To prove that for any real number x, if x²+ 7x < 0, then x < 0, we can use the properties of quadratic functions and inequalities.
By analyzing the quadratic expression, we can determine the conditions under which it is negative. This analysis shows that the inequality x²+ 7x < 0 holds true when x is less than 0. Consider the quadratic expression x² + 7x. To determine when this expression is negative, we can factor it as x(x + 7). According to the zero product property, this expression is equal to zero when either x or (x + 7) is equal to zero. Thus, the two critical points are x = 0 and x = -7.
Now, let's analyze the behavior of the quadratic expression in the intervals (-∞, -7), (-7, 0), and (0, +∞). Choose a test point from each interval, such as -8, -3, and 1, respectively. Evaluating the expression x²⁺7x for these test points, we find that for -8 and -3, the expression is positive, and for 1, it is positive as well.
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Mrs. Dawson is researching what it would cost to order flower arrangements for a fancy party. She wants one large centerpiece for the head table, and smaller arrangements for the smaller tables. Hampton Florist charges $12 for each smaller arrangement, plus $27 for the large centerpiece. Farid's Flowers, in contrast, charges $32 for the large centerpiece and $7 per arrangement for the rest. If Mrs. Dawson orders a certain number of small arrangements, the cost will be the same at either flower shop. How many small arrangements would that be? What would the total cost be? If Mrs. Dawson orders small arrangements, it will cost $ at either shop.
The number of flower arrangement and the costs are illustrations of linear equation
If Mrs. Dawson orders 1 small arrangement, it will cost $39 at either shop.
How to determine the number of small arrangements?Represent the number of small arrangements with x, and the total cost with y.
Using the data from the question, we have:
Hampton Florist: y = 12x + 27.
Farid's Flowers: y = 32 + 7x
When both flower arrangements cost the same, we have the following equation
12x + 27 = 32 + 7x
Collect like terms
12x - 7x = 32 - 27
Evaluate the like terms
5x = 5
Divide both sides by 5
x = 1
This means that 1 small arrangement would cost the same in both flower shops
How to determine the total cost?In (a), we have:
y = 12x + 27.
Substitute 1 for x
y = 12(1) + 27
y = 39
Hence, if Mrs. Dawson orders 1 small arrangement, it will cost $39 at either shop.
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How can the next term in the infinite sequence 1, 5, 12, 22, 35, ... be generated?
A. Square the term number, subtract the tem number from the result, multiply by 3, and divide the result by 2.
B. Square the term number, multiply the result by 3. divide by 2, and subtract the term number from the result.
C. Square the term number, divide the result by 2 subtract the term number, and multiply the result by 3.
D. Square the term number, multiply the result by 3 subtract the tem number, and divide the result by 2.
Answer:
Its D
Square the term number, multiply the result by 3, subtract the term number, and divide the result by 2
Which of the following statements is the most accurate comparison of LDA and ODA with regard to the bias-vanance trade-off?
the most accurate statement comparing LDA and ODA in terms of the bias-variance trade-off would be that LDA generally has lower variance and moderate bias, while ODA tends to have higher variance and lower bias.
LDA (Linear Discriminant Analysis) and ODA (One-Dimensional Analysis) are both techniques used in machine learning and statistical analysis, but they differ in their approach to the bias-variance trade-off.
The bias-variance trade-off refers to the trade-off between the bias of a model (error due to overly simplistic assumptions) and the variance of a model (error due to excessive complexity). A model with high bias may underfit the data, while a model with high variance may overfit the data.
In terms of the bias-variance trade-off, LDA tends to have low variance and moderate bias. It assumes that the data is normally distributed and that the class covariance matrices are equal. LDA attempts to find a linear combination of features that maximally separates the classes. However, LDA makes strong assumptions about the data distribution, which may limit its flexibility and result in bias.
On the other hand, ODA, also known as univariate analysis or one-dimensional analysis, typically has higher variance and lower bias compared to LDA. ODA considers each feature independently, disregarding any interdependencies among the features. By examining each feature individually, ODA allows for more flexibility and may capture complex relationships in the data. However, this flexibility can lead to higher variance, making ODA more prone to overfitting if the dataset is small or noisy.
Therefore, the most accurate statement comparing LDA and ODA in terms of the bias-variance trade-off would be that LDA generally has lower variance and moderate bias, while ODA tends to have higher variance and lower bias.
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Cardiorespiratory fitness is widely recognized as a major component of overall physical well-being. Direct measurement of maximal oxygen uptake (VO2max) is the single best measure of such fitness, but direct measurement is time-consuming and expensive. It is therefore desirable to have a prediction equation for VO2max in terms of easily obtained quantities. Consider the following variables.
y = VO2max (L/min)
x1 = weight (kg)
x2 = age (yr)
x3 = time necessary to walk 1 mile (min)
x4 = heart rate at the end of the walk (beats/min)
Here is one possible model for male students, consistent with the information given in the article "Validation of the Rockport Fitness Walking Test in College Males and Females."†
Y = 5.0 + 0.01x1 − 0.05x2 − 0.13x3 − 0.01x4 + ϵ
σ = 0.4
(a) Interpret β1.
A. Holding all other variables constant, a 1 kg increase in weight will result in a 0.01 L/min increase in VO2max.
B. Holding all other variables constant, a 1 kg increase in weight will result in a 0.01 L/min decrease in VO2max.
C. Holding all other variables constant, a 0.01 kg increase in weight will result in a 1 L/min increase in VO2max.
D. Holding all other variables constant, a 0.01 kg increase in weight will result in a 1 L/min decrease in vo2max. Interpret ß3
D. Holding all other variables constant, a 0.13 min increase in walk time will result in a 1 L/min decrease in VO2max
Interpret β3
A. Holding all other variables constant, a 0.13 min increase in walk time will result in a 1 L/min decrease in VO2max.
B. Holding all other variables constant, a 1 min increase in walk time will result in a 0.13 L/min decrease in vo2max.
C. Holding all other variables constant, a 1 min increase in walk time will result in a 0.13 L/min increase in VO2max
D. Holding all other variables constant, a 0.13 min increase in walk time will result in a 1 L/min increase in VO2max.
(b) What is the expected value of VO2max when weight is 76 kg, age is 25 yr, walk time is 14 min, and heart rate is 138 b/m?
L/min
(c) What is the probability that VO2max will be between 0.59 and 2.03 for a single observation made when the values of the predictors are as stated in part (b)? (Round your answer to four decimal places.)
a) Interpret β1: Holding all other variables constant, a 1 kg increase in weight will result in a 0.01 L/min decrease in VO2max. Option B is correct.
b) The expected value of VO2max when weight is 76 kg, age is 25 yr, walk time is 14 min, and heart rate is 138 b/m is 3.682 L/min. Option A is correct.
c) The probability that VO2max will be between 0.59 and 2.03 for a single observation made when the values of the predictors are as stated in part (b) is 0.0000. Option D is correct.
a) Interpret β1: Holding all other variables constant, a 1 kg increase in weight will result in a 0.01 L/min decrease in VO2max.
Option B is correct.
b) To find the expected value of VO2max when weight is 76 kg, age is 25 yr, walk time is 14 min, and heart rate is 138 b/m.
We can calculate it by plugging the values in the regression equation as follows:
Y = 5.0 + 0.01x1 − 0.05x2 − 0.13x3 − 0.01x4 + ϵ
= 5.0 + (0.01 * 76) - (0.05 * 25) - (0.13 * 14) - (0.01 * 138)
= 3.682 L/min.
Hence, the expected value of VO2max when weight is 76 kg, age is 25 yr, walk time is 14 min, and heart rate is 138 b/m is 3.682 L/min.
Option A is correct.
c) To find the probability that VO2max will be between 0.59 and 2.03 for a single observation made when the values of the predictors are as stated in part (b).
We can find it by standardizing the values and using the Z table as follows:
z-score for 0.59 = (0.59 - 3.682) / 0.4
= -8.055z-score for 2.03
= (2.03 - 3.682) / 0.4
= -4.175P(0.59 < Y < 2.03)
= P(z-score between -8.055 and -4.175)
= P(z > 8.055) - P(z > 4.175)
≈ 0.0000 (from the Z table)
Hence, the probability that VO2max will be between 0.59 and 2.03 for a single observation made when the values of the predictors are as stated in part (b) is 0.0000.
Option D is correct.
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x
-5
-4
-3
-2
-1
0
1
2.
3
f(x)
14
6
CO
O
-4
-6
-6
-4
0
6
Based on the table, which statement best describes a prediction for the end behavior of the graph of f(x)?
O As x = 0,f(x) = -00, and as x -o, f(x) o
As x = 0,f(x) - 00, and as x = -00,f(x) = 0
O As x - ,f(x) 0, and as x - -0,f(x) --
O AS X - c.f(x) - --, and as x + -0,f(x) ---
The solution is : Option C, function is → f(x) = x + 2
What is function?Function, in mathematics, an expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable.
here, we have,
From the table give in the picture,
Let the linear function represented by the table is,
f(x) = mx + b
Here, m = Slope of the line
b = y-intercept
Slope of a line passing through two points (-2, 0) and (1, 3) will be,
m = y2 - y1 / x2 - x1
= 1
Equation of the function will be,
f(x) = x + b
Since, a point (1, 3) lies on he given function,
3 = 1 + b
b = 3 - 1
b = 2
Therefore, function is → f(x) = x + 2
Option C will be the correct option.
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complete question:
X f(x)
-2 0
5. Which function matches the function table at the right?
A. f(x) = x+3
B.f(x) = 2x
C.f(x) = x + 2
D. f(x) = 4x - 1
Pls help
I need help with this
[tex] \sqrt[3]{4} \times \sqrt{3} [/tex]
25 points.
Step-by-step explanation:
[tex]\sqrt[3]{4}[/tex][tex]\\\sqrt{3}[/tex]=[tex]\sqrt[6]{432}[/tex]
[tex]4^{1/3}[/tex][tex]3^{1/2}[/tex]=[tex]432^{1/6}[/tex]
Hope that helps :)
The tip of the second hand travels around the edge of the face of a clock. How far does the tip of the second hand travel between the 6 and the 12, if the length of the second hand is 6 inches?
Recall that StartFraction Arc length over Circumference EndFraction = StartFraction n degrees over 360 degrees EndFraction.
A) 3 pi
B) 6 pi
C) 12 pi
D) 24 pi
Answer: 3 inches
Step-by-step explanation: IT MIGHT BE IF ITS WRONG IM SORRRYYY
Solve the following system of equations using elimination
Answer:
Well elimination is basically multiplying a number to make it possible for it to cancel out
We can multiply the first equation by 2
2(x+2y=-1)
This would be
2x+4y=-2
Its still the same thing but just with non simplified numbers
We can now do any method really to solve
I will just do the subtraction method
2x+4y=-2
-2x+y=4
Solve
2x-2x=0
4y-y= 3y
-2-4= -6
3y= -6
Now solve
y=-2
To find x subsitute in “y” and find ”x”.
x+2*-2=-1
x-4=-1
x=3
y= -2
x= 3
Please use an appropriate formula for calculations.
How many solutions are there to the
equation:
a + b + c + d + e = 485
If each of a, b, c, d, and e is an integer that is at
least 10?
There are 169,322,412 solutions to the equation a + b + c + d + e = 485, where each variable is an integer that is at least 10.
To solve this problem, we can use the concept of stars and bars (or balls and urns). The stars and bars method is used to find the number of non-negative integer solutions to an equation of the form a₁ + a₂ + ... + aᵣ = n, where aᵢ represents non-negative integers.
In this case, we have the equation a + b + c + d + e = 485, with the constraint that each variable (a, b, c, d, e) is at least 10. We can introduce a new set of variables a' = a - 10, b' = b - 10, c' = c - 10, d' = d - 10, and e' = e - 10. This transformation ensures that each variable is now a non-negative integer.
Substituting these new variables into the equation, we get:
(a' + 10) + (b' + 10) + (c' + 10) + (d' + 10) + (e' + 10) = 485
Rearranging the equation, we have:
a' + b' + c' + d' + e' = 435
Now, we can apply the stars and bars method to find the number of non-negative integer solutions to this equation. The formula is given by:
Number of solutions = (n + r - 1) choose (r - 1)
where n is the total number to be partitioned (435 in this case) and r is the number of variables (5 in this case).
Using the formula, we have:
Number of solutions = (435 + 5 - 1) choose (5 - 1)
= 439 choose 4
Evaluating this expression:
Number of solutions = (439 * 438 * 437 * 436) / (4 * 3 * 2 * 1)
= 169,322,412
Therefore, there are 169,322,412 solutions to the equation a + b + c + d + e = 485, where each variable is an integer that is at least 10.
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If four is added to a half of a
number. The result is equal to 2.
What is the number?
Answer:
-2
Step-by-step explanation:
4 + negative 2 (or -2) = 2
Translate the following sentence from English into symbolic
logic. No respectable scientists are astrologers. (Rx: x is
respectable; Sx: x is a scientist; Ax: x is an astrologer)
No respectable scientists are astrologers can be translated into symbolic logic as follows:
∀x [(Rx ∧ Sx) → ¬Ax]
Let's break down the sentence:
- Rx: x is respectable.
- Sx: x is a scientist.
- Ax: x is an astrologer.
The statement "No respectable scientists are astrologers" can be translated as follows:
For all x, if x is both respectable (Rx) and a scientist (Sx), then x is not an astrologer (¬Ax).
In other words, every individual x who is both respectable and a scientist cannot be an astrologer.
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An exam is given to students in an introductory statistics course. What is likely to be true of the shape of the histogram of scores if:
a. the exam is quite easy?
b. the exam is quite difficult?
c. half the students in the class have had calculus, the other half have had no prior college math courses, and the exam emphasizes mathematical manipulation? Explain your reasoning in each case.
a. If the exam is quite easy, it is likely that the majority of students will perform well and score high marks. As a result, the shape of the histogram of scores would be skewed to the right (positively skewed).
This is because there would be a concentration of scores towards the higher end of the scoring scale, with fewer scores towards the lower end.
b. Conversely, if the exam is quite difficult, it is likely that many students will struggle and score low marks. In this case, the shape of the histogram of scores would be skewed to the left (negatively skewed). There would be a concentration of scores towards the lower end of the scoring scale, with fewer scores towards the higher end.
c. When half the students have had calculus and the other half have had no prior college math courses, and the exam emphasizes mathematical manipulation, it can lead to a bimodal distribution in the histogram of scores. This means that there would be two distinct peaks or clusters in the distribution, representing the two groups of students with different math backgrounds.
The calculus students may perform better on the mathematical manipulation aspects of the exam, resulting in one peak, while the students without prior college math courses may struggle and have a separate peak at lower scores.
Overall, the shape of the histogram of scores is influenced by the difficulty level of the exam and the varying abilities of the students taking the exam.
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Lemma 1 Let g = (V, E, w) be a weighted, directed graph with designated root r e V. Let E' = {me(u): u E (V \ {r})}. Then, either T = (V, E') is an RDMST of g rooted at r or T contains a cycle. Lemma 2 Let g = (V, E, w) be a weighted, directed graph with designated root reV. Consider the weight function w': E → R+ defined as follows for each edge e = (u, v): w'le) = w(e) - m(u). Then, T = (V, E') is an RDMST of g = (V, E, W) rooted at r if and only if T is an RDMST of g = (V, E, w') rooted at r.
Lemma 1 states that in a weighted, directed graph with a designated root, if we create a new set of edges E' by removing edges from the root to each vertex except itself.
Lemma 1 introduces the concept of an RDMST (Rooted Directed Minimum Spanning Tree) in a weighted, directed graph and highlights the relationship between the set of edges E' and the existence of cycles in the resulting graph T. It states that if T is not an RDMST, it must contain a cycle, indicating that removing certain edges from the root to other vertices can lead to cycles.
Lemma 2 focuses on the weight function w' and its impact on determining an RDMST. It states that the resulting graph T is an RDMST rooted at the designated root in the original graph if and only if it is an RDMST rooted at the designated root in the graph with the modified weight function w'. This lemma demonstrates that adjusting the weights of the edges based on the weights of the vertices preserves the property of being an RDMST.
Overall, these two lemmas provide insights into the properties and characteristics of RDMSTs in weighted, directed graphs and offer a foundation for understanding their existence and construction.
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(3+4)⋅(22+3)
whats the answer for that equation
the answer should be 175
Confused anyone need help
Answer:
The temperature on the moon at midnight was -250 degrees.
Step-by-step explanation:
235 - 485 = -250
factor the trinomial 16x2 + 14x + 3
Answer:
Step-by-step explanation:
16x²+14x+3
=16x²+8x+6x+3
=8x(2x+1)+3(2x+1)
=(2x+1)(8x+3)
warning number 777777777777777777777777777777
Answer: What is the warning for???? anyway your answer x= -3, x=-5
Step-by-step explanation:
Hope this helps you! Have a good day! :)
T/F. If isometry a interchanges distinct points P and Q, then a fixes the midpoint of P and Q.
False. If an isometry interchanges distinct points P and Q, it does not necessarily fix the midpoint of P and Q. In general, an isometry is a transformation that preserves distances between points.
However, it does not guarantee that the midpoint of two interchanged points will be fixed. Consider a simple example of a reflection about a line passing through the midpoint of P and Q. This is an isometry that interchanges P and Q but does not fix their midpoint. The midpoint would be mapped to a different point under the reflection transformation.
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1.) A ball of radius 14 has a round hole of radius 8 drilled through its center. Find the volume of the resulting solid.
2.) Find the volume of the solid obtained by rotating the region enclosed by the graphs of y=9/x2 and y=10-x2 and about the line y=-9
The volume of the solid can be calculated as: V = 2π ∫[c,d] x * (h(x) + 9) dx.
To find the volume of the resulting solid, we can subtract the volume of the hole from the volume of the ball.
The volume of the ball can be calculated using the formula for the volume of a sphere: V_ball = (4/3) * π * r^3, where r is the radius of the ball. In this case, the radius of the ball is 14, so we have: V_ball = (4/3) * π * 14^3.
The volume of the hole can be calculated using the formula for the volume of a cylinder: V_hole = π * r^2 * h, where r is the radius of the hole and h is the height of the hole. In this case, the radius of the hole is 8, and since it passes through the center of the ball, the height of the hole is equal to the diameter of the ball, which is 2 * 14. So we have: V_hole = π * 8^2 * (2 * 14).
The volume of the resulting solid is then given by: V_result = V_ball - V_hole.
To find the volume of the solid obtained by rotating the region enclosed by the graphs of y=9/x^2 and y=10-x^2 about the line y=-9, we can use the method of cylindrical shells.
The volume of a solid obtained by rotating a curve around a line is given by the formula: V = 2π ∫[a,b] x * h(x) dx, where a and b are the x-values where the curves intersect, and h(x) is the distance between the line of rotation and the curve at each x-value.
In this case, the curves y = 9/x^2 and y = 10 - x^2 intersect at two points, let's say x = c and x = d. The line of rotation y = -9 is parallel to the x-axis and is located 9 units below it.
The volume of the solid can be calculated as: V = 2π ∫[c,d] x * (h(x) + 9) dx.
To find the values of c and d, we need to solve the equation 9/x^2 = 10 - x^2. Once we have the values of c and d, we can evaluate the integral to find the volume of the solid.
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Determine whether the following series are convergent or divergent.
a. (summation) n=3 to infinity of 6/(n+4)
b. (summation) n=2 to infinity of n/((Sq. root of n) +1)
c. (summation) n=1 to infinity of 1/ (Sq. root of n^4 +8)
d. (summation) n=2 to infinity of (-1)^(n-1) n/ ln/n
The following are the solutions of the given series:a) The given series can be written as:(summation) n=3 to infinity of 6/(n+4) = 6[(1/7) + (1/8) + (1/9) +...].It is a p-series of p = 1, since 1 < p = 2. Hence, it is divergent. b) The given series can be written as:(summation) n=2 to infinity of n/((Sq. root of n) +1) = (summation) n=2 to infinity of [n/((Sq. root of n) +1)] * [(Sq. root of n)-1]/[(Sq. root of n)-1].On solving this we get, (summation) n=2 to infinity of [(Sq. root of n)-1].This series is a p-series of p = 1/2, since p < 1. Hence, it is convergent. c) The given series can be written as:(summation) n=1 to infinity of 1/ (Sq. root of n^4 +8) .This is a convergent series because it is similar to the p-series with p = 2. Therefore, the series is convergent. d) The given series can be written as:(summation) n=2 to infinity of (-1)^(n-1) n/ ln/n .As per Alternating Series Test, this is an alternating series which is decreasing to 0, Hence, the series is convergent.
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According to the given information,
a. the series diverges.
b. the series diverges.
c. series is convergent
d. series is conditionally convergent
To determine the convergence or divergence of these series, we can analyze the behavior of the terms as n approaches infinity.
a. The series (summation) n=3 to infinity of 6/(n+4) can be rewritten as (summation) n=3 to infinity of 6/n.
As n approaches infinity, the term 6/n approaches zero. Since the harmonic series (1/n) is known to diverge, the given series also diverges.
b. The series (summation) n=2 to infinity of n/((Sq. root of n) +1) can be rewritten as (summation) n=2 to infinity of (n^(3/2))/(n + sqrt(n)).
As n approaches infinity, the term (n^(3/2))/(n + sqrt(n)) approaches (n^(3/2))/n = sqrt(n).
Since sqrt(n) increases without bound as n approaches infinity, the series diverges.
c. The series (summation) n=1 to infinity of 1/(Sq. root of (n^4 + 8)) can be rewritten as (summation) n=1 to infinity of 1/(n^2 + 8^(1/4)).
As n approaches infinity, the term 1/(n^2 + 8^(1/4)) approaches 0. Since the terms of the series approach zero as n approaches infinity, we need to investigate further.
By comparing the series to the p-series, we see that n^2 is larger than 1 for all n greater than or equal to 1. Therefore, the series (summation) n=1 to infinity of 1/(n^2 + 8^(1/4)) is convergent.
d. The series (summation) n=2 to infinity of (-1)^(n-1) n/ ln(n) can be analyzed using the alternating series test.
As n approaches infinity, the term n/ln(n) approaches infinity, and the series does not converge absolutely.
However, if we examine the behavior of the series using the alternating series test, we see that (-1)^(n-1) alternates between -1 and 1.
Additionally, the absolute value of n/ln(n) is a monotonically decreasing function as n increases.
Thus, the series is conditionally convergent by the alternating series test.
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Kiteretsuki builds a robot to help him paint a fence. The robot has a paint roller of width 1 foot, that works like a ball-point pen, so it has a steady flow of ink. Kiteretsuki sets the robot to work and leaves but doesn't realize that the robot has a programming error.
It paints one foot of the fence from left to right, then stops and paints a foot in the right to left direction. It then starts moving from left to right again, but this time moving two feet instead of one. However, after this, it only moves back to its previous position. The robot carries on in this fashion, increasing its reach by 1 foot every left to right movement and then returning to its previous starting point.
If Kiteretsuki returns after the robot have moved a total of 11 times, how many inches of the fence has the robot painted in that time?
Answer:
72 inches
Step-by-step explanation:
Due to the programming error, the robot first moves to the right and then to the left. The second time it moves to the right, it increases its distance by 1 foot to the right and then turns back and moves to the left, reaching the starting position again.
The patterns is as follows:
move 1: moves to the right by 1 foot.
moves 2: moves to the left.
moves 3: moves to the right by 2 feet.
moves 4: moves to the left
moves 5: moves to the right by 3 feet.d
moves 6: moves to the left
moves 7: moves to the right by 4 feet.
moves 8: moves to the left
moves 9: moves to the right by 5 feet.
moves 10: moves to the left
moves 11: moves to the right by 6 feet.
We see that in the end, the robot has managed to only move 6 ft. Since 1 ft = 12 inches, 6 ft = 6* 12 = 72 ft.
So, the robot has painted 72 inches of the fence before Kiteretsuki returns.
Miss smith buys avocados for a family reunion. She needs 12 avocados, and she buys them in bags of 5. How many bags does Miss Smith need?
Answer:
3 bags
Step-by-step explanation:
Since the avocados come in bags of 5, she will need to buy 3 bags. This will give her 15 avocados which is more than the 12 avocados that she needs but we have to buy 3 bags or else she won't have enough. So she will just have 3 avocados left over.
hope that made sense lol but I know the answer is 3 bc u can't buy half a bag. <3
b + -73 = -58
help please
Answer:
Step-by-step explanation:
b-73=-53
b=-53+73
b=+73-53
b=73-53
b=20
Please help me with this
Answer:
x=8
Step-by-step explanation:
The ratio of a side of PQRS to the corresponding side in TUVW. is 6:4=3:2.
The ratio of RS:VW=3:2. RS=12, and VW=x. 12:x=3:2. 3 multiplied by 4 is 12, so 2 multiplied by 4 is x. So, the makes x=8.
1. Describe the relationship between the terms in the sequence 13, 26, 52,
104, ... Then write the next three terms in the sequence.
Answer: All of the numbers in the sequence are going up twice the amount as before. The next three terms will be 208, 416, 832
Answer: 208, 416, 832
The numbers double by itself
Step-by-step explanation:
13+13 = 26, 26+26 = 52, 52+52 = 104, 104+104=208 and so on
Find the area of the shaded area
Answer:
1.7x3.9=6.63 so each shaded area is 6.63 then add
Step-by-step explanation:
Use the data set and line plot below. How many feathers are
2
1
4
214
inches or shorter?
A. 8
B. 12
C. 15
D. 5
Answer:
B.) 12
Step-by-step explanation:
2+1/4 is the fraction and all values less than two are on the line.
1 brown circle represents 1 feather
there are 7 dots for 2+1/4
4 dots for 2
1 dot for 3/4
Hope that helps :)
Answer:
answer is B. Aka 12
Step-by-step explanation:
thanks mark brainliest…:) please.
Solve for xx to the nearest tenth.
Answer:
in right angled triangleBCD
BC=√{DC²-BC²)=√{10²-6²)=8
again in right angled triangle ABC
AB=√(BC²-AC²)
x=√(8²-7²)=3.87
JELLY V. TUCHY Slipe old Distribution O of 1 Point The data below represent the per capita (average) disposable income (income after taxes) for 25 randomly selected cities in a recent year. Describe the shape of the distribution. Choose the correct answer below. Skewed left 30,206 34,278 36,997 40,291 30,448 34,633 37,244 41,059 Skewed right Bell-shaped O 30,732 34,968 37,811 41,437 Uniform 32,171 35,230 38,408 52,510 33,016 35,624 38,608 33,684 35,863 38,956 Get more help Clear all Check answer JELLY V. TUCHY Slipe old Distribution O of 1 Point The data below represent the per capita (average) disposable income (income after taxes) for 25 randomly selected cities in a recent year. Describe the shape of the distribution. Choose the correct answer below. Skewed left 30,206 34,278 36,997 40,291 30,448 34,633 37,244 41,059 Skewed right Bell-shaped O 30,732 34,968 37,811 41,437 Uniform 32,171 35,230 38,408 52,510 33,016 35,624 38,608 33,684 35,863 38,956
The shape of the distribution of per capita disposable income for the 25 randomly selected cities in a recent year can be described as skewed right.
To determine the shape of the distribution, we can examine the data and look for any noticeable patterns. In this case, we observe that the values for per capita disposable income generally increase as we move from left to right. This indicates a rightward skewness in the distribution.
Skewness refers to the asymmetry of a distribution. When a distribution is skewed right, the tail of the distribution extends towards the higher values, while the majority of the data tends to cluster towards the lower values. This suggests that there are few cities with relatively higher per capita disposable incomes, while the majority of cities have lower incomes.
In contrast, a bell-shaped distribution would indicate a symmetrical pattern with a peak in the center and an equal number of data points on both sides.
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Compute y' and y". The symbols C₁ and C₂ represent constants. y = C1e* + C2xe* y'(x) C₁et + C₂(x + 1) et y"(x) = C₁et + C₂ (2 + x) ex
The first derivative of y is y'(x) = C₁e^x + C₂(x + 1)e^x, and the second derivative of y is y''(x) = C₁e^x + C₂(2 + x)e^x.
To compute the first derivative, we apply the power rule and the product rule of differentiation. For y = C₁e^x + C₂xe^x, the derivative of the first term C₁e^x is C₁e^x, and the derivative of the second term C₂xe^x involves both the product rule and the chain rule.
Using the product rule, we differentiate C₂x and e^x separately, and then multiply them together. The derivative of C₂x is C₂, and the derivative of e^x is e^x. Then, we apply the chain rule to the second term, resulting in (x + 1)e^x. Therefore, the first derivative is y'(x) = C₁e^x + C₂(x + 1)e^x.
To compute the second derivative, we differentiate y'(x) with respect to x. Both terms in y'(x) involve the derivative of e^x, which is e^x. The derivative of C₁e^x is C₁e^x, and the derivative of C₂(x + 1)e^x involves the product rule and the chain rule similarly to the first derivative. Applying these rules, we find that y''(x) = C₁e^x + C₂(2 + x)e^x.
Therefore, the first derivative of y is y'(x) = C₁e^x + C₂(x + 1)e^x, and the second derivative is y''(x) = C₁e^x + C₂(2 + x)e^x.
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