Mhanifa can you please help? This is due asap!

Answer:

45cm

Step-by-step explanation:

3 x 5 x 3 x 1/2

(if im wrong im sorry)

Answer:

27

Step-by-step explanation:

3 x ((5) + 4)

3 x 9 =27

Answer:

I answered it on the second time you asked this question check it out

Answer:

312

Step-by-step explanation:

Answer:

739.47

Step-by-step explanation:

height - h, radius -r

V=hπ²r=5×3.14²×15=739.47

a) the value of the expression is 29.

b) the value of the expression is -3.

d) the value of the expression is 270.

a) To calculate the expression 4x2 + 3 + 6 - 2 + 7 X 2, follow the order of operations (PEMDAS/BODMAS):

4x2 = 8
7 X 2 = 14

Now we can substitute these values into the expression:

8 + 3 + 6 - 2 + 14

Performing the addition and subtraction from left to right:

= 11 + 6 - 2 + 14
= 17 - 2 + 14
= 15 + 14
= 29

Therefore, the value of the expression is 29.

b) To calculate the expression 4+2-6-1 - 7+ 12, again use the order of operations:

4 + 2 = 6
-7 + 12 = 5

Now we can substitute these values into the expression:

6 - 6 - 1 - 7 + 5

Performing the subtraction and addition from left to right:

= 0 - 1 - 7 + 5
= -1 - 7 + 5
= -8 + 5
= -3

Therefore, the value of the expression is -3.

c) To calculate the expression (-48 - 12) = (-3 + 11), perform the subtraction and addition:

-48 - 12 = -60
-3 + 11 = 8

Now we can substitute these values into the equation:

-60 = 8

The equation is not true since -60 is not equal to 8. Therefore, there is no solution to this equation.

d) To calculate the expression (-5)(6)(-9), perform the multiplication:

(-5)(6)(-9) = -30(-9)
= 270

Therefore, the value of the expression is 270.

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Answer:

No a triangle CAN’T have 2 obtuse angles. I dont know about the drop down menus since I can’t see the choices but there can’t be 2 obtuse angles in a triangle. I can guess two of them anyway

The second drop down one is “greater”

The last option is 180

Im not sure about he first since dropdowns aren’t presented

Answer:

The answer is x is greater than or equal to -2

Step-by-step explanation:

I just did the math by hand

Answer:  x ≤ -5

Step-by-step explanation:

3x - 11 ≥ 7x + 9

3x ≥ 7x + 20

-4x ≥ 20  when dividing negative numbers, change the sign to the opposite.

x ≤ -5

Answer:

D. the average difference in height between each player and the mean height

we are 99% confident that the true value of µ lies within the interval (12.5831, 13.9169).

We have a random sample from a normal distribution with mean µ and a true variance of 0.81.

From this sample of 16 values, the sample mean was 13.25.

We want to calculate the 99% confidence interval for µ.

We can use the t-distribution to calculate the confidence interval since the sample size is less than 30.

We need to find the t-value that corresponds to a 99% confidence interval and 15 degrees of freedom (n-1).

We can use a t-distribution table or calculator to find that the t-value is 2.9477.

Using this value, we can calculate the confidence interval as follows: Lower bound = sample mean - (t-value * standard error)Upper bound = sample mean + (t-value * standard error) The standard error is the standard deviation divided by the square root of the sample size.

So, in this case: Standard error = √(0.81/16) = 0.2025 Lower bound = 13.25 - (2.9477 * 0.2025) = 12.5831Upper bound = 13.25 + (2.9477 * 0.2025) = 13.9169Therefore, the 99% confidence interval for µ is (12.5831, 13.9169).

This means that if we repeated the process of taking a sample of 16 values many times and calculating a confidence interval each time, we would expect that 99% of those intervals would contain the true value of µ.

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Given: Sample size, n = 16, Sample mean, x = 13.25, Population variance, σ² = 0.81, Confidence level = 99%. The 99% confidence interval for the population mean, µ, is (12.676, 13.824). It means that if we repeat the process of drawing samples of size 16 from the same population infinite times and calculate the confidence intervals, then 99% of those confidence intervals will contain the true population mean.

Since the sample size is greater than 30 and we have a known population variance, we can use the z-distribution for finding the confidence interval for the population mean.

We can use the following formula to find the confidence interval at a given confidence level.

x - z(α/2) * σ/√n < µ < x + z(α/2) * σ/√n, Where z(α/2) is the z-value at α/2 level of significance.

z(α/2) can be found from the standard normal distribution table.

At 99% confidence level,

α = 1 - 0.99

= 0.01.

α/2 = 0.01/2

= 0.005.

At α/2 = 0.005 level of significance,

z(α/2) = 2.576

σ = √0.81

= 0.9

Substituting the values in the formula,

x - z(α/2) * σ/√n < µ < x + z(α/2) * σ/√n

13.25 - 2.576 * 0.9/√16 < µ < 13.25 + 2.576 * 0.9/√16

13.25 - 0.574 < µ < 13.25 + 0.57412.676 < µ < 13.824

Interpretation of Interval: The 99% confidence interval for the population mean, µ, is (12.676, 13.824).

It means that if we repeat the process of drawing samples of size 16 from the same population infinite times and calculate the confidence intervals, then 99% of those confidence intervals will contain the true population mean.

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Answer:

P = P (1 + r / n) ^ rt

Step-by-step explanation:

If a is a 7×9 matrix, the smallest possible dimension of nul A is 2. The correct option is a.

The smallest possible dimension of the null space (also known as the kernel) of matrix A depends on the rank of the matrix.

The rank of a matrix represents the maximum number of linearly independent rows or columns it contains.

In this case, we have a 7×9 matrix.

According to the rank-nullity theorem,

the dimension of the null space is given by the difference between the number of columns and the rank of the matrix.

The smallest possible dimension of the null space would be:

Dimension of null space = Number of columns - Rank of matrix

Since the matrix A has 9 columns, the smallest possible dimension of the null space would be:

Dimension of null space = 9 - Rank of matrix

The rank of the matrix can vary. It can range from 0 (if the matrix is a zero matrix) to a maximum of 7 (if all rows are linearly independent). So, depending on the rank, the smallest possible dimension of the null space can be any value between 9 and 2.

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Gauss-Seidel Method:
Iteration 1:
Starting with x(0) = [0, 0], we can substitute the initial values into the system of equations:
3(0) + 1(0) + 3x₂(1) + 6x₂(0) + 2x₂(0) = 0 -> 3x₂ = 0
3(0) + 3x₂(1) + 7x₂(0) = 4 -> 3x₂ = 4

Solving these equations, we find x(1) = [0, 4/3].

Iteration 2:
Using the updated values from the previous iteration, we have:
3x₁(1) + x₂(0) + 3x₂(1) + 6x₂(4/3) + 2x₂(4/3) = 0 -> 3x₁ + 16x₂ = -16/3
3x₁(1) + 3x₂(1) + 7x₂(4/3) = 4 -> 3x₁ + 19x₂ = 16/3

Solving these equations simultaneously, we obtain x(2) ≈ [-16/15, 8/15].

Iteration 3:
Using the updated values from the previous iteration:
3x₁(-16/15) + x₂(8/15) + 3x₂(-16/15) + 6x₂(8/15) + 2x₂(8/15) = 0 -> 3x₁ + 32x₂ = -16/5
3x₁(-16/15) + 3x₂(8/15) + 7x₂(8/15) = 4 -> 3x₁ + 19x₂ = 16/3

Solving these equations, we find x(3) ≈ [-16/35, 16/35].

After three iterations of the Gauss-Seidel method using the given initial value x(0) = [0, 0], we obtain an approximate solution of x(3) ≈ [-16/35, 16/35].

Jacobi's Method:

Iteration 1:
Starting with x(0) = [0, 0], we can update each component separately:
x₁(1) = (0 - (1(0) + 3x₂(0)) / 3 -> x₁ = 0
x₂(1) = (4 - (3x₁(0) + 7x₂(0))) / 3 -> x₂ = 4/3

Hence, x(1) = [0, 4/3].

Iteration 2:
Using the updated values from the previous iteration:
x₁(2) = (0 - (1(0) + 3x₂(4/3)) / 3 -> x₁ ≈ -16/15
x₂(2) = (4 - (3x₁(0) + 7x₂(4/3))) / 3 -> x₂ ≈ 8/15

Therefore, x(2) ≈ [-16/15, 8/15].

Iteration 3:
Using the updated values from the previous iteration:
x₁(3) = (0 - (1(-16/15) + 3x₂(8/15)) / 3 -> x₁ ≈ -16/35
x

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Answer: 3x-x+2=4

Step-by-step explanation:

12/X=3/6 CROSS MULTIPLY.

3X=12*6

3X=72 X=72/3 X= 24 FEET TALL.

Answer:

6

10

Step-by-step explanation:

30 5 6

70 7 10

Answer:

x =5, y = 4

Step-by-step explanation:

3x + 4y = 31..... (1)

2x - 4y = -6..... (2)

Adding equations (1) & (2)

[tex]3x + \cancel{4y} = 31 \\2x - \cancel{4y} = -6\\ - - - - - - - \\ 5x = 25 \\ x = \frac{25}{5} \\ \bold{ \purple{x = 5}} \\ plug \: x = 5 \: in \: eq \: (1) \\ 3(5) + 4y = 31 \\ 15 + 4y = 31 \\ 4y = 31 - 15 \\ 4y = 16 \\ y = \frac{16}{4} \\ \bold{ \red{y = 4}}[/tex]

A.) Similar?  YES  

Why or why not?  It is similar because as your can see in the picture above, it shows a large triangle and a small triangle. On the smaller triangle, the corner "G" has a degree of 67. On the larger triangle, the corner "P" has the same degree as the smaller one, therefore all the other corners have the same degree making the missing degree for "R" 34 degrees, and the missing "C" 79 degrees.  

If so, *similarity statement and scale factor: SF:  1.5  

*I didn't know what they meant by similarity statement

B.) Similar?  NO  

Why or why not?  The triangles are two totally different shapes, with totally different degree angles, making it totally different  

If so, *similarity statement and scale factor: SF:  2  

*I didn't know what they meant by similarity statement

C.) Similar?  NO  

Why or why not?  The triangles are two totally different shapes, with totally different degree angles, making it totally different  

If so, *similarity statement and scale factor: SF:  1.2  

*I didn't know what they meant by similarity statement

D.) Similar?  YES  

Why or why not?  They are the same shape; just with one enlarged and one decreased in size. They both have the same angle degree and everything else similar but the size of the shape.  

If so, *similarity statement and scale factor: SF:  2  

*I didn't know what they meant by similarity statement

**To find the scale factor you would have to divide the big number, to the smaller number... Like for figure D, the base of the BIG triangle is 56, and the small triangle is 28. 56 ÷ 28 = 2 Making 2 the SF (Scale Factor)

Answer:

c.32/3π units ³

Step-by-step explanation:

V= 4/3πr³

r=4/2=2units

V= 4/3π(2)³

V= 4/3π *8

V= 32/3π units ³

Answer:

V≈32/3

Step-by-step explanation:

V=4 /3πr3=4 /3·π·23≈33.51032

33.5/3.14=10.6

32/3=10.6

Please brainliest! I worked so hard!

Explanation: Its really similar to solving an equation, so all I did was add 2 to both sides :)

Answer: Its spring break relax PLS

Step-by-step explanation:

The given differential equation by undetermined coefficients is y'' - 10y' + 25y = 30x + 3. Its solution is as follows: Let us assume y = yh + yp where yh is the homogeneous solution and yp is the particular solution. To find the homogeneous solution, solve the following differential equation: y'' - 10y' + 25y = 0characteristic equation: r2 - 10r + 25 = 0(r - 5)2 = 0Thus, yh = c1e5x + c2xe5x

Now, let us find the particular solution by assuming the following particular solution: yp = Ax + B Substituting this into the differential equation: y'' - 10y' + 25y = 30x + 3 yields:-10A + 25B = 3, and0x + A = 30Solving for A and B: A = 30 and B = 15Thus, yp = 30x + 15Therefore, the general solution is:y = yh + yp = c1e5x + c2xe5x + 30x + 15, where c1 and c2 are arbitrary constants.

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Answer: No image? Incomplete question? FREE POINTS!

Step-by-step explanation:

BRAINLIEST PLEASE!

Answer:

S

=

{

(

−

2

,

5

)

}

Step-by-step explanation:

Answer:

1/2

Step-by-step explanation:

Hope it helps :)

Answer:

16.1, 16, 16

Step-by-step explanation:

1) we are going to do the mean :)

you add all the number together and divide by the same number

you should get 354/22 which is 16.0909....... since its round to tenth place, we place it at 16.1.

2)  median, for this one, you have to lay out the numbers and see which one is in the middle, in 14,15,16,17,19, 16 is the median.

3)  the number that appear the most is the mode, so right now we have

three 17s and six 16s, don't worry about the others because its not in the answer choice, so its 16.

Hope this helps :D

Here are the solutions to the given problems:

1. To find the sum of cells A1 and C3, we simply write the formula as: =SUM(A1,C3)

2. To find the sum of all rows from A5 to A27 using the range operator, we use the formula: =SUM(A5:A27)

3. To determine the largest value in cells D2 and D3, we use the formula: =MAX(D2,D3)

4. To find the number of numeric values from rows F5 to F21, cell G12, and cell H9, we use the formula: =COUNT(F5:F21,G12,H9)

The above formulas are used in Microsoft Excel for performing calculations.

Microsoft Excel is a popular spreadsheet program developed by Microsoft. It is a part of the Microsoft Office suite of productivity software, which also includes programs like Word, PowerPoint, and Outlook.

Excel provides a grid-based interface where users can organize and analyze data. The program uses a collection of cells arranged in rows and columns, forming a worksheet. Each cell can hold various types of data, such as numbers, text, dates, and formulas.

Excel offers a wide range of features and tools to perform calculations, create charts and graphs, manipulate data, and automate tasks. Users can enter data manually or import it from external sources, perform mathematical and statistical calculations, create formulas to link and manipulate data across cells, and use functions for various purposes.

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Answer:

19/21

Step-by-step explanation:

1×7+4×3/21

19/21