please help me
7. If microsecound = 0.5, how much force must be applied to a spring (spring constant of 0.8 N/m) which is attached to a block of wood (mass = 4.0 kg) in order to just begin to move the block?​

Answers

Answer 1

Answer:

Explanation:

Your question is quite confusing, particularly the information about microsecond = 0.5.

I'm going to ASSUME that you mean coefficient of static friction μs = 0.5

unfortunately typing a subscript "s" is very difficult and probably leads to such confusion.

I will also ASSUME that the block, and spring, and force vector are all horizontal.

If the force is slowly increased until the block slips, the spring will compress until the force on each end equals the maximum static friction force. As we are not concerned with the compression distance, only the force, we can ignore the spring constant information and simply find the maximum available static friction force.

F = μN

F = μmg

F = 0.5(4.0)(9.8)

F = 19.6 N

Not that it matters, but the spring will have extended or compressed 19.6/0.8 = 24.5 m, which is a very long and very light spring


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A__________ shows how velocity changes over time

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Velocity time graph goes into the blank hope it helps please mark me brainliest

Ex 3) A tennis player lobs the tennis ball up in the air during a serve at a rate 3 m/s.
How long will it take the tennis ball to reach its maximum height?

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10 seconds is the time it will take to reach maximum height

Physical activities teaches an individual sense of responsibility and initiative.
True Or False

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Answer:

true

Explanation:

Physical fitness is a personal responsibility so I would say true

the correct answer is true :)

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Sorry, I don't know but I think the correct answer is the first option.

Pls help need asap thank u!

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Answer:

c

Explanation:

What is the intensity level for a sound of Intensity 10-⁶w/m²​

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Thus, the intensity of the sound level is 63.01 dB.

Un péndulo de 4 m de longitud tiene una frecuencia de 5Hz. Calcular la longitud de otro péndulo que en el mismo lugar tiene una frecuencia de 4Hz

Answers

Conociendo la longitud y frecuencia de un péndulo, queremos encontrar la longitud de otro pendulo de tal forma que tenga otra frecuencia.

Veremos que la longitud del nuevo péndulo debe ser 6.25m

Sabemos que un péndulo de 4m de longitud tiene una frecuencia de 5Hz.

La frecuencia de un péndulo está dada por:

[tex]f = \frac{1}{2*\pi} *\frac{g}{l}[/tex]

Donde g es la aceleración gravitatoria y l es la longitud del péndulo, remplazando los datos que tenemos en esa ecuación obtenemos:

[tex]5 Hz = \frac{1}{2*3.14} *\sqrt{\frac{g}{4m} } \\\\(5Hz*2*3.14)^2*4m = g = 3,943.8 m/s^2[/tex]

Ahora debemos encontra la longitud de tal forma que la frecuencia sea 4Hz, entonces debemos resolver:

[tex]4Hz = \frac{1}{2*3.14} *\sqrt{ \frac{3943.8m/s^2}{l} }\\\\4hz*2*3.14 = \sqrt{ \frac{3943.8m/s^2}{l} }\\\\l =\frac{3943.8m/s^2}{ (4hz*2*3.14)^2} = 6.25m[/tex]

La longitud del nuevo péndulo deve ser 6.25m

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When converted to a household measurement, 9 kilograms is approximately equal to a

Answers

Ificicicucuivvicicicucucucu

Answer:

D) 19.8 lbs

Explanation:

1kg in household measurement is equal to 35.274 ounces. 35.274*9=317.466 ounces.

1kg is also equal to 2.205 lbs. 9*2.205=19.8416

9 kg is also equal to 9000 grams, but grams are not a part of the household measurement system

a) 9000 grams. b) 9000 ounces. c) 19.8 ounces. d) 19.8 pounds.

This leaves us with 19.8 lbs

What process makes this pattern on the ocean floor?

Answers

Plate tectonics


and the ocean floor
Bathymetry, the shape of the ocean floor, is largely a result of a process called plate tectonics.

please give me brainliest

A person is driving a car in a roundabout at 20 m/s so that its centripetal acceleration is 5 m/s2 . How much time it takes to complete 1 circle around the roundabout?

Answers

Answer:

Ac = v²/r

where, Ac is centripetal acceleration

v is velocity

r is radius

5 = (20)²/r

r = 400/5

r = 80m

from,

w = 2πf

where, w = angular velocity and f frequency

w = v/r

f = n/T

then,

v = 2πrn ,n = 1 to complete 1 cycle

T

T = 2πr/v

T = 2π*80/20

T = 25.14seconds.

The car would take 25.14s to complete 1 cycle of the roundabout.

What element is chemically similar to carbon

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nonmental

that should be the answer

Computes average speed when a person walk for 1 minute at speed of 1.5 m/s and another 1 minute at speed of 3.5 m/s along a straight road

Answers

Answer:

2.5 m/s

Explanation:

(60*1.5+60*3.5)/120=2.5

or

(1.5+3.5)/2=2.5

Based on your observations, what can you say about your prediction in Parts A and B above concerning the potential and kinetic energy?

Answers

Answer:

Explanation:

My perdiction was correct. I predicted in Part A that the Kinetic Energy would increase. In Part B I predicted that the potential energy would decrease due to the kinetic energy increasing.

Suppose a ball is dropped from a building. What is the change of velocity between the first and fifth seconds of its flight

Answers

Answer: 39.2m/s

Explanation:

Due to the free falling body, the acceleration of the ball is 9.8 m/s^2, and its initial velocity is 0 m/s.

V(t) = g*t

The change of velocity from t=1 to t=5:

Delta V = 9.8*(5-1) = 39.2 m/s

A machine whose efficiency is 75% is used to lift a load of 100m.calculate the effort put into the machine if it has a velocity ratio of 4.

Answers

Explanation:

M.A = load / Effort

efficiency = M.A/V.R X 100

75 = M.A / 4 X 100

75 = 25 X M.A

M.A = 75/25 = 3

M.A = load / effort

3 = 100/E

E = 100/3 = 33.333

A machine whose efficiency is 75% is used to lift a load of 100m. the effort needed to put into the machine is 33.33 meters if the velocity ratio is 4.

What is the mechanical advantage?

Mechanical advantage is defined as a measure of the ratio of output force to input force in a system, It is used to analyze the forces in simple machines like levers and pulleys.

Mechanical advantage = output force(load) /input force (effort)

Simple machines like static pulleys, as well as a movable pulleys, provide a great amount of mechanical advantage.

A machine whose efficiency is 75% is used to lift a load of 100m.calc if it has a velocity ratio of 4.

As we know that the mechanical advantage of a machine is equal to the product of its efficiency and velocity ratio.

mechanical advantage  = velocity ratio   ×Efficiency

       =4 × 0.75

       = 3

The mechanical advantage is 3 , which means the ratio of load to effort is 3

load / effort = 3

100 m/effort =3

effort = 33.33 m

Thus, the effort put into the machine comes out to be 33.33 m.

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When converted to a household measurement, 9 kilograms is approximately equal to a

Answers

Answer:

D) 19.8 lbs

Explanation:

1kg in household measurement is equal to 35.274 ounces. 35.274*9=317.466 ounces.

1kg is also equal to 2.205 lbs. 9*2.205=19.8416

9 kg is also equal to 9000 grams, but grams are not a part of the household measurement system

a) 9000 grams. b) 9000 ounces. c) 19.8 ounces. d) 19.8 pounds.

This leaves us with 19.8 lbs

ALREADY SOLVED Thank you for looking.

Answers

what nonsense you are say it have been solved when why did you put

Answer:

yes

Explanation:

Un avión vuela horizontalmente con una velocidad de 800 km/h y deja caer
un proyectil desde una altura de 500 respecto al suelo. a) ¿Cuánto tiempo
transcurre antes de que el proyectil se impacte en el suelo?; b) ¿Qué distancia
horizontal recorre el proyectil después de iniciar su caída?

Answers

The projectiles launch allows to find the results for the questions of the launch of the bomb are:

     a) The fall time is: t = 10.1 s

     b) The distance traveled is: x = 2.24 10³ m

Projectile launching is an application of kinematics where the acceleration on the x-axis is zero and the acceleration on the y-axis is gravity acceleration.

a) Let's find the time until we reach the ground.

The initial vertical velocity is zero, the initial height is I = 500 m, when reaching the ground its height y = 0.

        [tex]y = y_o + v_o_y - \frac{1}{2} g t^2[/tex]  

        0 = y₀ + 0 - ½ g t²

        t = [tex]\sqrt{\frac{2y_o}{g}[/tex]  

        t = [tex]\sqrt{\frac{2 \ 500}{9.8} }[/tex]  

        t = 10.1 s

b) We look for the horizontal distance traveled.

Let's reduce to the international measurement system (SI).

       v = 800 km / h ([tex]\frac{1000m}{1km}[/tex]) ([tex]\frac{1h}{3600s}[/tex]) = 222.22 m / s

       x = vₓ t

       x = 22.22 10.1

       x = 2.24 10³ m

In conclusion, using the projectile launch relationships, we can find the results for the questions that are:

     a) The fall time is: t = 10.1 s

     b) The distance traveled is: x = 2.24 10³ m

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A 23 g bullet traveling at 230 m/s penetrates a 2.0 kg block of wood and emerges cleanly at 170 m/s. If the block is stationary on a surface with a coefficient of kinetic friction of 0.15 when hit, how far does it move after the bullet emerges?

Answers

The distance traveled by the wood after the bullet emerges is 0.16 m.

The given parameters;

mass of the bullet, m = 23 g = 0.023 gspeed of the bullet, u = 230 m/smass of the wood, m = 2 kgfinal speed of the bullet, v = 170 m/scoefficient of friction, μ = 0.15

The final velocity of the wood after the bullet hits is calculated as follows;

[tex]m_1u_1 + m_2 u_2 = m_1v_1 + m_2v_2\\\\0.023(230) + 2(0) = 0.023(170) + 2v_2\\\\5.29 = 3.91 + 2v_2\\\\2v_2 = 1.38\\\\v_2 = \frac{1.38}{2} = 0.69 \ m/s[/tex]

The acceleration of the wood is calculated as follows;

[tex]\mu = \frac{a}{g} \\\\a = \mu g\\\\a = 0.15 \times 9.8\\\\a = 1.47 \ m/s^2[/tex]

The distance traveled by the wood after the bullet emerges is calculated as follows;

[tex]v^2 = v_0^2 + 2as\\\\v^2 = 0 + 2as\\\\v^2 = 2as\\\\s = \frac{v^2}{2a} \\\\s = \frac{(0.69)^2}{2(1.47)} \\\\s = 0.16 \ m[/tex]

Thus, the distance traveled by the wood after the bullet emerges is 0.16 m.

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10 basic rules of badminton?​

Answers

Explanation:

Rules

A match consists of the best of three games of 21 points.

The player/pair winning a rally adds a point to its score.

At 20-all, the player/pair which first gains a 2-point lead wins that game.

At 29-all, the side scoring the 30th point wins that game.

The player/pair winning a game serves first in the next game.

A badminton match can be played by two opposing players (singles) or four opposing players (doubles).

A competitive match must be played indoors utilising the official court dimensions.

A point is scored when the shuttlecock lands inside the opponent's court or if a returned shuttlecock hits the net or lands outside of the court the player will lose the point.

At the start of the rally, the server and receiver stand in diagonally opposite service courts.

A legal serve must be hit diagonally over the net and across the court.

A badminton serve must be hit underarm and below the server's waist height with the racquet shaft pointing downwards, the shuttlecock is not allowed to bounce. After a point is won, the players will move to the opposite serving stations for the next point.

The rules do not allow second serves.

During a point a player can return the shuttlecock from inside and outside of the court.

A player is not able to touch the net with any part of their body or racket.

A player must not deliberately distract their opponent.

A player is not able to hit the shuttlecock twice.

A 'let' may be called by the referee if an unforeseen or accidental issue arises.

A game must include two rest periods. These are a 90-second rest after the first game and a 5-minute rest after the second game.

1) A bowling has a mass of 5 kg and a speed of 8 m/s. What is its momentum?
2) If the bowling ball started from a momentum of O and reached a momentum of 40
kg*m/s in 2 seconds. What is the impulse impacted on the bowling ball?
3) What is the force of impact for the 2 seconds?

Answers

Hgihucycyvyvuvuvuvuvuvuvuvvuvuvuv

4. What is the density of a block with a mass of 36 g and a volume of 9 cm?
O A 45 g/cm3
O B.27 g/cm
O 0.4 g/cm
O D. 0.25 g/cm

Answers

Answer:

0.4 g/cm

Explanation:

density (g cm ³) = mass (g)

÷

volume (cm³)

Answer:

C. 4 g/cm

Explanation:

Use the formula:

density = mass ÷ volume

mass = 36volume = 9

Sub in the values:

density = 36 ÷ 9 = 4 g/cm

Answer = 4 g/cm

Ex 3) A tennis player lobs the tennis ball up in the air during a serve at a rate 3 m/s.
How long will it take the tennis ball to reach its maximum height?

Answers

Explanation:

s=(v^2-u^2)/2g

=(0-3^2)/2*10

= 0.45m

10. Unless a light ray comes into contact with a surface or enters a different material, it
travels in a

Answers

Answer:

Straight Path

Water which contains large amounts of calcium dissolved within it results from
a) factory sewage outfalls.
b) water dissolving materials in the ground.
c) volcanic activity.
d) increase in number of wells in area.

Answers

Answer: B

Explanation:

The other options have nothing to do with the water apart from transporting it.

What happens to the size of an Object when it is heated ?​

Answers

Answer:

size get smaller maybe there is no object remaining

Answer:

If they are heated the size. will be decreased.

8. What is the kinetic Energy of the 75 kg skydiver if she is falling at 52 m/s?
Formula:
Variables with units:
Work with Units:
Final Answer with Units:

Answers

Answer:

101,400 J

Explanation:

The kinetic energy of an object can be found by using the formula

[tex]k = \frac{1}{2} m {v}^{2} \\ [/tex]

m is the mass

v is the velocity

From the question

m = 75 kg

v = 52 m/s

We have

[tex]k = \frac{1}{2} \times 75 \times {52}^{2} \\ = \frac{1}{2} \times 75 \times 2704 \\ = 75 \times 1352 \\ = 101400[/tex]

We have the final answer as

101,400 J

Hope this helps you

PLEASE ANSWER ASAP IM GONNA MARK AS BRAINLIEST

What is the value of the force measured by the spring balance? ​

Answers

Spring balance is a mechanical device used for measuring the weight or force of an object by opposing the force of gravity with the force of an extended spring. The principle behind its working is the principle of Hooke's law.

The volume of an ideal gas is increased from 0.6 m3 to 2.4 m3 while maintaining a constant pressure of 1000 Pa (1000 N/m2). Determine, in J, the amount of work done by the gas in this expansion.

Answers

The amount of work done by the gas in the given expansion is 1800 J.

The given parameters;

initial volume of the ideal gas, V₁ = 0.6 m³final volume of the ideal gas, V₂ = 2.4 m³constant pressure of the gas, P = 1000 Pa

The amount of work done by the gas in the given expansion is calculated as follows;

W = PΔV

where;

ΔV is the change in volume of the gas

Substitute the given parameters and solve for the work done;

W = 1000(2.4  -  0.6

W = 1800 J

Thus, the amount of work done by the gas in the given expansion is 1800 J.

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1.protozoo ore ?
A. multicellular organisms B. one - Celled animals
C. amembers of the group Protocista
D. unicellulor Plants​

Answers

Answer:

c

Explanation:

amembers of the group protocista

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