sketch the graph of a function that has a local maximum at 6 and is differentiable at 6.

Answer: i would say B because it makes the most sence

Step-by-step explanation:

Answer:

hh

Step-by-step explanation:

Answer:

the answer is A:

sinA=h/c

sinC=h/a

Step-by-step explanation:

edge 2020

The pair of equations is sinA=h/a cosC=h/a

What is trigonometry?

Trigonometry is the branch of mathematics that deals with particular angles' functions and how to use those functions in calculations. There are six popular trigonometric functions for an angle. Sine (sin), cosine (cos), tangent (tan), cotangent (cot), secant (sec), and cosecant are their respective names and acronyms.

When a altitude is drawn from the base of the triangle

we can write

sinA=height/ a where a, is the side length of AB

also,cos C=height/a where a, is the side length of AB

Therefore,The pair of equations is where a, is the side length of AB

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Answer:

Taxes are money paid to the government, you need to pay these for the army , teachers, and it forms a better economy etc.!:) Have a nice day friend.

Step-by-step explanation:

rylee1015, it does matter because you are copying answers just to get points, and it might be wrong which is not fair, so stop it!!!:(

Answer:

3

Step-by-step explanation:

Answer:

The answer is A 56.25

Step-by-step explanation:

Since a square has 4 sides, divide 225 by 4 to get 56.25. To check your answer multiply 56.25 x 4 to get 225 in^2.

Hope this helps! Pls mark Brainliest!

Answer:

a.56.25

Step-by-step explanation:

Answer:

D)

Step-by-step explanation:

Sana maka tulong po

shout out tga pagadian

Step-by-step explanation:

Reduce 5/35 to lowest terms

The simplest form of 535 is 17.

Answer:

1/7

Step-by-step explanation:

divide both sides by 5

The equation [tex](sin(x)cos(x))^2 = sin(2x)[/tex] is verified to be an identity.

Simplify LHS and RHS?

To verify whether the equation [tex](sin(x)cos(x))^2 = sin(2x)[/tex] is an identity, we can simplify both sides of the equation and see if they are equivalent.

Starting with the left side of the equation:

[tex](sin(x)cos(x))^2 = (sin(x))^2(cos(x))^2[/tex]

Now, we can use the trigonometric identity [tex]sin(2x) = 2sin(x)cos(x)[/tex] to rewrite the right side of the equation:

[tex]sin(2x) = 2sin(x)cos(x)[/tex]

Substituting this into the equation, we have:

[tex](sin(x))^2(cos(x))^2 = (2sin(x)cos(x))[/tex]

Next, we can simplify the left side of the equation:

[tex](sin(x))^2(cos(x))^2 = (sin(x))^2(cos(x))^2[/tex]

Since both sides of the equation are identical, we can conclude that the given equation is indeed an identity:

[tex](sin(x)cos(x))^2 = sin(2x)[/tex]

Hence, the equation [tex](sin(x)cos(x))^2 = sin(2x)[/tex] is verified to be an identity.

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Answer:

the two consecutive negative integers are -2 and -1.

Step-by-step explanation:

Represent these negative integers by m and n.

Then (because the integers are consecutive) n = m + 1, and m^2 = n + 5.

Substituting m + 1 for n in the second equation, we get:

m^2 = m + 1 + 5, or

m^2 - m - 6 = 0

This factors into (m - 3)(m + 2) = 0.  The only negative root is -2.  

Thus, the two consecutive negative integers are -2 and -1.

Check:  Is the  square of the first five more than the second?

Is (-2)^2 = -1 + 5?  YES

The integers aer -2 and -1.

Answer:

17

Step-by-step explanation:

by Pythagoras

[tex]8 {}^{2} + 15 {}^{2} = {x}^{2} [/tex]

x=17

Answer:

Each month Bill reads 3 novels so you get

N = 3m

If you plug in 6 for m we get

N = 3(6) = 18

Bill needs to read 18 novels in 19 months

Step-by-step explanation:

The variance of the sampling distribution of means, on the other hand, is equal to the variance of all possible sample means of the same size taken from the population.

Since a sample size is always less than the population size, the variance of the population distribution is greater than the variance of the sampling distribution of means.

Therefore, option B is correct.
The probability of selecting one data value less than 190 IS (C)31%

When the variances of the population distribution and the sampling distribution of means are compared, the (B) population variance is larger than the sampling distribution variance.

The probability of selecting one data value less than 190 given the mean and standard deviation of a population of 200 and 20 respectively is 31% (option C).

Solution: Given,

mean (μ) = 200,

standard deviation (σ) = 20

We need to find the probability of selecting one data value less than 190.

P(x < 190) = ?

Z = (X - μ)/σ

Taking X = 190,

Z = (190 - 200)/20

= -0.5

From the standard normal table, the probability of

Z = -0.5 is 0.3085

Therefore,

P(x < 190) = P(Z < -0.5)

= 0.3085

= 31%

Hence, option C is correct.

When the variances of the population distribution and the sampling distribution of means are compared, the population variance is larger than the sampling distribution variance.

This can be explained as follows;

The population distribution is the distribution of an entire population, while the sampling distribution of the mean is the distribution of the means of all possible samples of a specific size drawn from that population.

The variance of the population distribution is equal to the variance of a single observation of the population.

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Answer:

8. center: (-7,5)

radius: 9

Step-by-step explanation:

8. to find the center, you need to get the equation in the form of (x-h)^2+(y-k)^2=r^2

you can do this by completing the square:

x^2+y^2+14x-10y-7=0

x^2+14x+49+y^2-10y+25=7+49+25

(x+7)^2+(y-5)^2=81

so, the center is (-7,5) and the radius is 9

Answer:

8 × 10⁻⁴

Step-by-step explanation:

Answer:

495

Step-by-step explanation:

Base area = 11*11 = 121

Lateral area = (11*4)*17/2 = 11*2*17 = 374

121+374=495

To calculate the magnitude of the gravitational force A exerts on B and B exerts on A, we can use Newton's law of universal gravitation:

[tex]F = (G * m1 * m2) / r^2[/tex]

where F is the gravitational force, G is the gravitational constant (approximately [tex]6.67430 *10^-11 N m^2 / kg^2)[/tex], m1 and m2 are the masses of the two spheres, and r is the distance between their centers.

For the force A exerts on B:

[tex]F_AB = (G * m_A * m_B) / r^2[/tex]

Substituting the given values: m_A = 7.5 kg, m_B = 6.3 kg, and r = 0.59 m:

F_AB = (6.67430 × 10^-11 N m^2 / kg^2) * (7.5 kg) * (6.3 kg) / (0.59 m)^2

Calculating the above expression gives the magnitude of the gravitational force A exerts on B.

For the force B exerts on A, we use the same formula:

[tex]F_BA = (G * m_A * m_B) / r^2[/tex]

Substituting the given values: m_A = 7.5 kg, m_B = 6.3 kg, and r = 0.59 m:

[tex]F_BA = (6.67430 * 10^-11 N m^2 / kg^2) * (6.3 kg) * (7.5 kg) / (0.59 m)^2[/tex]

Calculating the above expression gives the magnitude of the gravitational force B exerts on A.

To find the distance between the centers of the spheres when the force between them is 3.50 times 10^-9 N, we rearrange the formula to solve for r:

r = √((G * m_A * m_B) / F)

Substituting the given values: m_A = 7.5 kg, m_B = 6.3 kg, and F = 3.50 × 10^-9 N:

r = √[tex]((6.67430 * 10^-11 N m^2 / kg^2) * (7.5 kg) * (6.3 kg) / (3.50 *10^-9 N))[/tex]

Calculating the above expression gives the distance between the centers of the spheres.

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Answer:

k = 8

Step-by-step explanation:

10*8 - 90 = -10

:/

Answer:

Step-by-step explanation:

As triangles are similar

The ratio of the sides must be equal

so..

[tex]\frac{x}{8} =\frac{9}{5}[/tex]

[tex]x=\frac{9*8}{5}[/tex]

[tex]x=14.4[/tex]

hope it helps...

have a great day!!

To find the value of f(-2) given the differential equation dy/dx = e^(x-1) * e^y with the initial condition f(1) = 0, we can use separation of variables and solve the differential equation.

Starting with the given differential equation:

dy/dx = e^(x-1) * e^y

Separating variables by multiplying both sides by dx and e^(-y):

e^(-y) dy = e^(x-1) dx

Now, we can integrate both sides of the equation:

∫ e^(-y) dy = ∫ e^(x-1) dx

Integrating the left side with respect to y and the right side with respect to x:

e^(-y) = e^(x-1) + C

Applying the initial condition f(1) = 0, where x = 1 and f(1) = 0:

e^(-0) = e^(1-1) + C

1 = 1 + C

C = -2

Substituting the value of C back into the equation:

e^(-y) = e^(x-1) - 2

Now, we can find the value of f(-2) by substituting x = -2 into the equation:

e^(-y) = e^(-2-1) - 2

e^(-y) = e^(-3) - 2

To find the value of f(-2), we need to solve for y:

e^(-y) = 2 - e^(-3)

y = -ln(2 - e^(-3))

Therefore, the value of f(-2) is f(-2) = -ln(2 - e^(-3)).

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Answer:

117 Degrees

Step-by-step explanation:

plz give brailiest, the 1 and 117 are the exact same angle

Answer:

5%

Step-by-step explanation:

20=  100%

1 x100 = 100

100/20= 5

(a) The probability of the chosen hard drive to fail within one year is 0.005.

(b) The probability that the hard drive was manufactured by company C is 3.95%.

(a) The probability that a randomly chosen computer purchased from this manufacturer will experience a hard drive failure within one year is:

Probability of choosing hard drive from company A and failure within one year + Probability of choosing hard drive from company B and failure within one year + Probability of choosing hard drive from company C and failure within one year

P(A and F) = P(A) x P(F|A) = 0.5 x 0.001 = 0.0005

P(B and F) = P(B) x P(F|B) = 0.3 x 0.002 = 0.0006

P(C and F) = P(C) x P(F|C) = 0.2 x 0.005 = 0.0010

The probability that a randomly chosen computer purchased from this manufacturer will experience a hard drive failure within one year is:

0.0005 + 0.0006 + 0.0010 = 0.0021 (or 0.21%)

(b) Let F be the event that the hard drive fails within one year and C be the event that the hard drive is manufactured by company C.

We want to calculate P(C|F), the probability that the hard drive was manufactured by company C, given that it failed within one year;

P(C|F) = P(C and F) / P(F) = [P(C) x P(F|C)] / [P(A) x P(F|A) + P(B) x P(F|B) + P(C) x P(F|C)]

P(C|F) = (0.2 x 0.005) / (0.5 x 0.001 + 0.3 x 0.002 + 0.2 x 0.005)

P(C|F) = 0.083 / 0.0021 = 0.0395 (or 3.95%)

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The probability that the hard drive in my computer is manufactured by company C given that my computer experiences a hard drive failure within one year is approximately 0.74.

(a) Let the random variable X denote the number of hard drives in the computer manufacturer's hard drives that fail within one year. The probability distribution of X can be found as follows:

[tex]P(X = 0) = 0.5(1 - 0.001) + 0.3(1 - 0.002) + 0.2(1 - 0.005) = 0.9957[/tex]

[tex]P(X = 1) = 0.5(0.001) + 0.3(0.002) + 0.2(0.005) = 0.0016[/tex]

Thus, the probability that a randomly chosen computer purchased from this manufacturer will experience a hard drive failure within one year is 0.0016.

(b) Let the event H denote that the computer I buy experiences a hard drive failure within one year. Let the event Ci denote that the hard drive in my computer is manufactured by company

i. Then, using Bayes' theorem, we have:

[tex]P(C3 | H) = P(H | C3)P(C3) / P(H)[/tex]

We can find the values of the three probabilities in the above formula as follows:

P(H | C1) = 0.001

P(H | C2) = 0.002

P(H | C3) = 0.005

P(C1) = 0.5

P(C2) = 0.3

P(C3) = 0.2

[tex]P(H) = P(H | C1)P(C1) + P(H | C2)P(C2) + P(H | C3)P(C3)≈ 0.00135[/tex]

Thus, P(C3 | H) = 0.005(0.2) / 0.00135 ≈ 0.74

Therefore, the probability that the hard drive in my computer is manufactured by company C given that my computer experiences a hard drive failure within one year is approximately 0.74.

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Answer:

189cm^3

Step-by-step explanation:

First, we need to find the formula of "how to find the volume of any prism":

length * width *height

* = multiply

So that means we need to do:

7cm * 9cm * 3cm

= 189cm^3

^ = exponent

Hope this helped :)

Answer: 1/3

Step-by-step explanation:

2.5:7.5

3:9

just simplify

The probability of finding four or more tanks in the system at any time is approximately 0.95. The probability of having 6 or more tanks in the system is approximately 0.77.

A. The utilization of the test station is calculated by dividing the average service rate (1 tank per 8 minutes) by the arrival rate (1 tank every 16 minutes). Utilization = Service rate / Arrival rate = 1/2 = 0.5 or 50%.

B. The probability that a tank has to wait in the queue prior to testing can be calculated using the queuing theory formula for the M/M/1 queue. In this case, the utilization (ρ) is 0.5. The formula for the probability of waiting in the queue (Pw) is Pw = ρ^2 / (1 - ρ) = 0.5^2 / (1 - 0.5) = 0.25 / 0.5 = 0.5 or 50%.

C. The mean time a tank spends in the queue can be calculated using Little's Law, which states that the mean number of customers in a stable system (L) is equal to the arrival rate (λ) multiplied by the mean time spent in the system (W). In this case, L = λ * W. The mean number of tanks in the queue (Lq) can be calculated using Lq = λ * Wq, where Wq is the mean time spent in the queue. Given λ = 1/16 tanks per minute and Lq = 8 tanks, we can rearrange the equation to solve for Wq: Wq = Lq / λ = 8 / (1/16) = 128 minutes / 16 = 8 minutes.

D. The mean time a tank spends in the system (queue + test) is equal to the mean time spent in the queue (Wq) plus the mean service time (1/8 tanks per minute). Therefore, the mean time in the system (Ws) is Ws = Wq + 1/μ = 8 + 1/8 = 8.125 minutes.

E. The mean number of tanks expected to be in the queue at any time can be calculated using Little's Law: Lq = λ * Wq. Given λ = 1/16 tanks per minute and Wq = 8 minutes, we can calculate Lq: Lq = (1/16) * 8 = 0.5 tanks.

F. The mean number of tanks expected to be in the system at any time can be calculated using Little's Law: L = λ * Ws. Given λ = 1/16 tanks per minute and Ws = 8.125 minutes, we can calculate L: L = (1/16) * 8.125 = 0.507 tanks.

G. The probability of finding four or more tanks in the system at any time can be calculated using the Poisson distribution formula. By summing the probabilities for four, five, and more tanks, we get 0.043.

H. The probability of having 6 or more tanks in the system can also be calculated using the Poisson distribution formula, which results in a probability of 0.002.

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Answer:

44

Step-by-step explanation:

14x3.14 is 43.96 and that after being rounded to the nearest tenth becomes 44