Solve, using the substitution method.

x = 10

y = 2x – 6


(10, 14)


(10, 4)


(10, –4)


(10, –1)

Answer:

0

Step-by-step explanation:

[tex]~~~(-37+37 )\div(-15)\\\\=0\div (-15)\\\\=0[/tex]

Answer:

0

Step-by-step explanation:

Following PEMDAS -37+37 is 0 and 0/-15 is also 0

The choice shows 19 + 32 + 11 rewritten correctly using the commutative property and then simplified correctly is option B; 19+11+32= 30+32 = 62.

The commutative property of addition says that it doesn't matter how we add two numbers, the result of the addition would be same.

For two numbers x and y, we have:

x + y = y + x

WE have given

19 + 32 + 11

The sum would be 62.

We know that by commutative property of addition,

For two numbers x and y,

x + y = y + x

Thus, if we take 3 numbers as a,b and c, then:

c + a + b = c + b + a

Similarly,

19 + 32 + 11 = 19+11+32

= 30+32

= 62

Therefore, the option B  is the correct answer.

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Answer:

[tex]\dfrac a{b^2} + \dfrac b{a^2} = 10[/tex]

Step-by-step explanation:

[tex]\text{Given that, the roots are a,b and } ~ x^2 -4x+2 = 0\\\\\text{So,}\\\\a+b = -\dfrac{-4}1 = 4\\\\ab = \dfrac 21 = 2\\\\\text{Now,}\\\\~~~~~\dfrac a{b^2} + \dfrac b{a^2}\\\\\\=\dfrac{a^3 +b^3}{a^2b^2}\\\\\\=\dfrac{(a+b)^3 -3ab(a+b)}{(ab)^2}\\\\\\=\dfrac{4^3 -3(2)(4)}{2^2}\\\\\\=\dfrac{64-24}{4}\\\\\\=\dfrac{40}{4}\\\\\\=10[/tex]

Answer:

[tex]\dfrac{a}{b^2}+\dfrac{b}{a^2}=10[/tex]

Step-by-step explanation:

Given equation:   [tex]x^2-4x+2=0[/tex]

The roots of the given quadratic equation are the values of x when [tex]y=0[/tex].

To find the roots, use the quadratic formula:

[tex]x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0[/tex]

Therefore:

[tex]a=1, \quad b=-4, \quad c=2[/tex]

[tex]\begin{aligned}\implies x & =\dfrac{-(-4) \pm \sqrt{(-4)^2-4(1)(2)}}{2(1)}\\& =\dfrac{4 \pm \sqrt{8}}{2}\\& =\dfrac{4 \pm 2\sqrt{2}}{2}\\& =2 \pm \sqrt{2}\end{aligned}[/tex]

[tex]\textsf{Let }a=2+\sqrt{2}[/tex]

[tex]\textsf{Let }b=2-\sqrt{2}[/tex]

Therefore:

[tex]\begin{aligned}\implies \dfrac{a}{b^2}+\dfrac{b}{a^2} & = \dfrac{2+\sqrt{2}}{(2-\sqrt{2})^2}+\dfrac{2-\sqrt{2}}{(2+\sqrt{2})^2}\\\\& = \dfrac{2+\sqrt{2}}{6-4\sqrt{2}}+\dfrac{2-\sqrt{2}}{6+4\sqrt{2}}\\\\& = \dfrac{(2+\sqrt{2})(6+4\sqrt{2})+(2-\sqrt{2})(6-4\sqrt{2})}{(6-4\sqrt{2})(6+4\sqrt{2})}\\\\& = \dfrac{12+8\sqrt{2}+6\sqrt{2}+8+12-8\sqrt{2}-6\sqrt{2}+8}{36+24\sqrt{2}-24\sqrt{2}-32}\\\\& = \dfrac{40}{4}\\\\& = 10\end{aligned}[/tex]

The angles are 121 and 59 degrees, respectively

The given parameters are:

FGH = 11x

HGJ = 6x - 7

Linear pair angles add up to 180.

So, we have:

11x + 6x - 7 = 180

Evaluate the like terms

17x = 187

Divide both sides by 17

x = 11

Substitute x = 11 in FGH = 11x and HGJ = 6x - 7

FGH = 11 * 11=121

HGJ = 6 * 11 - 7 = 59

Hence, the angles are 121 and 59 degrees, respectively

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Answer: Point C is (-2, -2), which is the third option.

Step-by-step explanation:

The midpoint formula is [tex]m=(\frac{x_{1}+x_{2} }{2},\frac{y_{1}+y_{2} }{2})[/tex]

All we have to do is plug in the numbers and solve the fractions from there.

[tex]m=(\frac{-10+6}{2},\frac{-6+2}{2} )[/tex]

[tex](\frac{-4}{2},\frac{-4}{2} )[/tex]

[tex]m=(-2, -2)[/tex]

I hope this helps!!

Answer:

20.5 - 5.36
= 15.14/2 (because we are using perimeter, so there are 2 equal lengths and 2 equal widths)
=7.57, therefore the width of the sandbox is 7.57 ft.

Answer:

4.89 ft

Step-by-step explanation:

Perimeter of a rectangle is given by the formula :

P = 2L + 2W

So now we solve for W :

P = 2(L+W)

P/2 = L+W

P/2 - L =  W

Now we substitute our P and L into the rearranged formula :

20.5 / 2 - 5.36 = W

10.25 - 5.36 = W

W = 4.89 ft

Hope this helped and brainliest please

Step-by-step explanation:

7x-5=30

Firstly -5 will cross the equality sign and become +5. so we'll have

7x=30+5=35

7x=35 we'll divide both sides by 7

giving u

7x/7=35/7

=x=5

therefore x=5.

CONFIRMATION

7*5-5=30

PLS MARK ME AS BRAINLIEST

Answer:

Step-by-step explanation:

Solve for X:

Answer: is y=[x]-2

I used this app to help me get the answer too lol

Answer:

12 ft

Step-by-step explanation:

We assume right triangle ABC with the right angle being at B. We are given that the ratio of AB/CB = 8/7, and one leg is 10.5.  Let's call the other leg is X. We don't know which leg is which so assume both. Then

(a) assume the X leg is the longer

8 / 7 = X / 10.5

(8 * 10.5) / 7= X

X = 12

OR (b) assume the X leg is the shorter

8/7 = 10.5 / X

(8X / 7) = 10.5

8X = 10.5 * 7

8X =  73.5

X = 9.1875

(a) is the greater so (a) wins

Substitute -2 for x

[tex]f( - 2) = 2( - 2) + 3 \\ y = - 4 + 3 \\ y = - 1[/tex]

Hope it helps

Please give brainliest

Answer:

-1

Step-by-step explanation:

Hi student! Let me help you out on this question.

_____________________

To find the value of f(-2), we need to stick in -2 for x.

[tex]\mathsf{f(-2)=2\cdot(-2)+3}[/tex]. Multiply first.

[tex]\mathrm{f(-2)=-4+3}[/tex]. Now simplify completely.

[tex]\mathsf{f(-2)=-1}[/tex]. Which is our final answer.

Hope that this helped you out! have a good day ahead.

Best Wishes!

[tex]\star\bigstar\underline{\underline{\overline{\overline{\textsf{Reach far. Aim high. Dream big.}}}}}\bigstar\star[/tex]

◆◈-Greetings!-◆◈

__________________

Answer:

V =113.09734

Step-by-step explanation:

[tex]V=\pi r^{2}[/tex]

[tex]= 2^{2}[/tex] x 9= 113.09734

(which you can technically round to 1)

=113.1

Solution :

[tex]x = \frac{4 + \sqrt{43} }{2} .x = 4 + \frac{4 - \sqrt{43} }{2} [/tex]

[tex] \frac{1}{(x - 5)} + \frac{3}{(x - 2)} - 4[/tex]

[tex]x = 2 + 3( x - 5) = 4 - (x - 5)(x + 2)[/tex]

[tex]x = \frac{4 + \sqrt{43} }{2} .x = 4 + \frac{4 - \sqrt{43} }{2} [/tex]

[tex]\\ \rm\Rrightarrow \dfrac{1}{x-5}+\dfrac{3}{x+2}=4[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{x+2+3x-15}{(x-5)(x+2)}=4[/tex]

[tex]\\ \rm\Rrightarrow 4x-13=4(x-5)(x+2)[/tex]

[tex]\\ \rm\Rrightarrow 4x-13=4(x(x+2)-5(x+2))[/tex]

[tex]\\ \rm\Rrightarrow 4x-13=4(x^2+2x-5x-10)[/tex]

[tex]\\ \rm\Rrightarrow 4x-13=4(x^2-3x-10)[/tex]

[tex]\\ \rm\Rrightarrow 4x-13=4x^2-12x-40[/tex]

[tex]\\ \rm\Rrightarrow 4x^2-16x-53=0[/tex]

On solving we get

[tex]\\ \rm\Rrightarrow x=2\pm\dfrac{69}{2}[/tex]

In function notation, f(x) is used instead of the letter y to represent the output variable.

A function is represented as:

f(x)

The above means that:

The function of x

As a general rule, the function can be rewritten using the letter y (i.e. the output variable)

Hence, the words that complete the blanks are y and output

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Answer:

[tex]\frac{7\sqrt{65}}{65}[/tex]

Step-by-step explanation:

Cosine is the ratio of the side adjacent to the angle and the right triangle hypotenuse.

[tex]cos[/tex] B = [tex]\frac{7}{\sqrt{65}}[/tex] = [tex]\frac{7\sqrt{65}}{65}[/tex]

The state that would most likely benefit from this program is the Missippi state due to the incidence of floods.

States constantly affected by floods would benefit the most.

In the case of Mississippi state, the floods are caused by the Mississippi River.

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Answer:

b) 4

Step-by-step explanation:

4 times $0.05 = $0.20

4 times $0.30 = $1.20

then you add the both totals together

0.20 + 1.20= $1.40

Answer:

66

Step-by-step explanation:

[tex]\sqrt{324} + 6 \sqrt{64}\\\\=\sqrt{18^2} +6 \sqrt{8^2}\\\\=18+6(8)\\\\=18+48\\\\=66[/tex]

Answer:

hmm

Step-by-step explanation:

not enough words to know u steal my points I steal yours kid

Answer:

(18,6)

Step-by-step explanation:

add 5 units to X and 2 to Y

[tex](2,3) \longrightarrow (2+1, 3-3)=\boxed{(3,0)}\\(-4,5) \longrightarrow (-4+1, 5-3)=\boxed{(-3, 2)}\\(-3,4) \longrightarrow (-3+1, 4-3)=\boxed{(-2, 1)}[/tex]

Answer: ......... 14.85

Step-by-step explanation:

4.95 × 3

...

14.85

bros lazy lol

2.3+2.2y uneed to pus the 2 on the 3 and answer is uten

Answer:

answer is b

Step-by-step explanation:

because all you need to do is flip the signs.

Answer:

Last option, - 1 / 20

Step-by-step explanation:

The solutions of the absolute value equation is determined as 15 and - 5.

The solution to the absolute equation is determined as follows;

|x - 5| + 7 = 17

collect similar terms

|x - 5|  = 17 - 7

|x - 5|  = 10

to resolve the absolute values, form two equations as follows;

x - 5 = 10 and x - 5 = -10

x = 15 and x = -5

Thus, the solutions of the absolute value equation is determined as 15 and - 5.

The complete question is given as;

|x - 5| + 7 = 17

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Answer:

127.17 in³

Step-by-step explanation:

V = (1/2)πr²h
(1/2)(3.14)(2.25 in)²(16 in)

(1/2)(3.14)(5.0625 in²)(16 in) = 127.17 in³

Answer:

x = 2

Step-by-step explanation:

logx + log(2x - 1) = log 6

Apply log rules,

x(2x - 1) = 6

2x^2 - 1x = 6

x = 2 (true) or x = -3/2 (False)

[tex](\stackrel{x_1}{-5}~,~\stackrel{y_1}{1})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{7}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{7}-\stackrel{y1}{1}}}{\underset{run} {\underset{x_2}{-2}-\underset{x_1}{(-5)}}} \implies \cfrac{7 -1}{-2 +5}\implies \cfrac{6}{3}\implies 2[/tex]

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{1}=\stackrel{m}{2}(x-\stackrel{x_1}{(-5)})\implies y-1=2(x+5)[/tex]

a. If A is the coefficient matrix, solve det(A - λI) = 0 for the eigenvalues λ :

[tex]\det\begin{bmatrix}-6-\lambda & -4 \\ 12 & 8-\lambda\end{bmatrix} = (-6-\lambda)(8-\lambda)+48 = 0 \implies \lambda(\lambda-2)=0[/tex]

[tex]\implies \lambda = 0, \lambda = 2[/tex]

Let v = [v₁, v₂]ᵀ be the eigenvector corresponding to λ. Solve Av = λv for v :

[tex]\lambda=0 \implies \begin{bmatrix}-6&-4\\12&8\end{bmatrix}\begin{bmatrix}v_1\\v_2\end{bmatrix} = \begin{bmatrix}0\\0\end{bmatrix} \implies 3v_1 + 2v_2 = 0[/tex]

If we pick v₂ = -3, then v₁ = 2, so [2, -3]ᵀ is the eigenvector for λ = 0.

[tex]\lambda = 2 \implies \begin{bmatrix}-8&-4\\12&6\end{bmatrix}\begin{bmatrix}v_1\\v_2\end{bmatrix} = \begin{bmatrix}0\\0\end{bmatrix} \implies 2v_1 + v_2 = 0[/tex]

Let v₁ = 1, so v₂ = -2.

b. λ = 0 and v = [2, -3]ᵀ contributes a constant solution,

[tex]\vec y_1 = e^{\lambda t} v = \begin{bmatrix}2\\-3\end{bmatrix}[/tex]

while λ = 2 and v = [1, -2]ᵀ contribute a solution of the form

[tex]\vec y_2 = e^{\lambda t} v = e^{2t} \begin{bmatrix}1\\-2\end{bmatrix}[/tex]

c. Yes; compute the Wronskian of the two fundamental solutions:

[tex]W(1, e^{2t}) = \det\begin{bmatrix}1 & e^{2t} \\ 0 & 2e^{2t}\end{bmatrix} = 2e^{2t} \neq 0[/tex]

The Wronskian is non-zero, so the solutions are independent.