NO LINKS I will give brainliest, it’s a graph pls answer if you know how. Where are the smart people

Answer:

$800 in interest

Step-by-step explanation:

T = A(1 + rt)

T = 2,000(1 + .05(8))

T = 2,000(1.4)

T = 2800

2800 - 2000 = 800

Answer:

1.44m^3

Step-by-step explanation:

Given data

Number of balls= 8

Diameter of ball = 70cm = 0.7m

Radius= 35cm= 0.35m

We know that a ball has a spherical shape

The volume of a sphere is

V= 4/3πr^3

substitute

V= 4/3*3.142*0.35^3

V= 0.18m^3

Hence if 1 ball has a volume of 0.18m^3

Then 8 balls will have a volume of

=0.18*8

=1.44m^3

Answer:

let's divide the figure into two parts.

radius of the semicircle is 3.5m. two semi-circles make a circle and

area of circle=pi×r²

area of circle=22/7×(3.5m)2².

area of circle=38.5m²

area of rectangle=length ×width

area of rectangle =18m×7m

area of rectangle =126m²

area pf figure =38.5m²+126m²

area of figure=164.5m²

Answer:

Equation is a quadratic equation (polynomial ax+by+c with highest degree 2), so it has two solutions.

Answer:

B. is correct because it only can go 1 way.

Step-by-step explanation:

The orange divisor(s) above are the prime factors of the number 7,776. If we put all of it together we have the factors 2 x 2 x 2 x 2 x 2 x 3 x 3 x 3 x 3 x 3 = 7,776. It can also be written in exponential form as 25 x 35.

Answer:

side a = Smallest = 9 inches

side b = 18 inches

side c = 17 inches

Step-by-step explanation:

The formula for the perimeter of a triangle = side a + side b + side c

side a = Smallest

The perimeter of a triangle is 44 inches.

The length of one side is twice the length of the shortest side

Hence:

b = 2a

The length of the other side is eight inches longer than the length of the shortest side.

Hence,

c = 8 + a

Hence, we substitute into the Intial formula

a + 2a + 8 + a = 44 inches

4a + 8 = 44

4a = 44 - 8

4a = 36

a = 36/4

a = 9 inches

Solving for b

b = 2a

b = 2 × 9 inches = 18 inches

Solving for c

c = a + 8

c = 9 inches + 8 = 17 inches

The approximation of the integral ∫cos(x³ - 5) dx using composite Simpson's rule with n = 3 is approximately 1.01259.

The integral ∫cos(x³ - 5) dx using composite Simpson's rule with n = 3, we need to divide the integration interval into smaller subintervals and apply Simpson's rule to each subinterval.

The formula for composite Simpson's rule is

I ≈ (h/3) × [f(x₀) + 4f(x₁) + 2f(x₂) + 4f(x₃) + ... + 2f([tex]x_{n-2}[/tex]) + 4f([tex]x_{n-1}[/tex]) + f([tex]x_{n}[/tex])]

where h is the step size, n is the number of subintervals, and f([tex]x_{i}[/tex]) represents the function value at each subinterval.

In this case, n = 3, so we will have 4 equally-sized subintervals.

Let's assume the lower limit of integration is a and the upper limit is b. We can calculate the step size h as (b - a)/n.

Since the limits of integration are not provided, let's assume a = 0 and b = 1 for simplicity.

Using the formula for composite Simpson's rule, the approximation becomes:

I ≈ (h/3) [f(x₀) + 4f(x₁) + 2f(x₂) + 4f(x₃) + f(x₄)]

For n = 3, we have four equally spaced subintervals:

x₀ = 0, x₁ = h, x₂ = 2h, x₃ = 3h, x₄ = 4h

Using these values, the approximation becomes:

I ≈ (h/3) × [f(0) + 4f(h) + 2f(2h) + 4f(3h) + f(4h)]

Substituting the function f(x) = cos(x³ - 5):

I ≈ (h/3)  [cos((0)³ - 5) + 4cos((h)³ - 5) + 2cos((2h)³ - 5) + 4cos((3h)³ - 5) + cos((4h)³ - 5)]

Now, we need to calculate the step size h and substitute it into the above expression to find the approximation. Since we assumed a = 0 and b = 1, the interval width is 1.

h = (b - a)/n = (1 - 0)/3 = 1/3

Substituting h = 1/3 into the expression:

I ≈ (1/3)  [cos((-1)³ - 5) + 4cos((1/3)³ - 5) + 2cos((2/3)³ - 5) + 4cos((1)³ - 5) + cos((4/3)³ - 5)]

Evaluating the expression further:

I ≈ (1/3)  [cos(-6) + 4cos(-4.96296) + 2cos(-4.11111) + 4cos(-4) + cos(-3.7037)]

Approximating the values using a calculator, we get:

I ≈ 1.01259

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The scalar projection of b onto a is 5/9, and the vector projection of b onto a is (20/81, 35/81, -20/81).

To find the scalar and vector projections of vector b onto vector a, we can use the following formulas:

Scalar Projection:

The scalar projection of b onto a is given by the formula:

Scalar Projection = |b| * cos(θ)

Vector Projection:

The vector projection of b onto a is given by the formula:

Vector Projection = Scalar Projection * (a / |a|)

where |b| represents the magnitude of vector b, θ is the angle between vectors a and b, a is the vector being projected onto, and |a| represents the magnitude of vector a.

Let's calculate the scalar and vector projections of b onto a:

a = (4, 7, -4)

b = (4, -1, 1)

First, we calculate the magnitudes of vectors a and b:

|a| = √(4² + 7² + (-4)²) = √(16 + 49 + 16) = √81 = 9

|b| = √(4² + (-1)² + 1²) = √(16 + 1 + 1) = √18

Next, we calculate the dot product of vectors a and b:

a · b = (4 * 4) + (7 * -1) + (-4 * 1) = 16 - 7 - 4 = 5

Using the dot product, we can find the angle θ between vectors a and b:

cos(θ) = (a · b) / (|a| * |b|)

cos(θ) = 5 / (9 * √18)

Now, we can calculate the scalar projection:

Scalar Projection = |b| * cos(θ)

Scalar Projection = √18 * (5 / (9 * √18)) = 5 / 9

Finally, we calculate the vector projection:

Vector Projection = Scalar Projection * (a / |a|)

Vector Projection = (5 / 9) * (4, 7, -4) / 9 = (20/81, 35/81, -20/81)

Therefore, the scalar projection of b onto a is 5/9, and the vector projection of b onto a is (20/81, 35/81, -20/81).

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We can be 90% confident that the true difference between the mean daily calorie consumption of females in the September-February period and the mean daily calorie consumption of females in the March-August period falls within the range of 21460.3 to 23033.7 calories.

In this study conducted by a fitness magazine, two separate samples of females were chosen to investigate the difference in mean daily calorie consumption between two time periods: September-February and March-August. The first sample consisted of 265 females, and the second sample consisted of 220 females. The mean daily calorie consumption and standard deviations were calculated for each period. This information will be used to construct a confidence interval to estimate the difference between the mean daily calorie consumption of females in the two periods.

To construct a confidence interval for the difference between the mean daily calorie consumption of females in the September-February and March-August periods, we can use the formula:

Confidence Interval = (X₁ - X₂) ± (Z * SE)

Where:

X₁ and X₂ are the sample means of the two periods (September-February and March-August, respectively)

Z is the critical value associated with the desired confidence level (90% confidence level corresponds to Z = 1.645)

SE is the standard error of the difference between the means

First, let's calculate the sample means and standard deviations for each period:

For the September-February period: X₁ = 23873 calories, σ₁ = 192 (standard deviation), n₁ = 265 (sample size)

For the March-August period: X₂ = 2412.7 calories, σ₂ = 237.5 (standard deviation), n₂ = 220 (sample size)

Next, we calculate the standard error (SE) of the difference between the means using the formula:

SE = √((σ₁² / n₁) + (σ₂² / n₂))

Substituting the given values, we have:

SE = √((192² / 265) + (237.5² / 220))

Now, we can calculate the confidence interval using the formula mentioned earlier. With a 90% confidence level, the critical value Z is 1.645.

Substituting in the values, we get:

Confidence Interval = (23873 - 2412.7) ± (1.645 * SE)

Substituting the calculated value of SE, we can find the confidence interval:

Confidence Interval = (21460.3, 23033.7)

Therefore, we can be 90% confident that the true difference between the mean daily calorie consumption of females in the September-February period and the mean daily calorie consumption of females in the March-August period falls within the range of 21460.3 to 23033.7 calories.

Note: The confidence interval represents a range of values within which we believe the true difference lies, based on the given data and the selected confidence level.

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Answer:

x= 114, y= 66

Step-by-step explanation:

Opposite angles of a parallelogram are equal

The vector that is parallel to the line of intersection of the planes 4x - 3y + 2z = 12 and x + 5y - z = 7 is option (c) -7i + 6j + 23k.

To find a vector that is parallel to the line of intersection of two planes, we need to determine the direction of the line. This can be achieved by finding the cross product of the normal vectors of the planes.

The normal vector of the first plane 4x - 3y + 2z = 12 is (4, -3, 2), obtained by taking the coefficients of x, y, and z. Similarly, the normal vector of the second plane x + 5y - z = 7 is (1, 5, -1).

To find the cross product of these two normal vectors, we take their determinant: (4i, -3j, 2k) x (1i, 5j, -1k). Evaluating the determinant, we get (-23i - 6j - 13k).

The resulting vector -23i - 6j - 13k is parallel to the line of intersection of the planes. However, the given options only include positive coefficients for i, j, and k. To match the given options, we can multiply the vector by -1 to obtain a parallel vector. Thus, -(-23i - 6j - 13k) simplifies to -7i + 6j + 23k, which matches option (c). Therefore, option (c) -7i + 6j + 23k is the vector parallel to the line of intersection of the planes.

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z - 20x - 12y + 76 = 0 is the required equation of the plane that is tangent to the given surface at the point (5, 3, – 60).

Given the function is z=8-2x²-2y² and point is (5, 3, – 60).

We need to find the equation of the plane tangent to the given surface at the given point. The gradient vector of the function f(x, y, z) is given by(∂f/∂x)i + (∂f/∂y)j + (∂f/∂z)k∂f/∂x= -4x and ∂f/∂y= -4y

Therefore, the gradient vector is given by-4xi -4yj + k

Therefore, the equation of the tangent plane is given byz - z1=∇f(x1, y1) . (x - x1)i + ∇f(x1, y1) . (y - y1)j + (-1) [f(x1, y1, z1)]

where (x1, y1, z1) is the given pointWe have f(5, 3, – 60) = 8 – 2(5²) – 2(3²) = – 60

Therefore, the equation of the plane is given byz + 60= (-20i - 12j + k) . (x - 5) - (16i + 24j + k) . (y - 3)

Thus, z - 20x - 12y + 76 = 0 is the required equation of the plane that is tangent to the given surface at the point (5, 3, – 60).

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Answer:

Step-by-step explanation:

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1

cecewiliams23

08/12/2016

Mathematics

High School

answered

How many solutions does the equation 5x + 3x − 4 = 10 have

2

SEE ANSWERS

Answer

4.0/5

28

MathGeek289

Ambitious

236 answers

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This Must Only Have One Solution, Because The Right Side Of The Equation Is Just Plainly Ten. Lets Solve This:

5x + 3x - 4 = 10

Add Four To Both Sides To Begin Simplifying.

5x + 3x = 14

Now, Combine Like Terms.

8x = 14

Divide:

8x/8 = 1X = X

14/8

X = 14/8

14/8 = 1.75

X = 1.75

Check:

(5 * 1.75) + (3*1.75) - 4 = 10

8.75 + 5.25 - 4 = 10

14 - 4 = 10

10 = 10.

This Is True, So X Does Equal 1.75

Answer:

the solution to the system is (1,3)

Step-by-step explanation:

x = 1 , y = 3

Answer:

3x² – 5x + 2 is a polynomial because:

Exponents are whole numbers, and the expression has at least 1 term.

Exponents other than whole numbers can take the form of variables in denominators, and roots which we don't want.

Answer: D

Step-by-step explanation:

Answer:

reflection??.........

Answer:

they are congruent

Step-by-step explanation:

because they are the same size and have the smae area!

Answer:

0.43496 miles

Step-by-step explanation:

To convert from km to miles you can divide the km by 1.609 and that should give you an aproximate value for miles.

Answer:

Step-by-step explanation:

As each step has the same depth and rise, they are respectively 1.2/4=0.3m and 1.8/4=0.45m.

Dividing the steps along the dotted lines, the total rise of the 4 concrete steps  = (1+2+3+4)*0.45

= 4.5m

Total concrete volume = total rise * depth * width

= 4.5*0.3*1.8

= 2.43m^3

Answer:30

Step-by-step explanation:

The sum numbers are 1, 2, 4, 5, 8, 10, 20, 40

Therefore, x^2 - x^2cosθ + C = 0 is the general solution of the given differential equation.

General solution of the given differential equation is x^2 - x^2cosθ + C = 0, where C is the constant of integration.

To solve the differential equation, we have to integrate the given equation. Here, x sinθ dθ + (x^3 - 2x^2cosθ) dx = 0.

Let's integrate it using separation of variables.

x sinθ dθ = - (x^3 - 2x^2cosθ) dx

Dividing both sides by x^2, we get

sinθ dθ/x - (x - 2cosθ) dx/x^2 = 0

Now, integrate the above equation.

∫sinθ dθ/x - ∫(x - 2cosθ) dx/x^2 = ln|C|

Simplifying the above equation, we get

- cosθ/x + 1/x - x^(-1) sinθ = ln|C|

Multiplying both sides by -x, we get

cosθ - x + x^2 sinθ = -x ln|C|

Rearranging the terms, we get

x^2 - x^2cosθ + ln|C| = 0

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