr²h  +  ²/₃πr²

The height of the cone is calculated;

h = √(13² - 10²)

h = 8.31 in

V = ¹/₃π(10)²(8.31)  +  ²/₃π(10)²

V = 870.22 + 209.44

V = 1,079.66 in³

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The area of the region bounded by the curve r = 2sin(θ) in the sector 0≤θ≤π is π/2 square units.

The curve given by the polar equation r = 2sin(θ) is a sinusoidal spiral that starts at the origin, goes out to a maximum distance of 2 units, and then spirals back into the origin as θ increases from 0 to 2π. The sector 0≤θ≤π is half of this spiral, so we can find its area by integrating the area element dA = 1/2 r^2 dθ over this sector

A = ∫[0,π] 1/2 (2sin(θ))^2 dθ

Simplifying the integrand and applying the half-angle identity for sin^2(θ), we get

A = ∫[0,π] sin^2(θ) dθ

= ∫[0,π] (1 - cos^2(θ)) dθ

Integrating term by term, we get

A = [θ - 1/2 sin(2θ)]|[0,π]

= π/2 square units.

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A proportional relationship is a type of relationship between two quantities in which they maintain a constant ratio to each other.

The equation that defines the proportional relationship is given as follows:

y = kx.

In which k is the constant of proportionality, representing the increase in the output variable y when the constant variable x is increased by one.

The constant for this problem is given as follows:

k = y/x

k = 16/7.

Hence the equation is:

y = 16x/7.

The outputs for the given inputs are given as follows:

When y = 22, the input is given as follows:

22 = 16x/7

x = 22 x 7/16

x = 77/8.

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cos(sin⁻¹ˣ-tan^-1y) can be written as: x/√(1+y²) + √(1-x²)/√(1+y²). This can be answered by the concept of Trigonometry.

We can use the trigonometric identity cos(a-b) = cos(a)cos(b) + sin(a)sin(b) to write cos(sin⁻¹ˣ-tan^-1y) in terms of x and y.

Let a = sin⁻¹ˣ and b = tan^-1y, then we have:

cos(sin⁻¹ˣ-tan^-1y) = cos(a-b)

= cos(a)cos(b) + sin(a)sin(b)

= (√(1-x²))(1/√(1+y²)) + x/√(1+y²)

= x/√(1+y²) + √(1-x²)/√(1+y²)

Therefore, cos(sin⁻¹ˣ-tan^-1y) can be written as:

x/√(1+y²) + √(1-x²)/√(1+y²)

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The probability that fewer than 2 students come to office hours on any given Monday is 0.70.

To find the probability that fewer than 2 students come to office hours on any given Monday, we need to calculate the sum of the probabilities of X=0 and X=1.

P(X < 2) = P(X = 0) + P(X = 1)

= 0.40 + 0.30

= 0.70

From the given probability distribution, we can see that the probability of X=0 is 0.40 and the probability of X=1 is 0.30. These represent the probabilities of no students or one student showing up for office hours, respectively.

To find the probability that fewer than 2 students come to office hours on any given Monday, we need to add these probabilities together since X can only take on integer values.

Therefore, P(X < 2) = P(X = 0) + P(X = 1) = 0.40 + 0.30 = 0.70.

This means that there is a 70% chance that either no students or one student will show up for office hours on any given Monday.

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a) The general solution is y(x) = y_c(x) + y_p(x) = c1e^x + c2e^(4x) + 8ex.

b) The general solution is y(x) = y_c(x) + y_p(x) = c1e^(x/2)cos((√3/2)x) + c2e^(x/2)sin((√3/2)x) - (1/4)sin(3x).

For the differential equation y'' - 5y' + 4y = 8ex, the characteristic equation is r^2 - 5r + 4 = 0, which has roots r1 = 1 and r2 = 4. Thus, the complementary function is y_c(x) = c1e^x + c2e^(4x).

To find the particular solution, we guess a solution of the form y_p(x) = Ae^x. Then, y_p''(x) - 5y_p'(x) + 4y_p(x) = Ae^x - 5Ae^x + 4Ae^x = Ae^x. We need this to equal 8ex, so we set A = 8, and the particular solution is y_p(x) = 8ex.

Thus, the general solution is y(x) = y_c(x) + y_p(x) = c1e^x + c2e^(4x) + 8ex.

b) For the differential equation y'' - y' + y = 2sin(3x), the characteristic equation is r^2 - r + 1 = 0, which has roots r1,2 = (1 ± i√3)/2. Thus, the complementary function is y_c(x) = c1e^(x/2)cos((√3/2)x) + c2e^(x/2)sin((√3/2)x).

To find the particular solution, we guess a solution of the form y_p(x) = A sin(3x) + B cos(3x). Then, y_p''(x) - y_p'(x) + y_p(x) = -9A sin(3x) - 9B cos(3x) - 3A cos(3x) + 3B sin(3x) + A sin(3x) + B cos(3x) = -8A sin(3x) - 6B cos(3x). We need this to equal 2sin(3x), so we set A = -1/4 and B = 0, and the particular solution is y_p(x) = (-1/4)sin(3x).

Thus, the general solution is y(x) = y_c(x) + y_p(x) = c1e^(x/2)cos((√3/2)x) + c2e^(x/2)sin((√3/2)x) - (1/4)sin(3x).

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After continuing this process recursively until all integers are placed in the MIN HEAP. Using this method, we can see that there is only one possible MIN HEAP that can be made using the given set of integers. Therefore, the answer of the Binary Tree is 1.

Given the set of integers {88, 2, 9, 36}, there are 3 different Min Heaps that can be made using these integers. Min Heap is a binary tree where the parent node has a value less than or equal to its child nodes.

To determine the number of different MIN HEAPs that can be made using the set of integers {88, 2, 9, 36}, we can use the formula for the number of distinct permutations of n elements, which is n!. However, we need to take into account that MIN HEAP has a specific structure where the parent node is always smaller than its children nodes.

Then, we can choose the next smallest integer (9 or 36) as the left child of 2, and the remaining integer as the right child of 2. We can continue this process recursively until all integers are placed in the MIN HEAP.

Here are the 3 different Min Heaps:

1.       2
      /     \
    9        36
  /
88

2.       2
      /     \
    88      9
  /
36

3.       2
      /     \
    36       9
  /
88

These Min Heaps satisfy the condition of having the parent nodes with smaller values than their child nodes.

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The minimum number of supports required is 7.

To determine the minimum number of supports required for the twenty-four feet (six 4-ft sections) of track lighting to be installed in a continuous row in a retail store, follow these steps:

1. Determine the total length of the track lighting: 6 sections * 4 feet per section = 24 feet.

2. Consider that a support is needed at the beginning and end of the track.

3. Assess the spacing between supports. For instance, let's assume supports can be placed every 4 feet.

4. Calculate the number of supports in between the ends: (24 feet - 4 feet) / 4 feet = 5 supports.

5. Add the supports at the beginning and end: 5 supports + 2 supports = 7 supports.

The minimum number of supports required is 7.

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96

Explanation:

Write the prime factorization of both the numbers.

24=2×2×2×3

32=2×2×2×2×2

Answer:

Using a scale factor of -1/2, you can enlarge the center with the axis points, (-1,-1).

Step-by-step explanation:

In order to enlarge the triangle M, you would need to use the scale factor of -1/2.

With the center of enlargement then found on plotted axis (-1, -1), one would find a new triangle labeled N.

To find the surface area, you add up the area of the lateral faces and the area of the bases. The area of the triangular bases is 10.5 inches squared, and the area of the lateral faces is (3.5 * 9) + (4.5 * 9) + (3 * 9) = 99 inches squared. 10.5 + 99 = 109.5 inches squared

Answer:

To solve for x and y, we can use algebraic manipulation and substitution. Here are the steps:

Rearrange the first equation to solve for y in terms of x:

y = 2 - x

Substitute this expression for y into the second equation, and simplify:

x^3 + (2-x)^3 = 56

x^3 + 8 - 12x + 6x^2 - 3x^3 = 56

-2x^3 + 6x^2 - 12x + 8 = 0

Divide both sides by -2 to simplify the equation:

x^3 - 3x^2 + 6x - 4 = 0

Try to find a root of the equation using synthetic division or guess and check. One possible root is x = 2. Substituting this back into the first equation gives:

2 + y = 2

y = 0

So the solution is x=2 and y=0.

Therefore, the solution to the system of equations is x = 2 and y = 0.

Glucose is component is missing from the process of cellular respiration.

Glucose  + Oxygen → Carbon Dioxide + Water + Energy

What is cellular respiration in simple terms?

Cell breath is a progression of synthetic responses that separate glucose to create ATP, which might be utilized as energy to drive numerous responses all through the body. There are three primary strides of cell breath: glycolysis, the citrus extract cycle, and oxidative phosphorylation. Glycolysis, pyruvate oxidation, the citric acid or Krebs cycle, and oxidative phosphorylation are the stages of cellular respiration.

Glucose  + Oxygen → Carbon Dioxide + Water + Energy

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Answer:

[tex]f^{-1}(x) = \dfrac{6x + 5}{1 - x}[/tex]

Step-by-step explanation:

To find the inverse of a function, we can swap x and y (f(x)), then solve for y, and represent that y as [tex]f^{-1}(x)[/tex].

[tex]f(x) = \dfrac{x - 5}{x + 6}[/tex]

↓ swapping x and y

[tex]x = \dfrac{y - 5}{y + 6}[/tex]

↓ multiplying both sides by (y + 6)

[tex]x(y + 6) = y - 5[/tex]

↓ simplifying using the distributive property

[tex]xy + 6x = y - 5[/tex]

↓ subtracting 6x and y from both sides to isolate the y terms

[tex]xy - y = - 6x - 5[/tex]

↓ undistributing y from the left side

[tex]y(x - 1) = - 6x - 5x[/tex]

↓ dividing both sides by (x - 1)

[tex]y = \dfrac{-6x - 5}{x-1}[/tex]

↓ (optional) multiplying the fraction by [tex]\bold{\dfrac{-1}{-1}}[/tex]

[tex]y = \dfrac{6x + 5}{1 - x}[/tex]

↓ replacing y with [tex]f^{-1}(x)[/tex]

[tex]\boxed{f^{-1}(x) = \dfrac{6x + 5}{1 - x}}[/tex]

For a wooden beam has a rectangular cross section with height, h and width, w. The dimensions of the strongest beam that can be cut from a round log of diameter d = 22 inches are equal to 7.33 inches × 17.96 inches.

Mathematically, a dimension of a space is defined as the smallest number of coordinates required to determine any point within it. It is used as a measurement of the size of an object. Commonly it is expressed as length, width, and height. We have a wooden beam has a rectangular cross section,

height of beam = h

Width of beam = w

The strength of beam = S

Now, strength S of the beam is directly proportional to the width and the square of the height, that is S ∝ wh²

=> S = kwh², where k ->constant of proportionality.

The strongest beam that can be cut from a round log of diameter d = 22 inches

From the figure, d² = h² + w²

=> 22² = h² + w²

=> h² = 484 - w²

plug this value in above equation, S = kw(484 - w²)

For maximum of strength, dS/dw = 0 ( critical values)

=> [tex]\frac{ d( kw(484 - w²)}{dw} = 0[/tex]

=> k( 484 - 3w²) = 0

=> 484 - 3w² = 0

=> w² = 484/3

=> w = 22/√3 = 7.33

then, h² = 484 - w²

[tex]h^2= 484 - \frac{ 484}{3} [/tex]

=> [tex] h^2= 2( \frac { 484}{3} )[/tex]

=> [tex]h = (\frac{ \sqrt2}{\sqrt3} )22[/tex]

= 17.96

Hence, required value is 17.96 inches.

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Complete question:

A wooden beam has a rectangular cross section of height h and width w (see figure). The strength S of the beam is directly proportional to the width and the square of the height. What are the dimensions of the strongest beam that can be cut from a round log of diameter d = 22 inches? Round your answers to two decimal places.

Different sequence of answers is  59049.

Explanation: -  

To determine the number of different sequences of answers that can be created with ten multiple-choice questions, each having three possible answers, we need to use the multiplication principle of counting. This principle states that the total number of possible outcomes of a sequence of events is the product of the number of outcomes for each event.

For the first question, there are three possible answers. For the second question, there are three possible answers, and so on for each of the ten questions. Using the multiplication principle, we can determine the total number of different sequences of answers by multiplying the number of outcomes for each question together: 3 x 3 x 3 x 3 x 3 x 3 x 3 x 3 x 3 x 3 = 59,049

Therefore, there are 59,049 different sequences of answers that can be created with ten multiple-choice questions, each having three possible answers.

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The probability that you win is given as follows:

25/81.

Hence it is not true that you are more likely to win, as the probability of winning is less than 50%. Even tough there are more odd numbers than even number, you need two odd numbers for the product to generate an odd number.

A probability is calculated as the division of the desired number of outcomes by the total number of outcomes in the context of a problem/experiment.

For the product of two numbers, we have that:

5(1, 3, 5, 7 and 9) out of the 9 numbers, are odd, hence the probability of choosing two odd numbers is given as follows;

5/9 x 5/9 = 25/81.

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Answer: the quotient is 2x - 1 and the remainder is 0. So we can write:

(56x^2-60x+16) ÷ (28x-16) = 2x - 1.

Step-by-step explanation:

2x - 1

-------------

28x - 16 | 56x^2 - 60x + 16

56x^2 - 32x

--------------

-28x + 16

-28x + 16

----------

0

If the inputs of a J-K flip-flop are J= 1 and K = 1 while the outputs are Q = 0 and Q= 1, the outputs after the next clock pulse occurs are C) Q=1, Q=0. An eight-line multiplexer must have D) eight data inputs and three select inputs.

For the first question, with the J-K flip-flop:
Given inputs J = 1 and K = 1, and outputs Q = 0 and Q' = 1. After the next clock pulse occurs, the outputs will be:
A) Q = 0, Q' = 0
B) Q = 1, Q' = 1
C) Q = 1, Q' = 0
D) Q = 0, Q' = 1
Answer: Since the J-K flip-flop is in toggle mode when J = 1 and K = 1, the outputs will toggle. Therefore, the correct answer is C) Q = 1, Q' = 0.
For the second question, regarding an eight-line multiplexer:
A) four data inputs and three select inputs.
B) eight data inputs and two select inputs.
C) eight data inputs and four select inputs.
D) eight data inputs and three select inputs.
Answer: An eight-line multiplexer requires three select inputs to choose from eight data inputs ([tex]2^3[/tex] = 8). Therefore, the correct answer is D) eight data inputs and three select inputs.

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The equation to compute the area A of the circle is: [tex]A = π(r^2 - r0^2) + A0[/tex] where r0 is the initial radius and A0 is the initial area.

The equation to compute the area A of a circle with radius r is [tex]A = πr^2[/tex].

Using this equation and the given information that the radius is increasing at a rate of centimeters per second, we can write:

[tex]\frac{dA}dt} = 2rπ \frac{dr}{dt}[/tex]

where dA/dt represents the rate of change of area with respect to time, and [tex]\frac{dr}{dt}[/tex] represents the rate of change of radius with respect to time.

Part 1:

If we want to find the area of the circle at a specific time t, we can integrate both sides of the equation with respect to time:

[tex]\int\limits dA= \int\limits 2πr \frac{dr}{dt}  \, dt[/tex]

Integrating both sides gives:

[tex]A = πr^2 + C[/tex]

where C is the constant of integration. Since we are given the initial radius, we can use it to find the value of C:

When t = 0, r = r0

[tex]A = πr0^2 + C[/tex]

Therefore, [tex]C = A - πr0^2[/tex]

Substituting this value of C back into the equation gives:

[tex]A = πr^2 + A - πr0^2[/tex]

Simplifying gives:

[tex]A =π(r^2 - r0^2) + A0[/tex]

where A0 is the initial area of the circle.

Therefore, the equation to compute the area A of the circle is:

[tex]A = π(r^2 - r0^2) + A0[/tex]

where r0 is the initial radius and A0 is the initial area.

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Answer:

Step-by-step explanation:

Using a standard normal table, we can find the area under the curve between 1.20 and 1.85 to be approximately 0.4678. Therefore, the answer is (c) 0.4678.

Answer:

Step-by-step explanation:

use Pythagorean triangle:

a^{2} + b^{2} = c^{2}

a= 12

b= 16

c = ?

12^{2} + 16^{2} = c^{2}

144 + 256 = c^{2}

400 = c^{2}

\sqrt{400} = c

20 = c

c = 20 ft