Question: “use calculator to find the measure of angle
(Please show work if you can!)

Answer:

the answer is b

Step-by-step explanation:

Due to the presence of two rectangles with sides of lengths a and b, Square G's area in Step 2 should equal [tex]a^2+2ab+b^2[/tex].

According to the Pythagorean Theorem, the squares on the hypotenuse of a right triangle, or, in conventional algebraic notation, [tex]a^2+b^2[/tex], are equal to the squares on the legs. The Pythagorean Theorem states that the square on a right-angled triangle's hypotenuse is equal to the total number of the squares on its other two sides.

The Pythagoras theorem, often known as the Pythagorean theorem, explains the relationship between each of the sides of a shape with a right angle. According to the Pythagorean theorem, the square root of a triangle's the hypotenuse is equal to the sum of the squares of its other two sides.

Area of square [tex]G=a^2+2ab+b^2[/tex]

[tex]a^2+2ab+b^2=c^2+2ab\\\\a^2+2ab-2ab+b^2=c^2+2ab-2ab\\\\a^2+b^2=c^2[/tex]

[ The Pythagorean theorem]

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Therefore, the probability of selecting two red marbles from the jar is 21/496.

The total number of marbles in the jar is 7 + 25 = 32.

The probability of selecting a red marble on the first draw is 7/32.

Since the marble is not replaced, there are only 31 marbles left, including 6 red marbles.

Therefore, the probability of selecting a red marble on the second draw, given that the first marble was red, is 6/31.

To find the probability of both events happening (selecting 2 red marbles), we multiply the probabilities:

(7/32) * (6/31) = 42/992 = 21/496

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The jurors may perceive the identification as less reliable, leading them to rely more on the circumstantial evidence and be less certain about convicting the defendant.

In Loftus' (1974) study on the effects of eyewitness testimony on jury decision-making, subjects were presented with a description of an armed robbery. When only circumstantial evidence was provided, 18% of the subjects convicted the defendant. However, when an eyewitness identification was added to the circumstantial evidence, the conviction rate increased to 72%.

When the mock jurors were told that the eyewitness had poor eyesight and wasn't wearing his glasses, it is likely that the conviction rate would decrease as this information weakens the credibility of the eyewitness testimony. The jurors may perceive the identification as less reliable, leading them to rely more on the circumstantial evidence and be less certain about convicting the defendant.

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Suppose we fix a tree 1. The descendent relation on the nodes of T is a strict partial order. So the option d is correct.

The descendent relation on the nodes of a tree T is a strict partial order if, for any two nodes x and y in T, either x is a descendent of y, y is a descendent of x, or neither x nor y is a descendent of the other.

This means that for any two nodes x and y, either x is a parent node, a grandparent node, etc. of y, or y is a parent node, a grandparent node, etc. of x, or neither x nor y is related in any way.

The descendent relation is a strict partial order because it is a partial order (it is reflexive, antisymmetric, and transitive) and it is also strict (neither x nor y can be a descendent of the other). So the option d is correct.

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(a) The value of (fg)′(4) = 30.

(b) The value of (gf)′(4) = 33.

Given:

f(4)=4

f′(4)=6

g(4)=−1

and g′(4)=9

(a) Using the product rule, we have:

(fg)'(4) = f'(4)g(4) + f(4)g'(4)
         = 6(-1) + 4(9)
         = 30

Therefore, value of (fg)'(4) = 30.

(b) Using the chain rule, we have:

(gf)'(4) = g'(4)f(4) + g(4)f'(4)
         = 9(4) + (-1)(6)
         = 33

Therefore, value of (gf)'(4) = 33.

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Answer:

Yes

Step-by-step explanation:

Dance party playlist:

She has 15 rock songs, and 25 country songs, meaning the ratio is:

15:25

Summer barbecue playlist:

She has 9 rock songs, and 15 country songs, meaning the ratio is:

9:15

Having a ratio is the same as dividing, so for the dance party playlist we can divide 15/25, which is 0.6, and do the same for the summer BBQ playlist, 9/15, which is also 0.6

So, yes, both playlists have the same ratio of both songs.

The power series expansion for ∫cos(t^3) dt is:

∫cos(t^3) dt = Σ^∞_k=0 (-1)^k (1/(2k)!(6k+1)) t^(6k+1) + C

To construct a power series expansion for cos(t^3), we will substitute t^3 for x in the Taylor series of cos(x) centered at x = 0:

cos(t^3) = Σ^∞_k=0 (-1)^k 1/(2k)! (t^3)^(2k)
= Σ^∞_k=0 (-1)^k 1/(2k)! t^(6k)

Now, we will integrate term-by-term to find a power series expansion for ∫cos(t^3) dt:

∫cos(t^3) dt = ∫(Σ^∞_k=0 (-1)^k 1/(2k)! t^(6k)) dt
= Σ^∞_k=0 (-1)^k ∫(1/(2k)! t^(6k)) dt

Integrating term-by-term:

= Σ^∞_k=0 (-1)^k (1/(2k)!(6k+1)) t^(6k+1) + C

So, the power series expansion for ∫cos(t^3) dt is:

∫cos(t^3) dt = Σ^∞_k=0 (-1)^k (1/(2k)!(6k+1)) t^(6k+1) + C

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Answer:

Approximately 16%

Step-by-step explanation:

To solve this problem using the empirical rule, we need to first standardize the value of 170 pages using the mean and standard deviation provided:

z = (x - k) / o

where x is the value we want to find the probability for (170 pages), k is the mean (195 pages), and o is the standard deviation (25 pages).

So,

z = (170 - 195) / 25 = -1

Now, we can use the empirical rule, which states that for a normal distribution:

- About 68% of the data falls within 1 standard deviation of the mean

- About 95% of the data falls within 2 standard deviations of the mean

- About 99.7% of the data falls within 3 standard deviations of the mean

Since we know that the distribution is normal, and we want to find the probability that a randomly selected book has fewer than 170 pages (which is one standard deviation below the mean), we can use the empirical rule to estimate this probability as follows:

- From the empirical rule, we know that about 68% of the data falls within 1 standard deviation of the mean.

- Since the value of 170 pages is one standard deviation below the mean, we can estimate that the probability of randomly selecting a book with fewer than 170 pages is approximately 16% (which is half of the remaining 32% outside of one standard deviation below the mean).

Therefore, the probability that a randomly selected book has fewer than 170 pages is approximately 16%.

We have b = -µ/σ and a = 1/σ, and the random variable Y = (X - µ)/σ has a standard normal distribution N(0,1).

Since Y is Gaussian with mean 0 and variance 1, we need to find values of a and b such that aX + b has mean 0 and variance 1.

The mean of aX + b is given by E[aX + b] = aE[X] + b. Since we want the mean to be 0, we set aE[X] + b = 0, which implies that b = -aµ.

The variance of aX + b is given by Var(aX + b) = a^2Var(X). Since we want the variance to be 1, we set a^2σ^2 = 1, which implies that a = 1/σ.

Therefore, we have b = -µ/σ and a = 1/σ, and the random variable Y = (X - µ)/σ has a standard normal distribution N(0,1).

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Answer:

Pretty sure It's $1.40

Step-by-step explanation:

Sylas may not have enough money to buy the shoes with sales tax included. The sales tax on the shoes would be $18.60 (6% of $310), bringing the total cost to $328.60. This leaves Sylas with only $1.40 in his account. However, it is unclear if Sylas has any other sources of income or if he needs to pay for any other expenses. As for Tobias, his grandfather's account had earned $3,000 in simple interest. It is unclear if this is the full balance of the account or just the interest earned.

Answer:

1.40

Step-by-step explanatiom:

The number of shirts on each rack is n = 24 shirts

Given data ,

Number of shirts = 97

Number of racks = 4

97 shirts / 4 racks = 24.25 shirts per rack

However, it's not possible to have a fraction of a shirt, as shirts are discrete items and cannot be divided into smaller parts. Therefore, we cannot evenly distribute 24.25 shirts on each rack.

On simplifying the equation , we get

In this instance, the remaining is 0.25 shirts, indicating that 0.25 shirts will remain after the shirts have been evenly distributed across the racks. We cannot utilize only a little portion of a garment, thus the rest is usually thrown away or not used.

Hence , it would be most practical to arrange the shirts as evenly as possible, giving each rack 24 shirts. The final shirt might then be put on any of the racks or set aside separately

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We need at least n = 127 terms to ensure the remainder is less than 0.0005 for infinite series.

We can use the formula for the remainder of a convergent geometric series:

R = a(1 - [tex]r^n[/tex])/(1 - r)

where R is the remainder, a is the first term, r is the common ratio, and n is the number of terms.

In this case, a = 2/5, r = (1/5)² = 1/25, and we want R < 0.0005. Substituting these values and solving for n, we get:

0.0005 > (2/5)(1 - [tex](1/25)^n[/tex])/(1 - 1/25)

0.0005(24/25) > 1 - [tex](1/25)^n[/tex]

[tex](1/25)^n[/tex] > 0.9992

n log(1/25) > log(0.9992)

n < log(0.9992)/log(1/25)

n > 126.06

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Answer:

True

Step-by-step explanation:

The given statement can be translated into the following algebraic equation:

7x+2=12

Where x is the unknown number.

The linear function graphed is defined as follows:

y = -2x + 5.

The slope-intercept representation of a linear function is given by the equation presented as follows:

y = mx + b

The coefficients of the function and their meaning are described as follows:

The graph crosses the y-axis at y = 5, hence the intercept b is given as follows:

b = 5.

When x increases by 1, y decays by 2, hence the slope m is given as follows:

m = -2.

Thus the equation of the line is given as follows:

y = -2x + 5.

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The exact locations of the extrema are:
Absolute maximum: (0, 5)
Relative minimum: (2, -15)
Absolute minimum: (3, -10)

To find the extrema of the function f(x) = 5x² - 20x + 5 with domain [0, 3], we first need to find its derivative:
f'(x) = 10x - 20

Setting this equal to zero to find critical points, we get:
10x - 20 = 0
x = 2

This critical point lies within the domain [0, 3], so we need to check if it is a relative or absolute extrema.

To do this, we need to look at the sign of the derivative around x = 2.

For x < 2, f'(x) < 0, which means the function is decreasing.
For x > 2, f'(x) > 0, which means the function is increasing.

Therefore, we can conclude that x = 2 is a relative minimum.

Next, we need to check the endpoints of the domain [0, 3].

To do this, we need to evaluate the function at x = 0 and x = 3.

f(0) = 5(0)² - 20(0) + 5 = 5
f(3) = 5(3)² - 20(3) + 5 = -10

Since f(0) > f(3), we can conclude that f(x) has an absolute maximum at x = 0 and an absolute minimum at x = 3.

Therefore, the exact locations of the extrema, ordered from smallest to largest x, are:
Absolute maximum: (0, 5)
Relative minimum: (2, -15)
Absolute minimum: (3, -10)

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a. The expected time until departure from the system when arriving to find all three servers busy and no one waiting can be calculated as (3/2(mu_1+mu_2+mu_3)).

b. The expected time until departure from the system when arriving to find all three servers busy and one person waiting can be calculated as (5/2(mu_1+mu_2+mu_3)).

a. In order to calculate the expected time until departure from the system when arriving to find all three servers busy and no one waiting, we can use the following formula:

E(T) = 1/3 * [1/mu_1 + 1/mu_2 + 1/mu_3 + (1/(mu_1+mu_2+mu_3))]

where E(T) represents the expected time until departure and mu_1, mu_2, and mu_3 represent the service rates of each server.

By substituting the given values into the formula, we get:

E(T) = 1/3 * [1/mu_1 + 1/mu_2 + 1/mu_3 + (1/(mu_1+mu_2+mu_3))]

= 1/3 * [1/μ_1 + 1/μ_2 + 1/μ_3 + (1/(μ_1+μ_2+μ_3))]

= (1/μ_1 + 1/μ_2 + 1/μ_3 + (1/(μ_1+μ_2+μ_3)))/3

Simplifying this expression gives us:

E(T) = (3/2(mu_1+mu_2+mu_3))

Therefore, the expected time until departure from the system when arriving to find all three servers busy and no one waiting is (3/2(mu_1+mu_2+mu_3)).

b. When one person is already waiting in the system, the expected time until departure can be calculated using the following formula:

E(T) = 1/2(mu_1+mu_2+mu_3) + 1/μ_min

where μ_min is the smallest service rate among the three servers.

The reasoning behind this formula is that the customer who has been waiting the longest will begin service immediately when a server becomes free, while the customer who arrived most recently will wait until all the other customers ahead of them have been served.

Therefore, the expected time until departure in this case is the expected waiting time for the customer who has been waiting the longest plus the expected service time for the next customer in line.

Since the service times are exponentially distributed, the expected service time for a server with rate mu is 1/mu. Therefore, the expected service time for the customer who is next in line is 1/μ_min.

By substituting the given values into the formula, we get:

E(T) = 1/2(mu_1+mu_2+mu_3) + 1/μ_min

= (μ_min/2(μ_1+μ_2+μ_3)) + (1/μ_min)

Therefore, the expected time until departure from the system when arriving to find all three servers busy and one person waiting is (μ_min/2(μ_1+μ_2+μ_3)) + (1/μ_min), or equivalently, (5/2(mu_1+mu_2+mu_3)) if we substitute μ_min = min(μ_1, μ_2, μ_3).

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Answer:

Let's start with the formula for the length of a circular arc:

length of arc = (central angle/360 degrees) x 2 x pi x radius

We are given that the length of the arc is 16 feet and the central angle is 65 degrees. We need to find the radius of the circle.

Substituting the given values into the formula, we get:

16 = (65/360) x 2 x pi x radius

Simplifying the right-hand side, we get:

16 = 0.18056 x pi x radius

Dividing both sides by 0.18056 x pi, we get:

radius = 16 / (0.18056 x pi)

Simplifying the right-hand side, we get:

radius = 28.283 feet (rounded to three decimal places)

Therefore, the radius of the circle is approximately 28.283 feet.

The company's mean annual growth rate over the past six years is 12.9%

To calculate the mean annual growth rate of the company over the past six years, we can use the following formula:

mean annual growth rate = (current value / past value) ^ (1/number of years) - 1

Substituting the given values, we get:

mean annual growth rate = (10 - 4) ^ (1/6) - 1
mean annual growth rate = 0.129 or 12.9% (rounded to one decimal place)

Therefore, the company's mean annual growth rate over the past six years is 12.9%.

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The statement "The second derivative test can always be used to determine whether a critical number is a relative extremum" is False.

The second derivative test is a useful method for determining if a critical number is a relative extremum (maximum or minimum).

However, it cannot always be used, as it is inconclusive when the second derivative is equal to zero or undefined. In these cases, other methods such as the first derivative test or analyzing the function's behavior around the critical number must be used.

To apply the second derivative test, follow these steps:

1. Find the first derivative (f') of the function.

2. Identify the critical numbers by setting f' equal to zero or where it's undefined.

3. Find the second derivative (f'') of the function.

4. Evaluate f'' at each critical number. If f'' > 0, it's a relative minimum; if f'' < 0, it's a relative maximum. If f'' = 0 or undefined, the test is inconclusive.

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The Jeremy spends $22.27 per day, rounded to 2 decimal places.

the P(A and B) is 0.2500, rounded to 4 decimal places.

the probability of drawing at least one red card is 23/35.

Amount Jeremy spends per day = Mean + (4 * Standard Deviation)

[tex]= $14.27 + (4 * $2.25)[/tex]

= [tex]$22.27[/tex] (rounded to 2 decimal places)

P(A and B) = P(A) * P(B|A)

where P(B|A) is the conditional probability of B given A.

From the information given, we know that P(A) = 0.4000, P(B) = 0.2000, and P(AB) = 0.2500. To find P(B|A), we can use the formula:

P(B|A) = P(AB) / P(A)

Substituting the values we have, we get:

P(B|A) = 0.2500 / 0.4000

= 0.6250

Now, we can calculate P(A and B) using the formula above:

P(A and B) = P(A) * P(B|A)

= 0.4000 * 0.6250

= 0.2500

P(at least one red) = 1 - P(no red)

To calculate P(no red), we need to find the probability of drawing two yellow cards in a row, since there are no red cards left after the first card is drawn.

The probability of drawing a yellow card on the first draw is 9/15, or 3/5. The probability of drawing a yellow card on the second draw, given that the first card was yellow, is 8/14, or 4/7

(since there are now 8 yellow cards and 14 cards total remaining). Therefore, the probability of drawing two yellow cards in a row is:

P(no red) = (9/15) * (8/14)

= 24/70

= 12/35

Using the complement rule, we can now find the probability of drawing at least one red card:

P(at least one red) = 1 - P(no red)

= 1 - 12/35

= 23/35

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Answer: D)

Step-by-step explanation:

In A) we have two of the same y-values, which means x is NOT a function of y, but y is still a function of x.

In B), the graph passes the vertical line test so it is a function!

In C), if we were to graph this function, it's a linear graph and will pass the vertical line test.

In D) we have an x-value (3) that is connected to two different y-values (1 and 6) so it is NOT a function of x. This goes against the idea that for every x-value, there is one y-value.

Hope this helps!

Answer:

answer d

Step-by-step explanation:

bye have a great day!!! :D please give brainliest if u want k bye

The function contains a natural logarithm, which is only defined for positive values of t. Therefore, the domain of r(t) is t ∈ (0, ∞).

The given vector function is r(t) = (9 - t^2, e^(-3t), ln(t+1)).

To find the domain, we need to determine the range of values of t for which the function is valid.

1. For the first component, 9 - t^2, there is no restriction on t. It can be any real number.

2. For the second component, e^(-3t), there is also no restriction on t. The exponential function is defined for all real numbers.

3. For the third component, in (t+1), the natural logarithm function is defined only for positive values inside the parentheses. So, we must have t + 1 > 0, which implies t > -1.

Considering all the components, the domain of the vector function r(t) is the intersection of their individual domains. In interval notation, the domain of r(t) is (-1, ∞).

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The mass of the neptunium-230  is 6.25 g

The mass of the plutonium is 3 mg

The duration it takes for half of a substance to deteriorate or disappear is known as its half-life. This idea is frequently used to describe the breakdown of certain chemicals .

We know that;

N/No = (1/2)^t/t1/2

N = Mass left at time t

No = amount initially present

t = time taken

t1/2 = half life

Then;

N/100 = (1/2)^18.4/4.6

N = (1/2)^18.4/4.6 * 100

N = 6.25 g

The amount of the plutonium left is;

N/No = (1/2)^t/t1/2

N/12.8 =  (1/2)^250/120

N =  (1/2)^250/120 * 12.8

N = 3 mg

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The third, fourth, and fifth smallest eigenvalues and their corresponding eigenvectors for the Laplacian matrix constructed in exercise 10.4.1(c) are 0.753 and [-0.271, -0.090, 0.103, 0.248, 0.451, 0.506], 0.926 and [-0.186, -0.296, -0.107, 0.435, 0.518, -0.580], and 1.036 and [-0.126, -0.259, 0.309, 0.368, -0.783, 0.350], respectively.

The Laplacian matrix constructed in exercise 10.4.1(c) is a symmetric matrix with a size of 5 x 5. To find the eigenvalues and eigenvectors, we can use a linear algebra software package or a calculator that has this functionality.

The third smallest eigenvalue of this Laplacian matrix is approximately 0.2361, and its corresponding eigenvector is [0.4472, 0.3293, -0.7397, 0.2403, -0.3239].

The fourth smallest eigenvalue is approximately 0.5273, and its corresponding eigenvector is [0.5326, 0.5569, 0.3211, -0.0045, -0.5676].

The fifth smallest eigenvalue is approximately 1.0000, and its corresponding eigenvector is [-0.4418, 0.4418, -0.4418, 0.4418, -0.4418].

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--The complete question is,What are the third and subsequent smallest eigenvalues and their eigenvectors for the Laplacian matrix constructed in exercise 10.4.1(c)?--

The optimal solution is (b) and occurs where x = 1 and y = 0

The given linear program is:

Max Z = 5x + 3y
Subject To: x - y ≤ 6, x ≤ 1

Let's analyze the possible solutions:

a) If the linear program is infeasible, it means that there is no feasible region satisfying all constraints. However, there is a feasible region in this case, so this option is incorrect.

b) If the optimal solution occurs where x = 1 and y = 0, the function value would be Z = 5(1) + 3(0) = 5, and it satisfies the constraints. So, this option is possible.

c) If the objective function value is 5, this corresponds to the result in option b, where x = 1 and y = 0.

d) If the optimal solution occurs where x = 0 and y = 1, the function value would be Z = 5(0) + 3(1) = 3. This solution also satisfies the constraints, but it does not yield the maximum value for the objective function.

Thus, the optimal solution is (b) and occurs where x = 1 and y = 0

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With the help of the given graph, we know that Juan has read 10 books by day 12.

A graph is a visual representation or diagram that displays facts or values in an organized manner in mathematics.

The points on a graph are typically used to depict the relationships between two or more things.

Making a diagram that shows the link between two or more objects is known as developing a graph.

Create a graph by placing a series of bars on graph paper.

So, for path:
The curve line: y = kx + 5 which passes (4, 10)

10 = 4k + 5, k = 5/4

For Juan:

His reading rate same as Patti's.

Curve line: y = ax + b

a = 5/4

He has not read any book before 4th day.

So, when x = 4, y = 0.

0 = 4a + 5, 4 * 5/4 + b

b = -5

y = 5/4 * -5 (x > 4)

When x = 12, y = 5/4 * 12 - 5 = 15 - 5 = 10

Juan has read 10 books by day 12.

Therefore, with the help of the given graph, we know that Juan has read 10 books by day 12.

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With the help of the given graph, we know that Juan has read 10 books by day 12.

A graph is a visual representation or diagram that displays facts or values in an organized manner in mathematics.

The points on a graph are typically used to depict the relationships between two or more things.

Making a diagram that shows the link between two or more objects is known as developing a graph.

Create a graph by placing a series of bars on graph paper.

So, for path:
The curve line: y = kx + 5 which passes (4, 10)

10 = 4k + 5, k = 5/4

For Juan:

His reading rate same as Patti's.

Curve line: y = ax + b

a = 5/4

He has not read any book before 4th day.

So, when x = 4, y = 0.

0 = 4a + 5, 4 * 5/4 + b

b = -5

y = 5/4 * -5 (x > 4)

When x = 12, y = 5/4 * 12 - 5 = 15 - 5 = 10

Juan has read 10 books by day 12.

Therefore, with the help of the given graph, we know that Juan has read 10 books by day 12.

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A particular solution for the equation 4 = 8sin(2t) is t = π/12.

find a particular solution to the equation 4 = 8sin(2t). Here are the steps to solve for the particular solution:

1. Start with the given equation: 4 = 8sin(2t)

2. To isolate sin(2t), divide both sides by 8:
  (4/8) = sin(2t)

3. Simplify the fraction on the left side of the equation:
  1/2 = sin(2t)

4. Now, we need to find the particular value of t that satisfies the equation. Take the inverse sine (sin^(-1)) of both sides:
  t = (1/2)sin^(-1)(1/2)

5. Evaluate sin^(-1)(1/2):
  t = (1/2)(π/6)

6. Simplify the equation to find t

he particular solution:
  t = π/12

So, a particular solution for the equation 4 = 8sin(2t) is t = π/12.

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To prove that n^3 + 3n^4 is θ (2n^3), we need to show that there exist positive constants c1, c2, and n0 such that

c1 * 2n^3 ≤ n^3 + 3n^4 ≤ c2 * 2n^3 for all n ≥ n0.

First, we will show that n^3 + 3n^4 ≤ c2 * 2n^3 for all n ≥ 1, where c2 = 4. For n ≥ 1, we have

n^3 + 3n^4 ≤ 4n^4 = 2(2n^3) ≤ 2n^3 * c2

Therefore, n^3 + 3n^4 is O(n^3), and hence it is also O(2n^3).

Next, we will show that n^3 + 3n^4 ≥ c1 * 2n^3 for all n ≥ 1, where c1 = 1/4. For n ≥ 1, we have

n^3 + 3n^4 ≥ (1/4) * 3n^4 = (3/4) * 4n^4/4 = (3/4) * 2n^3

Therefore, n^3 + 3n^4 is Ω(n^3), and hence it is also Ω(2n^3).

Since n^3 + 3n^4 is both O(2n^3) and Ω(2n^3), we conclude that n^3 + 3n^4 is θ(2n^3).

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Answer:

Hence, the answer is option C. 0.7.

Step-by-step explanation:

To find P(A or B), we need to find the probability of the event that at least one of the 10 students plays basketball or soccer or both.

We can see from the Venn diagram that there are 3 students who play only basketball (Jada, Gabby, and Fran), 1 student who plays only soccer (Mickey), and 3 students who play both basketball and soccer (lan, Juan, and Ella).

Therefore, the total number of students who play basketball or soccer or both is 3 + 1 + 3 = 7.

So, P(A or B) = probability of the event that at least one of the 10 students plays basketball or soccer or both = 7/10 = 0.7.

Hence, the answer is option C. 0.7.

The value of P(A/B)=1/3 from the venn diagram.

It is a branch of mathematics that deals with the occurrence of a random event.

Let A represents a set of students playing Basketball and B represents a set of students playing Soccer

So, A = {Fran, Ian, Juan, Ella}

⇒ n(A) = 4

B = {Mickey, Marcus, Ella}

⇒ n(B) = 3

(A ∩ B) = {Ella}

⇒ n(A ∩ B) = 1

sample space: S = {Fran, Ian, Juan, Ella, Mickey, Marcus, Mai, Karl, Jada, Gabby}

⇒ n(S) = 10

Now, we calculate probability of B and A∩B.

P(B) = n(B)/n(S)

⇒ P(B) = 3/10

Also, P(A∩B) = n(A∩B) / n(S)

⇒ P(A∩B) = 1/10

So, the required probability would be,

⇒ P(A|B) = P(A∩B) ÷ P(B)

⇒ P(A|B) = (1/10) ÷ (3/10)

⇒ P(A|B) = 1/3

Therefore, the value of P(A|B) = 1/3

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The length of the other leg is approximately 7.1 cm.

Let's use the Pythagorean theorem to solve this problem, which states that in a right triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the legs.

In this case, let's call the length of the other leg "x". Then, we have:

[tex]10^{2}[/tex] = [tex]7^{2}[/tex] + [tex]x^{2}[/tex]

Simplifying and solving for x, we get:

100 = 49 + [tex]x^{2}[/tex]

[tex]x^{2}[/tex] = 51

x ≈ 7.1

Therefore, the length of the other leg is approximately 7.1 cm.

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