PLEASE ANSWER SUPER QUICKLY! FASTEST ANSWER = BRAINLIEST

Mr. Inges teaches physical education at Longville High School. He wanted to determine if more students like to play soccer or basketball during their gym class. He surveyed 50 students. Of those who responded, 30 students said that they like to play soccer, 23 students said that they like to play basketball, while 5 students said that they do not like to play soccer nor basketball. If a student from the survey is selected at random and it is known (given) that he/she likes soccer, what is the probability he/she likes basketball? Show all work.

If each person gets the same number of signatures, 3x+23 > 80 is the inequality can Winston use to determine the minimum number of signatures each person should get so he can run for class president.

Winston needs at least 80 number of signatures from students in his school before he can run for class president. He has 23 signatures already. He and two of his friends plan to get the remaining signatures during lunch

Winston needs at least 80 signatures. Let y be the number of signatures Winston manages to obtain. Then y > 80

He and 2 of his friends obtain  number of signatures.

Then y = 3x + 23

Or, the required inequality is 3x + 23 > 80.

Correct option is (C).

Therefore, If each person gets the same number of signatures, 3x+23 > 80 is the inequality can Winston use to determine the minimum number of signatures each person should get so he can run for class president.

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We have two solutions for x:

x = -8 + 2√5

x = -8 - 2√5

To solve the equation [tex]x^2 + 16x + 44 = 0[/tex], we can use the given information that [tex]x^2 + 16x + 44 = (x+8)^2 - 20[/tex]. We rewrite the equation as:

(x+8)² - 20 = 0

Now, we need to solve for x:

(x+8)² = 20

Take the square root of both sides:

x + 8 = ±√20

Now, we can simplify √20:

√20 = √(4 * 5) = 2√5

Subtract 8 from both sides to solve for x:

x = -8 ± 2√5

So, we have two solutions for x:

x = -8 + 2√5

x = -8 - 2√5

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The distribution of W = Σ W_i/n is a normal distribution with mean μ and variance σ²/n, where Wi's are independent normal random variables with a common variance σ².

When you sum up independent normal random variables (W_i's), the resulting distribution (W) will also be normal.

The mean (μ) of the resulting distribution is the sum of the means of the individual Wi's divided by n, and the variance is the sum of the variances of the individual Wi's divided by n². Since Wi's have a common variance σ², the variance of W is σ²/n. Therefore, W follows a normal distribution with mean μ and variance σ²/n.

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Step-by-step explanation:

m = number of math books

s = number of science books

h = number of history books

m + h + s = 3s

m + h = 2s

s = m - 6

m + h = 2(m - 6) = 2m - 12

h = m - 12

and since s = m - 6, this also means

h = s - 6

that means, the number of History reference books is 12 less than the Mathematics reference books. which is then 6 less than the number of Science reference books.

Answer:

-2/3

Step-by-step explanation:

To find the slope of a line passing through two given points, we can use the slope formula:

slope = (y2 - y1) / (x2 - x1)

where (x1, y1) and (x2, y2) are the coordinates of the two points.

Using the coordinates (-5,-4) and (-2,-6), we have:

slope = (-6 - (-4)) / (-2 - (-5))

slope = (-6 + 4) / (-2 + 5)

slope = -2 / 3

Therefore, the slope of the line passing through the points (-5,-4) and (-2,-6) is -2/3.

The value of x is 9 and we get the answer by formula of sum of logarithm.

What is logarithm?

A logarithm is a mathematical function that helps to solve exponential equations. It is the inverse operation of exponentiation and is used to find the exponent to which a base must be raised to produce a given value. In other words, if [tex]y = {a}^{x} [/tex], then the logarithm of y with respect to base a is x, written as [tex]log_{a}(y) = x[/tex]

We can start by applying the logarithmic rule that says that the sum of logarithms with the same base is equal to the logarithm of the product of the arguments,

[tex] log_{6}(3x) + log_{6}((x - 1)) = log_{6}(3x(x - 1)) [/tex]

So we have the equation,

[tex]log_{6}(3 \times x(x - 1)) = 3[/tex]Using the definition of logarithms, we can rewrite this equation as,

6³= 3x(x - 1)

216 = 3x²- 3x

Simplifying further,

72 = x² - x

x² - x - 72 = 0

We can factor the left-hand side of this equation as (x - 9)(x + 8) = 0

Therefore, the possible values of x are 9 and -8. However, we must check whether these solutions are valid, as the logarithm function is only defined for positive arguments.

If x = 9, then both arguments of the logarithms are positive, so this is a valid solution.

If x = -8, then the first argument of the logarithm is negative, which is not allowed, so this is not a valid solution.

Therefore, the only solution of the equation is x = 9.

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If q = D(x) = 800 - 4x, then, the elasticity is E(x) = x / (200 - x). Therefore, option A. is correct.

To find the elasticity of demand, we will use the following terms in the answer: elasticity (E), demand function (D(x)), and quantity (q). We are given the demand function D(x) = 800 - 4x.

First, let's find the derivative of the demand function with respect to x, which represents the slope of the demand curve at any point x. We will call this derivative D'(x).
D'(x) = -4

Now, to find the elasticity (E), we use the formula:
E(x) = (x * D'(x)) / D(x)

Substitute the values of D'(x) and D(x) in the formula:
E(x) = (x * -4) / (800 - 4x)

Simplify the equation:
E(x) = (-4x) / (800 - 4x)

This is equivalent to option A:
E(x) = x / (200 - x)

So, the correct answer is A. E(x) = x / (200 - x).

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The center of mass of the point masses lying on the x-axis is at x = -0.89.

To find the center of mass of the point masses lying on the x-axis, we'll use the given masses (m1, m2, m3) and positions (X1, X2, X3). The center of mass equation for the x-axis is,

X_cm = (m1 * X1 + m2 * X2 + m3 * X3) / (m1 + m2 + m3)

Plug in the values for the masses and positions:
m1 = 9, m2 = 3, m3 = 7
X1 = -5, X2 = 0, X3 = 4

Calculate the numerator (m1 * X1 + m2 * X2 + m3 * X3):
(9 * -5) + (3 * 0) + (7 * 4) = -45 + 0 + 28 = -17

Calculate the denominator (m1 + m2 + m3):
9 + 3 + 7 = 19

Divide the numerator by the denominator to find the center of mass:
X_cm = -17 / 19 ≈ -0.89

So, the center of mass of the point masses lying on the x-axis is at x = -0.89.

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To find the area of a parallelogram, we need to multiply the length of one of its sides by its corresponding height. In this case, we can take AB or BC as the base and draw a perpendicular line from D to AB or BC as the height. Let's choose AB as the base.

The length of AB is sqrt((6-3)² + (-3--5)²) = sqrt(10), and the corresponding height is the distance from D to AB, which can be found by taking the absolute value of the cross product of the vectors AB and AD, divided by the length of AB. This gives us (1/2)|(-2)(-2) - (3)(1)|/√10) = 1/√(10). Therefore, the area of the parallelogram is sqrt(10)*1/sqrt(10) = 1. So, the area of the parallelogram with vertices A(-5, 3), B(-3, 6), C(1, 4), and D(-1, 1) is 1 square unit.

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the Laplace transform of the given function f(t) is:

[tex]F(s) = s^{-2}[(1 - s)e^{-2s} - (1 + s)e^{-3s}][/tex]

To find the Laplace change of the given capability, we really want to utilize the properties of the Laplace change and compose the capability in a reasonable structure.

First, let's write the function in a different way by expanding the terms and using the definition of the unit step function u(t):

[tex]f(t) = (t - 3)u2(t) - (t - 2)u3(t)\\= tu2(t) - 3u2(t) - tu3(t) + 2u3(t)\\= tu2(t) - tu3(t) - 3u2(t) + 2u3(t)[/tex]

Now, we can take the Laplace transform of each term separately using the linearity property of the Laplace transform:

[tex]L{tu2(t)} = -\frac{d}{ds}L{u2(t)} = -\frac{d}{ds}\frac{1}{s^2} = \frac{2}{s^3},L{tu3(t)} = -\frac{d}{ds}L{u3(t)} = -\frac{d}{ds}\frac{1}{s^3} = \frac{3}{s^4},L{u2(t)} = \frac{1}{s^2},L{u3(t)} = \frac{1}{s^3}.[/tex]

Using these results, we can write the Laplace transform of f(t) as:

[tex]F(s) = L{f(t)} = L{tu2(t)} - L{tu3(t)} - 3L{u2(t)} + 2L{u3(t)}\\= \frac{2}{s^3} - \frac{3}{s^4} - 3\frac{1}{s^2} + 2\frac{1}{s^3}\\= \frac{2 - 2s e^{-2s} - 3e^{-3s} + 3s e^{-3s}}{s^3}\\[/tex]

Simplifying the expression, we get:

[tex]F(s) = \frac{s e^{-3s} - se^{-2s} - 1 + e^{-3s}}{s^3}\\= \frac{s e^{-3s} - se^{-2s}}{s^3} - \frac{1 - e^{-3s}}{s^3}\\= s^{-2}[(1 - s)e^{-2s} - (1 + s)e^{-3s}][/tex]

Therefore, the Laplace transform of the given function f(t) is:

[tex]F(s) = s^{-2}[(1 - s)e^{-2s} - (1 + s)e^{-3s}][/tex]

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The area between the curves is approximately 109.7 square units.

To find the points of intersection, we set the two equations equal to each other and solve for x:

[tex]20 - x^2 = -3x - 20[/tex]

Adding[tex]x^2[/tex] and 3x to both sides, we get:

[tex]20 + 20 = x^2 + 3x[/tex]

Simplifying further:

[tex]x^2 + 3x - 40 = 0[/tex]

This is a quadratic equation, which we can solve using the quadratic formula:

[tex]x = (-3\pm \sqrt{(3^2 - 4(1)(-40)))} / (2(1))[/tex]

x = (-3 ± √169) / 2

x = (-3 ± 13) / 2

So the solutions are:

x = 5 or x = -8

Therefore, the points of intersection are (5, -95) and (-8, 44).

To find the top curve, we need to determine which of the two functions has a greater y-value in the region of interest.

We can do this by evaluating each function at the x-values of the points of intersection:

[tex]y = 20 - x^2At x=5, y = 20 - 5^[/tex]2 = -5

[tex]At x=-8, y = 20 - (-8)^2 = -44[/tex]

y = -3x - 20

At x=5, y = -3(5) - 20 = -35

At x=-8, y = -3(-8) - 20 = 4

So the equation for the top curve is y = -3x - 20.

To find the area between the curves, we integrate the difference between the two curves with respect to x, over the interval where the top curve is given by y = -3x - 20:

[tex]A = \int (-8 to 5) [(-3x - 20) - (20 - x^2)] dx[/tex]

[tex]A = \int (-8 to 5) [-x^2 - 3x - 40] dx[/tex]

[tex]A = [-x^3/3 - (3/2)x^2 - 40x][/tex] from -8 to 5

A = [(125/3) - (75/2) - 200] - [(-512/3) + (192/2) + 320]

A = 333/3 - 4/3

A = 109.7 (rounded to 1 decimal place).

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Of the two ratios, the ratio that is a rate is 260 miles/8 gallons

From the question, we have the following parameters that can be used in our computation:

260 miles/8 gallons

260 miles/8 miles

As a general rule

Rates are used to compare quantities of different measurements

Hence, the ratios that is a rate is 260 miles/8 gallons

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If I ran Levene's test in SPSS and I received a 0.477 that means Homogeneity can be assumed. So, correct option is C.

Levene's test is a statistical test used to determine whether or not the variances of two or more groups are equal. The null hypothesis (H0) for Levene's test is that the variances are equal across all groups.

When running Levene's test in SPSS, the output will include a p-value. This p-value represents the probability of obtaining a test statistic as extreme or more extreme than the one observed, assuming that the null hypothesis is true.

In this case, a Levene's test result of 0.477 suggests that the p-value is greater than 0.05. This means that there is not enough evidence to reject the null hypothesis. Therefore, the assumption of homogeneity of variances can be made, and it is appropriate to use tests such as ANOVA or t-tests that assume equal variances.

A Levene's test result of 0.477 indicates that homogeneity of variances can be assumed, and there is no need to redo the study or reject the null hypothesis.

In conclusion, option c is the correct answer.

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The transfer function of Buck 1 converter is:

[tex]H1(s) = Vout1(s) / Vin1(s) = D / (1 - D) / (s + (R1 * (1 - D)) / (L1 * (1 - D) * C1))[/tex]

The transfer function of Buck 2 converter is:

[tex]H2(s) = Vout2(s) / Vin2(s) = D / (1 - D) / (s + (R2 * (1 - D)) / (L2 * (1 - D) * C2))[/tex]

To derive the open-loop transfer function of the cascaded system, we can find the transfer function of each converter separately and then multiply them.

For Buck 1 converter:

The output voltage Vout1 can be expressed as:

[tex]Vout1 = D * Vin1 / (1 - D) * (1 - exp(-t / (L1 * R1 * (1 - D) * C1)))[/tex]

where D is the duty cycle, Vin1 is the input voltage, L1 and C1 are the inductance and capacitance of the converter, R1 is the resistance of the load, and t is the time.

Taking the Laplace transform of the equation above, we get:

[tex]Vout1(s) = (D * Vin1 / (1 - D)) / (s + (R1 * (1 - D)) / (L1 * (1 - D) * C1))[/tex]

The transfer function of Buck 1 converter is:

[tex]H1(s) = Vout1(s) / Vin1(s) = D / (1 - D) / (s + (R1 * (1 - D)) / (L1 * (1 - D) * C1))[/tex]

For Buck 2 converter:

The output voltage Vout2 can be expressed as:

[tex]Vout2 = D * Vin2 / (1 - D) * (1 - exp(-t / (L2 * R2 * (1 - D) * C2)))[/tex]

where D is the duty cycle, Vin2 is the input voltage, L2 and C2 are the inductance and capacitance of the converter, R2 is the resistance of the load, and t is the time.

Taking the Laplace transform of the equation above, we get:

[tex]Vout2(s) = (D * Vin2 / (1 - D)) / (s + (R2 * (1 - D)) / (L2 * (1 - D) * C2))[/tex]

The transfer function of Buck 2 converter is:

[tex]H2(s) = Vout2(s) / Vin2(s) = D / (1 - D) / (s + (R2 * (1 - D)) / (L2 * (1 - D) * C2))[/tex]

The open-loop transfer function of the cascaded system is the product of the transfer functions of the two converters:

[tex]H(s) = H1(s) * H2(s) = D^2 / (1 - D)^2 / [(s + (R1 * (1 - D)) / (L1 * (1 - D) * C1)) * (s + (R2 * (1 - D)) / (L2 * (1 - D) * C2))][/tex]

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By answering the presented question, we may conclude that  Other commands might be used to achieve the same outcome, but these are the most commonly used.

In mathematics, you can multiply, divide, add, or subtract. An expression is constructed as follows: Number, expression, and mathematical operator A mathematical expression is made up of numbers, variables, and functions (such as addition, subtraction, multiplication or division etc.) It is possible to contrast expressions and phrases. An expression or algebraic expression is any mathematical statement that has variables, integers, and an arithmetic operation between them. For example, the phrase 4m + 5 has the terms 4m and 5, as well as the provided expression's variable m, all separated by the arithmetic sign +.

The following RISC-V instructions can be used to accomplish the NOR operation between registers X5 and X6 and store the result in register X7:

 OR   t0, x5, x6     // t0 = X5 | X6

 NOT  t0, t0         // t0 = ~(X5 | X6)

 ADDI x7, x0, 0      // zero out X7

 XOR  x7, t0, x7     // X7 = ~(X5 | X6)

The following RISC-V instructions can be used to accomplish the NOR operation between registers X8 and X9 and store the result in register X7:

 // X7 = ~(X8 | X9)

 OR   t0, x8, x9     // t0 = X8 | X9

 NOT  t0, t0         // t0 = ~(X8 | X9)

 ADDI x7, x0, 0      // zero out X7

 XOR  x7, t0, x7     // X7 = ~(X8 | X9)

The NOR result is calculated using bitwise OR and NOT operations, and the result is stored in the destination register using XOR. Before executing the XOR operation, the ADDI instruction is used to set the destination register to zero. Other commands might be used to achieve the same outcome, but these are the most commonly used.

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The given series is equivalent to the sum of two p-series: ∑n^(-1/2) + ∑n^(-2). Where the first series converges since p1 = 1/2 > 0 and the second series also converges since p2 = 2 > 1.

To start, we can simplify the given series as:

sqrt(n+4)/n^2 = 1

Taking the reciprocal of both sides:

n^2/sqrt(n+4) = 1

Multiplying both sides by sqrt(n+4):

n^2 = sqrt(n+4)

Squaring both sides:

n^4 = n+4

This is a quadratic equation that we can solve using the quadratic formula:

n = (-1 ± sqrt(17))/2

Since we are only interested in positive integer values of n, we take the larger root:

n = (-1 + sqrt(17))/2 ≈ 1.56

Now that we have found the value of n that satisfies the equation, we can rewrite the given series in terms of p-series:

sqrt(n+4)/n^2 = (n+4)^(1/2) / n^2
= (1 + 4/n)^(1/2) / n^2

Using the formula for the p-series:

∑n^-p = 1/1^p + 1/2^p + 1/3^p + ...

We can see that the given series is equivalent to:

(1 + 4/n)^(1/2) / n^2 = n^(-2) * (1 + 4/n)^(1/2)
= n^(-p1) + n^(-p2)

Where p1 is the smaller value and p2 is the larger value of p that make up the two p-series.

We can find p1 and p2 by comparing the exponents of n on both sides of the equation:

p1 = 1/2
p2 = 2

Therefore, the given series is equivalent to the sum of two p-series:

∑n^(-1/2) + ∑n^(-2)

Where the first series converges since p1 = 1/2 > 0 and the second series also converges since p2 = 2 > 1.

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The answer to if {an} and {bn} are divergent, then {an + bn} is divergent is b is False.

This statement is not always true. While it may be true in some cases, there are instances where both {an} and {bn} can be divergent, but their sum {an + bn} converges.

For example, let an = n and bn = -n.

Both {an} and {bn} are divergent, as n and -n go to infinity and negative infinity, respectively. However, when you add them together, {an + bn} becomes {n + (-n)}, which simplifies to {0} for all values of n. In this case, {an + bn} converges to 0.

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Answer:

  y ∈ ℝ

Step-by-step explanation:

You want the solution to the equation 0.4(3y + 18) = 1.2y + 7.2.

The parentheses can be removed by making use of the distributive property.

  0.4(3y + 18) = 1.2y + 7.2 . . . . . . given

  0.4(3y) +0.4(18) = 1.2y +7.2

  1.2y +7.2 = 1.2y +7.2 . . . . . . . . . true for any value of y

The set of solutions for y is all real numbers.

__

Additional comment

Actually, the solution set is "all complex numbers" as well as any other entities for which multiplication and addition with scalars are defined. For example, y could be a matrix of complex numbers, and the equation would still be true.

To calculate the Mean Absolute Deviation (MAD) using the given demand and forecast values.

The MAD is the average of the absolute differences between actual demand (A) and forecast (F).

Here are the steps to calculate MAD:
1. Calculate the absolute differences between actual demand and forecast for each observation.
2. Add up all the absolute differences.
3. Divide the sum of absolute differences by the number of observations.

Let's apply these steps to your data:

1. Calculate the absolute differences:
  - Observation 2: |30 - 35| = 5
  - Observation 3: |26 - 30| = 4
  - Observation 4: |34 - 26| = 8
  - Observation 5: |28 - 34| = 6
  - Observation 6: |38 - 28| = 10

2. Add up the absolute differences:
  5 + 4 + 8 + 6 + 10 = 33

3. Divide the sum of absolute differences by the number of observations (excluding the first one since there's no forecasting value for it):
  MAD = 33 / 5 = 6.6

So, the Mean Absolute Deviation (MAD) for the given data is 6.6.

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There are 216 PTA members involved this year.

The problem states that the enrollment in the PTA (Parent-Teacher Association) increased by 35% this year. We need to calculate how many members are involved this year given that there were 160 members last year.

To calculate the increase in membership, we need to find 35% of 160. We can do this by multiplying 160 by 0.35, which gives us 56.

Now we need to add this increase to the number of members last year to find the total number of members involved this year.

160 + 56 = 216

Therefore, there are 216 PTA members involved this year.

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To use the two-phase method to maximize z = x1 3x3 subject to the constraints, we first need to convert the problem into standard form. This involves introducing slack variables to represent the inequalities as equations and adding a non-negative variable for each constraint. In this case, we have:
maximize z = x1 - 3x3
subject to:-x1 + x2 = 0x3 + x4 = 5x1, x3, x4 ≥ 0

We can now apply the two-phase method, which involves two steps.
Step 1: Initialization phase
In this phase, we introduce artificial variables for each equation and set up an auxiliary problem to find a feasible solution. We then use the solution to the auxiliary problem to initialize the simplex method for the original problem. The auxiliary problem is:
maximize w = -x5 - x6
subject to:
-x1 + x2 + x5 = 0
x3 + x4 + x6 = 5
x1, x3, x4, x5, x6 ≥ 0
Solving this problem using the simplex method, we get a feasible solution at (x1, x2, x3, x4, x5, x6) = (0, 0, 5, 0, 0, 5).
Step 2: Optimization phase
In this phase, we use the simplex method to optimize the original problem by maximizing z = x1 - 3x3. We use the solution from the initialization phase as the starting point. The simplex tableau for the problem is:
|   | x1 | x2 | x3 | x4 | x5 | x6 | RHS |
|---|----|----|----|----|----|----|-----|
| 0 | 1  | 0  | -3 | 0  | 0  | 0  |  0  |
| 1 | -1 | 1  | 0  | 0  | 1  | 0  |  0  |
| 0 | 0  | 0  | 1  | 1  | 0  | 1  |  5  |
|---|----|----|----|----|----|----|-----|
|   | z  | 0  | 3  | 0  | 0  | 0  |  0  |
We can see that the optimal solution is at (x1, x2, x3, x4, x5, x6) = (3, 3, 0, 5, 0, 0), with z = 9. Therefore, the maximum value of z subject to the given constraints is 9, which is achieved when x1 = 3 and x3 = 0.

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The property described by that mathematical statement is:

The associativity of addition.

The operations on the left side of the equals sign are done in the order they appear, from left to right.

The operations on the right side are done using the associative property, first doing the operations inside the parentheses, then adding the remaining terms.

And the statement shows that for addition, the order of operations does not matter as long as you associate in the proper way using parentheses.

We would need 3 milliliters of the sample to have 9 million yeast cells for making bread.

To find out how many milliliters of a sample you would need to obtain 9 million yeast cells, given a yeast concentration of 3 million yeast cells/ml, you can follow these steps,

1. Determine the number of yeast cells needed: 9 million yeast cells.
2. Identify the yeast concentration: 3 million yeast cells/ml.
3. Divide the total number of yeast cells needed by the yeast concentration to find the required sample volume.

In this case,

(9 million yeast cells) / (3 million yeast cells/ml) = 3 ml

So, you would need 3 milliliters of the sample to have 9 million yeast cells for making bread.

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We would need 3 milliliters of the sample to have 9 million yeast cells for making bread.

To find out how many milliliters of a sample you would need to obtain 9 million yeast cells, given a yeast concentration of 3 million yeast cells/ml, you can follow these steps,

1. Determine the number of yeast cells needed: 9 million yeast cells.
2. Identify the yeast concentration: 3 million yeast cells/ml.
3. Divide the total number of yeast cells needed by the yeast concentration to find the required sample volume.

In this case,

(9 million yeast cells) / (3 million yeast cells/ml) = 3 ml

So, you would need 3 milliliters of the sample to have 9 million yeast cells for making bread.

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(a) negative infinity also approaches 0 because e^x becomes very large as x becomes very negative, (b)  f(x) is increasing on the interval (1, infinity) and decreasing on the interval (-infinity, 1), (c)  f(x) is concave downward on the interval (-infinity, 2) and concave upward on the interval (2, infinity) and (d) the graph approaches the x-axis as x approaches infinity and negative infinity.

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The requried absolute value function |x-(-12)| = |x+12| when x is less than -12.

If x is less than -12, then x-(-12) will result in a negative number. However, the absolute value of any number is always positive, so we can simplify |x-(-12)| by making the expression inside the absolute value bars positive.

Since x is less than -12, x-(-12) can be simplified as follows:

x - (-12) = x + 12

So, |x-(-12)| = |x+12| when x is less than -12.

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Answer:

x = 6 and y = -2

Step-by-step explanation:

If you plug it in,

y = -x + 4

-2 = - 6 + 4

- 2 = -2

x - 3y = 12

6- 3(-2) = 12

6 - (-6) = 12

12 = 12

The quadratic formula mentioned below is used to get the following solutions for x:

[tex]x = \frac{15y \pm \sqrt{225y^2 - 60y^3}}{15}[/tex]

we can use these solutions of x to find the corresponding values of y:

[tex]y = \frac{6x \pm \sqrt{36x^2 - 60xy}}{6}[/tex]

Partial derivative is a type of derivative that is taken with respect to one variable, with all other variables held constant.

The local extrema of the function f (x, y) = 3x2y y³−3x²−3y² 2  can be found by taking the partial derivative of the function with respect to x and y and then setting them equal to zero.

This gives us the following equations:

[tex]\frac{\partial f}{\partial x} = 6xy^3 - 6x = 0[/tex]

[tex]\frac{\partial f}{\partial y} = 3x^2y^2 - 6y = 0[/tex]

To solve these equations, we can set the partial derivatives equal to each other and solve for y:

[tex]6xy^3 - 6x = 3x^2y^2 - 6y[/tex]

[tex]3x^2y^2 - 6y = 6xy^3 - 6x[/tex]

[tex]3x^2y^2 - 6xy^3 = 6x - 6y[/tex]

[tex]y(3x^2 - 6xy^2) = 6x - 6y[/tex]

[tex]y = \frac{6x - 6y}{3x^2 - 6xy^2}[/tex]

Next, we can substitute this expression for y into the equation for the partial derivative with respect to x to get a quadratic equation in x:

[tex]6xy^3 - 6x = 6x\left(\frac{6x - 6y}{3x^2 - 6xy^2}\right)^3 - 6x[/tex]

[tex]6xy^3 - 6x = 6x\left(\frac{6x^2 - 36xy + 36y^2}{(3x^2 - 6xy^2)^2}\right) - 6x[/tex]

[tex]6xy^3 - 6x = 6x\left(\frac{6x^2 - 36xy + 36y^2 - 3x^2 + 6xy^2}{(3x^2 - 6xy^2)^2}\right)[/tex]

[tex]6xy^3 - 6x = 6x\left(\frac{3x^2 - 30xy + 30y^2}{(3x^2 - 6xy^2)^2}\right)[/tex]

[tex]0 = 3x^2 - 30xy + 30y^2[/tex]

This equation can be solved using the quadratic formula to get the following solutions for x:

[tex]x = \frac{15y \pm \sqrt{225y^2 - 60y^3}}{15}[/tex]

Finally, we can use these solutions to find the corresponding values of y:

[tex]y = \frac{6x \pm \sqrt{36x^2 - 60xy}}{6}[/tex]

Therefore, the local extrema of the function f (x, y) =3x2y y³−3x²−3y² 2  can be found by substituting the solutions for x and y into the original function and classifying them as either maximums or minimums depending on the sign of the function.

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