Answer:
68 cmStep-by-step explanation:
Let ABCD be a rhombus, all sides of the rhombus have equal length and its diagonal AC and BD are intersecting each other at a point O.
As we know that the diagonals in the rhombus bisect each other at 90°.
So, AO can be written as (AC/2)
= 16/2
= 8 cm
And, DO can be written as (BD/2)
= 30/2
= 15 cm
Then, consider the triangle AOD and apply Pythagoras theorem,
AD2 = AO2 + DO2
AD2 = 82 + 152
AD2 = 64 + 225
AD2 = 289
AD = √289
AD = 17 cm
Hence, the length of each side of the rhombus is 17 cm
Now,
The perimeter of rhombus = 4 × side of the rhombus
= 4 × 17
= 68 cm
Therefore, the perimeter of the rhombus is 68 cm.
Morgan won 7 blue ribbons and 4 red ribbons at her horse shows. What is the ratio of red ribbons to blue ribbons she won?
Answer:
4:7
Step-by-step explanation:
Evaluate the following real numbers:
1. l5l + l4l
2. 0.4 ÷ 10
3. ¼ + ⅔
4. 3 × 1 ½
5. ⅓ - ¼
6. (⅜) (8/5)
7. ⅖ + ⅗
8. -1 + (-1) + [-(9+4)]
9. the value of x + y if x = 4 and y = 6
10. 9² + 3³
Answer:
Q.1 Answer is 9
Q.2 Answer is 0.04
Q.3 Answer is 11/12
Q.4 Answer is 3/2
Q.5 Answer is 1/12
Q.6 Answer is 3/5
Q.7 Answer is 1
Q.8 Answer is -15
Q.9 Answer is 10
Q.10 Answer is 108
[tex]\sf 19=7x-2x[/tex]
Answer:
[tex]3\dfrac{4}{5}[/tex]
Step-by-step explanation:
19 = 7x - 2x
19 = (7 - 2)x
19 = 5x
Divide both side by 5
19/5 = x
[tex]x=3\dfrac{4}{5}[/tex]
[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]
Value of x is equal to ~
[tex] \boxed{3.8}[/tex][tex] \large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}[/tex]
[tex]19 = 7x - 2x[/tex][tex]5x = 19[/tex][tex]x = 19 \div 5[/tex][tex]x = 3.8[/tex]Dennis decided he wanted to go to the carnival. The carnival charges $6.00 for entry and $1.50 for each ride.
Part A
Write an expression to represent this scenario where r represents the number of rides.
Part B
Create and solve an equation to determine how many possible rides Deniss can ride if his parents gave him $35.00. Show your work.
We want to create a linear equation to model the given situation.
A) c(r) = $6.00 + $1.50*r
B) 19 rides.
We know that the carnival charges $6.00 for entry plus $1.50 for each ride.
A) With the given information we can see that if you ride for r rides, then the cost equation will be:
c(r) = $6.00 + $1.50*r
Where c(r) is the cost for going to the carnival and doing r rides.
B) If you have $35.00, then we can solve:
c(r) = $35.00 = $6.00 + $1.50*r
Now we can solve the equation for r.
$35.00 = $6.00 + $1.50*r
$35.00 - $6.00 = $1.50*r
$29.00 = $1.50*r
$29.00/$1.50 = r = 19.33
Rounding to the next whole number we get: r = 19
This means that with $35.00, Dennis could go to 19 rides.
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Graph y= –3x+4.
i need a pic
5o points and brain thing
Refer to the attachment
Order the set of numbers from least to greatest.
-0.62
-0.615
-5/6
Answer:
5/6, -0.62, -0.615
Step-by-step explanation:
Hope this Help If i got it wrong I'm sorry I tried :(
Solve the inequality.
-12 < 1/2(x+16) < 18
Answer:
-40 < x < 20
Step-by-step explanation:
step 1: -12 < 1/2(x+16) < 18 --> Distribute
step 2: -12 < 1/2x + 8 < 18 --> subtract 8
step 3: -20 < 1/2x < 10 --> Multiply by 2
answer : -40 < x < 20
Plzzzz I need Helpppp!!!
Answer:
(8x+15)=(7x+17){ being alternative angle}
8x+15=7x+17
8x-7x=17-15
x=2
here,
8x+15= 8×2+15
16+15=31
7x+17
7×2+17
14+17
31
again
(8x+15)+y=180°( being straight angle)
31+y=180
y=180-31
y= 149
[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]
In the given figure, Angles (8x + 15) and (7x + 17) are equal
because they form pair of Alternate interior angles.
[tex]8x + 15 = 7x + 17[/tex][tex]8x - 7x = 17 - 15[/tex][tex]x = 2[/tex]So,
[tex]8x + 15[/tex][tex]( 8\times 2) + 15[/tex][tex]16 + 15[/tex][tex]31 \degree[/tex]now, as we can see Angle y and (8x + 15) are forming linear pair; so their sum measures 180°
[tex](8x + 15) + y = 180[/tex][tex]31 + y = 180[/tex][tex]y = 180 - 31[/tex][tex]y = 149 \degree[/tex]How many solutions are there for the following equation? Why?
8(x + 9) = 72 – 5x
Select the option that correctly answers both questions.
1 There is one solution, because the coefficients of the variables on both sides of the equation are different.
2 There is one solution, because the coefficients of the variables on both sides of the equation are the same.
3 There are no solutions, because the coefficients of the variables on both sides of the equation are different.
4 There are no solutions, because the coefficients of the variables on both sides of the equation are the same.
Answer:
I think 2? maybe 1.
Step-by-step explanation:
because it becomes 8x+72=72-5x which can then become 3x=0 then x=0/3 and 0/3=0 so x=0
QUESTION 8
The city Music Hall charges $24.00 per adult and $14.00 per senior citizen. One day 492 people attended a concert. The total for tickets purchased
was $7878.00. How many senior citizens attended the concert?
O 393 senior citizens
O 99 senior citizens
O200 senior citizens
O 292 senior citizens
Answer:
Adults (x) = 99 and
Seniors (y) = 393
393 seniors
Step-by-step explanation:
Adults= x
Seniors = y
1) x+ y = 492
2) 24x + 14y = 7,878
1) x = 492 - y
2) 24 (492 - y) + 14 y = 7,878 (substitution)
11808 - 24y + 14y = 7,878
11,808 - 10y = 7,878
11,808 - 7,878 = 10y
3,930/10 = y
y = 393
1) x + 393 = 492 (substitution)
x = 492 - 393
x = 99
A rental car company charges $54.35 per day to rent a car and $0.09 for every mile driven. Jayden wants to rent a car, knowing that: • He plans to drive 425 miles. • He has at most $310 to spend. Use the drop-down menu below to write an inequality representing d, the total number of days Jayden can rent the car while staying within his budget.
The inequality representing d, the total number of days Jayden can rent the car while staying within his budget is 54.35d + 38.25 ≤ 310
Given:
Charge per day = $54.35
Charge per mile = $0.09
Total miles = 425 miles
Amount to spend = at most $310
let
d = number of days
The inequality:
54.35 × d + 0.09 × 425 ≤ 310
54.35d + 38.25 ≤ 310
54.35d ≤ 310 - 38.25
54.35d ≤ 271.75
d ≤ 271.75 / 54.35
d ≤ 5 days
Therefore, the total number of days Jayden can rent the car while staying within his budget is 5 days
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I need help please
And thank you
Answer:
-1, 3, and 5
Step-by-step explanation:
When mapping a function the inputs (x), the oval to the left, is the domain. The oval to the right, the output, is the range.
Given that
R
=
9
x
+
8
y
Find
x
when
y
=
3
and
R
=
5
Give your answer as an improper fraction in its simplest form.
Answer:
X = 19/9
Step-by-step explanation:
R = 9x + 8y
R = 5, Y = 3
5 = 9x + 8(3)
9x = 8(3) - 5
9x = 19
x = 19/9
Which of the sets of terms below does NOT include like terms? *
1 point
9m, -9m, 7m
1p, -7p, 7p
30, -25, 25
6x, 6y, 6z
The black line is the graph of y = x. Which of these
equations could represent the blue line?
Answer:
A
Step-by-step explanation:
Answer:
The answer is (y=1/2x )
whats 12.3/342/75x75xyx85
Answer: 167?
Step-by-step explanation:
Show 2 + 5 in number line.
The pictures is where my question is someone please answer it.
Answer:
functions: first one, third one, fifth one, seventh one, eigth one
the rest are not function
Step-by-step explanation:
if it is a function it either passes the line test or it doesnt have two outputs
If the scale is 3cm to 8 km, what is 5 cm?
Answer:
Step-by-step explanation:
3 cm=8 km
1cm=8/3 km
5 cm=8/3×5=40/3 =13 1/3 km
what is the equivalent value 3/2×(−2)
Answer:
= -3
multiplying and dividing fractions
Answer:
-3
Step-by-step explanation:
3/2^(-2)=-3
What is the equation of the line that passes through the point (6,14) and is parallel to the line with the following equation? y=-4/3x -1
Answer:
[tex]y=\displaystyle-\frac{4}{3}x+22[/tex]
Step-by-step explanation:
Hi there!
What we need to know:
Linear equations are typically organized in slope-intercept form: [tex]y=mx+b[/tex] where m is the slope and b is the y-interceptParallel lines always have the same slope (m)Determine the slope (m):
[tex]y=\displaystyle-\frac{4}{3}x -1[/tex]
The slope of the given line is [tex]\displaystyle-\frac{4}{3}[/tex], since it is in the place of m in y=mx+b. Because parallel lines always have the same slope, the slope of a parallel line would also be [tex]\displaystyle-\frac{4}{3}[/tex]. Plug this into y=mx+b:
[tex]y=\displaystyle-\frac{4}{3}x+b[/tex]
Determine the y-intercept (b):
[tex]y=\displaystyle-\frac{4}{3}x+b[/tex]
To find the y-intercept, plug in the given point (6,14) and solve for b:
[tex]14=\displaystyle-\frac{4}{3}(6)+b\\\\14=-8+b\\b=22[/tex]
Therefore, the y-intercept of the line is 22. Plug this back into [tex]y=\displaystyle-\frac{4}{3}x+b[/tex]:
[tex]y=\displaystyle-\frac{4}{3}x+22[/tex]
I hope this helps!
Which equations have the same pair of solutions? Select all that apply.
n(n + 3)(n - 4) = 0
2n(4n + 6)(6n - 4) = 0
0 = 2n(6 - 4n)(4 - 6n)
0 = n(2n + 3)(3n - 2)
2n(2n + 3)(3n - 2) = 0
3n(6n + 9)(9n - 6) = 0
Please help It really important
A
the domain is the x-axis number soooo
Domingo earns $13 dollars per hour and worked 47.5 hours that week. He is paid
double time for all hours worked over 40 hours in one week. What is his gross pay
for the week?
Domingo earns 715$ in the week that is his gross income
Check cashing companies
charge high fees. Banks charge
less, or nothing, to cash checks
for their account holders. How
can you be sure to avoid check
cashing companies?
Answer:
they usually cost nothing if you go through your bank
What is the P(Red Diamond Face Card) and the P (Black Face Card)
Answer:
9/1352.
Step-by-step explanation:
P(Red Diamond Face Card) = 3/52.
P (Black Face Card) = 6/52 = 3/26.
So the answer is 3/52 * 3/26
= 9/1352.
I need help ASAP !!!
Answer:
B is it
Step-by-step explanation:
Can someone pls help me
18/24=0.75
?/80=.75
80x.75=?
?=60
5x+10=60
-10 -10
5x=50
/5 /5
x=10
sub x in for 10
10x5=50+10=60
C.X=10
The parking lot at a grocery store has 90 cars in it. 30% of the cars are two-toned. How
many cars are two-toned?
27
if 90 is 100% and we have to find 30% we have to do this:
(90 * 30) / 100 = 27
two toned cars are 27
Solve for x and find the measure of the indicated angle.
D
100°
(13x + 2)
70°
(18x + 2)%
B
=
mZC =
Answer:
[tex]{ \rm{100 + (13x + 2) + (18x + 2) + 70 = 360}} \\ \\ { \rm{31x + 174 = 360}} \\ \\ { \rm{31x = 186}} \\ \\ { \rm{x = 6 }}[/tex]
• Angle C
[tex]{ \rm{m \angle C = (13x + 2)}} \\ \\ { \rm{m \angle C = (13 \times 6) + 2 }} \\ \\ { \rm{m \angle C =80 \degree }}[/tex]