Answer:
What is B physical manipulation
Explanation:
Physical manipulation means fertilizers that are manufactured, blended, or mixed, or animal manures or compost that have been changed from their initial physical state by manipulations such as drying, cooking, chopping, grinding, shredding, ashing, or pelleting.
Please allow me to know if my answer helped you with a thank you!
Miss Hawaii
Speed depends on how far something travels and
Answer:
Speed depends on how far something is travelling and the time taken for the object to travel that distance
Explanation:
(In reference to the speed formula) Speed=[tex]\frac{Distance(m)}{Time(m/s)}[/tex]
Definition of speed:
Speed is the magnitude (unit) of the rate at which an object is moving.
(pls do correct me if I have any mistakes it makes a big difference to help each other out!)
Name the type of joint present in skull.
Answer:
Sutures are nonmoving joints that connect bones of the skull
Explanation:
These joints have serrated edges that lock together with fibers of connective tissue.
Answer:
Immovable fibrous joints are present in our skull
Explanation:
brainliest plz
Which of the following statements is true?
a Penicillin is produced by fungal fermentation.
b
The effects of too much beer or wine can be
countered with antibiotics.
с
The deadly Death Cap mushroom can be treated
with penicillin.
d Antibiotics do not treat fungal diseases.
Answer:
a Penicillin is produced by fungal fermentation.
Explanation:
The industrial production of penicillin (PEN) occurs via fermentation using the filamentous fungus Penicillium chrysogenum
Penicillin G (benzylpenicillin) was first produced from a penicillium fungus that occurs in nature. The strain of fungus used today for the manufacture of penicillin G was created by genetic engineering to improve the yield in the manufacturing process.
Which theory of emotion explains the startle response
Answer:
In the present study, the startle blink reflex is used as a measure of emotion regulation to effective picture stimuli. Based on the aphasic theory of emotion, it is hypothesized that the startle response will be largest in magnitude in the presence of negative emotional stimuli (Varanasi, Spence, & Lang, 1988).
Most gasoline engines in today's automobiles are belt driven. This means that the crankshaft, a rod which rotates and drives the
pistons, is timed to the camshaft, the mechanism which actuates the valves, by means of a belt. Starting from rest, assume it
takes t = 0.0320 s for a crankshaft with a radius of r = 3.75 cm to reach 1250 rpm. If the belt does not stretch or slip, calculate
the angular acceleration ay of the larger camshaft, which has a radius of r2 = 7.50 cm, during this time period.
The angular acceleration of the larger camshaft is 995.72 rad/s².
The given parameters;
initial angular velocity, [tex]\omega _i[/tex] = 0time of motion, t = 0.032 sradius of the crankshaft, r = 3.75 cm final angular speed, [tex]\omega _f[/tex] = 1250 rpmThe angular acceleration of the 3.75 cm camshaft is calculated as follows;
[tex]\omega _f = \omega _i + \alpha t\\\\\omega _f =0 + \alpha t\\\\\omega _f = \alpha t\\\\(1250 \ \frac{rev}{\min} \times \frac{2 \pi \ rad}{rev} \times \frac{1\min}{60 \ s} ) = 0.032 \alpha \\\\130.92 = 0.032\alpha \\\\\alpha = \frac{130.92}{0.032} = 4091.25 \ rad/s^2[/tex]
The angular momentum of the camshaft is calculated as follows;
[tex]I_1 \alpha _1 = I_2 \alpha_2 \\\\\frac{1}{2} mr_1^2 \alpha _1 = \frac{1}{2}m R^2 \alpha_2\\\\r_1^2 \alpha _1 = R^2 \alpha_2\\\\\alpha_2 = \frac{r_1^2 \alpha _1 }{R^2} \\\\\alpha_2 =\frac{(0.037)^2 \times (4091.25)}{(0.075)^2} \\\\\alpha _2 = 995.72 \ rad/s^2[/tex]
Thus, the angular acceleration of the larger camshaft is 995.72 rad/s².
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Once you start pulling your object with less force than friction, what should you expect your object to do? What about when your object is pulled with more force than friction?
NO LINK S
#Case -1
If Pulling force is less than frictional force the object won't move .
#Case-2
If Pulling force is greater than frictional force then object will be .
In order to calculate friction force you need Limiting friction first .
[tex]\\ \sf\longmapsto F_L=\mu sN[/tex]
u s is coefficient of static friction and N is normal reaction
Or
[tex]\\ \sf\longmapsto F_L=\mu smg[/tex]
As N=mgAn object starts from rest and uniformly accelerates at a rate of 1.25 m/s2 for 7.0 seconds.
(a) What is the object's displacement during this 7-second time period?
(b) What is the object's final velocity?
(c) How many seconds does it take the object to have a displacement of 22 meters?
Explanation:
Since its accelerating, the velocity vs time graph is linear
For displacement we need initial velocity (which is zero because it starts from rest) and final velocity (which is calculatee thro acceleration formula
A= (vf - vi)/t
a= vf-0/t
1.25=vf / 7
1.25*7=vf
8.75 = vf
Now for displacement plug all the values in
X = 1/2(vf-vi)/t formula
The displacement (x) is 30.625 m
For part 3, we know new displacement that is 22m , the final and initial velocities are the same so just plug in the values for same formula above
The answer is t = 5.02
Im pretty sure all the answers are correct
A stimulus that increses the occurance of a response is called
Answer:
reinforcing stimulus
Explanation:
Think its correct
Answer:
reinforcing stimulus
Explanation:
because it increases the occurence of a response
THE BEST ANSWER WILL BE MARKED THE BRAINLIEST!
While driving your car at a fast constant speed, you have to press down hard on your gas pedal than you do while driving at a slower constant speed.
In both cases, the net force on your car is zero. Explain why you have to apply a greater pressure to your gas pedal.
Answer:
You have to apply more pressure to the pedal so more gas runs through the car allowing it to reach higher speeds
To move, a car or any other object must be accelerated from rest to the desired speed; this necessitates that the engine force be greater than the friction force. The net force must be zero once the car is moving at constant velocity; otherwise, the car will accelerate (gain speed).
What forces act on a car at constant speed?All forces acting on a car moving at a constant speed (uniform motion) are balanced. In this case, the two opposing backward forces (air resistance and friction) perfectly balance the applied force of the wheels on the road.When we say constant speed, we mean that a body or object moves at a constant change in distance over time. For example, if we are walking in a straight line at 1 step per second, we can say we are moving at a constant speed. Our acceleration is equal to zero in this case.To learn more about : Speed
Ref : https://brainly.com/question/4931057
#SPJ2
How can wind, coiled wire, and magnets be used together to generate electricity?
Answer:
b
Explanation:
hope helpful
have a great day
1. What does the term monecious mean?
Answer:
Monecious is a plant or invertebrate animal having both the male and female reproductive organs in the same individual; hermaphrodite.
25. Which of the following cannot be broken down into smaller parts through ordinary chemical means?
a. Nitrogen
b. Protein
C. Salt
d. Sugar
Answer:
the correct answer is sugar
The gravitational force between two objects is 2700 N. What will be the gravitational force between the objects if the distance between them triples?
F = GMm/r^2
So F is proportional to 1/r^2
F2 = 2700 x ( 1 / 3^2 ) = 300N
help pls will give brainiest :)
Answer:
use a flight sim
Motion maps for two objects, Y & Z, are shown.
How many seconds does Object Z start before Object Y?
- 2
- 3
- 4
- 5
Answer: it’s 3 seconds
Explanation:
Answer:
B
Explanation:
3 seconds, hope it helps
Ano ang mangyayari kung hindi mo gagamitin ang iyong talento?
Answer:
mas lalo kang tinatamaran magaral
You throw a rock up into the air as hard as you can. It stays in the air a total of 6.0 s. What
was the velocity of the rock when you threw it?
Answer:
5.9 x 10Explanation:
A 10 kg box initially at a speed of 10 m/s accelerates uniformly to a speed of 20 m/s in 2
seconds. Determine the
A. energy gained by the block
Answer:
What Um Sorry Where's The Answer?....
What is sustainability? How can we make sustainable development a reality? How sustainability can be measured?
Answer:
1)The ability to be maintained at a certain rate or amount is called sustainability.
3)Sustainability is measured by assessing performance of Social, Environmental, and Economic principles.
sorry but I don't know number 2.
I hope it will help you)):
If you traveled 50m/s for 60 seconds, how far did you travel? Remember speed=distance/time
Question options:
300 m/s
500 m/s
3,000 m/s
300 km/h
for some reason my question got removed-_-
How can people reconcile technology with environmental preservation?
What is the magnitude of the electric field at a point 0.0075 m from a 0.0035
C charge?
Use E-
kq
and k - 9.00 x 10° N.m²/C2.
A. 1.9 x 1010 N
B. 4.2 x 10' N
O c. 5.6 x 1011 N
D. 5.5 x 1012 N
Explanation:
E = 9×10^9 × 0.0035 /(0.0075)²
= 9×10^9 × 3.5×10`³/(7.5×10`³)²
= 31.5×10^6 /(56.25 ×10^-6)
= 0.56 × 10^12
= 5.6 × 10^11 N/C (option C)
PLEASE HELP ASAP WILL GIVE BRAINLIEST
Explanation
(m) is measured in kilograms (kg)
(F) is measured in newtons (N)acceleration (a) is measured in metres per second squared (m/s²)Q1) ~mass (m) is measured in kilograms (kg)
Q2)~acceleration (a) is measured in metres per second squared (m/s²)
Q3)~force (F) is measured in newtons (N)
Hope this helped you- have a good day bro cya)
describe an experiment to demonstrate surface tension in a liquid
Answer:
mę břöőda I dunno this answer
Explanation:
hope you find it
Two horses are side by side on a carousel. Which has a greater tangential speed the one closer to the center or the one farther from the center? Explain your answer.
Answer:
The horse father from the center has a greater tangential speed. Although both horses complete one circle in the same time period, the one farther from the center covers a greater distance during that same period.
Explanation:
An object of mass 1.0 kg is at rest on a smooth inclined plane with height h, length 8 m,
and which makes an angle of 30° with the horizontal. The object is allowed to move, it
slides down and onto a rough horizontal surface. After traveling a distance of 4 m it hits a spring and travels 1.3 m more, all along the rough horizontal surface. The spring
constant is 26.5 N/m. What is the coefficient of kinetic friction for the horizontal surface?
The coefficient of kinetic friction for the rough horizontal surface is 0.66.
The given parameters;
mass of the object, m = 1 kglength of the inclined plane, L = 8 mangle of inclination of the plane, θ = 30⁰ distance traveled before hitting the spring, d₁ = 4 mdistance traveled after hitting the spring, d₂ = 1.3 mthe spring constant, k = 26.5 N/mApply work-energy theorem; the work done the force of friction is equal to the energy stored in the spring.
[tex]F_kd_1 = \frac{1}{2} kd_2^2\\\\\mu_kmg cos(\theta)d_1 = \frac{1}{2} kd_2^2\\\\\mu_k(1 \times 9.8 \times cos(30)\times 4) = \frac{1}{2} \times 26.5 \times (1.3)^2\\\\33.95\mu_k = 22.39\\\\\mu_k = \frac{22.39}{33.95} \\\\\mu_k = 0.66[/tex]
Thus, the coefficient of kinetic friction for the rough horizontal surface is 0.66.
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In hockey activities, a warm hockey puck and a frozen hockey puck has a different coefficient of restitution: 0.5 for a warm hockey puck, and 0.35 for a frozen one. NHL requires the frozen pucks to be used in games. To make sure the puck can be used in the game, the referee drops the puck on its side from a height of 2.5 m. How high should the puck bounce if it is a frozen puck
If its is a frozen hockey puck, it bounce off the ground after collision to a height of 0.3m.
Given the data in the question;
Since the hockey puck was initially in the referee's hands
Initial velocity; [tex]u = 0m/s[/tex]Distance or height from which it was dropped; [tex]h = 2.5m[/tex]Acceleration due to gravity; [tex]g = 9.8 m/s^2[/tex]Coefficient of restitution a frozen puck; [tex]0.35[/tex]First we will find the velocity of the Puck when it hits the ground
From the Third Equation of Motion:
[tex]v^2 = u^2 + 2as[/tex]
Where v is the final velocity, u is the initial velocity, a is the acceleration due to gravity and s is the distance.
Since the pluck is under gravity, we will have:
[tex]v^2 = u^2 + 2gh[/tex]
We substitute in our value and find "v"
[tex]v^2 = 0 + (2 \ *\ 9.8m/s^2\ *\ 2.5m )\\\\v^2 = 47.04m^2/s^2\\\\v= \sqrt{47.04m^2/s^2}\\\\v = 6.85857m/s[/tex]
Now, Velocity of the hock puck after it hits the ground and bounce back;
We know that; Coefficient of restitution [tex]= \frac{Relative\ velocity\ after\ collision}{Relative\ velocity\ before\ collision}[/tex]
Hence, Relative Velocity after collision = Coefficient of restitution × Relative Velocity before collision
we substitute in our values;
Relative Velocity after collision [tex]= 0.35 \ *\ 6.85857m/s[/tex]
Relative Velocity after collision [tex]= 2.4 m/s[/tex]
Now, to determine how high should the puck bounced back
We use the Third Equation of Motion:
[tex]v^2 = u^2 + 2as[/tex]
Where v is the final velocity, u is the initial velocity, a is the acceleration due to gravity and s is the distance.
Since the pluck is under gravity, we will have:
[tex]v^2 = u^2 + 2gh[/tex]
Now, since the hockey puck bounces back, it is experiencing a negative acceleration
Hence, the equation becomes
[tex]v^2 = u^2 - 2gh[/tex]
We substitute our values into the equation and find "h"
[tex](0m/s)^2 = (2.4m/s)^2 - ( 2*9.8m/s^2*h)\\\\0 = 5.76m^2/s^2 - (19.6m/s^2*h)\\\\(19.6m/s*h) = 5.76m^2/s^2 \\\\h= \frac{ 5.76m^2/s^2 }{19.6m/s^2}\\\\h = 0.3m[/tex]
Therefore, If its is a frozen hockey puck, it bounce off the ground after collision to a height of 0.3m.
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A bowling ball, basketball, and tennis ball are all raised to the same height above the ground. Give the order of objects from the least potential energy to the most
Answer:
bowling ball, basket ball, tennis ball
Explanation:
find charge and charge density on the surface of a conducting sphere of radius 15.2cm where potential at 215 v
this is the correct answer
12. Suppose the polar bears were running on land instead of swimming. if the polar bear runs
at a speed of about 5.5m/s how far will it travel in 55 seconds?
the polar bear will travel 302.5m