Some material consisting of a collection of microscopic systems is kept at a high temperature, so that all excited states are populated and can participate in emission of photons. A photon detector capable of detecting photon energies from infrared through ultraviolet observes photons emitted with energies of 0.3 eV, 0.5 eV, 0.8 eV, 2.0 eV, 2.5 eV, and 2.8 eV. These are the only photon energy observed.
a) Draw and label a possible energy-level diagram for one of the microscopic systems, which has 4 bound states. On the diagram, indicate the transitions corresponding to the emitted photons. Explain briefly.
b) The material is now cooled down to a very low temperature, and the photon detector stops detecting photon emissions. Next a beam of light with a continuous range of energies from infrared thorugh ultraviolet shines on the material, and the photon detector observes the beam of light after it passes through the material. What photon energies in this beam of light are observed to be significantly reduced in intensity ("dark absorption lines")? Explain briefly.

Answer:

Electricity and magnetism are two related phenomena produced by the electromagnetic force. Together, they form electromagnetism. A moving electric charge generates a magnetic field. A magnetic field induces electric charge movement, producing an electric current.

A group of organs working together comprises an organ system, B.

Answer:

Acceleration = 2.8 m/s²

Explanation:

Given the following data;

Mass = 1500 kg

Net force = 4200 Newton

To find the truck's acceleration;

Newton's Second Law of Motion states that the acceleration of a physical object is directly proportional to the net force acting on the physical object and inversely proportional to its mass.

Mathematically, it is given by the formula;

[tex] Acceleration = \frac {Net \; force}{mass} [/tex]

Substituting into the formula, we have;

[tex] Acceleration = \frac {4200}{1500} [/tex]

Acceleration = 2.8 m/s²

Answer:

C. an infinite distance from the lens

Explanation:

There are five distinct cases of image formation in a convex lens depending upon the position of an object:

1. When the object is placed at an infinite distance from the lens, its real image is formed at the focal point.

2. When the object is placed before the center of curvature of the lens, its real image is formed between the center of curvature and the focal point.

3. When the object is placed at the center of curvature of the lens, its real image is formed at the center of curvature.

4. When the object is placed between the center of curvature and the focal length of the lens, its real image is formed behind the center of curvature.

5. When the object is placed at the focal point of the lens, its virtual image is formed at infinity.

Hence, from point 5 the answer is:

C. an infinite distance from the lens

The continuous changing of rocks from one kind to another is called as the Rock cycle. So, the correct option is D.

The rock cycle is defined as the change of rocks from one form to another as molten magma cools down and becomes an igneous rock which then breaks down into sediments and again forms sedimentary rocks under great pressure. The same rock that can become a metamorphic rock when subjected to great heat and pressure.

Every rock type is altered when it is forced out of its equilibrium conditions. Rock cycle is explained as the chain of processes which produce and transform the rock types in Earth's crust.

Thus, the continuous changing of rocks from one kind to another is called as the Rock cycle. So, the correct option is D.

Learn more about Rock cycle, here:

https://brainly.com/question/29767269

#SPJ3

Answer:

10m/s

Explanation:

velocity=displacement/time

=200/20

=10m/s

Answer:

C

[tex]6 = \frac{3}{2} \lambda \\ wavelength : \: \lambda = 4 \: m \\ from \: wave \: equation \\ v = f\lambda \\ v = 8 \times 4 \\ v = 24 \: {ms}^{ - 1} [/tex]

The speed of the waves will be =  [tex]24\dfrac{m}{s}[/tex]

Given data is frequency f = 8.0 Hz

As we know that the speed of the wave is given by the formula below

[tex]V=f\times \lambda[/tex]

Since

[tex]6=2 \lambda[/tex]

[tex]\lambda =3m[/tex]

now

[tex]V=8\times3[/tex]

[tex]V=24m[/tex]

The speed of the waves will be = [tex]24\dfrac{m}{s}[/tex]

To know more about waves speed follow

https://brainly.com/question/13761336

Answer:

a) [tex]v=0.999124c[/tex]

b) [tex]E=7.566*10^{22}[/tex]

c) [tex]E_a=760 times\ larger[/tex]

Explanation:

From the question we are told that

Distance to Betelgeuse [tex]d_b=430ly[/tex]

Mass of Rocket [tex]M_r=20000[/tex]

Total Time in years traveled [tex]T_d=36years[/tex]

Total energy used by the United States in the year 2000 [tex]E_{2000}=1.0*10^20[/tex]

Generally the equation of speed of rocket v mathematically given by

[tex]v=\frac{2d}{\triangle t}[/tex]

[tex]v=860ly/ \triangle t[/tex]

where

[tex]\triangle t=\frac{\triangle t'}{(\sqrt{1-860/ \triangle t)^2}}[/tex]

[tex]\triangle t=\frac{36}{(\sqrt{1-860/ \triangle t)^2}}[/tex]

[tex]\triangle t=\sqrt{(860)^2+(36)^2}[/tex]

[tex]\triangle t=860.7532[/tex]

Therefore

[tex]v=\frac{860ly}{ 860.7532}[/tex]

[tex]v=0.999124c[/tex]

b)

Generally the equation of the energy E required to attain prior speed mathematically given by

[tex]E=\frac{1}{\sqrt{1-(v/c)^2} }-1(20000kg)(3*10^8m/s)^2[/tex]

[tex]E=7.566*10^{22}[/tex]

c)Generally the equation of the energy [tex]E_a[/tex] required to accelerate the rocket mathematically given by

[tex]E_a=\frac{E}{E_{2000}}[/tex]

[tex]E_a=\frac{7.566*10^{22}}{1.0*10^{20}}[/tex]

[tex]E_a=760 times\ larger[/tex]

Answer: b the energy of light...

Explanation:

Answer: I=0.52 A

Explanation:

Given

Voltage is [tex]2.5\ V[/tex]

Resistance [tex]R=4.8\ \Omega[/tex]

Current is given by

[tex]I=\dfrac{V}{R}[/tex]

[tex]\Rightarrow I=\dfrac{2.5}{4.8}=0.52\ A[/tex]

Answer:

A<L BO DI ED

Explanation:

Answer:

Wavelength = [tex]1.36\times 10^{-34}\ m[/tex]

Explanation:

Given that,

The mass of a ball, m = 0.113 kg

Velocity of the ball, v = 43 m/s

We need to find the wavelength of the ball. It can be calculated by applying the De-Broglie concept. So,

[tex]\lambda=\dfrac{h}{mv}[/tex]

Put all the values,

[tex]\lambda=\dfrac{6.63\times 10^{-34}}{0.113\times 43}\\\\=1.36\times 10^{-34}\ m[/tex]

So, the wavelength of the ball is equal to [tex]1.36\times 10^{-34}\ m[/tex].

Answer:

271.095 m

Explanation:

✓ Let speed of sound in air that was given as (343 m/s) be represented as (Vi)

✓( speed of sound in concrete that was given as (3000 m/s ) be debited as (Vc)

✓ Let the distance travelled by the sound = s

✓duration of Time that exist between heard of sounds = 0.70s

But we know that

Time = (Distance / Speed)

✓Time it takes the sound to travel through air= s/vi = s/343

✓Time it takes the sound to travel through concrete= s/vc = s/3000

✓ (s/343) - (s/3000) = 0.70

Finding LCM and simplify

[(3000s - 343s)]/1029000 = 0.70

2657s /1029000 = 0.70

Making " s" subject of the formula

s= (1029000 × 0.70)/2657

s=720300/ 2657

s= 271.095 m

Hence, The impact took place at a distance of 271.095 m away from the person.

Answer:

c

Explanation:

Answer:

Pros of DNA phenotyping:

-Phenotypical characteristics can be predicted such as eye color, hair color, skin pigmentation, and many more.

-predict ancestry of an organism

-Use to find criminals

Cons of DNA phenotyping:

-Some phenotypical traits could not be predicted

- Invading privacy

This technology will surely help forensics, law enforcement as it helps track down unknown perpetrators of crime.

3 arguments for it:

- accurate in narrow down researches

- finding biological ancestry

3 arguments against it

It violates the privacy policy of an individual

Racial discrimination is done of public

Equality policies are not followed by it.

Answer:

The answer is "[tex]945\ N[/tex]"

Explanation:

Aluminum has 210 megapascals of tensile resistance. They choose a shear force only at bent foil edge to bend aluminum foil over an edge (that is the edge of its box) to pull them. When a roll of aluminium domestic foil is 30 cm in width and about 15.0 micrometers.

[tex]\to 0.000015 \times 0.300 = 0.0000045\\\\\to 210000000 = \frac{F}{0.0000045}\\\\\to F=210000000 \times 0.0000045\\\\\to F = 945\ N[/tex]

Answer:

https://web.njit.edu/~binchen/phys111/LectureNotes/Physics111_lecture08.pdf

Explanation:it's 38 slides so look at the more bottom ones and there will be your question and answer

Answer:

the magnitude of the magnetic field is 1.23 × 10⁻⁸ T  { in the +y direction }

Explanation:

Given the data in the question;

the relation between the electric field and the magnetic field in an electromagnetic wave can be written as follows;

c = E₀/B₀

where c is speed of light, E₀ is the amplitude of the electric field and B₀ is the amplitude of the magnetic field.

given that;  E₀ = 4.70 V/m, we know that; speed of light c = 3 × 10⁸ m/s

so from our relation; c = E₀/B₀

B₀ = E₀/c

we substitute

B₀ = 4.70 / 3 × 10⁸

B₀ = 1.23 × 10⁻⁸ T  { in the +y direction }

Therefore, the magnitude of the magnetic field is 1.23 × 10⁻⁸ T  { in the +y direction }

Answer:

No, Momentum is conserved.

Explanation:

The ballistic pendulum is a device in which a projectile such as a bullet is fired into a suspended heavy wooden stationary block. Some kinetic energy gets transformed into heat and sound, and some is used to deform the block. However, momentum is conserved.

Answer:

the length of the column in air

Answer:

A) determine magnetic fields

For   0 ≤ r ≤ a

Magnetic field = ∅ [tex]\frac{rI}{2\pi a^2}[/tex]

For  a ≤ r ≤ b

Magnetic field =  ∅ [tex]\frac{I}{2\pi r}[/tex]

For   b ≤ r ≤ c

Magnetic field in the region = ∅ [tex]\frac{I}{2\pi r} [ c^2 - r^2 / c^2-b^2 ][/tex]

For  r ≥ c

magnetic filed in the region = 0

B ) attached below

Explanation:

A) Determine the magnetic field in the following regions

i) For   0 ≤ r ≤ a

Magnetic field = ∅ [tex]\frac{rI}{2\pi a^2}[/tex]

attached below is the detailed solution

ii) For  a ≤ r ≤ b

Magnetic field =  ∅ [tex]\frac{I}{2\pi r}[/tex]

attached below is the detailed solution

iii) For   b ≤ r ≤ c

Magnetic field in the region = ∅ [tex]\frac{I}{2\pi r} [ c^2 - r^2 / c^2-b^2 ][/tex]

attached below is the detailed solution

iv) For  r ≥ c

magnetic filed in the region = 0  and this is because the net current enclosed in the region = 0

Answer: x²-x-4

Explanation:

Here, we are going to use the FOIL method to simplify.

--------------------------------------------------------------------------------------

Given

(x+2)(x-1)-2(x+1)

Expand parenthesis

= x²-x+2x-2-2x-2

Put like terms together

= x²-(x-2x+2x)-(2+2)

Combine like terms

= x²-x-4

Hope this helps!! :)

Please let me know if you have any questions

Answer:

x² - x - 4

Explanation:

Multiply the parentheses

x² - x + 2x - 2 - 2 (x + 1)

Distribute -2 through the parentheses

- 2 (x + 1)

Since two opposites add up to zero, remove them from the expression

x² - x - 2 - 2

Calculate the difference

x² - x - 4

Answer:

please give me brainlist and follow

Explanation:

Given:

The speed of the train ,which the boy is observing(t) = 18 km/hr

[ Now , to convert km/hr into m/s we have to multiply by 5/18 ]

So,

speed of the observed train = 18× 5/18

☞ 05 m/s

Also, The speed of the train in which the boy is sitting is(s) = 36 km/hr

Speed in m/s will be = 36 × 5/18

☞ 10 m/s

Also, The Length of the Train = 90m

Therefore:.

The speed of the train is given (expressed) by

= > speed \: = \frac{distance}{time}=>speed=

time

distance

= > time \: = \frac{distance}{Velocity }=>time=

Velocity

distance

Where,

velocity = Realtive velocity of both trains

Distance = Length of the train

So, The above mentioned formulae can also be written as :

= > time = \frac{length}{relative \: velocity}=>time=

relativevelocity

length

Here,

Relative velocity will be :

☞. s -(-t)

☞. 10 -(-5)

☞.15 m/s = Relative velocity

Now , Finally putting the values in the formulae respectively

■ Time = 90/15

■ Time = 6 sec [Answer]

Answer:

hello the diagram relating to this question is attached below

a) angular accelerations : B1 = 180 rad/sec,  B2 = 1080 rad/sec

b) Force exerted on B2 at P = 39.2 N

Explanation:

Given data:

Co = 150 N-m ,

a) Determine the angular accelerations of B1 and B2 when couple is applied

at point P ; Co = I* ∝B2'

                150  = ( (2*0.5^2) / 3 ) * ∝B2

∴ ∝B2' = 900 rad/sec

hence angular acceleration of B2 = ∝B2' + ∝B1 = 900 + 180 = 1080 rad/sec

at point 0 ; Co = Inet * ∝B1

                  150 = [ (2*0.5^2) / 3  + (2*0.5^2) / 3  + (2*0.5^2) ] * ∝B1

∴ ∝B1 = 180 rad/sec

hence angular acceleration of B1 =  180 rad/sec

b) Determine the force exerted on B2 at P

T2 = mB1g + T1  -------- ( 1 )

where ; T1 = mB2g  ( at point p )

                 = 2 * 9.81 = 19.6 N

back to equation 1

T2 = (2 * 9.8 ) + 19.6 = 39.2 N

Answer:

Seconds

Explanation:

Hope it helps you in your learning process.

The rate of flow of charge (per second) through a conductor is called electric current.

S. I unit of electric current is Ampere (named after French Physicist Andre Marie Ampere)

The process by which rock minerals are changed by natural processes into new substances is known as chemical weathering. Option A is correct.

The breakdown or dissolution of rocks and minerals on the Earth's surface is referred to as weathering.

Weathering is the erosion or disintegration of rocks, building materials, etc., induced by chemical interactions dissolved in it rather than by mechanical processes.

Water, ice, acids, salts, plants, animals, and temperature variations are all weathering agents.

Chemical weathering is the process by which rock minerals are transformed into new compounds by natural processes.

Hence, option A is correct.

To learn more about weathering refer;

https://brainly.com/question/14426457

#SPJ2

The speed of a wave is 40 m/s. If the wavelength is 80 centimeters, what is the frequency of the wave ?

Velocity (V) = 40 m/s

Wavelength [tex] (\lambda) [/tex] = 80 cm = 0.8 m

The frequency (F) of the wave.

We know,

[tex] \bf V \: = \: F \: × \: \lambda [/tex]

40 = F × 0.8

F = [tex] \frac{40}{0.8} [/tex]

F = 50

Answer:

   f = q

Explanation:

In the attachment we can see a diagram of the parallel rays.

The dotted line represents the normal to the mirror surface

These rays when reflected using the constructor equation

        [tex]\frac{1}{f} = \frac{1}{p} + \frac{1}{q}[/tex]

where p and q are the distance to the object and the image respectively.

Since the rays are parallel P = inf

          1 / f = 1 / inf + 1 / q

          f = q

this means that all the rays focus on one focal point.