The equation has only irrational or complex roots.
What is Algebra?
Algebra is a branch of mathematics that deals with symbols and the rules for manipulating these symbols. It involves the study of mathematical symbols and the rules for combining and manipulating them to solve equations and analyze relationships between quantities.
To show that the equation [tex]$x^3 - 3x + 1 = 0$[/tex] has no rational roots, we can use the Rational Root Theorem. According to the theorem, any rational root of the equation must be of the form [tex]\frac{p}{q}$,[/tex] where p is a factor of the constant term (in this case, 1) and q is a factor of the leading coefficient (in this case, 1).
Let's examine all possible rational roots of the equation:
[tex]$p = \pm 1, q = \pm 1$[/tex]
Possible rational roots: [tex]$\pm 1$[/tex]
We can substitute these values into the equation and check if any of them satisfy the equation.
For [tex]x = 1$: $1^3 - 3(1) + 1 = 1 - 3 + 1 = -1 \neq 0$[/tex]
For [tex]x = -1$: $(-1)^3 - 3(-1) + 1 = -1 + 3 + 1 = 3 \neq 0$[/tex]
Since none of the possible rational roots satisfy the equation, we can conclude that the equation [tex]x^3 - 3x + 1 = 0$[/tex] has no rational roots.
Therefore, the equation has only irrational or complex roots.
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It takes me into 30 minutes to walk from home to school when walking at 5 km per hour What is her average cycling speed If it takes her 15 minutes by bike to travel the same distance
Answer:
10 km/h
Step-by-step explanation:
I'm not really sure about this but no ones answering your question and I wanna help.
So basically to calculate the average speed you need to divide the distance travelled by time taken
But you do not have the distance traveled. But it is mentioned that it takes u 30 minutes to walk from home to school when walking at 5 km/h so to find the distance all you have to do is... 30 x 5 = 150 km
Now that we have the time and distance all we have to do is find the average speed.
Average Speed = distance ÷ time
So 150 ÷ 15 = 10 km/h
Find the area to the following figure. Round to the one decimal place.
Answer:
91in^2
Step-by-step explanation:
First, add 11 and 15: 11 + 15 = 26
Second, divide it by 2: 26/2 = 13
Third, multiply it by the height: 13 * 7 = 91in^2
What is the area of this polygon?
The middle is a square with side length of 12cm
Area of the square = 12 x 12 = 144 cm^2
There are 4 triangles with base of 13cm and height of 8 cm
Area of triangle = 1/2 x base x height
Area = 1/2 x 12 x 8 = 48cm^2 each
48 x 4 = 192 cm^2
Total area = 144 + 192 = 336 cm^2
HELP ASAP SKAKSKKAMAAAAA
Answer:
(240,20)
Step-by-step explanation:
use the linspace and plot commands in matlab to generate a figure containing the curves y=1.5sin(x) and y=x between x=0 and x=2.5
To generate a figure containing the curves y = 1.5*sin(x) and y = x in MATLAB using the linspace and plot commands, you can follow the steps below:
matlab
% Set the range of x values
x = linspace(0, 2.5, 100);
% Calculate y values for each curve
y1 = 1.5*sin(x);
y2 = x;
% Plot the curves
plot(x, y1, 'b', x, y2, 'r')
% Add labels and title
xlabel('x')
ylabel('y')
title('Curves: y = 1.5*sin(x) and y = x')
% Add a legend
legend('y = 1.5*sin(x)', 'y = x')
% Display the grid
grid on
In this code, we use linspace to create a range of x values from 0 to 2.5 with 100 points. Then, we calculate the corresponding y values for each curve using the equations y1 = 1.5*sin(x) and y2 = x. We use the plot command to plot the curves, with 'b' and 'r' specifying the colors of the curves. Next, we add labels, title, and a legend to the graph. Finally, we display the grid.
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When h is 1/2 and j is 1/3,g is 4. If g varies jointly with h and j, what is the value of g when h is 2 and j is 3?
Answer:
The value of g is 144 when h is 2 and j is 3 .
Step-by-step explanation:
If g varies jointly with h and j.
g = khj
Where k is the constant of proportionality.
Put value in the above
k = 4 × 6
k = 24
As when h = 2 , j = 3 and k = 24 .
Put in the above
g = 2 × 3 × 24
g = 144
Therefore the value of g is 144 when h is 2 and j is 3 .
not sure what the answer is
Given:
Base dimensions of a rectangular prism = 15 cm × x cm
The height of the prism = 8 cm
Volume of the prism = 600 cm.
To find:
The value of x.
Solution:
Base area of the prism is:
[tex]B=length\times width[/tex]
[tex]B=15\times x[/tex]
[tex]B=15x[/tex]
Volume of the prism is:
[tex]V=Bh[/tex]
Where, B is the base area and h is the height of the prism.
Putting [tex]V=600,B=15x,h=8[/tex], we get
[tex]600=15x\times 8[/tex]
[tex]600=(8)(15)x[/tex]
[tex]\dfrac{600}{(8)(15)}=x[/tex]
Therefore, the correct option is C.
Tommy is helping his mom at the grocery store. He notices that 5 pounds of potatoes cost $2.25. How much would 7 pounds of potatoes cost?
A. $3.45
B. $0.45
C. $3.15
D. $1.61
Answer:
Cost of 7 pound potato = $3.15
Step-by-step explanation:
Given:
Cost of 5 pound potato = $2.25
Find:
Cost of 7 pound potato
Computation:
Cost of 1 pound potato = 2.25 / 5
Cost of 1 pound potato = $0.45
Cost of 7 pound potato = 7 x Cost of 1 pound potato
Cost of 7 pound potato = 7 x 0.45
Cost of 7 pound potato = $3.15
Given any two squares, we can construct a square that equals (in area) the sum of the two given squares. Why?
We cannot construct a square that equals the sum of the areas of two given squares. This statement contradicts the mathematical principles and properties of squares and the Pythagorean theorem.
The statement that given any two squares, we can construct a square that equals the sum of the two given squares is actually false. This statement goes against the well-known mathematical concept known as the Pythagorean theorem.
The Pythagorean theorem states that in a right-angled triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides. This theorem holds true for right-angled triangles, but it does not hold true for squares.
In fact, if we take two squares and try to add their areas together, the result will not be a square with an area equal to the sum of the two given squares. The resulting shape will be a non-square rectangle or some other irregular shape.
Therefore, we cannot construct a square that equals the sum of the areas of two given squares. This statement contradicts the mathematical principles and properties of squares and the Pythagorean theorem.
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Lindsay and Lorraine are trying to match the jump rope world record. Together, they need to jump 48 times in a row. Lindsay has gotten 14 jumps in a row, and Lorraine has gotten 13. Write an equation using (j) as the variable and show your work to determine how many more jumps they need to complete.
( if u steal my points ill steal yours)
(no links or ill report)
Answer: They need to complete 21 more jumps all together .
Step-by-step explanation: So 14+13=J
14+13=27
27=j
World record: 48; 48-27=21
They will have to jump 21 more times in a row .
What is the solution to the equation?
O
a+5=9
a+53 -9
a+52 +53-9-5
a=3
a+
a+53-9
O a+52 +53 - 9+53
-
a+53-9
3
|
a = 14 3
6
2
Answer:
The format of this equation is wrong
Hey I'm Chloe Can you Help Me, I will give Brainlest, Thank you :)
During a professional baseball game, every spectator placed his or her ticket stub into one of several containers. After the game, the coach chose twenty people to march in the victory parade. What is the sample in this situation?
Answer:
The sample is the amount of people because not everyone is getting chosen
Step-by-step explanation:
I also agree, the coach choose certain people to march cuz not everyone is gonna be able to get used.
Find the center of the ellipse.
x2 + 4y2 – 10x – 40y + 121 = 0
Answer:
i dont what an ellipse is but here's the answer:
8x + 32y = 121
Answer:
123‐10×40y=0
10×+40y=123
Shoulda let me have you i coulda made you so happy but ion do 2nd chances, forever i wish u happiness PERIODT DOE.
now its time to make bankk
Answer:
periodttt. get out ya bag n make det money up.
Step-by-step explanation:
brainliestt:)?
What is the rate of change of the function described in
the table?
A. 12/5
B. 5
C. 25/2
D. 25
Answer:
B. 5
Step-by-step explanation:
This table does not describe a linear relationship. This is because the table does not have a constant rate of change; between the first two points, the function changes by
(1/2 - 1/10)/(0--1) = (5/10 - 1/10)/(1) = 5/10 - 1/10 = 4/10 = 2/5
Between the second two points, the function changes by
(5/2-1/2)/(1-0) = (4/2)/1 = 4/2 = 2
Comparing the first two y-coordinates, we have 1/10 and 1/2 = 5/10. This is the result of multiplication by 5.
Comparing the second two y-coordinates, we have 1/2 and 5/2. This is the result of multiplication by 5.
Comparing the rest of the y-coordinates, we can see that each time, the y-coordinate is multiplied by 5. This means the rate of change is 5.
4*10^(-3x)=18 Express the solution as a logarithm in base-101010.
Answer:
Hi how are you doing today Jasmine
Answer:
x= -1/3•log10(9/2)
x= -0.218
PLEASE HELP I HAVE TO TURN THIS IN IN 1 HOUR!
A round clock on a classroom wall has a diameter of 12 inches. What is the approximate area of the clock?
A. 38 square inches
B. 113 square inches
C. 226 square inches
D. 452 square inches
NO SPAMMING OR LINKS THEY WILL BE REPORTED!
Does any one know the answer to this thank you
Answer:
The First choice
Step-by-step explanation:
whats 38 divided by 70
Answer:
.5428571 repeating
or 19/35
Select the proposition that is a tautology. a. (p ^ q) → p b.(p ∨ q) → p с. (р ^ q) → р d. (p ^ q) → p
The proposition that is a tautology is d. (p ^ q) → p. In a tautology, the truth value of the proposition is always true, regardless of the truth values of its individual components.
To determine if a proposition is a tautology, we can construct a truth table and evaluate all possible combinations of truth values for its variables.
For option d, (p ^ q) → p, we have the following truth table:
p q (p ^ q) (p ^ q) → p
T T T T
T F F T
F T F T
F F F T
The proposition that is a tautology is d. (p ^ q) → p.
In a tautology, the truth value of the proposition is always true, regardless of the truth values of its individual components. To determine if a proposition is a tautology, we can construct a truth table and evaluate all possible combinations of truth values for its variables.
For option d, (p ^ q) → p, we have the following truth table:
p q (p ^ q) (p ^ q) → p
T T T T
T F F T
F T F T
F F F T
As we can see, regardless of the truth values of p and q, the proposition (p ^ q) → p always evaluates to true. Therefore, option d is a tautology.
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A group of researchers is designing an experiment to test whether working late at night reduces a person's productivity. The researchers selected a sample of 60 adults, and over the next month, 30 of them will complete assigned tasks late at night whereas the remaining 30 will complete the same tasks during the afternoon. At the end of the month, the researchers will compare the average amount of time it takes each group to complete the tasks. Why is it important that the researchers use randomization to assign each of the adults to a group
Answer: Randomization prevents the researchers from specifically assigning all adults who regularly stay up late to complete assigned tasks late at night.
-Randomization ensures each group will be similar in everything except the time of day they are assigned to work.
-Randomization prevents the adults from selecting their own group.
Step-by-step explanation:
The options include:
a. Randomization ensures each group will be similar in everything except the time of day they are assigned to work.
b. Randomization prevents the adults from selecting their own group.
c. Randomization eliminates lurking variable from the experiment.
d. Randomization prevents the researchers from specifically assigning all adults who regularly stay up late to complete assigned tasks late at night.
e. Randomization ensures that there'll be an equal number of adults in each group.
Randomization refers to a method that is based on chance alone whereby the participants in a particular study are assigned to treatment group. Based on the information given, it us important that the researchers use randomization to assign each of the adults to a group because:
• Randomization ensures each group will be similar in everything except the time of day they are assigned to work.
• Randomization prevents the researchers from specifically assigning all adults who regularly stay up late to complete assigned tasks late at night.
• Randomization prevents the adults from selecting their own group.
Given the differential equation
dy/dx = 3xy+y^2 / x^2+xy
i) Show that this equation is homogeneous.
ii) By substituting y =xv, solve this differential equation with initial
condition y(1) = 4.
The given differential equation is shown to be homogeneous, and the solution to the equation with the initial condition y(1) = 4 is :
y = 6x^2 * e^(-x/2) - 2x.
i) To show that the differential equation is homogeneous, we need to verify that it is invariant under the transformation y = ux, where u is a function of x.
Let's substitute y = ux into the given differential equation:
dy/dx = 3xy + y^2 / x^2 + xy
Using the chain rule, we can express dy/dx in terms of u and x:
dy/dx = d(ux)/dx = u + x * du/dx
Substituting this into the differential equation:
u + x * du/dx = 3x(ux) + (ux)^2 / x^2 + x(ux)
Simplifying the equation:
u + x * du/dx = 3u + u^2 / x + u
The equation can be further simplified:
x * du/dx = 2u + u^2 / x
We can see that the resulting equation is independent of x. Hence, the original differential equation is homogeneous.
ii) To solve the homogeneous differential equation, let's substitute y = xv back into the equation:
x * du/dx = 2u + u^2 / x
Multiplying through by x:
x^2 * du/dx = 2xu + u^2
Rearranging the equation:
x^2 * du / (2u + u^2) = dx
We can now integrate both sides:
∫ x^2 * du / (2u + u^2) = ∫ dx
The left-hand side can be further simplified using partial fraction decomposition:
∫ (A/u + B/(u+2)) du = ∫ dx
Solving for A and B, we get:
A = -2, B = 1
Substituting back into the integral:
∫ (-2/u + 1/(u+2)) du = ∫ dx
Simplifying the integral:
-2ln|u| + ln|u+2| = x + C
Now substituting u = y/x:
-2ln|y/x| + ln|(y/x)+2| = x + C
Using properties of logarithms, we can simplify this equation further:
ln((y+2x)/x^2) = -x/2 + C
Taking the exponential of both sides:
(y+2x)/x^2 = e^(-x/2+C)
Simplifying the right-hand side by combining e^C into a constant A:
(y+2x)/x^2 = A * e^(-x/2)
Now, solving for y:
y + 2x = Ax^2 * e^(-x/2)
Finally, rearranging the equation to solve for y:
y = Ax^2 * e^(-x/2) - 2x
Given the initial condition y(1) = 4, we can substitute x = 1 and y = 4 into the equation:
4 = A * e^(-1/2) - 2
Solving for A:
A * e^(-1/2) = 6
A = 6 * e^(1/2)
Substituting the value of A back into the equation, we have:
y = 6x^2 * e^(-x/2) - 2x
So the solution to the differential equation with the initial condition y(1) = 4 is y = 6x^2 * e^(-x/2) - 2x.
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The moment generating function for the standard normal distribution is given by My(t)=et. Use this MGF (and its derivatives) to show that the mean and variance of the standard normal distribution is 0
Using the MGF and its derivatives, we have shown that the mean and variance of the standard normal distribution are both 0.
The MGF for the standard normal distribution is given as:
M(t) = e^(t²/2)
To find the mean of the standard normal distribution, we take the first derivative of the MGF with respect to t and evaluate it at t = 0:
M'(t) = (1/2)e^(t²/2) × 2t
Evaluating at t = 0:
M'(0) = (1/2)e⁰ × 2(0) = 0
Since the first derivative of the MGF evaluated at t = 0 is 0, this implies that the mean of the standard normal distribution is 0.
To find the variance of the standard normal distribution, we take the second derivative of the MGF with respect to t and evaluate it at t = 0:
M''(t) = (1/2)e^(t²/2) × 2t² + (1/2)e^(t²/2)×2
Evaluating at t = 0:
M''(0) = (1/2)e⁰ × 2(0)² + (1/2)e⁰ × 2
= 0 + 1
= 1
Since the second derivative of the MGF evaluated at t = 0 is 1, this implies that the variance of the standard normal distribution is 1.
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Under her cell phone plan, Lily pays a flat cost of $40 per month and $4 per gigabyte.
She wants to keep her bill under $60 per month. Write and solve an inequality which
can be used to determine x, the number of gigabytes Lily can use while staying within
her budget.
Answer:
16
Step-by-step explanation:
60-44
The inequality is $40 + 4x < $60 and she has to spend 5 gigabytes to stay within her budget
Note that:
> means greater than
< means less than
≥ means greater than or equal to
≤ less than or equal to
The total amount Lily has to spend has to be less than $60
The total amount she can spend can be represented with this equation
Flat cost + variable cost < $60
Flat cost = $40
Variable cost = cost per gigabyte x gigabyte
$4 × x = $4x
$40 + 4x < $60
To solve for x, combine similar terms
$4x < $60 - $40
$4x < $20
x < 5
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Miguel wants to estimate the average price of a book at a bookstore. The bookstore has 13,000 titles, but Miguel only needs a sample of 200 books. How could Miguel collect a sample of books that is:
cluster sample?
multistage sample?
oversamples?
To best collect a sample of books from the 13,000 titles at the bookstore, Miguel should use a cluster sampling method.
What is the best sampling method?The best sampling method Miguel should use is a cluster sample.
A cluster sample involves dividing the population into clusters or groups and randomly selecting entire clusters to include in the sample.
In this situation, Miguel could divide the bookstore's titles into clusters, such as by genre or shelf location, and randomly select clusters to sample books from.
his method would help ensure representation from different areas of the bookstore and provide a diverse sample of books.
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In which interval is the radical function f of x is equal to the square root of the quantity x squared plus 2 times x minus 15 end quantity increasing?
[3, [infinity])
(4, [infinity])
[–5, 3]
(–[infinity], –5] ∪ [3, [infinity])
The correct answer is, [–5, 3]. In the other words, the interval in which the function [tex]f(x) = \sqrt{x^2 + 2x - 15}[/tex] is increasing is [–5, 3].
To determine the interval in which the radical function [tex]f(x) = \sqrt{x^2 + 2x - 15}[/tex] is increasing, we need to find the interval(s) where the derivative of the function is positive.
Let's first find the derivative of f(x):
[tex]f'(x) = (1/2) * (x^2 + 2x - 15)^(-1/2) * (2x + 2)[/tex]
To find where f'(x) > 0, we set f'(x) = 0 and solve for x:
[tex](1/2) * (x^2 + 2x - 15)^(-1/2) * (2x + 2) = 0[/tex]
Since the derivative is never equal to zero (since the denominator (x^2 + 2x - 15)^(-1/2) is never equal to zero), there are no critical points.
To determine the intervals of increase, we can evaluate f'(x) at test points in each interval. We'll consider the intervals defined by the given answer choices:
[3, ∞):
Choose a test point x > 3, let's say x = 4.
Evaluate [tex]f'(4) = (1/2) * (4^2 + 24 - 15)^{(-1/2)} * (24 + 2)[/tex]
[tex]= (1/2) * (16 + 8 - 15)^{(-1/2)} * 10[/tex]
[tex]= (1/2) * (9)^{(-1/2)} * 10[/tex]
= (1/2) * (1/3) * 10
= 5/3
Since f'(4) > 0, the function is increasing in the interval [3, ∞).
(4, ∞):
Choose a test point x > 4, let's say x = 5.
Evaluate f'(5) = (1/2) * (5^2 + 25 - 15)^(-1/2) * (25 + 2)
= (1/2) * (25 + 10 - 15)^(-1/2) * 12
= (1/2) * (20)^(-1/2) * 12
Since f'(5) = 0, the function is not increasing in the interval (4, ∞).
[–5, 3]:
Choose a test point x in the interval, let's say x = 0.
Evaluate [tex]f'(0) = (1/2) * (0^2 + 20 - 15)^{(-1/2)} * (20 + 2)[/tex]
[tex]= (1/2) * (-15)^{-1/2} * 2[/tex]
[tex]= (1/2) * (1/\sqrt{15}) * 2[/tex]
[tex]= 1/\sqrt{15}[/tex]
Since f'(0) > 0, the function is increasing in the interval [–5, 3].
(–∞, –5] ∪ [3, ∞):
Since we have already determined the function is increasing in [–5, 3] and [3, ∞), this interval is valid.
Therefore, the correct answer is, [–5, 3]. In the other words, the interval in which the function [tex]f(x) = \sqrt{x^2 + 2x - 15}[/tex] is increasing is [–5, 3].
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iGive a combinatorial proof of 1, 2+ 2.3+3.4++ (x - 1)^n = 2 =>("") Hint: Classify sets of three numbers from the integer interval [0...n] by their maximum element.
By classifying sets of three numbers from the interval [0...n] by their maximum element, we have provided a combinatorial proof of the identity 1, 2 + 2.3 + 3.4 + ... + (x - 1)^n = 2^(n+1).
The combinatorial proof of the identity 1, 2 + 2.3 + 3.4 + ... + (x - 1)^n = 2^(n+1) revolves around classifying sets of three numbers from the integer interval [0...n] by their maximum element.
Let's consider the right-hand side of the equation, which is 2^(n+1). This represents the number of subsets of an n-element set. We can think of each element in the set as having two choices: either it is included in a subset or not. Therefore, there are 2 choices for each element, resulting in a total of 2^(n+1) subsets.
Now, let's look at the left-hand side of the equation, which is the sum 1 + 2 + 2.3 + 3.4 + ... + (x - 1)^n. We can interpret each term as follows:
1: Represents the number of subsets with a maximum element of 0, which is only the empty set.
2: Represents the number of subsets with a maximum element of 1, which includes the subsets {0} and {1}.
2.3: Represents the number of subsets with a maximum element of 2, which includes the subsets {0, 1}, {0, 2}, and {1, 2}.
Similarly, for each subsequent term (x - 1)^n, it represents the number of subsets with a maximum element of x-1.
Now, if we add up all these terms, we are essentially counting the total number of subsets from the original set. This matches the right-hand side of the equation, which is 2^(n+1).
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Which graph represents an equation with the values shown in the table?
Answer:
4
Step-by-step explanation:
Find the general solution of the given differential equation. 7 dy dx + 56y = 8
y(x) =
Give the largest interval I over which the general solution is defined. (Think about the implications of any singular points. Enter your answer using interval notation.)
Determine whether there are any transient terms in the general solution.
The general solution of the given differential equation 7dy/dx + 56y = 8 is y(x) = -x/8 + C e^(-8x/7), where C is a constant.
To solve the differential equation, we first rearrange it to isolate dy/dx: dy/dx = (8 - 56y)/7. This is a first-order linear differential equation. The integrating factor is e^(∫(-56/7)dx) = e^(-8x/7). Multiplying both sides of the equation by this integrating factor, we obtain e^(-8x/7) dy/dx + 8e^(-8x/7)y = 8e^(-8x/7). The left-hand side can be written as the derivative of y multiplied by e^(-8x/7). Integrating both sides gives ∫d(y e^(-8x/7)) = ∫8e^(-8x/7) dx. Solving these integrals and rearranging, we find the general solution y(x) = -x/8 + C e^(-8x/7), where C is the constant of integration.
The largest interval I over which the general solution is defined is (-∞, ∞) since there are no singular points or restrictions mentioned in the differential equation. This means that the solution is valid for all real values of x.
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If you move a decimal to the left 3 times will the numbers increase in value
Answer:
The number will decrease in value
Step-by-step explanation: For example if we had 638.23 if I move the decimal to the left 3 times it would be .63823, and if we add zeros it would look like this, 0.63823 so the number would decrease in value