Let f(x)=x^2-6 and g(x)=7x
Please help thank you

Answer:

434 [tex]cm^3[/tex]

Step-by-step explanation:

volume of bottom: 6 x 10 x 5 = 300 [tex]cm^3[/tex]

volume of top:

[tex]V = (\frac{4}{3}\pi r^3)/2\\\\= (\frac{4}{3}\pi(4)^3)/2\\[/tex]

≈ 134.041 [tex]cm^3[/tex]

300 + 134.041 = 434.041

they want to the nearest tenth, so it would just be 434.0

Answer:

I think 7

Step-by-step explanation:

if the moon is purple then what toothpaste do u use on your but

Answer:

x = -1/2y+2

Step-by-step explanation:

4x+2y=8

Step 1: Add -2y to both sides.

4x+2y+−2y=8+−2y

4x=−2y+8

Step 2: Divide both sides by 4.

4x/4 = -2y+8/4

x = -1/2y+2

Hope this helps!

Answer: hey bro i can solve this for you but you need to show the quadrilateral. without it i can't solve it.

Step-by-step explanation:

Answer:If the figure is a square with a perimeter of 16 inches, then each side of the square is 4 inchest in length.

Step-by-step explanation:

Answer:

The length of each side is 4 inches.

Step-by-step explanation:

Since the shape is a square, all sides are equal so you do 16÷4 since there are 4 sides to get your answer of 4 inches.

9514 1404 393

Answer:

  1.3

Step-by-step explanation:

The two points are on the same vertical line, so the distance between them is the distance between their y-coordinates:

  2.5 -1.2 = 1.3

The distance between the two points is 1.3 units.

Answer:

90%

Step-by-step explanation:

Answer:

(3x+5)+(2x) = 90

5x + 5 = 90

5x = 85

x = 17

YVZ = 3×17 +5

=56°

Answer:

Volume=3418.1 ft²

Step-by-step explanation:

Volume:π r² h

r=8 ft

h=17ft

π×8²×17

=3418.052 ft³

=3418.1 ft³

hope it helps...

Answer:

x = 6.5

Step-by-step explanation:

Reference angle = 54°

Length of Side opposite to 54° = x

Hypotenuse = 8 cm

Recall: SOHCAHTOA.

Apply SOH:

Sin 54 = Opp/Hyp

Sin 54 = x/8

x = 8*sin 54

x = 6.47213595 ≈ 6.5 cm (nearest tenth)

Answer:

c Melindas account will have about 5.40 more than olivia's account

Step-by-step explanation:

Answer:

The first thing we need to do is to find the area bounded by:

y = x^3

y = 0

between:

x = 0 and x = 2

This is the integral of the given function between x = 0 and x = 2, written as:

[tex]\int\limits^2_0 {x^3} \, dx = \frac{2^4}{4} - \frac{0^4}{4} = 2^2 = 4[/tex]

This means that the area of the bounded region is 4 square units.

Now, if we do a full rotation around the x-axis, the volume generated will be equal to the area that we obtained times 2*pi units.

The volume is:

V = (4 square units)*(2*pi units) = 8*pi cubic units.

(Notice that no option coincides with this, there may be a mistake in the options)

Answer:

Arithmetic Sequence

Step-by-step explanation:

In Arithmetic sequence each term increases by adding/subtracting some constant k. This is in contrast to a geometric sequence where each term increases by dividing/multiplying some constant k.

Answer:

392 ft²

Step-by-step explanation:

The composite figure can be divided into a rectangle, 2 triangles and a square

Area of rectangle = Length * width

Area of rectangle = 21 feets * 14 feets = 294 feet²

Area of triangle = 0.5 * base * height

Area of triangle = 0.5 * 7 * 7 = 24.5

AREA of square = a² = 7² = 49 feets²

Total area :

294 feets + (2 * 24.5) feets² + 49 feets²

294 + 49 + 49 = 392 ft²

Answer:

let's say coconut trees is X is there from mango trees will be 2X

Step-by-step explanation:

2x+x=1320

3x=1320

divide both sides by three

3x/3=1320/3

x=440(coconut)

2x=880(mango)

Answer:

1.-Then we p-value indicates that we are in the rejection region we reject H₀

We support the claim of the garbage collector the average picking up more than 4 tn of garbage

2.- p  = 75 %

3.-3.-t(s) is in the rejection region we accept H₀ we have not evidence to support Marc´s claim

Step-by-step explanation:

1.- If p-value is 0,04   and significance level α = 5 %  or  α = 0,05 then p-value < α

Test hypothesis should be    ( x the average of garbage)      

Null hypothesis          H₀           x = 4 Tn

Alternative Hypothesis     Hₐ    x  > 4 Tn

Then  alternative hypothesis suggests a one tail-test to the right  and

p-value <  0,05

Then we p-value indicates that we are in the rejection region we reject H₀

We support the claim of the garbage collector the average picking up more than 4 tn of garbage

2.- As we are dealing with a normal distribution the CI  95 % is symmetrical with respect to the mean, therefore the proportion of student living in Brooklyn is:  

(0,73 + 0,77) /2

p = 0,75     p  = 75 %

Test hypothesis:

Null Hypothesis            H₀            μ    =  26

Alternative Hypothesis      Hₐ      μ   <  26

Alternative hypothesis tells us the test is a one-tail test to the left

Sample size   n = 25

Sample mean   μ  =  24,4

Sample Standard deviation  =  9,2

We assume normal distribution, and as n < 30 we use t-student table

with  24 degree of freedom

Significance level is 0,05  and df = 24  we find t (c)  in t- student table

t(c) = 1,7109      test to the left   t(c) = -1,7109

To calculate  t(s)

t(s)  =  (  24,4 - 26 ) / 9,2 / √25

t(s) =  - 1,6 * 5 / 9,2

t(s) = - 0,87

Comparing t(s)  and t(c) we have

t(s) > t(c)

t(s) is in the rejection region we accept H₀ we have not evidence to support Marc´s claim

Answer:

Electrician = 44

Plumber = 22

Step-by-step explanation:

Let :

Electrician Hourly wage = x

Plumber's hourly wage = y

Average = 33

(x + y ) /2 = 33

x + y = 66 - - - - (1)

7x + 4y = 396 - - - (2)

From (1)

x = 66 - y

Put x = 66 - y in (2)

7(66-y) + 4y = 396

462 - 7y + 4y = 396

-3y = - 66

y = 22

x = 66 - 22

x = 44

Electrician = 44

Plumber = 22

The fourth option is indeed correct on Edge 2021.

The graph that represents the system of nonlinear inequalities is graph (a)

The nonlinear inequalities are given as:

[tex]y \le x^2 - 1[/tex]

[tex]x > y^2 - 6[/tex]

Rewrite the above nonlinear inequalities as:

[tex]y - x^2 \le - 1[/tex]

[tex]x -y^2 > -6[/tex]

[tex]y - x^2 \le - 1[/tex] means that the inequality has a solid line, and the outside part is shaded

[tex]x -y^2 > -6[/tex] means that the inequality has a dotted line, and the inner part is shaded

So, the graph that represents the system of nonlinear inequalities is graph (a)

Read more about the system of nonlinear inequalities at:

https://brainly.com/question/9248293

Answer:

[tex]=13.6[/tex]

Step-by-step explanation:

[tex]\mathrm{Remove\:parentheses}:\quad \left(a\right)=a[/tex]

[tex]=4\left(3.4+2\right)-\frac{56}{7}[/tex]

[tex]=21.6-8[/tex]

[tex]\mathrm{Subtract\:the\:numbers:}\:21.6-8=13.6[/tex]

[tex]=13.6[/tex]

Answer:

CI 99% = (  0,022  ;  0,126 )

Step-by-step explanation:

First sample  

n₁  = 500

x₁  = 48

p₁ = x₁ / n₁   =  48 / 500      p₁  =  0,096      p₁  = 9,6 %

Second sample

n₂  = 400

x₂  = 68

p₂ = x₂ / n₂   =  68 / 400      p₂  =  0,17       p₂  = 17 %

CI = 99 %    significance level α = 1 %     α  = 0,01

z(c)  for α = 0,01  is from z- table    z(c) = 2,325

CI  =  ( p₂ - p₁ ) ±  z(c) *√ p*q* ( 1/n₁  +  1 / n₂ )

Where

p₂  -  p₁  =  0,17 - 0,096 = 0,074

p = ( x₁ + x₂ )  / n₁ + n₂

p =  ( 48  +  68  ) /( 500 + 400)

p = 116/ 900     p = 0,1288     and   q = 1 - p     q  = 0,8712

z(c) *√ p*q* ( 1/n₁  +  1 / n₂ ) = 2,325 * √ 0,1288*0,8712 ( 1 / 500 + 1/ 400)

2,235 * 0,02247

z(c) *√ p*q* ( 1/n₁  +  1 / n₂ ) = 0,052

Then

CI 99 %  =  0,074  ±  0,052

CI 99% = (  0,022  ;  0,126 )

The difference between the groups shows that the proportion in the second group was bigger than in the first group.

The CI in the context of the problem is  CI 99% = (  0,022  ;  0,126 )

Given first sample is  

n₁  = 500

x₁  = 48

  [tex]P_{1} =\dfrac{X_{1} }{n_{1} }[/tex]      [tex]P_{1} =\dfrac{48}{500}[/tex]      

p₁  =  0,096      p₁  = 9,6 %

Given second sample

n₂  = 400

x₂  = 68

[tex]P_{2} =\dfrac{X_{2} }{n_{2} }[/tex]      [tex]P_{2} =\dfrac{68}{400}[/tex]        

p₂  =  0,17       p₂  = 17 %

Since given CI = 99 %    so significance level  α = 1 %     α  = 0,01

From Z-Table  z(c)  for α= 0,01  is = 2,325

CI  =   [tex](P_{2} -P_{1}[/tex]   ±    [tex]Z(c)\sqrt[2]{p\times q} (\dfrac{1}{n_{1} } +\dfrac{1}{n_{2} } )[/tex]  

Where

p₂  -  p₁  =  0,17 - 0,096 = 0,074

[tex]P= \dfrac{X_{1} +X_{2} }{n_{1}+n_{2} }[/tex]

[tex]P=\dfrac{48+68}{500+400}[/tex]

[tex]P=\dfrac{116}{900}[/tex]

p = 0,1288     and   q = 1 - p     q  = 0,8712

[tex]Z(c)\sqrt[2]{p\times q} (\dfrac{1}{n_{1} } +\dfrac{1}{n_{2} } )[/tex]  [tex]2325\times\sqrt[2]{0.1288\times 0.8712} (\dfrac{1}{500_{} } +\dfrac{1}{400_{} } )[/tex]

  [tex]Z(c)\sqrt[2]{p\times q} (\dfrac{1}{n_{1} } +\dfrac{1}{n_{2} } )=0.052[/tex]

Then

CI 99 %  =  0,074  ±  0,052

CI 99% = (  0,022  ;  0,126 )

Hence the difference between the groups shows that the proportion in the second group was bigger than in the first group.

To know more about Chi square follow

https://brainly.com/question/4543358

Answer:

D.82.8°

Step-by-step explanation:

Hope it helps

Have a great day

Answer:

The answer should be -12

Answer:

Step-by-step explanation:

Answer:

Step-by-step explanation:

Part A

we have to solve the associated equation

4a^2 - 20a + 25 = 0

first of all we have to find the delta/4

Δ/4 = (b/2)^2 - ac  where a is the term that multiply a^2, b is the term that multiply a and c is the therm without the variable

Δ/4 = (-10)^2 -100 = 100-100 = 0

the delta is equal to 0 that is mean that the equation has two coincident solutions, that can be find thanks to this formula

a1,a2 = -b/2/a = 10/4 = 5/2

now we can factorize the trinomial in this way:

4(a-5/2)(a-5/2)

4[(2a-5)/2][(2a-5)/2]

(2a-5)(2a-5)

the side of the square is 2a-5

Part B

the area of the rectangle is expressed as difference by two squares, so it can be rewritten as

(3a+4b)(3a-4b)

so the dimension of the rectangle are

3a+4b and 3a-4b

Answer:

hi can i fu k u

Step-by-step explanation:

The answer is:

-0.5, -1.5

Answer:

= p× r²

= 3,14×7×7

= 21,98×7

= 153,86

[tex]153.86 \div 3.14 = 7[/tex]