Solve the following initial value problem: xdy/dx + (7x + 2)y =( e-^7x) Inx , y(1) = 0.

Answer:

Given ABCD ~ EFGH

FG = BC(EF/AB)

FG = 7(9/6)

FG = 63/6

FG = 10.5

GH = CD(EF/AB)

GH = 11(9/6)

GH = 99/6

GH = 16.5

EH = AD(EF/AB)

EH = 12(9/6)

EH = 108/6

EH = 18

In a river bank

you can put the answers from the end

1.) 1/12

2.) 2/13

3.) 8/41

4.) 1/4

5.) 11/74

6.) 2/35

7.) 15/58

8.) 5/18

9.) 1/7

10.) 1/13

To prove that for any real number x, if  x²+ 7x < 0, then x < 0, we can use the properties of quadratic functions and inequalities.

By analyzing the quadratic expression, we can determine the conditions under which it is negative. This analysis shows that the inequality x²+ 7x < 0 holds true when x is less than 0. Consider the quadratic expression x² + 7x. To determine when this expression is negative, we can factor it as x(x + 7). According to the zero product property, this expression is equal to zero when either x or (x + 7) is equal to zero. Thus, the two critical points are x = 0 and x = -7.

Now, let's analyze the behavior of the quadratic expression in the intervals (-∞, -7), (-7, 0), and (0, +∞). Choose a test point from each interval, such as -8, -3, and 1, respectively. Evaluating the expression x²⁺7x for these test points, we find that for -8 and -3, the expression is positive, and for 1, it is positive as well.

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Answer:

Step-by-step explanation:

Given equation:

q is independent variable, we need to solve it for s:

Correct choice is

Answer:

D) 8

Step-by-step explanation:

We're looking for [tex]x[/tex], which means the 7x and 5x will have the SAME x.

7(8) = 56

For the C corner, it is cornered as a 90 degree angle, so that means the (7x) + 34 degrees NEEDS to equal 90.

7(8) = 56 + 34 = 90!!

Now we have to see if 5(8) is correct

5(8) = 40 + 50 [The degree mark] = WHICH EQUALS 90 TOO..

Therefore, the answer is D) 8

14. (1112 - 6vw - 3wa)-(-702 + vw + 13w) = 1814 - 7vw - 3wa - 13w

15. The equivalent of the expression (5a + 26 - 4c) is 25a2 + 10ab - 20ac + 482 - 86c + 1602 + c.

16.  (b + b)(4 - 5)(25 - 8) = -34

14. Simplify (1112 - 6vw - 3wa)-(-702 + vw + 13w).

Given expression is (1112 - 6vw - 3wa)-(-702 + vw + 13w)

⇒ 1112 - 6vw - 3wa + 702 - vw - 13w

⇒ 1814 - 7vw - 3wa - 13w

15. We are to find the equivalent of the expression (5a + 26 - 4c).

a. 25a2 + 20ab - 40ac +482 - 16bc + 1602

b. 25a2 + 10ab - 20ac + 482 - 86C + 1602

c. 25a2 + 482 + 1602

d. 10a + 4b-8c5a + 26 - 4c

= 5a - 4c + 26 = 25a2 - 20ac +482 - 4c2 + 52 - 8ac

= 25a2 - 20ac + 482 - 4c2 + 10a - 8c = Option (b)

⇒ 25a2 + 10ab - 20ac + 482 - 86c + 16c2 + c.

16. Expand and simplify. (b + b)(4 - 5)(25 - 8)

Given expression is (b + b)(4 - 5)(25 - 8) = 2b(-1)(17) = -34

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a. The relation R defined on the set S = {1, 2, 3, ..., 18, 19} is an equivalence relation. It is reflexive, symmetric, and transitive, b. The equivalence class of 1, denoted [1], consists of the perfect squares in S: {1, 4, 9, 16}, c. The equivalence classes with more than one element are [1], [2], [3], ..., [18], and [19]. Each equivalence class represents a set of numbers that are squares of integers.

a. To show that the relation R is an equivalence relation, we need to demonstrate that it is reflexive, symmetric, and transitive.

i. Reflexive: For R to be reflexive, every element in S must be related to itself. Since the square of any integer is still an integer, xRx holds for all x in S, satisfying reflexivity.

ii. Symmetric: For R to be symmetric, if xRy holds, then yRx must also hold. Since multiplication is commutative, if xy is a square of an integer, then yx is also a square of an integer. Hence, R is symmetric.

iii. Transitive: For R to be transitive, if xRy and yRz hold, then xRz must also hold. Since the product of two squares of integers is itself a square of an integer, xz is also a square of an integer. Thus, R is transitive.

b. To find the equivalence class of 1, denoted [1], we determine all elements in S that are related to 1 under R. In this case, [1] consists of the perfect squares in S: {1, 4, 9, 16}.

c. The equivalence classes with more than one element are [1], [2], [3], ..., [18], and [19]. Each equivalence class represents a set of numbers that are squares of integers. The equivalence class [1] includes all perfect squares in S, while the other equivalence classes consist of a single element, which are non-square integers.

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Answer: the second one/ \/36/6

Step-by-step explanation:

Answer

c

Step-by-step explanation:

It is not d because of the way that it is formed

It cant be written any way else its already in its simplest form

Answer:

the bottom triangle is scaled down version of above one

then

[tex] \frac{18}{6} = \frac{x}{2} [/tex]

[tex]x = 6[/tex]

and

[tex] \frac{18}{6} = \frac{y}{5} [/tex]

[tex]y = 15[/tex]

The instantaneous rate of change for the function f(x) at x = 3 is 16.9068.

To determine the instantaneous rate of change for the function;  f(x) = 5x^ln(x), where x = 3, we can use the formula for the instantaneous rate of change, approximating the limit by using smaller and smaller values of h.

The instantaneous rate of change of the function f(x) at x = 3 can be found as follows:

Let h be a small increment of x that approaches zero. Then the formula for the instantaneous rate of change is given by:

f'(3) = lim[h→0] {(5(3+h)^(ln(3+h))-5(3^(ln3)))/h}

For the above formula, we have: Let f(x) = 5x^ln(x)

Then, f'(x) = 5x^ln(x) * [(d/dx) ln(x)] + 5*ln(x)*x^(ln(x) - 1)

Now, for the given problem, we can substitute 3 for x, and solve as follows: f'(3) = 5(3^ln(3)) * [(d/dx) ln(x)] + 5*ln(3)*3^(ln(3) - 1)

f'(3) = 5(3^ln(3)) * [(1/x)] + 5*ln(3)*3^(ln(3) - 1)

f'(3) = 5(3^ln(3)) * [(1/3)] + 5*ln(3)*3^(ln(3) - 1)

f'(3) = 5(3^ln(3) / 3) + 5*ln(3)*3^(ln(3) - 1)

Then, f'(3) = 5e ln(3) + 5 ln(3) / 3= (5e ln(3) + 5 ln(3) / 3)= 16.9068 (rounded to four decimal places).

Therefore, the instantaneous rate of change for the function f(x) at x = 3 is 16.9068.

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Answer: 40

Step-by-step explanation:

Answer:

3=20

4=15

5=12

Step-by-step explanation:

The exact distance between the points (8, -3) and (-2, 4) can be calculated using the distance formula in mathematics.

The formula for finding the distance between two points (x1, y1) and (x2, y2) in a two-dimensional Cartesian coordinate system is given by: Distance = sqrt((x2 - x1)^2 + (y2 - y1)^2). Using the coordinates (8, -3) and (-2, 4), we can substitute the values into the distance formula: Distance = sqrt((-2 - 8)^2 + (4 - (-3))^2) = sqrt((-10)^2 + (7)^2) = sqrt(100 + 49) = sqrt(149) ≈ 12.207

Therefore, the exact distance between the points (8, -3) and (-2, 4) is approximately 12.207 units.

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The function y = sin(kt) satisfies the differential equation y'' - 64y = 0 for pospositiveypospositiveyitiveitive values of k that are multiples of 8.

To determine the values of k for which the function y = sin(kt) satisfies the given differential equation, we need to substitute y into the equation and solve for k. Let's start by finding the first and second derivatives of y with respect to t.
The first derivative of y with respect to t is y' = kcos(kt), and the second derivative is y'' = -k^2sin(kt). Substituting these derivatives into the differential equation gives us:
(-k^2sin(kt)) - 64sin(kt) = 0Simplifying the equation, we get:
sin(kt) = -64*sin(kt)/k^2
We can divide both sides of the equation by sin(kt) (assuming sin(kt) is not zero) to get:
1 = -64/k^2
Solving for k^2, we find k^2 = -64. Since k must be positive, there are no positive values of k that satisfy this equation. Therefore, there are no positive values of k for which the function y = sin(kt) satisfies the given differential equation y'' - 64y = 0.

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Answer:

36.25 miles per gallon

Step-by-step explanation:

4/5 = .8

29/.8 = x/1

cross-multiply:

.8x = 29

x = 36.25

Answer:

55

Step-by-step explanation:

To find this, simply plug 10 in for x.

6(10)-5

6*10=60

60-5=55

Answer:

True

Step-by-step explanation:

Brainliest?

Answer:

I Believe the answer is True

Step-by-step explanation:

Answer:

x²+11x+30

Step-by-step explanation:

for this question, all we need to do is multiply (x+5) by (x+6)

we can use the distributive property.

(x+5)(x+6)

x² + 5x + 6x + 30

x² + 11x + 30

Then, the width of the pool covered by the concrete walkway is 16 + 2c feet (2c feet on each side), and the length of the pool covered by the concrete walkway is 26 + 2c feet (2c feet on each end).

We have given a rectangular swimming pool with a length of 26 feet and a width of 16 feet. We need to find the perimeter of the wood deck that surrounds the concrete walkway of width c around the pool and extends w feet on all sides.

Let's solve the given problem as follows:Firstly, let's calculate the dimensions of the concrete walkway. Let the width of the concrete walkway be 'c' feet.

Then, the width of the pool covered by the concrete walkway is 16 + 2c feet (2c feet on each side), and the length of the pool covered by the concrete walkway is 26 + 2c feet (2c feet on each end).

So, the dimensions of the pool and concrete walkway are (26 + 2c) ft. x (16 + 2c) ft.The dimensions of the wood deck that surrounds the concrete walkway by w feet on all sides will be (26 + 2c + 2w) ft. x (16 + 2c + 2w) ft.Now, let's write the expression for the perimeter of the wood deck.P = 2(Length + Width)P = 2[(26 + 2c + 2w) + (16 + 2c + 2w)]P = 2[42 + 4c + 4w]P = 84 + 8c + 8wThe expression for the perimeter of the wood deck is 84 + 8c + 8w. Hence, the answer is 84 + 8c + 8w.

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a. System in the matrix form is x' = Ax where A = [tex]\left[\begin{array}{ccc}0&1\\-5&6\end{array}\right][/tex] and x = [y, u].

b. The eigenvalues of the system are λ₁ = 5 and λ₂ = 1 and eigenvector are v₁ and v₂ = v₁, and v₁ is any non-zero value.

c. The general solution is equal to y(x) = c₁ × [tex]e^{(5x)[/tex] × [v₁] + c₂× [tex]e^{(x)[/tex]× [v₂].

a. Solution to the equation. y' - 5y + y = 32 is y(x) = c₁ × [tex]e^{(5x)[/tex] + c₂ × [tex]e^{(x)[/tex].

(a) To write the second order linear ODE as a system of two first order ODEs,

Introduce a new variable u = y'.

Then, we have,

u' = y'' - 5y + 6y

   = -5y + 6u

Now, write this as a system of two first order ODEs,

y' = u

u' = -5y + 6u

To express this system in matrix form,

Define the vector x = [y, u] and the matrix A = [tex]\left[\begin{array}{ccc}0&1\\-5&6\end{array}\right][/tex]

The system can then be written as,

x' = Ax

(b) To find the eigenvalues and eigenvectors of matrix A, solve the characteristic equation,

|A - λI| = 0

where I is the identity matrix.

Substituting the values of A, we have,

[tex]|\left[\begin{array}{ccc}0&1\\-5&6\end{array}\right][/tex] [tex]-\lambda\left[\begin{array}{ccc}1&0\\0&1\end{array}\right]|[/tex] = 0

[tex]\left[\begin{array}{ccc}-\lambda&1\\-5&6-\lambda\end{array}\right][/tex] = 0

(-λ)(6-λ) - (-5)(1) = 0

λ²- 6λ + 5 = 0

Factoring the quadratic equation, we get,

(λ - 5)(λ - 1) = 0

So the eigenvalues are λ₁ = 5 and λ₂ = 1.

To find the corresponding eigenvectors,

solve the equation (A - λI)v = 0 for each eigenvalue.

Let us start with λ = 5

(A - 5I)v = 0

[tex]|\left[\begin{array}{ccc}1&1\\-5&6\end{array}\right]|[/tex] v = 0

v₁ + v₂ = 0

-5v₁ + v₂ = 0

From the first equation, we get v₂ = -v₁.

Substituting this into the second equation, we have -5v₁ - v₁ = 0,

which simplifies to -6v₁ = 0.

This implies v₁ = 0, and consequently, v₂ = 0.

So, for λ = 5, the eigenvector is v₁ = 0 and v₂ = 0.

Now, let us find the eigenvector for λ = 1.

(A - I)v = 0

[tex]|\left[\begin{array}{ccc}-1&1\\-5&5\end{array}\right][/tex] v = 0

-v₁ + v₂ = 0

-5v₁ + 5v₂ = 0

From the first equation, we get v₂ = v₁.

Substituting this into the second equation, we have -5v₁ + 5v₁ = 0,

which simplifies to 0 = 0.

This implies that v₁ can be any non-zero value.

So, for λ = 1, the eigenvector is v₁ and v₂ = v₁, where v₁ is any non-zero value.

(e) The general solution to the second order ODE can be expressed using the eigenvalues and eigenvectors as follows,

y(x) = c₁ ×[tex]e^{(\lambda_{1} x)[/tex] × v₁ + c₂ × [tex]e^{(\lambda_{2} x)[/tex]× v₂

Plugging in the values we found earlier, the general solution becomes,

y(x) = c₁ × [tex]e^{(5x)[/tex] × [v₁] + c₂× [tex]e^{(x)[/tex]× [v₂]

where [v₁] and [v₂] are the eigenvectors corresponding to the eigenvalues λ₁ = 5 and λ₂ = 1 respectively.

(a) To find the solution to the equation y' - 5y + y = 32,

Use the general solution obtained above.

Comparing the equation with the standard form y' - 5y + 6y = 0,

The equation corresponds to the case where λ₂ = 1.

Substitute λ = 1, v₁ = 1, and v₂ = 1 into the general solution.

y(x) = c₁ × [tex]e^{(5x)[/tex] × [1] + c₂ × [tex]e^{(x)[/tex] × [1]

Simplifying this expression, we have,

y(x) = c₁ × [tex]e^{(5x)[/tex] + c₂ × [tex]e^{(x)[/tex]

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Answer:

28.27

Step-by-step explanation:

A=πr2=π·32≈28.27433

Answer:

If you're using 3.14 for pi, it's 28.26

Step-by-step explanation:

Answer:

a=-2

Step-by-step explanation:

3a−6=−12

Step 1: Add 6 to both sides.

3a−6+6=−12+6

3a=−6

Step 2: Divide both sides by 3.

3a/ 3 = −6/ 3

a=−2

Answer

Answer:

There is a 1/3 (or 0.33%) probability of rolling a number greater than or equal to 5.

Step-by-step explanation:

First, find what numbers are greater than or equal to 5:

5 and 6

Find what options you can get on a number cube:

1, 2, 3, 4, 5, and 6

Out of the 6 possible outcomes, there are only 2 that will get a number greater than or equal to 5. Write this as a fraction:

2/6

Simplify:

1/3

False, the null distribution is the distribution of the test statistic assuming the null hypothesis is true; it is mound-shaped and symmetric about the null mean.

The null distribution is the distribution of the test statistic under the assumption that the null hypothesis is true. However, its shape and symmetry are not necessarily predetermined.

The null distribution can take various forms depending on the specific test and the underlying data. It may or may not be mound shaped or symmetric about the null mean. The shape and characteristics of the null distribution are determined by the specific hypothesis being tested, the sample size, and other factors.

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The correct order of integration and associated limits for the given triple integral I = ∫∫∫[f(x, y, z)] dx dy dz with limits: 0 ≤ x ≤ 1 - 2y, 0 ≤ y, 0 ≤ z ≤ 2y²

The correct order of integration and associated limits for the given triple integral, let's first examine the region of integration R and its slices in different planes.

Region R is defined by 0 ≤ z ≤ 2y² and 0 ≤ x ≤ 1 - 2y.

1.Slices in the zy-plane: In the zy-plane, z is restricted to 0 ≤ z ≤ 2y², and y is unrestricted. Therefore, the integral can be written as:

I = ∫∫∫ f(x, y, z) dV = ∫∫∫ f(x, y, z) dz dy dx

2.Slices in the zx-plane: In the zx-plane, z is unrestricted, and x is restricted to 0 ≤ x ≤ 1 - 2y. Therefore, the integral can be written as:

I = ∫∫∫ f(x, y, z) dV = ∫∫∫ f(x, y, z) dx dz dy

3.Slices in the yz-plane: In the yz-plane, y is unrestricted, and z is restricted to 0 ≤ z ≤ 2y². Therefore, the integral can be written as:

I = ∫∫∫ f(x, y, z) dV = ∫∫∫ f(x, y, z) dy dz dx

Considering the given hint, we can choose any of the above orders of integration as all of them are correct ways to write the integral. However, for simplicity, let's choose the order: I = ∫∫∫ f(x, y, z) dz dy dx.

Now, let's determine the limits of integration for each variable in this order:

∫∫∫ f(x, y, z) dz dy dx = ∫∫ [∫[f(x, y, z) dz] from z=0 to z=2y²] dy dx

The innermost integral with respect to z is evaluated from 0 to 2y². The next integral with respect to y is evaluated from 0 to a certain limit determined by the region R. Finally, the outermost integral with respect to x is evaluated from 0 to 1 - 2y.

Therefore, the order of integration and the associated limits for the triple integral are:

I = ∫∫∫ f(x, y, z) dz dy dx

I = ∫∫ [∫[f(x, y, z) dz] from z=0 to z=2y²] dy dx

I = ∫∫∫[f(x, y, z)] dx dy dz with limits: 0 ≤ x ≤ 1 - 2y, 0 ≤ y, 0 ≤ z ≤ 2y²

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Answer:

hi sh Sheet sh I monorailg Jericho improve Odom Ybor