Answers
Answer:
Explanation:
angle of incidence.
Related Questions
Which device converts electric energy into mechanical energy?
O A. An electromagnet
O B. A motor
O C. A transformer
O D. A generator
Answers
Answer:
B motor
Explanation:
If a current of 1.10 A flows through a 7.00 Ω resistor of length 3.00 m, what is the electric field strength inside the resistor?
Answers
Answer:
the electric field strength inside the resistor is 2.57 V/m
Explanation:
Given;
current flowing through the wire, I = 1.10 A
resistance of the wire, R = 7.00 Ω
length of the wire, L = 3.00 m
The emf created inside the resistor is calculated as;
V = IR
V = 1.10 x 7
V = 7.7 V
The electric field strength inside the resistor is calculated as;
E = V/L
E = 7.7 / 3
E = 2.57 V/m
Therefore, the electric field strength inside the resistor is 2.57 V/m
A 6.47 micro-coloumb particle moves through a region of space where an electric field of magnitude 1300 N/C points in the positive x direction, and a magnetic field of magnitude 1.33 T points in the positive z direction. If the net force acting on the particle is 6.27E^-3 N in the positive x direction>
Required:
Calculate the magnitude of the particle's velocity. Assume the particle's velocity is in the xy plane.
Answers
Answer:
v = 248.8 m/s
Explanation:
Given that,
Charge, q = [tex]6.47\ \mu C[/tex]
Electric field, E = 1300 N/C
Magnetic field, B =1.33 T
The force acting on the particle, [tex]F=6.27\times 10^{-3}\ N[/tex]
We need to find the magnitude of the particle's velocity. The net force on the particle is given by :
[tex]F=qE+qvB\\\\6.27\times 10^{-3}=6.47\times 10^{-6}\times 1300+6.47\times 10^{-6}\times 1.33v\\\\6.27\times 10^{-3}-6.47\times 10^{-6}\times 1300=6.47\times 10^{-6}\times 1.33v\\\\-0.002141=6.47\times 10^{-6}\times 1.33v\\\\v=\dfrac{0.002141}{6.47\times 10^{-6}\times 1.33}\\\\v=248.8\ m/s[/tex]
So, the magnitude of the particle's velocity is 248.8 m/s.
please help me !
1. Suppose that the temperature drops 25 degrees overnight. When you get into your car the next morning, your low tire pressure light comes on. Explain, in terms of the ideal gas law, why this happened (assume air is an ideal gas). (10 points)
Answers
Answer:
The drop in temperature overnight causes a decrease in the average kinetic energy of the air molecules inside the tires. According to the ideal gas law, this leads to a decrease in tire pressure. The low tire pressure light in vehicles is triggered when the pressure falls below a certain threshold, alerting the driver to check and adjust the tire pressure.
Explanation:
The ideal gas law, represented by the equation PV = nRT, relates the pressure (P), volume (V), number of moles (n), and temperature (T) of an ideal gas. In this case, we can analyze how the drop in temperature affects the tire pressure.
When the temperature drops, according to the ideal gas law, the pressure of a gas will decrease if the volume and the number of moles remain constant. This is because the decrease in temperature causes a decrease in the average kinetic energy of the gas particles, leading to less frequent and less forceful collisions with the tire walls, resulting in a decrease in pressure.
In the context of the tire pressure, the air inside the tires behaves as an ideal gas. When the temperature drops overnight, the air inside the tires also cools down, causing a decrease in its temperature. As a result, the average kinetic energy of the air molecules decreases, leading to a decrease in pressure inside the tires.
The low tire pressure light comes on as a result of this drop in pressure. The tire pressure monitoring system in modern vehicles is designed to detect significant deviations from the recommended tire pressure. When the pressure drops below a certain threshold, typically due to temperature changes or a puncture, the light is triggered to alert the driver to check and adjust the tire pressure.
Therefore, the drop in temperature overnight causes a decrease in the average kinetic energy of the air molecules inside the tires, resulting in a decrease in tire pressure, which triggers the low tire pressure warning light.
Hope this helps!
Help me please it’s due right now review question help
Answers
Answer:
M.E = mgh
given, m=400g = 400/1000=0.4kg
h=1.75m
g=9.81m/s²
M.E =0.4×9.81×1.75
=6.867J
In an application, Germanium is
made p-type material by adding
Indium. The rate of adding is one
indium atom
per
3 Germanium
atom. Assume donor density to be
zero and ni = 6.2 Cubic
metre at room temperature.
Determine the value
of
the
aceeptor atom density
Answers
Answer:
produce electronics
Explanation:
The uses of Germanium are recorded beneath: Germanium's principle use is to deliver strong state hardware, semiconductors and fiber optic frameworks. As a phosphor in fluorescent lights.
A bird is flying directly toward a stationary bird-watcher and emits a frequency of 1490 Hz. The bird-watcher, however, hears a frequency of 1505 Hz. What is the speed of the bird, expressed as a percentage of the speed of sound
Answers
Answer:
The speed of the bird is 1.00% of the speed of sound.
Explanation:
The speed of the bird can be found by using the Doppler equation:
[tex] f = f_{0}(\frac{v - v_{r}}{v - v_{s}}) [/tex]
Where:
v: is the speed of sound = 343 m/s
f₀: is the frequency emitted = 1490 Hz
f: is the frequency observed = 1505 Hz
[tex]v_{r}[/tex]: is the speed of the receiver = 0 (it is stationary)
[tex]v_{s}[/tex]: is the speed of the source =?
The minus sign of [tex]v_{s}[/tex] is because the source is moving towards the receiver.
By solving the above equation for [tex]v_{s}[/tex] we have:
[tex] v_{s} = v - \frac{f_{0}*v}{f} = 343 - \frac{1490*343}{1505} = 3.42 m/s [/tex]
The above speed in terms of the speed of sound is:
[tex]\% v_{s} = \frac{3.42}{343}\times 100 = 1.00 \%[/tex]
Therefore, the speed of the bird is 1.00% of the speed of sound.
I hope it helps you!
what is the stress in a steel wire that is 5m long and 0.04cm squared in cross section If the wire bears a load of 20kg?
Answers
Answer:
Explanation:
stress = ?
length =5 m
area of cross section = 0.04 cm or 0.0004m
force = 20 × 10 = 200 N ( w = mg) g = 10
formula : stress = force / cross-sectional area
stress = 200 / 0.0004
stress = 500,000 Nm^-2
Which expenses do you think will change based on how much you drive
Answers
Increased driving can lead to higher vehicle maintenance and repair expenses, increased fuel costs, potential increases in auto insurance premiums, and additional parking fees, all of which should be considered when estimating the overall impact on your expenses.
The expenses that are likely to change based on how much you drive can be broadly categorized into two main areas: vehicle-related expenses and fuel-related expenses.
1. Vehicle-related expenses: The more you drive, the more wear and tear your vehicle will experience, leading to increased maintenance and repair costs. Regular oil changes, tire replacements, brake pad replacements, and other routine maintenance tasks will be required more frequently.
2. Fuel-related expenses: It's intuitive that the more you drive, the more fuel you'll consume, resulting in higher fuel expenses. Fuel prices can vary, but regardless of fluctuations, increased mileage will directly impact your fuel budget. Fuel-efficient vehicles may mitigate some of these costs, but the overall impact on your expenses will still be noticeable.
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Your eyes form upside-down images, which are then flipped right-side-up by our brains.
True
False
Answers
Answer:
I believe it is true, but our brains don’t do it, I think it is the lenses in our eyes that do it. I might be wrong tho
Explanation:
Answer:
Yes it is true that our eyes form upside-down images, which are flipped right-side-up by our brain.
why entrepreneurs should not be a wild risk taker?
Answers
Explanation:
Entrepreneurs are not wild risk takers but are instead calculating risk takers. They appear to be risk takers because they see the market differently than the rest of us do. 3. ... Entrepreneurs tend to be optimistic about their chances for success, and usually their optimism is based in reality.
Pls quickly brainliest to the first to anwser
Answers
Answer:
8m/s^2
Explanation:
hope it helps........
Explanation:
you're supposed to know the formula of acceleration which is velocity of a time then you can solve the question
a train has an initial velocity of 30 m/s. If the train accelerates uniformly at a rate of 6.3 m/s ^ for 2.8 seconds what is the trains final velocity?
Answers
T
Answer:
the velocity is a second final to initial velocity of 39
a disk of a radius 50 cm rotates at a constant rate of 100 rpm. what distance in meters will a point on the outside rim travel during 30 seconds of rotation?
Answers
Explanation:
100 rev/min (2π rad/rev) / (60 sec/min) = 3⅓π rad/s
d = ωrt = 3⅓π(0.50)(30) = 50π m ≈ 157 m
6) Which of the following describes a good team member?
A) She is willing to compromise.
B) He is aggressive.
C) She is stubborn.
D) He is conceited.
Answers
Answer: A
Explanation:
Because someone who is aggressive, stubborn, or proud of theirselves are more likely to think they're above everyone else and be a bully. However someone who is willing to compromise is better since you can generally make everyone happy that way
HOPE THIS HELPS ^^
You are watching a s Saturday morning cartoon concerning a jungle hero called George of the Jungle. George attempts to save a friend, an ape named Ape, from a stampeding herd of wildebeests. Ape is at the base of a tall tree which has a vine attached to its top. George is in another tree holding the other end of the vine. George plans to swing down from the tree, grab Ape at the bottom of the swing, and continue up to safety on a ledge which is half of George's initial height in the tree. Assuming that Ape weights the same as George, will they successfully make it to the top of the ledge? If you believe they do, how high a ledge could they make it to? If you disagree, suggest what could be done for George to save Ape.
Answers
Answer:
I don't think so because if Ape was the same weight as george I don't
think he can hold him but maybe so let's say he could hold his own ape then Yes I think he could make it to the ledge Now I think they could make it to the ledge which was half the size.
Sorry if this sounded weird English is my 2nd language Oh and if this helped please give brainiest thank you <3
what is the velocity of the object 2.3 seconds after it is released from the top of the empire state building?
Answers
Explanation:
Object is under the effect of the acceleration of gravity
v = 1/2 a t^2 a = 9.81 m/s^2 t = 2.3
v = 25.9 m/s^2 = ~ 26 m/s ( two significant digits)
Fairly easy question I’ll give extra points help.
Answers
1. third law
2. first law
3. third law
4. second law
Help please. Question about a potential energy.
Answers
Calculate the terminal velocity of
the following nain drops faning
through air (a) one with a diameter
of 0.3cm 6 one with a a diameter
of o. Olm. Take the density of
water to be looo Kym3 and the
eis cosity of air to be ixlos pas.
The buoyancy effect of the air
may be ignored)
Answers
answer asap!!! i suck at acceleration
Answers
Answer: 2.67
Explanation: it said he went from 0 to 8 in 3 seconds so if we divide eight By three we get 2.67 rounded to the nearest hundredth so you accelerated that 2.67 m/s
A hand dryer blows heated air downwards out of the exit duct at a velocity of 4 m/s. The temperature and density of the ambient air at the inlet are 15 C and 1.23 kg/m3, while at the outlet it has temperature 35 C and density 1.15 kg/m3 The blower power is 10.0 W and the heater power is 715 W. Consider the inlet to be at the large mass of ambient air which has negligible velocity.
a) What is the pressure at the outlet? 4 m/s, 35 C
b) You will be applying the energy equation. Why can you ignore any height differences in this situation?
c) If the specific heat of air C-1000 J/(kg K), where Δυ-C Δ T, find the change in internal energy per unit mass from the inlet to outlet.
d) Find the mass flow rate through the dryer.
e) What is the power loss in the system?
f) What is the loss in the system?
g) What is the head loss in the system?
h) What is the total loss coefficient of the system, referred to the outlet velocity?
i) If there were no heater, would the temperature of gas at the outlet be higher, the same, or lower than the inlet? Explain why.
Answers
Answer:
nzkdjdksishdjsdjjdjnzkskejeoueeuieeoyrie ryrhdhcksodopdncndnszdkhfoeosheiwuef wokxkzdkjdoeehxjbxbdkeiehdhdhddjjddjdhhdhdhhhjdhfjdjjfjddhdheudiwiehdbejwowud
Explanation:
isos
A carnival ride starts at rest and is accelerated from an initial angle of zero to a final angle of 6.3 rad by a rad counterclockwise angular acceleration of 2.0 s2 What is the angular velocity at 6.3 rad?
Answers
The final angular velocity of the carnival ride at a displacement of 6.3 rad is 25.2 rad/s.
Final angular velocity of the carnival ride
The final angular velocity of the carnival ride is determined by applying third kinematic equation as shown below;
ωf = ωi + 2αθ
where;
ωf is the final angular velocity of the carnival ride = ?ωi is the initial angular velocity of the carnival ride = 0α is the angular acceleration = 2.0 rad/s²θ is the angular displacement of the carnival ride = 6.3 radωf = 0 + 2(2.0) x 6.3
ωf = 25.2 rad/s
Thus, the final angular velocity of the carnival ride at a displacement of 6.3 rad is 25.2 rad/s.
Learn more about angular velocity here: https://brainly.com/question/6860269
Answer: 5.0 rad/s
Explanation: Because that’s what khan said so try it out.
The water pressure to an apartment is increased by the water company. The water enters the apartment through an entrance valve at the front of the apartment. Where will the increase in the static water pressure be greatest when no water is flowing in the system
Answers
Answer:
Option C
Explanation:
Options for the question are as follows -
A. At a faucet close to entrance valve
B. At a faucet away from the entrance valve
C. It will be the same at all faucets
D. There will be no increase in the pressure at the faucets
Solution -
The static force will be the same at all faucets and also the area of the faucets be same.
Thus, the pressure created at all faucets will be the same.
Thus, option C is correct
CiCi is hiking in the woods after a rainstorm when she sees a single large mass of rock and soil moving quickly downhill.
Which type of mass movement is this?
A. landslide
B. slump
C. creep
D. mudflow
Answers
Can someone tell me anything useful about energy management in the human body?
Answers
Answer:
The human body carries out its main functions by consuming food and turning it into usable energy. Immediate energy is supplied to the body in the form of adenosine triphosphate (ATP). Since ATP is the primary source of energy for every body function, other stored
Explanation:
this what teacher explain to us
Batteries are not perfect. They can't deliver infinite current. As the current load on a battery gets larger, the voltage output gets smaller.
a. True
b. False
Answers
One hazard of space travel is debris left by previous missions. There are several thousand objects orbiting Earth that are large enough to be detected by radar, but there are far greater numbers of very small objects, such as flakes of paint. The force exerted by a 0.100-mg chip of paint that strikes a spacecraft window at a relative speed of 4.00 x 103 m/s, given the collision lasts 6.00 x 10-8 s is Fill input: x 106 N.
Answers
Answer:
The correct answer is "6666.67 N".
Explanation:
The given values are:
Mass,
m = 0.100
Relative speed,
v = 4.00 x 10³
time,
t = 6.00 x 10⁻⁸
As we know,
⇒ [tex]F=m(\frac{\Delta v}{\Delta t} )[/tex]
On substituting the given values, we get
⇒ [tex]=0.100\times 10^{-6}(\frac{4\times 10^3}{6\times 10^{-8}} )[/tex]
⇒ [tex]=6666.67 \ N[/tex]
Temperature is the measure of the average kinetic energy of the particles in an object. True False
Answers
Answer:
true
Explanation:
with increased temperature particles move faster as they gain kinetic energy
a constant force of magnitude F=45 N and making an angle of 30 to the horizontal is applied on a stationary block placed on the floor over a distance of 8 m. the work done by the force
Answers
The work done by the force on the block is approximately 311.2 Joules.
To calculate the work done by the constant force of magnitude F = 45 N over a distance of 8 m at an angle of 30 degrees to the horizontal, we need to find the component of the force that acts parallel to the displacement.
The horizontal component of the force can be calculated using trigonometry:
F_horizontal = F * cos(angle)
= 45 N * cos(30 degrees)
= 45 N * (√3 / 2)
≈ 38.9 N
Now, we can calculate the work done by the force using the equation:
Work = Force * Distance * cos(theta)
where theta is the angle between the force and the displacement.
Work = F_horizontal * Distance * cos(0)
= 38.9 N * 8 m * cos(0)
= 38.9 N * 8 m
= 311.2 Joules
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