In Hausdorff-space "X", if A and B are disjoint "compact-subspaces", then there is disjoint "open-sets" U and V such that A is contained in U and B is contained in V, this is because by Hausdorff-Property, the existence of disjoint open neighborhoods for any two "distinct-points".
To prove the existence of disjoint "open-sets" U and V with A⊂U and B⊂V, where A and B are "compact-subspaces" of "Hausdorff-space" X,
Step (1) : A and B are disjoint compact-subspaces, we use Hausdorff property to find "open-sets" Uₐ and [tex]U_{b}[/tex] such that "A⊂Uₐ" and "B⊂[tex]U_{b}[/tex]", and "Uₐ∩[tex]U_{b}[/tex] = ∅". This can be done for every pair of points in A and B, respectively, because X is Hausdorff.
Step (2) : We consider, set U = ⋃ Uₐ, where "union" is taken over all of Uₐ for each-point in A. U is = union of "open-sets", hence open.
Step (3) : We consider set V = ⋃ [tex]U_{b}[/tex], where union is taken over for all [tex]U_{b}[/tex] for "every-point" in B. V is also a union of open-sets and so, open.
Step (4) : We claim that U and V are disjoint. Suppose there exists a point x in U∩V. Then x must be in Uₐ for some point a in A and also in [tex]U_{b}[/tex] for some point b in B. Since A and B are disjoint, a and b are different points. However, this contradicts the fact that Uₐ and [tex]U_{b}[/tex] are disjoint open sets.
Therefore, U and V are disjoint open sets with A⊂U and B⊂V.
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The given question is incomplete, the complete question is
Let A and B be disjoint compact subspaces of a Hausdorff space X. Show that there exist disjoint open sets U and V, with A⊂U and B⊂V.
The range of a projectile that is launched with an initial velocity v at an angle of a with the horizontal is given by R
sin
where g is the acceleration due to gravity or 9.8 meters per second squared. If a projectile is launched with an initial velocity of 1
meters per second, what angle is required to achieve a range of 20 meters? Round answers to the nearest whole number.
Answer:
[tex]\theta=30.285^{\circ}[/tex]
Step-by-step explanation:
The range of a projectile is given by :
[tex]R=\dfrac{u^2\sin2\theta}{g}[/tex]
Put R = 20 m, u = 15 m/s and finding the value of angle of projection
So,
[tex]R=\dfrac{u^2\sin2\theta}{g}\\\\\sin2\theta=\dfrac{Rg}{u^2}\\\\\sin2\theta=\dfrac{20\times 9.8}{15^2}\\\\\sin2\theta=0.871\\\\2\theta=\sin^{-1}(0.871)\\\\2\theta=60.57\\\\\theta=30.285^{\circ}[/tex]
So, the required angle of projection is equal to [tex]30.285^{\circ}[/tex].
Please help, Im stuck on this part of a review and Im really confused asap
Answer:
( 6, -1 )
Step-by-step explanation:
When you rotate 1 from the x axis by 90° it becomes -1 from the y axis.
When you rotate 6 by 9° from thr y axis, it becomes again 6 on the x axis
Your new x value is 6 and y is -1
So (6,-1)
Answer:
(-6, 1)
Step-by-step explanation:
To find the point obtained by rotating point P = (1, 6) counterclockwise by an angle of 90 degrees (r₉₀°), we can use the rotation formula:
x' = x * cos(θ) - y * sin(θ)
y' = x * sin(θ) + y * cos(θ)
In this case, θ is 90 degrees.
Substituting the values into the formula:
x' = 1 * cos(90°) - 6 * sin(90°)
y' = 1 * sin(90°) + 6 * cos(90°)
cos(90°) = 0 and sin(90°) = 1, so we have:
x' = 1 * 0 - 6 * 1 = -6
y' = 1 * 1 + 6 * 0 = 1
Therefore, r₉₀°(P) = (-6, 1). The point P = (1, 6) rotates counterclockwise by 90 degrees to the point (-6, 1).
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I need help with short sides of the triangles on Pythagorean theorem
Answer:
5
Step-by-step explanation:
13² - 12² = 25
√25 = 5
Have a great day <3
Subject:Mathematics
Answer:F : 13 1/2
Step-by-step explanation:27 divided by 2 is 13 1/2
Work out
1/8
of 760
please help
Answer: 95
Step-by-step explanation:
Think of 1/8 times 760 as 760/8 because it’s the same thing.
I’ll mark you brainlieist
Analyze and sketch a graph of the function. Find any intercepts, relative extrema, points of inflection, and asymptotes. (If an answer does not exist, enter DNE.)
f(x) = 3x2/3 − 2x
I keep getting stuck at taking the first derivative and solving for critical points. So please show all work and even some of the tedious algebra bits included so I can see where I'm messing up?
The function f(x) = 3x²/3 - 2x has no intercepts, a relative minimum at (1, -1), no points of inflection, and no asymptotes.
Intercepts: To find the x-intercepts, we set f(x) equal to zero and solve for x:
0 = 3x²/3 - 2x
0 = x² - 2x
0 = x(x - 2)
x = 0 or x = 2
Therefore, both x = 0 and x = 2 are not actual x-intercepts, but rather double roots.
Relative Extrema: To find the relative extrema, we take the derivative of f(x) and set it equal to zero,
f'(x) = 2x - 2
0 = 2x - 2
2 = 2x
x = 1
Substituting x = 1 back into the original function, we find f(1) = -1. Therefore, the relative minimum occurs at (1, -1).
f''(x) = 2
Since the second derivative is a constant, it never equals zero. Therefore, there are no points of inflection for this function.
Asymptotes: To determine if there are any asymptotes, we examine the behavior of the function as x approaches positive or negative infinity. Since the highest power of x in the function is 2, the graph does not approach any vertical asymptotes.
For horizontal asymptotes, we look at the limits as x approaches positive or negative infinity:
lim(x→∞) f(x) = lim(x→∞) (3x²/3 - 2x) = ∞
The limits approach positive infinity in both cases, indicating that there are no horizontal asymptotes. Graphically, the function represents a parabola that opens upwards, with a relative minimum at (1, -1).
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not sure how to do this. need help
Answer:
a) 25/2 or 12.5
b) 78,125
c) 625
d) 30,517,578,125
These box plots show daily low temperatures for a sample of days in two different towns
Answer:
A. The median for town A, 30 degrees, is less than the median for town B, 40 degrees.
Step-by-step explanation:
HELPPP PLSSS IF YOUR A BOT I WILL REPORT !! A(b) is a function
Let {N(t),t > 0} be a renewal process. Derive a renewal-type equation for E[SN (1)+1).
The renewal-type equation for E[SN(1)+1] is E[SN(1)+1] = 2, indicating that the expected value of the sum of the number of renewals by time 1 plus 1 is equal to 2.
To derive a renewal-type equation for E[SN(1)+1], we can use the renewal-reward theorem.
Let Tn be the interarrival times of the renewal process, where n represents the nth renewal. The random variable N(t) represents the number of renewals that occur by time t.
Using the renewal-reward theorem, we have:
E[SN(1)+1] = E[T1 + T2 + ... + TN(1) + 1]
Since the interarrival times are independent and identically distributed (i.i.d.), we can express this as:
E[SN(1)+1] = E[T] * E[N(1)] + 1
Now, we need to compute the expressions for E[T] and E[N(1)].
E[T] represents the expected interarrival time, which is equal to the reciprocal of the renewal rate. Let λ be the renewal rate, then E[T] = 1/λ.
E[N(1)] represents the expected number of renewals by time 1. This can be calculated using the renewal equation:
E[N(t)] = λ * t
Therefore, E[N(1)] = λ * 1 = λ.
Substituting these expressions back into the renewal-type equation, we have:
E[SN(1)+1] = (1/λ) * λ + 1 = 1 + 1 = 2
Hence, the renewal-type equation for E[SN(1)+1] is E[SN(1)+1] = 2.
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Assume that all components of three panels, randomly selected and with 5, 5 and 5 components respectively, were examined. Assume that a component chosen at random is defective with probability 0.09 , independently of the other components.
What is the probability of detecting at most one defective component, when all components of these three panels are examined?
The probability of detecting at most one defective component when all components of the three panels are examined is approximately 0.78136 or 78.14%.
To calculate the probability of detecting at most one defective component when all components of the three panels are examined, we need to consider the possible combinations of defective components in each panel.
Let's break down the problem step by step:
Panel 1:
- There are 5 components in Panel 1.
- The probability of a component being defective is 0.09.
- We want to calculate the probability of detecting at most one defective component.
The probability of detecting no defective components in Panel 1 is:
P(0 defective) = (1 - 0.09)^5 = 0.52201
The probability of detecting exactly one defective component in Panel 1 is:
P(1 defective) = 5 * 0.09 * (1 - 0.09)^4 = 0.40408
The probability of detecting at most one defective component in Panel 1 is:
P(at most 1 defective) = P(0 defective) + P(1 defective) = 0.52201 + 0.40408 = 0.92609
Panel 2 and Panel 3 have the same probabilities as Panel 1 since they also have 5 components and the same probability of a component being defective.
Now, to calculate the probability of detecting at most one defective component when examining all three panels, we multiply the probabilities of each panel:
P(at most 1 defective in all three panels) = P(at most 1 defective in Panel 1) * P(at most 1 defective in Panel 2) * P(at most 1 defective in Panel 3)
= 0.92609 * 0.92609 * 0.92609
= 0.78136
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Find the least common multiple of 18, 24, 42
Answer: 504. Multiple for : 18, 24 and 42. Factorize of the above numbers : 18 = 2 • 32 24 = 23 • 3. 42 = 2 • 3 • 7
What is the slide e of the line shown below?
Answer:
13/6
Step-by-step explanation:
slope = (y2-y1)/(x2-x1) where the variables indicate the coordinates of the two points
slope = (-7-6)/(-5-1) = -13/-6 = 13/6
Roy received math test scores of 05, 90, 90, and 85.
7. What is Roy's median test score?
8. What score would Roy need to get on
his next test to have a mean of 92
Median = 87.5 Sorry about the other one
Which point is a solution to the inequality in this graph
Given:
The graph of an inequality.
To find:
The point which is a solution of the given graph of inequality.
Solution:
From the given graph it is clear that the boundary line of the graph is a dotted line. It means the points lie in shaded region are in the solution set but the points on the line are not included in the solution set.
The points (3,2) and (-3,-6) are lie on the boundary line. it means they are not the solution of the inequality represented by the given graph.
Point (5,0) lies on the positive x-axis at the distance of 5 units from the origin and it doesn't lies in the shaded region. So, (5,0) is not a solution.
Point (0,5) lies on the negative y-axis at the distance of 5 units from the origin and it lies in the shaded region. So, (0,5) is a solution.
Therefore, the correct option is B.
The volume of a rectangular prism is 1,560 cm3. The height is 12 cm. The width is w and the length is w + 3. Find w.
Answer:
w=10 cm
Step-by-step explanation:
The formula for the volume of a rectangular prism is V=whl.
So in this case, the equation would be 1560=w·12·(w+3). Then, we can simplify this equation.
1. Divide 12 to both sides of the equation. 1560/12=130. The equation becomes 130=w(w+3).
2. Distribute w through the parentheses, the equation becomes 130=w²+3w.
3. Then, -130 from both sides of the equation, so we can get the quadratic: w²+3w-130=0.
4. Factor the quadratic. w²+3w-130=(w-10)(w+13).
5. (w-10)(w+13)=0. w=10 or w=-13. However, w is the width of a rectangular prism, can the width of a shape be negative? No. So we can ignore the solution w=-13. Therefore, w=10cm.
6. To make sure our answer is correct, let's substitute the values back into the volume of a rectangular prism formula: V=whl. w=10; h=12; l=10+3=13; V=10(12)(13)=120*13=1560 cm³. As a result, our answer is correct, w=10 cm.
Hope this helps, have a nice day.
Alinear trendline used to forecast sales for a given time period takes the form y = b+ bil. increases by , then the estimated y value all else e tone period, increases, b1; constant o tone period, increases, bo, constant bione period, increases; bo constant bi: one period, increases bi: constant
The linear trendline used to forecast sales for a given time period takes the form y = b0 + b1t, where y represents the estimated sales, b0 is the constant term, b1 is the coefficient of the time period variable (t), and t is the time period.
In this equation, the coefficient b1 determines the relationship between the time period and the estimated sales. If b1 increases, it means that for each additional time period, the estimated sales will also increase. On the other hand, if b1 is constant, it implies that the estimated sales do not change with each additional time period.
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The sum of two nonnegative numbers is 20. Find the numbers if the sum of their squares is as large as possible; as small as possible.
a. The numbers are 10 and 10.
b. The numbers are 0 and 20.
c. The numbers are 1 and 19.
d. The numbers are 20 and 0.
Option D. The numbers are 20 and 0.
Let the two nonnegative numbers be x and y such that x + y = 20. We know that the sum of the squares of the two nonnegative numbers x and y is as large as possible and as small as possible.
x + y = 20, or y = 20 - x (Since the numbers are non-negative, x, y ≥ 0)
Substituting y = 20 - x into x² + y² = P (for the sake of simplicity), we get x² + (20 - x)² = Px² + 400 - 40x + x² = P
We will take the first derivative with respect to x now: 2x - 40 = 0x = 20
Therefore, one of the nonnegative numbers is 20, and the other is zero. Consequently, the smallest possible sum of squares is 400 (since 20² + 0² = 400).Option D. The numbers are 20 and 0.
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Given, the sum of two nonnegative numbers is 20.
The problem asks us to find the numbers if the sum of their squares is as large as possible; as small as possible.
Therefore, let's find the sum of their squares at first.If 'x' and 'y' are two numbers, then the sum of their squares is given by:
[tex]x^2 + y^2[/tex]
If the sum of two nonnegative numbers is 20, then one number can be written as x and the other number can be written as y in terms of x.
Thus,y = 20 − xNow, the sum of their squares:
[tex]x^2 + y^2 = x^2 + (20 - x)^2[/tex]
= [tex]x^2 + 400 + x^2 - 40x[/tex]
= [tex]2x^2 - 40x + 400[/tex]
The above expression represents a parabola which opens upward because the coefficient of x^2 is positive.
Therefore, the sum of the squares of the two numbers will be maximum at the vertex of the parabola.
The x-coordinate of the vertex can be found as
:−b/2a = −(−40)/(2.2) = 10Hence, x = 10 and y = 10.
Substituting x = 10 and y = 10, we get
[tex]x^2 + y^2 = 200.[/tex]
Now, to find the smallest value of the sum of their squares, we can observe that the smallest value of x is 0, and the largest value of y is 20.
Thus, if x = 0 and y = 20, we get x^2 + y^2 = 400.
Answer: The numbers are 10 and 10. The numbers are 0 and 20.
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bro I NEED HELP FAST
Help Please! Find The Circumference Of A Circle With R=12.3.
Answer:
77.28
Step-by-step explanation:
c=π2r
12.3 times 2 =
24.6π
=77.28317928
=77.28
Answer:
77.3
Step-by-step explanation:
Osing Trig to Find a Side Apr 06, 5:40:44 PM In AOPQ, the measure of ZQ=90°, the measure of Z0=26°, and QO = 4.9 feet. Find the length of PQ to the nearest tenth of a foot. P (hypotenuse) X (opp. of 20) 2009 Q 4.9
Answer:5.4
Step-by-step explanation:
how many square miles does ATC and radar services attempt to cover? How many aircraft at any given time is ATC monitoring, and spread over how many airports within the USA?
The work of providing air traffic control and radar services in the United States falls under the purview of the Federal Aviation Administration (FAA). ATC and radar services that cover all airspace over the United States, regardless of whether flights are domestic or international.
What is the radar servicesFAA provides ATC and radar services in the US. ATC and radar services cover all US airspace, including domestic and international flights. The FAA manages the NAS, covering 29.5 million sq mi. This includes airspace over the entire United States, including Alaska, Hawaii, Guam, Puerto Rico. VI ATC monitors varying number of aircraft based on time, weather, and traffic.
The FAA deals with 44k flights daily in the US. Note that this number may increase during peak travel periods. The FAA manages ATC for 13k+ US airports. Incl. international, regional, gen. aviation & priv. airstrips. The number can vary due to new or old airports.
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Claim: the average age of online students is 32 years old. Can you prove it is not? What is the null hypothesis? o What is the alternative hypothesis? What distribution should be used? o What is the test statistic? o What is the p-value? o What is the conclusion? o How do we interpret the results, in context of our study? • Claim: the proportion of males in online classes is 35%. Can you prove it is not? o What is the null hypothesis? o What is the alternative hypothesis? o What distribution should be used? o What is the test statistic? o What is the p-value? o What is the conclusion? o How do we interpret the results, in context of our study?
To predict a linear regression score, you first need to train a linear regression model using a set of training data.
Once the model is trained, you can use it to make predictions on new data points. The predicted score will be based on the linear relationship between the input variables and the target variable,
A higher regression score indicates a better fit, while a lower score indicates a poorer fit.
To predict a linear regression score, follow these steps:
1. Gather your data: Collect the data p
points (x, y) for the variable you want to predict (y) based on the input variable (x).
2. Calculate the means: Find the mean of the x values (x) and the mean of the y values (y).
3. Calculate the slope (b1): Use the formula b1 = Σ[(xi - x)(yi - y)] Σ(xi - x)^2, where xi and yi are the individual data points, and x and y are the means of x and y, respectively.
4. Calculate the intercept (b0): Use the formula b0 = y - b1 * x, where y is the mean of the y values and x is the mean of the x values.
5. Form the linear equation: The linear equation will be in the form y = b0 + b1 * x, where y is the predicted value, x is the input variable, and b0 and b1 are the intercept and slope, respectively.
6. Predict the linear regression score: Use the linear equation to predict the value of y for any given value of x by plugging in the x value into the equation. The resulting y value is your predicted linear regression score.
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let x equals negative 14 times pi over 3 period part a: determine the reference angle of x. (4 points) part b: find the exact values of sin x, tan x, and sec x in simplest form. (6 points)
The exact values of sin x, tan x and sec x in simplest form are: sin x = -√3/2, tan x = √3, sec x = -2/√3.
To solve this problem, we'll work with the angle x, which is equal to -14π/3. Part a: Determine the reference angle of x. The reference angle is the positive acute angle formed between the terminal side of the angle and the x-axis. To find the reference angle, we ignore the negative sign and convert the angle to its equivalent positive angle within one revolution.
The positive equivalent angle can be obtained by adding 2π (or 360 degrees) repeatedly until we obtain a positive angle. In this case, we have: -14π/3 + 2π = -14π/3 + 6π/3 = -8π/3. The reference angle of x is 8π/3. Part b: Find the exact values of sin x, tan x, and sec x in simplest form. sin x = sin(-14π/3) = -sin(14π/3) (Using the symmetry of sine function)
= -sin(4π + 2π/3) (Dividing by 4π to obtain an angle within one revolution)
= -sin(2π/3) (Sine of an angle 2π/3 is known) = -√3/2.
tan x = tan(-14π/3) = tan(14π/3) (Using the symmetry of tangent function)
= tan(4π + 2π/3) (Dividing by 4π to obtain an angle within one revolution)
= tan(2π/3) (Tangent of an angle 2π/3 is known)= √3. sec x = sec(-14π/3) = sec(14π/3) (Using the symmetry of secant function)= sec(4π + 2π/3) (Dividing by 4π to obtain an angle within one revolution)= sec(2π/3) (Secant of an angle 2π/3 is known)= -2/√3. Therefore, the exact values in simplest form are: sin x = -√3/2, tan x = √3, sec x = -2/√3.
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Answer: The exact values of sin x, tan x and sec x in simplest form are: sin x = -√3/2, tan x = √3, sec x = -2/√3.
Step-by-step explanation: To solve this problem, we'll work with the angle x, which is equal to -14π/3. Part a: Determine the reference angle of x. The reference angle is the positive acute angle formed between the terminal side of the angle and the x-axis. To find the reference angle, we ignore the negative sign and convert the angle to its equivalent positive angle within one revolution.
The positive equivalent angle can be obtained by adding 2π (or 360 degrees) repeatedly until we obtain a positive angle. In this case, we have: -14π/3 + 2π = -14π/3 + 6π/3 = -8π/3. The reference angle of x is 8π/3. Part b: Find the exact values of sin x, tan x, and sec x in simplest form. sin x = sin(-14π/3) = -sin(14π/3) (Using the symmetry of sine function)
= -sin(4π + 2π/3) (Dividing by 4π to obtain an angle within one revolution)
= -sin(2π/3) (Sine of an angle 2π/3 is known) = -√3/2.
tan x = tan(-14π/3) = tan(14π/3) (Using the symmetry of tangent function)
= tan(4π + 2π/3) (Dividing by 4π to obtain an angle within one revolution)
= tan(2π/3) (Tangent of an angle 2π/3 is known)= √3. sec x = sec(-14π/3) = sec(14π/3) (Using the symmetry of secant function)= sec(4π + 2π/3) (Dividing by 4π to obtain an angle within one revolution)= sec(2π/3) (Secant of an angle 2π/3 is known)= -2/√3. Therefore, the exact values in simplest form are: sin x = -√3/2, tan x = √3, sec x = -2/√3.
Please can someone help me?
Answer:
Step-by-step explanation:
please help me .........
Answer: the answer is b
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
first add them together. the y cancels out and your left with 3x=15. divide by 3 on both sides and you get x=5. The only answer with positive 5 as an x value is b
Write the Central Limit Theorem for sample means. 3. The average time taken to complete a project in a real estate company is 18 months, with a standard deviation of 3 months. Assuming that the project completion time approximately follows a normal distribution, find the probability that the mean completion time of 4 such projects falls between 16 and 19 months.
The probability that the mean completion time of 4 projects falls between 16 and 19 months is approximately 0.6568 or 65.68%.
The Central Limit Theorem states that for a sufficiently large sample size, the distribution of sample means will approach a normal distribution regardless of the shape of the population distribution.
Specifically, if we have a random sample of n observations drawn from a population with mean μ and standard deviation σ, then the distribution of the sample means will have a mean equal to the population mean μ and a standard deviation equal to the population standard deviation σ divided by the square root of the sample size n.
In this case, the average time taken to complete a project in the real estate company is 18 months, with a standard deviation of 3 months.
Assuming that the project completion time approximately follows a normal distribution, we can use the Central Limit Theorem to find the probability that the mean completion time of 4 such projects falls between 16 and 19 months.
First, we need to calculate the standard deviation of the sample mean. Since we have 4 projects, the sample size is n = 4.
Therefore, the standard deviation of the sample mean is σ/√n = 3/√4 = 3/2 = 1.5 months.
Next, we can standardize the values of 16 and 19 months using the formula z = (x - μ) / (σ/√n), where x is the value, μ is the population mean, σ is the population standard deviation, and n is the sample size.
For 16 months: z1 = (16 - 18) / (1.5) = -2/1.5 = -1.33
For 19 months: z2 = (19 - 18) / (1.5) = 1/1.5 = 0.67
Using a standard normal distribution table, we can look up the probabilities corresponding to the z-scores -1.33 and 0.67.
The table provides the cumulative probabilities for values up to a certain z-score.
For -1.33, the cumulative probability is approximately 0.0918.
For 0.67, the cumulative probability is approximately 0.7486.
To find the probability between these two z-scores, we subtract the cumulative probability associated with -1.33 from the cumulative probability associated with 0.67:
P(-1.33 < Z < 0.67) = 0.7486 - 0.0918 = 0.6568
Therefore, the probability that the mean completion time of 4 projects falls between 16 and 19 months is approximately 0.6568 or 65.68%.
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Use the image provided to answer please
The population of a city is 218720.
The population has been increasing at the rate of 2% per year.
What was the population 3 years ago?