Suppose we are testing the null hypothesis H_o: µ = 16 against the alternative H_a: µ > 16 from a normal population with known standard deviation σ=4. A sample of size 324 is taken. We use the usual z statistic as our test statistic. Using the sample, a z value of 2.34 is calculated. (Remember z has a standard normal distribution.)

a) What is the p value for this test? ______
b) Would the null value have been rejected if this was a 2% level test?
OY
ON

c) Would the null value have been rejected if this was a 1% level test?
OY
ON

d) What was the value of x calculated from our sample? _______

The specific enthalpy at the exit of the pipe is 2804 kJ/kg.

The expression of specific enthalpy at the exit of the pipe can be found by the following method:

Here, m = mass flow rate of the steam = 3 kg/s

q1 = specific enthalpy at inlet of the pipe = 2744 kJ/kg

W = work done on the system = 0 (steady-state)

Q = rate of heat transfer = 696 kW

z1 = elevation of the inlet = 0 m

z2 = elevation of the outlet = +71 m

Since the rate of heat transfer is given as

Q = -m(h2 - h1) + W + Q_hot

So, h2 = [Q - Q_hot + m(h1) - W]/m

Where W = 0 and Q_hot = 0

h2 = (696 - 0 + 3(2744))/3

h2 = 2804 kJ/kg

Therefore, the specific enthalpy at the exit of the pipe is 2804 kJ/kg.

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Answer:

whats ur question?

Step-by-step explanation:

Answer:0.3 m

Step-by-step explanation:

Given

Ken can Jump [tex]1\ \frac{1}{5}\ m[/tex]

Steve can Jump [tex]1.5\ m[/tex]

Converting mixed fraction into a fraction

[tex]\Rightarrow 1\ \dfrac{1}{5}=\dfrac{1\times 5+1}{5}\\\\\Rightarrow \dfrac{6}{5}\ m=1.2\ m[/tex]

The difference between their Jumps is

[tex]\Rightarrow 1.5-1.2=0.3\ m[/tex]

Steve Jumps 0.3 m more than ken

The mean absolute deviation of last week's temperatures is 7.2°F.

Given below is the table of last week's and this week's low temperatures:Last week's temperatures: 29°F, 35°F, 42°F, 46°F, 52°FThis week's temperatures: 27°F, 31°F, 35°F, 38°F, 42°F, 46°F, 50°F

The range of this week's temperatures is found by subtracting the smallest value from the largest value. Therefore, the range of this week's temperatures is 50°F - 27°F = 23°F.

Mean absolute deviation is a measure of how much the data deviates from the mean of the data. To find the mean absolute deviation of last week's temperatures, we first need to find the mean of the data set.Using the formula for mean, we have:

Mean = (29 + 35 + 42 + 46 + 52)/5 = 40.8°F

To find the absolute deviations of each temperature from the mean, we need to subtract each temperature from the mean and take the absolute value.Absolute deviations:

|29 - 40.8| = 11.8|35 - 40.8|

= 5.8|42 - 40.8|

= 1.2|46 - 40.8|

= 5.2|52 - 40.8|

= 11.2

Next, we need to find the mean of these absolute deviations. Using the formula for mean again, we have:Mean absolute deviation = (11.8 + 5.8 + 1.2 + 5.2 + 11.2)/5 = 7.2°F

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[tex]4000(1.003)^{(x-1)}[/tex]

Step-by-step explanation:

Answer:

abd

Step-by-step explanation:

im smart

Answer:

The answer is A B D F

Step-by-step explanation:

I took the test sorry I don't have a better explanation.

To find the arc length, we can use the formula:

[tex]\[ L = \frac{\theta}{360} \times 2\pi r \]\\Given:\( r = \frac{d}{2} = \frac{30}{2} = 15 \) ft\( \theta = 42 \) degrees\( \pi = 3.14 \)\\Substituting the given values into the formula:\[ L = \frac{42}{360} \times 2 \times 3.14 \times 15 \]\[ L = \frac{42}{360} \times 94.2 \]\[ L = \frac{3956.4}{360} \]\[ L \approx 10.99 \] ftTherefore, the arc length traveled by the car, to the nearest hundredth, is 10.99 feet. The correct option is c.[/tex]

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Answer: 40 people like song A whereas 20 people like song B. Thus, it is reasonable to say that more people liked Song A .

Step-by-step explanation:

Step-by-step explanation:

hey, hope it helps.. :))

Answer:

10.10 15.15

Step-by-step explanation:

25.30 15.12 25.13

Answer:

Hi

Step-by-step explanation:

Answer:

The answer is "320".

Step-by-step explanation:

They have to be 1, 3, 5, 7, and 9 as your final digit. Your middle digit may be anything other than the first digit, and only the last digit or 0, is anything.

Now let us take a look at strange digits ending in 1.

This can start from any digit other than 0, so there are 8 options during the first digit.

Its middle digit could only be 1 digit and 1 digit. Even so, it can also be 0, since it has 8 options.

So, [tex]8\times 8 = 64[/tex] strange number ending in 1.

For other strange amounts, the very same logic is working.

And thus there are 64 possible odd numbers for just about any number ending in any of the five odd digits: 1, 3, 5, 7, or 9.

The answer is [tex]5 \times 64 = 320[/tex].

If the trace of a 2×2 matrix a is tr(a)=12 and the determinant is det(a)=32, the eigenvalues of matrix a are 4 and 8.

To find the eigenvalues of a 2×2 matrix, we can use the following formula:

λ² - tr(a) * λ + det(a) = 0,

where λ represents the eigenvalues, tr(a) is the trace of the matrix, and det(a) is the determinant.

In this case, we are given that tr(a) = 12 and det(a) = 32. Substituting these values into the formula, we have:

λ^2 - 12λ + 32 = 0.

To solve this quadratic equation, we can factorize it or use the quadratic formula. Factoring the equation, we get:

(λ - 4)(λ - 8) = 0.

Setting each factor equal to zero, we find two solutions:

λ - 4 = 0 => λ = 4,

λ - 8 = 0 => λ = 8.

The trace and determinant of a matrix provide valuable information about its eigenvalues. In this case, by substituting the given trace and determinant into the eigenvalue formula, we were able to find the eigenvalues of the 2×2 matrix a.

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Answer:

this means there is no answer to the problem

Step-by-step explanation:

Objective function is Z = 9 XC,RB + 11 XCB,GM, and the constraint for minimum vitamin C for Red Berry is75XC,RB + 350XCB,RB + 200XA,RB >= 0.

Objective function for the given statement is Z = 9 XC,RB + 11 XCB,GM,

where, XC, RB is the number of gallons of Cherry juice used in Red Berry, XCB, GM is the number of gallons of Cranberry juice used in Green Mush and also, XA, RB is the number of gallons of Avocado juice used in Red Berry, XC, GM is the number of gallons of Cherry juice used in Green Mush, XCB, GM is the number of gallons of Cranberry juice used in Green Mush, XA, GM is the number of gallons of Avocado juice used in Green Mush.

Hence, the objective function is Z = 9 XC,RB + 11 XCB,GM.

Minimum vitamin C for Red Berry will be given by the equation,

350XCB,RB + 400XC,RB + 200XA,RB >= 325XC,RB

=> 75XC,RB + 350XCB,RB + 200XA,RB >= 0

So, the constraint for minimum vitamin C for Red Berry is75XC,RB + 350XCB,RB + 200XA,RB >= 0.

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Answer:

c

Step-by-step explanation:

Given piecewise functions are: g(x) = {x² – 5 , 2€ (-[infinity], -7)9x - 17, 9 x € (-7,2](x + 1)(x - 5) , 2 € (2,00)

We are supposed to evaluate g(x) at x = 7. As per the given conditions,

we have the following; g(x) = {x² – 5 , 2€ (-[infinity], -7)9x - 17, 9 x € (-7,2](x + 1)(x - 5) , 2 € (2,00)

Now, g(7) represents the value of function g(x) at x = 7. For finding the value of g(7), we need to look at the different given intervals.

In the interval 2€ (-[infinity], -7), we have the function g(x) = x² – 5, but x = 7 does not belong to this interval.

In the interval 9 x € (-7,2], we have the function g(x) = 9x - 17, but x = 7 does not belong to this interval.

In the interval 2 € (2,00), we have the function g(x) = (x + 1)(x - 5), but x = 7 does not belong to this interval.

As x = 7 does not belong to any of the given intervals, g(7) is not defined.

Hence, the correct option is "Not defined".

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Answer:

2(11*9) + 2(11*h) + 2(9*h) = 558

h = 9 in.

Step-by-step explanation:

2(11*9) + 2(11*h) + 2(9*h) = 558

198 + 22h + 18h = 558

40h = 558-198

40h = 360

h = 9 in.

To find the 95% confidence interval when n=100 and p=0.72, we can use the following formula:

$$\left(\hat{p}-z_{\alpha/2} \sqrt{\frac{\hat{p}(1-\hat{p})}{n}}, \hat{p}+z_{\alpha/2} \sqrt{\frac{\hat{p}(1-\hat{p})}{n}}\right)$$

Where, $\hat{p}$ is the point estimate of the population proportion, $n$ is the sample size, $z_{\alpha/2}$ is the critical value of the standard normal distribution at a significance level of $\alpha$, which can be obtained from a table. For a 95% confidence level, $\alpha$ is equal to 0.05/2 = 0.025 on each tail.

The corresponding z-value is 1.96 (approximately).Hence, plugging in the values, we get

$$\begin{aligned}\left(0.72-1.96 \sqrt{\frac{0.72(0.28)}{100}}, 0.72+1.96 \sqrt{\frac{0.72(0.28)}{100}}\right) \\ \left(0.631, 0.809\right)\end{aligned}$$

Therefore, the 95% confidence interval is (0.631, 0.809) rounded to three decimal places.

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The particular solution to the differential equation with the initial condition y(0) = 1 is:

[tex]y = 1 + cos(t) + 1 - e^{(cos(t))[/tex]

To solve the given differential equation:

dy/dt + sin(t) = 1

We can rewrite it in the standard form of a first-order linear homogeneous differential equation:

dy/dt = 1 - sin(t)

The integrating factor for this equation is [tex]e^{(\int(-sin(t))dt)} = e^{(-cos(t)).[/tex]

Now, multiply both sides of the equation by the integrating factor:

[tex]e^{(-cos(t)) \times dy/dt} = (1 - sin(t)) \times e^{(-cos(t))[/tex]

The left-hand side can be rewritten using the chain rule:

[tex]d/dt [e^{(-cos(t))} \times y] = (1 - sin(t)) \times e^{(-cos(t))[/tex]

Integrate both sides with respect to t:

[tex]\int d/dt [e^{(-cos(t))} \times y] dt = \int (1 - sin(t)) \times e^{(-cos(t)) dt[/tex]

[tex]e^{(-cos(t))} \times y = \int (1 - sin(t)) \times e^{(-cos(t)) dt[/tex]

To evaluate the integral on the right-hand side, let u = -cos(t), du = sin(t) dt:

[tex]e^{(-cos(t))} \times y = \int (1 - sin(t)) \times e^{(-cos(t)) dt[/tex]

[tex]= \int (1 - sin(t)) \times e^u du[/tex]

[tex]= \int (e^u - sin(t) \times e^u) du[/tex]

[tex]= e^u - \int sin(t) \times e^u du[/tex]

Now, integrate the second term by parts:

[tex]\int sin(t) \times e^u du = -e^u \times cos(t) + \int e^u \times cos(t) dt[/tex]

Substituting the expression back into the equation:

[tex]e^{(-cos(t))} \times y = e^u - (-e^u \times cos(t) + \int e^u \times cos(t) dt)[/tex]

Simplifying:

[tex]e^{(-cos(t))} \times y = e^{(-cos(t))} + e^{(-cos(t))} \times cos(t) - \int e^{(-cos(t))} \times cos(t) dt[/tex]

To solve the remaining integral, let v = -cos(t), dv = sin(t) dt:

[tex]\int e^{(-cos(t))} \times cos(t) dt = \int e^v \times (-dv)[/tex]

[tex]= -\int e^v dv[/tex]

[tex]= -e^v + C[/tex]

[tex]= -e^{(-cos(t))} + C[/tex]

Substituting back into the equation:

[tex]e^{(-cos(t))} \times y = e^{(-cos(t))} + e^{(-cos(t))} \times cos(t) - (-e^{(-cos(t))} + C)[/tex]

Divide both sides by [tex]e^{(-cos(t))[/tex]:

[tex]y = 1 + cos(t) + 1 + C \times e^{(cos(t))[/tex]

Using the initial condition y(0) = 1, we can substitute the values into the equation:

[tex]1 = 1 + cos(0) + 1 + C \times e^{(cos(0))[/tex]

[tex]1 = 1 + 1 + C \times e^1[/tex]

[tex]C \times e = -1[/tex]

Therefore, the particular solution to the differential equation with the initial condition y(0) = 1 is:

[tex]y = 1 + cos(t) + 1 - e^{(cos(t))[/tex]

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Complete question =

Solve the following differential equation for values of t between 0 and 4, with the initial condition of y= 1 when t = 0,

dy/dt + sin(t) = 1

Answer:

12 students.

Step-by-step explanation:

If you had 4 sheets, you would want to start by dividing them all in 3's, since that's easiest. (open the file i just for a better example of how the sheet should look).

Now, let's assume these sheets are regular office sized paper.

Start by handing 1 third out to A student.

Now, since there are 4 sheets, divided in 3 sections, we multiply to see the result of how many sections there are.

4 x 3 = 12.

Therefore, 12 students will receive a third of the tissue paper.

Answer:

please stop being lazy by using OCR! next time type the question!

there's nothing such as  = -x2 3x + 1

it's probablhy f(x) = -x² + 3x + 1

Answer:

2 distinct irrational roots

Step-by-step explanation:

The proportion of values between 152 and 124 cm is 0.8996 or 89.96%.

Proportion between 152 and 124 cm according to a normal distribution with mu = 138cm and sigma = 7cm is 0.8996.

According to the given question, we know that the mean is μ = 138 cm, standard deviation is σ = 7 cm.

We have to find the proportion that is between 152 and 124 cm.

To solve the problem, first we have to find the z-scores for 152 and 124 cm.

We can calculate the z-scores as follows:Z-score for 152 cm is given by:z152​=(152−138)7=2z_{152}=\frac{(152-138)}{7}=2z152​=(152−138)7=2Z-score for 124 cm is given by:z124​=(124−138)7=−2z_{124}=\frac{(124-138)}{7}=-2z124​=(124−138)7=−2

We can use a z-table or calculator to find the proportion of values between these two z-scores.

The area under the standard normal curve between z = -2 and z = 2 is approximately 0.8996.

Therefore, the proportion of values between 152 and 124 cm is 0.8996 or 89.96%.

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Answer:

{7, 13)

Step-by-step explanation:

IR - 31 = 10

IR = 41

7*13 = 41

(-7)*13 = -41

(-13)*13 = -169

Complete question

A square pyramid. The square base has side lengths of 6.5 meters and the height of 6 meters.

What is the volume of the pyramid?

Answer:

84.5m³

Step-by-step explanation:

The volume of a square. Pyramid is given as :

V = 1/3 * base * height

Base = l² ; l = side length

Base = 6.5² = 42.25 m²

V = 1/3 * 42.25 * 6

V = 42.25 * 2

V = 84.5

The volume of square pyramid = 84.5m³

Answer:

X=25

Step-by-step explanation:

y+2=-7+2=5

[tex]5^{2} =25[/tex]

The question is incomplete. Here is the complete question.

Mavis is interested whether military status is related to gender in American Samoa. The data she collected about the population of American Samoa in 2010 is below.

Find the marginal distribution of military status in percentages. Round to the nearest whole percentages.

In Armed Forces:

Military-dependent:

Civilian:

Answer: In Armed Forces: 0%

              Military-dependent: 3%

              Civilian: 97%

Step-by-step explanation: Marginal Distribution is defined as the probability distribution of variables contained in a subset.

For the American Samoa's military status, marginal distribution is

1) In Armed Forces:

[tex]p_{1}=\frac{87}{55,519}*100[/tex]

[tex]p_{1}=0.15[/tex]

2) Military-dependent:

[tex]p_{2}=\frac{1709}{55,519}*100[/tex]

[tex]p_{2}=3.08[/tex]

3) Civilian:

[tex]p_{3}=\frac{53,723}{55,519}*100[/tex]

[tex]p_{3}=96.77[/tex]

Now round each percentage to the nearest whole percentage:

Armed forces: 0%

Military: 3%

Civilian: 97%

The marginal distributions of military status are, in nearest whole percentage:

Armed forces: 0%

Military: 3%

Civilian: 97%